Method and system for rectifying sound wave pressure in sound wave amplitude well logging
An environmental pressure, sound wave technology, used in surveying, earthmoving, wellbore/well components, etc., can solve different problems that affect the accuracy of measurement
- Summary
- Abstract
- Description
- Claims
- Application Information
AI Technical Summary
Problems solved by technology
Method used
Image
Examples
Embodiment 1
[0140] Suppose a logging team measures a well and obtains the following data:
[0141] The logging environment pressure parameter is ρh 1 =4.7841×10 5 kg / m 2 , the crystal emission voltage monitored at the same time is 7100V, and the amplitude of the sound wave received at 3feet (here takes the first wave as an example) is 1200mV.
[0142] First, in the instrument's Figure 4 The ambient pressure parameter found in the "voltage-amplitude" characteristic curve is 4.7841×10 5 kg / m 2 The curve (in practice may not be exactly 4.7841×10 5 kg / m 2 curve, but according to Figure 4 This curve can be easily found by interpolation), then the coefficient of the "voltage-amplitude" relationship curve is
[0143]
[0144] where μ 1 =0.1673, and the actual measured data is: v 1 =7100V, p 1 =1200mV,
[0145] Substitute these parameters and data into equation (6) to obtain the acoustic amplitude p after the emission voltage correction alone a The value of:
[0146] =1200-0....
Embodiment 2
[0169] Suppose a logging team measures a well and obtains the following data:
[0170] The logging environment pressure parameter is ρh 1 = 1.4071×10 5 kg / m 2 , and the monitored crystal emission voltage is 6500V, and the amplitude of the sound wave received at 3feet (here takes the first wave as an example) is 980mV.
[0171] First, in the instrument's Figure 4 The ambient pressure parameter found in the "voltage-amplitude" characteristic curve is 1.4071×10 5 kg / m 2 The curve of (in practice may not be exactly 1.4071×10 5 kg / m 2 curve, but according to Figure 4 This curve can be easily found by interpolation), then the coefficient of the "voltage-amplitude" relationship curve is
[0172]
[0173] where μ 1 =0.163, while the actual data measured is: v 1 =6500V, p 1 =980mV.
[0174] Substitute these parameters and data into equation (6) to obtain the acoustic amplitude p after the emission voltage correction alone a The value of:
[0175] =980-0.163(6500-70...
PUM
Login to View More Abstract
Description
Claims
Application Information
Login to View More 


