Intelligent control method of variable-frequency refrigerator
A technology of intelligent control and frequency conversion refrigerators, which is applied in the direction of household refrigerators, household refrigeration devices, coolers, etc., can solve the problems of slow cooling speed and achieve the effects of rapid cooling, quality assurance, and reduced temperature fluctuation time
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Embodiment 1
[0054] see figure 1 , taking the air-cooled refrigerator using the VTB113Y inverter compressor produced by Gacibela as an example, the room with the door open is a cold room, and the volume of the cold room is 300L, that is, 0.3m3. The specific steps of the intelligent control method are as follows:
[0055] Step 1: Set the cooling time t of the refrigerator to 60s, and detect the temperature T of the refrigerator compartment when the refrigerator is running normally 1 At 4°C, the compressor speed R old 2700r / min;
[0056] Step 2: Open the door of the refrigerating room, then close the door, and detect the temperature T of the refrigerating room after 10 seconds 2 is 8°C.
[0057] Step 3: Calculate the load increase ΔQ caused by opening the refrigerator door;
[0058] First, calculate the air mass m of the refrigerator according to the volume of the refrigerator:
[0059] m=ρV=1.293kg / m 3 ×0.3m 3 =0.387kg (2)
[0060] In formula (2), the value of standard air density ρ...
Embodiment 2
[0089] see figure 1 , taking the air-cooled refrigerator using the VNX1116Y inverter compressor produced by Gaxibera as an example, the room with the door open is a freezer, and the volume of the freezer is 250L, that is, 0.25m3. The specific steps of the intelligent control method are as follows:
[0090] Step 1: Set the cooling time t of the refrigerator to 300s, and detect the temperature T of the freezer when the refrigerator is running normally 1 For -23°C, the compressor speed R old 3600r / min;
[0091] Step 2: Open the door of the freezer, then close the door, and get the temperature T of the freezer after 10 seconds 2 -10°C.
[0092] Step 3: Calculate the load increase ΔQ caused by opening the freezer door;
[0093] First, calculate the air mass m of the freezer according to the volume of the freezer:
[0094] m=ρV=1.293kg / m 3 ×0.25m 3 =0.32325kg (2)
[0095] In formula (2), the value of standard air density ρ is 1.293kg / m3;
[0096] ΔQ=kcm(T 2 -T 1 )
[009...
Embodiment 3
[0124] see figure 1 , taking the air-cooled refrigerator using the BSA090NJMV inverter compressor produced by LG as an example, the room with the door open is a cold room, and the volume of the cold room is 280L, that is, 0.28m3. The specific steps of the intelligent control method are as follows:
[0125] Step 1: Set the cooling time t of the refrigerator to 120s, and detect the temperature T of the refrigerator compartment when the refrigerator is running normally 1 At 4°C, the compressor speed R old 2400r / min;
[0126] Step 2: Open the door of the refrigerating room, then close the door, and detect the temperature T of the refrigerating room after 10 seconds 2 is 9°C.
[0127] Step 3: Calculate the load increase ΔQ caused by opening the refrigerator door;
[0128] First, calculate the air mass m of the refrigerator according to the volume of the refrigerator:
[0129] m=ρV=1.293kg / m 3 ×0.28m 3 =0.36204kg (2)
[0130] In formula (2), the value of standard air density...
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