Heavy-Duty Tire Tread Structure for Wear and Heat Resistance
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Solution Overview
Problem
Conventional heavy-duty tires face a trade-off between wear resistance and heat resistance, making it difficult to achieve both performance characteristics simultaneously.
Innovation Solution
The tire design incorporates a cap layer with a cap surface layer and a cap intermediate layer, where the cap surface layer has a higher tan δ in tensile tests than the cap intermediate layer, and the difference in tan δ between the two layers is 0.03 or more, enhancing wear resistance and heat resistance.
Engineering Contradictions & Design Principles
Engineering Contradiction Analysis
1Strength
If the tread rubber uses a cap layer and base layer configuration, then wear resistance is improved, but heat resistance deteriorates
Solution Approach 1:
The cap layer is segmented into two distinct layers: a cap surface layer (higher tan δ) and a cap intermediate layer (lower tan δ). This segmentation allows each sub-layer to perform its specialized function - the surface layer provides wear resistance while the intermediate layer provides heat resistance, resolving the contradiction between these two properties.
Solution Approach 2:
Different regions of the cap layer are assigned different material properties. The cap surface layer has higher tan δ values optimized for wear resistance, while the cap intermediate layer has lower tan δ values optimized for heat resistance. This local differentiation of material properties allows simultaneous achievement of both wear and heat resistance.
2Strength
If the cap surface layer has higher tan δ than the cap intermediate layer with difference of 0.03 or more, then wear resistance is enhanced, but the complexity of the tread rubber structure increases
Solution Approach 1:
The cap layer is divided into two functional segments with different tan δ characteristics. This segmentation enables the surface layer to have higher tan δ for wear resistance while the intermediate layer has lower tan δ for heat dissipation, achieving enhanced wear resistance through structured complexity rather than material complexity.
Solution Approach 2:
The invention changes the tan δ parameter distribution within the cap layer by creating a gradient where the surface layer has higher tan δ than the intermediate layer by 0.03 or more. This parameter differentiation optimizes wear resistance while maintaining manageable structural complexity through controlled material property variation.
Applied Scientific Principles
This section explains which scientific principles are used to turn an abstract innovation direction into a practical engineering solution.
Function Achieved in This Case
This configuration allows for a higher level of compatibility between wear resistance and heat resistance, ensuring durability and maintaining performance even as the tire wears.
Implementation Method 1
the cap surface layer has a larger tan δ in a tensile test under conditions of: room temperature of 24° C., amplitude of 2%, and 50 Hz, than the cap intermediate layer, and difference between tan δ of the cap surface layer in a tensile test under conditions of: room temperature of 24° C., amplitude of 2%, and 50 Hz, and tan δ of the cap intermediate layer in a tensile test under conditions of: room temperature of 24° C., amplitude of 2%, and 50 Hz, is 0.03 or more
Data Source
AI summary
The provided is a heavy-duty tire 1, wherein tread rubber 7 has: a cap layer 7c; and a base layer 7b disposed on an inner circumferential side of tire than the cap layer, the cap layer comprises: a cap surface layer 7c1; and a cap intermediate layer 7c2, the cap surface layer has a larger tan δ in a tensile test under conditions of: room temperature of 24° C., amplitude of 2%, and 50 Hz, than the cap intermediate layer, and difference between tan δ of the cap surface layer in a tensile test under conditions of: room temperature of 24° C., amplitude of 2%, and 50 Hz, and tan δ of the cap intermediate layer in a tensile test under conditions of: room temperature of 24° C., amplitude of 2%, and 50 Hz, is 0.03 or more.