Method for calculating allowable shear strength and method for constructing a structural frame

Abstract

To provide an allowable shear strength calculation method that can reduce necessary labor.SOLUTION: An allowable shear strength calculation method includes a calculation step S310 of, based on a result of a test of a test piece 6 simulating a junction 5 between a wooden member 3 and a deck plate 4 and an analysis model having the junction 5 between the wooden member 3 and the deck plate 4 as an element, calculating an allowable shear strength of the junction 5. Based on a first allowable shear strength jq0, a second allowable shear strength jq90, and an absolute value of a rotation amount θ of the junction 5, the calculation step S310 calculates an allowable shear strength correction value jqθ obtained by correcting a principal stress of the junction 5 in a fiber direction of the wooden member 3. Based on the first allowable shear strength jq0 and the allowable shear strength correction value jqθ, the calculation step S310 calculates a strength correction coefficient α according to a first aspect ratio H / L. Based on the first allowable shear strength jq0 and the strength correction coefficient α, the calculation step S310 calculates an allowable shear strength jq of the junction 5.SELECTED DRAWING: Figure 3

Description

[Technical Field]

[0001] The present invention relates to a method for calculating the allowable shear strength of a structural frame having a horizontal plane composed of a frame structure made of wooden members and deck plates, and to a method for constructing such a structural frame. [Background technology]

[0002] In recent years, with the forest resources planted after World War II now reaching their peak utilization stage, there has been a surge in efforts to promote the use of wood in buildings, including public structures. The Forestry Agency is taking the lead in revising laws to promote the use of timber. As wooden buildings become more widespread and larger in scale, it is anticipated that new construction methods will be established.

[0003] On the other hand, since wood materials are natural materials rather than industrial products like steel, evaluation from a statistical perspective is necessary, taking into account variations in strength and other properties, in addition to the perspective of structural mechanics. As a result, classical methods are often used compared to other structures.

[0004] When constructing a structural frame, it is necessary to calculate the allowable shear strength of the structural frame. Conventionally, Non-Patent Document 1 discloses a method for calculating the allowable shear strength of the horizontal plane of a structural frame in which a frame structure composed of wooden beams and a sheathing material are joined together. In a structural frame, the shear behavior of the joints is caused by the deformation of the wooden beams and the relative displacement of the joints due to the rigid rotation of the sheathing material, and the shear behavior of each joint is different. For this reason, it is difficult to calculate the shear strength of each joint.

[0005] Therefore, in the method for calculating the allowable shear strength described in Non-Patent Document 1, a full-scale test specimen is prepared, and a full-scale test is conducted to calculate the one-sided shear characteristics of each joint. Based on the joint arrangement in the full-scale test, the arrangement parameters of the joints are calculated according to Non-Patent Document 1. Then, the allowable shear strength per joint is calculated based on the calculated one-sided shear characteristics and the arrangement parameters of the joints. [Prior art documents] [Non-patent literature]

[0006] [Non-Patent Document 1] Edited by the Committee for the Revision of Allowable Stress Design for Wooden Frame Construction Houses, "Allowable Stress Design for Wooden Frame Construction Houses (2017 Edition)," published by the Japan Housing and Wood Technology Center, March 2017, pp. 182-197, 291-317. [Overview of the project] [Problems that the invention aims to solve]

[0007] The method for calculating allowable shear strength described in Non-Patent Document 1 involves constructing a full-scale test specimen and conducting a full-scale test. This requires significant costs and effort, including material procurement, personnel allocation, testing facility usage, design, and construction. Furthermore, because the test is conducted using a full-scale specimen, if the construction conditions of the structural frame, such as the number of joints or the aspect ratio of the horizontal plane, are changed, it is necessary to construct a new full-scale specimen according to the construction conditions and calculate the allowable shear strength. However, constructing a full-scale specimen for each construction condition requires considerable effort.

[0008] Therefore, the present invention was devised in view of the above circumstances, and its purpose is to provide a method for calculating allowable shear strength and a method for constructing a structural frame that can reduce the amount of labor required. [Means for solving the problem]

[0009] The inventors have discovered a new method for calculating the allowable shear strength of a joint by using test results from a test specimen simulating the joint between a wooden member and a deck plate, and a finite element analysis model that uses the joint between the wooden member and the deck plate as an element. This reduces the effort required to fabricate a full-scale structural frame for each condition. As a result, it becomes possible to easily calculate the allowable shear strength of the structural frame.

[0010] The allowable shear strength calculation method according to the present invention is a method for calculating the allowable shear strength of a structural frame having a horizontal plane composed of a frame structure made of wooden members and a deck plate, and comprises a calculation step of calculating the allowable shear strength of the joint based on the test results of a test specimen that simulates the joint between the wooden members and the deck plate and a finite element analysis model in which the joint between the wooden members and the deck plate is an element. The test results include a first shear characteristic in the fiber direction of the wooden member of the test specimen and a second shear characteristic in the direction perpendicular to the fiber of the wooden member of the test specimen, and the calculation step calculates the allowable shear strength of the joint based on the first shear characteristic, the second shear characteristic and the analysis model. It is characterized by the following.

[0011] The present invention relates to a method for constructing a structural frame comprising a horizontal structural plane composed of a framework structure made of wooden members and a deck plate, comprising: a calculation step of calculating the allowable shear strength of the joint based on the test results of a test specimen simulating the joint between the wooden members and the deck plate and an analytical model in which the joint between the wooden members and the deck plate is an element; a determination step of determining whether the calculated allowable shear strength of the horizontal structural plane exceeds the shear force required for the horizontal structural plane; The system comprises a setting step of setting construction conditions for constructing the structural frame when the allowable shear strength of the horizontal frame exceeds the shear force, and a construction step of constructing the structural frame that satisfies the construction conditions set in the setting step, wherein the setting step sets the number of joints as the construction condition based on the allowable shear strength of the horizontal frame that exceeds the shear force and the allowable shear strength of the joints, and the construction step constructs the structural frame that satisfies the number of joints set in the setting step. The test results include a first shear characteristic in the fiber direction of the wooden member of the test specimen and a second shear characteristic in the direction perpendicular to the fiber of the wooden member of the test specimen, and the calculation step calculates the allowable shear strength of the joint based on the first shear characteristic, the second shear characteristic and the analysis model. It is characterized by doing so. [Effects of the Invention]

[0012] According to the present invention, it is possible to provide a method for calculating allowable shear strength and a method for constructing a structural frame that can reduce the amount of labor required. [Brief explanation of the drawing]

[0013] [Figure 1]Figure 1 is a schematic perspective view showing an example of a structural frame. [Figure 2] Figure 2 shows the concept of the allowable shear strength of the joint in the present invention when an external force is applied to the structural frame. [Figure 3] Figure 3 is a flowchart showing an example of a method for calculating the allowable shear strength in an embodiment. [Figure 4] Figure 4(a) shows an example of the first test specimen, and Figure 4(b) shows an example of the second test specimen. [Figure 5] Figure 5 is a diagram illustrating a method for calculating the allowable shear strength and shear stiffness of a test specimen based on the relationship between load and relative displacement. [Figure 6] Figure 6(a) shows an example of a finite element analysis model, and Figure 6(b) is an enlarged view of part a of Figure 6(a). [Figure 7] Figure 7(a) shows the relationship between the position of the joint of the upper wooden member and the absolute value of the amount of rotation, and Figure 7(b) shows the relationship between the position of the joint of the lower wooden member and the absolute value of the amount of rotation. [Figure 8] Figure 8(a) shows the relationship between the position of the joint of the wooden member on the left side and the absolute value of the amount of rotation, and Figure 8(b) shows the relationship between the position of the joint of the wooden member on the right side and the absolute value of the amount of rotation. [Figure 9] Figure 9 shows an example of the concept of the allowable shear strength correction value for joint 5. [Figure 10] Figures 10(a) and 10(b) show the relationship between the aspect ratio and the load-bearing strength correction coefficient. [Figure 11] Figure 11 shows an actual test specimen. [Figure 12] Figure 12 shows the conventional concept of stress at a joint when an external force is applied to the structural frame. [Figure 13] Figure 13(a) is a schematic diagram showing an example of the configuration of the calculation device, and Figure 13(b) is a schematic diagram showing an example of the function of the calculation device. [Figure 14] Figure 14 is a flowchart showing an example of a method for constructing a structural frame in an embodiment. [Modes for carrying out the invention]

[0014] The following describes in detail, with reference to the drawings, the embodiments for implementing the allowable shear strength calculation method and the structural frame construction method to which the present invention is applied. In each figure, the height direction is defined as Z, the direction intersecting the height direction Z is defined as the first direction X, and the direction intersecting the height direction Z and the first direction X is defined as the second direction Y.

[0015] As shown in Figure 1, the allowable shear strength calculation method according to the present invention calculates the allowable shear strength of a structural frame 1 having a horizontal plane composed of a frame structure 2 made of wooden members 3 and a deck plate 4.

[0016] The structural frame 1 comprises a horizontal plane composed of a framework structure 2 made of wooden members 3 and a plurality of deck plates 4. The structural frame 1 is, for example, a floor structure comprising wooden members 3 and deck plates 4. The structural frame 1 may also be, for example, a roof structure comprising wooden members 3 and deck plates 4. The framework structure 2 is formed by combining wooden members 3 in a rectangular shape in plan view. Based on the laying direction of the deck plates 4, the width direction of the deck plates 4 is defined as the first direction X, and the span direction of the deck plates 4 is defined as the second direction Y. Multiple deck plates 4 are laid in the first direction X. Multiple deck plates 4 are joined to each other by known fasteners such as drilling tapping screws and nails. The thickness of the deck plates 4 is, for example, about 1.0 mm to 1.6 mm. The depth of the deck plates 4 is, for example, 50 to 120 mm.

[0017] The wooden member 3 has a pair of wooden members 31 whose longitudinal direction is in the first direction X, and a pair of wooden members 32 whose longitudinal direction is in the second direction Y. Of the pair of wooden members 31, one is also called the upper wooden member 31, and the other is also called the lower wooden member 31. Of the pair of wooden members 32, one is also called the left wooden member 32, and the other is also called the right wooden member 32.

[0018] The wooden members 3 are arranged with the fiber direction as the longitudinal direction and the direction perpendicular to the fiber as the short direction. That is, the fiber direction of wooden member 31, whose longitudinal direction is the first direction X, is along the first direction X, and the direction perpendicular to the fiber of wooden member 31 is along the second direction Y. Similarly, the fiber direction of wooden member 32, whose longitudinal direction is the second direction Y, is along the second direction Y, and the direction perpendicular to the fiber of wooden member 32 is along the first direction X.

[0019] The aspect ratio of the horizontal plane is H / L, where H is the ratio of the length in the second direction Y to L is the ratio of the length in the first direction X.

[0020] The structural frame 1 comprises multiple joints 5 where wooden members 3 and deck plates 4 are joined together by fasteners. The fasteners are known fasteners such as drilling tapping screws and nails.

[0021] Figure 12 shows the conventional concept of stress in a joint 5 when an external force P acts on the structural frame 1. In Figure 12, the arrows in the joint 5 indicate the principal stresses. As shown in Figure 12, the shear behavior of the joint 5 due to the external force P acting on the structural frame 1 is caused by the deformation of the wooden member 3 and the relative displacement of the joint 5 due to the rigid rotation of the deck plate 4. Therefore, the shear behavior of each joint 5 has different principal stress directions. It is known that the principal stress direction of the joint 5 is approximately the same as the fiber direction near the center in the axial direction of the wooden member 3, but tilts in the direction perpendicular to the fibers as it approaches the ends. Since the wooden member 3 is an orthotropic material with different strengths in the fiber direction and the direction perpendicular to the fibers, the strength of the joint 5 decreases as the principal stress direction rotates by a certain amount (0° to 90°) relative to the fiber direction.

[0022] Conventionally, when calculating the allowable shear strength of a horizontal structural plane, it is difficult to uniformly evaluate the shear performance of each joint 5 because, as described above, the direction of the principal stress differs at each joint 5. For this reason, the method has generally been limited to obtaining characteristic values ​​of the joints from full-scale tests, which involve creating and testing full-scale structural frame specimens, and then calculating the shear performance based on the arrangement constants of the joints (see Non-Patent Literature 1 (Revised Committee for Allowable Stress Design of Wooden Frame Houses, "Allowable Stress Design of Wooden Frame Houses (2017 Edition)," published by the Japan Housing and Wood Technology Center, March 2017, pp. 182-197)).

[0023] Figure 2 shows the allowable shear strength of the joint 5 in the present invention when an external force P is applied to the structural frame 1. j This diagram illustrates the concept of q. In Figure 2, the arrow at joint 5 indicates the allowable shear strength of joint 5. j The value q is shown. Therefore, in this invention, as shown in Figure 2, a mechanical model is defined in which the principal stress direction of the joint 5 is assumed to coincide with the fiber direction of the wooden member 3. Allowable shear strength of the joint 5 in the mechanical model j To calculate q, a finite element analysis model M is set up for the joint 5, which has a first shear characteristic in the fiber direction and a second shear characteristic in the direction perpendicular to the fibers. Then, the allowable shear strength of the structural frame 1 is calculated by simply evaluating the shear behavior of the joint 5 based on this model and the test results of a test specimen 6 that simulates the joint 5. Here, the allowable shear strength of the structural frame 1 is the allowable shear strength of the horizontal plane. g Q and the allowable shear strength of joint 5 j It includes q. Also, "allowable shear strength" mainly refers to "short-term allowable shear strength".

[0024] The method for calculating the allowable shear strength in this invention is performed by a calculation device 100, which is a computer, using information input by an operator.

[0025] Figure 13(a) is a schematic diagram showing an example of the configuration of the calculation device 100. As the calculation device 100, a known electronic device such as a personal computer (PC) is used. The calculation device 100 comprises, for example, a housing 10, a CPU (Central Processing Unit) 101, a ROM (Read Only Memory) 102, a RAM (Random Access Memory) 103, a storage unit 104, and I / F 105~108. Each component 101~107 is connected by an internal bus 110.

[0026] The CPU 101 controls the entire computing device 100. The ROM 102 stores the operating code of the CPU 101. The RAM 103 is a working area used when the CPU 101 is operating. The storage unit 104 stores various information such as a string database. As the storage unit 104, known data storage media such as an SD memory card, an HDD (Hard Disk Drive), or an SSD (Solid State Drive) can be used.

[0027] I / F105 is a known interface for sending and receiving various types of information with the input device 111. The input device 111 may be a known input device such as a keyboard. Operators can input or select various types of information and control commands for the calculation device 100 via the input device 111. The input device 111 may be omitted.

[0028] I / F106 is a known interface for sending and receiving various types of information with the display device 113. The display device 113 displays various types of information. For example, a display is used as the display device 113.

[0029] I / F107 is a known interface for sending and receiving various types of information over a public communication network. Multiple I / F107 interfaces may be provided and used to send and receive various types of information over a communication network such as the Internet.

[0030] Note that, as the I / Fs 105 to 107, for example, the same ones may be used, and as each of the I / Fs 105 to 107, for example, a plurality of them may be used respectively.

[0031] FIG. 13(b) is a schematic diagram showing an example of the functions of the calculation device 100. The computer includes, for example, an acquisition unit 11, a calculation unit 12, a storage unit 13, and a display unit 14. The acquisition unit 11 acquires and inputs various information such as test results of the test body 6. The calculation unit 12 is capable of performing arithmetic processing based on various information, and calculates, for example, the allowable shear strength based on the information acquired by the acquisition unit 11 and the information stored in the storage unit 13. Further, the calculation unit 12 can create a finite element analysis model M and execute a finite element analysis using the created finite element analysis model M. The storage unit 13 stores various information. The display unit 14 displays various information. Note that each function shown in FIG. 13(b) is realized by the CPU 101 executing a program stored in the storage unit 104 or the like with the RAM 103 as a work area.

[0032] In the present invention, the allowable shear strength g Q of the horizontal plane is represented by the following mathematical formulas (1) to (3) using the allowable shear strength j q of the joint 5.

[0033]

Equation

[0034] Allowable shear strength of joint 5 j q is the first allowable shear strength in the test results of test specimen 6. j Based on q0 and the strength correction coefficient α, it is calculated using the following formula (4).

[0035]

number

[0036] According to the above formula (1), the allowable shear strength of the horizontal plane g Q is the allowable shear strength. jh Q and allowable shear strength jv It can be calculated using the smaller of Q and . This allows for a more conservative calculation of the allowable shear strength of the horizontal structure.

[0037] According to the above formulas (2) and (3), the allowable shear strength jh Q and allowable shear strength jv Q represents the number of joints (5). j n and the allowable shear strength of the joint 5 j It can be calculated based on the product with q. This gives the allowable shear strength. jh Q and allowable shear strength jv Q can be expressed concisely.

[0038] Below, an example of a method for calculating the allowable shear strength in the present invention will be described in detail.

[0039] Figure 3 is a flowchart illustrating an example of the method for calculating the allowable shear strength in the present invention. The method for calculating the allowable shear strength of the joint 5 of the structural frame 1 is based on the test results of a test specimen 6 that simulates the joint 5 between the wooden member 3 and the deck plate 4, and a finite element analysis model M that uses the joint 5 between the wooden member 3 and the deck plate 4 as an element.j The system includes a calculation step S310 in which q is calculated by computer.

[0040] The method for calculating the allowable shear strength may further include a shear test step S110 and a model creation step S210, which are performed prior to the calculation step S310.

[0041] <Shear test process S110> In the shear test step S110, a shear test is performed on a test specimen 6 that simulates the joint 5 between the wooden member 3 and the deck plate 4, and the test results of the test specimen 6 are obtained. In the shear test step S110, the test specimen 6 is actually manufactured, and the shear test is performed on the manufactured test specimen 6. If the test results of the test specimen 6 have been obtained in advance, the shear test step S110 can be omitted.

[0042] As shown in Figure 4, the test specimen 6 is constructed by joining a wooden piece 63, which mimics a wooden member 3, and a steel plate 64, which mimics a deck plate 4, with a fastener 65. The test specimen 6 is constructed by placing a pair of steel plates 64 on the near side and far side of the paper in Figure 4, with the wooden piece 63 in between, and joining them with the fastener 65. Ungraded cedar lumber was used for the wooden piece 63. A steel plate with a thickness of 1.2 mm was used for the steel plate 64. The steel plate 64 has a yield strength of 333 (N / mm²). 2 ), tensile strength is 473 (N / mm²). 2 ), a steel plate with an elongation of 33.0% was used. For the fastener 65, a drilling tapping screw with a diameter of φ6 mm and a shank length of 50 mm was used.

[0043] The test specimen 6 uses two types of specimens: a first specimen 61 that is subjected to force parallel to the grain direction of the wood block 63, and a second specimen 62 that is subjected to force parallel to the grain direction of the wood block 63. In the first specimen 61, three fasteners 65 are provided along the direction of force application. In the second specimen 62, two fasteners 65 are provided along the direction perpendicular to the direction of force application. Six specimens each of the first specimen 61 and the second specimen 62 are prepared, and shear tests are performed on each of the first specimen 61 and the second specimen 62.

[0044] The shear test was performed using unidirectional repeated loading in accordance with the test method for joints and connections described in Non-Patent Document 1 (see "Allowable Stress Design for Wooden Frame Houses (2017 Edition)," edited by the Committee for the Revision of Allowable Stress Design for Wooden Frame Houses, published by the Japan Housing and Wood Technology Center, March 2017, pp. 305-313). The relative displacement δ between the wood block 63 and the steel plate 64 was measured, and the yield displacement δ was determined. y Fixed sequence method (δ y Unidirectional displacements were applied once each at 1 / 2, 1, 2, 4, 6, ..., and the load was applied until it decreased to 80% of the maximum load. The shear test allowed us to obtain the relationship between the relative displacement δ per joint 65 and the load.

[0045] The test results include the shear characteristics of test specimen 6 (allowable shear strength and shear stiffness of test specimen 6). The test results include the first shear characteristics in the fiber direction of the wood piece 63 (wooden member) of the first test specimen 61, and the second shear characteristics in the direction perpendicular to the fibers of the wood piece 63 (wooden member) of the second test specimen 62. The first shear characteristics are the first allowable shear strength. j q0 and the first shear stiffness j k0 and the second shear characteristic is the second allowable shear strength. j q 90 and second shear stiffness j k 90 The test results may include the relationship between the relative displacement δ obtained by the shear test and the load. The test results include the yield strength P of the test specimen 6. y and maximum load-bearing capacity P max It may include and.

[0046] The shear characteristics (allowable shear strength and shear stiffness) of test specimen 6 can be evaluated in accordance with the evaluation method described in Non-Patent Literature 1 (edited by the Committee for the Revision of Allowable Stress Design for Wooden Frame Construction Houses, "Allowable Stress Design for Wooden Frame Construction Houses (2017 Edition)," published by the Japan Housing and Wood Technology Center, March 2017, see pp. 305-313).

[0047] The shear characteristics of test specimen 6 are evaluated based on the relationship between the relative displacement δ obtained by the shear test and the load. In detail, as shown in Figure 5, first, in the envelope E of the relationship between the relative displacement δ obtained by the shear test and the load, (1) 0.1 × maximum load capacity P on the envelope E max And, 0.4 × maximum load-bearing capacity P max Draw the first straight line L1 connecting the points. (2) 0.4 × maximum load capacity P on the envelope E max And, 0.9 × maximum load-bearing capacity P max (3) Draw a second straight line L2 connecting the two points. (4) Translate the second straight line L2 until it touches the envelope E, and make this the third straight line L3. (5) Set the load at the intersection of the first straight line L1 and the third straight line L3 to the yield strength P of the test specimen 6. y (5) Yield strength P y The relative displacement δ at the intersection of the fourth straight line L4, which is extended parallel to the horizontal axis, and the envelope E is defined as the yield displacement δ of the test specimen 6. y (6) The origin (0,0) and (δ) of the relationship between relative displacement δ and load. y , P y The fifth straight line L5 connecting () and () is defined as the shear stiffness k of the test specimen 6.

[0048] For each of the first test specimen 61 and the second test specimen 62, the shear stiffness and yield strength P were determined based on the relationship between the relative displacement δ obtained by the shear test and the load. y and maximum load-bearing capacity P max This is my assessment.

[0049] Table 1 shows the shear stiffness and yield strength P obtained by shear tests. y and maximum load-bearing capacity P max The coefficient of variation CV and are shown. The shear stiffness and yield strength P are shown in Table 1. y and maximum load-bearing capacity P max This is the average value of the six test subjects.

[0050] [Table 1]

[0051] First allowable shear strength j q0 is the yield strength P of the first test specimen 61.y and maximum load-bearing capacity P max Based on the variation coefficient β, the yield strength P of the first test specimen 61 is calculated using the following formula (5). In formula (5), y and maximum load-bearing capacity P max The average value of the 6 first test specimens 61 can be used. Second allowable shear strength j q 90 The yield strength P of the first test specimen 61 is y and maximum load-bearing capacity P max Based on the variation coefficient β, the yield strength P of the second test specimen 62 is calculated using the following formula (6). In formula (6), the yield strength P of the second test specimen 62 is calculated. y and maximum load-bearing capacity P max The average value of 62 second test subjects can be used.

[0052] Allowable shear strength of test specimen 6 (1st allowable shear strength) j q0 and second allowable shear strength j q 90 ) is, for example, the yield strength P of test specimen 6. y The value obtained by multiplying by the variation coefficient β, and the maximum load-bearing capacity P of test specimen 6. max The smaller of the following two values ​​is used: ×2 / 3 multiplied by the variation coefficient β. By using the smaller of these two values, it becomes possible to evaluate the allowable shear strength of test specimen 6 on the safe side.

[0053]

number

[0054]

number

[0055] The coefficient of variability β is expressed, for example, by the following formula (7), assuming the population distribution is a normal distribution and based on the 50% lower tolerance at a 75% confidence level derived from statistical processing.

[0056]

number

[0057] Here, it is customary to use the 95% lower allowable limit at a 75% confidence level for joint and connection tests, and the 50% lower allowable limit at a 75% confidence level for full-scale tests using full-scale structural frames. In this regard, since the evaluation of the full-scale test is divided into two processes in the present invention, it is deemed appropriate to follow the evaluation of the full-scale test. Therefore, in this embodiment, the 50% lower allowable limit at a 75% confidence level is used. This makes it possible to evaluate the allowable shear strength of the test specimen 6 in a manner closer to that of a full-scale test.

[0058] Based on Table 1 and equations (5) to (7), the first allowable shear strength is determined as a result of the shear test. j q0 and the first shear stiffness j k0 and the second allowable shear strength j q 90 And, the second shear stiffness j k 90 The results are shown in Table 2. The test results of the shear test are the allowable shear strength of joint 5, which will be described later. j It is used in calculation step S310 to calculate q.

[0059] [Table 2]

[0060] <Model creation process S210> In the model creation step S210, the calculation unit 12 creates a finite element analysis model M. The finite element analysis model M is used in the calculation step S310, described later, to calculate the amount of rotation of the principal stress at the joint 5 with respect to the fiber direction of the wooden member 3. If the finite element analysis model M has already been created, the model creation step S210 can be omitted.

[0061] The finite element analysis model M can be created using known finite element analysis software. In this embodiment, finite element analysis is performed using Marc, a nonlinear finite element analysis software from MSCSoftware. As shown in Figure 6, the finite element analysis model M models the horizontal plane of the structural frame 1, with the joint 5 between the wooden member 3 and the deck plate 4 being a spring element. In addition, the finite element analysis model M uses the wooden member 3 as a beam element, the deck plate 4 as a shell element, and the joints between the deck plates 4 as spring elements. The spring elements are arranged at two locations in each valley in the width direction of the deck plate 4 (average interval of 150 mm) and at 150 mm intervals in the longitudinal direction of the deck plate 4. Similarly, the joints between the deck plates 4 are also spaced at 150 mm intervals. The number of spring elements in the first direction X of the joint 5 of the finite element analysis model M jh Let n be the number in the second direction Y. jv Let n be the value.

[0062] In the finite element analysis model M described above, the spring elements at the joint 5 between the wooden member 3 and the deck plate 4 were spaced at 150 mm intervals, but they can also be set in a range of, for example, 50 mm to 600 mm. Similarly, in the finite element analysis model M described above, the spring elements at the joints between the deck plates 4 were spaced at 150 mm intervals, but they can also be set in a range of, for example, 50 mm to 600 mm.

[0063] The boundary conditions were set as a monotonic load that imposed a forced displacement in the first direction X on one wooden member 31, and the other wooden member 31 was fixed. The joint part of the wooden member 3 was a pin joint, which restricted the out-of-plane displacement in the height direction Z.

[0064] The analysis variables were set as the aspect ratio H / L of the horizontal plane, with three specifications of H / L = 0.33, 1.0, and 3.0 (models M-1 to M-3). The length L in the first direction X of the horizontal plane was unified to 3,000 mm, and the lengths H in the second direction Y of the horizontal plane were 1,000 mm, 3,000 mm, and 9,000 mm. Table 3 shows a list of the finite element analysis models M in this embodiment.

[0065]

Table 3

[0066] <Calculation step S310> In the calculation step S310, the allowable shear strength j q of the joint part 5 is calculated by reflecting the test results of the test specimen 6 in the finite element analysis model M. In the calculation step S310, an operator inputs various information such as the test results of the test specimen 6 obtained in the shear test step S110 into the computer (calculation device 100) in which the finite element analysis model M created in the model creation step S210 is stored. In the calculation step S310, the acquisition unit 11 acquires various information such as the test results of the test specimen 6 in the computer, and the calculation unit 12 calculates the allowable shear strength j q of the joint part 5. In the calculation step S310, by reflecting various information such as the test results of the test specimen 6 in the finite element analysis model M, the calculation unit 12 calculates the allowable shear strength j q of the joint part 5.

[0067] The calculation step S310 includes a first step S311, a second step S312, a third step S313, a fourth step S314, and a fifth step S315.

[0068] <<First step S311>> In the first step S311, based on the first shear property, the second shear property, and the first aspect ratio H / L of the horizontal plane, the amount of rotation Δθ of the principal stress direction of the joint 5 with respect to the fiber direction of the wooden member 3 is calculated by finite element analysis. The amount of rotation Δθ is used in the second step S312 for calculating the allowable shear strength correction value of the joint 5 described later. The aspect ratio for performing the finite element analysis is also referred to as the first aspect ratio H / L. j q θ is used.

[0069] First, in the first step S311, a computer storing the finite element analysis model M acquires the test results of the test specimen 6. The shear rigidity of the spring element of the joint 5 is the first shear rigidity j [[ID=]10]k0 and the second shear rigidity j k 90 of the test specimen 6 in the test results obtained by the shear test step S110 are used.

[0070] ]] Regarding the spring element of the joint 5 in the finite element analysis model M, it is modeled by a two-directional spring having a restoring force in the fiber direction and the direction orthogonal to the fiber axis of the wooden member 3. Here, it is premised that the material axis direction of the wooden member 3 is along the fiber direction, and the direction orthogonal to the material axis of the wooden member 3 is along the direction orthogonal to the fiber. Therefore, in the first step S311, the acquired first shear rigidity j k0 is set as the shear rigidity in the material axis direction (fiber direction) of the spring element of the joint 5 of the wooden member 3. Also, in the first step S311, the acquired second shear rigidity j k 90 is set as the shear rigidity in the direction orthogonal to the material axis (direction orthogonal to the fiber) of the spring element of the joint 5 of the wooden member 3.

[0071] Also, regarding the spring element of the joint between the deck plates 4, it is modeled by a one-directional spring having a restoring force in the second direction Y corresponding to the direction in which the deck plate 4 is displaced by an external force. The shear rigidity of the spring element of the joint between the deck plates 4 is set to be larger than the shear rigidity of the spring element of the joint 5 so that the deformation of the joint 5 between the wooden member 3 and the deck plate 4 becomes dominant. Table 4 shows a list of the shear rigidities of the spring elements.

[0072] [Table 4]

[0073] Next, in the first step S311, the amount of rotation Δθ in the principal stress direction of the joint 5 relative to the fiber direction of the wooden member 3 is calculated by finite element analysis using the finite element analysis model M, based on the first shear characteristics, the second shear characteristics, and the first aspect ratio H / L of the horizontal structural plane. In the first step S311, the amount of rotation Δθ is calculated for each of the joints 5 of models M-1 to M-3.

[0074] Figure 7(a) shows the relationship between the position of the joint 5 of the upper wooden member 31 and the absolute value of the rotation amount Δθ, and Figure 7(b) shows the relationship between the position of the joint 5 of the lower wooden member 31 and the absolute value of the rotation amount Δθ. Figure 8(a) shows the relationship between the position of the joint 5 of the left wooden member 32 and the absolute value of the rotation amount Δθ, and Figure 8(b) shows the relationship between the position of the joint 5 of the right wooden member 32 and the absolute value of the rotation amount Δθ.

[0075] As shown in Figures 7 and 8, in each side, the absolute value of the rotation amount Δθ is distributed around 0° near the center, confirming that the fiber direction of the wooden member 3 (the direction of the material axis of the wooden member 3) coincides with the direction of the shear force. As you approach the ends, the absolute value of the rotation amount Δθ increases, confirming that the direction of the shear force creates a constant angle with respect to the fiber direction of the wooden member 3. Furthermore, it can be confirmed that the absolute value of the rotation amount Δθ near the ends is larger in the direction of the shorter side of the aspect ratio H / L.

[0076] <<Second process S312>> The second step S312 is the first allowable shear strength j q0 and second allowable shear strength j q 90 Based on the absolute value of the rotation amount Δθ, the principal stress of the joint 5 is corrected in the direction of the fibers to obtain the allowable shear strength correction value. j q θ The following is calculated. Figure 9 shows the allowable shear strength correction value for joint 5. j q θAn example of this concept is shown. As shown in Figure 9, the principal stress at the joint 5 is corrected in the direction of the wood fibers of the wooden member 3 to obtain the allowable shear strength correction value. j q θ It will be evaluated as such.

[0077] Allowable shear strength correction value j q θ Based on the description in "Design Standards for Timber Structures and Commentary - Allowable Stress and Allowable Load-Bearing Capacity Design Method -" published by the Architectural Institute of Japan in December 2006, pp. 217-218, the first allowable shear strength j q0 and second allowable shear strength j q 90 Based on the absolute value of the rotation amount Δθ, the following formula (8) is used to calculate the allowable shear strength correction value. j q θ This is calculated for each joint 5.

[0078]

number

[0079] <<3rd process S313>> Step 3, S313, is the allowable shear strength correction value. j q θ and the first allowable shear strength j q0 and number of joints j Based on n, the strength correction coefficient α corresponding to the first aspect ratio is calculated using the following formula (9). In the following formula (9), the allowable shear strength correction value of each joint 5 is used. j q θ The first allowable shear strength is calculated by averaging and summing the values ​​by the number of joints 5. j The value obtained by dividing by q0 is defined as the strength correction coefficient α. The number of joints 5 in equation (9) jn is the number of spring elements in the joint 5 of the finite element analysis model M.

[0080]

number

[0081] Table 5 shows the number of joints 5 in Model M-1. j n and Σ Allowable shear strength correction value j q θ / j n and the load-bearing strength correction coefficient α are shown. Table 6 shows the number of joints 5 in model M-2. j n and Σ Allowable shear strength correction value j q θ / j n and the load-bearing strength correction coefficient α are shown. Table 7 shows the number of joints 5 in model M-3. j n and Σ Allowable shear strength correction value j q θ / j n and the load-bearing strength correction coefficient α are shown.

[0082] [Table 5]

[0083] [Table 6]

[0084] [Table 7]

[0085] Figure 10(a) shows the relationship between the first aspect ratio of the horizontal structural plane and the load-bearing strength correction coefficient α of the joint 5 in the wooden member 31. Figure 10(b) shows the relationship between the first aspect ratio of the horizontal structural plane and the load-bearing strength correction coefficient α of the joint 5 in the wooden member 32. In the third step S313, the relationship between the first aspect ratio of the horizontal structural plane and the load-bearing strength correction coefficient α may be evaluated, for example, as a regression equation, and a load-bearing strength correction coefficient α corresponding to the arbitrary aspect ratio may be calculated based on the evaluated regression equation and an arbitrary aspect ratio. For example, using the above models M-1 to M-3, Regression equation (upper and lower sides): Strength correction coefficient α = 0.8894 × (aspect ratio H / L) -0.042 Regression equation (left and right sides): Strength correction coefficient α = 0.0279 × ln{(aspect ratio H / L)} + 0.9708 This is obtained. Note that the regression equation can be a curve or a straight line.

[0086] Table 8 shows the load-bearing strength correction coefficient α according to the aspect ratio based on the regression equation.

[0087] [Table 8]

[0088] As shown in Table 8, based on the evaluated regression equation and an arbitrary aspect ratio, a strength correction coefficient α corresponding to that arbitrary aspect ratio can be calculated. In other words, even for any aspect ratio H / L other than the first aspect ratio H / L (0.33, 1.0, 3.0) used in the finite element analysis, a strength correction coefficient α corresponding to the aspect ratio can be calculated.

[0089] In the third step S313, for a predetermined aspect ratio H / L (for example, aspect ratio H / L = 1.0), the strength correction coefficient α calculated by formula (9) and the strength correction coefficient α calculated based on the regression equation can be obtained. In this case, it is preferable to use the smaller of the strength correction coefficient α calculated by formula (9) and the strength correction coefficient α calculated based on the regression equation. This allows the allowable shear strength of the joint 5, which will be described later. jThis allows us to calculate q using a conservative approach.

[0090] <<4th process S314>> The fourth step S314 is the first allowable shear strength j Based on q0 and the strength correction coefficient α, the allowable shear strength of the joint 5 j q is calculated using the following formula (4).

[0091]

number

[0092] <<5th process S315>> Step 5, S315, is the allowable shear strength of the joint 5. j Based on q and the number of joints 5 on the wooden member 3, the allowable shear strength of the horizontal structural plane g Q is calculated using the following formulas (1) to (3).

[0093] In detail, step 5 S315 is the allowable shear strength of joint 5 j q and the number of joints 5 on the wooden member 31 jh Based on n, the allowable shear strength due to horizontal deformation of the joint 5 between the wooden member 31 of the horizontal structural plane and the deck plate 4 jh Q is calculated using the following formula (2). Also, the fifth step S315 is the allowable shear strength of the joint 5. j q and the number of joints 5 on the wooden member 32 jv Based on n and the aspect ratio H / L, the allowable shear strength due to horizontal deformation of the joint 5 between the wooden member 32 and the deck plate 4 in the horizontal structural plane. jv Q is calculated using the following formula (3). Then, the fifth step S315 is the allowable shear strength calculated using formula (2). jh Q and the allowable shear strength calculated by formula (3) jv The smaller of Q and is the allowable shear strength of the horizontal plane. g Q is calculated using the following formula (1). The number of joints 5 in formula (2). jh n and the number of joints 5 in equation (3). jvn is the number of joints 5 in the structural frame 1 that should actually be constructed.

[0094]

number

[0095] This completes one example of a method for calculating allowable shear strength.

[0096] Next, the validity of the allowable shear strength calculated using the allowable shear strength calculation method according to the present invention will be explained by comparing it with the allowable shear strength obtained from full-scale tests.

[0097] Figure 11 shows an outline of full-scale test specimen 8. For the full-scale test, specimen 8 was L=3000mm × H=3072.5mm, with an aspect ratio H / L=1.0. Deck plates (1.2mm thick, 50mm deep) were used for the surface material, and cedar lumber (ungraded, 105mm × 150mm) was used as the support members. The mechanical properties of the deck plates included a yield strength of 345 (N / mm²). 2 ), tensile strength is 464 (N / mm²). 2 The elongation was 36.4%. The deck plate and support members were joined at 200 mm intervals using drilling tapping screws (φ6-50 mm). Number of joints between the support members and the deck plate in the width direction of the deck plate (first direction X) jhLet n=15, and the number of joints between the support member and the deck plate in the deck plate span direction (second direction Y). jv n=14. The deck plates were joined together at 200mm intervals using drilling tapping screws (φ6-19mm). The joints were secured with two short tenon N90 nails and hold-down hardware to prevent premature failure of the joints.

[0098] The full-scale test was conducted in accordance with the test method described in Non-Patent Literature 1 (edited by the Committee for the Revision of Allowable Stress Design for Wooden Frame Construction Houses, "Allowable Stress Design for Wooden Frame Construction Houses (2017 Edition)," published by the Japan Housing and Wood Technology Center, March 2017, see pp. 298-299). The full-scale test was conducted using alternating positive and negative loading, similar to the tests used to calculate the stiffness and allowable shear strength of the vertical and horizontal structural planes. The lower part of the support member was fixed, and a forced displacement was applied to the upper part of the support member under load. The apparent shear deformation angle γ (rad) was set to 1 / 450, 1 / 300, 1 / 200, 1 / 150, 1 / 100, 1 / 75, and 1 / 50, three times each, and the load was applied until it decreased to 80% of the maximum load. Displacement measurements were taken by measuring the horizontal displacement δ1 of one support member (the support member to which forced displacement was applied), the horizontal displacement δ2 of the other support member, and the vertical displacements δ3 and δ4 of the other support member. The shear deformation angle shown in the following equations (10) to (12) was calculated. Note that δ1 and δ2 are the average values ​​of the two measurement points.

[0099]

number

[0100] In this full-scale test, an envelope was created for the full-scale test specimen 8, and the allowable shear strength of the horizontal plane (referred to as the allowable shear strength according to the comparative example) was calculated. The allowable shear strength according to the comparative example was calculated from the load-deformation angle curve on the side that ultimately failed under alternating positive and negative loading, using the method described in Non-Patent Literature 1 (edited by the Committee for Revision of Allowable Stress Design for Wooden Frame Construction Houses, "Allowable Stress Design for Wooden Frame Construction Houses (2017 Edition)," published by the Japan Housing and Wood Technology Center, March 2017, see pp. 300-301). Yield strength P from this full-scale test y This was used as the allowable shear strength based on the comparative example.

[0101] In the comparative example, a load reduction occurred after the true shear deformation angle γ0 exceeded 1 / 100 rad, and the loading was terminated. As a result, the allowable shear strength in the comparative example was 33.3 kN.

[0102] On the other hand, the allowable shear strength of the horizontal structure according to the present invention g When calculating Q, Model M-2 with an aspect ratio H / L = 1.0 was used. Referring to Table 6, the strength correction coefficient α = 0.898 was set for the joint 5 on the wooden member 31, and the strength correction coefficient α = 0.971 was set for the joint 5 on the wooden member 32. Referring to Table 2, the first allowable shear strength j We set q0 = 2.56 (kN).

[0103] Referring to formula (4) above, the allowable shear strength of the joint 5 on the wooden member 31 j q = 2.56 (kN) × 0.898 = 2.30 (kN). Referring to the above formula (4), the allowable shear strength of the joint 5 on the wooden member 32. j q = 2.56 (kN) × 0.971 = 2.49 (kN). In this way, the allowable shear strength per joint 5 on the model is obtained using the finite element analysis model M. j Calculate q.

[0104] Allowable shear strength of horizontal structural planes according to the present invention gQ is calculated using the above formulas (1) to (3). As described above, in the full-scale test specimen 8 as a comparative example, the number of joints between the support member and the deck plate in the deck plate width direction (first direction X) jh n=15. Therefore, referring to equation (2), jh Q = 2.30 (kN) × 15 = 34.5 (kN). Similarly, in the full-scale test specimen 8 as a comparative example, the number of joints between the support member and the deck plate in the deck plate span direction (second direction Y) is jn = 14. Therefore, referring to formula (3), jv Q = 2.49 (kN) × 14 × 1.0 = 34.9 (kN). In this invention, the calculated allowable shear strength is... j q is assumed to be the allowable shear strength per joint 5 of the actual structural frame 1. Therefore, the calculated allowable shear strength of joint 5 is j q and the number of joints 5 in the structural frame 1 (full-scale test specimen 8 in the above example) that should actually be calculated. j By multiplying n by , the allowable shear strength of the horizontal structure is obtained. jh Q and allowable shear strength jv Calculate Q and Q respectively.

[0105] Refer to formula (1) and determine the allowable shear strength of the horizontal structural plane according to the present invention example. g Q = 34.5 (kN).

[0106] Table 9 shows the allowable shear strength according to the present invention. g Q and the allowable shear strength according to the comparative example are shown.

[0107] [Table 9]

[0108] From Table 9, the allowable shear strength for the comparative example is 33.3 (kN), and the allowable shear strength for the present invention example is 33.3 (kN). g Q is 34.5 (kN), and the allowable shear strength according to the comparative example is the allowable shear strength according to the present invention example. g It was 0.97 times Q. Therefore, according to the present invention, the allowable shear strength of the horizontal structural planeg It was confirmed that Q could be evaluated accurately through actual university-level testing.

[0109] According to this embodiment, the calculation step S310 calculates the allowable shear strength of the joint 5 based on the test results of the test specimen and the finite element analysis model M. j q is calculated by computer. This reduces the effort required to conduct full-scale tests and allows for the calculation of the allowable shear strength of joint 5. j q can be calculated. Therefore, the required effort can be reduced.

[0110] According to this embodiment, the calculation step S310 reflects the test results of the test specimen 6 into the finite element analysis model M, thereby determining the allowable shear strength of the joint 5. j Calculate q. This will give the allowable shear strength of joint 5. j q can be calculated with high accuracy. Therefore, it is possible to calculate the allowable shear strength of structural frame 1 with high accuracy.

[0111] According to this embodiment, the test results of the test specimen 6 include the first shear characteristics in the fiber direction of the wooden member of the test specimen 6 and the second shear characteristics in the direction perpendicular to the fiber of the wooden member of the test specimen 6, and the calculation step S310 calculates the allowable shear strength of the joint 5 based on the first shear characteristics, the second shear characteristics and the finite element analysis model M. j q is calculated. This allows the allowable shear strength of the joint 5 considering the anisotropy of the wooden member 3. j q can be calculated. Therefore, it becomes possible to calculate the allowable shear strength of structural frame 1 with higher accuracy.

[0112] According to this embodiment, the calculation step S310 calculates the allowable shear strength of the joint 5 based on the aspect ratio H / L of the horizontal structural plane. j q is calculated. This gives the allowable shear strength of joint 5 considering the aspect ratio H / L of the horizontal plane. j q can be calculated. This reduces the effort required to conduct full-scale tests according to the aspect ratio. Therefore, it becomes possible to further reduce the required effort.

[0113] According to this embodiment, the aspect ratio H / L is 0.33 or more and 3.0 or less. This allows the allowable shear strength of the joint 5 considering the aspect ratio H / L which is commonly used as a horizontal structural plane. j q can be calculated. Therefore, the required effort can be further reduced.

[0114] According to this embodiment, the calculation process S310 is further preceded by a shear test process S110 in which a shear test is performed on the test specimen 6. This allows the allowable shear strength of the joint 5 to be determined based on the test results of the shear test. j q can be calculated. Therefore, it becomes possible to calculate the allowable shear strength of structural frame 1 with higher accuracy.

[0115] According to this embodiment, the first allowable shear strength j Based on q0 and the strength correction coefficient α, the allowable shear strength of the joint 5 j q is calculated. This gives the allowable shear strength of joint 5 based on finite element analysis. j q can be calculated with high accuracy relative to the allowable shear strength determined by full-scale testing. Therefore, it becomes possible to appropriately calculate the allowable shear strength of structural frame 1.

[0116] According to this embodiment, calculation step S310 evaluates the relationship between a plurality of first aspect ratios H / L and a strength correction coefficient α corresponding to the first aspect ratio H / L, and calculates a strength correction coefficient α corresponding to the second aspect ratio H / L based on the evaluated relationship and an arbitrary second aspect ratio H / L. This makes it possible to calculate the allowable shear strength even for arbitrary second aspect ratios that do not require finite element analysis. Therefore, it is possible to further reduce the required labor.

[0117] According to this embodiment, the second allowable shear strength is the smaller of the following two values: the yield strength in the fiber direction of the wooden member of the test specimen 6 multiplied by the variation coefficient β, and the value obtained by multiplying 2 / 3 of the maximum strength by the variation coefficient β. The second allowable shear strength is the smaller of the following two values: the yield strength in the direction perpendicular to the fibers of the wooden member of the test specimen 6 multiplied by the variation coefficient β, and the value obtained by multiplying 2 / 3 of the maximum strength by the variation coefficient β. This makes it possible to evaluate the allowable shear strength of the test specimen 6 in a manner closer to that of a full-scale test. Therefore, it becomes possible to calculate the allowable shear strength of the structural frame 1 with higher accuracy.

[0118] According to this embodiment, the allowable shear strength of the joint 5 j q and the number of joints 5 on the wooden member 3. j Based on n, the allowable shear strength of the horizontal structural plane g Q is calculated. This makes it possible to express the allowable shear strength of the horizontal structural plane, which was previously calculated from full-scale test results, as a mathematical formula. g It becomes possible to calculate Q numerically. Therefore, the required effort can be further reduced.

[0119] Furthermore, according to this embodiment, the allowable shear strength of the joint 5 j q and the number of joints 5 on the wooden member 3. j Based on n, the allowable shear strength of the horizontal structural plane g Calculate Q. Allowable shear strength per joint 5. j Since q has been calculated, even if the number of joints 5 is changed, the allowable shear strength of the horizontal structure can be easily adjusted according to the number of joints 5. g Q can be calculated.

[0120] Next, we will describe an example of a method for constructing the structural frame. Figure 14 shows an example of a flowchart for constructing the structural frame.

[0121] The method for constructing the structural frame is to construct a structural frame 1 having a horizontal plane composed of a framework structure 2 made of wooden members 3 and deck plates 4.

[0122] The method for constructing a structural frame comprises a calculation step S310, a determination step S410, a setting step S510, and a construction step S610. The method for constructing a structural frame may further include, for example, a shear test step S110 and a model creation step S210. Regarding the shear test step S110, the model creation step S210, and the calculation step S310, explanations will be omitted as appropriate if they are the same as those for the allowable shear strength calculation method described above.

[0123] <Judgment step S410> The determination step S410 determines the allowable shear strength of the horizontal structure calculated in the calculation step S310. g It is determined whether Q exceeds the shear force Q required for the horizontal structural plane. In the determination step S410, the allowable shear strength of the horizontal structural plane is determined. g If Q exceeds the shear force Q required for the horizontal structural plane, the next setting step S510 is performed. In the determination step S410, the allowable shear strength of the horizontal structural plane is determined. g If Q does not exceed the shear force Q required for the horizontal plane, the number of joints 5 as a construction condition. j Change at least one of n and the aspect ratio H / L, and perform calculation step S310 again to calculate the allowable shear strength of the horizontal structure. g Calculate Q. Allowable shear strength of the horizontal plane. g If Q does not exceed the shear force Q required for the horizontal structural frame, the conditions are changed as appropriate, and the shear test process S110 and model creation process S210 are repeated, followed by the calculation process S310 to determine the allowable shear strength of the horizontal structural frame. g Q may be calculated. In this way, in the determination step S410, the allowable shear strength of the horizontal plane as the inherent performance of the structural frame 1 is calculated. g It is determined whether Q exceeds the shear force Q of the horizontal plane, which is the required performance of the structural frame 1. The shear force Q required for the horizontal plane is set appropriately based on external forces such as seismic forces acting on the structural frame 1.

[0124] <Setting process S510> Setting process S510 is the allowable shear strength of the horizontal structural plane. gIf Q exceeds the shear force Q required for the horizontal plane, construction conditions are set for constructing the structural frame 1. The construction conditions include, for example, the number of joints 5. j n includes the aspect ratio H / L.

[0125] Setting process S510 is to set the allowable shear strength of the horizontal structural frame to exceed the shear force Q required for the horizontal structural frame. g Q and the allowable shear of the joint 5 calculated in calculation step S310 j Based on q, the number of joints 5 is the construction condition. j n( jh n, jv Set n). Setting step S510 is, for example, the number of joints 5. j n≧ g Q / j Based on q, the number of joints 5 is a construction condition. j Set n. In setting step S510, j n≧ g Q / j Number of joints 5 that satisfy q j By setting a value greater than the minimum natural number of n, it becomes possible to incorporate a safety factor in the design of the structural frame 1, for example. Setting process S510 is, for example g Q / j If q = 13.5, the construction condition is the number of joints 5. j n≧14 is sufficient. In this case, setting step S510 is, for example, the number of joints 5. jh n=15, number of joints 5 jv Set n=14 as the construction condition.

[0126] Setting process S510 is to set the allowable shear strength of the horizontal structural frame to exceed the shear force Q required for the horizontal structural frame. g The aspect ratio H / L associated with Q is set as a construction condition. Setting process S510 determines the allowable shear strength of the joint 5 based on the strength correction coefficient α when the aspect ratio H / L = 1.0, for example. j Calculate q and the allowable shear strength of the calculated joint 5 j Allowable shear strength of the horizontal structure based on q g Q( jh Q, jvWhen Q) is calculated, the allowable shear strength of the horizontal structural plane g The aspect ratio H / L = 1.0 is set as the construction condition for the aspect ratio H / L associated with Q.

[0127] <Construction process S610> In the construction process S610, the structural frame 1 is constructed based on the construction conditions set in the setting process S510.

[0128] Construction step S610 is the number of joints set in setting step S510 j A structural frame 1 satisfying n is constructed. Construction step S610 is, for example, the number of joints 5 in setting step S510. jh n=15, number of joints 5 jv When n=14 is set as a construction condition, the number of joints 5 jh n=15, number of joints 5 jv Construct a structural frame 1 that satisfies n=14.

[0129] Construction process S610 constructs a structural frame 1 that satisfies the aspect ratio H / L set in setting process S510. If aspect ratio H / L=1.0 was set as a construction condition in setting process S510, construction process S610 constructs a structural frame 1 that satisfies aspect ratio H / L=1.0.

[0130] In particular, according to this embodiment, the determination step S410 determines the allowable shear strength of the calculated horizontal structural plane g The setting process S510 determines whether Q exceeds the shear force Q required for the horizontal structural frame, and sets the allowable shear strength of the horizontal structural frame that exceeds the shear force Q required for the horizontal structural frame. g Q and the allowable shear strength of joint 5 j Based on q, the number of joints 5 is a construction condition when constructing the structural frame 1. j n( jh n, jv n) is set, and the construction process S610 is performed by setting the number of joints set in the setting process S510. j A structural frame 1 that satisfies n is constructed. This results in the number of joints 5. jEven when changing n, the effort required to conduct full-scale tests can be reduced, and the allowable shear strength of the horizontal structure can be calculated. g It is possible to quickly determine whether Q exceeds the shear force Q required for the horizontal structural plane. This reduces the amount of labor required. Furthermore, it becomes possible to construct a structural frame 1 that meets the required performance.

[0131] In particular, according to this embodiment, the determination step S410 determines the allowable shear strength of the calculated horizontal structural plane g The setting process S510 determines whether Q exceeds the shear force Q required for the horizontal structural frame, and sets the allowable shear strength of the horizontal structural frame that exceeds the shear force Q required for the horizontal structural frame. g The aspect ratio H / L associated with Q is set as a construction condition, and in construction process S610, a structural frame 1 is constructed that satisfies the aspect ratio H / L set in setting process S510. This reduces the effort required to conduct full-scale tests even when the aspect ratio H / L is changed, and the allowable shear strength of the horizontal frame is calculated. g It is possible to quickly determine whether Q exceeds the shear force Q required for the horizontal structural plane. This reduces the amount of labor required. Furthermore, it becomes possible to construct a structural frame 1 that meets the required performance.

[0132] While embodiments of this invention have been described above, these embodiments are presented as examples and are not intended to limit the scope of the invention. Furthermore, this invention can be implemented in various novel forms in addition to the embodiments described above. Therefore, the above embodiments can be omitted, replaced, or modified in various ways without departing from the spirit of this invention. Such novel forms and modifications are included in the scope and spirit of this invention, as well as in the invention described in the claims and its equivalents. [Explanation of Symbols]

[0133] 1: Structural frame 2: Framing structure 3: Wooden components 31: Wooden components 32: Wooden components 4: Deck Plate 5: Joint 6: Test specimen 61: First test specimen 62: Second test specimen 63: Wood piece 64: Steel plate 65:Joint tool 8: Full-scale test specimen M: Finite element analysis model S110: Shear test process S210: Model creation process S310: Calculation process S311: 1st process S312: 2nd process S313: 3rd process S314: 4th process S315: 5th process S410: Judgment process S510: Setting process S610: Construction process X: 1st direction Y: Second direction Z: Height direction

Claims

1. A method for calculating the allowable shear strength of a structural frame having a horizontal plane composed of a frame structure made of wooden members and a deck plate, The system includes a calculation process for calculating the allowable shear strength of a joint based on the test results of a test specimen simulating the joint between a wooden member and a deck plate, and an analytical model that uses the joint between the wooden member and the deck plate as an element. The aforementioned test results are as follows: The first shear characteristics of the wooden member of the test specimen in the fiber direction, The second shear characteristic of the wooden member of the test specimen in the direction perpendicular to the fibers, The calculation step involves calculating the allowable shear strength of the joint based on the first shear characteristics, the second shear characteristics, and the analysis model. A method for calculating allowable shear strength characterized by the following.

2. The calculation process described above is: The allowable shear strength of the joint is calculated by reflecting the above test results in the above analysis model. A method for calculating the allowable shear strength according to claim 1, characterized by the above.

3. The calculation process involves calculating the allowable shear strength of the joint based on the aspect ratio of the horizontal structural plane. A method for calculating the allowable shear strength according to claim 2, characterized by the above.

4. The aspect ratio is between 0.33 and 3.

0. A method for calculating the allowable shear strength according to claim 3, characterized by the above.

5. The calculation step is further further comprising a shear test step in which a shear test is performed on the test specimen to obtain the test results. A method for calculating the allowable shear strength according to claim 1, characterized by the above.

6. The aforementioned test results are as follows: The first shear characteristics of the wooden member of the test specimen, including the first allowable shear strength and the first shear stiffness, obtained by a shear test in the fiber direction of the wooden member of the test specimen, The second shear characteristics include the second allowable shear strength and second shear stiffness of the test specimen, obtained by shear testing the wooden member of the test specimen in the direction perpendicular to the fibers, The calculation process described above is: Based on the first shear characteristics, the second shear characteristics, and the first aspect ratio of the horizontal structural plane, the amount of rotation in the principal stress direction of the joint with respect to the fiber direction of the wooden member is calculated using the analysis model. Based on the first allowable shear strength, the second allowable shear strength, and the absolute value of the amount of rotation, an allowable shear strength correction value is calculated by correcting the principal stress of the joint in the direction of the wood fibers of the wooden member. Based on the first allowable shear strength and the allowable shear strength correction value, a strength correction coefficient corresponding to the first aspect ratio is calculated. The allowable shear strength of the joint is calculated based on the first allowable shear strength and the strength correction coefficient. A method for calculating the allowable shear strength according to claim 1, characterized by the above.

7. The calculation process described above is: The relationship between a plurality of the first aspect ratios and the load-bearing strength correction coefficient corresponding to the first aspect ratio is evaluated. Based on the evaluated relationship and an arbitrary second aspect ratio, the yield strength correction coefficient corresponding to the second aspect ratio is calculated. A method for calculating the allowable shear strength according to claim 6, characterized by the above.

8. The first allowable shear strength is the smaller of the following two values: the yield strength in the fiber direction of the wooden member of the test specimen multiplied by the variation coefficient β of the following formula (7), and the value obtained by multiplying 2 / 3 of the maximum strength by the variation coefficient β. The second allowable shear strength is the smaller of the following two values: the yield strength in the direction perpendicular to the fibers of the wooden member of the test specimen multiplied by the variation coefficient β, and the value obtained by multiplying 2 / 3 of the maximum strength by the variation coefficient β. A method for calculating the allowable shear strength according to claim 6 or 7, characterized by the above. [Math 11] (Here, β is the coefficient of variation, and the coefficient of variation CV is the standard deviation / mean, k 50% This is a coefficient used to determine the 50% lower limit of tolerance at a 75% confidence level.

9. The calculation step involves calculating the allowable shear strength of the horizontal structural plane based on the allowable shear strength of the joint and the number of joints on the wooden member. A method for calculating the allowable shear strength according to claim 6 or 7, characterized by the above.

10. A method for constructing a structural frame having a horizontal plane composed of a framework structure made of wooden members and deck plates, Based on the test results of a test specimen simulating the joint between a wooden member and a deck plate, and an analytical model using the joint between the wooden member and the deck plate as an element, the allowable shear strength of the joint was calculated. A calculation step of calculating the allowable shear strength of the horizontal structural plane based on the calculated allowable shear strength of the joint and the number of joints on the wooden member, A determination step of determining whether the calculated allowable shear strength of the horizontal structural plane exceeds the shear force required for the horizontal structural plane, If the allowable shear strength of the horizontal structural plane exceeds the shear force, a setting step is performed to set the construction conditions when constructing the structural frame, The process includes constructing the structural frame that satisfies the construction conditions set in the setting step, The setting step involves setting the number of joints as a construction condition based on the allowable shear strength of the horizontal structural plane and the allowable shear strength of the joints, which are greater than the shear force. The construction step involves constructing the structural frame that satisfies the number of joints set in the setting step, The aforementioned test results are as follows: The first shear characteristics of the wooden member of the test specimen in the fiber direction, The second shear characteristic of the wooden member of the test specimen in the direction perpendicular to the fibers, The calculation step involves calculating the allowable shear strength of the joint based on the first shear characteristics, the second shear characteristics, and the analysis model. A method for constructing a structural frame characterized by the following.

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