Chromanone Synthesis via Halobenzene Substitution

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Solution Overview

Problem

The high cost of substituted phenols used in synthesizing chromanone derivatives increases the expense of producing these compounds, necessitating a more cost-effective method for their preparation.

Innovation Solution

A method involving the reaction of substituted halobenzene with an alcohol in the presence of a base and a catalyst, followed by oxidation and cyclization, which uses cheaper halobenzene instead of phenol, thereby reducing production costs and improving yield.

Engineering Contradictions & Design Principles

VSEngineering Contradiction Analysis

1Ease of manufacture

If substituted phenols are used as raw materials for preparing substituted chromanone derivatives, then the synthesis can proceed through conventional methods, but the production cost increases due to the high expense of substituted phenols

Engineering Contradiction:
Improveconventional synthesis methodVSAvoidproduction cost
Core Design Contradiction:
Ease of manufactureVSQuantity of substance

Solution Approach 1:

The patent replaces expensive substituted phenols with cheaper substituted halobenzenes as raw materials. This substitution directly addresses the cost issue by using more economical starting materials while maintaining the ability to synthesize the desired chromanone derivatives through a modified reaction pathway involving nucleophilic aromatic substitution.

Inventive Principle:
Principle #27Cheap short-living objects (Disposable)

Solution Approach 2:

The patent changes the chemical parameters of the raw materials from phenolic compounds to halobenzene derivatives. This parameter change in the starting material structure enables cost reduction while achieving the same synthetic objective through different reaction mechanisms and conditions.

Inventive Principle:
Principle #35Parameter changes

2Ease of manufacture

If substituted phenols are used as raw materials, then the synthesis pathway is conventional, but the yield and efficiency of preparing substituted chromanone derivatives are reduced

Engineering Contradiction:
Improveconventional synthesis pathwayVSAvoidyield and efficiency
Core Design Contradiction:
Ease of manufactureVSProductivity

Solution Approach 1:

By using substituted halobenzenes instead of substituted phenols, the patent not only reduces cost but also improves reaction efficiency. The halobenzene-based pathway provides better yields and faster reaction rates, directly enhancing productivity while maintaining synthetic accessibility.

Inventive Principle:
Principle #27Cheap short-living objects (Disposable)

Applied Scientific Principles

This section explains which scientific principles are used to turn an abstract innovation direction into a practical engineering solution.

Function Achieved in This Case

This method effectively synthesizes chromanone derivatives with high yields while avoiding the use of expensive phenols, thus reducing production costs and enhancing efficiency.

Implementation Method 1

The compound of formula (II) may be prepared by reacting a compound of formula (III) with a compound of formula (IV) in the presence of a catalyst and a base. The catalyst may include a ligand and a copper compound.

Methodology Applied
Scientific EffectCatalysis: Catalysis

Implementation Method 2

3-(2-Fluoro-phenoxy)-propionic acid was dehydrated and cyclized in the presence of concentrated sulfuric acid to 8-Fluoro-4-chromanone

Methodology Applied
Scientific EffectDehydration:

Implementation Method 3

3-(2-Fluoro-phenoxy)-propionic acid was dehydrated and cyclized in the presence of concentrated sulfuric acid to 8-Fluoro-4-chromanone

Methodology Applied
Scientific EffectCyclization:

Data Source

PatentUS12139468B2Methods for preparing substituted chromanone derivatives
Publication Date: 2024.11.12 HANGZHOU DUYI TECHNOLOGY CO LTD
  • US12139468B2 patent drawing
  • US12139468B2 patent drawing
  • US12139468B2 patent drawing

AI summary

The present disclosure relates to a method for preparing a compound of formula (I).In the compound of formula (I), n may be 0 to 5 and each of R1, R2, R3, and R4 may be independently selected from the group consisting of H, —O-Alkyl, halo, alkyl, —CN, or —NO3.