Method and apparatus for configuring a 2x EHT-STF sequence for broadband in a wireless LAN system

Abstract

To provide a method and device for receiving a PPDU in a wireless LAN system.SOLUTION: Specifically, a reception STA receives the PPDU from a transmission STA through a wideband and decodes the PPDU. The PPDU includes an STF signal. The STF signal is generated on the basis of a first STF sequence for the wideband. When the wideband is a 320 MHz band, the first STF sequence is a sequence including an M sequence and is defined as {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2).SELECTED DRAWING: Figure 24

Description

[Technical Field]

[0001] This specification relates to a technique for receiving PPDU over broadband in a wireless LAN system, and more specifically, to a method and apparatus for proposing an STF sequence that yields a PAPR optimized with consideration to RU or MRU. [Background technology]

[0002] Wireless local area networks (WLANs) have been improved in various ways. For example, the IEEE 802.11ax standard proposed an improved communication environment using OFDMA (orthogonal frequency division multiple access) and DL MU MIMO (downlink multi-user multiple input, multiple output) technologies.

[0003] This specification proposes technical features that can be utilized in new communication standards. For example, the new communication standard is the recently discussed EHT (Extreme High Throughput) standard. The EHT standard can utilize newly proposed bandwidth increases, improved PPDU (PHY layer protocol data unit) structures, improved sequencing, and HARQ (Hybrid automatic repeat request) technology. The EHT standard can be called the IEEE 802.11be standard.

[0004] New wireless LAN standards utilize an increased number of spatial streams. In this case, signaling techniques within the wireless LAN system need to be improved to properly utilize the increased number of spatial streams. [Overview of the Initiative] [Problems that the invention aims to solve]

[0005] This specification proposes a method and apparatus for configuring a 2x EHT-STF sequence for broadband in a wireless LAN system. [Means for solving the problem]

[0006] One example in this specification proposes a method for receiving PPDU over broadband.

[0007] This embodiment is implemented in a network environment that supports a next-generation wireless LAN system (IEEE 802.11be or EHT wireless LAN system). The next-generation wireless LAN system is an improved version of the 802.11ax system and can satisfy backward compatibility with the 802.11ax system.

[0008] This embodiment proposes a method for configuring 2x STF sequences that are mapped to RU or MRU (Multi-RU) when transmitting TB PPDU over a wideband (240 MHz or 320 MHz).

[0009] The receiving STA (station) receives PPDU (Physical Protocol Data Unit) from the transmitting STA via broadband.

[0010] The receiving STA decodes the PPDU.

[0011] The aforementioned PPDU includes the STF (Short Training Field) signal.

[0012] The STF signal is generated based on the first STF sequence for the broadband.

[0013] When the broadband is a 320 MHz band, the first STF sequence is defined as a sequence including an M sequence as follows.

[0014] {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0015] In this case, sqrt() represents the square root.

[0016] The aforementioned M sequence is defined as follows. The aforementioned M sequence is the same as the M sequence defined in an 802.11ax wireless LAN system.

[0017] M={-1,-1,-1,1,1,1,-1,1,1,1,-1,1,1,-1,1} [Effects of the Invention]

[0018] According to the embodiments proposed herein, when transmitting TB PPDU over broadband, a novel effect is obtained in which an optimized PAPR can be obtained by proposing an EHT-STF sequence that takes into account the various RUs or MRUs defined in an 802.11be wireless LAN system. This has the effect of enabling the estimation of subcarrier efficiency and effective AGC (automatic gain control). [Brief explanation of the drawing]

[0019] [Figure 1] An example of a transmitting and / or receiving device as described herein is shown. [Figure 2] This is a conceptual diagram illustrating the structure of a wireless LAN (WLAN). [Figure 3] This is a diagram illustrating the normal link setup process. [Figure 4] This is a diagram showing an example of a PPDU used in IEEE standards. [Figure 5]This diagram shows the arrangement of resource units (RUs) used in the 20MHz bandwidth. [Figure 6] This diagram shows the arrangement of resource units (RUs) used in the 40MHz bandwidth. [Figure 7] This diagram shows the arrangement of resource units (RUs) used in the 80MHz bandwidth. [Figure 8] The structure of the HE-SIG-B field is shown. [Figure 9] This demonstrates an example where multiple User STAs are assigned to the same RU via MU-MIMO technology. [Figure 10] This shows the operation related to UL-MU. [Figure 11] An example of a trigger frame is shown. [Figure 12] An example of the common information field in a trigger frame is shown below. [Figure 13] An example of a subfield included in the per-user information field is shown below. [Figure 14] This section explains the technical characteristics of UORA technology. [Figure 15] An example of channels used / supported / defined within the 2.4GHz band is shown. [Figure 16] This shows an example of channels used / supported / defined within the 5GHz band. [Figure 17] This shows an example of channels used / supported / defined within the 6GHz band. [Figure 18] An example of a PPDU used in this specification is shown below. [Figure 19] The following are examples of modifications of the transmitting and / or receiving devices described herein. [Figure 20] This embodiment shows an example of 2x HE-STF tones in channel-specific PPDU transmission. [Figure 21] This diagram shows a 26+52RU combination in an 80MHz band tone plan. [Figure 22]This is a procedure flowchart illustrating the operation of the transmitting device according to this embodiment. [Figure 23] This is a procedure flowchart illustrating the operation of the receiving device according to this embodiment. [Figure 24] This flowchart illustrates the procedure by which the transmitting STA in this embodiment transmits a PPDU. [Figure 25] This flowchart illustrates the procedure by which the receiving STA according to this embodiment receives the PPDU. [Modes for carrying out the invention]

[0020] In this specification, "A or B" may mean "just A," "just B," or "both A and B." Furthermore, in this specification, "A or B" may be interpreted as "A and / or B." For example, in this specification, "A, B or C" may mean "just A," "just B," "just C," or "any combination of A, B and C."

[0021] In this specification, slashes ( / ) and commas can mean "and / or". For example, "A / B" can mean "A and / or B". Thus, "A / B" can mean "just A", "just B", or "both A and B". For example, "A, B, C" can mean "A, B or C".

[0022] In this specification, "at least one of A and B" can mean "just A," "just B," or "both A and B." Furthermore, in this specification, the expressions "at least one of A or B" and "at least one of A and / or B" can be interpreted in the same way as "at least one of A and B."

[0023] Furthermore, in this specification, "at least one of A, B and C" may mean "just A," "just B," "just C," or "any combination of A, B and C." Also, "at least one of A, B or C" or "at least one of A, B and / or C" may mean "at least one of A, B and C."

[0024] Furthermore, parentheses used in this specification can mean "for example." Specifically, when "control information (PDCCH)" is shown, "PDCCH" is proposed as an example of "control information." Also, "control information" in this specification is not limited to "PDCCH," and "PDDCH" is proposed as an example of "control information." Furthermore, when "control information (i.e., PDCCH)" is shown, "PDCCH" is proposed as an example of "control information."

[0025] In this specification, technical features described individually within a single drawing may be represented individually or simultaneously.

[0026] The following examples in this specification apply to various wireless communication systems. For example, the following examples in this specification apply to wireless LAN (wireless local area network, WLAN) systems. For example, this specification applies to the IEEE 802.11a / g / n / ac standards and the IEEE 802.11ax standard. This specification also applies to newly proposed EHT standards or IEEE 802.11be standards. Furthermore, the examples in this specification also apply to new wireless LAN standards that improve upon the EHT standards or IEEE 802.11be. In addition, the examples in this specification apply to mobile communication systems. For example, this specification applies to mobile communication systems based on LTE (Long Term Evolution) and its evolution based on 3GPP® (3rd Generation Partnership Project) standards. Furthermore, the examples in this specification apply to 5GNR standard communication systems based on 3GPP standards.

[0027] The following describes the technical features to which this specification applies in order to explain the technical features of this specification.

[0028] Figure 1 shows an example of a transmitting and / or receiving device as described herein.

[0029] An example in Figure 1 can perform various technical features described below. Figure 1 relates to at least one STA (station). For example, STA (110, 120) in this specification is referred to by various names such as mobile terminal, wireless device, Wireless Transmit / Receive Unit (WTRU), User Equipment (UE), Mobile Station (MS), Mobile Subscriber Unit, or simply user. STA (110, 120) in this specification is referred to by various names such as network, base station, node-B, access point (AP), repeater, router, relay. STA (110, 120) in this specification is referred to by various names such as receiving device, transmitting device, receiving STA, transmitting STA, receiving device, transmitting device.

[0030] For example, an STA(110, 120) can perform either an AP (Access Point) role or a non-AP role. That is, an STA(110, 120) as described herein can perform AP and / or non-AP functions. In this specification, AP may also be referred to as AP STA.

[0031] The STA(110, 120) described herein can support various communication standards other than the IEEE 802.11 standard. For example, it can support communication standards related to 3GPP standards (e.g., LTE, LTE-A, 5GNR standards). Furthermore, the STA described herein can be implemented in various devices such as mobile phones, vehicles, and personal computers. In addition, the STA described herein can support communication for various communication services such as voice calls, video calls, data communication, and autonomous driving.

[0032] In this specification, STA(110, 120) may include medium access control (MAC) and a physical layer interface to the wireless medium in accordance with the IEEE 802.11 standard.

[0033] Based on Figure 1(a), STA(110, 120) can be explained as follows.

[0034] The first STA(110) includes a processor (111), memory (112), and transceiver (113). The indicated processor, memory, and transceiver may each be implemented as separate chips, or at least two or more blocks / functions may be implemented via a single chip.

[0035] The transceiver (113) of the first STA performs signal transmission and reception operations. Specifically, it can transmit and receive IEEE 802.11 packets (e.g., IEEE 802.11a / b / g / n / ac / ax / be, etc.).

[0036] For example, the first STA (110) can perform the intended operation of the AP. For example, the AP's processor (111) can receive signals via the transceiver (113), process the received signals, generate transmit signals, and perform control for signal transmission. The AP's memory (112) can store signals received via the transceiver (113) (i.e., received signals) and signals transmitted via the transceiver (i.e., transmitted signals).

[0037] For example, the second STA (120) can perform the intended operation of a Non-AP STA. For example, a non-AP transceiver (123) can perform signal transmission and reception operations. Specifically, it can transmit and receive IEEE 802.11 packets (e.g., IEEE 802.11a / b / g / n / ac / ax / be, etc.).

[0038] For example, the Non-AP STA processor (121) can receive signals via the transceiver (123), process the received signals, generate transmit signals, and perform control for signal transmission. The Non-AP STA memory (122) can store signals received via the transceiver (123) (i.e., received signals) and signals transmitted via the transceiver (i.e., transmitted signals).

[0039] For example, in the following specification, the operation of the device indicated as AP is performed in the first STA(110) or the second STA(120). For example, if the first STA(110) is AP, the operation of the device indicated as AP is controlled by the processor(111) of the first STA(110), and the relevant signals are transmitted or received via a transceiver(113) controlled by the processor(111) of the first STA(110). In addition, control information related to the operation of AP and the AP's transmit / receive signals are stored in the memory(112) of the first STA(110). In addition, if the second STA(110) is AP, the operation of the device indicated as AP is controlled by the processor(121) of the second STA(120), and the relevant signals are transmitted or received via a transceiver(123) controlled by the processor(121) of the second STA(120). In addition, control information related to the operation of AP and the AP's transmit / receive signals are stored in the memory(122) of the second STA(110).

[0040] For example, in the following specification, the operation of a device indicated as non-AP (or User-STA) is performed in the first STA (110) or the second STA (120). For example, if the second STA (120) is non-AP, the operation of the device indicated as non-AP is controlled by the processor (121) of the second STA (120), and the relevant signals are transmitted or received via a transceiver (123) controlled by the processor (121) of the second STA (120). In addition, control information related to the operation of non-AP and AP transmit / receive signals are stored in the memory (122) of the second STA (120). For example, if the first STA (110) is non-AP, the operation of the device indicated as non-AP is controlled by the processor (111) of the first STA (110), and the relevant signals are transmitted or received via a transceiver (113) controlled by the processor (111) of the first STA (120). Furthermore, control information related to the operation of the non-AP and the AP's transmit / receive signals are stored in the memory (112) of the first STA (110).

[0041] In the following specification, devices referred to as (transmit / receive)STA, 1stSTA, 2ndSTA, STA1, STA2, AP, 1stAP, 2ndAP, AP1, AP2, (transmit / receive)Terminal, (transmit / receive)Device, (transmit / receive)apparatus, network, etc., mean the STA(110, 120) in Figure 1. For example, devices referred to as (transmit / receive)STA, 1stSTA, 2ndSTA, STA1, STA2, AP, 1stAP, 2ndAP, AP1, AP2, (transmit / receive)Terminal, (transmit / receive)Device, (transmit / receive)apparatus, network, etc., without specific designations, also mean the STA(110, 120) in Figure 1. For example, in the following example, the operation of various STAs sending and receiving signals (e.g., PPPDU) may be performed in the transceiver(113, 123) in Figure 1. Furthermore, in the following example, the operation of various STAs generating transmit / receive signals or performing data processing or calculations in advance for transmit / receive signals may be performed by the processor (111, 121) in Figure 1. For example, an example of the operation of generating transmit / receive signals or performing data processing or calculations in advance for transmit / receive signals may include: 1) the operation of determining / acquiring / composing / calculating / decoding / encoding bit information of subfields (SIG, STF, LTF, Data) contained within the PPDU; 2) the operation of determining / composing / acquiring time resources and frequency resources (e.g., subcarrier resources) used for subfields (SIG, STF, LTF, Data) contained within the PPDU; 3) the operation of determining / composing / acquiring specific sequences (e.g., pilot sequences, STF / LTF sequences, extra sequences applied to SIG) used for subfields (SIG, STF, LTF, Data) contained within the PPDU; 4) power control operations and / or power saving operations applied to the STA; and 5) operations related to determining / acquiring / composing / calculating / decoding / encoding ACK signals.Also, in the following example, various information (e.g., information related to fields / sub-fields / control fields / parameters / powers, etc.) used by various STAs for determining / acquiring / composing / operating / decoding / encoding transmission and reception signals is stored in the memories (112, 122) of FIG. 1.

[0042] The apparatus / STA of FIG. 1(a) described above is modified as shown in FIG. 1(b). Based on FIG. 1(b) below, the STAs (110, 120) in this specification will be described.

[0043] For example, the transceivers (113, 123) shown in FIG. 1(b) can perform the same functions as the transceivers shown in FIG. 1(a) described above. For example, the processing chips (114, 124) shown in FIG. 1(b) can include processors (111, 121) and memories (112, 122). The processors (111, 121) and memories (112, 122) shown in FIG. 1(b) can perform the same functions as the processors (111, 121) and memories (112, 122) shown in FIG. 1(a) described above.

[0044] In the following, mobile terminal, wireless device, wireless Transmit / Receive Unit (WTRU), User Equipment (UE), Mobile Station (MS), Mobile Subscriber Unit, user, user STA, network, base station, Node-B, access point (AP), repeater, router, relay, receiving device, transmitting device, receiving STA, transmitting STA, receiving device, transmitting device, receiving apparatus, and / or transmitting apparatus mean the STA (110, 120) shown in Figure 1(a) / (b) or the processing chip (114, 124) shown in Figure 1(b). That is, the technical features of this specification may be implemented on the STA (110, 120) shown in Figure 1(a) / (b) or only on the processing chip (114, 124) shown in Figure 1(b). For example, the technical characteristic of the transmitting STA transmitting control signals can be understood as the technical characteristic that the control signals generated in the processor (111, 121) shown in Figure 1(a) / (b) are transmitted via the transceivers (113, 123) shown in Figure 1(a) / (b). Alternatively, the technical characteristic of the transmitting STA transmitting control signals can be understood as the technical characteristic that the control signals to be transmitted to the transceivers (113, 123) are generated in the processing chip (114, 124) shown in Figure 1(b).

[0045] For example, the technical feature that the receiving STA receives a control signal can be understood as the technical feature that the control signal is received by the transceivers (113, 123) shown in FIG. 1(a). Or, the technical feature that the receiving STA receives a control signal can be understood as the technical feature that the control signal received by the transceivers (113, 123) shown in FIG. 1(a) is obtained by the processors (111, 121) shown in FIG. 1(a). Or, the technical feature that the receiving STA receives a control signal can be understood as the technical feature that the control signal received by the transceivers (113, 123) shown in FIG. 1(b) is obtained by the processing chips (114, 124) shown in FIG. 1(b).

[0046] Referring to FIG. 1(b), software codes (115, 125) are included in the memories (112, 122). The software codes (115, 125) include instructions for controlling the operations of the processors (111, 121). The software codes (115, 125) are included in various programming languages.

[0047] The processors (111, 121) or processing chips (114, 124) shown in FIG. 1 can include an ASIC (application-specific integrated circuit), other chip sets, logic circuits, and / or data processing devices. The processor is an AP (application processor). For example, the processors (111, 121) or processing chips (114, 124) shown in FIG. 1 can include at least one of a DSP (digital signal processor), a CPU (central processing unit), a GPU (graphics processing unit), and a modem (modulator and demodulator). For example, the processors (111, 121) or processing chips (114, 124) shown in FIG. 1 can be a SNAPDRAGON manufactured by Qualcomm (registered trademark) TMEXYNOS series processor, manufactured by Samsung®. TM Series processors, A-series processors manufactured by Apple®, HELIO manufactured by MediaTek® TM ATOM series processors, manufactured by INTEL®. TM This refers to a series processor or an improved (enhanced) version thereof.

[0048] In this specification, "uplink" refers to a link for communication from a non-AP STA to an AP STA, and uplink PPDU / packets / signals, etc., are transmitted via the uplink. Similarly, in this specification, "downlink" refers to a link for communication from an AP STA to a non-AP STA, and downlink PPDU / packets / signals, etc., are transmitted via the downlink.

[0049] Figure 2 is a conceptual diagram showing the structure of a wireless LAN (WLAN).

[0050] The upper part of Figure 2 shows the structure of the IEEE (Institute of Electrical and Electronic Engineers) 802.11 Infrastructure BSS (Basic Service Set).

[0051] Referring to the top of Figure 2, a wireless LAN system can include one or more infrastructure BSS(200, 205) (hereinafter, BSS). BSS(200, 205) is not a concept that refers to a specific area, but rather a set of APs (access points, 225) and STAs such as STA1 (Station, 200-1) that can synchronize and communicate with each other. A BSS(205) can include one or more connectable STAs (205-1, 205-2) in a single AP(230).

[0052] A BSS may include at least one STA, APs (225, 230) that provide distribution services, and a distribution system (DS, 210) that connects multiple APs.

[0053] The distribution system (210) can connect multiple BSSs (200, 205) to implement an extended service set (ESS, 240). ESS (240) is a term used to refer to a network formed by one or more APs connected via the distribution system (210). APs included in a single ESS (240) share the same SSID (service set identification).

[0054] The portal (portal,220) can act as a bridge to connect a wireless LAN network (IEEE802.11) with other networks (e.g., 802.X).

[0055] In a BSS like the one shown at the top of Figure 2, networks are implemented between APs (225, 230) and between APs (225, 230) and STAs (200-1, 205-1, 205-2). However, it is also possible to configure a network and communicate between STAs without APs (225, 230). A network that enables communication between STAs without APs (225, 230) is defined as an ad-hoc network or an independent BSS (independent basic service set, IBSS).

[0056] The lower part of Figure 2 is a conceptual diagram showing IBSS.

[0057] Referring to the bottom of Figure 2, IBSS is a BSS that operates in ad-hoc mode. Since IBSS does not include APs, there is no centralized management entity that performs management functions in a central location. That is, in IBSS, STAs (250-1, 250-2, 250-3, 255-4, 255-5) are managed in a distributed manner. In IBSS, all STAs (250-1, 250-2, 250-3, 255-4, 255-5) are configured as mobile STAs and are not allowed to connect to the distribution system, thus forming a self-contained network.

[0058] Figure 3 is a diagram illustrating the normal link setup process.

[0059] In the S310 step shown, the STA can perform an operation to find a network. This operation to find a network may include the STA's scanning operation. That is, in order for the STA to access a network, it needs to find a network it can join. Before the STA can join a wireless network, it needs to identify compatible networks, and the process of identifying networks that exist in a particular area is called scanning. There are two scanning methods: active scanning and passive scanning.

[0060] Figure 3 illustrates the process of finding a network, including the active scanning process. In active scanning, the STA performing the scanning moves to a different channel and sends a probe request frame to search for nearby APs, and waits for a response. The responder sends a probe response frame to the STA that sent the probe request frame. Here, the responder is the STA that last sent a beacon frame in the BSS of the channel being scanned. In BSS, APs send beacon frames, so APs become the responders, while in IBSS, STAs within IBSS return and send beacon frames, so the responder is not constant. For example, an STA that sent a probe request frame on channel 1 and received a probe response frame on channel 1 can store the BSS-related information contained in the received probe response frame and move to the next channel (e.g., channel 2) and perform scanning in the same way (i.e., sending and receiving probe requests / responses on channel 2).

[0061] Although not shown as an example in Figure 3, scanning operations can also be performed using a passive scanning method. An STA performing scanning based on passive scanning can wait for beacon frames while moving between channels. In IEEE 802.11, beacon frames are one of the management frames, used to announce the presence of a wireless network and are periodically transmitted to the scanning STA to find the wireless network and join it. In BSS, APs perform the role of periodically transmitting beacon frames, and in IBSS, STAs within IBSS return and transmit beacon frames. When a scanning STA receives a beacon frame, it stores the information about the BSS contained in the beacon frame and records the beacon frame information on each channel while moving to other channels. An STA that receives a beacon frame stores the BSS-related information contained in the received beacon frame and can move to the next channel and perform scanning on the next channel in the same way.

[0062] Once the STA discovers the network, it can perform an authentication process via step S320. This authentication process is referred to as the first authentication process to clearly distinguish it from the security configuration operation in step S340, which will be described later. The authentication process in S320 may include a process in which the STA sends an authentication request frame to the AP, and in response, the AP sends an authentication response frame to the STA. The authentication frame used in the authentication request / response corresponds to the management frame.

[0063] The authentication frame may include information such as the authentication algorithm number, authentication transaction sequence number, status code, challenge text, RSN (Robust Security Network), and finite cyclic group.

[0064] The STA can send an authentication request frame to the AP. Based on the information contained in the received authentication request frame, the AP can decide whether or not to grant authentication to the STA. The AP can provide the STA with the result of the authentication process via an authentication response frame.

[0065] A successfully authenticated STA can perform the connection process based on step S330. The connection process involves the STA sending an association request frame to the AP, and the AP responding by sending an association response frame to the STA. For example, the association request frame may include information related to various capabilities, such as the listen interval, SSID (service set identifier), supported rates, supported channels, RSN, mobility domain, supported operating classes, Traffic Indication Map Broadcast request, and interworking service capabilities. For example, a connection response frame may include information related to various capabilities, such as status code, AID (Association ID), support rate, EDCA (Enhanced Distributed Channel Access) parameter set, RCPI (Received Channel Power Indicator), RSNI (Received Signal to Noise Indicator), mobility domain, timeout interval (association comeback time), overlapping BSS scan parameters, TIM broadcast response, and QoS map.

[0066] After that, in step S340, the STA can execute a security setting process. The security setting process in step S340 can include, for example, a process of performing private key setup via a 4-way handshake over an EAPOL (Extensible Authentication Protocol over LAN) frame.

[0067] FIG. 4 is a drawing showing an example of a PPDU used in the IEEE standard.

[0068] As shown, various forms of PPDU (PHY protocol data unit) are used in standards such as IEEE a / g / n / ac. Specifically, the LTF and STF fields include training signals, the SIG-A and SIG-B contain control information for the receiving station, and the data field contains user data corresponding to the PSDU (MAC PDU / Aggregated MAC PDU).

[0069] Also, FIG. 4 also includes an example of the HE PPDU of the IEEE 802.11ax standard. The HE PPDU according to FIG. 4 is an example of a PPDU for multiple users. The HE-SIG-B is only included in the case of multiple users, and the corresponding HE-SIG-B is omitted in the PPDU for a single user.

[0070] As indicated, the HE-PPDU for Multiple User (MU) can include L-STF (legacy-short training field), L-LTF (legacy-long training field), L-SIG (legacy-signal), HE-SIG-A (high efficiency-signal A), HE-SIG-B (high efficiency-signal B), HE-STF (high efficiency-short training field), HE-LTF (high efficiency-long training field), data field (or MAC payload), and PE (Packet Extension) field. Each field is transmitted during the indicated time interval (i.e., 4 or 8 μs, etc.).

[0071] The resource unit (RU) used in PPDU is described below. A resource unit can contain multiple subcarriers (or tones). Resource units are used when transmitting signals to multiple STAs based on OFDMA technology. Resource units are also defined when transmitting signals to a single STA. Resource units are used for STF, LTF, data fields, etc.

[0072] Figure 5 is a diagram showing the arrangement of resource units (RUs) used in the 20MHz bandwidth.

[0073] As shown in Figure 5, Resource Units (RUs), each corresponding to a different number of tones (i.e., subcarriers), can be used to constitute some fields of the HE-PPDU. For example, resources are allocated in the RU units shown for the HE-STF, HE-LTF, and data fields.

[0074] As shown at the top of Figure 5, 26 units (i.e., units corresponding to 26 tones) are arranged. Six tones are used as guard bands in the leftmost band of the 20MHz bandwidth, and five tones are used as guard bands in the rightmost band of the 20MHz bandwidth. In addition, seven DC tones are inserted in the center band, i.e., the DC band, and there may be 26 units corresponding to 13 tones on each side of the DC band. Furthermore, 26, 52, and 106 units are allocated to the other bands. Each unit is allocated for the receiving station, i.e., the user.

[0075] On the other hand, the RU configuration in Figure 5 can be used not only for situations involving multiple users (MU) but also for situations involving a single user (SU), in which case it is possible to use one 242 unit as shown at the bottom of Figure 5, in which case three DC tones are inserted.

[0076] As shown in the example in Figure 5, various sizes of RUs, namely 26RU, 52RU, 106RU, 242RU, etc., are proposed, the specific sizes of such RUs may be expanded or increased, so this embodiment is not limited to the specific size of each RU (i.e., the number of corresponding tones).

[0077] Figure 6 is a diagram showing the arrangement of resource units (RUs) used in the 40 MHz bandwidth.

[0078] Similar to how various sizes of RU were used in the example in Figure 5, the example in Figure 6 also uses 26RU, 52RU, 106RU, 242RU, 484RU, etc. In addition, five DC tones are inserted at the center frequency, twelve tones are used as guard bands in the leftmost band of the 40MHz bandwidth, and eleven tones are used as guard bands in the rightmost band of the 40MHz bandwidth.

[0079] Furthermore, as shown, 484 RUs can be used when used for a single user. On the other hand, the specific number of RUs can be changed, as in the example in Figure 4.

[0080] Figure 7 is a diagram showing the arrangement of resource units (RUs) used in the 80MHz bandwidth.

[0081] Similar to how various RU sizes were used in the examples in Figures 5 and 6, the example in Figure 7 can also use 26RU, 52RU, 106RU, 242RU, 484RU, 996RU, etc. Additionally, seven DC tones are inserted at the center frequency, 12 tones are used as guard bands in the leftmost band of the 80MHz bandwidth, and 11 tones are used as guard bands in the rightmost band of the 80MHz bandwidth. Furthermore, a 26RU configuration can be used, utilizing 13 tones on each side of the DC bandwidth.

[0082] Also, as shown, when used for a single user, the 996RU can be used, in which case five DC tones are inserted.

[0083] The RUs described herein are used in UL (Uplink) and DL (Downlink) communications. For example, when UL-MU communication is solicited by a trigger frame, the transmitting STA (e.g., AP) can assign a first RU (e.g., 26 / 52 / 106 / 242RU, etc.) to the first STA and a second RU (e.g., 26 / 52 / 106 / 242RU, etc.) to the second STA via the trigger frame. Thereafter, the first STA can transmit a first trigger-based PPDU based on the first RU, and the second STA can transmit a second trigger-based PPDU based on the second RU. The first and second trigger-based PPDUs are transmitted to the AP in the same time interval.

[0084] For example, when a DL MU PPDU is configured, the transmitting STA (e.g., AP) can assign the first RU (e.g., 26 / 52 / 106 / 242RU) to the first STA and the second RU (e.g., 26 / 52 / 106 / 242RU) to the second STA. That is, within a single MU PPDU, the transmitting STA (e.g., AP) can transmit the HE-STF, HE-LTF, and Data fields for the first STA via the first RU, and the HE-STF, HE-LTF, and Data fields for the second STA via the second RU.

[0085] Information regarding the RU's placement is signaled via HE-SIG-B.

[0086] Figure 8 shows the structure of the HE-SIG-B field.

[0087] As shown, the HE-SIG-B field (810) includes a common field (820) and a user-specific field (830). The common field (820) may contain information that applies in common to all users receiving the SIG-B (i.e., user STA). The user-specific field (830) can be called a user-specific control field. If the SIG-B is transmitted to multiple users, the user-specific field (830) may apply to only some of those users.

[0088] As shown in Figure 8, the common field (820) and the user-specific field (830) can be encoded separately.

[0089] The common field (820) can contain N*8 bits of RU allocation information. For example, the RU allocation information can contain information about the location of the RUs. For instance, if a 20MHz channel is used as shown in Figure 5, the RU allocation information can contain information about which RUs (26RU / 52RU / 106RU) are placed in which frequency band.

[0090] An example of a case where RU allocation information consists of 8 bits is as follows:

[0091] [Table 1]

[0092] As shown in the example in Figure 5, a maximum of nine 26RUs can be allocated to a 20MHz channel. When the RU allocation information for the common field (820) is set to "00000000" as shown in Table 1, nine 26RUs are allocated to the corresponding channel (i.e., 20MHz). Also, when the RU allocation information for the common field (820) is set to "00000001" as shown in Table 1, seven 26RUs and one 52RU are allocated to the corresponding channel. In other words, in the example in Figure 5, a 52RU is allocated on the far right, and seven 26RUs are allocated to its left.

[0093] Table 1 shows only a portion of the RU locations for which RU allocation information can be displayed.

[0094] For example, RU allocation information may further include the example shown in Table 2 below.

[0095] [Table 2]

[0096] "01000y2y1y0" relates to an example where 106RU is assigned to the leftmost end of a 20MHz channel, and five 26RU are assigned to its right. In this case, a large number of STAs (e.g., User-STAs) are assigned to the 106RU based on MU-MIMO technology. Specifically, up to eight STAs (e.g., User-STAs) are assigned to the 106RU, and the number of STAs (e.g., User-STAs) assigned to the 106RU is determined based on 3-bit information (y2y1y0). For example, if the 3-bit information (y2y1y0) is set to N, the number of STAs (e.g., User-STAs) assigned to the 106RU based on MU-MIMO technology is N+1.

[0097] Typically, multiple RUs are assigned multiple distinct STAs (e.g., User STAs). However, for a single RU exceeding a certain size (e.g., 10⁶ subcarriers), multiple STAs (e.g., User STAs) are assigned based on MU-MIMO technology.

[0098] As shown in Figure 8, a user-specific field (830) can contain multiple user fields. As described above, the number of STAs (e.g., User STAs) assigned to a particular channel is determined based on the RU allocation information in the common field (820). For example, if the RU allocation information in the common field (820) is "00000000", then one User STA is assigned to each of the nine 26RUs (i.e., a total of nine User STAs are assigned). In other words, a maximum of nine User STAs can be assigned to a particular channel via OFDMA technology. Also, a maximum of nine User STAs can be assigned to a particular channel via non-MU-MIMO technology.

[0099] For example, if the RU allocation is set to "01000y2y1y0", the 106 RU located on the far left will be allocated multiple User STAs via MU-MIMO technology, and the five 26 RU located to its right will be allocated five User STAs via non-MU-MIMO technology. This case is illustrated in the example shown in Figure 9.

[0100] Figure 9 shows an example where multiple User STAs are assigned to the same RU via MU-MIMO technology.

[0101] For example, if the RU allocation is set to "01000010" as shown in Figure 9, then, based on Table 2, 106 RUs are allocated to the leftmost end of a particular channel, and five 26 RUs are allocated to its right. Additionally, a total of three User STAs are allocated to the 106 RUs via MU-MIMO technology. As a result, a total of eight User STAs are allocated, allowing the HE-SIG-B user-specific field (830) to contain eight User fields.

[0102] The eight User fields are included in the order shown in Figure 9. Also, as shown in Figure 8, two User fields are implemented within one User block field.

[0103] The User fields shown in Figures 8 and 9 are constructed based on two formats. Specifically, User fields related to MU-MIMO technology are constructed using the first format, while User fields related to non-MU-MIMO technology are constructed using the second format. Referring to an example in Figure 9, User fields 1 through 3 are based on the first format, and User fields 4 through 8 are based on the second format. Either the first or second format can contain the same length (e.g., 21 bits) of bit information.

[0104] Each User field can have the same size (e.g., 21 bits). For example, the User field in the first format (MU-MIMO technology format) is structured as follows:

[0105] For example, the first bit (e.g., B0-B10) within the User field (i.e., 21 bits) can contain identification information for the User STA to which the User field is assigned (e.g., STA-ID, partial AID, etc.). Additionally, the second bit (e.g., B11-B14) within the User field (i.e., 21 bits) can contain information regarding the spatial configuration. Specifically, an example of the second bit (i.e., B11-B14) may be the same as those shown in Tables 3 and 4 below.

[0106] [Table 3]

[0107] [Table 4]

[0108] As shown in Table 3 and / or Table 4, the second bits (i.e., B11-B14) can contain information about the number of Spatial Streams allocated to multiple User STAs allocated by MU-MIMO technology. For example, if three User STAs are allocated to 106RU based on MU-MIMO technology as shown in Figure 9, N_user is set to "3", which determines the values ​​of N_STS[1], N_STS[2], and N_STS[3] as shown in Table 3. For example, if the value of the second bits (B11-B14) is "0011", then N_STS[1]=4, N_STS[2]=1, and N_STS[3]=1. That is, in the example in Figure 9, four Spatial Streams are allocated to User field 1, one Spatial Stream is allocated to User field 2, and one Spatial Stream is allocated to User field 3.

[0109] As shown in the example in Table 3 and / or Table 4, the information regarding the number of spatial streams for a user station (User STA) (i.e., the second bits, B11-B14) consists of 4 bits. Furthermore, the information regarding the number of spatial streams for a user station (User STA) (i.e., the second bits, B11-B14) can support up to 8 spatial streams. Also, the information regarding the number of spatial streams (i.e., the second bits, B11-B14) can support up to 4 spatial streams for a single User STA.

[0110] Additionally, the third bit (i.e., B15-18) within the User field (i.e., 21 bits) can contain MCS (Modulation and Coding Scheme) information. The MCS information is applied to the data field within the PPDU containing the relevant SIG-B.

[0111] In this specification, MCS, MCS information, MCS index, MCS field, etc., can be represented by specific index values. For example, MCS information can be represented by index 0 to index 11. MCS information may include information about the constellation modulation type (e.g., BPSK, QPSK, 16_QAM, 64_QAM, 256_QAM, 1024_QAM, etc.) and information about the code rate (e.g., 1 / 2, 2 / 3, 3 / 4, 5 / 6, etc.). MCS information may exclude information about the channel coding type (e.g., BSS or LDPC).

[0112] Additionally, the fourth bit (i.e., B19) within the User field (i.e., 21 bits) is the Reserved field.

[0113] Additionally, the fifth bit (i.e., B20) within the User field (i.e., 21 bits) can contain information about the coding type (e.g., BSS or LDPC). That is, the fifth bit (i.e., B20) can contain information about the type of channel coding (e.g., BSS or LDPC) applied to the data field in the PPDU containing the relevant SIG-B.

[0114] The example above relates to the User field in the first format (the format for MU-MIMO technology). An example of the User field in the second format (the format for non-MU-MIMO technology) is as follows:

[0115] The first bit in the User field of the second format (e.g., B0-B10) can contain User STA identification information. The second bit in the User field of the second format (e.g., B11-B13) can contain information about the number of spatial streams applied to the corresponding RU. The third bit in the User field of the second format (e.g., B14) contains information about whether a beamforming steering matrix is ​​applied. The fourth bit in the User field of the second format (e.g., B15-B18) can contain MCS (Modulation and coding scheme) information. The fifth bit in the User field of the second format (e.g., B19) can contain information about whether DCM (Dual Carrier Modulation) is applied. The sixth bit in the User field of the second format (i.e., B20) can contain information about the coding type (e.g., BSS or LDPC).

[0116] Figure 10 illustrates the operation related to UL-MU. As shown, the transmitting STA (e.g., AP) can establish a channel connection via contending (i.e., backoff operation) and transmit a trigger frame (1030). That is, the transmitting STA (e.g., AP) can transmit a PPDU containing the trigger frame (1330). Once the PPDU containing the trigger frame is received, a trigger-based (TB) PPDU is transmitted after a delay equal to the SIFS.

[0117] TB PPDUs (1041, 1042) are sent at the same time and originate from multiple STAs (e.g., User STAs) whose AIDs are displayed in the Trigger frame (1030). The ACK frame (1050) for the TB PPDU is implemented in various forms.

[0118] The specific characteristics of the trigger frame are explained through Figures 11 to 13. When UL-MU communication is used, OFDMA (orthogonal frequency division multiple access) technology or MU MIMO technology is used, or OFDMA and MU MIMO technology are used simultaneously.

[0119] Figure 11 shows an example of a trigger frame. The trigger frame in Figure 11 allocates resources for uplink MU transmission (Uplink Multiple-User transmission) and is sent, for example, from an AP. The trigger frame consists of a MAC frame and is included in the PPDU.

[0120] Each of the fields shown in Figure 11 may be partially omitted, and other fields may be added. Furthermore, the length of each field may change from what is shown.

[0121] The frame control field (1110) in Figure 11 contains information about the MAC protocol version and other additional control information, while the duration field (1120) contains time information for NAV configuration and information about the STA identifier (e.g., AID).

[0122] The RA field (1130) contains the address information of the receiving STA for the trigger frame and may be omitted if necessary. The TA field (1140) contains the address information of the STA (e.g., AP) that transmits the trigger frame, and the common information field (1150) contains common control information applicable to the receiving STA that receives the trigger frame. For example, it may include a field that indicates the length of the L-SIG field of the up PPDU transmitted in response to the trigger frame, and information that controls the content of the SIG-A field (i.e., the HE-SIG-A field) of the up PPDU transmitted in response to the trigger frame. In addition, common control information may include information regarding the length of the CP and the length of the LTF field of the up PPDU transmitted in response to the trigger frame.

[0123] Furthermore, it is desirable to include individual user information fields (1160#1 to 1160#N) corresponding to the number of receiving STAs that receive the trigger frame in Figure 11. These individual user information fields are also called "assignment fields."

[0124] Furthermore, the trigger frame in Figure 11 may include a padding field (1170) and a frame check sequence field (1180).

[0125] As shown in Figure 11, each of the individual user information fields (1160#1 to 1160#N) can again contain a number of subfields.

[0126] Figure 12 shows an example of the common information field in a trigger frame. Some of the subfields in Figure 12 may be omitted, and other subfields may be added. Also, the length of each subfield shown may be modified.

[0127] The indicated length field (1210) has the same value as the length field of the L-SIG field of the up PPDU transmitted in response to the trigger frame, and the length field of the L-SIG field of the up PPDU indicates the length of the up PPDU. Consequently, the length field (1210) of the trigger frame is used to indicate the length of the corresponding uplink PPDU.

[0128] Furthermore, the cascade indicator field (1220) indicates whether or not a cascade operation will be performed. Cascade operation means that both downlink MU transmission and uplink MU transmission are performed within the same TXOP. That is, it means that after a downlink MU transmission is performed, an uplink MU transmission will be performed after a previously set time (e.g., SIFS). In a cascade operation, there may be only one transmitting device (e.g., AP) performing downlink communication, and multiple transmitting devices (e.g., non-AP) performing uplink communication.

[0129] The CS request field (1230) indicates whether the receiving device that received the trigger frame needs to consider the status of the wireless medium, NAV, etc., when transmitting the corresponding uplink PPDU.

[0130] The HE-SIG-A information field (1240) contains information that controls the content of the SIG-A field (i.e., the HE-SIG-A field) of the up PPDU transmitted in response to the trigger frame.

[0131] The CP and LTF type fields (1250) may include information regarding the LTF length and CP length of the up PPDU transmitted in response to the trigger frame. The trigger type field (1060) may indicate the purpose for which the trigger frame is used, such as a normal trigger, a trigger for beamforming, or a request for Block ACK / NACK.

[0132] In this specification, it can be assumed that the trigger type field (1260) of a trigger frame indicates a trigger frame of type Basic for a normal trigger. For example, a trigger frame of type Basic can be called a basic trigger frame.

[0133] Figure 13 shows an example of subfields included in a per-user information field. The per-user information field (1300) in Figure 13 can be understood as one of the individual per-user information fields (1160#1 to 1160#N) mentioned in Figure 11. Some of the subfields included in the per-user information field (1300) in Figure 13 may be omitted, and other subfields may be added. Also, the length of each subfield shown may be changed.

[0134] The User Identifier field (1310) in Figure 13 indicates the identifier of the STA (i.e., the receiving STA) corresponding to the individual user information. An example of an identifier may be all or part of the AID (Association Identifier) ​​value of the receiving STA.

[0135] The RU allocation field (1320) is also included. That is, when a receiving STA identified in the user identifier field (1310) transmits a TB PPDU in response to a trigger frame, it transmits the TB PPDU via the RU indicated by the RU allocation field (1320). In this case, the RU indicated by the RU allocation field (1320) is the RU shown in Figures 5, 6, and 7.

[0136] The subfield in Figure 13 may include a coding type field (1330). The coding type field (1330) can indicate the coding type of the TB PPDU. For example, if BCC coding is applied to the TB PPDU, the coding type field (1330) is set to "1", and if LDPC coding is applied, the coding type field (1330) is set to "0".

[0137] Furthermore, the subfield in Figure 13 may include an MCS field (1340). The MCS field (1340) can indicate the MCS technology to be applied to the TB PPDU. For example, if BCC coding is applied to the TB PPDU, the coding type field (1330) is set to "1", and if LDPC coding is applied, the coding type field (1330) is set to "0".

[0138] The following is a description of UORA (UL OFDMA-based Random Access) technology.

[0139] Figure 14 illustrates the technical characteristics of UORA technology.

[0140] A transmitting STA (e.g., AP) can allocate six RU resources via a trigger frame, as shown in Figure 14. Specifically, the AP can allocate the first RU resource (AID 0, RU1), the second RU resource (AID 0, RU2), the third RU resource (AID 0, RU3), the fourth RU resource (AID 2045, RU4), the fifth RU resource (AID 2045, RU5), and the sixth RU resource (AID 3, RU6). Information regarding AID 0, AID 3, or AID 2045 is included, for example, in the user identification field (1310) in Figure 13. Information regarding RU1 through RU6 is included, for example, in the RU allocation field (1320) in Figure 13. AID=0 signifies a UORA resource for an associated STA, and AID=2045 signifies a UORA resource for an unassociated STA. As a result, the first to third RU resources in Figure 14 are used as UORA resources for associated STAs, the fourth to fifth RU resources in Figure 14 are used as UORA resources for unassociated STAs, and the sixth RU resource in Figure 14 is used as a resource for a regular ULMU.

[0141] In the example shown in Figure 14, STA1's OBO (OFDMA random access backoff) counter decreases to 0, and STA1 randomly selects the second RU resource (AID 0, RU2). Also, since STA2 / 3's OBO counters are greater than 0, no uplink resources are assigned to STA2 / 3. Furthermore, in Figure 14, STA4's AID (i.e., AID=3) is included in the trigger frame, so the RU6 resource is assigned without backoff.

[0142] Specifically, in Figure 14, STA1 is an associated STA, so there are a total of 3 eligible RA RUs (RU1, RU2, RU3) for STA1, which reduces STA1's OBO counter by 3 until it reaches 0. Similarly, in Figure 14, STA2 is an associated STA, so there are a total of 3 eligible RA RUs (RU1, RU2, RU3) for STA2, which reduces STA2's OBO counter by 3, but the OBO counter remains greater than 0. Furthermore, in Figure 14, STA3 is an unassociated STA, so there are a total of 2 eligible RA RUs (RU4, RU5) for STA3, which reduces STA3's OBO counter by 2, but the OBO counter remains greater than 0.

[0143] Figure 15 shows an example of channels used / supported / defined within the 2.4 GHz band.

[0144] The 2.4GHz band can be referred to by other names, such as the first band. Furthermore, the 2.4GHz band refers to the frequency range in which channels adjacent to 2.4GHz (for example, channels with center frequencies between 2.4 and 2.5GHz) are used / supported / defined.

[0145] The 2.4GHz band contains numerous 20MHz channels. Within the 2.4GHz band, 20MHz channels can have multiple channel indices (e.g., index 1 to index 14). For example, the center frequency of a 20MHz channel assigned channel index 1 is 2.412GHz, the center frequency of a 20MHz channel assigned channel index 2 is 2.417GHz, and the center frequency of a 20MHz channel assigned channel index N is (2.407 + 0.005 * N)GHz. Channel indices are referred to by various names, such as channel numbers. Specific numerical values ​​for channel indices and center frequencies may change.

[0146] Figure 15 shows four channels within the 2.4 GHz band as an example. Each of the first to fourth frequency domains (1510 to 1540) can contain one channel. For example, the first frequency domain (1510) can contain channel 1 (a 20 MHz channel with index 1). In this case, the center frequency of channel 1 is set to 2412 MHz. The second frequency domain (1520) can contain channel 6. In this case, the center frequency of channel 6 is set to 2437 MHz. The third frequency domain (1530) can contain channel 11. In this case, the center frequency of channel 11 is set to 2462 MHz. The fourth frequency domain (1540) can contain channel 14. In this case, the center frequency of channel 14 is set to 2484 MHz.

[0147] Figure 16 shows an example of channels used / supported / defined within the 5GHz band.

[0148] The 5GHz band can be referred to by other names such as the second band / band. The 5GHz band refers to the frequency domain in which channels with a center frequency between 5GHz and 6GHz (or less than 5.9GHz) are used / supported / defined. Alternatively, the 5GHz band can include multiple channels between 4.5GHz and 5.5GHz. The specific figures shown in Figure 16 are subject to change.

[0149] Multiple channels within the 5GHz band include UNII (Unlicesed National Information Infrastructure)-1, UNII-2, UNII-3, and ISM. UNII-1 can be called UNII Low. UNII-2 can include frequency domains called UNII Mid and UNII-2 Extended. UNII-3 can be called UNII-Upper.

[0150] Within the 5GHz band, multiple channels are configured, and the bandwidth of each channel can be set in various ways, such as 20MHz, 40MHz, 80MHz, or 160MHz. For example, the 5170MHz to 5330MHz frequency domain / range within UNII-1 and UNII-2 can be divided into eight 20MHz channels. At 5170MHz, the 5330MHz frequency domain / range can be divided into four channels via a 40MHz frequency domain. At 5170MHz, the 5330MHz frequency domain / range can be divided into two channels via an 80MHz frequency domain. Alternatively, at 5170MHz, the 5330MHz frequency domain / range can be divided into one channel via a 160MHz frequency domain.

[0151] Figure 17 shows an example of channels used / supported / defined within the 6GHz band.

[0152] The 6GHz band can be referred to by other names, such as the third band / band. The 6GHz band refers to the frequency domain in which channels with a center frequency of 5.9GHz or higher are used / supported / defined. The specific figures shown in Figure 17 are subject to change.

[0153] For example, the 20MHz channel in Figure 17 is defined starting from 5.940GHz. Specifically, the leftmost channel among the 20MHz channels in Figure 17 can have index 1 (or channel index, channel number, etc.), and its center frequency is assigned to 5.945GHz. That is, the center frequency of index N channel is determined to be (5.940 + 0.005 * N)GHz.

[0154] Therefore, the indices (or channel numbers) for the 20MHz channels in Figure 17 are 1, 5, 9, 13, 17, 21, 25, 29, 33, 37, 41, 45, 49, 53, 57, 61, 65, 69, 73, 77, 81, 85, 89, 93, 97, 101, 105, 109, 113, 117, 121, 125, 129, 133, 137, 141, 145, 149, 153, 157, 161, 165, 169, 173, 177, 181, 185, 189, 193, 197, 201, 205, 209, 213, 217, 221, 225, 229, and 233. Furthermore, according to the (5.940 + 0.005 * N) GHz rule mentioned above, the indices for the 40 MHz channels in Figure 17 are 3, 11, 19, 27, 35, 43, 51, 59, 67, 75, 83, 91, 99, 107, 115, 123, 131, 139, 147, 155, 163, 171, 179, 187, 195, 203, 211, 219, and 227.

[0155] Figure 17 shows an example with 20, 40, 80, and 160 MHz channels, but 240 MHz and 320 MHz channels will be added.

[0156] The following describes the PPDUs transmitted / received in the STA of this specification.

[0157] Figure 18 shows an example of a PPDU used in this specification.

[0158] The PPDU in Figure 18 is referred to by various names, such as EHT PPDU, transmit PPDU, receive PPDU, first type, or nth type PPDU. For example, in this specification, PPDU or EHT PPDU is referred to by various names, such as transmit PPDU, receive PPDU, first type, or nth type PPDU. Furthermore, EHT PPUs are used in EHT systems and / or new wireless LAN systems that improve upon EHT systems.

[0159] The PPDU in Figure 18 can represent some or all of the PPDU types used in an EHT system. For example, the example in Figure 18 is used for both SU (single-user) mode and MU (multi-user) mode. Also, the PPDU in Figure 18 is for one receiving STA or multiple receiving STAs. When the PPDU in Figure 18 is used for TB (Trigger-Based) mode, the EHT-SIG in Figure 18 is omitted. Furthermore, an STA that has received a trigger frame for UL-MU (Uplink-MU) communication can transmit a PPDU in the example in Figure 18 with the EHT-SIG omitted.

[0160] In Figure 18, the L-STF to EHT-LTF sequence is called a preamble or physical preamble, and is generated, transmitted, received, acquired, and decoded in the physical layer.

[0161] In Figure 18, the subcarrier spacing for the L-STF, L-LTF, L-SIG, RL-SIG, U-SIG, and EHT-SIG fields is determined to be 312.5 kHz, while the subcarrier spacing for the EHT-STF, EHT-LTF, and Data fields is determined to be 78.125 kHz. That is, the tone index (or subcarrier index) for the L-STF, L-LTF, L-SIG, RL-SIG, U-SIG, and EHT-SIG fields can be displayed in units of 312.5 kHz, and the tone index (or subcarrier index) for the EHT-STF, EHT-LTF, and Data fields can be displayed in units of 78.125 kHz.

[0162] In Figure 18, the PPDU for L-LTF and L-STF is the same as in the conventional field.

[0163] The L-SIG field in Figure 18 can contain, for example, 24 bits of bit information. For example, the 24 bits of information can include a 4-bit Rate field, a 1-bit Reserved bit, a 12-bit Length field, a 1-bit ParitY bit, and a 6-bit Tail bit. For example, the 12-bit Length field can contain information about the length or time duration of the PPDU. For example, the value of the 12-bit Length field is determined based on the type of PPDU. For example, if the PPDU is a non-HT, HT, VHT PPDU or an EHT PPDU, the value of the Length field can be determined as a multiple of 3. For example, if the PPDU is an HE PPDU, the value of the Length field is determined as a multiple of 3 + 1 or a multiple of 3 + 2.

[0164] For example, the transmitting STA can apply BCC encoding based on a code rate of 1 / 2 to the 24 bits of information in the L-SIG field. Subsequently, the transmitting STA can obtain 48 bits of BCC encoded data. BPSK modulation is applied to these 48 bits to generate 48 BPSK symbols. The transmitting STA can map these 48 BPSK symbols to positions excluding the pilot subcarriers {subcarrier indices -21, -7, +7, +21} and the DC subcarrier {subcarrier index 0}. As a result, the 48 BPSK symbols are mapped to subcarrier indices -26 to -22, -20 to -8, -6 to -1, +1 to +6, +8 to +20, and +22 to +26. The transmitting STA can further map the signals {-1,-1,-1,1} to subcarrier indices {-28, -27, +27, 28}. The above signal is used for channel estimation for the frequency domains corresponding to {-28, -27, +27, 28}.

[0165] The transmitting STA can generate an RL-SIG, which is generated similarly to the L-SIG. BPSK modulation is applied to the RL-SIG. Based on the presence of the RL-SIG, the receiving STA can determine that the received PPDU is either an HE PPDU or an EHT PPDU.

[0166] After the RL-SIG in Figure 18, a U-SIG (Universal SIG) is inserted. The U-SIG can be called by various names such as the first SIG field, first SIG, first type SIG, control signal, control signal field, and first (type) control signal.

[0167] A U-SIG can contain N bits of information and may include information to identify the type of EHT PPDU. For example, a U-SIG is composed of two symbols (e.g., two consecutive OFDM symbols). Each symbol for the U-SIG (e.g., an OFDM symbol) can have a duration of 4 us. Each symbol of the U-SIG is used to transmit 26 bits of information. For example, each symbol of the U-SIG is transmitted and received based on 52 data tones and 4 pilot tones.

[0168] Through a U-SIG (or U-SIG field), for example, A-bit information (e.g., 52 uncoded bits) can be transmitted, with the first symbol of the U-SIG transmitting the first X bits of the total A-bit information (e.g., 26 uncoded bits), and the second symbol of the U-SIG transmitting the remaining Y bits of the total A-bit information (e.g., 26 uncoded bits). For example, a transmitting STA can obtain the 26 uncoded bits contained in each U-SIG symbol. The transmitting STA can perform convolutional encoding (i.e., BCC encoding) based on a rate of R=1 / 2 to generate 52-coded bits and perform interleaving on the 52-coded bits. The transmitting STA can perform BPSK modulation on the interleaved 52-coded bits to generate 52 BPSK symbols to be assigned to each U-SIG symbol. A single U-SIG symbol is transmitted based on 56 tones (subcarriers) from subcarrier index -28 to subcarrier index +28, excluding DC index 0. The 52 BPSK symbols generated by the transmitting STA are transmitted based on the remaining tones (subcarriers), excluding the pilot tones -21, -7, +7, and +21.

[0169] For example, the A-bit information transmitted by the U-SIG (e.g., 52 uncoded bits) may include a CRC field (e.g., a 4-bit field) and a tail field (e.g., a 6-bit field). The CRC field and tail field are transmitted via a second symbol of the U-SIG. The CRC field is generated based on the 26 bits assigned to the first symbol of the U-SIG and the remaining 16 bits in the second symbol excluding the CRC / tail field, and is generated based on a conventional CRC calculation algorithm. The tail field is used to terminate the trellis of the convolutional decoder and is set to, for example, "000000".

[0170] The A-bit information transmitted by a U-SIG (or U-SIG field), for example, 52 uncoded bits, can be divided into version-independent bits and version-dependent bits. For example, the size of the version-independent bits can be fixed or variable. For example, the version-independent bits may be assigned only to the first symbol of the U-SIG, or they may be assigned to both the first and second symbols of the U-SIG. For example, the version-independent bits and version-dependent bits can be referred to by various names, such as the first control bits and the second control bits.

[0171] For example, the version-independent bits of the U-SIG can contain a 3-bit PHY version identifier. For example, the 3-bit PHY version identifier can contain information related to the PHY version of the transmitted and received PPDUs. For example, the first value of the 3-bit PHY version identifier can indicate that the transmitted and received PPDUs are EHT PPDUs. Also, when a transmitting STA transmits an EHT PPDU, it can set the 3-bit PHY version identifier to the first value. Also, a receiving STA can determine that the received PPDU is an EHT PPDU based on the PHY version identifier with the first value.

[0172] For example, the version-independent bits of a U-SIG may include a 1-bit UL / DL flag field. The first value of the 1-bit UL / DL flag field is related to UL communication, and the second value of the UL / DL flag field is related to DL communication.

[0173] For example, the version-independent bits of the U-SIG can contain information about the length of the TXOP and information about the BSS color ID.

[0174] For example, if an EHT PPDU can be divided into various types (e.g., EHT PPDUs related to SU mode, EHT PPDUs related to MU mode, EHT PPDUs related to TB mode, EHT PPDUs related to Extended Range transmission, etc.), then information regarding the type of EHT PPDU is included in the version-dependent bits of the U-SIG.

[0175] For example, a U-SIG may include information about: 1) a bandwidth field containing information about bandwidth; 2) a field containing information about the MCS technology applied to the EHT-SIG; 3) an indicator field containing information related to whether or not dual subcarrier modulation (DCM) technology is applied to the EHT-SIG; 4) a field containing information about the number of symbols used for the EHT-SIG; 5) a field containing information about whether or not the EHT-SIG is generated across the entire bandwidth; 6) a field containing information about the type of EHT-LTF / STF; and 7) fields indicating the length of the EHT-LTF and the CP length.

[0176] Preamble puncturing is applied to the PPDU in Figure 18. Preamble puncturing means that puncturing is applied to a portion of the PPDU's overall bandwidth (for example, a secondary 20MHz bandwidth). For example, if an 80MHz PPDU is transmitted, the STA will apply puncturing to the secondary 20MHz bandwidth of the 80MHz band, allowing the PPDU to be transmitted only through the primary 20MHz bandwidth and the secondary 40MHz bandwidth.

[0177] For example, preamble puncturing patterns are pre-set. For example, if the first puncturing pattern is applied, puncturing is applied only to the secondary 20MHz band within the 80MHz band. For example, if the second puncturing pattern is applied, puncturing is applied to only one of the two secondary 20MHz bands included in the secondary 40MHz band within the 80MHz band. For example, if the third puncturing pattern is applied, puncturing is applied only to the secondary 20MHz band included in the primary 80MHz band within the 160MHz band (or 80+80MHz band). For example, if the fourth puncturing pattern is applied, the primary 40MHz band included in the primary 80MHz band within the 160MHz band (or 80+80MHz band) is present, and puncturing is applied to at least one 20MHz channel that does not belong to the primary 40MHz band.

[0178] Information regarding preamble puncturing applied to the PPDU is included in the U-SIG and / or EHT-SIG. For example, the first field of the U-SIG may contain information regarding the contiguous bandwidth of the PPDU, and the second field of the U-SIG may contain information regarding preamble puncturing applied to the PPDU.

[0179] For example, U-SIGs and EHT-SIGs can include information about preamble puncturing based on the following method: If the bandwidth of the PPDU exceeds 80 MHz, the U-SIGs are configured individually in 80 MHz units. For example, if the bandwidth of the PPDU is 160 MHz, the PPDU includes a first U-SIG for the first 80 MHz band and a second U-SIG for the second 80 MHz band. In this case, the first field of the first U-SIG contains information about the 160 MHz bandwidth, and the second field of the first U-SIG can contain information about preamble puncturing applied to the first 80 MHz band (i.e., information about the preamble puncturing pattern). Also, the first field of the second U-SIG contains information about the 160 MHz bandwidth, and the second field of the second U-SIG can contain information about preamble puncturing applied to the second 80 MHz band (i.e., information about the preamble puncturing pattern). On the other hand, an EHT-SIG following the first U-SIG may contain information about preamble puncturing applied to the second 80 MHz band (i.e., information about the preamble puncturing pattern), and an EHT-SIG following the second U-SIG may contain information about preamble puncturing applied to the first 80 MHz band (i.e., information about the preamble puncturing pattern).

[0180] Furthermore, or more generally, U-SIG and EHT-SIG can include information about preamble puncturing based on the following methods: U-SIG can include information about preamble puncturing for all bandwidths (i.e., information about preamble puncturing patterns). That is, EHT-SIG does not include information about preamble puncturing, and only U-SIG can include information about preamble puncturing (i.e., information about preamble puncturing patterns).

[0181] U-SIGs are configured in 20MHz units. For example, when an 80MHz PPDU is configured, the U-SIGs are duplicated; that is, the 80MHz PPDU contains four identical U-SIGs. PPDUs with a bandwidth exceeding 80MHz can contain different U-SIGs.

[0182] U-SIGs are configured in 20MHz units. For example, when an 80MHz PPDU is configured, the U-SIGs are duplicated; that is, the 80MHz PPDU contains four identical U-SIGs. PPDUs with a bandwidth exceeding 80MHz can contain different U-SIGs.

[0183] The EHT-SIG in Figure 18 may contain control information for the receiving STA. The EHT-SIG is transmitted via at least one symbol, which may have a length of 4 us. Information regarding the number of symbols used for the EHT-SIG is included in the U-SIG.

[0184] EHT-SIG incorporates the technical features of HE-SIG-B as described in Figures 8 and 9. For example, EHT-SIG can include common fields and user-specific fields, similar to the example in Figure 8. Common fields in EHT-SIG are omitted, and the number of user-specific fields is determined based on the number of users.

[0185] Similar to the example in Figure 8, the common fields and user-specific fields of the EHT-SIG are coded separately. A single user block field within a user-specific field can contain information for two users, while the last user block field within a user-specific field can contain information for one user. In other words, a single user block field in an EHT-SIG can contain a maximum of two user fields. Similar to the example in Figure 9, each user field is either related to MU-MIMO assignment or non-MU-MIMO assignment.

[0186] Similar to the example in Figure 8, the common field of the EHT-SIG can include a CRC bit and a Tail bit, with the length of the CRC bit determined to be 4 bits and the length of the Tail bit determined to be 6 bits and set to "000000".

[0187] Similar to the example in Figure 8, the common fields of the EHT-SIG can include RU allocation information. RU allocation information refers to information about the location of RUs to which multiple users (i.e., multiple receiving STAs) are allocated. RU allocation information is composed of 8-bit (or N-bit) units, as in Table 1.

[0188] Tables 5 through 7 show examples of 8-bit (or N-bit) information for various RU allocations. Each table and the displayed index can be modified, and some entries may be omitted from Tables 5 through 7, while others may be added that are not displayed.

[0189] Examples from Tables 5 to 7 relate to information regarding the location of RUs allocated in the 20 MHz band. For example, "Index 0" in Table 5 is used in a situation where nine 26RUs are allocated individually (for example, the situation shown in Figure 5 where nine 26RUs are allocated individually).

[0190] On the other hand, in the EHT system, multiple RUs can be assigned to a single STA. For example, in "Index 60" in Table 6, one 26RU is assigned to one user (i.e., a receiving STA) at the left end of the 20MHz band, one 26RU and one 52RU are assigned to another user (i.e., a receiving STA) to its right, and five 26RUs are individually assigned to the right of those.

[0191] [Table 5]

[0192] [Table 6]

[0193] [Table 7]

[0194] A mode in which the common field of the EHT-SIG is omitted is supported. This mode in which the common field of the EHT-SIG is omitted can be called compressed mode. When compressed mode is used, multiple users of the EHT PPDU (i.e., multiple receiving STAs) can decode the PPDU (e.g., the data field of the PPDU) based on non-OFDMA. That is, multiple users of the EHT PPDU can decode the PPDU (e.g., the data field of the PPDU) received over the same frequency band. On the other hand, when non-compressed mode is used, multiple users of the EHT PPDU can decode the PPDU (e.g., the data field of the PPDU) based on OFDMA. That is, multiple users of the EHT PPDU can receive the PPDU (e.g., the data field of the PPDU) over different frequency bands.

[0195] The EHT-SIG is constructed based on various MCS techniques. As mentioned above, information related to the MCS techniques applied to the EHT-SIG is included in the U-SIG. The EHT-SIG is constructed based on DCM techniques. For example, of the N data tones allocated for the EHT-SIG (e.g., 52 data tones), the first modulation technique is applied to half of the consecutive tones, and the second modulation technique is applied to the remaining half of the consecutive tones. That is, the transmitting STA can modulate specific control information to a first symbol based on the first modulation technique and assign it to half of the consecutive tones, and modulate the same control information to a second symbol based on the second modulation technique and assign it to the remaining half of the consecutive tones. As mentioned above, information related to whether or not DCM techniques are applied to the EHT-SIG (e.g., a 1-bit field) is included in the U-SIG. The EHT-STF in Figure 18 is used to improve automatic gain control estimation in MIMO (multiple input multiple output) or OFDMA environments. The EHT-LTF in Figure 18 is used to estimate the channel in MIMO or OFDMA environments.

[0196] The EHT-STF in Figure 18 can be configured in various types. For example, the first type of STF (i.e., 1x STF) is generated based on a first-type STF sequence in which non-zero coefficients are placed in 16 subcarrier intervals. The STF signal generated based on the first-type STF sequence can have a period of 0.8 μs, and a 0.8 μs periodic signal repeats 5 times to become a first-type STF with a length of 4 μs. For example, the second type of STF (i.e., 2x STF) is generated based on a second-type STF sequence in which non-zero coefficients are placed in 8 subcarrier intervals. The STF signal generated based on the second-type STF sequence can have a period of 1.6 μs, and a 1.6 μs periodic signal repeats 5 times to become a second-type EHT-STF with a length of 8 μs. Below, an example of a sequence for constructing an EHT-STF (i.e., an EHT-STF sequence) is presented. The following sequence can be modified in various ways.

[0197] EHT-STF is constructed based on the following M sequence.

[0198] [Mathematics 1] M={-1,-1,-1,1,1,1,-1,1,1,1,-1,1,1,-1,1}

[0199] The EHT-STF for a 20MHz PPDU is constructed based on the following formula. The following example is a first-type (i.e., 1x STF) sequence. For example, a first-type sequence is included in an EHT-PPDU that is not a TB (trigger-based) PPDU. In the following formula, (a:b:c) means an interval defined as b tone interval (i.e., subcarrier interval) from a tone index (i.e., subcarrier index) to c tone index. For example, formula 2 below can represent a sequence defined as a 16-tone interval from tone index -112 to index 112. Since a subcarrier spacing of 78.125kHz is applied to the EHT-STF, a 16-tone interval means that the EHT-STF coefficient (or element) is placed in a 78.125*16=1250kHz interval. Also, * means multiplication and sqrt() means square root.

[0200] [Math 2] EHT-STF(-112:16:112)={M}*(1+j) / sqrt(2) EHT-STF(0)=0

[0201] The EHT-STF for a 40MHz PPDU is constructed based on the following formula. The following example is a first-type (i.e., 1x STF) sequence.

[0202] [Mathematics 3] EHT-STF(-240:16:240)={M,0,-M}*(1+j) / sqrt(2)

[0203] The EHT-STF for an 80MHz PPDU is constructed based on the following formula. The following example is a first-type (i.e., 1x STF) sequence.

[0204] [Mathematics 4] EHT-STF(-496:16:496)={M,1,-M,0,-M,1,-M}*(1+j) / sqrt(2)

[0205] The EHT-STF for a 160MHz PPDU is constructed based on the following formula. The following example is a first-type (i.e., 1x STF) sequence.

[0206] [Math 5] EHT-STF(-1008:16:1008)={M,1,-M,0,-M,1,-M,0,-M,-1,M,0,-M,1,-M}*(1+j) / sqrt(2)

[0207] For an 80+80MHz PPDU, the sequence for the lower 80MHz of the EHT-STF is the same as in Equation 4. For an 80+80MHz PPDU, the sequence for the upper 80MHz of the EHT-STF is constructed based on the following formula.

[0208] [Mathematics 6] EHT-STF(-496:16:496)={-M,-1,M,0,-M,1,-M}*(1+j) / sqrt(2)

[0209] Equations 7 through 11 below relate to an example of a second-type (i.e., 2x STF) sequence.

[0210] [Mathematics 7] EHT-STF(-120:8:120)={M,0,-M}*(1+j) / sqrt(2)

[0211] The EHT-STF for 40MHz PPDU is constructed based on the following formula.

[0212] [Mathematics 8] EHT-STF(-248:8:248)={M,-1,-M,0,M,-1,M}*(1+j) / sqrt(2) EHT-STF(-248)=0 EHT-STF(248)=0

[0213] The EHT-STF for 80MHz PPDU is constructed based on the following formula.

[0214] [Mathematics 9] EHT-STF(-504:8:504)={M,-1,M,-1,-M,-1,M,0,-M,1,M,1,-M,1,-M}*(1+j) / sqrt(2)

[0215] The EHT-STF for 160MHz PPDU is constructed based on the following formula.

[0216] [Math 10] EHT-STF(-1016:16:1016)={M,-1,M,-1,-M,-1,M,0,-M,1,M,1,-M,1,-M,0,-M,1,-M,1,M,1,-M,0,-M,1,M,1,-M,1,-M}*(1+j) / sqrt(2) EHT-STF(-8)=0, EHT-STF(8)=0, EHT-STF(-1016)=0,EHT-STF(1016)=0

[0217] For an 80+80MHz PPDU, the sequence for the lower 80MHz of the EHT-STF is the same as in equation 9. For an 80+80MHz PPDU, the sequence for the upper 80MHz of the EHT-STF is constructed based on the following equation.

[0218] [Math 11] EHT-STF(-504:8:504)={-M,1,-M,1,M,1,-M,0,-M,1,M,1,-M,1,-M}*(1+j) / sqrt(2) EHT-STF(-504)=0, EHT-STF(504)=0

[0219] EHT-LTFs can have first, second, and third types (i.e., 1x, 2x, and 4x LTFs). For example, first / second / third type LTFs are generated based on LTF sequences in which non-zero coefficients are placed in 4 / 2 / 1 subcarrier intervals. First / second / third type LTFs can have time lengths of 3.2 / 6.4 / 12.8 μs. In addition, various lengths of GI (e.g., 0.8 / 1 / 6 / 3.2 μs) can be applied to first / second / third type LTFs.

[0220] Information regarding the type of STF and / or LTF (including information regarding GI applicable to the LTF) is contained in the SIG A field and / or SIG B field in Figure 18, etc.

[0221] The PPDU in Figure 18 (i.e., EHT-PPDU) is constructed based on the examples in Figures 5 and 6.

[0222] For example, an EHT PPDU transmitted over a 20MHz bandwidth, i.e., a 20MHz EHT PPDU, is constructed based on the RUs shown in Figure 5. That is, the locations of the RUs for the EHT-STF, EHT-LTF, and data fields included in the EHT PPDU are determined as shown in Figure 5.

[0223] An EHT PPDU transmitted over the 40MHz bandwidth, i.e., a 40MHz EHT PPDU, is constructed based on the RUs shown in Figure 6. That is, the location of the RUs for the EHT-STF, EHT-LTF, and data field included in the EHT PPDU is determined as shown in Figure 6.

[0224] Since the RU position in Figure 6 corresponds to 40MHz, repeating the pattern in Figure 6 twice will determine the tone plan for 80MHz. In other words, the 80MHz EHT PPDU is transmitted based on a new tone plan in which the RU in Figure 6 (which is not the RU in Figure 7) is repeated twice.

[0225] If the pattern in Figure 6 is repeated twice, the DC region will consist of 23 tones (i.e., 11 guard tones + 12 guard tones). That is, a tone plan for an 80MHz EHT PPDU allocated based on OFDMA can have 23 DC tones. On the other hand, an 80MHz EHT PPDU allocated based on Non-OFDMA (i.e., a non-OFDMA full bandwidth 80MHz PPDU) can be configured based on 996RU and may include 5 DC tones, 12 left-side guard tones, and 11 right-side guard tones.

[0226] The tone plan for 160 / 240 / 320MHz consists of the pattern shown in Figure 6 repeated many times.

[0227] The PPDU in Figure 18 is identified as an EHT PPDU based on the following method.

[0228] The receiving STA can determine the type of the received PPDU to be an EHT PPDU based on the following: For example, if 1) the first symbol after the L-LTF signal of the received PPDU is BPSK, 2) an RL-SIG (where the L-SIG is repeated) is detected in the received PPDU, and 3) applying "modulo3" to the value of the Length field of the L-SIG of the received PPDU results in "0", then the received PPDU is determined to be an EHT PPDU. If the received PPDU is determined to be an EHT PPDU, the receiving STA can detect the type of the EHT PPDU (e.g., SU / MU / Trigger-Based / Extended Range type) based on the bit information contained in the symbols after the RL-SIG in Figure 18. Furthermore, the receiving STA can determine that the received PPDU is an EHT PPDU based on 1) the first symbol after the L-LTF signal which is BSPK, 2) the RL-SIG which is consecutive to the L-SIG field and is the same as the L-SIG, and 3) the L-SIG which includes the Length field where the result of applying "modulo3" is set to "0".

[0229] For example, a receiving STA can determine the type of the received PPDU to be an HE PPDU based on the following: For example, if 1) the first symbol after the L-LTF signal is BPSK, 2) an RL-SIG (where L-SIG is repeated) is detected, and 3) the result of applying "modulo3" to the Length value of L-SIG is detected as "1" or "2", then the received PPDU is determined to be an HE PPDU.

[0230] For example, the receiving STA can determine the type of the received PPDU as non-HT, HT, or VHT PPDU based on the following: For example, if 1) the first symbol after the L-LTF signal is BPSK, and 2) no RL-SIG (where L-SIG is repeated) is detected, the received PPDU is determined to be non-HT, HT, or VHT PPDU. Also, even if the receiving STA detects a repetition of RL-SIG, if the result of applying "modulo3" to the Length value of L-SIG is detected as "0", the received PPDU is determined to be non-HT, HT, or VHT PPDU.

[0231] In the following example, signals referred to as (transmit / receive / up / down) signals, (transmit / receive / up / down) frames, (transmit / receive / up / down) packets, (transmit / receive / up / down) data units, (transmit / receive / up / down) data, etc., are signals transmitted and received based on the PPDU in Figure 18. The PPDU in Figure 18 is used to transmit and receive various types of frames. For example, the PPDU in Figure 18 is used for control frames. An example of a control frame may include RTS (request to send), CTS (clear to send), PS-Poll (Power Save-Poll), Block ACK Req, Block ACK, NDP (Null Data Packet) announcement, and Trigger frame. For example, the PPDU in Figure 18 is used for management frames. An example of a management frame may include Beacon frames, (Re-)Association request frames, (Re-)Association response frames, Probe request frames, and Probe response frames. For example, the PPDU in Figure 18 is used for data frames. For example, the PPDU in Figure 18 may be used to transmit at least two or more of the following simultaneously: control frames, management frames, and data frames.

[0232] Figure 19 shows a modified example of the transmitting and / or receiving apparatus described herein.

[0233] Each device / STA in Figures 1(a) / (b) is modified as shown in Figure 19. The transceiver (630) in Figure 19 is the same as the transceivers (113, 123) in Figure 1. The transceiver (630) in Figure 19 may include a receiver and a transmitter.

[0234] The processor (610) in Figure 19 is the same as the processors (111, 121) in Figure 1. Alternatively, the processor (610) in Figure 19 is the same as the processing chips (114, 124) in Figure 1.

[0235] The memory (150) in Figure 19 is the same as the memory (112, 122) in Figure 1. Alternatively, the memory (150) in Figure 19 is a different external memory than the memory (112, 122) in Figure 1.

[0236] Referring to Figure 19, the power management module (611) manages power to the processor (610) and / or transceiver (630). The battery (612) supplies power to the power management module (611). The display (613) outputs the results processed by the processor (610). The keypad (614) receives inputs used by the processor (610). The keypad (614) can display on the display (613). The SIM card (615) is an integrated circuit used to securely store IMSI (international mobile subscriber identity) and associated keys used to identify and authenticate subscribers in mobile phone devices such as mobile phones and computers.

[0237] Referring to Figure 19, the speaker (640) can output sound-related results processed by the processor (610). The microphone (641) can receive sound-related inputs used by the processor (610).

[0238] 1. STF sequence (or STF signal)

[0239] The primary purpose of the HE-STF field is to improve automatic gain control estimation in MIMO transmission.

[0240] Figure 20 shows an example of 2x HE-STF tones in channel-specific PPDU transmission according to this embodiment. Specifically, Figure 20 illustrates HE-STF tones with a periodicity of 1.6 μs (i.e., 8 tone samples) in 20 MHz / 40 MHz / 80 MHz bandwidths. Therefore, in Figure 21, the HE-STF tones for each bandwidth (or channel) can be positioned at intervals of 8 tones.

[0241] The 2x HE-STF signal shown in Figure 20 is applied to the uplink MU PPDU. That is, the PPDU transmitted over the uplink in response to the trigger frame described above includes the 2x HE-STF signal shown in Figure 20.

[0242] In Figure 20, the x-axis represents the frequency domain. The numbers on the x-axis indicate tone indices, and the arrows indicate that a non-zero value is mapped to the corresponding tone index.

[0243] Figure 20(a) is a diagram illustrating a 2x HE-STF tone in a 20MHz PPDU transmission.

[0244] Referring to Figure 20(a), when an HE-STF sequence for a period of 1.6 μs (i.e., a 2x HE-STF sequence) is mapped to a tone on a 20 MHz channel, the 2x HE-STF sequence is mapped to tones with tone indices ranging from -120 to 120, excluding DC, that have tone indices that are multiples of 8, and 0 is mapped to the remaining tones. In other words, on a 20 MHz channel, a 2x HE-STF tone can be located at a tone index that is a multiple of 8, excluding DC, among the tones with tone indices ranging from -120 to 120. Therefore, there are a total of 30 2x HE-STF tones on a 20 MHz channel to which a 2x HE-STF sequence can be mapped.

[0245] Figure 20(b) is a diagram illustrating a 2x HE-STF tone in 40MHz PPDU transmission.

[0246] Referring to Figure 20(b), when an HE-STF sequence for a period of 1.6 μs (i.e., a 2x HE-STF sequence) is mapped to a tone on a 40 MHz channel, the 2x HE-STF sequence is mapped to tones with tone indices ranging from -248 to 248, excluding DC, that have tone indices that are multiples of 8, and 0 is mapped to the remaining tones. In other words, on a 40 MHz channel, a 2x HE-STF tone can be located at a tone index ranging from -248 to 248, excluding DC, that has tone indices that are multiples of 8. However, tones with tone indices ±248 here are guard tones (left and right guard tones) and are nulled (i.e., have a value of 0). Therefore, there are a total of 60 2x HE-STF tones on a 40 MHz channel to which a 2x HE-STF sequence can be mapped.

[0247] Figure 20(c) is a diagram illustrating a 2x HE-STF tone in 80MHz PPDU transmission.

[0248] Referring to Figure 20(c), when an HE-STF sequence for a 1.6 μs period (i.e., a 2x HE-STF sequence) is mapped to a tone on an 80 MHz channel, the 2x HE-STF sequence is mapped to tones with tone indices ranging from -504 to 504, excluding DC, that have tone indices that are multiples of 8, and 0 is mapped to the remaining tones. In other words, on an 80 MHz channel, a 2x HE-STF tone can be located at a tone index ranging from -504 to 504, excluding DC, that has tone indices that are multiples of 8. However, tones with tone indices ±504 are guard tones (left and right guard tones) and are nulled (i.e., have a value of 0). Therefore, there are a total of 124 2x HE-STF tones on an 80 MHz channel to which a 2x HE-STF sequence can be mapped.

[0249] The 2x HE-STF sequence in Figure 20 is used to construct the HE-STF field for HE TB PPDU.

[0250] 1. Embodiments applicable to this specification

[0251] In wireless LAN 802.11 systems, we are considering using a wider bandwidth than existing 802.11ax or transmitting increased streams using more antennas to increase peak throughput. We are also considering methods of using aggregation of various bands.

[0252] In this specification, considering the use of a wide bandwidth, specifically the case of transmitting PPDU using 240 / 320 MHz, we propose a 2x EHT STF sequence. In particular, various RU aggregations are considered.

[0253] In the existing 802.11ax standard, 1x / 2x HE-STF sequences are defined. 1x HE-STF is used for all HE PPDUs except uplink-transmitted HE TB PPDUs, while 2x HE-STF is used for HE TB PPDUs. The 1x HE-STF sequence is mapped to 16 subcarrier units, and performing an IFFT on this generates a 12.8us symbol, with the same signal repeated every 0.8us. Repeating this 0.8us signal five times constitutes a 4us 1x HE-STF. The 2x HE-STF sequence is mapped to 8 subcarrier units, and performing an IFFT on this generates a 12.8us symbol, with the same signal repeated every 1.6us. Repeating this 1.6us signal five times constitutes an 8us 2x HE-STF. In this specification, the design of a 2x STF sequence for transmitting PPDUs in wideband is discussed, and this is referred to as the 2x EHT-STF sequence. Figure 18 shows a typical structure of an 802.11be PPDU, and the proposed 2x EHT-STF sequence is the frequency domain sequence applied to the EHT-STF in Figure 18. In the case of an EHT TB PPDU to which the 2x EHT-STF sequence is applied in Figure 18, the EHT-SIG may be omitted.

[0254] The above can be expressed separately as follows: The STF signal is generated based on an STF sequence. The STF sequence is expressed based on a pre-set subcarrier interval (e.g., 78.125 kHz). The STF sequence described herein is referred to by various names such as EHT-STF sequence or EHT STF sequence.

[0255] As mentioned above, STFs can be set in various types. For example, the first type of STF (i.e., 1xSTF) is generated based on a first-type STF sequence in which non-zero coefficients are arranged at 16 subcarrier intervals. The STF signal generated based on the first-type STF sequence has a period of 0.8 μs, and this 0.8 μs periodic signal is repeated 5 times to become a first-type STF with a length of 4 μs (shown in Figure 20). For example, the second type of STF (i.e., 2x STF) is generated based on a second-type STF sequence in which non-zero coefficients are arranged at 8 subcarrier intervals. The STF signal generated based on the second-type STF sequence has a period of 1.6 μs, and this 1.6 μs periodic signal is repeated 5 times to become a second-type EHT-STF with a length of 8 μs (shown in Figure 21). For example, among STFs, the third type (i.e., 4xEHT-STF) is generated based on a third-type STF sequence in which non-zero coefficients are arranged at four subcarrier intervals.

[0256] As mentioned above, the second type (i.e., 2x STF) STF is used for TB PPDUs that are transmitted in response to the Trigger Frame, while the first type STF is used for other types of SU / MU PPDUs that are not TB PPDUs.

[0257] In 802.11be, the contiguous 240 / 320MHz and non-contiguous 160+80 / 80+160 / 160+160MHz bandwidths are further utilized in addition to the existing 20 / 40 / 80 / 160 / 80+80MHz bandwidths, and the configuration of the 2x EHT-STF sequence applied to 240 / 320MHz may differ depending on the tone plan. In this specification, we consider a broadband tone plan with a structure in which the existing 80MHz tone plan of 11ax is repeated. In such a situation, a broadband 2x EHT-STF sequence can be constructed by repeating an 80MHz 2x STF sequence. However, due to the repeating nature of the sequence, the PAPR may be high, and therefore it is necessary to apply further phase rotation. In 802.11ax, a 160MHz 2x HE-STF sequence was constructed by repeating an 80MHz 2x HE-STF sequence twice, and then the sequence was constructed by multiplying the first 40MHz portion of the secondary 80MHz channel (or a relatively high-frequency 80MHz channel) by -1. In this specification, we extend and apply this method, proposing a sequence in which an 80MHz 2x STF sequence is repeated, and an additional phase rotation of 20 / 40 / 80MHz units is applied to the channels other than the primary channel (or a relatively low-frequency 80MHz channel) to lower the PAPR. Furthermore, at 320MHz, we propose a sequence in which a 160MHz 2x STF sequence is repeated, and an additional phase rotation of 20 / 40 / 80 / 160MHz units is applied to the secondary 160MHz channel (or a relatively high-frequency 160MHz channel) to lower the PAPR. 240 / 160+80 / 80+160MHz can be considered as 320 / 160+160MHz with the 80MHz portion punctured.In other words, the sequence obtained by removing the punctured 80MHz 2x EHT-STF portion from a 2x EHT-STF used at 320 / 160+160MHz can be used for a 2x EHT-STF at 240 / 160+80 / 80+160MHz. Therefore, in this specification, we first propose a 320 / 160+160MHz 2x EHT-STF sequence, and then propose a 240 / 160+80 / 80+160MHz 2x EHT-STF sequence obtained by puncturing this sequence. We also propose a 2x EHT-STF sequence based on the repetition of an 80MHz 2x STF sequence at 240 / 160+80 / 80+160MHz.

[0258] When optimizing a 2x EHT-STF sequence, the PAPR (Peak To Average Power Ratio) must be considered for each RU because it is applied to the TB PPDU. Furthermore, since multiple RU aggregation has been approved in 802.11be, the PAPR for specific RU combinations must also be considered. Below is a list of RUs and RU combinations considered when calculating PAPR when optimizing a 2x EHT-STF sequence at 320MHz and 240MHz.

[0259] 320MHz: 26RU (148 pieces), 52RU (64 pieces), 106RU (32 pieces), 242RU (16 pieces), 484RU (8 pieces), 996 RU (4 pieces), 26+52RU (16 pieces), 242+484RU (16 pieces), 2x996 RU (2 pieces), 484+996 RU(8 pieces), 3x996 RU(4 pieces), 4x 996 RU(1 piece)

[0260] 240MHz: 26RU (111 pieces), 52RU (48 pieces), 106RU (24 pieces), 242RU (12 pieces), 484RU (6 pieces), 996 RU (3 pieces), 26+52RU (12 pieces), 242+484RU (12 pieces), 2x996 RU (2 pieces), 484+996 RU(8 pieces), 3x996 RU(1 piece)

[0261] Figure 7 shows the tone plan for the 80MHz bandwidth. Repeating this four times or three times results in the number of RUs as described above.

[0262] Figure 21 is a diagram showing the 26+52RU combination in an 80MHz band tone plan.

[0263] In the case of RU aggregation, 26+52RU allows for four consecutive combinations of 26RU and 52RU, as shown by the shading in Figure 21 for each 80MHz channel. Therefore, at 320MHz, 16 different combinations of 26RU and 52RU are possible, and at 240MHz, 12 different combinations are possible.

[0264] The 242+484RU allows for a total of four different combinations on each 80MHz channel. Therefore, 16 different combinations are possible at 320MHz, and 12 different combinations are possible at 240MHz.

[0265] 484+996 RU allows for a total of 4 combinations on each 160MHz channel, this combination is permitted on both the primary 160MHz and secondary 160MHz channels at 320MHz, resulting in a total of 8 combinations, and this combination is permitted on two consecutive 80MHz channels at 240MHz, similarly resulting in a total of 8 combinations.

[0266] 2x996 RU allows for one combination in total for each 160MHz channel, this combination is permitted for both the primary 160MHz and secondary 160MHz at 320MHz, allowing for a total of two combinations, and this combination is permitted for two consecutive 80MHz channels at 240MHz, similarly allowing for a total of two combinations.

[0267] At 320MHz, 3x996 RU allows for a total of four possible combinations of 996 RUs, while at 240MHz, only one combination is possible.

[0268] Only one combination of 4x 996 RU is possible at 320MHz.

[0269] In the following proposal, PAPR refers to the largest PAPR value among multiple RUs and RU combinations. Furthermore, the sequence is optimized from a PAPR perspective, and while bandwidth is considered only for contiguous situations during PAPR calculation, the proposed sequence is also applied directly to non-contiguous situations.

[0270] We propose an optimized sequence using the same M sequence as in 802.11ax, and the M sequence is as follows:

[0271] M={-1,-1,-1,1,1,1,-1,1,1,1,-1,1,1,-1,1}

[0272] In the following example, the method for displaying the sequence is based on the following:

[0273] For example, EHTS -496:16:496 In the case of a sequence, the sequence is defined within an index range from -496 to +496, with elements defined at intervals of only 16. That is, specific values ​​are assigned to -496, -480, -464, and so on.

[0274] In this specification, 1x sequencing is EHTS -496:16:496 A sequence is defined with 16 index intervals, as in a standard sequence. Similarly, a 2x sequence is defined with 8 index intervals. For example, a 4x sequence is defined with 4 index intervals.

[0275] The index of a sequence can indicate its position in the frequency domain and is determined based on the subcarrier frequency spacing value. For example, when delta_f (e.g., 78.125kHz) is applied to an HE-STF sequence (or HE-STF field), index 0 means the DC element, index 16 means the 16*delta_fkHz point, and index -16 means the -16*delta_fkHz point. For example, the delta_f value can be set to 312.5kHz / N (N=integer) or 312.5kHz*N (N=integer).

[0276] On the other hand, for the sake of explanation, comma notation can be omitted within the sequence, but for example, {M 1 -M 0 -M 1 -M}*(1+j) / sqrt(2) means {M,1,-M,0,-M,1,-M}*(1+j) / sqrt(2).

[0277] 2.1.320MHz 2x EHT-STF sequence

[0278] A method of simply repeating the existing 80MHz 1x HE STF sequence and a sequence are proposed, which repeats this and applies additional phase rotation in units of 20 / 40 / 80MHz to channels other than the primary channel (or 80MHz channels with relatively low frequencies) to reduce the PAPR. Also, a method of simply repeating the existing 160MHz 1x HE STF sequence and a sequence are proposed, which repeats this and applies additional phase rotation in units of 20 / 40 / 80 / 160MHz to the secondary 160MHz channel (or 160MHz channels with relatively high frequencies) to reduce the PAPR. For reference, all the following PAPRs are calculated when applying a 4-fold IFFT (Inverse Fast Fourier Transform) / IDFT (Inverse Discrete Fourier Transform), and the unit is dB.

[0279] 2.1.180MHz 2x HE-STF sequence repetition

[0280] The existing 80MHz 2x HE-STF sequence of 802.11ax can be repeated 4 times to form a 2x EHT-STF sequence as follows.

[0281] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0282] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS1016 =EHTS 1032 =EHTS 2040 =0

[0283] Max PAPR is 10.8833.

[0284] 2.1. 280MHz 2x HE-STF sequence repetition and additional phase rotation in 20MHz units on the secondary channel (or channels excluding the lowest frequency 80MHz channel).

[0285] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0286] or

[0287] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0288] or

[0289] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M-1 M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M1 M 1 -M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0290] Of all the sequences mentioned above, the following coefficients are replaced with 0.

[0291] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0292] Max PAPR is 7.7789.

[0293] 2.1.3.80MHz 2x HE-STF sequence repetition and additional phase rotation in 40MHz units on the secondary channel (or channels excluding the lowest frequency 80MHz channel).

[0294] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0295] or

[0296] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0297] Of all the sequences mentioned above, the following coefficients are replaced with 0.

[0298] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0299] The maximum PAPR is 8.9154.

[0300] 2.1.4. 80MHz 2x HE-STF sequence repetition and additional phase rotation in 80MHz units in the secondary channel (or channels excluding the lowest frequency 80MHz channel).

[0301] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0302] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016=EHTS 1032 =EHTS 2040 =0

[0303] Max PAPR is 9.0112.

[0304] As in this embodiment (2.1.4), the 2x EHT-STF sequence obtained by repeatedly using an 80MHz 2x HE-STF sequence and considering additional phase rotation has an even lower PAPR than the 2x EHT-STF sequence obtained by simply repeating an 80MHz 2x HE-STF sequence as in the above embodiment (2.1.1). This has the effect of allowing estimation of subcarrier efficiency and effective AGC.

[0305] Furthermore, in the proposed 2x EHT-STF sequence, even if a specific non-zero coefficient is set for the elements with tone indices of -8, +8, -1016, +1016, -1032, +1032, -2040, and +2040, there is no problem from the PAPR perspective. However, from the perspective of transmission power, which is not from the PAPR perspective, power may be supplied to tones that do not need power, resulting in performance loss. In particular, if a specific non-zero coefficient is supplied to DC, problems such as DC offset may occur, causing signal distortion. That is, by setting the elements with tone indices of -8, +8, -1016, +1016, -1032, +1032, -2040, and +2040 to 0, it is possible to solve the problem of performance loss when AGC is operating in the receiving STA.

[0306] 2.1.5. 160MHz 2x HE-STF sequence repeat

[0307] The existing 802.11ax 160MHz 2x HE-STF sequence can be repeated twice to construct a 2x EHT-STF sequence, as follows:

[0308] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0309] Of all the sequences mentioned above, the following coefficients are replaced with 0.

[0310] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0311] MaxPAPR is 9.0115.

[0312] 2.1.6. 160MHz 2x HE-STF sequence repetition and additional phase rotation in 20MHz units on the secondary channel (or the relatively high frequency 160MHz channel)

[0313] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0314] or

[0315] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0316] Or

[0317] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0318] Or

[0319] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0320] Or

[0321] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0322] Or

[0323] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0324] Or

[0325] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0326] Or

[0327] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0328] Or

[0329] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0330] Or

[0331] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0332] Or

[0333] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 M -1 M 1 M 1 -M 0-M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0334] Or

[0335] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0336] Or

[0337] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0338] Or

[0339] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0340] Or

[0341] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0342] Or

[0343] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0344] Or

[0345] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0346] Or

[0347] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0348] Or

[0349] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0350] Or

[0351] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0352] Or

[0353] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0354] Or

[0355] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0356] Or

[0357] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0358] Or

[0359] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0360] Or

[0361] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0362] Or

[0363] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0364] Or

[0365] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0366] Or

[0367] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0368] Or

[0369] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0370] Or

[0371] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0372] Or

[0373] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0374] Or

[0375] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0376] Or

[0377] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0378] Or

[0379] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0380] Or

[0381] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0382] Or

[0383] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0384] Or

[0385] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0386] Or

[0387] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0388] Or

[0389] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0390] Or

[0391] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0392] Or

[0393] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0394] Or

[0395] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0396] Or

[0397] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0398] Or

[0399] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0400] Or

[0401] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0402] Or

[0403] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0404] Or

[0405] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M 1 M 1 -M 0-M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0406] Or

[0407] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0408] Or

[0409] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0410] Or

[0411] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0412] Or

[0413] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0414] Or

[0415] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0416] Or

[0417] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0418] Or

[0419] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0420] Or

[0421] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0422] Or

[0423] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0424] Or

[0425] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0426] Or

[0427] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0428] Or

[0429] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0430] Or

[0431] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0432] Or

[0433] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0434] Or

[0435] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0436] Or

[0437] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0438] Or

[0439] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0440] Or

[0441] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0442] Or

[0443] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 M -1 M 1 M 1 -M 0-M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0444] Or

[0445] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0446] Or

[0447] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0448] Or

[0449] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0450] Or

[0451] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0452] Or

[0453] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0454] Or

[0455] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0456] Or

[0457] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0458] Or

[0459] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0460] Or

[0461] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0462] Or

[0463] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0464] Or

[0465] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0466] Or

[0467] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0468] Or

[0469] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0470] Or

[0471] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0472] Or

[0473] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0474] Or

[0475] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0476] Or

[0477] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0478] Or

[0479] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0480] Or

[0481] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0482] Or

[0483] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0484] Or

[0485] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0486] Or

[0487] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0488] Or

[0489] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0490] Or

[0491] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0492] Or

[0493] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0494] Or

[0495] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0496] Or

[0497] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0498] Or

[0499] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0500] Or

[0501] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0502] Or

[0503] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0504] Or

[0505] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0506] Or

[0507] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0508] Or

[0509] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0510] Or

[0511] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0512] Or

[0513] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0514] Or

[0515] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0516] Or

[0517] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0518] Or

[0519] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0520] Or

[0521] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0522] Or

[0523] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0524] Or

[0525] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0526] Or

[0527] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0528] Or

[0529] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M 1 M 1 -M 0-M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0530] Or

[0531] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0532] Or

[0533] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0534] Or

[0535] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0536] Or

[0537] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0538] Or

[0539] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0540] Or

[0541] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0542] Or

[0543] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0544] Or

[0545] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0546] Or

[0547] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1-M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0548] Or

[0549] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1-M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0550] Or

[0551] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1-M 0 M -1 -M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0552] Or

[0553] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1-M 0 M -1 -M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0554] Or

[0555] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1-M 0 M -1 -M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0556] Or

[0557] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1-M 0 M -1 -M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0558] Or

[0559] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1-M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0560] Or

[0561] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1-M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0562] Or

[0563] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1-M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0564] Or

[0565] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1-M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0566] Or

[0567] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0568] Or

[0569] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0570] Or

[0571] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0572] Or

[0573] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0574] Or

[0575] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0576] Or

[0577] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0578] Or

[0579] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 M -1 M 1 M 1 -M 0-M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0580] Or

[0581] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0582] or

[0583] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0584] Of all the sequences mentioned above, the following coefficients are replaced with 0.

[0585] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0586] MaxPAPR is 9.0115.

[0587] 2.1.7. 160MHz 2x HE-STF sequence repetition and additional phase rotation in 40MHz units on the secondary channel (or the relatively high frequency 160MHz channel)

[0588] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0589] Or

[0590] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0591] Or

[0592] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0593] Or

[0594] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0595] or

[0596] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0597] or

[0598] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0599] Of all the sequences mentioned above, the following coefficients are replaced with 0.

[0600] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0601] MaxPAPR is 9.0115.

[0602] 2.1.8. 160MHz 2x HE-STF sequence repetition and additional phase rotation in 80MHz units on the secondary channel (or the relatively high frequency 160MHz channel)

[0603] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0604] or

[0605] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0606] Of all the sequences mentioned above, the following coefficients are replaced with 0.

[0607] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0608] MaxPAPR is 9.0115.

[0609] 2.1.9. 160MHz 2x HE-STF sequence repetition and additional phase rotation in 160MHz units in the secondary channel (or the relatively high frequency 160MHz channel)

[0610] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0611] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0612] MaxPAPR is 9.0115.

[0613] From a PAPR perspective, proposal 2.1.2 is appropriate. From an implementation perspective, method 2.1.4, which involves repeatedly performing an 11ax 80MHz phase rotation and multiplying the high frequency 160MHz or secondary 160MHz portion by -1, is advantageous. Alternatively, simply repeating an 11ax 1600MHz phase rotation is advantageous from an implementation standpoint.

[0614] In the above, a 2x EHT-STF sequence for a contiguous 320MHz situation is proposed. This sequence can also be applied to a non-contiguous 160+160MHz situation. That is, the sequence corresponding to low 160MHz in the 2x EHT-STF sequence at contiguous 320MHz is applied to either low 160MHz or primary 160MHz in the non-contiguous 160+160MHz situation, and the sequence corresponding to high 160MHz in the 2x EHT STF sequence at contiguous 320MHz is applied to either high 160MHz or secondary 160MHz in the non-contiguous 160+160MHz situation. For example, considering the sequence proposed in 2.1.4, the sequence for non-contiguous 160+160MHz can be expressed as follows.

[0615] Contiguous 320MHz

[0616] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0617] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0618] Non-contiguous 160+160MHz

[0619] Low 160MHz or primary 160MHz

[0620] EHTS -1016:8:1016 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0621] EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =0

[0622] High 160MHz or secondary 160MHz

[0623] EHTS -1016:8:1016 ={-M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0624] EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =0

[0625] As another example, considering the sequence proposed in 2.1.9, the sequence at non-contiguous 160+160MHz can be expressed as follows:

[0626] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0627] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0628] Non-contiguous 160+160MHz

[0629] Low 160MHzまたはprimary 160MHz

[0630] EHTS -1016:8:1016 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0631] EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =0

[0632] High 160MHzまたはsecondary 160MHz

[0633] EHTS -1016:8:1016 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0634] EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =0

[0635] 2.2.240MHz 2x EHT-STF sequence

[0636] Of the 2x EHT-STF proposed at 320MHz mentioned above, the punctured 80MHz 2x EHT-STF portion can be excluded and proposed for 240 / 160+80 / 80+160MHz.

[0637] 2.2.1.320MHz 2x EHT-STF puncturing

[0638] For example, let's assume the following 320MHz 2x EHT-STF sequence is used.

[0639] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0640] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0641] In this case, if the first 80MHz signal is punctured, the following 240MHz 2x EHT STF sequence can be used.

[0642] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0643] EHTS-1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[0644] If the second 80MHz is punctured, the following 240MHz 2x EHT STF sequence can be used.

[0645] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0646] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[0647] If the third 80MHz is punctured, the following 240MHz 2x EHT STF sequence can be used.

[0648] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0649] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[0650] If the fourth 80MHz is punctured, the following 240MHz 2x EHT STF sequence can be used.

[0651] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0652] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[0653] As another example, let's assume the following 320MHz 2x EHT STF sequence is used.

[0654] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0655] In this case, if the first 80MHz signal is punctured, the following 240MHz 2x EHT STF sequence can be used.

[0656] EHTS -1528:8:1528 ={-M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0657] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[0658] If the second 80MHz is punctured, the following 240MHz 2x EHT STF sequence can be used.

[0659] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0660] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[0661] If the third 80MHz is punctured, the following 240MHz 2x EHT STF sequence can be used.

[0662] EHTS -1528:8:1528={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0663] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[0664] If the fourth 80MHz is punctured, the following 240MHz 2x EHT STF sequence can be used.

[0665] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0666] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[0667] Furthermore, we propose a method of simply repeating the existing 80MHz 2x HE STF sequence, and a sequence that repeats this and applies additional phase rotation in units of 20 / 40 / 80MHz to the other channels, excluding the primary channel (or the 80MHz channel with a relatively low frequency), to lower the PAPR.

[0668] 2.2.2.80MHz 2x HE-STF sequence repeat

[0669] The existing 80MHz 2x HE-STF sequence can be repeated three times to construct a 2x EHT-STF sequence, as follows:

[0670] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0671] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[0672] Max PAPR is 9.6339.

[0673] 2.2.3.80MHz 2x HE-STF sequence repetition and additional phase rotation in 20MHz units on the secondary channel (or channels excluding the lowest frequency 80MHz channel).

[0674] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0675] Of all the sequences mentioned above, the following coefficients are replaced with 0.

[0676] EHTS -1528 =EHTS-520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[0677] Max PAPR is 7.6361.

[0678] 2.2.4.80MHz 2x HE-STF sequence repetition and additional phase rotation in 40MHz units on the secondary channel (or channels excluding the lowest frequency 80MHz channel).

[0679] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0680] or

[0681] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0682] Of all the sequences mentioned above, the following coefficients are replaced with 0.

[0683] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[0684] Max PAPR is 8.7809.

[0685] As in this embodiment (2.2.4), the 2x EHT-STF sequence obtained by repeatedly using an 80MHz 2x HE-STF sequence and considering additional phase rotation has an even lower PAPR than the 2x EHT-STF sequence obtained by simply repeating an 80MHz 2x HE-STF sequence as in the above embodiment (2.2.2). This has the effect of allowing estimation of subcarrier efficiency and effective AGC.

[0686] Furthermore, in the proposed 2x EHT-STF sequence, there are no problems from a PAPR perspective even if a specific non-zero coefficient is set for the elements with tone indices of -504, +504, -520, +520, -1528, and +1528. However, from a transmission power perspective, not a PAPR perspective, power may be supplied to tones that do not need power, resulting in performance loss. In particular, if a specific non-zero coefficient is supplied to DC, problems such as DC offset may occur, causing signal distortion. That is, by setting the elements with tone indices of -504, +504, -520, +520, -1528, and +1528 to 0, it is possible to solve the performance loss problem during AGC operation in the receiving STA.

[0687] 2.2.5.80MHz 2x HE-STF sequence repetition and additional phase rotation in 80MHz units in the secondary channel (or channels excluding the lowest frequency 80MHz channel).

[0688] EHTS -1528:8:1528={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0689] or

[0690] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0691] Of all the sequences mentioned above, the following coefficients are replaced with 0.

[0692] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[0693] Max PAPR is 8.7809.

[0694] When constructing a 240MHz 2x EHT-STF sequence by puncturing a 320MHz signal, the method in 2.2.1 is preferred, as this provides the implemented gain as a 2x EHT-STF sequence coupled with 320MHz. While the method in 2.2.3 may also be preferred when considering PAPR and various RF capability situations, it may increase implementation overhead. The more advantageous method in implementation is the one in 2.2.5 (where the primary 80MHz is excluded, or where all frequencies except the lowest frequency 80MHz are multiplied by -1).

[0695] In the above, a 2x EHT-STF sequence for a contiguous 240MHz situation is proposed. This sequence can also be applied to a non-contiguous 160+80MHz situation. That is, the sequence corresponding to low 80 / 160MHz in the 2x EHT-STF sequence for a contiguous 240MHz situation is applied to either low 80 / 160MHz or primary 80 / 160MHz in a non-contiguous 160+80MHz situation, and the sequence corresponding to high 160 / 80MHz in the 2x EHT-STF sequence for a contiguous 240MHz situation is applied to either high 160 / 80MHz or the other 160 / 80MHz in a non-contiguous 160+80MHz situation. For example, considering the sequence proposed in 2.2.5, the sequence for a non-contiguous 160+80MHz situation can be expressed as follows.

[0696] Contiguous 240MHz

[0697] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0698] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[0699] Non-contiguous 160+80MHz (when 160MHz is at a low frequency and 80MHz is at a high frequency, or when primary 160MHz is continuous)

[0700] Low 160MHz or primary 160MHz

[0701] EHTS -1016:8:1016 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0702] EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =0

[0703] High 80MHz or the other 80MHz

[0704] EHTS -504:5:504 ={-M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0705] EHTS -504 =EHTS 504 =0

[0706] Non-contiguous 160+80MHz (when 80MHz is at low frequency and 160MHz is at high frequency, or when only primary 80MHz is continuous)

[0707] Low 80MHz or primary 80MHz

[0708] EHTS -504:5:504 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0709] EHTS -504 =EHTS 504 =0

[0710] High 160MHz or the other 160MHz

[0711] EHTS -1016:8:1016 ={-M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0712] EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =0

[0713] Furthermore, this specification proposes a 2x EHT-STF sequence that minimizes maximum PAPR in a situation that also takes into account the preamble puncturing pattern and full bandwidth allocation (i.e., non-preamble puncturing).

[0714] The following shows the non-preamble puncturing and preamble puncturing considered at 320 MHz.

[0715] Full band allocation:[OOOO OOOO OOOO OOOO]

[0716] Preamble puncturing

[0717] [XXOO OOOO OOOO OOOO]

[0718] [OOXX OOOO OOOO OOOO]

[0719] [OOOO XXOO OOOO OOOO]

[0720] [OOOO OOXX OOOO OOOO]

[0721] [OOOO OOOO XXOO OOOO]

[0722] [OOOO OOOO OOXX OOOO]

[0723] [OOOO OOOO OOOO XXOO]

[0724] [OOOO OOOO OOOO OOXX]

[0725] [XXXX OOOO OOOO OOOO]

[0726] [OOOO XXXX OOOO OOOO]

[0727] [OOOO OOOO XXXX OOOO]

[0728] [OOOO OOOO OOOO XXXX]

[0729] In the above, O or X means that a specific 20MHz channel is either not punctured or has been punctured, and the channels are listed in order from the lowest frequency 20MHz channel to the highest frequency 20MHz channel.

[0730] Furthermore, the non-preamble puncturing and preamble puncturing considered at 240MHz are shown below.

[0731] Full band allocation:[OOOO OOOO OOOO]

[0732] Preamble puncturing

[0733] [XXOO OOOO OOOO]

[0734] [OOXX OOOO OOOO]

[0735] [OOOO XXOO OOOO]

[0736] [OOOO OOXX OOOO]

[0737] [OOOO OOOO XXOO]

[0738] [OOOO OOOO OOXX]

[0739] [XXXX OOOO OOOO]

[0740] [OOOO XXXX OOOO]

[0741] [OOOO OOOO XXXX]

[0742] The aforementioned preamble puncturing pattern is indicated by the Punctured Channel Information field of U-SIG (U-SIG-2). The Punctured Channel Information field consists of 5 bits.

[0743] Specifically, when a PPDU is transmitted using a non-OFDMA method, the five bits in the Punctured Channel Information field are set according to the items in the table below to signal the non-OFDMA puncturing pattern for the entire PPDU bandwidth. The table below defines the preamble puncturing patterns for non-OFDMA methods for different PPDU bandwidths. Values ​​not defined in the Punctured Channel Information field are valid.

[0744] JPEG0007909578000008.jpg64145

[0745] JPEG0007909578000009.jpg107131

[0746] JPEG0007909578000010.jpg116144

[0747] As another example, when a PPDU is transmitted using the OFDMA method, if the bandwidth is first specified as 80 / 160 / 320MHz based on the BW (bandwidth) field of U-SIG-1, then the 4-bit bitmap (the last bit is ignored) in the Punctured Channel Information field can indicate whether or not puncturing is performed for each 80MHz segment (20MHz channel). The 4-bit bitmap is applied from the lowest bit to the highest bit, from the lowest frequency 20MHz channel to the highest frequency 20MHz channel. If each bit of the 4-bit bitmap points to 0, the corresponding 20MHz channel is punctured, and if each bit of the 4-bit bitmap points to 1, the corresponding 20MHz channel is not punctured. The permitted puncturing patterns for an 80MHz segment are as follows: 0111, 1011, 1101, 1110, 0011, 1100, and 1001. Other field values ​​are also valid in addition to the permitted puncturing patterns. The field values ​​for the aforementioned puncturing pattern may differ from those for other 80MHz frequencies.

[0748] In the following proposal, PAPR refers to the largest PAPR value among multiple RUs, RU combinations, and preamble puncturing patterns. Furthermore, the sequence is optimized from a PAPR perspective, and during PAPR calculation, the bandwidth is considered only for contiguous situations, but the proposed sequence is also applied directly to non-contiguous situations.

[0749] 2.3.320MHz 2x EHT STF sequence

[0750] We propose a method for simply repeating the existing 80MHz 2x HE STF sequence, and a sequence that repeats this sequence and applies additional phase rotation in units of 20 / 40 / 80MHz to the channels other than the primary channel (or the 80MHz channel with a relatively low frequency) to lower the PAPR. We also propose a method for simply repeating the existing 160MHz 2x HE STF sequence, and a sequence that repeats this sequence and applies additional phase rotation in units of 20 / 40 / 80 / 160MHz to the secondary 160MHz channel (or the 160MHz channel with a relatively high frequency) to lower the PAPR. For reference, all PAPRs below are calculated using a 4x IFFT and are in dB.

[0751] 2.3.1.80MHz 2x HE STF sequence repeat

[0752] An existing 80MHz 2x HE STF sequence can be repeated four times to construct a 2x EHT STF sequence, as follows:

[0753] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0754] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS2040 =0

[0755] Max PAPR is 10.8833.

[0756] 2.3.2.80MHz 2x HE STF sequence repetition and additional phase rotation in 20MHz units in the secondary channel (or channels excluding the lowest frequency 80MHz channel).

[0757] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 -M 1-M 1 M 1 -M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0758] Of the sequences mentioned above, the following coefficients are replaced with 0.

[0759] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0760] Max PAPR is 7.9806.

[0761] 2.3.3.80MHz 2x HE STF sequence repetition and additional phase rotation in 40MHz units on the secondary channel (or channels excluding the lowest frequency 80MHz channel).

[0762] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0763] or

[0764] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0765] Of all the sequences mentioned above, the following coefficients are replaced with 0.

[0766] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0767] The maximum PAPR is 8.9154.

[0768] 2.3.4.80MHz 2x HE STF sequence repetition and additional phase rotation in 80MHz units in the secondary channel (or channel excluding the lowest frequency 80MHz channel).

[0769] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0770] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0771] Max PAPR is 9.7431.

[0772] 2.3.5. 160MHz 2x HE STF sequence repeat

[0773] An existing 160MHz 2x HE STF sequence can be repeated twice to construct a 2x EHT STF sequence, as follows:

[0774] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0775] Of all the sequences mentioned above, the following coefficients are replaced with 0.

[0776] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8=EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0777] MaxPAPR is 9.0115.

[0778] 2.3.6. 160MHz 2x HE STF sequence repetition and additional phase rotation in 20MHz units on the secondary channel (or the relatively high frequency 160MHz channel)

[0779] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0780] or

[0781] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0782] or

[0783] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0784] Or

[0785] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0786] Or

[0787] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0788] Or

[0789] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0790] Or

[0791] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0792] Or

[0793] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0794] Or

[0795] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0796] Or

[0797] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0798] Or

[0799] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0800] Or

[0801] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0802] Or

[0803] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0804] Or

[0805] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0806] Or

[0807] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0808] Or

[0809] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0810] Or

[0811] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0812] Or

[0813] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0814] Or

[0815] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0816] Or

[0817] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0818] Or

[0819] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M 1 M 1 -M 0-M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0820] Or

[0821] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0822] Or

[0823] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0824] Or

[0825] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0826] Or

[0827] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0828] Or

[0829] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0830] Or

[0831] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0832] Or

[0833] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0834] Or

[0835] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0836] Or

[0837] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0838] Or

[0839] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0840] Or

[0841] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0842] Or

[0843] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0844] Or

[0845] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0846] Or

[0847] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0848] Or

[0849] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0850] Or

[0851] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0852] Or

[0853] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0854] Or

[0855] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0856] Or

[0857] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0858] Or

[0859] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0860] Or

[0861] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0862] Or

[0863] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0864] Or

[0865] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0866] Or

[0867] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0868] Or

[0869] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0870] Or

[0871] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0872] Or

[0873] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 M -1 M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0874] Or

[0875] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0876] Or

[0877] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0878] Or

[0879] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0880] Or

[0881] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0882] Or

[0883] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0884] Or

[0885] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0886] Or

[0887] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0888] Or

[0889] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0890] Or

[0891] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0892] Or

[0893] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0894] Or

[0895] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0896] Or

[0897] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M 1 M 1 -M 0-M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0898] Or

[0899] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0900] Or

[0901] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0902] Or

[0903] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0904] Or

[0905] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0906] Or

[0907] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0908] Or

[0909] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0910] Or

[0911] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0912] Or

[0913] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1-M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0914] Or

[0915] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1-M 0 M -1 -M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0916] Or

[0917] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1-M 0 M -1 -M 1 -M 1- M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0918] Or

[0919] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1-M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0920] Or

[0921] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1-M 0 M -1 -M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0922] Or

[0923] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0924] Or

[0925] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0926] Or

[0927] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0928] Or

[0929] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M -1 -M -1 M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0930] or

[0931] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 M -1 M 1 M 1 -M 0-M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0932] or

[0933] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 M -1 M 1 M 1 -M 0 -M 1 M -1 M -1 M}*(1+j) / sqrt(2)

[0934] or

[0935] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 M -1 M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[0936] Of all the sequences mentioned above, the following coefficients are replaced with 0.

[0937] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032=EHTS 2040 =0

[0938] MaxPAPR is 9.0115.

[0939] 2.3.7. 160MHz 2x HE STF sequence repetition and additional phase rotation in 40MHz units on the secondary channel (or the relatively high frequency 160MHz channel).

[0940] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0941] or

[0942] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0943] Of all the sequences mentioned above, the following coefficients are replaced with 0.

[0944] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0945] MaxPAPR is 9.0115.

[0946] 2.3.8. 160MHz 2x HE STF sequence repetition and additional phase rotation in 80MHz units on the secondary channel (or the relatively high frequency 160MHz channel).

[0947] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0948] Of the sequences mentioned above, the following coefficients are replaced with 0.

[0949] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0950] Max PAPR is 9.1649.

[0951] 2.3.9. 160MHz 2x HE STF sequence repetition and additional phase rotation in 160MHz units in the secondary channel (or the relatively high frequency 160MHz channel)

[0952] EHTS -2040:8:2040={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0953] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0954] Max PAPR is 9.7066.

[0955] From a PAPR perspective, proposal 2.3.2 is appropriate. From an implementation perspective, method 2.3.4, which involves repeatedly performing an 11ax 80MHz phase rotation and multiplying the high frequency 160MHz or secondary 160MHz portion by -1, is advantageous. Alternatively, method 2.3.8, which involves repeatedly performing an 11ax 160MHz phase rotation and multiplying the high frequency 80MHz portion of the high frequency 160MHz or secondary 160MHz portion by -1, is advantageous.

[0956] In the above section, a 2x EHT STF sequence for a contiguous 320MHz situation is proposed. This sequence can also be applied to a non-contiguous 160+160MHz situation. That is, the sequence corresponding to low 160MHz in the 2x EHT STF sequence for a contiguous 320MHz situation is applied to either low 160MHz or primary 160MHz in a non-contiguous 160+160MHz situation, and the sequence corresponding to high 160MHz in the 2x EHT STF sequence for a contiguous 320MHz situation is applied to either high 160MHz or secondary 160MHz in a non-contiguous 160+160MHz situation. For example, considering the sequence proposed in 2.3.4, the sequence for a non-contiguous 160+160MHz situation can be expressed as follows.

[0957] Contiguous 320MHz

[0958] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0959] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0960] Non-contiguous 160+160MHz

[0961] Low 160MHz or primary 160MHz

[0962] EHTS -1016:8:1016 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0963] EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =0

[0964] High 160MHz or secondary 160MHz

[0965] EHTS -1016:8:1016 ={-M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0966] EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =0

[0967] As another example, considering the sequence proposed in 4.1.8, the sequence at non-contiguous 160+160MHz can be expressed as follows:

[0968] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0969] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0970] Non-contiguous 160+160MHz

[0971] Low 160MHzまたはprimary 160MHz

[0972] EHTS -1016:8:1016 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[0973] EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =0

[0974] High 160MHzまたはsecondary 160MHz

[0975] EHTS -1016:8:1016 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0976] EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =0

[0977] 2.4.240MHz 2x EHT STF sequence

[0978] Of the 2x EHT STF proposed at 320MHz mentioned above, the punctured 80MHz 2x EHT STF portion can be removed and proposed for 240 / 160+80 / 80+160MHz.

[0979] 2.4.1.320MHz 2x EHT STF puncturing

[0980] For example, let's assume the following 320MHz 2x EHT STF sequence is used.

[0981] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0982] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0983] In this case, if the first 80MHz signal is punctured, the following 240MHz 2x EHT STF sequence can be used.

[0984] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0985] EHTS-1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[0986] If the second 80MHz is punctured, the following 240MHz 2x EHT STF sequence can be used.

[0987] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0988] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[0989] If the third 80MHz is punctured, the following 240MHz 2x EHT STF sequence can be used.

[0990] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0991] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[0992] If the fourth 80MHz is punctured, the following 240MHz 2x EHT STF sequence can be used.

[0993] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0994] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[0995] As another example, let's assume the following 320MHz 2x EHT STF sequence is used.

[0996] EHTS -2040:8:2040 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[0997] EHTS -2040 =EHTS -1032 =EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =EHTS 1032 =EHTS 2040 =0

[0998] In this case, if the first 80MHz signal is punctured, the following 240MHz 2x EHT STF sequence can be used.

[0999] EHTS -1528:8:1528 ={-M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[1000] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[1001] If the second 80MHz is punctured, the following 240MHz 2x EHT STF sequence can be used.

[1002] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[1003] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[1004] If the third 80MHz is punctured, the following 240MHz 2x EHT STF sequence can be used.

[1005] EHTS-1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[1006] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[1007] If the fourth 80MHz is punctured, the following 240MHz 2x EHT STF sequence can be used.

[1008] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[1009] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[1010] Furthermore, we propose a method of simply repeating the existing 80MHz 2x HE STF sequence, and a sequence that repeats this and applies additional phase rotation in units of 20 / 40 / 80MHz to the other channels, excluding the primary channel (or the 80MHz channel with a relatively low frequency), to lower the PAPR.

[1011] 2.4.2.80MHz 2x HE STF sequence repeat

[1012] An existing 80MHz 2x HE STF sequence can be repeated three times to construct a 2x EHT STF sequence, as follows:

[1013] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M

[1014] 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[1015] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[1016] Max PAPR is 9.6339.

[1017] 2.4.3.80MHz 2x HE STF sequence repetition and additional phase rotation in 20MHz units in the secondary channel (or channels excluding the lowest frequency 80MHz channel).

[1018] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[1019] or

[1020] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 M -1 -M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M 1 -M 1 -M}*(1+j) / sqrt(2)

[1021] Of all the sequences mentioned above, the following coefficients are replaced with 0.

[1022] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[1023] Max PAPR is 8.0381.

[1024] 2.4.4.80MHz 2x HE STF sequence repetition and additional phase rotation in 40MHz units in the secondary channel (or channel excluding the lowest frequency 80MHz channel).

[1025] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[1026] or

[1027] EHTS -1528:8:1528={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[1028] Of all the sequences mentioned above, the following coefficients are replaced with 0.

[1029] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[1030] The maximum PAPR is 8.9149.

[1031] 2.4.5.80MHz 2x HE STF sequence repetition and additional phase rotation in 80MHz units in the secondary channel (or channel excluding the lowest frequency 80MHz channel).

[1032] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[1033] or

[1034] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[1035] Of all the sequences mentioned above, the following coefficients are replaced with 0.

[1036] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[1037] The maximum PAPR is 8.9149.

[1038] When constructing a 240MHz 2x EHT STF sequence by puncturing a 320MHz signal, the method in 2.4.1 is preferred, as this provides the implemented gain as a 2x EHT STF sequence coupled with 320MHz. While the method in 2.4.3 may also be preferred when considering PAPR and various RF capability situations, it may increase implementation overhead. The more advantageous method in implementation is the one in 2.4.5 (by excluding primary 80MHz, or by multiplying all parts excluding the lowest frequency 80MHz by a negative value).

[1039] In the above, a 2x EHT STF sequence for a contiguous 240MHz situation is proposed. This sequence can also be applied to a non-contiguous 160+80MHz situation. That is, the sequence corresponding to low 80 / 160MHz in the 2x EHT STF sequence for a contiguous 240MHz situation is applied to either low 80 / 160MHz or primary 80 / 160MHz in a non-contiguous 160+80MHz situation, and the sequence corresponding to high 160 / 80MHz in the 1x EHT STF sequence for a contiguous 240MHz situation is applied to either high 160 / 80MHz or the other 160 / 80MHz in a non-contiguous 160+80MHz situation. For example, considering the sequence proposed in 2.4.5, the sequence for a non-contiguous 160+80MHz situation can be expressed as follows.

[1040] Contiguous 240MHz

[1041] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[1042] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[1043] Non-contiguous 160+80MHz (when 160MHz is at low frequency and 80MHz is at high frequency, or when primary 160MHz is continuous)

[1044] Low 160MHz or primary 160MHz

[1045] EHTS -1016:8:1016 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[1046] EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =0

[1047] High 80MHz or the other 80MHz

[1048] EHTS -504:5:504 ={-M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[1049] EHTS -504 =EHTS 504 =0

[1050] Non-contiguous 160+80MHz (when 80MHz is at low frequency and 160MHz is at high frequency, or when only primary 80MHz is continuous)

[1051] Low 80MHz or primary 80MHz

[1052] EHTS -504:5:504 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[1053] EHTS -504 =EHTS 504 =0

[1054] High 160MHz or the other 160MHz

[1055] EHTS -1016:8:1016 ={-M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[1056] EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =0

[1057] As another example, let's assume the following 240MHz 2x EHT STF sequence is used.

[1058] Contiguous 240MHz

[1059] EHTS -1528:8:1528 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[1060] EHTS -1528 =EHTS -520 =EHTS -504 =EHTS 504 =EHTS 520 =EHTS 1528 =0

[1061] Non-contiguous 160+80MHz (when 160MHz is at low frequency and 80MHz is at high frequency, or when primary 160MHz is continuous)

[1062] Low 160MHz or primary 160MHz

[1063] EHTS -1016:8:1016 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[1064] EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =0

[1065] High 80MHz or the other 80MHz

[1066] EHTS -504:5:504 ={-M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[1067] EHTS -504 =EHTS 504 =0

[1068] Non-contiguous 160+80MHz (when 80MHz is at low frequency and 160MHz is at high frequency, or when only primary 80MHz is continuous)

[1069] Low 80MHz or primary 80MHz

[1070] EHTS -504:5:504 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[1071] EHTS -504 =EHTS 504 =0

[1072] High 160MHz or the other 160MHz

[1073] EHTS -1016:8:1016 ={M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[1074] EHTS -1016 =EHTS -8 =EHTS8=EHTS 1016 =0

[1075] Figure 22 is a procedure flowchart showing the operation of the transmitting device according to this embodiment.

[1076] The STF sequence described above (i.e., the EHT-STF / EHTS sequence) is transmitted according to the example shown in Figure 22.

[1077] The example shown in Figure 22 is performed in the transmitting device (AP and / or non-APSTA).

[1078] Some of the steps (or detailed sub-steps described later) in the example shown in Figure 22 are omitted.

[1079] In step S2210, the transmitter can obtain control information for the STF sequence. For example, the transmitter can obtain information regarding the Bandwidth (e.g., 80 / 160 / 240 / 320 MHz) to be applied to the STF sequence. Additionally or alternatively, the transmitter can obtain information regarding the characteristics to be applied to the STF sequence (e.g., information instructing the generation of 1x, 2x, and 4x sequences).

[1080] In step S2220, the transmitting device can configure or generate a control signal / field (e.g., EHT STF signal / field) based on the acquired control information (e.g., information regarding bandwidth).

[1081] Step S2220 may include more specific sub-steps.

[1082] For example, step S2220 may further include the step of selecting one STF sequence from among a number of STF sequences based on control information obtained via S2210.

[1083] Additionally or alternatively, step S2220 may further include a step that performs power boosting.

[1084] The S2220 step can also be called the step that generates a Sequence.

[1085] In step S2230, the transmitting device can transmit the signal / field / sequence configured via step S2220 to the receiving device based on step S2230.

[1086] Step S2220 may include more specific sub-steps.

[1087] For example, the transmitter can perform a Phase rotation step. Specifically, the transmitter can also perform a Phase rotation step in units of 20 MHz * N (N = integer) on the sequence generated via the S2220 step.

[1088] Additionally or alternatively, the transmitter performs at least one of the following operations: CSD, Spatial Mapping, IDFT / IFFT operation, or GI insertion (insert).

[1089] The signals / fields / sequences configured herein are transmitted in the form shown in Figure 22.

[1090] Figure 22 shows an example related to an example of a transmitting device (AP and / or non-APSTA).

[1091] As shown in Figure 1, the transmitting device may include a memory 112, a processor 111, and a transceiver 113.

[1092] The memory 112 can store information for a number of STF sequences described herein. It can also store control information for STF sequence / PPDU generation.

[1093] The processor 111 can generate various sequences (e.g., STF sequences) based on the information stored in the memory 112 and configure a PPDU. An example of a PPDU generated by the processor 111 is shown in Figure 18.

[1094] The processor 111 can perform some of the operations shown in Figure 22. For example, it can acquire control information for STF sequence generation and construct an STF sequence.

[1095] For example, the processor 111 may include additional detail units. The detail units included in the processor 111 are configured as shown in Figure 19. That is, as shown, the processor 111 can perform operations such as CSD, Spatial Mapping, IDFT / IFFT operation, and GI insertion (insert).

[1096] The transceiver 113 shown includes an antenna and is capable of performing analog signal processing. Specifically, the processor 111 can control the transceiver 113 to transmit the PPDU generated by the processor 111.

[1097] Figure 23 is a procedure flowchart illustrating the operation of the receiving device according to this embodiment.

[1098] The STF sequence described above (i.e., the EHT-STF / EHTS sequence) is transmitted according to the example shown in Figure 23.

[1099] The example shown in Figure 23 is performed in the receiving device (AP and / or non-APSTA).

[1100] Some of the steps (or detailed sub-steps described later) in the example shown in Figure 23 are omitted.

[1101] In step S2310, the receiving device can receive a signal / field containing an STF sequence (i.e., an EHT-STF / EHTS sequence) via the S2310 step. The received signal is in the form shown in Figure 18.

[1102] The sub-step of step S2310 is determined based on step S2230. That is, step S2310 can perform operations to restore the results of the Phase rotation CSD, Spatial Mapping, IDFT / IFFT operations, and GI insertion (insert) operations applied in step S2230.

[1103] In the S2310 step, the STF sequence can perform various functions, such as finding the time / frequency synchronization of the signal or estimating the AGC gain.

[1104] In step S2320, the receiving device can perform decoding on the received signal based on the STF sequence.

[1105] For example, step S2320 may include a step of decoding the data field of the PPDU, which contains an STF sequence. That is, the receiving device can decode the signal contained within the data field of the PPDU that was successfully received based on the STF sequence.

[1106] In step S2330, the receiving device can process the data decoded via step S2320.

[1107] For example, the receiving device can perform a processing operation to transmit the decoded data to a higher layer (e.g., the MAC layer) via the S2320 step. Furthermore, if the higher layer instructs the PHY layer to generate a signal in response to the data transmitted to the higher layer, it can perform subsequent operations.

[1108] Figure 23 shows an example related to an example of a transmitting device (AP and / or non-APSTA).

[1109] As shown in Figure 1, the transmitting device may include a memory 112, a processor 111, and a transceiver 113.

[1110] The memory 112 can store information for a number of STF sequences described herein. It can also store control information for STF sequence / PPDU generation.

[1111] The processor 111 can generate various sequences (e.g., STF sequences) based on the information stored in the memory 112 and configure a PPDU. An example of a PPDU generated by the processor 111 is shown in Figure 18.

[1112] The processor 111 can perform some of the operations shown in Figure 22. For example, it can acquire control information for STF sequence generation and construct an STF sequence.

[1113] For example, the processor 111 may include additional detail units. The detail units included in the processor 111 are configured as shown in Figure 19. That is, as shown, the processor 111 can perform operations such as CSD, Spatial Mapping, IDFT / IFFT operation, and GI insertion (insert).

[1114] The transceiver 113 shown includes an antenna and is capable of performing analog signal processing. Specifically, the processor 111 can control the transceiver 113 to transmit the PPDU generated by the processor 111.

[1115] Some of the technical features shown in Figure 23 are implemented by the transceiver 113. Specifically, the Analog RF processing shown is included in the transceiver 113.

[1116] The embodiments described above will be explained below with reference to Figures 1 to 23.

[1117] Figure 24 is a flowchart illustrating the procedure for transmitting a PPDU according to this embodiment.

[1118] An example shown in Figure 24 is executed in a network environment that supports a next-generation wireless LAN system (IEEE 802.11be or EHT wireless LAN system). This next-generation wireless LAN system is an improved version of the 802.11ax system and can satisfy backward compatibility with the 802.11ax system.

[1119] An example shown in Figure 24 is performed in a transmitting STA, which can correspond to an AP (access point). The receiving STA in Figure 24 can correspond to an STA that supports an EHT (Extremely High Throughput) wireless LAN system.

[1120] This embodiment proposes a method for configuring 2x STF sequences that are mapped to RU or MRU (Multi-RU) when transmitting TB PPDU over a wideband (240 MHz or 320 MHz).

[1121] In step S2410, the transmitting STA (station) generates a PPDU (Physical Protocol Data Unit).

[1122] In step S2420, the transmitting STA transmits the PPDU to the receiving STA via broadband.

[1123] The aforementioned PPDU includes the STF (Short Training Field) signal.

[1124] The STF signal is generated based on the first STF sequence for the broadband.

[1125] When the broadband is a 320 MHz band, the first STF sequence is defined as a sequence including an M sequence as follows.

[1126] {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[1127] In this case, sqrt() represents the square root.

[1128] The aforementioned M sequence is defined as follows. The aforementioned M sequence is the same as the M sequence defined in an 802.11ax wireless LAN system.

[1129] M={-1,-1,-1,1,1,1,-1,1,1,1,-1,1,1,-1,1}

[1130] The first STF sequence is arranged at 8-tone intervals, from the lowest tone with a tone index of -2040 to the highest tone with a tone index of +2040. In this case, elements of the first STF sequence with tone indices of -8, +8, -1016, +1016, -1032, +1032, -2040, and +2040 are set to 0.

[1131] The first STF sequence is a sequence in which the second STF sequence is repeated and then phase rotation is applied. The second STF sequence is an STF sequence for the 80 MHz band as defined in an 802.11ax wireless LAN system. The second STF sequence is defined as follows.

[1132] {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[1133] In other words, the first STF sequence is obtained using a 2x HE-STF sequence for an 80 MHz bandwidth as defined in the existing 802.11ax standard.

[1134] The broadband can include first to fourth 80MHz bands. The first to fourth 80MHz bands are arranged in order from lowest frequency to highest frequency. The phase rotation is applied to the second, third, or fourth 80MHz band in the broadband. That is, the phase rotation is applied to the remaining 80MHz bands, excluding the first 80MHz band which has the lowest frequency.

[1135] As an example, the first STF sequence is obtained by applying a phase rotation (multiplying by -1) to the 80MHz channel with the highest frequency (the fourth 80MHz band) and the 80MHz channel with the second highest frequency (the third 80MHz band) in a sequence obtained by repeating the second STF sequence four times.

[1136] The aforementioned PPDU is a trigger-based (TB) PPDU. That is, the aforementioned PPDU is a PPDU that is triggered by a trigger frame.

[1137] The PPDU is received via a Resource Unit (RU) or Multi-RU (MRU). The RU or MRU may include combinations of 26-tone RUs, 52-tone RUs, 106-tone RUs, 242-tone RUs, 484-tone RUs, 996-tone RUs, 26+52-tone RUs, 242+484-tone RUs, 2x996-tone RUs, 484+996-tone RUs, 3x996-tone RUs, or 4x996-tone RUs. If the broadband is 320MHz, there are 148 26-tone RUs, 64 52-tone RUs, 32 106-tone RUs, 16 242-tone RUs, 8 484-tone RUs, 4 996-tone RUs, 16 26+52-tone RUs, 16 242+484-tone RUs, 2 x 996-tone RUs, 8 484+996-tone RUs, 4 x 996-tone RUs, and 1 x 4 x 996-tone RU. Among the numerous RU combinations, the largest PAPR value is considered the Max PAPR value of the first STF sequence.

[1138] In this case, the 26+52 tone RU is an aggregated MRU of 26 tone RU and 52 tone RU, the 242+484 tone RU is an aggregated MRU of 242 tone RU and 484 tone RU, the 484+996 tone RU is an aggregated MRU of 484 tone RU and 996 tone RU, the 2x996 tone RU is an aggregated MRU of two 996 tone RUs, the 3x996 tone RU is an aggregated MRU of three 996 tone RUs, and the 4x996 tone RU is an aggregated MRU of four 996 tone RUs.

[1139] Furthermore, the first STF sequence is mapped to frequency tones as follows: The first STF sequence is arranged at 8-tone intervals from the lowest tone with a tone index of -2040 to the highest tone with a tone index of +2040. That is, each element of the first STF sequence is mapped to a frequency tone with the aforementioned tone index.

[1140] However, the first STF sequence is mapped to a tone included in the RU or MRU. That is, the first STF sequence is mapped only to tones included in the RU or MRU that are assigned by the trigger frame based on the tone index of the first STF sequence. For example, if three 996 tone RUs are assigned by the trigger frame, the first STF sequence is not mapped to the remaining 996 tone RU.

[1141] The aforementioned STF signal is used for AGC (Automatic Gain Control) estimation in MIMO (Multiple Input Multiple Output) transmission.

[1142] The PPDU may include a legacy preamble, a control field, and a data field. In this case, the STF signal is included in the control field. The control field and the data field can support an 802.11be wireless LAN system.

[1143] Specifically, the legacy field may include L-STF (Legacy-Short Training Field), L-LTF (Legacy-Long Training Field), L-SIG (Legacy-Signal), and RL-SIG (Repeated L-SIG). The control field may include U-SIG (Universal-Signal), EHT-STF, and EHT-LTF. The STF signal is included in the EHT-STF. Since the PPDU is a TB PPDU, the control field may not include EHT-SIG (Extremely High Throughput-Signal).

[1144] Furthermore, the STF sequence for the 240MHz / 160+80MHz / 80+160MHz band is determined by performing puncturing (80MHz-based preamble puncturing) on ​​80MHz in the aforementioned STF sequence for the 320MHz / 160+160MHz band (first STF sequence). In other words, the STF sequence for the 240MHz / 160+80MHz / 80+160MHz band can be obtained using the STF sequence for the 320MHz / 160+160MHz band without separately defining the STF sequence for the 240MHz / 160+80MHz / 80+160MHz band (unified technology).

[1145] For example, the STF sequence (first STF sequence) for the 320MHz / 160+160MHz band is defined as {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2), so the STF sequence for the 240MHz / 160+80MHz / 80+160MHz band is determined by the 80MHz band being punctured.

[1146] If the first 80MHz of the 320MHz / 160+160MHz band is punctured, the STF sequence for the 240MHz / 160+80MHz / 80+160MHz band is {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2).

[1147] If the second 80MHz of the 320MHz / 160+160MHz band is punctured, the STF sequence for the 240MHz / 160+80MHz / 80+160MHz band is {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2).

[1148] If the third 80MHz of the 320MHz / 160+160MHz band is punctured, the STF sequence for the 240MHz / 160+80MHz / 80+160MHz band is {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2).

[1149] If the fourth 80MHz of the 320MHz / 160+160MHz band is punctured, the STF sequence for the 240MHz / 160+80MHz / 80+160MHz band is {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2).

[1150] Figure 25 is a flowchart illustrating the procedure for receiving a PPDU in this embodiment.

[1151] An example shown in Figure 25 is implemented in a network environment that supports a next-generation wireless LAN system (IEEE 802.11be or EHT wireless LAN system). This next-generation wireless LAN system is an improved version of the 802.11ax system and can satisfy backward compatibility with the 802.11ax system.

[1152] An example shown in Figure 25 is implemented in a receiving STA and can be used with STAs that support EHT (Extremely High Throughput) wireless LAN systems. The transmitting STA in Figure 25 can be used with APs (access points).

[1153] This embodiment proposes a method for configuring 2x STF sequences that are mapped to RU or MRU (Multi-RU) when transmitting TB PPDU over a wideband (240 MHz or 320 MHz).

[1154] In step S2510, the receiving STA (station) receives a PPDU (Physical Protocol Data Unit) from the transmitting STA via broadband.

[1155] In step S2520, the receiving STA decodes the PPDU.

[1156] The aforementioned PPDU includes the STF (Short Training Field) signal.

[1157] The STF signal is generated based on the first STF sequence for the broadband.

[1158] When the broadband is a 320 MHz band, the first STF sequence is defined as a sequence including an M sequence as follows.

[1159] {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2)

[1160] In this case, sqrt() represents the square root.

[1161] The aforementioned M sequence is defined as follows. The aforementioned M sequence is the same as the M sequence defined in an 802.11ax wireless LAN system.

[1162] M={-1,-1,-1,1,1,1,-1,1,1,1,-1,1,1,-1,1}

[1163] The first STF sequence is arranged at 8-tone intervals, from the lowest tone with a tone index of -2040 to the highest tone with a tone index of +2040. In this case, elements of the first STF sequence with tone indices of -8, +8, -1016, +1016, -1032, +1032, -2040, and +2040 are set to 0.

[1164] The first STF sequence is a sequence in which the second STF sequence is repeated and then phase rotation is applied. The second STF sequence is an STF sequence for the 80 MHz band as defined in an 802.11ax wireless LAN system. The second STF sequence is defined as follows.

[1165] {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M}*(1+j) / sqrt(2)

[1166] In other words, the first STF sequence is obtained using a 2x HE-STF sequence for an 80 MHz bandwidth as defined in the existing 802.11ax standard.

[1167] The broadband can include first to fourth 80MHz bands. The first to fourth 80MHz bands are arranged in order from lowest frequency to highest frequency. The phase rotation is applied to the second, third, or fourth 80MHz band in the broadband. That is, the phase rotation is applied to the remaining 80MHz bands, excluding the first 80MHz band which has the lowest frequency.

[1168] As an example, the first STF sequence is obtained by applying a phase rotation (multiplying by -1) to the 80MHz channel with the highest frequency (the fourth 80MHz band) and the 80MHz channel with the second highest frequency (the third 80MHz band) in a sequence obtained by repeating the second STF sequence four times.

[1169] The aforementioned PPDU is a trigger-based (TB) PPDU. That is, the aforementioned PPDU is a PPDU that is triggered by a trigger frame.

[1170] The PPDU is received via a Resource Unit (RU) or Multi-RU (MRU). The RU or MRU may include combinations of 26-tone RUs, 52-tone RUs, 106-tone RUs, 242-tone RUs, 484-tone RUs, 996-tone RUs, 26+52-tone RUs, 242+484-tone RUs, 2x996-tone RUs, 484+996-tone RUs, 3x996-tone RUs, or 4x996-tone RUs. If the broadband is 320MHz, there are 148 26-tone RUs, 64 52-tone RUs, 32 106-tone RUs, 16 242-tone RUs, 8 484-tone RUs, 4 996-tone RUs, 16 26+52-tone RUs, 16 242+484-tone RUs, 2 x 996-tone RUs, 8 484+996-tone RUs, 4 x 996-tone RUs, and 1 x 4 x 996-tone RU. Among the numerous RU combinations, the largest PAPR value is considered the Max PAPR value of the first STF sequence.

[1171] In this case, the 26+52 tone RU is an aggregated MRU of 26 tone RU and 52 tone RU, the 242+484 tone RU is an aggregated MRU of 242 tone RU and 484 tone RU, the 484+996 tone RU is an aggregated MRU of 484 tone RU and 996 tone RU, the 2x996 tone RU is an aggregated MRU of two 996 tone RUs, the 3x996 tone RU is an aggregated MRU of three 996 tone RUs, and the 4x996 tone RU is an aggregated MRU of four 996 tone RUs.

[1172] Furthermore, the first STF sequence is mapped to frequency tones as follows: The first STF sequence is arranged at 8-tone intervals from the lowest tone with a tone index of -2040 to the highest tone with a tone index of +2040. That is, each element of the first STF sequence is mapped to a frequency tone with the aforementioned tone index.

[1173] However, the first STF sequence is mapped to a tone included in the RU or MRU. That is, the first STF sequence is mapped only to tones included in the RU or MRU that are assigned by the trigger frame based on the tone index of the first STF sequence. For example, if three 996 tone RUs are assigned by the trigger frame, the first STF sequence is not mapped to the remaining 996 tone RU.

[1174] The aforementioned STF signal is used for AGC (Automatic Gain Control) estimation in MIMO (Multiple Input Multiple Output) transmission.

[1175] The PPDU may include a legacy preamble, a control field, and a data field. In this case, the STF signal is included in the control field. The control field and the data field can support an 802.11be wireless LAN system.

[1176] Specifically, the legacy field may include L-STF (Legacy-Short Training Field), L-LTF (Legacy-Long Training Field), L-SIG (Legacy-Signal), and RL-SIG (Repeated L-SIG). The control field may include U-SIG (Universal-Signal), EHT-STF, and EHT-LTF. The STF signal is included in the EHT-STF. Since the PPDU is a TB PPDU, the control field may not include EHT-SIG (Extremely High Throughput-Signal).

[1177] Furthermore, the STF sequence for the 240MHz / 160+80MHz / 80+160MHz band is determined by performing puncturing (80MHz base preamble puncturing) at 80MHz in the aforementioned STF sequence for the 320MHz / 160+160MHz band (first STF sequence). In other words, the STF sequence for the 240MHz / 160+80MHz / 80+160MHz band can be obtained using the STF sequence for the 320MHz / 160+160MHz band without separately defining the STF sequence for the 240MHz / 160+80MHz / 80+160MHz band (unified technology).

[1178] For example, the STF sequence (first STF sequence) for the 320MHz / 160+160MHz band is defined as {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2), so the STF sequence for the 240MHz / 160+80MHz / 80+160MHz band is determined by the 80MHz band being punctured.

[1179] If the first 80MHz of the 320MHz / 160+160MHz band is punctured, the STF sequence for the 240MHz / 160+80MHz / 80+160MHz band is {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2).

[1180] If the second 80MHz of the 320MHz / 160+160MHz band is punctured, the STF sequence for the 240MHz / 160+80MHz / 80+160MHz band is {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2).

[1181] If the third 80MHz of the 320MHz / 160+160MHz band is punctured, the STF sequence for the 240MHz / 160+80MHz / 80+160MHz band is {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2).

[1182] If the fourth 80MHz of the 320MHz / 160+160MHz band is punctured, the STF sequence for the 240MHz / 160+80MHz / 80+160MHz band is {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2).

[1183] 3.Device configuration

[1184] The technical features of this specification described above are applicable to various devices and methods. For example, the technical features of this specification described above are implemented / supported through the device in Figure 1 and / or Figure 19. For example, the technical features of this specification described above are applicable to only a portion of Figure 1 and / or Figure 19. For example, the technical features of this specification described above are implemented based on the processing chips 114, 124 in Figure 1, or based on the processors 111, 121 and memories 112, 122 in Figure 1, or based on the processor 610 and memory 620 in Figure 19. For example, the device of this specification receives a PPDU (Physical Protocol Data Unit) from a transmitting STA via broadband and decodes the PPDU.

[1185] The technical features of this specification are implemented based on a CRM (computer-readable medium). For example, the CRM proposed herein is at least one computer-readable medium containing instructions that are executed by at least one processor.

[1186] The CRM can store instructions for performing operations that include receiving a Physical Protocol Data Unit (PPDU) from a transmitting STA over broadband, and decoding the PPDU. Instructions stored in the CRM according to this specification are executed by at least one processor. The at least one processor associated with the CRM according to this specification is the processor (111, 121) or processing chip (114, 124) in Figure 1, or the processor 610 in Figure 19. On the other hand, the CRM according to this specification is the memory (112, 122) in Figure 1, the memory 620 in Figure 19, or a separate external memory / storage medium / disk, etc.

[1187] The technical features described herein are applicable to a variety of applications and business models. For example, these technical features are applicable to wireless communication in devices that support artificial intelligence (AI).

[1188] Artificial intelligence refers to the field of studying artificial intelligence or methodologies for creating it, while machine learning refers to the field of defining various problems dealt with in the field of artificial intelligence and studying methodologies for solving them. Machine learning can also be defined as an algorithm that improves its performance for a particular task through continuous experience.

[1189] An artificial neural network (ANN) is a model used in machine learning that consists of artificial neurons (nodes) that form a network of synaptic connections, and is generally considered to have problem-solving capabilities. An artificial neural network is defined by the connection patterns between neurons in other layers, the learning process that updates the model parameters, and the activation function that generates the output values.

[1190] An artificial neural network can include an input layer, an output layer, and optionally one or more hidden layers. Each layer contains one or more neurons, and the artificial neural network can include synapses connecting neurons. In an artificial neural network, each neuron can output an input signal, a weighted value, and a function value of the activation function for the bias received via the synapse.

[1191] Model parameters refer to parameters determined through learning, including synaptic connection weights and neuron bias. Hyperparameters, on the other hand, refer to parameters that need to be set before learning in a machine learning algorithm, including the learning rate, iteration count, mini-batch size, and initialization function.

[1192] The goal of training an artificial neural network is to determine the model parameters that minimize the loss function. The loss function is used as an indicator to determine the optimal model parameters during the training process of the artificial neural network.

[1193] Machine learning can be classified into supervised learning, unsupervised learning, and reinforcement learning based on the learning method.

[1194] Supervised learning refers to a method of training an artificial neural network when labels are provided for the training data. When labels are input to the artificial neural network, they represent the correct answer (or result value) that the artificial neural network needs to infer. Unsupervised learning refers to a method of training an artificial neural network when labels are not provided for the training data. Reinforcement learning refers to a learning method in which a defined agent is trained to select the action or sequence of actions that maximizes the cumulative reward in each state within a given environment.

[1195] Machine learning implemented as a deep neural network (DNN), which includes multiple hidden layers, is also called deep learning, and deep learning is a part of machine learning. In the following, machine learning will be used to include deep learning.

[1196] Furthermore, the technical features described above can be applied to wireless communication for robots.

[1197] A robot is a machine that automatically processes or operates tasks assigned to it using its own capabilities. In particular, a robot that has the ability to perceive its environment, make decisions on its own, and perform actions is called an intelligent robot.

[1198] Robots can be classified into industrial, medical, household, and military categories depending on their intended use and field. Robots are equipped with drive units, including actuators or motors, and can perform various physical actions, such as moving robotic joints. Mobile robots also include drive units with wheels, brakes, propellers, etc., and can travel on the ground or fly through the air via these drive units.

[1199] Furthermore, the technical features described above apply to devices that support augmented reality.

[1200] Augmented reality is a general term encompassing virtual reality (VR), augmented reality (AR), and mixed reality (MR). VR technology provides real-world objects and backgrounds solely as computer graphics (CG) images, AR technology provides virtual CG images alongside images of real objects, and MR technology is a computer graphics technology that mixes and combines virtual objects with the real world.

[1201] Mixed Reality (MR) technology is similar to augmented reality (AR) technology in that it displays virtual objects together. However, while AR uses virtual objects to complement other virtual objects, MR uses virtual objects in a way that they are equivalent in nature.

[1202] XR technology is applied to HMDs (Head-Mount Displays), HUDs (Head-Up Displays), mobile phones, tablet PCs, laptops, desktops, TVs, digital signage, and other devices, and devices that utilize XR technology can be called XR devices.

[1203] The claims described herein can be combined in various ways. For example, the technical features of the method claims herein can be combined and implemented in an apparatus, and the technical features of the apparatus claims herein can be combined and implemented in a method. Furthermore, the technical features of the method claims herein and the technical features of the apparatus claims herein can be combined and implemented in an apparatus, and the technical features of the method claims herein and the technical features of the apparatus claims herein can be combined and implemented in a method.

Claims

1. In a method for a WLAN (Wireless Local Area Network) system, The receiving STA (station) receives a PPDU (Physical Protocol Data Unit) from the transmitting STA, The receiving STA includes the step of decoding the PPDU, The PPDU includes an STF (Short Training Field) signal and a data field. The STF signal is generated based on the first STF sequence, Based on the fact that the bandwidth of the PPDU is 320 MHz, the first STF sequence is defined as follows based on the M sequence: {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2), sqrt(2) represents the square root, The aforementioned M sequence is defined as follows: M=｛-1,-1,-1,1,1,1,-1,1,1,1,-1,1,1,-1,1｝、 The values ​​of the first STF sequence at indices -8, +8, -1016, +1016, -1032, +1032, -2040, and +2040 are 0. The first STF sequence is arranged at intervals of 8 tones, from the lowest tone with a tone index of -2040 to the highest tone with a tone index of +2040. The data field is received via 52 + 26 tone MRUs (multiple resource units) in each 80 MHz frequency subblock of the bandwidth of the PPDU, which is 320 MHz. The aforementioned 52+26 tone MRU is obtained by a combination of 52 tone RU and 26 tone RU. The aforementioned 52 tone RUs are indexed from 52 tone RU1 to 52 tone RU16 in order from low frequency to high frequency. The aforementioned 26 tone RUs are indexed from 26 tone RU1 to 52 tone RU37 in order from low frequency to high frequency. The aforementioned 52+26 tone MRU is The MRU is a combination of the aforementioned 52-tone RU3 and the aforementioned 26-tone RU8, The MRU is a combination of the aforementioned 52-tone RU6 and the aforementioned 26-tone RU11, The MRU is a combination of the aforementioned 52-tone RU11 and the aforementioned 26-tone RU27, A method comprising an MRU which is a combination of the 52-tone RU14 and the 26-tone RU30.

2. The method according to claim 1, wherein the PPDU is a TB (trigger based) PPDU.

3. The method according to claim 1, wherein the first STF sequence is mapped to the tones included in the 52+26 tone MRU.

4. The first STF sequence is a sequence in which the second STF sequence is repeated and then phase rotation is applied. The second STF sequence is an STF sequence for the 80 MHz band as defined in an 802.11ax wireless LAN system, The bandwidth of the PPDU includes first to fourth 80 MHz bands, The first to fourth 80 MHz bands are arranged in order from the lowest frequency to the highest frequency. The method according to claim 1, wherein the phase rotation is applied to the second, third, or fourth 80 MHz band in the bandwidth of the PPDU.

5. The second STF sequence is defined as follows: {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M} * (1+j) / sqrt(2), the method according to claim 4.

6. The method according to claim 1, wherein the STF signal is used for AGC (Automatic Gain Control) estimation in MIMO (Multiple Input Multiple Output) transmission.

7. The PPDU further includes legacy fields and control fields, The STF signal is included in the control field, The method according to claim 1, wherein the control field and the data field support an 802.11be wireless LAN system.

8. In a WLAN (Wireless Local Area Network) system, at the receiving STA (station), Memory and Transmitter and receiver, The system comprises a processor coupled to the memory and the transceiver, The processor is, Receive a PPDU (Physical Protocol Data Unit) from the transmitting STA. The PPDU is configured to decode, The PPDU includes an STF (Short Training Field) signal and a data field. The STF signal is generated based on the first STF sequence, Based on the fact that the bandwidth of the PPDU is 320 MHz, the first STF sequence is defined as follows based on the M sequence: {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2), sqrt(2) represents the square root, The aforementioned M sequence is defined as follows: M=｛-1,-1,-1,1,1,1,-1,1,1,1,-1,1,1,-1,1｝、 The values ​​of the first STF sequence at indices -8, +8, -1016, +1016, -1032, +1032, -2040, and +2040 are 0. The first STF sequence is arranged at intervals of 8 tones, from the lowest tone with a tone index of -2040 to the highest tone with a tone index of +2040. The data field is received via 52 + 26 tone MRUs (multiple resource units) in each 80 MHz frequency subblock of the bandwidth of the PPDU, which is 320 MHz. The aforementioned 52+26 tone MRU is obtained by a combination of 52 tone RU and 26 tone RU. The aforementioned 52 tone RUs are indexed from 52 tone RU1 to 52 tone RU16 in order from low frequency to high frequency. The aforementioned 26 tone RUs are indexed from 26 tone RU1 to 52 tone RU37 in order from low frequency to high frequency. The aforementioned 52+26 tone MRU is The MRU is a combination of the aforementioned 52-tone RU3 and the aforementioned 26-tone RU8, The MRU is a combination of the aforementioned 52-tone RU6 and the aforementioned 26-tone RU11, The MRU is a combination of the aforementioned 52-tone RU11 and the aforementioned 26-tone RU27, A receiving STA including an MRU which is a combination of the 52-tone RU14 and the 26-tone RU30.

9. In a method for a WLAN (Wireless Local Area Network) system, The transmitting STA (station) generates a PPDU (Physical Protocol Data Unit), The transmitting STA includes the step of transmitting the PPDU to the receiving STA, The PPDU includes an STF (Short Training Field) signal and a data field. The STF signal is generated based on the first STF sequence, Based on the fact that the bandwidth of the PPDU is 320 MHz, the first STF sequence is defined as follows based on the M sequence: {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M 0 -M 1 -M 1 M 1 -M 0 M -1 -M -1 M -1 M}*(1+j) / sqrt(2), sqrt(2) represents the square root, The aforementioned M sequence is defined as follows: M=｛-1,-1,-1,1,1,1,-1,1,1,1,-1,1,1,-1,1｝、 The values ​​of the first STF sequence at indices -8, +8, -1016, +1016, -1032, +1032, -2040, and +2040 are 0. The first STF sequence is arranged at intervals of 8 tones, from the lowest tone with a tone index of -2040 to the highest tone with a tone index of +2040. The data field is transmitted via 52 + 26 tone MRUs (multiple resource units) in each 80 MHz frequency subblock of the bandwidth of the PPDU, which is 320 MHz. The aforementioned 52+26 tone MRU is obtained by a combination of 52 tone RU and 26 tone RU. The aforementioned 52 tone RUs are indexed from 52 tone RU1 to 52 tone RU16 in order from low frequency to high frequency. The aforementioned 26 tone RUs are indexed from 26 tone RU1 to 52 tone RU37 in order from low frequency to high frequency. The aforementioned 52+26 tone MRU is The MRU is a combination of the aforementioned 52-tone RU3 and the aforementioned 26-tone RU8, The MRU is a combination of the aforementioned 52-tone RU6 and the aforementioned 26-tone RU11, The MRU is a combination of the aforementioned 52-tone RU11 and the aforementioned 26-tone RU27, A method comprising an MRU which is a combination of the 52-tone RU14 and the 26-tone RU30.

10. The method according to claim 9, wherein the PPDU is a TB (trigger based) PPDU.

11. The method according to claim 9, wherein the first STF sequence is mapped to the tones included in the 52+26 tone MRU.

12. The first STF sequence is a sequence in which the second STF sequence is repeated and then phase rotation is applied. The second STF sequence is an STF sequence for the 80 MHz band as defined in an 802.11ax wireless LAN system, The bandwidth of the PPDU includes first to fourth 80 MHz bands, The first to fourth 80 MHz bands are arranged in order from the lowest frequency to the highest frequency. The method according to claim 9, wherein the phase rotation is applied to the second, third, or fourth 80 MHz band in the bandwidth of the PPDU.

13. The second STF sequence is defined as follows: {M -1 M -1 -M -1 M 0 -M 1 M 1 -M 1 -M} * (1+j) / sqrt(2), the method according to claim 12.

14. The method according to claim 9, wherein the STF signal is used for AGC (Automatic gain control) estimation in MIMO (Multiple Input Multiple Output) transmission.

15. The PPDU further includes legacy fields and control fields, The STF signal is included in the control field, The method according to claim 9, wherein the control field and the data field support an 802.11be wireless LAN system.

Images