Formaldehyde-free light shaving board and preparation method thereof
A particleboard and lightweight technology, applied in the field of lightweight particleboard, fiberboard, and aldehyde-free lightweight man-made panels, can solve the problems that affect the production efficiency and production cost of products, affect the board-making effect on the surface of the board, and uneven distribution of EPS particles, etc. It can improve the efficiency of plate making, facilitate indoor movement, and shorten the time of hot pressing.
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Embodiment 1
[0059]To prepare terephthalic acid modified polyether polyol, the molar ratio of -COOH in terephthalic acid to -OH of polyether polyol is 1:1, and the steps are:
[0060]Add polyether polyols (respectively 50g R2303 or 83.3g R2305 or 116.7gR2307 or 166.7R2310) into the reaction kettle, raise the temperature to 80℃, and slowly add 166.1g terephthalic acid and 0.02g dibutyltin dilaurate. The mixture is heated to 140°C and reacted for 1h. Vacuum at 105°C to an absolute pressure of 90Pa, remove trace moisture, and then obtain terephthalic acid-modified polyether polyol (prepared separately according to the added polyether polyol) Terephthalic acid modified R2303, R2305, R2307 or R2310).
Embodiment 2
[0062]To prepare phthalic acid modified polyether polyol, the molar ratio of -COOH in phthalic acid to -OH of polyether polyol is 1.03:1, the steps are:
[0063]Add polyether polyol (respectively 50g R2303 or 83.3g R2305 or 116.7gR2307 or 166.7R2310) into the reaction kettle, raise the temperature to 80℃, and slowly add 169.5g phthalic acid and 0.01g bis(dodecyl sulfide) ) Dibutyltin, heated to 138℃, reacted for 1.5h, evacuated at 105℃ to 100Pa absolute pressure, and removed trace water, then the phthalic acid modified polyether polyol can be obtained (according to the added polyether polyol) Alcohol was prepared respectively to phthalic acid modified R2303, R2305, R2307 or R2310).
Embodiment 3
[0065]To prepare isophthalic acid modified polyether polyol, the molar ratio of -COOH in isophthalic acid to -OH of polyether polyol is 1.05:1, and the steps are:
[0066]Add polyether polyol (respectively 50g R2303 or 83.3g R2305 or 116.7g R2307 or 166.7g R2310) into the reaction kettle, increase the temperature to 80°C, and slowly add 174.4g isophthalic acid and 0.03g stannous octoate, and increase the temperature to 142℃, react for 0.8h, 103℃ evacuated to 80Pa absolute pressure, remove trace moisture, then isophthalic acid modified polyether polyol can be prepared (isophthalic dihydric alcohol is prepared according to the added polyether polyol) Formic acid modified R2303, R2305, R2307 or R2310).
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