An asymmetric suction scroll compressor profile and design method

Abstract

The application provides a kind of asymmetric suction scroll compressor profile and design method. It includes: the outside profile A (1-1) of static disc vortex circle, inside profile A (1-2), the outside profile B (2-1) of dynamic disc vortex circle, inside profile B (2-2), and asymmetric three circular arc tooth head correction profile;Asymmetric three circular arc tooth head correction profile includes: three circular arc tooth head correction profile A that connects outside, inside profile A at static disc vortex circle tooth head, and three circular arc tooth head correction profile B that connects outside, inside profile B at dynamic disc vortex circle tooth head;The profile of dynamic disc vortex circle and static disc vortex circle encloses a pair of compression cavities V 1、 V 2With the same content volume ratio, the suction volume S1 of compression cavity V 1≠The suction volume S2 of compression cavity V 2, the exhaust volume D1 of compression cavity V 1≠The exhaust volume D2 of compression cavity V 2.The application can make a pair of compression cavities when communicating, the pressure of both is same, no irreversible loss is generated, at the same time, it ensures that no residual volume is generated, and the pressure ratio of compressor is improved.

Description

Technical Field

[0001] This invention belongs to the field of scroll compressor technology, and specifically relates to an asymmetric suction scroll compressor profile and design method. Background Technology

[0002] With the application of scroll compressors in mobile machinery such as new energy vehicles and electric aircraft, scroll compressors are developing towards miniaturization and high speed. To improve the space utilization of the compressor, the rotation angle of the stationary scroll is often increased by a certain angle, generally not exceeding 180°. This design can increase the suction volume of the scroll compressor, make full use of the scroll space, and at the same time bring the suction positions of the two suction chambers of the scroll closer together, reducing suction overheating. However, the asymmetrical suction results in a different volume ratio between the two compression chambers of the compressor. Therefore, at the beginning of exhaust, the two compression chambers are connected, and the mixing of working fluids with different pressures leads to large pressure pulsations, resulting in irreversible losses and reduced compressor efficiency. To improve the asymmetry of working fluid pressure in the compression chambers at the beginning of exhaust and the moment of working fluid mixing, the teeth of the scroll are often modified (including direct truncation and asymmetric double-circular arc tooth modification methods, etc.), so that the high-pressure chamber connects to the compressor center chamber before the low-pressure chamber, so that when the two compression chambers are connected, the pressures are the same or similar, reducing irreversible losses.

[0003] However, current tooth correction methods inevitably result in a large clearance volume. The existence of clearance volume not only reduces the utilization rate of the scroll area, but also, with the current trend of miniaturization of scroll compressors, the internal pressure ratio of the compressor is usually much smaller than its external pressure ratio. Therefore, the existence of a large clearance volume will cause the high-pressure gas in the clearance volume to mix with the low-pressure gas in the compression chamber, resulting in irreversible losses.

[0004] In summary, during the exhaust process of asymmetric intake scroll compressors, pressure pulsations caused by mixing in the symmetric compression chamber result in irreversible losses, and current tooth correction methods cause a large clearance volume. Summary of the Invention

[0005] This invention addresses the problems of irreversible losses caused by existing asymmetric intake and large clearance volumes resulting from existing tooth correction methods. It proposes an asymmetric intake scroll compressor profile and design method. This invention ensures that when a pair of compression chambers are connected, the pressures are identical, preventing irreversible losses, eliminating clearance volumes, and improving the compressor's pressure ratio.

[0006] Technical solution. An asymmetric intake scroll compressor profile, comprising: an outer profile A and an inner profile A of the stationary scroll ring, an outer profile B and an inner profile B of the moving scroll ring, and an asymmetric three-circular-arc tooth head correction profile; The asymmetric three-circular-arc tooth head correction profile includes: a three-circular-arc tooth head correction profile A connecting the outer and inner profiles A at the stationary disk volute tooth head, and a three-circular-arc tooth head correction profile B connecting the outer and inner profiles B at the moving disk volute tooth head. A pair of compression chambers enclosed by the profiles of the moving and stationary disk vortices V 1. V 2. With the same internal volume ratio, the compression chamber V The intake volume S1 is not equal to the compression chamber. V The intake volume S2 is 2, and the compression chamber is 2. V The exhaust volume D1 is not equal to the compression chamber. V The exhaust volume D2 is 2.

[0007] In the aforementioned asymmetric intake scroll compressor profile, the three-circular-arc tooth head correction profile A includes: a correction angle of... β The correction angle for the outer arc A of tooth 2 is 2. β The inner arc A of the tooth is 1+π, and the middle arc A of the tooth connects the outer and inner arcs A; The outer and inner arcs A of the tooth are internally tangent to the outer and inner profile lines A, respectively; the middle arc A of the tooth is internally tangent to the outer arc A and externally tangent to the inner arc A. β 2≠ β 1.

[0008] In the aforementioned asymmetric intake scroll compressor profile, the three-circular-arc tooth head correction profile B includes: a correction angle of... β The outer arc B of tooth 1 has a correction angle of 1. β The inner arc B of the tooth is 2+π, and the middle arc B of the tooth connects the outer and inner arcs B; The outer and inner arcs B of the tooth are respectively tangent to the outer and inner profile lines B; the middle arc B of the tooth is tangent to the outer arc B and tangent to the inner arc B. β 2≠ β 1.

[0009] In the aforementioned asymmetric intake scroll compressor profile, the outer arc B meshes with the inner arc A; the middle arc B meshes with the middle arc A; and the inner arc B meshes with the outer arc A. The absolute value of the difference between the radii of the meshing arcs is the rotation radius of the moving disc.

[0010] The aforementioned design method for the profile of an asymmetric intake scroll compressor comprises the following steps: S1. Generates the inner and outer profiles of the dynamic and static disk vortex rings; S2. Based on S1, perform tooth head correction by adding arcs and straight lines to obtain: stationary disk connecting arc, stationary disk straight line segment, stationary disk correction arc, moving disk connecting arc, moving disk straight line segment, and moving disk correction arc. S3. Based on S2, perform asymmetric three-circle correction to obtain: tooth outer circle A, tooth middle circle A, tooth inner circle A, tooth outer circle B, tooth middle circle B, and tooth inner circle B.

[0011] S1 is as follows: Initially set the pitch of the dynamic and static disk vortex profiles. P t Wall thickness t Number of static disc rotations m 1. Number of rotations of the moving disc m 2 and expected content product ratio BIVR 0; corresponding to the calculation of the compression chamber V 1. V 2's product ratio BIVR 1. BIVR 2; will BIVR 1 is used as a design standard, if BIVR 1= BIVR 0, implement S2; if BIVR 1≠ BIVR 0, Adjustment P t , m 1. m 2 and t Until the two are equal.

[0012] S2 is as follows: Input the initially set correction angle. β 1 and radial correction amount Δr The equations for the connecting arcs of the moving and stationary disks, the straight segments of the moving and stationary disks, the corrected arcs of the moving and stationary disks, and the inner and outer profile parameters of the vortex rings of the moving and stationary disks are obtained. The main parameters include the radius of the connecting arcs. r Correcting the radius of the arc R Intersection of a straight line segment and a modified circular arc P 1. The intersection of the straight line segment and the connecting arc P 2; Calculation BIVR 1; if BIVR 1= BIVR If 0, then S3 is executed; otherwise, for β 1. Δr , m 1 and m 2. Adjustments were made, and the profile parameter equations and the aforementioned... BIVR 1. Perform calculations until... BIVR 1= BIVR 0; where the static disk R , r and intersection P 1. P The formula for calculating the coordinates is as follows (1): (1) In the formula, a —Base circle radius;α —The initial angle of the involute of a circle; β 1—Correction angle; r — Rotation radius of the moving disc; r 0、 R 0、 d 0 — Intermediate calculation geometric parameters; r— Connect the radius of the arc; R —Correct the radius of the arc; d —Intermediate calculation of geometric parameters; c —The angle between the counterclockwise rotation of the positive X-axis and the line connecting the center of the correction arc and the center of the connecting arc; P 1x —Intersection of the straight line segment and the modified circular arc P The X coordinate of 1; P 1y —Intersection of the straight line segment and the modified circular arc P The Y-coordinate of 1; P 2x —Intersection of the straight segment and the connecting arc P The X coordinate of 2; P 2y —Intersection of the straight segment and the connecting arc P The Y-coordinate of 2; In a scroll compressor, the profile of the moving disc is obtained by rotating the profile of the stationary disc by 180°. Therefore, the above parameter calculations are applicable to both the moving and stationary discs.

[0013] After S2 is completed, V The area of ​​the inspiratory chamber of 1 is S 1, V The area of ​​the inhalation chamber of 2 is S 2; V The exhaust chamber area of ​​1 is D 1, V The exhaust chamber area of ​​2 is D 2; BIVR 1= S 1 / D 1, BIVR 2= S 2 / D 2, S 1> S 2 and D 1= D 2, BIVR 1> BIVR 2.

[0014] S3 is as follows: The stationary disc correction arc is taken as the tooth inner arc A after asymmetric three-arc correction; with... P Point 1 is the intersection point. Draw an externally tangent correction arc to the stationary disk, with a radius equal to the radius of the connecting arc of the stationary disk. r The arc is taken as the arc A in the tooth; the correction angle is initially selected. β2; The correction angle of the profile on the outer side of the stationary plate is... β Draw an arc inscribed in the outer profile A at point 2, which is the outer arc A of the tooth, and ensure that the middle arc A of the tooth is inscribed in the outer arc A of the tooth. Connect the moving disc to the outer arc B of the circular arc tooth; P Point 2 is the intersection point. Draw an external arc tangent to the moving disk, with a radius equal to the radius of the moving disk's correction arc. R The arc is taken as the arc B in the tooth; based on the initially selected correction angle. β 2. The correction angle of the profile inside the moving plate is... β Draw an arc inscribed in the inner profile B at the point of 2+π, which is the inner arc B of the tooth, and ensure that the arc B in the middle of the tooth is inscribed in the inner arc B of the tooth. After the asymmetric three-circle arc tooth head correction is completed, the calculation is performed. V 2's product ratio BIVR 2, if BIVR 2= BIVR If the value is 0, the calculation ends; otherwise, adjust. β 2. Re-correct the profile using the three-circle tooth head until... BIVR 2= BIVR 0; where BIVR 2= BIVR 1= BIVR 0.

[0015] Beneficial effects: This invention addresses the problems of irreversible losses caused by existing asymmetric intake and large clearance volumes caused by existing tooth correction. It proposes an asymmetric intake scroll compressor profile and design method to ensure adaptability to compressor installation conditions, rational use of space, and increased intake volume. Secondly, it ensures that the pressure of a pair of compression chambers is the same when they are connected, without generating irreversible losses. At the same time, it ensures that no clearance volume is generated and improves the compressor's pressure ratio. Attached Figure Description

[0016] To more clearly illustrate the technical solutions in the embodiments of the present invention or the prior art, the drawings used in the description of the embodiments or the prior art will be briefly introduced below. The drawings described below are only some embodiments of the present invention. For those skilled in the art, other drawings can be obtained based on these drawings without creative effort.

[0017] Figure 1 Flowchart of profile design for this invention; Figure 2 The profile of the stationary disc tooth head after the second step of this invention is completed; Figure 3 A schematic diagram of the larger intake volume cross-sectional area after the second step of the present invention; Figure 4 A schematic diagram of the smaller intake volume cross-sectional area after the second step of the present invention; Figure 5 A schematic diagram of the cross-sectional area of ​​a pair of exhaust chambers after the second step of the present invention is completed; Figure 6 A schematic diagram of the correction of the three circular arc tooth head of the stationary disk after the third step of the present invention; Figure 7 A schematic diagram of the three-circular-arc tooth head correction profile B after the third step of the present invention; Figure 8 A schematic diagram illustrating the modified meshing relationship of the three-circular-arc tooth head of this invention; Figure 9 A schematic diagram of the cross-sectional area of ​​a pair of exhaust chambers after the third step of this invention is completed; Figure 10 Another line design flowchart of the present invention.

[0018] In the attached diagram: S1—Inner intake chamber of stationary disc; S2—Inner intake chamber of moving disc; D1—Inner exhaust chamber of stationary disc; D2—Inner exhaust chamber of moving disc; D3—Inner exhaust chamber of stationary disc after three-circle tooth head correction; D4—Inner exhaust chamber of moving disc after three-circle tooth head correction; 1-1—Outer profile A; 1-2—Inner profile A; 1-3-1—Connecting arc of stationary disc; 1-3-2—Straight line segment of stationary disc; 1-3-3—Corrected arc of stationary disc; 1-4-1—Outer arc of tooth A; 1-4-2—Inner arc of tooth A; 1-4-3—Inner arc of tooth A; 2-3-1—Connecting arc of moving disc; 2-3-2—Straight line segment of moving disc; 2-3-3—Corrected arc of moving disc; 2-4-1—Outer arc of tooth B; 2-4-2—Inner arc of tooth B; 2-4-3—Inner arc of tooth B. Detailed Implementation

[0019] To make the objectives, technical solutions, and advantages of the embodiments of the present invention clearer, the technical solutions of the embodiments of the present invention will be clearly and completely described below with reference to the accompanying drawings. Obviously, the described embodiments are only some embodiments of the present invention, not all embodiments. Based on the embodiments of the present invention, all other embodiments obtained by those skilled in the art without creative effort are within the scope of protection of the present invention.

[0020] The features and illustrative embodiments of various aspects of the present invention will now be described in detail. Numerous specific details are set forth in the following detailed description to provide a thorough understanding of the invention. However, it will be apparent to those skilled in the art that the invention may be practiced without requiring some of these specific details. The following description of embodiments is merely intended to provide a better understanding of the invention by illustrating examples of the invention. The invention is by no means limited to any specific setups and methods set forth below, but covers any improvements, substitutions, and modifications to structures, methods, and devices without departing from the spirit of the invention. Well-known structures and techniques are not shown in the drawings and the following description to avoid unnecessarily obscuring the invention.

[0021] In the description of this invention, it should be noted that the directions or positional relationships indicated by terms such as "center," "upper," "lower," "left," "right," "vertical," "horizontal," "inner," and "outer" are based on the directions or positional relationships shown in the accompanying drawings and are only for the convenience of describing and simplifying the invention, and should not be construed as limiting the invention. Furthermore, the use of ordinal numbers (e.g., "first and second," etc.) is for distinguishing objects and is not limited to this order, and should not be construed as indicating or implying relative importance.

[0022] In the description of this invention, it should be noted that, unless otherwise explicitly specified and limited, the terms "installation," "connection," and "linking" should be interpreted broadly, encompassing both direct connection and indirect connection via an intermediate medium. Those skilled in the art can understand the specific meaning of these terms in this invention based on the specific circumstances.

[0023] It should be noted that, unless otherwise specified, the embodiments of the present invention and the features thereof can be combined with each other, and the various embodiments can be referenced and cited in each other. The present invention will now be described in detail with reference to the accompanying drawings and embodiments.

[0024] The present invention will be further described in detail below with reference to the embodiments and accompanying drawings, but the embodiments of the present invention are not limited thereto.

[0025] Example 1. An asymmetric intake scroll compressor profile, see [reference needed]. Figure 1-Figure 10 This includes: the outer profile A1-1 and inner profile A1-2 of the stationary disk vortex, the outer profile B2-1 and inner profile B2-2 of the moving disk vortex, and the asymmetric three-circular-arc tooth head correction profile; The asymmetric three-circular-arc tooth head correction profile includes: a three-circular-arc tooth head correction profile A connecting the outer and inner profiles A at the stationary disk volute tooth head, and a three-circular-arc tooth head correction profile B connecting the outer and inner profiles B at the moving disk volute tooth head. A pair of compression chambers enclosed by the profiles of the moving and stationary disk vortices V1. V 2. With the same internal volume ratio, the compression chamber V The intake volume S1 is not equal to the compression chamber. V The intake volume S2 is 2, and the compression chamber is 2. V The exhaust volume D1 is not equal to the compression chamber. V The exhaust volume D2 is 2.

[0026] The aforementioned three-circle-arc tooth head correction profile A includes: a correction angle of... β The external arc of tooth 2, A1-4-1, has a correction angle of . β The inner arc of the tooth is A1-4-3 with a radius of 1+π, and the middle arc of the tooth is A1-4-2 connecting the outer and inner arcs A. The outer and inner arcs A of the tooth are internally tangent to the outer and inner profile lines A, respectively; the middle arc A1-4-2 of the tooth is internally tangent to the outer arc A1-4-1 and externally tangent to the inner arc A1-4-3, respectively. β 2≠ β 1.

[0027] The aforementioned three-circle arc tooth head correction profile B includes: a correction angle of... β The external arc of tooth 1, B2-4-1, has a correction angle of... β The inner arc of the tooth is B2-4-3 with a radius of 2+π, and the middle arc of the tooth is B2-4-2 connecting the outer and inner arcs B. The outer and inner arcs B of the tooth are respectively tangent to the outer and inner profile lines B; the middle arc B2-4-2 of the tooth is tangent to the outer arc B2-4-1 and tangent to the inner arc B2-4-3. β 2≠ β 1.

[0028] The aforementioned external arc B2-4-1 meshes with the internal arc A1-4-3; the middle arc B2-4-2 meshes with the middle arc A1-4-2; the internal arc B2-4-3 meshes with the external arc A1-4-1; the absolute value of the difference between the radii of the meshing arcs is the rotation radius of the moving disc.

[0029] The aforementioned design method for the profile of an asymmetric intake scroll compressor comprises the following steps: S1. Generates the inner and outer profiles of the dynamic and static disk vortex rings; S2. Based on S1, perform tooth head correction by adding arcs and straight lines to obtain: stationary disk connecting arc 1-3-1, stationary disk straight line segment 1-3-2, stationary disk correction arc 1-3-3, moving disk connecting arc 2-3-1, moving disk straight line segment 2-3-2, moving disk correction arc 2-3-3. S3. Based on S2, perform asymmetric three-circle correction to obtain: external arc A1-4-1, middle arc A1-4-2, internal arc A1-4-3, external arc B2-4-1, middle arc B2-4-2, and internal arc B2-4-3.

[0030] The aforementioned S1 is as follows: initially setting the pitch of the vortex profiles of the moving and stationary disks. P t Wall thickness t Number of static disc rotations m 1. Number of rotations of the moving disc m 2 and expected content product ratio BIVR 0; corresponding to the calculation of the compression chamber V 1. V 2's product ratio BIVR 1. BIVR 2; will BIVR 1 is used as a design standard, if BIVR 1= BIVR 0, implement S2; if BIVR 1≠ BIVR 0, Adjustment P t , m 1. m 2 and t Until the two are equal.

[0031] The aforementioned S2 is as follows: Input the initially set correction angle. β 1 and radial correction amount Δr The equations for the connecting arcs of the moving and stationary disks, the straight segments of the moving and stationary disks, the corrected arcs of the moving and stationary disks, and the inner and outer profile parameters of the vortex rings of the moving and stationary disks are obtained. The main parameters include the radius of the connecting arcs. r Correcting the radius of the arc R Intersection of a straight line segment and a modified circular arc P 1. The intersection of the straight line segment and the connecting arc P 2; Calculation BIVR 1; if BIVR 1= BIVR If 0, then S3 is executed; otherwise, for β 1. Δr , m 1 and m 2. Adjustments were made, and the profile parameter equations and the aforementioned... BIVR 1. Perform calculations until... BIVR 1= BIVR 0; where the static disk R , r and intersection P 1. P The formula for calculating the coordinates is as shown in equation (1): (1) In the formula, a —Base circle radius; α —The initial angle of the involute of a circle; β 1—Correction angle; r — Rotation radius of the moving disc; r 0、 R 0、 d 0 — Intermediate calculation geometric parameters; r— Connect the radius of the arc; R —Correct the radius of the arc; d —Intermediate calculation of geometric parameters; c —The angle between the counterclockwise rotation of the positive X-axis and the line connecting the center of the correction arc and the center of the connecting arc; P 1x —Intersection of the straight line segment and the modified circular arc P The X coordinate of 1; P 1y —Intersection of the straight line segment and the modified circular arc P The Y-coordinate of 1; P 2x —Intersection of the straight segment and the connecting arc P The X coordinate of 2; P 2y —Intersection of the straight segment and the connecting arc P The Y-coordinate of 2; In a scroll compressor, the profile of the moving disc is obtained by rotating the profile of the stationary disc by 180°. Therefore, the above parameter calculations are applicable to both the moving and stationary discs.

[0032] After S2 is completed, V The area of ​​the inspiratory chamber of 1 is S 1, V The area of ​​the inhalation chamber of 2 is S 2; V The exhaust chamber area of ​​1 is D 1, V The exhaust chamber area of ​​2 is D 2; BIVR 1= S 1 / D 1, BIVR 2= S 2 / D 2, S 1> S 2 and D 1= D 2, BIVR 1> BIVR 2.

[0033] The aforementioned S3 is as follows: The stationary disc correction arc 1-3-3 is taken as the asymmetric three-arc correction internal tooth arc A1-4-3; with... PPoint 1 is the intersection point. Draw an externally tangent arc 1-3-3 to the stationary disk, with a radius equal to the radius of the connecting arc 1-3-1 on the stationary disk. r The arc is taken as the tooth mid-circle arc A1-4-2; the correction angle is initially selected. β 2; The correction angle of the profile on the outer side of the stationary plate is... β Draw an arc inscribed in the outer profile A1-1 at point 2, which is the outer arc A1-4-1 of the tooth, and ensure that the middle arc A1-4-2 of the tooth is inscribed in the outer arc A1-4-1; Connect the moving disc to the outer arc of the 2-3-1 toothed circular arc B2-4-1; with P Point 2 is the intersection point. Draw an externally tangent arc 2-3-1 to the moving disk, with a radius equal to the radius of the corrected arc 2-3-3 of the moving disk. R The arc, as the tooth center arc B2-4-2; based on the initially selected correction angle β 2. The correction angle of the profile inside the moving plate is... β Draw an arc inscribed in the inner profile B2-2 at the point of 2+π as the inner arc B2-4-3 of the tooth, and ensure that the inner arc B2-4-2 of the tooth is inscribed in the inner arc B2-4-3 of the tooth. After the asymmetric three-circle arc tooth head correction is completed, the calculation is performed. V 2's product ratio BIVR 2, if BIVR 2= BIVR If the value is 0, the calculation ends; otherwise, adjust. β 2. Re-correct the profile using the three-circle tooth head until... BIVR 2= BIVR 0; where BIVR 2= BIVR 1= BIVR 0.

[0034] The compressor designed using this profile design method ensures that, under limited installation conditions, it makes reasonable use of space, increases the intake volume, and ensures that the pressure in the two chambers is the same when they are connected, thus avoiding or reducing irreversible losses. At the same time, it ensures that there is no clearance volume in the meshing of the moving and stationary discs, improves the utilization rate of the scroll area, and avoids irreversible losses caused by clearance volume.

[0035] Example 2. An asymmetric intake scroll compressor profile and design method, see [link to example]. Figure 1-Figure 10 The profile of the asymmetric intake scroll compressor includes the inner and outer profiles of the stationary disk scroll ring, the inner and outer profiles of the moving disk scroll ring, and the asymmetric three-circular-arc tooth head correction profile. The inner and outer profiles of the stationary disk scroll ring are involutes of circles, and the different starting angles of the involutes form scroll rings of a certain thickness; the phase angle between the moving disk profile and the stationary disk profile is 180°; the inner profile of the stationary disk meshes with the outer profile of the moving disk, and the inner profile of the moving disk meshes with the outer profile of the stationary disk, forming a pair of compression chambers; The asymmetric three-circular-arc tooth head correction profile includes a stationary disk three-circular-arc tooth head correction and a three-circular-arc tooth head correction profile B; the stationary disk three-circular-arc tooth head correction includes a correction angle of... β 2. Outer arc of the tooth and β 1+π inner arc of the tooth; the outer arc of the tooth is internally tangent to the outer profile of the stationary disk; the inner arc of the tooth is internally tangent to the inner profile of the stationary disk; the middle arc of the stationary disk tooth is internally tangent to the outer arc of the stationary disk tooth, and simultaneously externally tangent to the inner arc of the tooth; the correction angle β 2≠ β 1; The three-circular arc tooth head correction profile B includes a correction angle of... β 1. Outer arc of the tooth and β 2+π inner arc of the tooth; the outer arc of the tooth is internally tangent to the outer profile of the moving disk; the inner arc of the tooth is internally tangent to the inner profile of the moving disk; the middle arc of the stationary disk tooth is externally tangent to the outer arc of the moving disk tooth, and simultaneously internally tangent to the inner arc of the moving disk tooth; the correction angle β 2≠ β 1; The outer arc of the moving disk teeth meshes with the inner arc of the stationary disk teeth, the middle arc of the moving disk teeth meshes with the middle arc of the stationary disk teeth, and the inner arc of the moving disk teeth meshes with the outer arc of the stationary disk teeth. The absolute value of the difference between the radii of the meshing arcs is the radius of rotation of the moving disk.

[0036] Furthermore, the present invention proposes two preferred profile design methods, the design methods being as follows: The first aspect of this invention is: In asymmetric intake scroll compressors, the typical number of scroll turns on the stationary disc is... m 1. Number of rotations of the moving disk vortex m The difference is between -0.5 and 0.5. m 1≠ m 2.

[0037] remember BIVR 1 is the compression cavity formed by the meshing of the inner profile of the stationary disk vortex and the outer profile of the moving disk vortex. V The internal volume ratio of 1 is the ratio of the intake volume to the exhaust volume of the compression chamber. BIVR 2 is the compression cavity formed by the meshing of the inner profile of the moving disk vortex and the outer profile of the stationary disk vortex. V The volume ratio of 2 is the ratio of the intake volume to the exhaust volume of the compression chamber.

[0038] The first aspect of the present invention comprises three steps: the first step generates the inner and outer profiles of the moving and stationary disk vortex rings; the second step, based on the first step, performs tooth head correction by adding arcs and straight lines to obtain the moving and stationary disk modified connecting arc, straight line segment, modified arc, and the corrected inner and outer profiles of the moving and stationary disk vortex rings; the third step, based on the second step, performs asymmetric three-arc correction to obtain the outer arc, middle arc, inner arc, and inner and outer profiles of the moving and stationary disk vortex rings.

[0039] In the first step, preferably, the pitch of the initially set vortex profile of the moving and stationary disks is first input. P t Wall thickness t Number of static disc rotations m 1. Number of rotations of the moving disc m 2. And the required content volume ratio in the design. BIVR 0; Calculate the compression chamber V 1 and V 2's product ratio BIVR 1 and BIVR 2; Preferred BIVR 1 is used as a design standard to judge BIVR 1. Whether or not it is related to BIVR If 0 is equal, proceed to step two; otherwise, adjust. P t , m 1. m 2 and t Then, re-enter the data, and recalculate and judge it. BIVR 1. Whether or not it is related to BIVR 0 equals; until the two are equal, proceed to the second step.

[0040] The second step, based on the first step, involves correcting the inner and outer profiles of the moving and stationary disk volutes by adding circular arcs and straight lines to the tooth tips; inputting the initially set correction angle. β 1 and Δr The equations for the connecting arc, straight line segment, modified arc, and inner and outer profiles of the vortex rings of the moving and stationary disks are obtained. The main parameters include the radius of the connecting arc. r Correcting the radius of the arc R Intersection of a straight line segment and a modified circular arc P 1. The intersection of the straight line segment and the connecting arc P 2, and calculate at this time BIVR 1; if BIVR 1. Expectations BIVR If they are equal to 0, proceed to step three; otherwise, proceed to... β 1. Δr , m 1 and m 2. Make adjustments ( m 1 and m 2. The first step should be followed to ensure...m 1 and m (The difference between 2 and 3 remains unchanged), and the parametric equations of the profile are re-evaluated. BIVR 1. Perform calculations until... BIVR 1= BIVR 0. After completing the second step, proceed to the third step. The static disk... R , r and intersection P 1. P The formula for calculating the coordinates is shown in formula (1) below: (1) In the formula, a —Base circle radius; α —The initial angle of the involute of a circle; β 1—Correction angle; r — Rotation radius of the moving disc; r 0、 R 0、 d 0 — Intermediate calculation geometric parameters; r— Connect the radius of the arc; R —Correct the radius of the arc; d —Intermediate calculation of geometric parameters; c —The angle between the counterclockwise rotation of the positive X-axis and the line connecting the center of the correction arc and the center of the connecting arc; P 1x —Intersection of the straight line segment and the modified circular arc P The X coordinate of 1; P 1y —Intersection of the straight line segment and the modified circular arc P The Y-coordinate of 1; P 2x —Intersection of the straight segment and the connecting arc P The X coordinate of 2; P 2y —Intersection of the straight segment and the connecting arc P The Y-coordinate of 2. In a scroll compressor, the profile of the moving disc can be obtained by rotating the profile of the stationary disc by 180°, therefore the above parameter calculations are applicable to both the moving and stationary discs.

[0041] After the second step is completed, the V The area of ​​the inspiratory chamber of 1 is S 1, the aforementioned V The area of ​​the inhalation chamber of 2 is S 2; V The exhaust chamber area of ​​1 is D 1, V The exhaust chamber area of ​​2 is D 2; BIVR 1= S 1 / D 1, BIVR 2=S 2 / D 2. At this time, due to S 1> S 2 and D 1= D 2, therefore BIVR 1> BIVR 2. This causes pressure loss due to the mixing of working fluids at different pressures when the compression ends and the exhaust begins.

[0042] The third step involves performing asymmetric three-circle arc correction on the moving and stationary disk volute teeth based on the second step. First, the stationary disk correction arc is taken as the inner circle of the stationary disk teeth after the asymmetric three-circle arc correction. Further, using the aforementioned... P Point 1 is the intersection point. Draw a corrected arc tangent to the stationary disk, with a radius equal to the radius of the connecting arc. r The arc is the tooth-center arc of the stationary disc after the asymmetric three-circle correction; the correction angle is initially selected. β 2; The correction angle of the profile on the outer side of the stationary disc is β Point 2 is used to construct an arc internally tangent to the outer profile of the stationary disk. This arc is the outer arc of the stationary disk tooth after the asymmetric three-arc correction. Furthermore, the middle arc of the stationary disk tooth is required to be internally tangent to the outer arc. Thus, the asymmetric three-arc corrected tooth profile of the stationary disk is obtained, including the outer arc profile, the middle arc profile, and the inner arc profile.

[0043] Furthermore, the moving disk undergoes asymmetric three-circle arc correction. First, the connecting arc serves as the outer circular arc of the moving disk teeth after asymmetric three-circle arc correction; furthermore, based on the aforementioned... P Point 2 is the intersection point. Draw an external arc tangent to the moving disk connecting arc, with a radius equal to the radius of the moving disk's modified arc. R The arc, which is the arc in the teeth of the moving plate after the asymmetric three-arc correction; based on the initially selected correction angle β 2. The correction angle of the profile inside the moving disk is... β A point of 2+π is used to construct an arc internally tangent to the inner profile of the moving disk. This arc is the inner arc of the moving disk tooth after the asymmetric three-arc correction. Furthermore, the middle arc of the moving disk tooth is required to be internally tangent to the inner arc of the moving disk tooth. Thus, the asymmetric three-arc corrected tooth profile of the moving disk is obtained, including the outer arc profile, the middle arc profile, and the inner arc profile of the moving disk tooth.

[0044] At this point, the outer arc of the moving disc teeth meshes with the inner arc of the stationary disc teeth, the middle arc of the moving disc teeth meshes with the middle arc of the stationary disc teeth, and the inner arc of the moving disc teeth meshes with the outer arc of the stationary disc teeth. The absolute value of the difference between the radii of the meshing arcs is the radius of rotation of the moving disc, thus satisfying the meshing condition.

[0045] After the asymmetric three-circle arc tooth head correction is completed, further calculations are performed. V 2's product ratio BIVR2, if BIVR 2 and expectations BIVR If the values ​​are equal to 0, the calculation ends; otherwise, adjust. β 2. Re-correct the profile with three circular arc tooth tips and... BIVR 2. Perform calculations until... BIVR 2= BIVR 0, calculation complete. At this point, BIVR 2= BIVR 1= BIVR At 0, when compression ends and exhaust begins, the pressure in both exhaust chambers is the same, avoiding irreversible losses; and the moving and stationary discs are always engaged, with no clearance volume; in addition, the compressor pressure ratio is increased.

[0046] The second aspect of the present invention is The second aspect of the present invention comprises four steps: the first step generates the inner and outer profiles of the stationary and moving disk vortex rings; the second step, based on the first step, modifies the inner profile of the stationary disk and the outer profile of the moving disk to obtain the inner arc of the stationary disk teeth and the outer arc of the moving disk teeth; the third step, based on the second step, modifies the outer profile of the stationary disk and the inner profile of the moving disk to obtain the outer arc of the stationary disk teeth and the inner arc of the moving disk teeth; the fourth step, based on the tangency and meshing relationship and the expected internal volume ratio... BIVR 0. The circular arcs in the stationary disc teeth and the circular arcs in the moving disc teeth are obtained.

[0047] In the first step, preferably, the pitch of the initially set vortex profile of the moving and stationary disks is first input. P t Wall thickness t Number of static disc rotations m 1. Number of rotations of the moving disc m 2 and the expected content volume ratio BIVR 0; Calculate the compression chamber V 1 and V 2's product ratio BIVR 1 and BIVR 2; Preferred BIVR 1 is used as a design standard to judge BIVR 1. Whether or not it is related to BIVR If 0 is equal, proceed to step two; otherwise, adjust. P t , m 1. m 2 and t Then, re-enter the data, and recalculate and judge it. BIVR 1. Whether or not it is related to BIVR 0 equals; until the two are equal, proceed to the second step.

[0048] The second step involves inputting the initially set correction angle. β 1 and Δr According to Formula 1, calculate the corrected radius of the arc ( R and the radius of the connecting arc r The development angle of the profile inside the stationary disk is... β A line is drawn at point 1+π, internally tangent to the inner side profile of the stationary disk, with a radius of... R The arc is the inner arc of the stationary disc teeth; simultaneously, the development angle of the profile on the outer side of the moving disc is... β 1. Make a point internally tangent to the profile with a radius of . r The arc is the outer arc of the moving disc tooth.

[0049] The third step involves inputting the initially set second correction angle. β 2 and Δr 2; In formula 1 β 1 replaced with β 2. Calculate the second corrected arc radius ( R 2) The radius of the second connecting arc ( r 2) The development angle of the outer profile of the stationary disk is β Two points are made internally tangent to the outer profile of the stationary disk with a radius of [missing information]. r The arc of 2 is the outer arc of the stationary disc tooth; at the same time, the development angle of the profile on the inner side of the moving disc is... β Draw a line inscribed in the shape at point 2+π with a radius of π. R The arc of 2 is the inner arc of the moving disc tooth.

[0050] The fourth step, firstly, involves making a radius of... r The arc tangent to the inner arc of the stationary disc tooth and the arc tangent to the outer arc of the stationary disc tooth are the middle arc of the stationary disc tooth; simultaneously, a radius of... R The arc tangent to the outer arc of the moving disk teeth and inscribed in the inner arc of the moving disk teeth is the middle arc of the moving disk teeth; further, the compression cavity is calculated. V 1 content product ratio BIVR 1, and the expected internal pressure ratio BIVR Compare with 0; if they are equal, proceed to the next step; otherwise, check the values. β 1. Δr , m 1 and m 2. Adjustments were made, and the equations for the profile parameters were re-evaluated. BIVR 1. Perform calculations until... BIVR 1= BIVR 0; further, calculate V 2 and BIVR 2, and the expected internal pressure ratio BIVR The operation is compared to 0; if they are equal, the calculation ends; otherwise, the operation continues. β 2 and Δr 2. Adjustments were made, and the equations for the profile parameters were re-evaluated. BIVR2. Perform calculations until... BIVR 2= BIVR 0, end the operation.

[0051] The outer arc of the moving disc teeth meshes with the inner arc of the stationary disc teeth; the middle arc of the moving disc teeth meshes with the middle arc of the stationary disc teeth; and the inner arc of the moving disc teeth meshes with the outer arc of the stationary disc teeth. The absolute value of the difference between the radii of the meshing arcs is the radius of rotation of the moving disc, thus satisfying the meshing condition. At this time, BIVR 2= BIVR 1= BIVR At 0, when compression ends and exhaust begins, the pressure in both exhaust chambers is the same, avoiding irreversible losses; and the moving and stationary discs are always engaged, with no clearance volume; in addition, the compressor pressure ratio is increased.

[0052] Compared to existing technologies, the compressor designed by this invention using this profile design method ensures that, under limited installation conditions, it makes reasonable use of space, increases the intake volume, and ensures that the pressure in the two chambers is the same when they are connected, thus avoiding or reducing irreversible losses; in addition, the moving and stationary discs are always engaged, and there is no clearance volume; furthermore, it improves the compressor's pressure ratio.

[0053] Example 3. An asymmetric intake scroll compressor profile and design method, see [link to example]. Figure 1-Figure 10 The profile of the asymmetric intake scroll compressor includes: the outer profile A1-1 and inner profile A1-2 of the stationary scroll, the outer profile B2-1 and inner profile B2-2 of the moving scroll, and the asymmetric three-circular-arc tooth head correction profile; the asymmetric three-circular-arc tooth head correction profile includes: the three-circular-arc tooth head correction profile A connecting the outer and inner profiles A at the tooth head of the stationary scroll, and the three-circular-arc tooth head correction profile B connecting the outer and inner profiles B at the tooth head of the moving scroll; the profiles of the moving and stationary scrolls enclose a pair of compression chambers. V 1. V 2. Having the same content volume ratio ( BIVR 1= BIVR 2) Compression chamber V The intake volume S1 is not equal to the compression chamber. V The intake volume S2 is 2, and the compression chamber is 2. V The exhaust volume D1 is not equal to the compression chamber. V The exhaust volume D2 is 2.

[0054] The three-circular arc tooth head correction profile A includes a correction angle of... β The outer arc A1-4-1 of tooth 2 and the correction angle are: β1+π inner arc A1-4-3; the outer arc A1-4-1 is internally tangent to the outer profile A1-1; the inner arc A1-4-3 is internally tangent to the inner profile A1-2; the middle arc A1-4-2 is internally tangent to the outer arc A1-4-1 and externally tangent to the inner arc A1-4-3; the correction angle β 2≠ β 1.

[0055] The three-circular arc tooth head correction profile B includes a correction angle of... β 1. External arc of tooth B2-4-1 and β 2+π inner arc B2-4-3; the outer arc B2-4-1 is internally tangent to the outer profile B2-1; the inner arc B2-4-3 is internally tangent to the inner profile B2-2 of the moving disk; the middle arc B2-4-2 of the moving disk tooth is externally tangent to the outer arc B2-4-1, and simultaneously internally tangent to the inner arc B2-4-3 of the moving disk tooth; the correction angle β 2≠ β 1.

[0056] The outer arc B2-4-1 of the tooth meshes with the inner arc A1-4-3 of the tooth; the middle arc B2-4-2 of the moving disc tooth meshes with the middle arc A1-4-2 of the tooth; the inner arc B2-4-3 of the moving disc tooth meshes with the outer arc A1-4-1 of the tooth; the absolute value of the difference between the radii of the meshing arcs is the radius of rotation of the moving disc.

[0057] The aforementioned method for designing the profile of an asymmetric intake scroll compressor includes the following steps: The first step generates the inner and outer profiles 1-1, 1-2, 2-1, and 2-2 of the moving and stationary disk vortex rings. The second step, based on the first step, performs tooth head correction by adding arcs and straight lines to obtain the moving and stationary disk modified connecting arcs 1-3-1 and 2-3-1, straight line segments 1-3-2 and 2-3-2, corrected arcs 1-3-3 and 2-3-3, and the corrected inner and outer profiles 1-1, 1-2, 2-1, and 2-2 of the moving and stationary disk vortex rings. The third step performs asymmetric three-arc correction on the second step to obtain the outer arcs 1-4-1 and 2-4-1, the middle arcs 1-4-2 and 2-4-2, the inner arcs 1-4-3 and 2-4-3, and the inner and outer profiles 1-1, 1-2, 2-1, and 2-2 of the moving and stationary disk vortex rings.

[0058] In the first step, preferably, the pitch of the initially set vortex profile of the moving and stationary disks is first input. P t Wall thickness t Number of static disc rotations m 1. Number of rotations of the moving disc m 2. And the required content volume ratio of the design. BIVR 0; Calculate the compression chamber V1 and V 2's product ratio BIVR 1 and BIVR 2; Preferred BIVR 1 is used as a design standard to judge BIVR 1. Whether or not it is related to BIVR If 0 is equal, proceed to step two; otherwise, adjust. P t , m 1. m 2 and t Then, re-enter the data, and recalculate and judge it. BIVR 1. Whether or not it is related to BIVR 0 equals; until the two are equal, proceed to the second step; The second step, based on the first step, involves correcting the tooth tip by adding a circular arc to the inner and outer profiles 1-1 of the moving and stationary disk volutes; inputting the initially set correction angle. β 1 and Δr This yields the connecting arcs 1-3-1 and 2-3-1 of the moving and stationary disks, the straight segments 1-3-2 and 2-3-2, the corrected arcs 1-3-3 and 2-3-3, and the inner and outer profiles of the vortex rings of the moving and stationary disks 1-1, 1-2, 2-1, and 2-2. The main parameters include the radius of the connecting arcs. r Correcting the radius of the arc R Intersection of a straight line segment and a modified circular arc P 1. The intersection of straightness and connecting arc P 2, and calculate the above. BIVR 1; if the above BIVR 1 and the expected BIVR If they are equal to 0, proceed to step three; otherwise, proceed to... β 1. Δr , m 1 and m 2. Make adjustments ( m 1 and m 2. The first step should be followed to ensure... m 1 and m (The difference between 2 and 3 remains unchanged), and the profile parametric equations and the above are re-evaluated. BIVR 1. Perform calculations until... BIVR 1= BIVR 0, after completing the second step, proceed to the third step; the static disk R , r and intersection P 1. P The formula for calculating the coordinates is shown in formula (1) below: (1) In the formula, a —Base circle radius; α —The initial angle of the involute of a circle; β1—Correction angle; r — Rotation radius of the moving disc; r 0、 R 0、 d 0 — Intermediate calculation geometric parameters; r— Connect the radius of the arc; R —Correct the radius of the arc; d —Intermediate calculation of geometric parameters; c —The angle between the counterclockwise rotation of the positive X-axis and the line connecting the center of the correction arc and the center of the connecting arc; P 1x —Intersection of the straight line segment and the modified circular arc P The X coordinate of 1; P 1y —Intersection of the straight line segment and the modified circular arc P The Y-coordinate of 1; P 2x —Intersection of the straight segment and the connecting arc P The X coordinate of 2; P 2y —Intersection of the straight segment and the connecting arc P The Y-coordinate of 2. In a scroll compressor, the profile of the moving disc can be obtained by rotating the profile of the stationary disc by 180°, therefore the above parameter calculations are applicable to both the moving and stationary discs.

[0059] After the second step is completed, V The area of ​​the inspiratory chamber of 1 is S 1, V The area of ​​the inhalation chamber of 2 is S 2; V The exhaust chamber area of ​​1 is D 1, V The exhaust chamber area of ​​2 is D 2; the aforementioned BIVR 1= S 1 / D 1, the aforementioned BIVR 2= S 2 / D 2, the aforementioned S 1> S 2 and the above D 1= D 2, the aforementioned BIVR 1> BIVR 2.

[0060] The third step involves asymmetric three-circle arc correction of the moving and stationary disk volute teeth based on the second step. First, the corrected arc 1-3-3 becomes the asymmetric three-circle arc A1-4-3 within the tooth. Further, using... P Point 1 is the intersection point. Draw an external arc tangent to the correction arc 1-3-3, with a radius equal to the radius of the connecting arc 1-3-1. rThe arc is the toothed arc 1-4-2 of the stationary disc after the asymmetric three-circle correction; the correction angle is initially selected. β 2; The correction angle of the profile on the outer side of the stationary plate is... β Point 2 is used to construct an arc internally tangent to the outer profile A1-1, which is the asymmetric three-arc modified outer arc A1-4-1. It is also ensured that the middle arc A1-4-2 is internally tangent to the outer arc A1-4-1. Thus, the asymmetric three-arc modified tooth profile of the stationary disc is obtained, including the stationary disc tooth outer arc profile 1-4-1, the stationary disc tooth middle arc profile 1-4-2, and the stationary disc tooth inner arc profile 1-4-3.

[0061] Furthermore, the moving plate undergoes asymmetric three-circle correction. First, the moving plate connecting arc 2-3-1 serves as the asymmetric three-circle correction external tooth arc B2-4-1; furthermore, with... P Point 2 is the intersection point. Draw an externally tangent arc 2-3-1 to the moving disk, with a radius equal to the radius of the corrected arc 2-3-3 of the moving disk. R The arc, which is the arc B2-4-2 in the teeth of the moving plate after the asymmetric three-circle correction; based on the initially selected correction angle β 2. The correction angle of the profile inside the moving plate is... β A point of 2+π is used to construct an arc internally tangent to the inner profile B2-2 of the moving disk. This arc is the inner arc B2-4-3 of the moving disk tooth after asymmetric three-arc correction, ensuring that the middle arc B2-4-2 of the moving disk tooth is internally tangent to the inner arc B2-4-3. Thus, the asymmetric three-arc corrected tooth profile of the moving disk is obtained, including the outer arc profile 2-4-1, the middle arc profile 2-4-2, and the inner arc profile 2-4-3.

[0062] After the asymmetric three-circle arc tooth head correction is completed, further calculations are performed. V 2's product ratio BIVR 2, if BIVR 2 and expectations BIVR If the values ​​are equal to 0, the calculation ends; otherwise, adjust. β 2. Re-correct the profile with three circular arc tooth tips and... BIVR 2. Perform calculations until... BIVR 2= BIVR 0, calculation complete; the BIVR 2= BIVR 1= BIVR 0.

[0063] Example 4. Hereinafter, we will use... Figure 1-Figure 9 This embodiment will be described below. In an asymmetric intake scroll compressor, the typical number of scroll turns on the stationary disc is... m 1. Number of rotations of the moving disk vortex m2. The difference is between -0.5 and 0.5. In the first embodiment, taking the number of revolutions of the stationary disc as 0.5 more revolutions than the number of revolutions of the moving disc as an example, in this case, m 1= m 2+0.5.

[0064] remember BIVR 1 is the compression cavity formed by the meshing of the inner profile A1-2 of the stationary disk vortex and the outer profile B2-1 of the moving disk vortex. V The internal volume ratio of 1 is the ratio of the intake volume to the exhaust volume of the compression chamber. BIVR 2 is the compression cavity formed by the meshing of the inner profile B2-2 of the moving disk vortex and the outer profile A1-1 of the stationary disk vortex. V The volume ratio of 2 is the ratio of the intake volume to the exhaust volume of the compression chamber.

[0065] like Figure 1 The flowchart shown is a profile design method of the present invention, which includes three steps. The first step generates the inner and outer profiles 1-1, 1-2, 2-1, and 2-2 of the moving and stationary disk vortex rings. The second step, based on the first step, performs tooth head correction by adding arcs and straight lines to obtain the connecting arcs 1-3-1 and 2-3-1 of the moving and stationary disks, the straight line segments 1-3-2 and 2-3-2, the corrected arcs 1-3-3 and 2-3-3, and the corrected inner and outer profiles 1-1, 1-2, 2-1, and 2-2 of the moving and stationary disk vortex rings. The third step, based on the second step, performs asymmetric three-arc correction to obtain the outer arcs 1-4-1 and 2-4-1, the middle arcs 1-4-2 and 2-4-2, the inner arcs 1-4-3 and 2-4-3, and the inner and outer profiles 1-1, 1-2, 2-1, and 2-2 of the moving and stationary disk vortex rings.

[0066] a) In the first step, preferably, the pitch of the initially set dynamic and static disk vortex profiles is first input. P t Wall thickness t Number of static disc rotations m 1. Number of rotations of the moving disc m 2. And the required content volume ratio in the design. BIVR 0; Calculate the compression chamber V 1 and V 2's product ratio BIVR 1 and BIVR 2; Preferred BIVR 1 is used as a design standard to judge BIVR 1. Whether or not it is related to BIVR If 0 is equal, proceed to step two; otherwise, adjust. P t , m 1. m 2 and t Then, re-enter the data, and recalculate and judge it. BIVR 1. Whether or not it is related to BIVR 0 equals; until the two are equal, proceed to the second step.

[0067] b) The second step, based on the first step, involves correcting the tooth tip profile of the inner and outer volutes of the moving and stationary disks using a combination of circular arcs and straight lines. Input the initially set correction angle. β 1 and radial correction amount Δr The parametric equations for the connecting arcs 1-3-1 and 2-3-1 of the moving and stationary disks, the straight segments 1-3-2 and 2-3-2, the modified arcs 1-3-3 and 2-3-3, and the inner and outer profiles of the vortex rings of the moving and stationary disks 1-1, 1-2, 2-1, and 2-2 are obtained. The main parameters include the radius of the connecting arcs. r Correcting the radius of the arc R Intersection of a straight line segment and a modified circular arc P 1. The intersection of the straight line segment and the connecting arc P 2, and calculate at this time BIVR 1; if BIVR 1. Expectations BIVR If they are equal to 0, proceed to step three; otherwise, proceed to... β 1. Δr , m 1 and m 2. Make adjustments m 1 and m 2. The relationship in the first step should be followed; adjustments are made in this embodiment. m 1 and m At time 2, it should be ensured m 1= m 2+0.5, re-evaluate the profile parameter equations and BIVR 1. Perform calculations until... BIVR 1= BIVR 0. Complete step two and proceed to step three. Static disk. R , r and intersection P 1. P The formula for calculating the coordinates is shown in formula (1) below, and the parameters are as follows: Figure 2 As shown: 1 In the formula, a —Base circle radius; α —The initial angle of the involute of a circle; β 1—Correction angle; r — Rotation radius of the moving disc; r 0、 R 0、 d 0 — Intermediate calculation geometric parameters; r— Connect the radius of the arc; R —Correct the radius of the arc; d —Intermediate calculation of geometric parameters; c—The angle between the counterclockwise rotation of the positive X-axis and the line connecting the center of the correction arc and the center of the connecting arc; P 1x —Intersection of the straight line segment and the modified circular arc P The X coordinate of 1; P 1y —Intersection of the straight line segment and the modified circular arc P The Y-coordinate of 1; P 2x —Intersection of the straight segment and the connecting arc P The X coordinate of 2; P 2y —Intersection of the straight segment and the connecting arc P The Y-coordinate of 2. In a scroll compressor, the profile of the moving disc can be obtained by rotating the profile of the stationary disc by 180°, therefore the above parameter calculations are applicable to both the moving and stationary discs.

[0068] like Figure 3 As shown, after the second step is completed, the... V 1 inspiratory chamber area S 1; such as Figure 4 As shown, after the second step is completed, the... V 2 Inhalation chamber area S 2; such as Figure 5 As shown, after the second step is completed, V 1 exhaust chamber area D 1 and V 2 Exhaust chamber area D 2; BIVR 1= S 1 / D 1, BIVR 2= S 2 / D 2. At this time, due to S 1> S 2 and D 1= D 2, therefore BIVR 1> BIVR 2. This causes pressure loss due to the mixing of working fluids at different pressures when the compression ends and the exhaust begins.

[0069] c) The third step, based on the second step, involves asymmetric three-circle arc correction of the moving and stationary disk volute teeth, such as... Figure 6 The diagram shows the asymmetric three-circle correction curve for the stationary disc; firstly, the correction arc 1-3-3 is the asymmetric three-circle correction internal tooth arc A1-4-3; furthermore, with... P Point 1 is the intersection point. Draw an external arc 1-3-3, tangent to the corrected arc, with a radius equal to the radius of the connecting arc 1-3-1. r The arc is the toothed arc 1-4-2 of the stationary disc after the asymmetric three-circle correction; the correction angle is initially selected.β 2; The correction angle for the outer profile A1-1 is... β Draw an arc inscribed in the outer profile A1-1 from point 2. This arc is the asymmetric three-arc correction outer arc A1-4-1, ensuring that 1-4-2 is inscribed in this arc 1-4-1. Thus, the asymmetric three-arc correction tooth tip for the stationary disc is obtained, comprising the outer arc A1-4-1, the middle arc A1-4-2, and the inner arc A1-4-3.

[0070] Furthermore, the moving plate is corrected using an asymmetrical three-circle correction, such as... Figure 7 The image shows the asymmetric three-circle arc correction profile of the moving disk. First, the moving disk connects to arc 2-3-1, which is the asymmetric three-circle arc correction external tooth arc B2-4-1; further, with... P Point 2 is the intersection point. Draw an externally tangent arc 2-3-1 to the moving disk, with a radius equal to the radius of the corrected arc 2-3-3 of the moving disk. R The arc, which is the arc B2-4-2 in the teeth of the moving plate after the asymmetric three-circle correction; based on the initially selected correction angle β 2. The correction angle for the inner profile B2-2 of the moving disc is... β A point 2+π is used to construct an arc internally tangent to the inner profile B2-2 of the moving disk. This arc is the inner arc B2-4-3 of the moving disk tooth after asymmetric three-arc correction, ensuring that 2-4-2 is internally tangent to this arc 2-4-3. Thus, the asymmetric three-arc corrected tooth tip of the moving disk is obtained, comprising the outer arc B2-4-1, the middle arc B2-4-2, and the inner arc B2-4-3.

[0071] At this point, 2-4-1 meshes with 1-4-3, 2-4-2 meshes with 1-4-2, and 2-4-3 meshes with 1-4-1. As shown in formula (2) below, the absolute values ​​of the differences between the arc radii of 2-4-1 and 1-4-3, and between 2-4-2 and 1-4-2, are all the rotation radii of the moving disc, satisfying the meshing condition: (2) This proves that the difference between the radii of 2-4-3 and 1-4-1 is the radius of rotation of the moving disk. Rotating the moving disk 180° causes its coordinate system to coincide with the coordinate system of the stationary disk. Figure 8 As shown, at this time O The center of the moving and static disk base circle, O 1 is the center of the inner arc B2-4-3 of the moving disc tooth. O 2 is the center of the arc B2-4-2 in the moving disc tooth. O 3 is the center of the inner arc A1-4-3 of the tooth. O 4 is the center of the outer arc A1-4-1 of the tooth. O 5 is the center of the arc A1-4-2 in the tooth. O 6 is the center of the outer arc B2-4-1 of the tooth. P3 is the intersection of the inner circular arc B2-4-3 and the middle circular arc B2-4-2 of the moving disk tooth, which is also the tangent point of the two circular arcs; P 4 is the intersection of the outer arc A1-4-1 and the middle arc 1-4-2 of the tooth, which is also the tangent point of the two arcs; In triangle O.O 2 O 3 and triangle O.O 5 O 6 in: (3) And because of | O.O 6| and | O.O 3| Collinear, O 2 O 3 / / O 5 O 6, therefore ∠ O.O 3 O 2=∠ O.O 6 O 5; therefore, the triangle described O.O 2 O 3 and triangle O.O 5 O 6. Congruent; therefore | O.O 2|=| O.O 5|.

[0072] And because of | O.O 4|=| O.O 1| The calculation is as follows: (4) On the triangle O.O 1 O 2 and triangle O.O 4 O 5 in: | O.O 2|=| O.O 5|,| O.O 4|=| O.O 1|, and ∠ O 1 O.O 2=∠ O 4 O.O 5. Triangles O.O 1 O 2 and triangle O.O 4 O 5. Congruence, | O 1 O 2|=| O 4 O 5|.

[0073] The difference between the radii of arcs 2-4-3 and 1-4-1 is calculated as follows: (5) It is proven that the absolute value of the difference between the radii of the arcs 2-4-3 and 1-4-1 is the radius of rotation of the moving disc, thus satisfying the meshing condition.

[0074] After the asymmetric three-circle arc tooth head correction is completed, further calculations are performed. V 2's product ratio BIVR 2, if BIVR 2 and expectations BIVR If the values ​​are equal to 0, the calculation ends; otherwise, adjust. β 2. Re-correct the profile with three circular arc tooth tips and... BIVR 2. Perform calculations until... BIVR 2= BIVR 0, calculation complete. For example... Figure 9 The image shows a schematic diagram of a pair of exhaust chamber cross-sections after the third step is completed. V The exhaust chamber area of ​​1 is D 3, V The exhaust chamber area of ​​2 is D 4; BIVR 1= S 1 / D 3, BIVR 2= S 2 / D 4. At this time, although S 1> S 2 but D 4< D 3, therefore it can be made BIVR 1= BIVR 2.

[0075] at this time, BIVR 2= BIVR 1= BIVR At 0, when compression ends and exhaust begins, the pressure in both exhaust chambers is the same, avoiding irreversible losses; and the moving and stationary discs are always engaged, with no clearance volume; in addition, the compressor pressure ratio is increased.

[0076] Example 5. Hereinafter, using Figure 10 This embodiment will be described.

[0077] like Figure 10 As shown, the process includes four steps. The first step generates the inner and outer profiles 1-1, 1-2, 2-1, and 2-2 of the moving and stationary disk volutes. The second step, based on the first step, modifies the inner profile A1-2 and the outer profile B2-1 to obtain the inner tooth arc A1-4-3 and the outer tooth arc B2-4-1. The third step, based on the second step, modifies the outer profile A1-1 and the inner profile B2-2 of the moving disk to obtain the outer tooth arc A1-4-1 and the inner tooth arc B2-4-3 of the moving disk. The fourth step, based on the tangency and meshing relationship and the expected internal volume ratio... BIVR0 yields the in-tooth arc A1-4-2 and the in-tooth arc B2-4-2 of the moving disc.

[0078] a) In the first step, preferably, the pitch of the initially set dynamic and static disk vortex profiles is first input. P t Wall thickness t Number of static disc rotations m 1. Number of rotations of the moving disc m 2 and the expected content volume ratio BIVR 0; Calculate the compression chamber V 1 and V 2's product ratio BIVR 1 and BIVR 2; Preferred BIVR 1 is used as a design standard to judge BIVR 1. Whether or not it is related to BIVR If 0 is equal, proceed to step two; otherwise, adjust. P t , m 1. m 2 and t Then, re-enter the data, and recalculate and judge it. BIVR 1. Whether or not it is related to BIVR 0 equals; until the two are equal, proceed to the second step.

[0079] b) In the second step, input the initially set correction angle. β 1 and Δr According to Formula 1, calculate the corrected radius of the arc ( R and the radius of the connecting arc r The development angle of the inner profile A1-2 is... β Draw a line inscribed in the shape at point 1+π with radius 1-2. R The arc is the inner arc A1-4-3; simultaneously, the development angle of the outer profile B2-1 is... β 1. Draw a line internally tangent to the shape line 2-1 with a radius of . r The arc is the outer arc of the tooth, B2-4-1.

[0080] c) In the third step, input the initially set second correction angle. β 2 and Δr 2; In formula 1 β 1 replaced with β 2. Calculate the second corrected arc radius ( R 2) The radius of the second connecting arc ( r 2) The development angle of the outer profile A1-1 is... β Two points are internally tangent to the profile with a radius of [missing information]. r The arc of 2 is the outer arc of the tooth A1-4-1; at the same time, the development angle of the inner profile B2-2 on the moving plate is...β Draw a line inscribed in the shape at point 2+π with a radius of π. R The arc of 2 is the inner arc B2-4-3 of the moving disc tooth.

[0081] The fourth step, firstly, involves making a radius of... r The arc 1-4-1, externally tangent to the inner arc of the tooth and internally tangent to the outer arc of the stationary disc tooth, is the middle arc A1-4-2 of the tooth; simultaneously, a radius of... R The arc tangent to the outer arc B2-4-1 of the moving disc tooth and tangent to the inner arc B2-4-3 of the moving disc tooth is the middle arc B2-4-2 of the moving disc tooth; further, the compression cavity is calculated. V 1 content product ratio BIVR 1, and the expected internal pressure ratio BIVR Compare with 0; if they are equal, proceed to the next step; otherwise, check the values. β 1. Δr , m 1 and m 2. Adjustments were made, and the equations for the profile parameters were re-evaluated. BIVR 1. Perform calculations until... BIVR 1= BIVR 0; further, calculate V 2 and BIVR 2, and the expected internal pressure ratio BIVR The operation is compared to 0; if they are equal, the calculation ends; otherwise, the operation continues. β 2 and Δr 2. Adjustments were made, and the equations for the profile parameters were re-evaluated. BIVR 2. Perform calculations until... BIVR 2= BIVR 0, end the operation. 2-4-1 meshes with 1-4-3, 2-4-2 meshes with 1-4-2, and 2-4-3 meshes with 1-4-1. The absolute value of the difference between the meshing arc radii is the radius of rotation of the moving disc, satisfying the meshing condition. At this point, BIVR 2= BIVR 1= BIVR At 0, when compression ends and exhaust begins, the pressure in both exhaust chambers is the same, avoiding irreversible losses; and the moving and stationary discs are always engaged, with no clearance volume; in addition, the compressor pressure ratio is increased.

[0082] The above detailed embodiments are a description of the present invention. It should not be considered that the specific embodiments of the present invention are limited to these descriptions. For those skilled in the art, several simple deductions and substitutions can be made without departing from the concept of the present invention, and all of these should be considered to fall within the protection scope of the present invention.

Claims

1. An asymmetric intake scroll compressor profile, characterized in that, include: The outer profile A (1-1) and inner profile A (1-2) of the stationary disk vortex, the outer profile B (2-1) and inner profile B (2-2) of the moving disk vortex, and the asymmetric three-circular-arc tooth head correction profile; The asymmetric three-circular-arc tooth head correction profile includes: a three-circular-arc tooth head correction profile A connecting the outer and inner profiles A at the stationary disk volute tooth head, and a three-circular-arc tooth head correction profile B connecting the outer and inner profiles B at the moving disk volute tooth head. A pair of compression chambers enclosed by the profiles of the moving and stationary disk vortices V 1. V 2. With the same internal volume ratio, the compression chamber V The intake volume S1 is not equal to the compression chamber. V The intake volume S2 is 2, and the compression chamber is 2. V The exhaust volume D1 is not equal to the compression chamber. V The exhaust volume D2 is 2.

2. The asymmetric intake scroll compressor profile according to claim 1, characterized in that, The three-circular arc tooth head correction profile A includes: a correction angle of... β The outer arc A (1-4-1) of tooth 2 has a correction angle of . β The inner arc A of the tooth is 1+π (1-4-3), and the middle arc A of the tooth connects the outer and inner arcs A (1-4-2). The outer and inner arcs A of the tooth are internally tangent to the outer and inner profile lines A, respectively; the middle arc A (1-4-2) of the tooth is internally tangent to the outer arc A (1-4-1) and externally tangent to the inner arc A (1-4-3), respectively. β 2≠ β 1.

3. The asymmetric intake scroll compressor profile according to claim 2, characterized in that, The three-circular arc tooth head correction profile B includes: a correction angle of... β The outer arc B (2-4-1) of tooth 1 has a correction angle of 1. β The inner arc B of the tooth is 2+π (2-4-3), and the middle arc B of the tooth connects the outer and inner arcs B (2-4-2). The outer and inner arcs B of the tooth are respectively tangent to the outer and inner profile lines B; the middle arc B (2-4-2) of the tooth is tangent to the outer arc B (2-4-1) and tangent to the inner arc B (2-4-3). β 2≠ β 1.

4. The asymmetric intake scroll compressor profile according to claim 3, characterized in that, The outer arc B (2-4-1) meshes with the inner arc A (1-4-3); the middle arc B (2-4-2) meshes with the middle arc A (1-4-2); the inner arc B (2-4-3) meshes with the outer arc A (1-4-1); the absolute value of the difference between the radii of the meshing arcs is the radius of rotation of the moving disc.

5. A method for designing the profile of an asymmetric intake scroll compressor as described in any one of claims 1-4, characterized in that, The steps are as follows: S1. Generates the inner and outer profiles of the dynamic and static disk vortex rings; S2. Based on S1, perform tooth tip correction by adding arcs and straight lines to obtain: stationary disk connecting arc (1-3-1), stationary disk straight line segment (1-3-2), stationary disk correction arc (1-3-3), moving disk connecting arc (2-3-1), moving disk straight line segment (2-3-2), moving disk correction arc (2-3-3). S3. Based on S2, perform asymmetric three-circle correction to obtain: tooth outer circle A (1-4-1), tooth middle circle A (1-4-2), tooth inner circle A (1-4-3), tooth outer circle B (2-4-1), tooth middle circle B (2-4-2), and tooth inner circle B (2-4-3).

6. The design method according to claim 5, characterized in that, S1 is as follows: Initially set the pitch of the dynamic and static disk vortex profiles. P t Wall thickness t Number of static disc rotations m 1. Number of rotations of the moving disc m 2 and expected content product ratio BIVR 0; corresponding to the calculation of the compression chamber V 1. V 2's product ratio BIVR 1. BIVR 2; will BIVR 1 is used as a design standard, if BIVR 1= BIVR 0, implement S2; if BIVR 1≠ BIVR 0, Adjustment P t , m 1. m 2 and t Until the two are equal.

7. The design method according to claim 6, characterized in that, S2 is as follows: Input the initially set correction angle. β 1 and radial correction amount Δr The equations for the connecting arcs of the moving and stationary disks, the straight segments of the moving and stationary disks, the corrected arcs of the moving and stationary disks, and the inner and outer profile parameters of the vortex rings of the moving and stationary disks are obtained. The main parameters include the radius of the connecting arcs. r Correcting the radius of the arc R Intersection of a straight line segment and a modified circular arc P 1. The intersection of the straight line segment and the connecting arc P 2; Calculation BIVR 1; if BIVR 1= BIVR If 0, then S3 is executed; otherwise, for β 1. Δr , m 1 and m 2. Adjustments were made, and the profile parameter equations and the aforementioned... BIVR 1. Perform calculations until... BIVR 1= BIVR 0; where the static disk R , r and intersection P 1. P The formula for calculating the coordinates is as follows (1): （1） In the formula, a —Base circle radius; α —The initial angle of the involute of a circle; β 1—Correction angle; ρ — Rotation radius of the moving disc; r 0、 R 0、 d 0 — Intermediate calculation geometric parameters; r— Connect the radius of the arc; R —Correct the radius of the arc; d —Intermediate calculation of geometric parameters; γ —The angle between the counterclockwise rotation of the positive X-axis and the line connecting the center of the correction arc and the center of the connecting arc; P 1x —Intersection of the straight line segment and the modified circular arc P The X coordinate of 1; P 1y —Intersection of the straight line segment and the modified circular arc P The Y-coordinate of 1; P 2x —Intersection of the straight segment and the connecting arc P The X coordinate of 2; P 2y —Intersection of the straight segment and the connecting arc P The Y-coordinate of 2; In a scroll compressor, the profile of the moving disc is obtained by rotating the profile of the stationary disc by 180°. Therefore, the above parameter calculations are applicable to both the moving and stationary discs. After S2 is completed, V The area of ​​the inspiratory chamber of 1 is S 1, V The area of ​​the inhalation chamber of 2 is S 2; V The exhaust chamber area of ​​1 is D 1, V The exhaust chamber area of ​​2 is D 2; BIVR 1= S 1 / D 1, BIVR 2= S 2 / D 2, S 1> S 2 and D 1= D 2, BIVR 1> BIVR 2.

8. The design method according to claim 7, characterized in that, S3 is as follows: The stationary disc correction arc (1-3-3) is taken as the tooth inner arc A (1-4-3) after asymmetric three-arc correction; with P Point 1 is the intersection point. Draw an externally tangent arc (1-3-3) to the stationary disk, with a radius equal to the radius of the connecting arc (1-3-1) on the stationary disk. r The arc is taken as the arc A in the tooth (1-4-2); the correction angle is initially selected. β 2; The correction angle of the profile on the outer side of the stationary plate is... β Draw an arc inscribed in the outer profile A (1-1) at point 2, as the outer arc A (1-4-1), and ensure that the middle arc A (1-4-2) is inscribed in the outer arc A (1-4-1). Connect the moving disc to the outer arc B (2-4-1) of the circular arc (2-3-1); with P Point 2 is the intersection point. Draw an externally tangent arc (2-3-1) to the moving disk, with a radius equal to the radius of the moving disk's corrected arc (2-3-3). R The arc is taken as the arc B (2-4-2) in the tooth; based on the initially selected correction angle. β 2. The correction angle of the profile inside the moving plate is... β Draw an arc inscribed in the inner profile B(2-2) from the point of 2+π as the inner arc B(2-4-3) of the tooth, and ensure that the inner arc B(2-4-2) of the tooth is inscribed in the inner arc B(2-4-3). After the asymmetric three-circle arc tooth head correction is completed, the calculation is performed. V 2's product ratio BIVR 2, if BIVR 2= BIVR If the value is 0, the calculation ends; otherwise, adjust. β 2. Re-correct the profile using the three-circle tooth head until... BIVR 2= BIVR 0; where BIVR 2= BIVR 1= BIVR 0.

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