A method for transmitting a probe frame and related apparatus

Abstract

The application provides a detection frame transmission method and related devices. The method is applied to a first device, and the method comprises: generating a detection frame, the detection frame comprising a first field, the first field comprising a predefined first sequence, wherein the first sequence comprises a sequence obtained by modulating a second sequence by at least one modulation mode, the modulation mode comprising: QPSK, 16-QAM, 64-QAM, 256-QAM, 1024-QAM, and 4096-QAM; and sending the detection frame, so that when a channel is measured by using the first sequence, the channel quality of a communication link in at least one of the modulation modes of QPSK, 16-QAM, 64-QAM, 256-QAM, 1024-QAM, and 4096-QAM can be accurately measured, and the application scenarios of the EHT-LTF sequence are enriched.

Description

Technical Field

[0001] This application relates to the field of communication technology, and in particular to a method and apparatus for transmitting detection frames. Background Technology

[0002] In a wireless local area network (WLAN), communication links can be established between access points (APs) and stations (STAs) to communicate with each other via a shared wireless communication medium. Generally, WLAN devices can adjust transmission parameters based on the channel quality of the communication link to optimize throughput or reliability. For example, in 802.11ax, the high efficient long training field (HE-LTF) sequence is used to measure the channel quality of the communication link; in 802.11be, the extremely high throughput long training field (EHT-LTF) sequence is used. However, currently, the subcarrier components in HE-LTF or EHT-LTF sequences are all +1, 0, or -1, meaning the current HE-LTF or EHT-LTF sequences are binary phase shift keying (BPSK) modulated HE-LTF or EHT-LTF sequences. Understandably, HE-LTF or EHT-LTF sequences under BPSK modulation have low distortion and a low peak-to-average power ratio (PAPR). Therefore, when using HE-LTF or EHT-LTF sequences to measure the channel quality of communication links, they can only accurately measure the channel quality of communication links under BPSK modulation. In other words, current HE-LTF or EHT-LTF sequences have limited applicability and cannot achieve accurate measurement of communication link channel quality in more application scenarios. Summary of the Invention

[0003] This application provides a method and related apparatus for detecting frame transmission, which enables accurate measurement of the channel quality of communication links under at least one of the modulation schemes of QPSK, 16-QAM, 64-QAM, 256-QAM, 1024-QAM, and 4096-QAM when using a first sequence for channel measurement, thus enriching the applicable scenarios of the EHT-LTF sequence.

[0004] In a first aspect, a probe frame transmission method is provided. This method is applied to a first device and includes: generating a probe frame; the probe frame includes a first field, which includes a predefined first sequence, wherein the first sequence includes a sequence obtained by modulating a second sequence using at least one of the following modulation methods: Quadrature Phase Shift Keying (QPSK), 16-QAM, 64-QAM, 256-QAM, 1024-QAM, and 4096-QAM; and transmitting the probe frame, thereby enabling the measurement of the channel quality of the communication link under at least one of the modulation methods (QPSK, 16-QAM, 64-QAM, 256-QAM, 1024-QAM, and 4096-QAM) when performing channel measurements using the first sequence, thus enriching the applicable scenarios for HE-LTF sequences or EHT-LTF sequences. Meanwhile, because the PAPR of the first sequence is low, the distortion of the first sequence is small, which allows for accurate measurement of the channel quality of the communication link under at least one of the modulation schemes of QPSK, 16-QAM, 64-QAM, 256-QAM, 1024-QAM, and 4096-QAM when using the first sequence for channel measurement.

[0005] Secondly, a probe frame transmission method is provided, which is applied to a second device. The method includes: receiving a probe frame; the probe frame includes a first field, the first field including a predefined first sequence, wherein the first sequence includes a sequence obtained by modulating a second sequence using at least one of the following modulation methods: Quadrature Phase Shift Keying (QPSK), 16-QAM (16-QAM), 64-QAM, 256-QAM, 1024-QAM, and 4096-QAM; and performing channel measurement based on the first sequence, so that when performing channel measurement using the first sequence, the channel quality of the communication link under at least one of the modulation methods of QPSK, 16-QAM, 64-QAM, 256-QAM, 1024-QAM, and 4096-QAM can be measured, thus enriching the applicable scenarios of HE-LTF sequences or EHT-LTF sequences. Meanwhile, because the PAPR of the first sequence is low, the distortion of the first sequence is small, which allows for accurate measurement of the channel quality of the communication link under at least one of the modulation schemes of QPSK, 16-QAM, 64-QAM, 256-QAM, 1024-QAM, and 4096-QAM when using the first sequence for channel measurement.

[0006] Thirdly, a communication device is provided, comprising a processing module and a transceiver module. The processing module is used to generate a probe frame; the probe frame includes a first field, the first field including a predefined first sequence, wherein the first sequence includes a sequence obtained by modulating a second sequence using at least one of the following modulation methods: Quadrature Phase Shift Keying (QPSK), 16-QAM, 64-QAM, 256-QAM, 1024-QAM, and 4096-QAM; the transceiver module is used to transmit the probe frame.

[0007] Fourthly, a communication device is provided, comprising a processing module and a transceiver module. The transceiver module is used to receive a probe frame; the probe frame includes a first field, the first field including a predefined first sequence, wherein the first sequence includes a sequence obtained by modulating a second sequence using at least one of the following modulation methods: Quadrature Phase Shift Keying (QPSK), 16-QAM, 64-QAM, 256-QAM, 1024-QAM, and 4096-QAM; the processing module is used to perform channel measurement based on the first sequence.

[0008] Optionally, in conjunction with the first, second, third, or fourth aspect, the second sequence is an HE-LTF sequence or an EHT-LTF sequence in 4x mode with a bandwidth of 80MHz.

[0009] The HE-LTF sequence is:

[0010] HE-LTF 4x(-500∶500)＝[1，-1，-1，-1，-1，1，-1，-1，1，-1，-1，-1，1，1，-1，-1，-1，1，-1，-1，1，-1，1，1，1，-1，1，-1，1，-1，-1，-1，-1，1，1，1，1，1，-1，-1，1，-1，1，-1，-1，-1，1，1，-1，-1，1，-1，-1，-1，1，1，1，-1，-1，1，1，-1，-1，1，-1，1，1，-1，1，-1，1，1，1，-1，1，-1，1，1，1，1，1，1，-1，-1，-1，1，-1，1，-1，-1，-1，1，-1，-1，1，1，1，1，1，1，-1，1，-1，1，1，-1，1，-1，1，-1，1，-1，1，-1，-1，1，1，1，1，-1，-1，-1，-1，-1，-1，-1，-1，1，-1，-1，1，-1，-1，1，1，1，-1，1，-1，-1，-1，1，1，1，-1，1，1，-1，-1，1，-1，-1，-1，1，1，1，1，-1，1，1，1，1，1，1，-1，1，-1，-1，1，-1，1，-1，-1，1，1，1，1，1，-1，1，1，-1，-1，1，1，1，-1，1，1，-1，1，1，-1，-1，1，1，-1，-1，-1，-1，1，1，1，1，1，-1，1，1，1，1，1，-1，1，-1，1，-1，-1，1，-1，-1，-1，-1，-1，1，-1，-1，-1，1，1，-1，1，-1，1，-1，-1，-1，-1，-1，1，1，1，1，-1，1，-1，-1，1，1，-1，-1，-1，1，1，1，1，1，-1，1，-1，1，-1，-1，1，1，1，-1，1，1，1，1，1，-1，1，1，-1，1，-1，1，-1，-1，-1，-1，-1，1，-1，-1，-1，-1，-1，1，1，1，1，-1，-1，1，1，-1，-1，1，-1，-1，1，-1，-1，-1，1，1，-1，-1，1，-1，-1，-1，-1，-1，1，1，-1，1，-1，1，1，-1，1，-1，-1，-1，-1，-1，-1，1，-1，-1，-1，-1，1，1，1，-1，1，1，-1，-1，1，-1，-1，-1，1，1，1，-1，1，-1，1，-1，-1，-1，1，-1，1，-1，1，-1，-1，-1，1，-1，-1，1，-1，1，1，-1，-1，-1，1，1，-1，-1，-1，-1，1，-1，1，1，-1，1，-1，1，1，1，1，1，1，-1，-1，1，-1，-1，-1，1，-1，1，-1，-1，-1，1，1，1，1，1，1，-1，1，-1，1，1，1，-1，1，-1，1，1，-1，1，-1，-1，1，1，-1，-1，1，1，1，-1，-1，-1，1，-1，-1，1，1，-1，-1，-1，1，-1，1，-1，-1，1，1，1，1，1，-1，-1，-1，-1，1，-1，1，-1，1，1，1，-1，1，-1，-1，1，-1，-1，-1，1，1，-1，-1，-1，1，-1，-1，1，-1，-1，-1，-1，1，-1，1，1，-1，-1，-1，1，-1，-1，0，0，0，0，0，-1，-1，1，-1，1，1，1，1，1，1，-1，-1，-1，-1，1，-1，-1，1，-1，-1，-1，1，1，-1，-1，-1，1，-1，-1，1，-1，1，1，1，-1，1，-1，1，-1，-1，-1，-1，1，1，1，1，1，-1，-1，1，-1，1，-1，-1，-1，1，1，-1，-1，1，-1，-1，-1，1，1，1，-1，-1，1，1，-1，-1，1，-1，1，1，-1，1，-1，1，1，1，-1，1，-1，1，1，1，1，1，1，-1，-1，-1，1，-1，1，-1，-1，-1，1，-1，-1，1，1，1，1，1，1，-1，1，-1，1，1，-1，1，-1，-1，-1，-1，1，1，-1，-1，-1，1，1，-1，1，-1，-1，1，-1，-1，-1，1，-1，1，-1，1，-1，-1，-1，1，-1，1，-1，1，1，1，-1，-1，-1，1，-1，-1，1，1，-1，1，1，1，-1，-1，-1，-1，1，-1，-1，-1，-1，-1，-1，1，-1，1，1，-1，1，-1，1，1，-1，-1，-1，-1，-1，1，-1，-1，1，1，-1，-1，-1，1，-1，-1，1，-1，-1，1，1，-1，-1，1，1，1，1，-1，-1，-1，-1，-1，1，-1，-1，-1，-1，-1，1，-1，1，-1，1，1，-1，1，1，1，1，1，-1，1，1，1，-1，-1，1，-1，1，-1，1，1，1，1，1，-1，-1，-1，1，1，-1，-1，-1，-1，-1，-1，-1，-1，1，1，1，1，1，-1，1，-1，1，-1，-1，1，1，1，-1，1，1，1，1，1，-1，1，1，-1，1，-1，1，-1，-1, -1, -1, -1, 1, -1, -1, -1, -1, -1, 1, 1, 1, -1, -1, 1, -1, -1, -1, 1, -1, -1, -1, 1, -1, -1, -1, -1, -1, -1, -1, 1, -1, 1, -1, 1, -1, 1, -1, -1, -1, -1, -1, - 1, -1, 1, -1, -1, -1, -1, 1, 1, -1, 1, 1, -1, -1, -1, -1, 1, 1, -1, 1, -1, -1, -1, 1, 1, -1, 1, 1, -1, 1, 1, -1, 1, 1, 1, 1, -1, -1, -1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, -1, 1, -1, 1, -1, -1, -1, -1, -1, 1, 1, -1, 1, 1, 1, -1, 1, 1, -1, -1, -1, -1, -1, 1, -1, 1, -1, 1, -1, -1, -1, 1, -1, -1, -1, 1, -1, 1, -1, -1, -1, 1, -1, -1, -1, - 1, 1, 1, 1, -1, 1, 1, -1, -1, 1, 1, 1, -1, 1, 1, -1, -1, -1, -1, 1, 1, 1, 1, -1, 1, -1, 1, -1, -1, 1, 1, -1, 1, 1, 1, -1, -1, 1, 1, 1, -1, 1, 1, 1, -1]. ,

[0011] Among them, HE-LTF 4x The expression (-500∶500) means that the values ​​on each subcarrier in the sequence from -500 to 500 are sequentially the values ​​in the HE-LTF sequence. It can be seen that the components of the second sequence are all +1, 0, or -1. Under BPSK modulation, the HE-LTF sequence has low distortion and low PAPR, thus allowing for accurate measurement of the channel quality of the link under BPSK modulation.

[0012] The EHT-LTF sequence is:

[0013] EHT-LTF 4x(-500∶500)＝[1，-1，-1，-1，-1，1，-1，-1，1，-1，-1，-1，1，1，-1，-1，-1，1，-1，-1，1，-1，1，1，1，-1，1，-1，1，-1，-1，-1，-1，1，1，1，1，1，-1，-1，1，-1，1，-1，-1，-1，1，1，-1，-1，1，-1，-1，-1，1，1，1，-1，-1，1，1，-1，-1，1，-1，1，1，-1，1，-1，1，1，1，-1，1，-1，1，1，1，1，1，1，-1，-1，-1，1，-1，1，-1，-1，-1，1，-1，-1，1，1，1，1，1，1，-1，1，-1，1，1，-1，1，-1，1，-1，1，-1，1，-1，-1，1，1，1，1，-1，-1，-1，-1，-1，-1，-1，-1，1，-1，-1，1，-1，-1，1，1，1，-1，1，-1，-1，-1，1，1，1，-1，1，1，-1，-1，1，-1，-1，-1，1，1，1，1，-1，1，1，1，1，1，1，-1，1，-1，-1，1，-1，1，-1，-1，1，1，1，1，1，-1，1，1，-1，-1，1，1，1，-1，1，1，-1，1，1，-1，-1，1，1，-1，-1，-1，-1，1，1，1，1，1，-1，1，1，1，1，1，-1，1，-1，1，-1，-1，1，-1，-1，-1，-1，-1，1，-1，-1，-1，1，1，-1，1，-1，1，-1，-1，-1，-1，-1，1，1，1，1，-1，1，-1，-1，1，1，-1，-1，-1，1，1，1，1，1，-1，1，-1，1，-1，-1，1，1，1，-1，1，1，1，1，1，-1，1，1，-1，1，-1，1，-1，-1，-1，-1，-1，1，-1，-1，-1，-1，-1，1，1，1，1，-1，-1，1，1，-1，-1，1，-1，-1，1，-1，-1，-1，1，1，-1，-1，1，-1，-1，-1，-1，-1，1，1，-1，1，-1，1，1，-1，1，-1，-1，-1，-1，-1，-1，1，-1，-1，-1，-1，1，1，1，-1，1，1，-1，-1，1，-1，-1，-1，1，1，1，-1，1，-1，1，-1，-1，-1，1，-1，1，-1，1，-1，-1，-1，1，-1，-1，1，-1，1，1，-1，-1，-1，1，1，-1，-1，-1，-1，1，-1，1，1，-1，1，-1，1，1，1，1，1，1，-1，-1，1，-1，-1，-1，1，-1，1，-1，-1，-1，1，1，1，1，1，1，-1，1，-1，1，1，1，-1，1，-1，1，1，-1，1，-1，-1，1，1，-1，-1，1，1，1，-1，-1，-1，1，-1，-1，1，1，-1，-1，-1，1，-1，1，-1，-1，1，1，1，1，1，-1，-1，-1，-1，1，-1，1，-1，1，1，1，-1，1，-1，-1，1，-1，-1，-1，1，1，-1，-1，-1，1，-1，-1，1，-1，-1，-1，-1，1，-1，1，1，-1，-1，-1，1，-1，-1，0，0，0，0，0，-1，-1，1，-1，1，1，1，1，1，1，-1，-1，-1，-1，1，-1，-1，1，-1，-1，-1，1，1，-1，-1，-1，1，-1，-1，1，-1，1，1，1，-1，1，-1，1，-1，-1，-1，-1，1，1，1，1，1，-1，-1，1，-1，1，-1，-1，-1，1，1，-1，-1，1，-1，-1，-1，1，1，1，-1，-1，1，1，-1，-1，1，-1，1，1，-1，1，-1，1，1，1，-1，1，-1，1，1，1，1，1，1，-1，-1，-1，1，-1，1，-1，-1，-1，1，-1，-1，1，1，1，1，1，1，-1，1，-1，1，1，-1，1，-1，-1，-1，-1，1，1，-1，-1，-1，1，1，-1，1，-1，-1，1，-1，-1，-1，1，-1，1，-1，1，-1，-1，-1，1，-1，1，-1，1，1，1，-1，-1，-1，1，-1，-1，1，1，-1，1，1，1，-1，-1，-1，-1，1，-1，-1，-1，-1，-1，-1，1，-1，1，1，-1，1，-1，1，1，-1，-1，-1，-1，-1，1，-1，-1，1，1，-1，-1，-1，1，-1，-1，1，-1，-1，1，1，-1，-1，1，1，1，1，-1，-1，-1，-1，-1，1，-1，-1，-1，-1，-1，1，-1，1，-1，1，1，-1，1，1，1，1，1，-1，1，1，1，-1，-1，1，-1，1，-1，1，1，1，1，1，-1，-1，-1，1，1，-1，-1，-1，-1，-1，-1，-1，-1，1，1，1，1，1，-1，1，-1，1，-1，-1，1，1，1，-1，1，1，1，1，1，-1，1，1，-1，1，-1，1，-1，-1, -1, -1, -1, 1, -1, -1, -1, -1, -1, 1, 1, 1, -1, -1, 1, -1, -1, -1, 1, -1, -1, -1, 1, -1, -1, -1, -1, -1, -1, -1, 1, -1, 1, -1, 1, -1, 1, -1, -1, -1, -1, -1, - 1, -1, 1, -1, -1, -1, -1, 1, 1, -1, 1, 1, -1, -1, -1, -1, 1, 1, -1, 1, -1, -1, -1, 1, 1, -1, 1, 1, -1, 1, 1, -1, 1, 1, 1, 1, -1, -1, -1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, -1, 1, -1, 1, -1, -1, -1, -1, -1, 1, 1, -1, 1, 1, 1, -1, 1, 1, -1, -1, -1, -1, -1, 1, -1, 1, -1, 1, -1, -1, -1, 1, -1, -1, -1, 1, -1, 1, -1, -1, -1, 1, -1, -1, -1, - 1,1,1,1,-1,1,1,-1,-1,1,1,1,-1,1,-1,1,1,-1,-1,-1,-1,-1,1,1,1,1,-1,1 , -1, 1, -1, -1, -1, 1, -1, 1, 1, -1, 1, 1, 1, -1, -1, 1, 1, 1, -1, 1, 1, -1, 1, 1, 1, 1, -1]. EHT-LTF, 4x The expression (-500∶500) means that the values ​​on each subcarrier in the sequence from -500 to 500 are sequentially the values ​​in the EHT-LTF sequence. It can be seen that the components of the second sequence are all +1, 0, or -1. Under BPSK modulation, the EHT-LTF sequence has low distortion and low PAPR, thus allowing for accurate measurement of the channel quality of the link under BPSK modulation.

[0014] Optionally, in combination with the first, second, third, or fourth aspect, the first sequence satisfies the following formula:

[0015] s i =[a0, c i ,0,0,0,0,0,(-1j)*a1].

[0016] The second sequence is an HE-LTF sequence, a0 and a1 are subsequences of the HE-LTF sequence, j is the imaginary unit, and i is an integer greater than or equal to 1 and less than or equal to 7.

[0017] c1=[1j, 1j, 1j, -1j, -1j, -1j, 1j, 1j, -1j].

[0018] c2=[-1,-1,-1,-1j,-1j,-1j, 1j, 1j,-1j].

[0019] c3=[-1,-1,-1,1,1,-1j,1j,1j,-1j].

[0020] c4=[-1,-1,-1,1,1,1,1j,1j,-1j].

[0021] c5=[-1,-1,-1,1,1,1,-1,1j,-1j].

[0022] c6=[-1,--1,-1,1,1,1,-1,-1,-1j].

[0023] c7=[-1,-1,-1,1,1,1,-1,-1,1].

[0024] In other words, the above technical solution realizes a sequence under QPSK modulation, which enables accurate measurement of the channel quality of the communication link under QPSK modulation when using this sequence to measure the channel quality of the communication link.

[0025] Optionally, in combination with the first, second, third, or fourth aspect, the first sequence satisfies the following formula:

[0026]

[0027] Among them, s k1 =[a0, c k1 ,0,0,0,0,0,(-1j)*a1];s k2 =[a0, c k2 ,0,0,0,0,0,0,(-1j)*a1]; The second sequence is an HE-LTF sequence, where a0 and a1 are subsequences of the HE-LTF sequence, and j is the imaginary unit.

[0028] Where k1 is 1 and k2 is 7; or, k1 is 4 and k2 is 5 or 6; or, k1 is 5 and k2 is 1 or 2.

[0029] c1=[1j, 1j, 1j, -1j, -1j, -1j, 1j, 1j, -1j].

[0030] c2=[-1,-1,-1,-1j,-1j,-1j, 1j, 1j,-1j].

[0031] c4=[-1,-1,-1,1,1,1,1j,1j,-1j].

[0032] c5=[-1,-1,-1,1,1,1,-1,1j,-1j].

[0033] c6=[-1,-1,-1,1,1,1,-1,-1,-1j].

[0034] c7=[-1,-1,-1,1,1,1,-1,-1,1].

[0035] In other words, the above technical solution realizes a sequence under 16-QAM modulation, which enables accurate measurement of the channel quality of the communication link under 16-QAM modulation when using this sequence to measure the channel quality of the communication link.

[0036] Optionally, in combination with the first, second, third, or fourth aspect, the first sequence satisfies the following formula:

[0037]

[0038] Among them, s k3 =[a0, c k3 ,0,0,0,0,0,(-1j)*a1];s k4 =[a0, c k4 ,0,0,0,0,0,(-1j)*a1];s k5 =[a0, c k5 ,0,0,0,0,0,0,(-1j)*a1]; The second sequence is an HE-LTF sequence, where a0 and a1 are subsequences of the HE-LTF sequence, and j is the imaginary unit.

[0039] Where k3 is 1, k4 is 6, and k5 is 7; or, k3 is 1, k4 is 7, and k5 is 5 or 6; or, k3 is 2, k4 is 7, and k5 is 6 or 7; or, k3 is 3, k4 is 5, and k5 is 6; or, k3 is 3, k4 is 5, and k5 is 7; or, k3 is 3, k4 is 6, and k5 is 5 or 6; or, k3 is 3, k4 is 7, and k5 is 1, 2, 3, or 4; or, k3 is 4, k4 is 4, and k5 is 7; or, k3 is 4, k4 is 5, and k5 is 3. 4 or 5; or, k3 is 4, k4 is 6, k5 is 1, 2, 3 or 4; or, k3 is 5, k4 is 1, k5 is 3 or 4; or, k3 is 5, k4 is 1, k5 is 5; or, k3 is 5, k4 is 2, k5 is 4, 5 or 6; or, k3 is 5, k4 is 3, k5 is 1, 2, 3 or 4; or, k3 is 5, k4 is 4, k5 is 1 or 2; or, k3 is 6, k4 is 1, k5 is 1 or 2; or, k3 is 6, k4 is 2, k5 is 1, 2 or 3.

[0040] c1=[1j, 1j, 1j, -1j, -1j, -1j, 1j, 1j, -1j].

[0041] c2=[-1,-1,-1,-1j,-1j,-1j, 1j, 1j,-1j].

[0042] c3=[-1,-1,-1,1,1,-1j,1j,1j,-1j].

[0043] c4=[-1,-1,-1,1,1,1,1j,1j,-1j].

[0044] c5=[-1,-1,-1,1,1,1,-1,1j,-1j].

[0045] c6=[-1,-1,-1,1,1,1,-1,-1,-1j].

[0046] c7=[-1,-1,-1,1,1,1,-1,-1,1].

[0047] In other words, the above technical solution realizes a sequence under 64-QAM modulation, which enables accurate measurement of the channel quality of a communication link under 64-QAM modulation when using this sequence to measure the channel quality of the communication link.

[0048] Optionally, in combination with the first, second, third, or fourth aspect, the first sequence satisfies the following formula:

[0049]

[0050] Among them, s k6 =[a0, c k6 ,0,0,0,0,0,(-1j)*a1];s k7 =[a0, c k7 ,0,0,0,0,0,(-1j)*a1];s k8 =[a0, c k8 ,0,0,0,0,0,(-1j)*a1];s k9 =[a0, c k9 ,0,0,0,0,0,0,(-1j)*a1]; The second sequence is an HE-LTF sequence, where a0 and a1 are subsequences of the HE-LTF sequence, and j is the imaginary unit.

[0051] Where k6 is 1, k7 is 7, k8 is 4, and k9 is 7; or, k6 is 1, k7 is 7, k8 is 6, and k9 is 3; or, k6 is 2, k7 is 7, k8 is 7, and k9 is 4; or, k6 is 3, k7 is 5, k8 is 7, and k9 is 4; or, k6 is 3, k7 is 6, k8 is 5, and k9 is 5; or, k6 is 3, k7 is 7, k8 is 1, and k9 is 5; or, k6 is 3, k7 is 7, k8 is 2, and k9 is 6; or, k6 is 3, k7 is 7, k8 is 3, and k9 is 4 ; or, k6 is 4, k7 is 4, k8 is 6, k9 is 7; or, k6 is 4, k7 is 6, k8 is 1, k9 is 6; or, k6 is 4, k7 is 6, k8 is 4, k9 is 3; or, k6 is 5, k7 is 1, k8 is 1, k9 is 7; or, k6 is 5, k7 is 2, k8 is 6, k9 is 2; or, k6 is 5, k7 is 4, k8 is 1, k9 is 1; or, k6 is 5, k7 is 4, k8 is 2, k9 is 3; or, k6 is 6, k7 is 1, k8 is 1, k9 is 1.

[0052] c1=[1j, 1j, 1j, -1j, -1j, -1j, 1j, 1j, -1j].

[0053] c2=[-1,-1,-1,-1j,-1j,-1j, 1j, 1j,-1j].

[0054] c3=[-1,-1,-1,1,1,-1j,1j,1j,-1j].

[0055] c4=[-1,-1,-1,1,1,1,1j,1j,-1j].

[0056] c5=[-1,-1,-1,1,1,1,-1,1j,-1j].

[0057] c6=[-1,-1,-1,1,1,1,-1,-1,-1j].

[0058] c7=[-1,-1,-1,1,1,1,-1,-1,1].

[0059] In other words, the above technical solution realizes a sequence under 256-QAM modulation, which enables accurate measurement of the channel quality of the communication link under 256-QAM modulation when using this sequence to measure the channel quality of the communication link.

[0060] Optionally, in combination with the first, second, third, or fourth aspect, the first sequence satisfies the following formula:

[0061]

[0062] Among them, s k10=[a0, c k10 ,0,0,0,0,0,(-1j)*a1];s k11 =[a0, c k11 ,0,0,0,0,0,(-1j)*a1];s k12 =[a0, c k12 ,0,0,0,0,0,(-1j)*a1];s k13 =[a0, c k13 ,0,0,0,0,0,(-1j)*a1];s k1 =[a0, c k14 ,0,0,0,0,0,0,(-1j)*a1]; The second sequence is an HE-LTF sequence, where a0 and a1 are subsequences of the HE-LTF sequence, and j is the imaginary unit.

[0063] Where k10 is 1, k11 is 7, k12 is 6, k13 is 1, and k14 is 5; or, k10 is 2, k11 is 7, k12 is 5, k13 is 7, and k14 is 5; or, k10 is 6, k11 is 1, k12 is 2, k13 is 4, and k14 is 4; or, k10 is 4, k11 is 6, k12 is 4, k13 is 1, and k14 is 6 ; or, k10 is 6, k11 is 2, k12 is 1, k13 is 4, k14 is 5; or, k10 is 3, k11 is 6, k12 is 7, k13 is 1, k14 is 2; or, k10 is 5, k11 is 3, k12 is 1, k13 is 6, k14 is 1; or, k10 is 4, k11 is 6, k12 is 2, k13 is 6, k14 is 6.

[0064] c1=[1j, 1j, 1j, -1j, -1j, -1j, 1j, 1j, -1j].

[0065] c2=[-1,-1,-1,-1j,-1j,-1j, 1j, 1j,-1j].

[0066] c3=[-1,-1,-1,1,1,-1j,1j,1j,-1j].

[0067] c4=[-1,-1,-1,1,1,1,1j,1j,-1j].

[0068] c5=[-1,-1,-1,1,1,1,-1,1j,-1j].

[0069] c6=[-1,-1,-1,1,1,1,-1,-1,-1j].

[0070] c7=[-1,-1,-1,1,1,1,-1,-1,1].

[0071] In other words, the above technical solution realizes a sequence under 1024-QAM modulation, which enables accurate measurement of the channel quality of the communication link under 1024-QAM modulation when using this sequence to measure the channel quality of the communication link.

[0072] Optionally, in combination with the first, second, third, or fourth aspect, the first sequence satisfies the following formula:

[0073]

[0074] Among them, s k15 =[a0, c k15 ,0,0,0,0,0,(-1j)*a1];s k16 =[a0, c k16 ,0,0,0,0,0,(-1j)*a1];s k17 =[a0, c k17 ,0,0,0,0,0,(-1j)*a1];s k18 =[a0, c k18 ,0,0,0,0,0,(-1j)*a1];s k1 =[a0, c k19 ,0,0,0,0,0,(-1j)*a1];s k20 =[a0, c k20 ,0,0,0,0,0,0,(-1j)*a1]; The second sequence is an HE-LTF sequence, where a0 and a1 are subsequences of the HE-LTF sequence, and j is the imaginary unit.

[0075] Where k15 is 5, k16 is 2, k17 is 4, k18 is 7, k19 is 2, and k20 is 5; or, k15 is 5, k16 is 2, k17 is 5, k18 is 1, k19 is 7, and k20 is 2; or, k15 is 6, k16 is 2, k17 is 2, k18 is 3, k19 is 7, and k20 is 5; or, k15 is 3, k16 is 6, k17 is 6, k18 is 4, k19 is 5, and k20 is 4. ; or, k15 is 4, k16 is 7, k17 is 2, k18 is 2, k19 is 3, k20 is 2; or, k15 is 6, k16 is 1, k17 is 2, k18 is 3, k19 is 5, k20 is 4; or, k15 is 2, k16 is 7, k17 is 7, k18 is 3, k19 is 6, k20 is 3; or, k15 is 1, k16 is 7, k17 is 5, k18 is 5, k19 is 4, k20 is 2.

[0076] c1=[1j, 1j, 1j, -1j, -1j, -1j, 1j, 1j, -1j].

[0077] c2=[-1,-1,-1,-1j,-1j,-1j, 1j, 1j,-1j].

[0078] c3=[-1,-1,-1,1,1,-1j,1j,1j,-1j].

[0079] c4=[-1,-1,-1,1,1,1,1j,1j,-1j].

[0080] c5=[-1,-1,-1,1,1,1,-1,1j,-1j].

[0081] c6=[-1,-1,-1,1,1,1,-1,-1,-1j].

[0082] c7=[-1,-1,-1,1,1,1,-1,-1,1].

[0083] In other words, the above technical solution realizes a sequence under 4096-QAM modulation, which enables accurate measurement of the channel quality of the communication link under 4096-QAM modulation when using this sequence to measure the channel quality of the communication link.

[0084] Optionally, in conjunction with the first, second, third, or fourth aspect, a0 refers to elements 1 through 489 in the HE-LTF, and a1 refers to elements 504 through 1001 in the HE-LTF. This achieves the generation of a first sequence from an HE-LTF sequence in 802.11ax with an 80MHz bandwidth 4x mode, resulting in a low PAPR for the first sequence.

[0085] Optionally, in combination with the first, second, third, or fourth aspect, the first sequence satisfies the following formula:

[0086] p u =[b0, d u ,0,0,0,0,0,(-1j)*b1].

[0087] In this sequence, the second sequence is an EHT-LTF sequence, b0 and b1 are subsequences of the EHT-LTF sequence, j is the imaginary unit, and u is an integer greater than or equal to 1 and less than or equal to 5.

[0088] d1=[1j, 1j, 1j, -1j, 1j, 1j].

[0089] d2=[-1, 1j, 1j, -1j, 1j, 1j].

[0090] d3=[-1,-1,-1,-1j, 1j, 1j].

[0091] d4=[-1,-1,-1,1,-1,1j].

[0092] d5=[-1,-1,-1,1,-1,-1].

[0093] In other words, the above technical solution realizes a sequence under QPSK modulation, which enables accurate measurement of the channel quality of the communication link under QPSK modulation when using this sequence to measure the channel quality of the communication link.

[0094] Optionally, in combination with the first, second, third, or fourth aspect, the first sequence satisfies the following formula:

[0095]

[0096] Where, p t1 =[b0, d t1 ,0,0,0,0,0,(-1j)*b1];p t2 =[b0, d t2 ,0,0,0,0,0,0,(-1j)*b1]; The second sequence is an EHT-LTF sequence, b0 and b1 are subsequences in the EHT-LTF sequence, and j is the imaginary unit.

[0097] Where t1 is 5 and t2 is 1, 2, 3, 4 or 5; or t1 is 1 and t2 is 5; or t1 is 4 and t2 is 5.

[0098] d1=[1j, 1j, 1j, -1j, 1j, 1j].

[0099] d2=[-1, 1j, 1j, -1j, 1j, 1j].

[0100] d3=[-1,-1,-1,-1j, 1j, 1j].

[0101] d4=[-1,-1,-1,1,-1,1j].

[0102] d5=[-1,-1,-1,1,-1,-1].

[0103] In other words, the above technical solution realizes a sequence under 16-QAM modulation, which enables accurate measurement of the channel quality of the communication link under 16-QAM modulation when using this sequence to measure the channel quality of the communication link.

[0104] Optionally, in combination with the first, second, third, or fourth aspect, the first sequence satisfies the following formula:

[0105]

[0106] Where, p t3=[b0, d t3 ,0,0,0,0,0,(-1j)*b1];p t4 =[b0, d t4 ,0,0,0,0,0,(-1j)*b1];p t5 =[b0, d t5 ,0,0,0,0,0,0,(-1j)*b1]; The second sequence is an EHT-LTF sequence, b0 and b1 are subsequences in the EHT-LTF sequence, and j is the imaginary unit.

[0107] Where t3 is 5, t4 is 5, and t5 is 1, 2, 3, 4, or 5; or, t3 is 5, t4 is 1, and t5 is 5; or, t3 is 5, t4 is 1, and t5 is 1.

[0108] d1=[1j, 1j, 1j, -1j, 1j, 1j].

[0109] d2=[-1, 1j, 1j, -1j, 1j, 1j].

[0110] d3=[-1,-1,-1,-1j, 1j, 1j].

[0111] d4=[-1,-1,-1,1,-1,1j].

[0112] d5=[-1,-1,-1,1,-1,-1].

[0113] In other words, the above technical solution realizes a sequence under 64-QAM modulation, which enables accurate measurement of the channel quality of a communication link under 64-QAM modulation when using this sequence to measure the channel quality of the communication link.

[0114] Optionally, in combination with the first, second, third, or fourth aspect, the first sequence satisfies the following formula:

[0115]

[0116] Where, p t6 =[b0, d t6 ,0,0,0,0,0,(-1j)*b1];p t7 =[b0, d t7 ,0,0,0,0,0,(-1j)*b1];p t8 =[b0, d t8 ,0,0,0,0,0,(-1j)*b1];pt9=[b0,d t9 ,0,0,0,0,0,0,(21j)*b1];The second sequence is an EHT-LTF sequence, b0 and b1 are subsequences in the EHT-LTF sequence, and j is the imaginary unit.

[0117] Where t6 is 5, t7 is 5, t8 is 5, and t9 is 1, 2, 3, or 4; or t6 is 5, t7 is 5, t8 is 1, and t9 is 1, 4, or 5; or t6 is 5, t7 is 1, t8 is 5, and t9 is 5.

[0118] d1=[1j, 1j, 1j, -1j, 1j, 1j].

[0119] d2=[-1, 1j, 1j, -1j, 1j, 1j].

[0120] d3=[-1,-1,-1,-1j, 1j, 1j].

[0121] d4=[-1,-1,-1,1,-1,1j].

[0122] d5=[-1,-1,-1,1,-1,-1].

[0123] In other words, the above technical solution realizes a sequence under 256-QAM modulation, which enables accurate measurement of the channel quality of the communication link under 256-QAM modulation when using this sequence to measure the channel quality of the communication link.

[0124] Optionally, in combination with the first, second, third, or fourth aspect, the first sequence satisfies the following formula:

[0125]

[0126] Where, p t10 =[b0, d t10 ,0,0,0,0,0,(-1j)*b1];p t11 =[b0, d t11 ,0,0,0,0,0,(-1j)*b1];p t12 =[b0, d t12 ,0,0,0,0,0,(-1j)*b1];p t13 =[b0, d t1 ,0,0,0,0,0,(-1j)*b1];p t14 =[b0, d t14 ,0,0,0,0,0,0,(-1j)*b1]; The second sequence is an EHT-LTF sequence, b0 and b1 are subsequences in the EHT-LTF sequence, and j is the imaginary unit.

[0127] Where t10 is 5, t11 is 5, t12 is 5, t13 is 1, and t14 is 2 or 4; or, t10 is 5, t11 is 5, t12 is 5, t13 is 4, and t14 is 1 or 5; or, t10 is 5, t11 is 5, t12 is 1, t13 is 5, and t14 is 1 or 5; or, t10 is 5, t11 is 5, t12 is 1, t13 is 5, and t14 is 5; or, t10 is 5, t11 is 5, t12 is 5, t13 is 2, and t14 is 5; or, t10 is 5, t11 is 5, t12 is 5, t13 is 1, and t14 is 3.

[0128] d1=[1j, 1j, 1j, -1j, 1j, 1j].

[0129] d2=[-1, 1j, 1j, -1j, 1j, 1j].

[0130] d3=[-1,-1,-1,-1j, 1j, 1j].

[0131] d4=[-1,-1,-1,1,-1,1j].

[0132] d5=[-1,-1,-1,1,-1,-1].

[0133] In other words, the above technical solution realizes a sequence under 1024-QAM modulation, which enables accurate measurement of the channel quality of the communication link under 1024-QAM modulation when using this sequence to measure the channel quality of the communication link.

[0134] Optionally, in combination with the first, second, third, or fourth aspect, the first sequence satisfies the following formula:

[0135]

[0136] Where, p t15 =[b0, d t15 ,0,0,0,0,0,(-1j)*b1];p r16 =[b0, d t1 ,0,0,0,0,0,(-1j)*b1];p t17 =[b0, d t17 ,0,0,0,0,0,(-1j)*b1];p t18 =[b0, d t18 ,0,0,0,0,0,(-1j)*b1];p t19 =[b0, d t19 ,0,0,0,0,0,(-1j)*b1];pt 20 =[b0, d t20,0,0,0,0,0,0,(-1j)*b1]; The second sequence is an EHT-LTF sequence, b0 and b1 are subsequences in the EHT-LTF sequence, and j is the imaginary unit.

[0137] Where t15 is 5, t16 is 5, t17 is 5, t18 is 1, t19 is 2, and t20 is 5; or, t15 is 5, t16 is 5, t17 is 5, t18 is 1, t19 is 1, and t20 is 3; or, t15 is 5, t16 is 5, t17 is 1, t18 is 5, t19 is 5, and t20 is 1; or, t15 is 5, t16 is 5, t17 is 5, t18 is 5, t19 is 3, and t20 is 3. ; or, t15 is 5, t16 is 5, t17 is 5, t18 is 1, t19 is 1, t20 is 2; or, t15 is 5, t16 is 5, t17 is 5, t18 is 1, t19 is 4, t20 is 1; or, t15 is 5, t16 is 5, t17 is 5, t18 is 4, t19 is 5, t20 is 1; or, t15 is 5, t16 is 5, t17 is 5, t18 is 1, t19 is 4, t20 is 5.

[0138] d1=[1j, 1j, 1j, -1j, 1j, 1j].

[0139] d2=[-1, 1j, 1j, -1j, 1j, 1j].

[0140] d3=[-1,-1,-1,-1j, 1j, 1j].

[0141] d4=[-1,-1,-1,1,-1,1j].

[0142] d5=[-1,-1,-1,1,-1,-1].

[0143] In other words, the above technical solution realizes a sequence under 4096-QAM modulation, which enables accurate measurement of the channel quality of the communication link under 4096-QAM modulation when using this sequence to measure the channel quality of the communication link.

[0144] Optionally, in conjunction with the first, second, third, or fourth aspects, b0 represents the 1st to 492nd elements of the EHT-LTF sequence, and b1 represents the 504th to 1001st elements of the EHT-LTF sequence. This achieves the generation of a first sequence from an EHT-LTF sequence in 802.11be with an 80MHz bandwidth 4x mode, resulting in a low PAPR for the first sequence.

[0145] Fifthly, a chip is provided, the chip including at least one logic circuit and an input / output interface, the logic circuit being used to read and execute stored instructions, and when the instructions are executed, causing the chip to perform a method as described in either the first or second aspect.

[0146] A sixth aspect provides a computer-readable storage medium, characterized in that the computer-readable storage medium stores a computer program, the computer program including program instructions, which, when executed by a computer, cause the computer to perform the method as described in either the first or second aspect.

[0147] A seventh aspect provides a communication device including a processor and a transceiver, the processor being configured to support the communication device in performing corresponding functions in the methods of the first or second aspect. The transceiver is used to support communication between the communication device and other communication devices besides the communication device. The communication device may further include a memory coupled to the processor, which stores necessary program instructions and data for the communication device. The transceiver may be integrated into the communication device or independent of the communication device, without limitation.

[0148] Eighthly, a computer program product containing instructions is provided that, when run on a computer, causes the computer to perform the method of either the first or second aspect.

[0149] Ninth aspect, a communication system is provided, including the first device and / or the second device described above. Attached Figure Description

[0150] The accompanying drawings used in the description of the embodiments will be briefly introduced below.

[0151] Figure 1 This is a schematic diagram of a carrier tone plan for 80MHz in 802.11ax provided in an embodiment of this application;

[0152] Figure 2 This is a schematic diagram of the frame structure of a detection frame provided in an embodiment of this application;

[0153] Figure 3 This is a schematic diagram of an 80MHz tone plan in 802.11be provided in an embodiment of this application;

[0154] Figure 4 A network architecture diagram of a wireless local area network (WLAN) provided for embodiments of this application;

[0155] Figure 5 The diagram shown is a hardware structure schematic of a communication device applicable to the embodiments of this application;

[0156] Figure 6 A schematic flowchart illustrating a detection frame transmission method provided in an embodiment of this application;

[0157] Figure 7 This is a schematic diagram of the frame structure of a detection frame provided in an embodiment of this application;

[0158] Figure 8 This is a schematic diagram of the structure of a communication device provided in an embodiment of this application. Detailed Implementation

[0159] The technical solutions in the embodiments of this application will be described below with reference to the accompanying drawings. The terms "system" and "network" in the embodiments of this application can be used interchangeably. Unless otherwise stated, " / " indicates that the objects before and after are in an "or" relationship; for example, A / B can represent A or B. "And / or" in this application is merely a description of the relationship between related objects, indicating that three relationships can exist. For example, A and / or B can represent: A alone, A and B simultaneously, and B alone, where A and B can be singular or plural. Furthermore, in the description of this application, unless otherwise stated, "multiple" refers to two or more. "At least one of the following" or similar expressions refer to any combination of these items, including any combination of single or plural items. For example, at least one of a, b, or c can represent: a, b, c, ab, ac, bc, or abc, where a, b, and c can be one or multiple. Furthermore, to facilitate a clear description of the technical solutions in the embodiments of this application, the terms "first" and "second" are used in the embodiments of this application to distinguish between network elements and similar items with essentially the same function. Those skilled in the art will understand that the terms "first" and "second" do not limit the quantity or execution order, and that the terms "first" and "second" are not necessarily different.

[0160] References to "one embodiment" or "some embodiments" in the embodiments described in this application mean that one or more embodiments of this application include a specific feature, structure, or characteristic described in connection with that embodiment. Therefore, the phrases "in one embodiment," "in some embodiments," "in other embodiments," "in still other embodiments," etc., appearing in different parts of this specification do not necessarily refer to the same embodiment, but rather mean "one or more, but not all, embodiments," unless otherwise specifically emphasized. The terms "comprising," "including," "having," and variations thereof mean "including but not limited to," unless otherwise specifically emphasized.

[0161] The following detailed embodiments further illustrate the objectives, technical solutions, and beneficial effects of this application. It should be understood that the following are merely specific embodiments of this application and are not intended to limit the scope of protection of this application. Any modifications, equivalent substitutions, improvements, etc., made based on the technical solutions of this application should be included within the scope of protection of this application.

[0162] In the various embodiments of this application, unless otherwise specified or in case of logical conflict, the terminology and / or descriptions of different embodiments are consistent and can be referenced by each other. The technical features of different embodiments can be combined to form new embodiments according to their inherent logical relationship.

[0163] The following is an explanation of some of the terms (or communication terms) used in this application.

[0164] 1. Carrier distribution of 802.11ax

[0165] It should be noted that this scheme involves modifying the highly efficient long training field (HE-LTF) sequence for the 80MHz bandwidth in 802.11ax. Therefore, only the carrier tone plan for the 80MHz bandwidth in 802.11ax will be described here. See [link to relevant documentation]. Figure 1 , Figure 1 This is a schematic diagram of a carrier tone plan of 80MHz in 802.11ax provided in an embodiment of this application. Figure 1 This illustrates a subcarrier design for 802.11ax 80MHz, such as... Figure 1As shown, the 80MHz bandwidth of 802.11ax includes 36 resource units (RUs)26, or 16 RUs52, or 8 RUs106, or 4 RUs242, or 1 RU996 and 5 DC subcarriers. There is no gap between the first and second RUs242; there are 7 DC subcarriers / empty subcarriers between the second and third RUs242; there is also no gap between the third and fourth RUs242. Understandably, RU26 can refer to a resource unit consisting of 26 consecutive subcarriers, i.e., RU26 includes: 24 data subcarriers and 2 pilot subcarriers. Similarly, RU52 can refer to a resource unit consisting of 52 consecutive subcarriers, i.e., RU52 includes 48 data subcarriers and 4 pilot subcarriers; RU106 can refer to a resource unit consisting of 106 consecutive subcarriers, i.e., RU106 includes 24 data subcarriers and 2 pilot subcarriers; RU242 can refer to a resource unit consisting of 242 consecutive subcarriers, i.e., RU242 includes 234 data subcarriers and 8 pilot subcarriers; RU484 can refer to a resource unit consisting of 484 consecutive subcarriers, i.e., RU484 includes 468 data subcarriers and 16 pilot subcarriers; RU996 can refer to a resource unit consisting of 996 consecutive subcarriers, i.e., RU996 includes 980 data subcarriers and 16 pilot subcarriers.

[0166] based on Figure 1 The 80MHz subcarrier design shown in 802.11ax specifies the HE-LTF sequence for channel estimation and defines the corresponding probe frame format.

[0167] See Figure 2 , Figure 2 This is a schematic diagram of the frame structure of a detection frame provided in an embodiment of this application. For example... Figure 2As shown, the probe frame includes a legacy short training field (L-STF), a legacy long training field (L-LTF), a legacy signal field (L-SIG), a repeated legacy signal field (RL-SIG), a high-efficient signal-a field (HE-SIG-A), a high-efficient short training field (HE-STF), a high-efficient long training field (HE-LTF), and a packet extension (PE) field.

[0168] exist Figure 2 In the probe frame, the HE-LTF field is a high-efficiency long training field for multiple input multiple output (MIMO) channel estimation. This field can contain one or more HE-LTF symbols, each of which is an orthogonal frequency division multiple access (OFDMA) symbol.

[0169] In the 802.11ax system, the HE-LTF sequence used for channel estimation employs two modes: 2x and 4x. Since this application only relates to the 4x mode, only the 4x mode will be described here. It can be understood that in the 802.11ax system, the 4x mode means that the subcarrier index mapped by the HE-LTF sequence is the same as the subcarrier index in the tone plan of the data portion.

[0170] 2. Carrier distribution of 802.11be

[0171] It should be noted that this scheme involves modifying the 80MHz bandwidth EHT-LTF sequence in 802.11be. Therefore, only the 80MHz tone plan in 802.11be will be described here. Figure 3 This is a schematic diagram of an 80MHz tone plan in 802.11be provided in an embodiment of this application. Figure 3 This illustrates an 802.11be 80MHz subcarrier design, such as... Figure 3As shown, the 80MHz bandwidth of 802.11be includes 36 RU26, or 16 RU52, or 8 RU106, or 4 RU242, or 2 RU484 and 5 DC subcarriers / empty subcarriers, or 1 RU996 and 5 DC subcarriers. Specifically, there are 5 DC subcarriers between the first and second RU242; there are also 5 DC subcarriers between the third and fourth RU242.

[0172] It should be noted that for tone plans with larger bandwidths, such as 160MHz or 320MHz, they can be obtained by copying and phase-rotating an 80MHz tone plan, and this is not a limitation here.

[0173] 3. 4x mode

[0174] In the 802.11ax system, 4x mode refers to a subcarrier index in the HE-LTF sequence mapping that is the same as the subcarrier index in the data portion's carrier distribution (tone plan). In the 802.11be system, 4x mode refers to a subcarrier index in the EHT-LTF sequence mapping that is the same as the subcarrier index in the data portion's carrier distribution (tone plan).

[0175] The above content briefly explains the meaning of the terms (communication terms) involved in the embodiments of this application. It is intended to help people better understand the technical solutions provided in the embodiments of this application and does not constitute a limitation on the technical solutions provided in the embodiments of this application.

[0176] It should be understood that the embodiments of this application can be applied to wireless local area network (WLAN) scenarios, and can be applied to IEEE 802.11 system standards, such as 802.11ax, 802.11be, or next-generation standards. Alternatively, the embodiments of this application can also be applied to wireless local area network systems such as Internet of Things (IoT) networks or Vehicle to X (V2X) networks. Of course, the embodiments of this application can also be applied to other possible communication systems, such as LTE systems, LTE frequency division duplex (FDD) systems, LTE time division duplex (TDD) systems, Universal Mobile Telecommunication System (UMTS), Worldwide Interoperability for Microwave Access (WiMAX) communication systems, and future 6G communication systems, etc.

[0177] The following example uses a scenario where the embodiments of this application can be applied to WLAN. It should be understood that WLAN has evolved from the 802.11a / g standard to 802.11n, 802.11ac, 802.11ax, and the currently discussed 802.11be. Among them, 802.11n can also be called high throughput (HT); 802.11ac can also be called very high throughput (VHT); 802.11ax can also be called high efficient (HE) or Wi-Fi 6; 802.11be can also be called extremely high throughput (EHT) or (Wi-Fi 7), while standards before HT, such as 802.11a / b / g, are collectively referred to as non-high throughput (Non-HT).

[0178] See Figure 4 , Figure 4 This is a network architecture diagram of a WLAN provided in an embodiment of this application. Figure 4Taking a WLAN comprising one access point (AP) and two stations (STAs) as an example, the STA associated with the AP can receive and send wireless frames to the AP. Furthermore, this embodiment also applies to communication between APs; for example, APs can communicate with each other through a distributed system (DS). This embodiment also applies to communication between STAs. It should be understood that... Figure 4 The number of APs and STAs listed is just an example; there could be more or fewer.

[0179] Access points are points through which terminal devices (such as mobile phones) access wired (or wireless) networks. They are primarily deployed in homes, buildings, and campuses, with a typical coverage radius of tens to hundreds of meters. They can also be deployed outdoors. An access point acts as a bridge between wired and wireless networks, connecting various wireless network clients and then connecting the wireless network to the Ethernet. Specifically, access points can be terminal devices (such as mobile phones) or network devices (such as routers) with Wi-Fi chips. Access points can be devices that support the 802.11be standard. They can also be devices that support various wireless local area networks (WLAN) standards within the 802.11 family, including 802.11ax, 802.11ac, 802.11n, 802.11g, 802.11b, 802.11a, and 802.11be next-generation. The access point in this application can be a high-efficiency (HE) AP or an extremely high-throughput (EHT) AP, or it can be an access point that is compatible with a future generation of Wi-Fi standards.

[0180] The STA involved in the embodiments of this application can be various user terminals, user equipment, access devices, subscriber stations, subscriber units, mobile stations, user agents, user equipment, or other names with wireless communication functions. The user terminal can include various handheld devices, vehicle-mounted devices, wearable devices, computing devices, or other processing devices connected to a wireless modem with wireless communication functions, as well as various forms of user equipment (UE), mobile station (MS), terminal, terminal equipment, portable communication devices, handheld devices, portable computing devices, entertainment devices, gaming devices or systems, global positioning system devices, or any other suitable device configured for network communication via wireless media. For example, the STA can be a router, switch, and bridge, etc. Here, for ease of description, the devices mentioned above are collectively referred to as a site or STA.

[0181] The AP and STA involved in the embodiments of this application can be APs and STAs that comply with the IEEE 802.11 system standard. An AP is a device deployed in a wireless communication network to provide wireless communication functions for its associated STAs. The AP can serve as the hub of the communication system and is typically a network-side product that supports the MAC and PHY of the 802.11 system standard. Examples include base stations, routers, gateways, repeaters, communication servers, switches, or bridges. The base station can include various forms of macro base stations, micro base stations, repeater stations, etc. For ease of description, the devices mentioned above are collectively referred to as APs. STAs are typically terminal products that support the media access control (MAC) and physical layer (PHY) of the 802.11 system standard, such as mobile phones and laptops.

[0182] The detection frame transmission method provided in this application can be applied to a wireless communication system. This wireless communication system can be a wireless local area network (WLAN) or a cellular network. The method can be implemented by a communication device within the wireless communication system, or by a chip or processor within that device. This communication device can be a wireless communication device that supports parallel transmission across multiple links, for example, a multi-link device or a multi-band device. Compared to devices that only support single-link transmission, multi-link devices have higher transmission efficiency and higher throughput. A multi-link device includes one or more affiliated STAs, each of which is a logical station and can operate on a single link. The affiliated STA can be an access point (AP) or a non-access point station (non-AP STA). For ease of description, this application refers to multi-link devices belonging to AP sites as multi-link APs or multi-link AP devices or AP multi-link devices, and multi-link devices belonging to non-AP STA sites as multi-link STAs or multi-link STA devices or STA multi-link devices.

[0183] Furthermore, the technical solutions provided in this application are applicable to various system architectures. The network architectures and business scenarios described in this application are for the purpose of more clearly illustrating the technical solutions of this application and do not constitute a limitation on the technical solutions provided in this application. As those skilled in the art will understand, with the evolution of network architectures and the emergence of new business scenarios, the technical solutions provided in this application are also applicable to similar technical problems.

[0184] Optional, Figure 4 The wireless access points, sites, etc., can be implemented by a single device, multiple devices working together, or a functional module within a single device. This application does not specifically limit this. It is understood that the above functions can be network elements in hardware devices, software functions running on dedicated hardware, or virtualization functions instantiated on a platform (e.g., a cloud platform).

[0185] For example, Figure 4 Each device in the system can be accessed via Figure 5 This is achieved through the communication device 500. Figure 5The diagram shows a hardware structure of a communication device applicable to embodiments of this application. The communication device 500 includes at least one processor 501, a communication line 502, a memory 503, and at least one communication interface 504.

[0186] The processor 501 may be a general-purpose central processing unit (CPU), a microprocessor, an application-specific integrated circuit (ASIC), or one or more integrated circuits used to control the execution of the program of the present application.

[0187] Communication line 502 may include a path for transmitting information between the aforementioned components.

[0188] Communication interface 504 is any transceiver-like device (such as an antenna) used to communicate with other devices or communication networks, such as Ethernet, RAN, wireless local area networks (WLAN), etc.

[0189] The memory 503 may be a read-only memory (ROM) or other type of static storage device capable of storing static information and instructions, random access memory (RAM) or other type of dynamic storage device capable of storing information and instructions, or electrically erasable programmable read-only memory (EEPROM), compact disc read-only memory (CD-ROM) or other optical disc storage, optical disc storage (including compressed optical discs, laser discs, optical discs, digital universal optical discs, Blu-ray discs, etc.), magnetic disk storage media or other magnetic storage devices, or any other medium capable of carrying or storing desired program code in the form of instructions or data structures and accessible by a computer, but is not limited thereto. The memory may exist independently and be connected to the processor via communication line 502. The memory may also be integrated with the processor. The memory provided in this embodiment of the application is generally non-volatile. The memory 503 is used to store computer execution instructions for executing the scheme of this application and is controlled by the processor 501 for execution. The processor 501 is used to execute computer execution instructions stored in the memory 503, thereby implementing the method provided in the following embodiments of this application.

[0190] Optionally, the computer execution instructions in the embodiments of this application may also be referred to as application code, and the embodiments of this application do not specifically limit this.

[0191] In one possible implementation, processor 501 may include one or more CPUs, for example... Figure 5 CPU0 and CPU1 in the CPU.

[0192] In one possible implementation, the communication device 500 may include multiple processors, such as... Figure 5 Processors 501 and 507 are shown in the diagram. Each of these processors can be a single-core (single-CPU) processor or a multi-core (multi-CPU) processor. A processor here can refer to one or more devices, circuits, and / or processing cores used to process data (such as computer program instructions).

[0193] In one possible implementation, the communication device 500 may further include an output device 505 and an input device 506. The output device 505 communicates with the processor 501 and can display information in various ways. For example, the output device 505 may be a liquid crystal display (LCD), a light-emitting diode (LED) display device, a cathode ray tube (CRT) display device, or a projector, etc. The input device 506 communicates with the processor 501 and can receive user input in various ways. For example, the input device 506 may be a mouse, keyboard, touchscreen device, or sensing device, etc.

[0194] The aforementioned communication device 500 can be a general-purpose device or a dedicated device. In specific implementations, the communication device 500 can be a portable computer, a network server, a handheld digital assistant (PDA), a mobile phone, a tablet computer, a wireless terminal device, an embedded device, or something similar. Figure 5 Devices with similar structures. This application does not limit the type of communication device 500 to any particular embodiment.

[0195] When the communication device is powered on, the processor 501 can read the software program in the memory 503, interpret and execute the instructions of the software program, and process the data of the software program. When data needs to be transmitted wirelessly, the processor 501 performs baseband processing on the data to be transmitted and outputs the baseband signal to the radio frequency (RF) circuit. The RF circuit processes the baseband signal and transmits the RF signal outward in the form of electromagnetic waves through the antenna. When data is sent to the communication device, the RF circuit receives the RF signal through the antenna, converts the RF signal into a baseband signal, and outputs the baseband signal to the processor 501. The processor 501 converts the baseband signal into data and processes the data.

[0196] In another implementation, the radio frequency circuit and antenna can be set up independently of the processor that performs baseband processing. For example, in a distributed scenario, the radio frequency circuit and antenna can be arranged in a remote manner, independent of the communication device.

[0197] The technical solutions provided by the embodiments of this application are described below with reference to the accompanying drawings. It can be understood that the first device can be... Figure 4 In the AP, the second device can be Figure 4 The AP or STA in the middle; or, the first device can be the AP or STA in the middle. Figure 4 In the STA, the second device can also be Figure 4 The term STA in this context is not limited to any particular device. The following example, where the first device is an AP and the second device is a STA, illustrates the technical solution provided in this application.

[0198] See Figure 6 , Figure 6 This is a flowchart illustrating a detection frame transmission method provided in an embodiment of this application. Figure 6 As shown, the method includes, but is not limited to, the following steps:

[0199] 601. A first device generates a probe frame; the probe frame includes a first field, the first field including a predefined first sequence, wherein the first sequence includes a sequence obtained by modulating a second sequence using at least one of the following modulation methods: quadrature phase shift keying (QPSK), quadrature amplitude modulation (QAM), 64-QAM, 256-QAM, 1024-QAM, and 4096-QAM.

[0200] The frame structure of the probe frame can be referenced from Figure 2 or Figure 7 This will not be elaborated upon here.

[0201] Optionally, the first field can be Figure 2The HE-LTF field; or, the first field can be the HE-LTF field; Figure 7 The LTF field in this context is not limited here. For example, in 802.11ax, the first field is... Figure 2 The HE-LTF field in 802.11be; in 802.11be, the first field is... Figure 7 The LTF field in the text.

[0202] The first sequence includes a sequence obtained by modulating the second sequence using at least one of the following modulation methods: the first sequence includes at least one of the following: a sequence obtained by modulating the second sequence using QPSK, a sequence obtained by modulating the second sequence using 16-QAM, a sequence obtained by modulating the second sequence using 64-QAM, a sequence obtained by modulating the second sequence using 256-QAM, a sequence obtained by modulating the second sequence using 1024-QAM, or a sequence obtained by modulating the second sequence using 4096-QAM.

[0203] Optionally, the second sequence can be an HE-LTF sequence in 802.11ax with an 80MHz bandwidth 4x mode, or an EHT-LTF sequence in 802.11be with an 80MHz bandwidth 4x mode. The “80MHz bandwidth” mentioned in this application can refer to a bandwidth of 80MHz.

[0204] For example, in 802.11ax, the HE-LTF sequence is:

[0205] HE-LTF 4x(-500∶500)＝[1，-1，-1，-1，-1，1，-1，-1，1，-1，-1，-1，1，1，-1，-1，-1，1，-1，-1，1，-1，1，1，1，-1，1，-1，1，-1，-1，-1，-1，1，1，1，1，1，-1，-1，1，-1，1，-1，-1，-1，1，1，-1，-1，1，-1，-1，-1，1，1，1，-1，-1，1，1，-1，-1，1，-1，1，1，-1，1，-1，1，1，1，-1，1，-1，1，1，1，1，1，1，-1，-1，-1，1，-1，1，-1，-1，-1，1，-1，-1，1，1，1，1，1，1，-1，1，-1，1，1，-1，1，-1，1，-1，1，-1，1，-1，-1，1，1，1，1，-1，-1，-1，-1，-1，-1，-1，-1，1，-1，-1，1，-1，-1，1，1，1，-1，1，-1，-1，-1，1，1，1，-1，1，1，-1，-1，1，-1，-1，-1，1，1，1，1，-1，1，1，1，1，1，1，-1，1，-1，-1，1，-1，1，-1，-1，1，1，1，1，1，-1，1，1，-1，-1，1，1，1，-1，1，1，-1，1，1，-1，-1，1，1，-1，-1，-1，-1，1，1，1，1，1，-1，1，1，1，1，1，-1，1，-1，1，-1，-1，1，-1，-1，-1，-1，-1，1，-1，-1，-1，1，1，-1，1，-1，1，-1，-1，-1，-1，-1，1，1，1，1，-1，1，-1，-1，1，1，-1，-1，-1，1，1，1，1，1，-1，1，-1，1，-1，-1，1，1，1，-1，1，1，1，1，1，-1，1，1，-1，1，-1，1，-1，-1，-1，1，-1，1，-1，-1，-1，-1，-1，1，1，1，1，-1，-1，1，1，-1，-1，1，-1，-1，1，-1，-1，-1，1，1，-1，-1，1，-1，-1，-1，-1，-1，1，1，-1，1，-1，1，1，-1，1，-1，-1，-1，-1，-1，-1，1，-1，-1，-1，-1，1，1，1，-1，1，1，-1，-1，1，-1，-1，-1，1，1，1，-1，1，-1，1，-1，-1，-1，1，-1，1，-1，1，-1，-1，-1，1，-1，-1，1，-1，1，1，-1，-1，-1，1，1，-1，-1，-1，-1，1，-1，1，1，-1，1，-1，1，1，1，1，1，1，-1，-1，1，-1，-1，-1，1，-1，1，-1，-1，-1，1，1，1，1，1，1，-1，1，-1，1，1，1，-1，1，-1，1，1，-1，1，-1，-1，1，1，-1，-1，1，1，1，-1，-1，-1，1，-1，-1，1，1，-1，-1，-1，1，-1，1，-1，-1，1，1，1，1，1，-1，-1，-1，-1，1，-1，1，-1，1，1，1，-1，1，-1，-1，1，-1，-1，-1，1，1，-1，-1，-1，1，-1，-1，1，-1，-1，-1，-1，1，-1，1，1，-1，-1，-1，1，-1，-1，0，0，0，0，0，-1，-1，1，-1，1，1，1，1，1，1，-1，-1，-1，-1，1，-1，-1，1，-1，-1，-1，1，1，-1，-1，-1，1，-1，-1，1，-1，1，1，1，-1，1，-1，1，-1，-1，-1，-1，1，1，1，1，1，-1，-1，1，-1，1，-1，-1，-1，1，1，-1，-1，1，-1，-1，-1，1，1，1，-1，-1，1，1，-1，-1，1，-1，1，1，-1，1，-1，1，1，1，-1，1，-1，1，1，1，1，1，1，-1，-1，-1，1，-1，1，-1，-1，-1，1，-1，-1，1，1，1，1，1，1，-1，1，-1，1，1，-1，1，-1，-1，-1，-1，1，1，-1，-1，-1，1，1，-1，1，-1，-1，1，-1，-1，-1，1，-1，1，-1，1，-1，-1，-1，1，-1，1，-1，1，1，1，-1，-1，-1，1，-1，-1，1，1，-1，1，1，1，-1，-1，-1，-1，1，-1，-1，-1，-1，-1，-1，1，-1，1，1，-1，1，-1，1，1，-1，-1，-1，-1，-1，1，-1，-1，1，1，-1，-1，-1，1，-1，-1，1，-1，-1，1，1，-1，-1，1，1，1，1，-1，-1，-1，-1，-1，1，-1，-1，-1，-1，-1，1，-1，1，-1，1，1，-1，1，1，1，1，1，-1，1，1，1，-1，-1，1，-1，1，-1，1，1，1，1，1，-1，-1，-1，1，1，-1，-1，-1，-1，-1，-1，-1，-1，1，1，1，1，1，-1，1，-1，1，-1，-1，1，1，1，-1，1，1，1，1，1，-1，1，1，-1，1，-1，1，-1，-1，-1, -1, -1, 1, -1, -1, -1, -1, -1, 1, 1, 1, -1, -1, 1, -1, -1, -1, 1, -1, -1, -1, 1, -1, -1, -1, -1, -1, -1, -1, ... -1, 1, -1, -1, -1, -1, 1, 1, -1, 1, 1, -1, -1, 1, -1, -1, -1, 1, 1, -1, 1, -1, -1, -1, 1, 1, -1, 1, 1, -1, 1, 1, 1, 1, -1, -1, -1, -1, 1, -1, 1, -1, 1, -1, 1 ,-1,-1,1,-1,1,-1,-1,-1,-1,-1,-1,-1,1,1,-1,1,1,-1,1,-1,1,1,-1,-1,-1,-1,-1,-1,-1,1,-1,1,-1,1,-1,-1,-1,-1,1,-1,-1,1,-1,-1,-1,1,-1,1,-1,-1,-1,1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,- 1,1,1,1,-1,1,1,-1,-1,1,1,1,-1,1,-1,1,1,-1,-1,-1,-1,-1,1,1,1,1,-1,1 , -1, 1, -1, -1, -1, 1, -1, 1, 1, -1, 1, 1, 1, -1, -1, 1, 1, 1, -1, 1, 1, -1, 1, 1, 1, 1, -1]. HE-LTF, 4x The expression (-500∶500) means that the values ​​on each subcarrier in the sequence numbered -500 to 500 are the values ​​in the HE-LTF sequence. It can be seen that the components of the second sequence are all +1, 0 or -1. Under BPSK modulation, the HE-LTF sequence has low distortion and low PAPR, so the channel quality of the link under BPSK modulation can be accurately measured.

[0206] For example, in 802.11be, the EHT-LTF sequence is:

[0207] EHT-LTF 4x(-500∶500)＝[1，-1，-1，-1，-1，1，-1，-1，1，-1，-1，-1，1，1，-1，-1，-1，1，-1，-1，1，-1，1，1，1，-1，1，-1，1，-1，-1，-1，-1，1，1，1，1，1，-1，-1，1，-1，1，-1，-1，-1，1，1，-1，-1，1，-1，-1，-1，1，1，1，-1，-1，1，1，-1，-1，1，-1，1，1，-1，1，-1，1，1，1，-1，1，-1，1，1，1，1，1，1，-1，-1，-1，1，-1，1，-1，-1，-1，1，-1，-1，1，1，1，1，1，1，-1，1，-1，1，1，-1，1，-1，1，-1，1，-1，1，-1，-1，1，1，1，1，-1，-1，-1，-1，-1，-1，-1，-1，1，-1，-1，1，-1，-1，1，1，1，-1，1，-1，-1，-1，1，1，1，-1，1，1，-1，-1，1，-1，-1，-1，1，1，1，1，-1，1，1，1，1，1，1，-1，1，-1，-1，1，-1，1，-1，-1，1，1，1，1，1，-1，1，1，-1，-1，1，1，1，-1，1，1，-1，1，1，-1，-1，1，1，-1，-1，-1，-1，1，1，1，1，1，-1，1，1，1，1，1，-1，1，-1，1，-1，-1，1，-1，-1，-1，-1，-1，1，-1，-1，-1，1，1，-1，1，-1，1，-1，-1，-1，-1，-1，1，1，1，1，-1，1，-1，-1，1，1，-1，-1，-1，1，1，1，1，1，-1，1，-1，1，-1，-1，1，1，1，-1，1，1，1，1，1，-1，1，1，-1，1，-1，1，-1，-1，-1，-1，-1，1，-1，-1，-1，-1，-1，1，1，1，1，-1，-1，1，1，-1，-1，1，-1，-1，1，-1，-1，-1，1，1，-1，-1，1，-1，-1，-1，-1，-1，1，1，-1，1，-1，1，1，-1，1，-1，-1，-1，-1，-1，-1，1，-1，-1，-1，-1，1，1，1，-1，1，1，-1，-1，1，-1，-1，-1，1，1，1，-1，1，-1，1，-1，-1，-1，1，-1，1，-1，1，-1，-1，-1，1，-1，-1，1，-1，1，1，-1，-1，-1，1，1，-1，-1，-1，-1，1，-1，1，1，-1，1，-1，1，1，1，1，1，1，-1，-1，1，-1，-1，-1，1，-1，1，-1，-1，-1，1，1，1，1，1，1，-1，1，-1，1，1，1，-1，1，-1，1，1，-1，1，-1，-1，1，1，-1，-1，1，1，1，-1，-1，-1，1，-1，-1，1，1，-1，-1，-1，1，-1，1，-1，-1，1，1，1，1，1，-1，-1，-1，-1，1，-1，1，-1，1，1，1，-1，1，-1，-1，1，-1，-1，-1，1，1，-1，-1，-1，1，-1，-1，1，-1，-1，-1，-1，1，-1，1，1，-1，-1，-1，1，-1，-1，0，0，0，0，0，-1，-1，1，-1，1，1，1，1，1，1，-1，-1，-1，-1，1，-1，-1，1，-1，-1，-1，1，1，-1，-1，-1，1，-1，-1，1，-1，1，1，1，-1，1，-1，1，-1，-1，-1，-1，1，1，1，1，1，-1，-1，1，-1，1，-1，-1，-1，1，1，-1，-1，1，-1，-1，-1，1，1，1，-1，-1，1，1，-1，-1，1，-1，1，1，-1，1，-1，1，1，1，-1，1，-1，1，1，1，1，1，1，-1，-1，-1，1，-1，1，-1，-1，-1，1，-1，-1，1，1，1，1，1，1，-1，1，-1，1，1，-1，1，-1，-1，-1，-1，1，1，-1，-1，-1，1，1，-1，1，-1，-1，1，-1，-1，-1，1，-1，1，-1，1，-1，-1，-1，1，-1，1，-1，1，1，1，-1，-1，-1，1，-1，-1，1，1，-1，1，1，1，-1，-1，-1，-1，1，-1，-1，-1，-1，-1，-1，1，-1，1，1，-1，1，-1，1，1，-1，-1，-1，-1，-1，1，-1，-1，1，1，-1，-1，-1，1，-1，-1，1，-1，-1，1，1，-1，-1，1，1，1，1，-1，-1，-1，-1，-1，1，-1，-1，-1，-1，-1，1，-1，1，-1，1，1，-1，1，1，1，1，1，-1，1，1，1，-1，-1，1，-1，1，-1，1，1，1，1，1，-1，-1，-1，1，1，-1，-1，-1，-1，-1，-1，-1，-1，1，1，1，1，1，-1，1，-1，1，-1，-1，1，1，1，-1，1，1，1，1，1，-1，1，1，-1，1，-1，1，-1，-1, -1, -1, -1, 1, -1, -1, -1, -1, -1, 1, 1, 1, -1, -1, 1, -1, -1, -1, 1, -1, -1, -1, 1, -1, -1, -1, -1, -1, -1, -1, 1, -1, 1, -1, 1, -1, 1, -1, -1, -1, -1, -1, - 1, -1, 1, -1, -1, -1, -1, 1, 1, -1, 1, 1, -1, -1, -1, -1, 1, 1, -1, 1, -1, -1, -1, 1, 1, -1, 1, 1, -1, 1, 1, -1, 1, 1, 1, 1, -1, -1, -1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, -1, 1, -1, 1, -1, -1, -1, -1, -1, 1, 1, -1, 1, 1, 1, -1, 1, 1, -1, -1, -1, -1, -1, -1, 1, -1, 1, -1, 1, -1, 1, -1, -1, 1, -1, 1, -1, -1, 1, -1, -1, 1, -1, -1, 1, -1, -1, 1, -1, -1, -1,1,1,1,-1,1,1,-1,-1,1,1,1,-1,1,-1,1,1,-1,-1,-1,-1,-1,1,1,1,1,-1,1 , -1, 1, -1, -1, -1, 1, -1, 1, 1, -1, 1, 1, 1, -1, -1, 1, 1, 1, -1, 1, 1, -1, 1, 1, 1, 1, -1]. EHT-LTF, 4x The expression (-500∶500) means that the values ​​on each subcarrier in the sequence from -500 to 500 are sequentially the values ​​in the EHT-LTF sequence. It can be seen that the components of the second sequence are all +1, 0, or -1. Under BPSK modulation, the EHT-LTF sequence has low distortion and low PAPR, thus allowing for accurate measurement of the channel quality of the link under BPSK modulation.

[0208] Optionally, the first sequence can be implemented using at least one of the following methods 1-6, or the first sequence can be implemented using at least one of the following methods 7-12. It is understood that, for method 1 or method 7, the first sequence is a sequence obtained by modulating the second sequence using QPSK; for method 2 or method 8, the first sequence is a sequence obtained by modulating the second sequence using 16-QAM; for method 3 or method 9, the first sequence is a sequence obtained by modulating the second sequence using 64-QAM; for method 4 or method 10, the first sequence is a sequence obtained by modulating the second sequence using 256-QAM; for method 5 or method 11, the first sequence is a sequence obtained by modulating the second sequence using 1024-QAM; and for method 6 or method 12, the first sequence is a sequence obtained by modulating the second sequence using 4096-QAM. It should be noted that the second sequence involved in methods 1 to 6 is the HE-LTF sequence in the 80MHz bandwidth 4x mode of 802.11ax, and the second sequence involved in methods 7 to 12 is the EHT-LTF sequence in the 80MHz bandwidth 4x mode of 802.11be.

[0209] Method 1: The first sequence satisfies the following formula (1):

[0210] s i =[a0, c i ,0,0,0,0,0,(-1j)*a1] (1);

[0211] Where i is an integer greater than or equal to 1 and less than or equal to 7. This implements a sequence under QPSK modulation, enabling accurate measurement of the channel quality of a communication link under QPSK modulation when using this sequence to measure the channel quality.

[0212] Method 2: The first sequence satisfies the following formula (2):

[0213]

[0214] Among them, s k1 =[a0, c k1 ,0,0,0,0,0,(-1j)*a1];s k2 =[a0, c k2 ,0,0,0,0,0,(-1j)*a1].

[0215] Where k1 is 1 and k2 is 7; or, k1 is 4 and k2 is 5 or 6; or, k1 is 5 and k2 is 1 or 2. This realizes the sequence under 16-QAM modulation, so that when using this sequence to measure the channel quality of the communication link, the channel quality of the communication link under 16-QAM modulation can be accurately measured.

[0216] Method 3: The first sequence satisfies the following formula (3):

[0217]

[0218] Among them, s k3 =[a0, c k3 ,0,0,0,0,0,(-1j)*a1];s k4 =[a0, c k4 ,0,0,0,0,0,(-1j)*a1];s k5 =[a0, c k5 ,0,0,0,0,0,(-1j)*a1].

[0219] Where k3 is 1, k4 is 6, and k5 is 7; or, k3 is 1, k4 is 7, and k5 is 5 or 6; or, k3 is 2, k4 is 7, and k5 is 6 or 7; or, k3 is 3, k4 is 5, and k5 is 6; or, k3 is 3, k4 is 5, and k5 is 7; or, k3 is 3, k4 is 6, and k5 is 5 or 6; or, k3 is 3, k4 is 7, and k5 is 1, 2, 3, or 4; or, k3 is 4, k4 is 4, and k5 is 7; or, k3 is 4, k4 is 5, and k5 is 3. 4 or 5; or, k3 is 4, k4 is 6, k5 is 1, 2, 3 or 4; or, k3 is 5, k4 is 1, k5 is 3 or 4; or, k3 is 5, k4 is 1, k5 is 5; or, k3 is 5, k4 is 2, k5 is 4, 5 or 6; or, k3 is 5, k4 is 3, k5 is 1, 2, 3 or 4; or, k3 is 5, k4 is 4, k5 is 1 or 2; or, k3 is 6, k4 is 1, k5 is 1 or 2; or, k3 is 6, k4 is 2, k5 is 1, 2 or 3. This realizes a sequence under 64-QAM modulation, enabling accurate measurement of the channel quality of a communication link under 64-QAM modulation when using this sequence to measure the channel quality.

[0220] Method 4: The first sequence satisfies the following formula (4):

[0221]

[0222] Among them, s k6 =[a0, c k6 ,0,0,0,0,0,(-1j)*a1];s k7 =[a0, c k7 ,0,0,0,0,0,(-1j)*a1];s k8 =[a0, c k8 ,0,0,0,0,0,(-1j)*a1];s k9 =[a0, c k9,0,0,0,0,0,(-1j)*a1].

[0223] Where k6 is 1, k7 is 7, k8 is 4, and k9 is 7; or, k6 is 1, k7 is 7, k8 is 6, and k9 is 3; or, k6 is 2, k7 is 7, k8 is 7, and k9 is 4; or, k6 is 3, k7 is 5, k8 is 7, and k9 is 4; or, k6 is 3, k7 is 6, k8 is 5, and k9 is 5; or, k6 is 3, k7 is 7, k8 is 1, and k9 is 5; or, k6 is 3, k7 is 7, k8 is 2, and k9 is 6; or, k6 is 3, k7 is 7, k8 is 3, and k9 is 4 Alternatively, k6 is 4, k7 is 4, k8 is 6, and k9 is 7; or k6 is 4, k7 is 6, k8 is 1, and k9 is 6; or k6 is 4, k7 is 6, k8 is 4, and k9 is 3; or k6 is 5, k7 is 1, k8 is 1, and k9 is 7; or k6 is 5, k7 is 2, k8 is 6, and k9 is 2; or k6 is 5, k7 is 4, k8 is 1, and k9 is 1; or k6 is 5, k7 is 4, k8 is 2, and k9 is 3; or k6 is 6, k7 is 1, k8 is 1, and k9 is 1. This achieves a sequence under 256-QAM modulation, enabling accurate measurement of the channel quality of a communication link under 256-QAM modulation when using this sequence to measure the channel quality.

[0224] Method 5: The first sequence satisfies the following formula (5):

[0225]

[0226] Among them, s k10 =[a0, c k10 ,0,0,0,0,0,(-1j)*a1];s k11 =[a0, c k11 ,0,0,0,0,0,(-1j)*a1];s k12 =[a0, c k12 ,0,0,0,0,0,(-1j)*a1];s k13 =[a0, c k13 ,0,0,0,0,0,(-1j)*a1];s k14 =[a0, c k14 ,0,0,0,0,0,(-1j)*a1].

[0227] Where k10 is 1, k11 is 7, k12 is 6, k13 is 1, and k14 is 5; or, k10 is 2, k11 is 7, k12 is 5, k13 is 7, and k14 is 5; or, k10 is 6, k11 is 1, k12 is 2, k13 is 4, and k14 is 4; or, k10 is 4, k11 is 6, k12 is 4, k13 is 1, and k14 is 6. Alternatively, k10 is 6, k11 is 2, k12 is 1, k13 is 4, and k14 is 5; or k10 is 3, k11 is 6, k12 is 7, k13 is 1, and k14 is 2; or k10 is 5, k11 is 3, k12 is 1, k13 is 6, and k14 is 1; or k10 is 4, k11 is 6, k12 is 2, k13 is 6, and k14 is 6. This achieves a sequence under 1024-QAM modulation, enabling accurate measurement of the channel quality of communication links under 1024-QAM modulation when using this sequence to measure the channel quality.

[0228] Method 6: The first sequence satisfies the following formula (6):

[0229]

[0230] Among them, s k15 =[a0, c k1 ,0,0,0,0,0,(-1j)*a1];s k16 =[a0, c k16 ,0,0,0,0,0,(-1j)*a1];s k17 =[a0, c k1 ,0,0,0,0,0,(-1j)*a1];s k18 =[a0, c k18 ,0,0,0,0,0,(-1j)*a1];s k19 =[a0, c k19 ,0,0,0,0,0,(-1j)*a1];s k2 =[a0, c k20 ,0,0,0,0,0,(-1j)*a1].

[0231] Where k15 is 5, k16 is 2, k17 is 4, k18 is 7, k19 is 2, and k20 is 5; or, k15 is 5, k16 is 2, k17 is 5, k18 is 1, k19 is 7, and k20 is 2; or, k15 is 6, k16 is 2, k17 is 2, k18 is 3, k19 is 7, and k20 is 5; or, k15 is 3, k16 is 6, k17 is 6, k18 is 4, k19 is 5, and k20 is 4. Alternatively, k15 is 4, k16 is 7, k17 is 2, k18 is 2, k19 is 3, and k20 is 2; or k15 is 6, k16 is 1, k17 is 2, k18 is 3, k19 is 5, and k20 is 4; or k15 is 2, k16 is 7, k17 is 7, k18 is 3, k19 is 6, and k20 is 3; or k15 is 1, k16 is 7, k17 is 5, k18 is 5, k19 is 4, and k20 is 2. This achieves a sequence under 4096-QAM modulation, enabling accurate measurement of the channel quality of communication links under 4096-QAM modulation when using this sequence to measure the channel quality.

[0232] Method 7: The first sequence satisfies the following formula (7):

[0233] p u =[b0, d u ,0,0,0,0,0,(-1j)*b1] (7);

[0234] Where u is an integer greater than or equal to 1 and less than or equal to 5. This implements a sequence under QPSK modulation, enabling accurate measurement of the channel quality of a communication link under QPSK modulation when using this sequence to measure the channel quality.

[0235] Method 8: The first sequence satisfies the following formula (8):

[0236]

[0237] Where, p t1 =[b0, d t1 ,0,0,0,0,0,(-1j)*b1];p t2 =[b0, d t2 ,0,0,0,0,0,(-1j)*b1].

[0238] Where t1 is 5 and t2 is 1, 2, 3, 4 or 5; or t1 is 1 and t2 is 5; or t1 is 4 and t2 is 5. This realizes a sequence under 16-QAM modulation, which enables accurate measurement of the channel quality of a communication link under 16-QAM modulation when using this sequence to measure the channel quality of the communication link.

[0239] Method 9: The first sequence satisfies the following formula (9):

[0240]

[0241] Where, p t3 =[b0, d t3 ,0,0,0,0,0,(-U)*b1];p t4 =[b0, d t4 ,0,0,0,0,0,(-1j)*b1];p t5 =[b0, d t5 ,0,0,0,0,0,(-1j)*b1].

[0242] Where t3 is 5, t4 is 5, and t5 is 1, 2, 3, 4, or 5; or, t3 is 5, t4 is 1, and t5 is 5; or, t3 is 5, t4 is 1, and t5 is 1. This achieves a sequence under 64-QAM modulation, enabling accurate measurement of the channel quality of a communication link under 64-QAM modulation when using this sequence to measure the channel quality.

[0243] Method 10: The first sequence satisfies the following formula (10):

[0244]

[0245] Where, p t6 =[b0, d t6 ,0,0,0,0,0,(-1j)*b1];p t7 =[b0, d t7 ,0,0,0,0,0,(-1j)*b1];p t8 =[b0, d t8 ,0,0,0,0,0,(-1j)*b1];p t9 =[b0, d t9 ,0,0,0,0,0,(-1j)*b1].

[0246] Where t6 is 5, t7 is 5, t8 is 5, and t9 is 1, 2, 3, or 4; or, t6 is 5, t7 is 5, t8 is 1, and t9 is 1, 4, or 5; or, t6 is 5, t7 is 1, t8 is 5, and t9 is 5. This realizes a sequence under 256-QAM modulation, enabling accurate measurement of the channel quality of communication links under 256-QAM modulation when using this sequence to measure the channel quality of communication links.

[0247] Method 11: The first sequence satisfies the following formula (11):

[0248]

[0249] Where, p t10 =[b0, d t10 ,0,0,0,0,0,(-1j)*b1];p t11 =[b0, d t11 ,0,0,0,0,0,(-1j)*b1];p t1 =[b0, d t12 ,0,0,0,0,0,(-1j)*b1];p t13 =[b0, d t1 ,0,0,0,0,0,(-1j)*b1];p t14 =[b0, d t14 ,0,0,0,0,0,(-1j)*b1].

[0250] Where t10 is 5, t11 is 5, t12 is 5, t13 is 1, and t14 is 2 or 4; or, t10 is 5, t11 is 5, t12 is 5, t13 is 4, and t14 is 1 or 5; or, t10 is 5, t11 is 5, t12 is 1, t13 is 5, and t14 is 1 or 5; or, t10 is 5, t11 is 5, t12 is 1, t13 is 5, and t14 is 5; or, t10 is 5, t11 is 5, t12 is 5, t13 is 2, and t14 is 5; or, t10 is 5, t11 is 5, t12 is 5, t13 is 1, and t14 is 3. This realizes a sequence under 1024-QAM modulation, enabling accurate measurement of the channel quality of a communication link under 1024-QAM modulation when using this sequence to measure the channel quality.

[0251] Method 12: The first sequence satisfies the following formula (12):

[0252]

[0253] Where, p t1 =[b0, d t1 ,0,0,0,0,0,(-1j)*b1];p t16 =[b0, d t16 ,0,0,0,0,0,(-1j)*b1];p t17 =[b0, d t17 ,0,0,0,0,0,(-1j)*b1];p t18 =[b0, d t1 ,0,0,0,0,0,(-1j)*b1];p t1 =[b0, d t19 ,0,0,0,0,0,(-1j)*b1];p t20 =[b0, d t20,0,0,0,0,0,(-1j)*b1].

[0254] Where t15 is 5, t16 is 5, t17 is 5, t18 is 1, t19 is 2, and t20 is 5; or, t15 is 5, t16 is 5, t17 is 5, t18 is 1, t19 is 1, and t20 is 3; or, t15 is 5, t16 is 5, t17 is 1, t18 is 5, t19 is 5, and t20 is 1; or, t15 is 5, t16 is 5, t17 is 5, t18 is 5, t19 is 3, and t20 is 3. Alternatively, t15 is 5, t16 is 5, t17 is 5, t18 is 1, t19 is 1, and t20 is 2; or t15 is 5, t16 is 5, t17 is 5, t18 is 1, t19 is 4, and t20 is 1; or t15 is 5, t16 is 5, t17 is 5, t18 is 4, t19 is 5, and t20 is 1; or t15 is 5, t16 is 5, t17 is 5, t18 is 1, t19 is 4, and t20 is 5. This achieves a sequence under 4096-QAM modulation, enabling accurate measurement of the channel quality of a communication link under 4096-QAM modulation when using this sequence to measure the channel quality.

[0255] Optionally, in methods 1-6, a0 and a1 are subsequences in the HE-LTF sequence, and j is the imaginary unit. For example, a0 is the 1st to 489th element in the HE-LTF sequence, and a1 is the 504th to 1001st element in the HE-LTF sequence. This achieves the generation of the first sequence based on the HE-LTF sequence in the 80MHz bandwidth 4x mode of 802.11ax, resulting in a low PAPR for the first sequence.

[0256] In methods 1-6, c1 = [1j, 1j, 1j, -1j, -1j, -1j, 1j, 1j, -1j]; c2 = [-1, -1, -1, -1j, -1j, -1j, 1j, 1j, -1j]; c3 = [-1, -1, -1, 1, 1, -1j, 1j, 1j, -1j]; c4 = [-1, -1, -1, 1, 1, 1, 1j, 1j, -1j]; c5 = [-1, -1, -1, 1, 1, 1, 1, -1, 1j, -1j]; c6 = [-1, -1, -1, 1, 1, 1, 1, -1, -1j]; c7 = [-1, -1, -1, 1, 1, 1, -1, -1, 1]. That is, c i It refers to the 490th to 498th elements in the first sequence.

[0257] Optionally, in methods 7-12, b0 and b1 are subsequences in the EHT-LTF sequence, and j is the imaginary unit. For example, b0 is the 1st to 492nd element in the EHT-LTF sequence, and b1 is the 504th to 1001st element in the EHT-LTF sequence. This achieves the generation of the first sequence based on the EHT-LTF sequence in 802.11be 80MHz bandwidth 4x mode, resulting in a low PAPR for the first sequence.

[0258] In methods 7-12, d1 = [1j, 1j, 1j, -1j, 1j, 1j]; d2 = [-1, 1j, 1j, -1j, 1j]; d3 = [-1, -1, -1, -1j, 1j, 1j]; d4 = [-1, -1, -1, 1, -1, 1j]; d5 = [-1, -1, -1, 1, -1, -1]. That is, d u It refers to the 493rd to 498th elements in the first sequence.

[0259] Optionally, for method 1, let the second sequence s = HE - LTF 4x (-500∶500), the position is changed to pos, the first sequence is... Right now Specifically, when dividing the second sequence into multiple subsequences, the second sequence can be denoted as s = [a0, c, 0, 0, 0, 0, 0, a1], where c is the 490th to 498th element in the second sequence. For example, the first sequence is s1, which can be understood as obtaining s1 after transforming the 490th to 498th elements and the 504th to 1001st elements in s. As another example, the first sequence is s7, which can be understood as obtaining s7 after transforming the 504th to 1001st elements in s.

[0260] Furthermore, the first sequence involved in any of methods 2-6 can be understood as being generated based on the first sequence involved in method 1. For example, method 1 involves seven sequences obtained by modulating the second sequence using QPSK, namely s1-s7. In method 2, k1 is 1 and k2 is 7, i.e. This can be understood as: obtaining q1 through s1 and s7 in method 1. Similarly, in method 3, the case where k3 is 1, k4 is 6, and k5 is 7, i.e. This can be understood as: obtaining q2 through s1, s6, and s7 in the method.

[0261] Optionally, for method 7, let the second sequence p = EHT - LTF 4x (-500∶500), the position is changed to pos, the first sequence is... Right now The transformed positions occupy approximately 0.5 units of the second sequence length. Specifically, when dividing the second sequence into multiple subsequences, the second sequence can be denoted as p = [b0, d, 0, 0, 0, 0, 0, b1], where d represents the 493rd to 498th elements in the second sequence. For example, the first sequence is p1, which can be understood as p1 obtained by transforming the 493rd to 498th elements and the 504th to 1001st elements of p. Similarly, the first sequence is p5, which can be understood as p5 obtained by transforming the 504th to 1001st elements of p.

[0262] Furthermore, the first sequence involved in any of methods 8-12 can be understood as being generated based on the first sequence involved in method 1. For example, method 7 involves five sequences obtained by modulating the second sequence using QPSK, namely p1-p5. And in method 2, t1 is 5 and t2 is 1, i.e. This can be understood as: obtaining q6 through p1 and p5 in method 1. Similarly, in method 9, the case where t3 is 5, t4 is 5, and t5 is 1, i.e. This can be understood as: obtaining q7 through p5, p5, and p1 in the method.

[0263] 602. The second device receives the probe frame.

[0264] Accordingly, the first device sends a probe frame.

[0265] For example, step 602 may include: the second device receiving a probe frame from the first device. Correspondingly, the first device sends a probe frame to the second device.

[0266] 603. The second device performs channel measurements according to the first sequence.

[0267] As can be seen, in the above technical solution, the first device sends a probe frame. Since the probe frame includes a first field, which includes a predefined first sequence, and the first sequence includes a sequence obtained by modulating a second sequence using at least one of the following modulation methods: QPSK, 16-QAM, 64-QAM, 256-QAM, 1024-QAM, and 4096-QAM, the second device can perform channel measurements based on the first sequence after receiving the probe frame. Therefore, when performing channel measurements using the first sequence, the second device can measure the channel quality of the communication link under at least one of the modulation methods: QPSK, 16-QAM, 64-QAM, 256-QAM, 1024-QAM, and 4096-QAM, thus enriching the applicable scenarios for HE-LTF or EHT-LTF sequences. Meanwhile, because the PAPR of the first sequence is low, the distortion of the first sequence is small, which enables the second device to accurately measure the channel quality of the communication link under at least one of the modulation schemes of QPSK, 16-QAM, 64-QAM, 256-QAM, 1024-QAM, and 4096-QAM when using the first sequence for channel measurement.

[0268] In addition, based on Figure 3 For the 80MHz subcarrier design shown, this application defines the corresponding probe frame format. See [link to relevant documentation]. Figure 7 , Figure 7 This is a schematic diagram of the frame structure of a detection frame provided in an embodiment of this application. For example... Figure 7 As shown, the probe frame includes L-STF, L-LTF, L-SIG, repeated legacy short training field (RL-STF), universal signal (U-SIG) field, extremely high throughput signal (EHT-SIG) field, extremely high throughput short training field (EHT-STF), long training field (L-LTF), and PE field. The LTF fields include binary phase shift keying long training fields (BPSK LTFs) and 4q-QAM-LTF fields. It is understood that BPSK LTFs may include at least one extremely high throughput long training field (EHT-LTF) field. 4 q The -QAM-LTFs field can include at least 4 q -QAM-LTF field.

[0269] It should be noted that, in this application, when the second sequence is an EHT-LTF sequence in 802.11be 80MHz bandwidth 4x mode, the first sequence can be included in the 4q-QAM-LTFs field. For example, the sequence obtained by modulating the second sequence with 16-QAM can be included in the 4q-QAM-LTFs field. 2 In the -QAM-LTF field, the sequence obtained by modulating the second sequence with 64-QAM can be included in 4 3 -QAM-LTF field.

[0270] It should be noted that, in this application, the sum of the differences between the peak-to-average power ratio (PAPR) of the first subsequence corresponding to each RU in any sequence included in the first sequence and the PAPR of the corresponding RU in the second sequence is less than or equal to a preset threshold. An RU may include one of the following: a 26-tone RU, a 52-tone RU, a 106-tone RU, a 242-tone RU, a 484-tone RU, or a 996-tone RU. The first subsequence is the subsequence with the highest PAPR among the subsequences corresponding to an RU. For example, in the case of a transmission bandwidth of 80MHz, there are 36 26-tone RUs distributed across this bandwidth, and each 26-tone RU corresponds to a subsequence with one PAPR; the first subsequence is the subsequence with the highest PAPR among the 36 26-tone RUs. For example, with a transmission bandwidth of 80MHz, there are 18 52-tone RUs distributed across this bandwidth. Each 52-tone RU corresponds to a subsequence with a PAPR, and the first subsequence is the subsequence with the largest PAPR among the 18 52-tone RUs. It is understood that in this embodiment, an RU comprising K subcarriers is referred to as a K-tone RU. For example, a 26-tone RU refers to an RU comprising 26 subcarriers. That is, the concept of a K-tone RU is the same as the concept of a K-tone RU in the existing 802.11ax standard.

[0271] In addition, the preset threshold is a value predefined in the protocol, and this application does not impose any restrictions.

[0272] In this application, the sum of the differences between the PAPR of the first subsequence corresponding to each RU of at least one RU in any sequence included in the first sequence and the PAPR of the corresponding RU in the second sequence is less than or equal to a preset threshold. This means that the PAPR of the first subsequence corresponding to each RU of at least one RU in any sequence included in the first sequence is close to the PAPR of the corresponding RU in the second sequence. Because the second sequence can support channel measurement by AP or STA, and the transmit power efficiency of the second sequence is better, the transmit power efficiency of the first sequence whose PAPR is close to that of the second sequence is also better. That is, the first sequence whose PAPR is close to that of the second sequence can also better support channel measurement by AP or STA.

[0273] For example, let δ be the sum of the differences between the PAPR of the first subsequence corresponding to each RU of at least one RU in any sequence included in the first sequence and the PAPR of the corresponding RU in the second sequence. For method 1, we can let... Among them, PAPR s (x) is the PAPR corresponding to a RU in the second sequence. It can be the PAPR of the subsequence with the largest PAPR among the subsequences corresponding to the RU in any sequence included in the first sequence. For example, PAPR s (1) It can be the PAPR corresponding to the 26-tone RU of the second sequence. It can be the PAPR of the subsequence with the largest PAPR among the subsequences corresponding to the 26-tone RU in any sequence included in the first sequence; PAPR s (2) is the PAPR corresponding to the 52-tone RU of the second sequence. PAPR is the PAPR of the subsequence with the highest PAPR among the subsequences corresponding to the 52-tone RU in any sequence included in the first sequence; PAPR s (3) is the PAPR corresponding to the 106-tone RU of the second sequence. PAPR is the PAPR of the subsequence with the highest PAPR among the subsequences corresponding to the 106-tone RU in any sequence included in the first sequence; PAPR s (4) is the PAPR corresponding to the 242-tone RU of the second sequence. PAPR is the PAPR of the subsequence with the highest PAPR among the subsequences corresponding to the 242-tone RU in any sequence included in the first sequence; PAPR s (5) is the PAPR corresponding to the 484-tone RU of the second sequence. PAPR is the PAPR of the subsequence with the highest PAPR among the subsequences corresponding to the 484-tone RU in any sequence included in the first sequence; PAPR s (6) is the PAPR corresponding to the 996-tone RU of the second sequence. For any sequence included in the first sequence, the PAPR of the subsequence with the largest PAPR corresponding to the 996-tone RU is given. It is understandable that the above applies to PAPs(1)-PAPR. s (6) The description is merely an example; other situations may exist, which will not be elaborated upon here. It should be noted that PAPR... s (1)-PAPR s (6) should be the PAPR corresponding to different RUs in the second sequence. It is also the PAPR of the subsequence with the largest PAPR among the subsequences corresponding to different RUs in any sequence included in the first sequence, and PAP s (x) and When x takes the same value, the corresponding RU is the same. For method seven, we can let... Among them, PAP p (x) is the PAPR corresponding to a RU in the second sequence. It can be the PAPR of the subsequence with the largest PAPR among the subsequences corresponding to the RU in any sequence included in the first sequence. Furthermore, PAPR varies depending on the value of x. p (x) and The meanings of these terms can be found in the PAPR documentation. s (x) and Further details are omitted here. It should be noted that in this application, the δ values ​​in Tables 1-12 are all less than or equal to a preset threshold, and the PAPR of the first sequence in Tables 1-12 is close to that of the second sequence. Because the second sequence can support channel measurement by the AP or STA, and the transmit power efficiency of the second sequence is better, the transmit power efficiency of the first sequence whose PAPR is close to that of the second sequence in Tables 1-12 is also relatively good. That is, the first sequence whose PAPR is close to that of the second sequence can also better support channel measurement by the AP or STA.

[0274] In the case where the second sequence is an HE-LTF sequence in 802.11ax 80MHz bandwidth 4x mode, the PAPR of the first and second sequences in mode 1 under different RUs can be found in Table 1. Referring to Table 1, it can be seen that when i=1 in Method 1, the PAPR of the subsequence with the largest PAPR in the subsequence corresponding to 26-tone RU in s1 is 7.0810dB, the PAPR of the subsequence corresponding to 52-tone RU in s1 is 7.6445dB, the PAPR of the subsequence corresponding to 106-tone RU in s1 is 6.6954dB, the PAPR of the subsequence corresponding to 242-tone RU in s1 is 6.9515dB, the PAPR of the subsequence corresponding to 484-tone RU in s1 is 6.5287dB, and the PAPR of the subsequence corresponding to 996-tone RU in s1 is 7.4502dB. Therefore, the δ corresponding to s1 is 0.1551. Since 0.1551 is less than the preset threshold, it means that the PAPR of s1 is close to the second sequence, which indicates that the transmit power efficiency of s1 is also relatively good and can well support AP or STA to perform channel measurement. Similarly, when i=2 in mode 1, the PAPR of s2 under different RUs is shown in Table 1, and the corresponding δ is 0.2086; when i=3 in mode 1, the PAPR of s3 under different RUs is shown in Table 1, and the corresponding δ is 0.1144; when i=4 in mode 1, the PAPR of s4 under different RUs is shown in Table 1, and the corresponding δ is 0.0507; when i=5 in mode 1, the PAPR of s5 under different RUs is shown in Table 1, and the corresponding δ is 0.1046; when i=6 in mode 1, the PAPR of s6 under different RUs is shown in Table 1, and the corresponding δ is 0.1519; when i=7 in mode 1, the PAPR of s7 under different RUs is shown in Table 1, and the corresponding δ is 0.0669. That is, 0.2086, 0.1144, 0.0507, etc. are all less than the preset threshold, which means that the PAPR of s2, s3, s4, etc. are close to the second sequence, thus indicating that the transmit power efficiency of s2, s3, s4, etc. is also relatively good, and can well support AP or STA to perform channel measurement.Additionally, in Tables 1-6, the PAPR corresponding to the 26-tone RU of the second sequence is 7.0810 dB, the PAPR corresponding to the 52-tone RU of the second sequence is 7.6445 dB, the PAPR corresponding to the 106-tone RU of the second sequence is 6.6954 dB, the PAPR corresponding to the 242-tone RU of the second sequence is 6.9515 dB, the PAPR corresponding to the 484-tone RU of the second sequence is 6.5287 dB, and the PAPR corresponding to the 996-tone RU of the second sequence is 7.2951 dB. These will not be elaborated further.

[0275] Table 1: PAPR of the first and second sequences in Method 1 under different RUs

[0276]

[0277]

[0278] In the case where the second sequence is an HE-LTF sequence in 802.11ax 80MHz bandwidth 4x mode, the PAPR of the first and second sequences in mode 2 under different RUs can be found in Table 2. It is understood that in this application, q1(1,7) can be interpreted as: That is, k1 is 1 and k2 is 7; similarly, q1(4,5) can be understood as: That is, k1 is 4 and k2 is 5. For the other values ​​in Table 2, such as q1(4, 6), the interpretation of q1(1, 7) can be referenced, and will not be elaborated upon here. Furthermore, referring to Table 2, At that time, the PAPR of the subsequence with the highest PAPR corresponding to the 26-tone RU in q1 was 7.0810 dB, the PAPR of the subsequence with the highest PAPR corresponding to the 52-tone RU in q1 was 7.6445 dB, the PAPR of the subsequence with the highest PAPR corresponding to the 106-tone RU in q1 was 6.6954 dB, the PAPR of the subsequence with the highest PAPR corresponding to the 242-tone RU in q1 was 6.9515 dB, the PAPR of the subsequence with the highest PAPR corresponding to the 484-tone RU in q1 was 6.5287 dB, and the PAPR of the subsequence with the highest PAPR corresponding to the 996-tone RU in q1 was 7.3083 dB. Therefore, At that time, δ is 0.0132. Similarly, When q1 is under different RU, see Table 2, δ is 0.0011; At that time, the PAPR of q1 under different RUs is shown in Table 2, and δ is 0.0191; At that time, the PAPR of q1 under different RUs is shown in Table 2, and δ is 0.0047; For the PAPR of q1 under different RU, see Table 2, where δ is 0.0086.

[0279] Table 2: PAPR of the first and second sequences in Method 2 under different RUs

[0280]

[0281]

[0282] In the case where the second sequence is an HE-LTF sequence in 802.11ax 80MHz bandwidth 4x mode, the PAPR of the first and second sequences in mode 3 under different RUs can be found in Table 3. It is understood that in this application, q2(1, 6, 7) can be interpreted as: That is, k3 is 1, k4 is 6, and k5 is 7; similarly, q2(1, 7, 5) can be understood as: That is, k3 is 1, k4 is 7, and k5 is 5. For the other values ​​in Table 3, such as q2(1, 7, 6), the interpretation of q2(1, 6, 7) can be referenced, and will not be elaborated upon here. Furthermore, referring to Table 3, At that time, the PAPR of the subsequence with the highest PAPR in the subsequence corresponding to the 26-tone RU in q2 was 7.0810 dB, the PAPR of the subsequence corresponding to the 52-tone RU in q2 was 7.6445 dB, the PAPR of the subsequence corresponding to the 106-tone RU in q2 was 6.6954 dB, the PAPR of the subsequence corresponding to the 242-tone RU in q2 was 6.9515 dB, the PAPR of the subsequence corresponding to the 484-tone RU in q2 was 6.5287 dB, and the PAPR of the subsequence corresponding to the 996-tone RU in q2 was 7.3074 dB. Therefore, At that time, δ is 0.0123. Similarly, When q2 is at different RU values, see Table 3, where δ is 0.0003. Furthermore, for the remaining cases in Table 3, δ from top to bottom is 0.0091, 0.0161, 0.0056, 0.0167, 0.0041, 0.0077, 0.0015, 0.0069, 0.0121, 0.0036, 0.0125, 0.0005, 0.0185, 0.0083, 0.0135, 0.0124, 0.0 173, 0.0012, 0.0088, 0.0138, 0.0044, 0.0181, 0.0154, 0.0071, 0.0156, 0.0046, 0.0098, 0.0059, 0.0155, 0.0146, 0.0096, 0.0133, 0.0066, 0.0008, 0.0039, 0.0109.

[0283] Table 3: PAPR of the first and second sequences in Method 3 under different RUs

[0284]

[0285]

[0286]

[0287]

[0288] In the case where the second sequence is an HE-LTF sequence in 802.11ax 80MHz bandwidth 4x mode, the PAPR for the first and second sequences in mode 4 under different RUs can be found in Table 4. It is understood that in this application, q3(1, 7, 4, 7) can be interpreted as: That is, k6 is 1, k7 is 7, k8 is 4, and k9 is 7; similarly, q3(1, 7, 6, 3) can be understood as: That is, k6 is 1, k7 is 7, k8 is 6, and k9 is 3. For the other values ​​in Table 4, such as q3(2, 7, 7, 4), the interpretation of q3(1, 7, 4, 7) can be referenced, and will not be elaborated upon here. Furthermore, referring to Table 4, At that time, the PAPR of the subsequence with the highest PAPR in the subsequence corresponding to the 26-tone RU in q3 was 7.0810 dB, the PAPR of the subsequence corresponding to the 52-tone RU in q3 was 7.6445 dB, the PAPR of the subsequence corresponding to the 106-tone RU in q3 was 6.6954 dB, the PAPR of the subsequence corresponding to the 242-tone RU in q3 was 6.9515 dB, the PAPR of the subsequence corresponding to the 484-tone RU in q3 was 6.5287 dB, and the PAPR of the subsequence corresponding to the 996-tone RU in q3 was 7.2955 dB. Therefore, At that time, δ is 0.0004. Similarly, When q3 is at different RU, see Table 4, where δ is 0.0001. Furthermore, for the remaining cases in Table 4, δ from top to bottom is 0.0010, 0.0001, 0.0007, 0.0002, 0.0007, 0.0004, 0.0003, 0.0009, 0.0000, 0.0002, 0.0007, 0.0008, 0.0007, and 0.0006.

[0289] Table 4: PAPR of the first and second sequences in Method 4 under different RUs

[0290]

[0291]

[0292] In the case where the second sequence is an HE-LTF sequence in 80MHz bandwidth 4x mode of 802.11ax, the PAPR of the first and second sequences under different RUs in mode 5 can be found in Table 5. It is understood that in this application, q4(1, 7, 6, 1, 5) can be interpreted as: That is, k10 is 1, k11 is 7, k12 is 6, k13 is 1, and k14 is 5; similarly, q4(2, 7, 5, 7, 5) can be understood as: That is, k10 is 2, k11 is 7, k12 is 5, k13 is 7, and k14 is 5. For the other values ​​in Table 5, such as q4(6, 1, 2, 4, 4), the interpretation of q4(1, 7, 6, 1, 5) can be referenced, and will not be elaborated upon here. Furthermore, referring to Table 5, At that time, the PAPR of the subsequence with the highest PAPR in the subsequence corresponding to the 26-tone RU in q4 was 7.0810 dB, the PAPR of the subsequence corresponding to the 52-tone RU in q4 was 7.6445 dB, the PAPR of the subsequence corresponding to the 106-tone RU in q4 was 6.6954 dB, the PAPR of the subsequence corresponding to the 242-tone RU in q4 was 6.9515 dB, the PAPR of the subsequence corresponding to the 484-tone RU in q4 was 6.5287 dB, and the PAPR of the subsequence corresponding to the 996-tone RU in q4 was 7.2951 dB. Therefore, At that time, δ was 2.16 × 10 -5 Similarly, For the PAPR of q4 under different RUs, see Table 5, where δ is 2.45 × 10⁻⁶. -5 Furthermore, for the remaining cases in Table 5, δ from top to bottom is 2.51 × 10⁻⁶. -5 4.06×10 -5 4.58×10 -5 5.26×10 -5 5.43×10 -5 5.71×10 -5 .

[0293] Table 5: PAPR of the first and second sequences in Method 5 under different RUs

[0294]

[0295] In the case where the second sequence is an HE-LTF sequence in 80MHz bandwidth 4x mode of 802.11ax, the PAPR of the first and second sequences under different RUs in mode 6 can be found in Table 6. It is understood that in this application, q5(5, 2, 4, 7, 2, 5) can be interpreted as: That is, k15 is 5, k16 is 2, k17 is 4, k18 is 7, k19 is 2, and k20 is 5; similarly, q5(5, 2, 5, 1, 7, 2) can be understood as: That is, k15 is 5, k16 is 2, k17 is 5, k18 is 1, k19 is 7, and k20 is 2. For the other values ​​in Table 6, such as q5(6, 2, 2, 3, 7, 5), the interpretation of q5(5, 2, 4, 7, 2, 5) can be referenced, and will not be elaborated upon here. Furthermore, referring to Table 6, At that time, the PAPR of the subsequence with the highest PAPR in the subsequence corresponding to the 26-tone RU in q5 was 7.0810 dB, the PAPR of the subsequence corresponding to the 52-tone RU in q5 was 7.6445 dB, the PAPR of the subsequence corresponding to the 106-tone RU in q5 was 6.6954 dB, the PAPR of the subsequence corresponding to the 242-tone RU in q5 was 6.9515 dB, the PAPR of the subsequence corresponding to the 484-tone RU in q5 was 6.5287 dB, and the PAPR of the subsequence corresponding to the 996-tone RU in q5 was 7.2951 dB. Therefore, At that time, δ was 1.09 × 10 -6 Similarly, For the PAPR of q5 under different RUs, see Table 6, where δ is 4.07 × 10⁻⁶. -6 Furthermore, for the remaining cases in Table 6, δ from top to bottom is 5.02 × 10⁻⁶. -6 5.45×10 -6 7.14×10 -6 8.36×10 -6 8.95×10 -6 9.02×10 -6 .

[0296] Table 6: PAPR of the first and second sequences in Method 6 under different RUs

[0297]

[0298]

[0299] In the case where the second sequence is an EHT-LTF sequence in 802.11be with an 80MHz bandwidth 4x mode, the PAPR of the first and second sequences in mode 7 under different RUs can be found in Table 7. Referring to Table 7, it can be seen that when u = 1 in method 7, the PAPR of the subsequence with the largest PAPR in the subsequence corresponding to the 26-tone RU in p1 is 4.1824 dB, the PAPR of the subsequence corresponding to the 52-tone RU in p1 is 4.1720 dB, the PAPR of the subsequence corresponding to the 106-tone RU in p1 is 4.7226 dB, the PAPR of the subsequence corresponding to the 242-tone RU in p1 is 5.2664 dB, the PAPR of the subsequence corresponding to the 484-tone RU in p1 is 5.6165 dB, and the PAPR of the subsequence corresponding to the 996-tone RU in p1 is 6.0614 dB. Therefore, the δ corresponding to p1 is 0.2422. Similarly, when u=2 in mode 7, the PAPR of p2 under different RUs is shown in Table 7, and the δ corresponding to p2 is 0.1989; when u=3 in mode 7, the PAPR of s3 under different RUs is shown in Table 7, and the δ corresponding to p3 is 0.2461; when u=4 in mode 7, the PAPR of p4 under different RUs is shown in Table 7, and the δ corresponding to p4 is 0.1821; when u=5 in mode 7, the PAPR of p5 under different RUs is shown in Table 7, and the δ corresponding to p5 is 0.014. Additionally, in Tables 7-12, the PAPR corresponding to the 26-tone RU of the second sequence is 4.1824 dB, the PAPR corresponding to the 52-tone RU of the second sequence is 4.1720 dB, the PAPR corresponding to the 106-tone RU of the second sequence is 4.7226 dB, the PAPR corresponding to the 242-tone RU of the second sequence is 5.2664 dB, the PAPR corresponding to the 484-tone RU of the second sequence is 5.6165 dB, and the PAPR corresponding to the 996-tone RU of the second sequence is 5.8192 dB. These will not be elaborated further.

[0300] Table 7: PAPR of the first and second sequences in Method 7 under different RUs

[0301]

[0302] In the case where the second sequence is an EHT-LTF sequence in 802.11be 80MHz bandwidth 4x mode, the PAPR for the first and second sequences in mode eight under different RUs can be found in Table 8. It is understood that in this application, q6(5,5) can be interpreted as: That is, t1 is 5 and t2 is 5; similarly, q6(5,1) can be understood as: That is, t1 is 5 and t2 is 1. For the other cases in Table 8, such as q6(5,4), the interpretation of q6(5,5) can be referenced, and will not be elaborated upon here. Furthermore, referring to Table 8, At that time, the PAPR of the subsequence with the highest PAPR in the subsequence corresponding to the 26-tone RU in q6 was 4.1824 dB, the PAPR of the subsequence corresponding to the 52-tone RU in q6 was 4.1720 dB, the PAPR of the subsequence corresponding to the 106-tone RU in q6 was 4.7226 dB, the PAPR of the subsequence corresponding to the 242-tone RU in q6 was 5.2664 dB, the PAPR of the subsequence corresponding to the 484-tone RU in q6 was 5.6165 dB, and the PAPR of the subsequence corresponding to the 996-tone RU in q6 was 5.8052 dB. Therefore, At that time, δ is 0.0140. Similarly, For the PAPR of q6 under different RUs, see Table 8, where δ is 0.0170. Additionally, for the remaining cases in Table 8, δ from top to bottom is 0.0538, 0.064, 0.0783, 0.0794, and 0.1191, respectively.

[0303] Table 8: PAPR of the first and second sequences in Method 8 under different RUs

[0304]

[0305] In the case where the second sequence is an EHT-LTF sequence in 80MHz bandwidth 4x mode of 802.11be, the PAPR for the first and second sequences in mode 9 under different RUs can be found in Table 9. It is understood that in this application, q7(5, 5, 1) can be interpreted as: That is, t3 is 5, t4 is 5, and t5 is 1; similarly, q7(5, 1, 5) can be understood as: That is, t3 is 5, t4 is 1, and t5 is 5. For the other values ​​in Table 9, such as q7(1, 7, 6), the interpretation of q7(1, 6, 7) can be referenced, and will not be elaborated upon here. Furthermore, referring to Table 9, At that time, the PAPR of the subsequence with the highest PAPR in the subsequence corresponding to the 26-tone RU in q7 was 4.1824 dB, the PAPR of the subsequence corresponding to the 52-tone RU in q7 was 4.1720 dB, the PAPR of the subsequence corresponding to the 106-tone RU in q7 was 4.7226 dB, the PAPR of the subsequence corresponding to the 242-tone RU in q7 was 5.2664 dB, the PAPR of the subsequence corresponding to the 484-tone RU in q7 was 5.6165 dB, and the PAPR of the subsequence corresponding to the 996-tone RU in q7 was 5.8195 dB. Therefore, At that time, δ is 0.0003. Similarly, For the PAPR of q7 under different RUs, see Table 9, where δ is 0.0131. Additionally, for the remaining cases in Table 9, δ from top to bottom is 0.0140, 0.0153, 0.6005, 0.0243, and 0.0268 respectively.

[0306] Table 9: PAPR of the first and second sequences in Method 9 under different RUs

[0307]

[0308] In the case where the second sequence is an EHT-LTF sequence in 80MHz bandwidth 4x mode in 802.11be, the PAPR for the first and second sequences under different RUs in mode 10 can be found in Table 10. It is understood that in this application, q8(5, 5, 5, 4) can be interpreted as: That is, t6 is 5, t7 is 5, t8 is 5, and t9 is 4; similarly, q8(5, 5, 1, 5) can be understood as: That is, t6 is 5, t7 is 5, t8 is 1, and t9 is 5. For the other values ​​in Table 10, such as q8(5, 5, 5, 2), the interpretation of q8(5, 5, 5, 4) can be referenced, and will not be elaborated upon here. Furthermore, referring to Table 10, At that time, the PAPR of the subsequence with the highest PAPR in the subsequence corresponding to the 26-tone RU in q8 was 4.1824 dB, the PAPR of the subsequence corresponding to the 52-tone RU in q8 was 4.1720 dB, the PAPR of the subsequence corresponding to the 106-tone RU in q8 was 4.7226 dB, the PAPR of the subsequence corresponding to the 242-tone RU in q8 was 5.2664 dB, the PAPR of the subsequence corresponding to the 484-tone RU in q8 was 5.6165 dB, and the PAPR of the subsequence corresponding to the 996-tone RU in q8 was 5.8189 dB. Therefore, At that time, δ is 0.0003. Similarly, For the PAPR of q8 under different RUs, see Table 10, where δ is 0.0006. In addition, for the remaining cases in Table 10, δ from top to bottom is 0.0023, 0.0052, 0.0057, 0.0071, 0.0115, and 0.0130 respectively.

[0309] Table 10: PAPR of the first and second sequences in Method 10 under different RUs

[0310]

[0311] In the case where the second sequence is an EHT-LTF sequence in 80MHz bandwidth 4x mode of 802.11be, the PAPR for the first and second sequences under different RUs in mode 11 can be found in Table 11. It is understood that in this application, q9(5, 5, 5, 1, 2) can be interpreted as: That is, t10 is 5, t11 is 5, t12 is 5, t13 is 1, and t14 is 2; similarly, q9(5, 5, 5, 1, 4) can be understood as: That is, t10 is 5, t11 is 5, t12 is 5, t13 is 1, and t14 is 4. For the other values ​​in Table 11, such as q9(5, 5, 5, 4, 5), the interpretation of q9(5, 5, 5, 1, 2) can be referenced, and will not be elaborated upon here. Furthermore, referring to Table 11, At that time, the PAPR of the subsequence with the highest PAPR in the subsequence corresponding to the 26-tone RU in q9 was 4.1824 dB, the PAPR of the subsequence corresponding to the 52-tone RU in q9 was 4.1720 dB, the PAPR of the subsequence corresponding to the 106-tone RU in q9 was 4.7226 dB, the PAPR of the subsequence corresponding to the 242-tone RU in q9 was 5.2664 dB, the PAPR of the subsequence corresponding to the 484-tone RU in q9 was 5.6165 dB, and the PAPR of the subsequence corresponding to the 996-tone RU in q9 was 5.8197 dB. Therefore, At that time, δ is 0.0002. Similarly, For the PAPR of q9 under different RUs, see Table 11, where δ is 0.0007. In addition, for the remaining cases in Table 11, δ from top to bottom is 0.0008, 0.0010, 0.0017, 0.0018, 0.0020, and 0.0026 respectively.

[0312] Table 11: PAPR of the first and second sequences in Method 11 under different RUs

[0313]

[0314] In the case where the second sequence is an EHT-LTF sequence in 802.11be 80MHz bandwidth 4x mode, the PAPR for the first and second sequences in mode 12 under different RUs can be found in Table 12. It is understood that in this application, q 10 (5, 5, 5, 1, 2, 5) can be understood as: That is, t15 is 5, t16 is 5, t17 is 5, t18 is 1, t19 is 2, and t20 is 5; similarly, q 10 (5, 5, 5, 1, 1, 3) can be understood as: That is, t15 is 5, t16 is 5, t17 is 5, t18 is 1, t19 is 1, and t20 is 3. Among these, for the remaining values ​​in Table 12, such as q... 10 (5, 5, 1, 5, 5, 1) etc. can be referenced from q. 10 The interpretation of (5, 5, 5, 1, 2, 5) will not be elaborated here. Furthermore, referring to Table 12, it can be seen that... At that time, q 10The subsequence with the highest PAPR in the subsequence corresponding to the 26-tone RU has a PAPR of 4.1824 dB. 10 The subsequence with the highest PAPR in the subsequence corresponding to the 52-tone RU has a PAPR of 4.1720 dB. 10 The subsequence with the highest PAPR in the subsequence corresponding to the 106-tone RU has a PAPR of 4.7226 dB. 10 The subsequence with the highest PAPR in the subsequence corresponding to the 242-tone RU has a PAPR of 5.2664 dB. 10 The subsequence with the highest PAPR in the subsequence corresponding to the 484-tone RU has a PAPR of 5.6165 dB. 10 The subsequence with the highest PAPR in the subsequence corresponding to the 996-tone RU has a PAPR of 5.8194 dB. Therefore, At that time, q 10 The PAPR values ​​under different RUs are shown in Table 12, with δ being 0.0002. Additionally, for the remaining cases in Table 12, δ values ​​from top to bottom are 0.0003, 0.0003, 0.0005, 0.0006, 0.0007, and 0.0010.

[0315] Table 12: PAPR of the first and second sequences in Method 12 under different RUs

[0316]

[0317]

[0318] The above primarily describes the solution provided in this application from the perspective of interaction between various devices. It is understood that each device, in order to achieve the aforementioned functions, includes corresponding hardware structures and / or software modules for executing each function. Those skilled in the art should readily recognize that, based on the units and algorithm steps of the examples described in conjunction with the embodiments disclosed herein, this application can be implemented in hardware or a combination of hardware and computer software. Whether a function is executed in hardware or by computer software driving hardware depends on the specific application and design constraints of the technical solution. Those skilled in the art can use different methods to implement the described functions for each specific application, but such implementation should not be considered beyond the scope of this application.

[0319] This application embodiment can divide the AP or STA into functional modules according to the above method example. For example, each function can be divided into a separate functional module, or two or more functions can be integrated into one processing module. The integrated module can be implemented in hardware or as a software functional module. It should be noted that the module division in this application embodiment is illustrative and is only a logical functional division. In actual implementation, there may be other division methods.

[0320] When using integrated modules, see [link to relevant documentation]. Figure 8 , Figure 8 This is a schematic diagram of a communication device provided in an embodiment of this application. The communication device 800 can be applied to the above-described... Figure 6 In the method shown, such as Figure 8 As shown, the communication device 800 includes a processing module 801 and a transceiver module 802. The processing module 801 may be one or more processors, and the transceiver module 802 may be a transceiver or a communication interface. This communication device can be used to implement the AP or STA involved in any of the above method embodiments, or to implement the functions of network elements involved in any of the above method embodiments. The network element or network function may be a network component in a hardware device, a software function running on dedicated hardware, or a virtualization function instantiated on a platform (e.g., a cloud platform). Optionally, the communication device 800 may further include a storage module 803 for storing the program code and data of the communication device 800.

[0321] In one example, when the communication device acts as a STA or is a chip applied in a STA, it performs the steps executed by the STA in the above method embodiments. The transceiver module 802 supports communication with the AP, etc., and specifically performs... Figure 6 The processing module 801 can be used to support the communication device 800 in performing the processing actions in the above method embodiments, such as supporting the STA in performing step 602, and / or other processes using the techniques described herein.

[0322] For example, processing module 801 is used to generate a probe frame; the probe frame includes a first field, the first field including a predefined first sequence, wherein the first sequence includes a sequence obtained by modulating a second sequence using at least one of the following modulation methods: Quadrature Phase Shift Keying (QPSK), 16-QAM, 64-QAM, 256-QAM, 1024-QAM, and 4096-QAM; transceiver module 802 is used to transmit the probe frame. Regarding the first sequence, refer to... Figure 7The relevant descriptions in the text will not be repeated here.

[0323] In one example, when the communication device functions as an access point (AP) or is a chip used in an AP, it performs the steps executed by the AP in the above method embodiments. The transceiver module 802 supports communication with STAs, etc., and specifically performs... Figure 6 The processing module 801 can be used to support the communication device 800 in performing the processing actions in the above method embodiments, such as supporting the AP in performing step 601, and / or other processes using the techniques described herein.

[0324] For example, transceiver module 802 is used to receive probe frames; the probe frame includes a first field, the first field including a predefined first sequence, wherein the first sequence includes a sequence obtained by modulating a second sequence using at least one of the following modulation methods: Quadrature Phase Shift Keying (QPSK), 16-QAM (16-Orthogonal Amplitude Modulation), 64-QAM, 256-QAM, 1024-QAM, and 4096-QAM; processing module 801 is used to perform channel measurements based on the first sequence. Regarding the first sequence, refer to... Figure 7 The relevant descriptions in the text will not be repeated here.

[0325] In one possible implementation, when the STA or AP is a chip, the transceiver module 802 can be an input / output interface, pins, or circuits. For example, the input / output interface can be used to input data to be processed into the logic circuit and can output the processing results of the logic circuit. Specifically, the input / output interface can be a general purpose input / output (GPIO) interface, which can connect to multiple peripheral devices (such as displays (LCDs), cameras, radio frequency (RF) modules, antennas, etc.). The input / output interface is connected to the processor via a bus.

[0326] The processing module 801 can be a logic circuit that can execute stored instructions, causing the chip to perform... Figure 6 The method involved in the illustrated embodiment. It will be understood that the instructions can be stored in a storage module.

[0327] The storage module can be an internal storage module of the chip, such as a register or cache. Alternatively, the storage module can be an external storage module, such as a read-only memory (ROM) or other types of static storage devices that can store static information and instructions, such as random access memory (RAM).

[0328] It should be noted that the functions of logic circuits and input / output interfaces can be implemented through hardware design, software design, or a combination of hardware and software; no restrictions are imposed here.

[0329] This application also provides a communication device, including a processor and a transceiver, wherein the processor is configured to support the communication device in performing actions such as... Figure 6 The illustrated embodiment. This transceiver supports communication between the communication device and other communication devices outside the communication device. The communication device may also include a memory coupled to a processor, which stores necessary program instructions and data for the communication device. The transceiver may be integrated into the communication device or independent of it; this is not limited. For example, in a distributed scenario, the transceiver may be independent of the communication device and arranged in a remote manner.

[0330] This application embodiment also provides a chip, which includes at least one logic circuit and an input / output interface. The logic circuit is used to read and execute stored instructions, and when the instructions are executed, the chip causes the chip to perform actions such as... Figure 6 The illustrated embodiment.

[0331] This application embodiment also provides a computer-readable storage medium storing a computer program. The computer program includes program instructions, which, when executed by a computer, cause the computer to perform actions such as... Figure 6 The illustrated embodiment.

[0332] This application also provides a computer program product containing instructions that, when run on a computer, cause the computer to perform the following: Figure 6 The illustrated embodiment.

[0333] The units described above as separate components may or may not be physically separate. The components shown as units may or may not be physical units; that is, they may be located in one place or distributed across multiple network units. Some or all of the units can be selected to achieve the objectives of the embodiments of this application, depending on actual needs. Furthermore, the network element units in the various embodiments of this application may be integrated into one processing unit, or each unit may exist physically separately, or two or more units may be integrated into one unit. The integrated units described above can be implemented in hardware or as software network element units.

[0334] If the integrated units described above are implemented as software network elements and sold or used as independent products, they can be stored in a computer-readable storage medium. Based on this understanding, the essential contribution of the technical solution of this application, or all or part of the technical solution, can be embodied in the form of a software product. This computer software product is stored in a storage medium and includes several instructions to cause a computer device (which may be a personal computer, cloud server, or network device, etc.) to execute all or part of the steps of the methods described in the various embodiments of this application. The aforementioned storage medium includes various media capable of storing program code, such as USB flash drives, portable hard drives, read-only memory (ROM), random access memory (RAM), magnetic disks, or optical disks. The above descriptions are merely specific embodiments of this application, but the scope of protection of this application is not limited thereto. Any person skilled in the art can easily conceive of various equivalent modifications or substitutions within the scope of the technology disclosed in this application, and these modifications or substitutions should all be covered within the scope of protection of this application. Therefore, the scope of protection of this application should be determined by the scope of the claims.

Claims

1. A method for detecting frame transmission, characterized in that, The method is applied to a first device, and the method includes: Generate a probe frame; the probe frame includes a first field, the first field including a predefined first sequence, wherein the first sequence includes a sequence obtained by modulating a second sequence using at least one of the following modulation methods, the modulation methods including: quadrature phase shift keying (QPSK), 16-quadrature amplitude modulation (16-QAM), 64-QAM, 256-QAM, 1024-QAM, 4096-QAM; Send the probe frame; The second sequence is either a high-efficiency long training field HE-LTF sequence or an ultra-high throughput long training field EHT-LTF sequence in 4x mode with a bandwidth of 80MHz.

2. A method for detecting frame transmission, characterized in that, The method is applied to a second device, and the method includes: Receive a probe frame; the probe frame includes a first field, the first field including a predefined first sequence, wherein the first sequence includes a sequence obtained by modulating a second sequence using at least one of the following modulation methods, the modulation methods including: quadrature phase shift keying (QPSK), 16-quadrature amplitude modulation (16-QAM), 64-QAM, 256-QAM, 1024-QAM, 4096-QAM; Perform channel measurements based on the first sequence; The second sequence is either a high-efficiency long training field HE-LTF sequence or an ultra-high throughput long training field EHT-LTF sequence in 4x mode with a bandwidth of 80MHz.

3. The method according to claim 1 or 2, characterized in that, The HE-LTF sequence is: [1,-1,-1,-1,-1,1,-1,-1,1,-1,-1,-1,1,1,-1,-1,-1,1,-1,-1,1,-1,1,1,1,-1,1,-1,1,-1,-1,-1,-1,1,1,1,1,1,-1,-1,1,-1,1,-1,-1,-1,1,1,-1,-1,1,-1,-1,-1,1,1,1,-1,-1,1,1,-1,-1,1,-1,1,1,-1,1,-1,1,1,1,-1,1,-1,1,1,1,1,1,1,-1,-1,-1,1,-1,1,-1,-1,-1,1,-1,-1,1,1,1,1,1,1,-1,1,-1,1,1,-1,1,-1,1,-1,1,-1,1,-1,-1,1,1,1,1,-1,-1,-1,-1,-1,-1,-1,-1,1,-1,-1,1,-1,-1,1,1,1,-1,1,-1,-1,-1,1,1,1,-1,1,1,-1,-1,1,-1,-1,-1,1,1,1,1,-1,1,1,1,1,1,1,-1,1,-1,-1,1,-1,1,-1,-1,1,1,1,1,1,-1,1,1,-1,-1,1,1,1,-1,1,1,-1,1,1,-1,-1,1,1,-1,-1,-1,-1,1,1,1,1,1,-1,1,1,1,1,1,-1,1,-1,1,-1,-1,1,-1,-1,-1,-1,-1,1,-1,-1,-1,1,1,-1,1,-1,1,-1,-1,-1,-1,-1,1,1,1,1,-1,1,-1,-1,1,1,-1,-1,-1,1,1,1,1,1,-1,1,-1,1,-1,-1,1,1,1,-1,1,1,1,1,1,-1,1,1,-1,1,-1,1,-1,-1,-1,-1,-1,1,-1,-1,-1,-1,-1,1,1,1,1,-1,-1,1,1,-1,-1,1,-1,-1,1,-1,-1,-1,1,1,-1,-1,1,-1,-1,-1,-1,-1,1,1,-1,1,-1,1,1,-1,1,-1,-1,-1,-1,-1,-1,1,-1,-1,-1,-1,1,1,1,-1,1,1,-1,-1,1,-1,-1,-1,1,1,1,-1,1,-1,1,-1,-1,-1,1,-1,1,-1,1,-1,-1,-1,1,-1,-1,1,-1,1,1,-1,-1,-1,1,1,-1,-1,-1,-1,1,-1,1,1,-1,1,-1,1,1,1,1,1,1,-1,-1,1,-1,-1,-1,1,-1,1,-1,-1,-1,1,1,1,1,1,1,-1,1,-1,1,1,1,-1,1,-1,1,1,-1,1,-1,-1,1,1,-1,-1,1,1,1,-1,-1,-1,1,-1,-1,1,1,-1,-1,-1,1,-1,1,-1,-1,1,1,1,1,1,-1,-1,-1,-1,1,-1,1,-1,1,1,1,-1,1,-1,-1,1,-1,-1,-1,1,1,-1,-1,-1,1,-1,-1,1,-1,-1,-1,-1,1,-1,1,1,-1,-1,-1,1,-1,-1,0,0,0,0,0,-1,-1,1,-1,1,1,1,1,1,1,-1,-1,-1,-1,1,-1,-1,1,-1,-1,-1,1,1,-1,-1,-1,1,-1,-1,1,-1,1,1,1,-1,1,-1,1,-1,-1,-1,-1,1,1,1,1,1,-1,-1,1,-1,1,-1,-1,-1,1,1,-1,-1,1,-1,-1,-1,1,1,1,-1,-1,1,1,-1,-1,1,-1,1,1,-1,1,-1,1,1,1,-1,1,-1,1,1,1,1,1,1,-1,-1,-1,1,-1,1,-1,-1,-1,1,-1,-1,1,1,1,1,1,1,-1,1,-1,1,1,-1,1,-1,-1,-1,-1,1,1,-1,-1,-1,1,1,-1,1,-1,-1,1,-1,-1,-1,1,-1,1,-1,1,-1,-1,-1,1,-1,1,-1,1,1,1,-1,-1,-1,1,-1,-1,1,1,-1,1,1,1,-1,-1,-1,-1,1,-1,-1,-1,-1,-1,-1,1,-1,1,1,-1,1,-1,1,1,-1,-1,-1,-1,-1,1,-1,-1,1,1,-1,-1,-1,1,-1,-1,1,-1,-1,1,1,-1,-1,1,1,1,1,-1,-1,-1,-1,-1,1,-1,-1,-1,-1,-1,1,-1,1,-1,1,1,-1,1,1,1,1,1,-1,1,1,1,-1,-1,1,-1,1,-1,1,1,1,1,1,-1,-1,-1,1,1,-1,-1,-1,-1,-1,-1,-1,-1,1,1,1,1,1,-1,1,-1,1,-1,-1,1,1,1,-1,1,1,1,1,1,-1,1,1,-1,1,-1,1,-1,-1,-1,-1,-1,1,-1,-1,-1,-1,-1,1,1,1,1,-1,-1,1,1,-1,-1,1,-1,-1,1,-1,-1,-1,1,1,-1,-1,1,-1,-1,-1,-1,-1,1,1,-1,1,-1,1,1,-1,1,-1,-1,-1,-1,-1,-1,1,-1,-1,-1,-1,1,1,1,-1,1,1,-1,-1,1,-1,-1,-1,1,1,1,-1,1,-1,-1,-1,1,1,-1,1,1,-1,1,1,1,1,1,1,1,1,-1,-1,-1,-1,1,1,-1,1,-1,1,-1,1,-1,1,-1,-1,1,-1,1,-1,-1,-1,-1,-1,-1,1,1,-1,1,1,1,-1,1,-1,1,1,1,-1,-1,-1,-1,-1,-1,1,-1,1,-1,-1,-1,1,-1,1,-1,-1,1,-1,1,1,-1,-1,1,1,-1,-1,-1,1,1,1,-1,1,1,-1,-1,1,1,1,-1,1,-1,1,1,-1,-1,-1,-1,-1,1,1,1,1,-1,1,-1,1,-1,-1,-1,1,-1,1,1,-1,1,1,1,-1,-1,1,1,1,-1,1,1,-1,1,1,1,1,-1]； The EHT-LTF sequence is: [1,-1,-1,-1,-1,1,-1,-1,1,-1,-1,-1,1,1,-1,-1,-1,1,-1,-1,1,-1,1,1,1,-1,1,-1,1,-1,-1,-1,-1,1,1,1,1,1,-1,-1,1,-1,1,-1,-1,-1,1,1,-1,-1,1,-1,-1,-1,1,1,1,-1,-1,1,1,-1,-1,1,-1,1,1,-1,1,-1,1,1,1,-1,1,-1,1,1,1,1,1,1,-1,-1,-1,1,-1,1,-1,-1,-1,1,-1,-1,1,1,1,1,1,1,-1,1,-1,1,1,-1,1,-1,1,-1,1,-1,1,-1,-1,1,1,1,1,-1,-1,-1,-1,-1,-1,-1,-1,1,-1,-1,1,-1,-1,1,1,1,-1,1,-1,-1,-1,1,1,1,-1,1,1,-1,-1,1,-1,-1,-1,1,1,1,1,-1,1,1,1,1,1,1,-1,1,-1,-1,1,-1,1,-1,-1,1,1,1,1,1,-1,1,1,-1,-1,1,1,1,-1,1,1,-1,1,1,-1,-1,1,1,-1,-1,-1,-1,1,1,1,1,1,-1,1,1,1,1,1,-1,1,-1,1,-1,-1,1,-1,-1,-1,-1,-1,1,-1,-1,-1,1,1,-1,1,-1,1,-1,-1,-1,-1,-1,1,1,1,1,-1,1,-1,-1,1,1,-1,-1,-1,1,1,1,1,1,-1,1,-1,1,-1,-1,1,1,1,-1,1,1,1,1,1,-1,1,1,-1,1,-1,1,-1,-1,-1,-1,-1,1,-1,-1,-1,-1,-1,1,1,1,1,-1,-1,1,1,-1,-1,1,-1,-1,1,-1,-1,-1,1,1,-1,-1,1,-1,-1,-1,-1,-1,1,1,-1,1,-1,1,1,-1,1,-1,-1,-1,-1,-1,-1,1,-1,-1,-1,-1,1,1,1,-1,1,1,-1,-1,1,-1,-1,-1,1,1,1,-1,1,-1,1,-1,-1,-1,1,-1,1,-1,1,-1,-1,-1,1,-1,-1,1,-1,1,1,-1,-1,-1,1,1,-1,-1,-1,-1,1,-1,1,1,-1,1,-1,1,1,1,1,1,1,-1,-1,1,-1,-1,-1,1,-1,1,-1,-1,-1,1,1,1,1,1,1,-1,1,-1,1,1,1,-1,1,-1,1,1,-1,1,-1,-1,1,1,-1,-1,1,1,1,-1,-1,-1,1,-1,-1,1,1,-1,-1,-1,1,-1,1,-1,-1,1,1,1,1,1,-1,-1,-1,-1,1,-1,1,-1,1,1,1,-1,1,-1,-1,1,-1,-1,-1,1,1,-1,-1,-1,1,-1,-1,1,-1,-1,-1,-1,1,-1,1,1,-1,-1,-1,1,-1,-1,0,0,0,0,0,-1,-1,1,-1,1,1,1,1,1,1,-1,-1,-1,-1,1,-1,-1,1,-1,-1,-1,1,1,-1,-1,-1,1,-1,-1,1,-1,1,1,1,-1,1,-1,1,-1,-1,-1,-1,1,1,1,1,1,-1,-1,1,-1,1,-1,-1,-1,1,1,-1,-1,1,-1,-1,-1,1,1,1,-1,-1,1,1,-1,-1,1,-1,1,1,-1,1,-1,1,1,1,-1,1,-1,1,1,1,1,1,1,-1,-1,-1,1,-1,1,-1,-1,-1,1,-1,-1,1,1,1,1,1,1,-1,1,-1,1,1,-1,1,-1,-1,-1,-1,1,1,-1,-1,-1,1,1,-1,1,-1,-1,1,-1,-1,-1,1,-1,1,-1,1,-1,-1,-1,1,-1,1,-1,1,1,1,-1,-1,-1,1,-1,-1,1,1,-1,1,1,1,-1,-1,-1,-1,1,-1,-1,-1,-1,-1,-1,1,-1,1,1,-1,1,-1,1,1,-1,-1,-1,-1,-1,1,-1,-1,1,1,-1,-1,-1,1,-1,-1,1,-1,-1,1,1,-1,-1,1,1,1,1,-1,-1,-1,-1,-1,1,-1,-1,-1,-1,-1,1,-1,1,-1,1,1,-1,1,1,1,1,1,-1,1,1,1,-1,-1,1,-1,1,-1,1,1,1,1,1,-1,-1,-1,1,1,-1,-1,-1,-1,-1,-1,-1,-1,1,1,1,1,1,-1,1,-1,1,-1,-1,1,1,1,-1,1,1,1,1,1,-1,1,1,-1,1,-1,1,-1,-1,-1,-1,-1,1,-1,-1,-1,-1,-1,1,1,1,1,-1,-1,1,1,-1,-1,1,-1,-1,1,-1,-1,-1,1,1,-1,-1,1,-1,-1,-1,-1,-1,1,1,-1,1,-1,1,1,-1,1,-1,-1,-1,-1,-1,-1,1,-1,-1,-1,-1,1,1,1,-1,1,1,-1,-1,1,-1,-1,-1,1,1,1,-1,1,-1,-1,-1,1,1,-1,1,1,-1,1,1,1,1,1,1,1,1,-1,-1,-1,-1,1,1,-1,1,-1,1,-1,1,-1,1,-1,-1,1,-1,1,-1,-1,-1,-1,-1,-1,1,1,-1,1,1,1,-1,1,-1,1,1,1,-1,-1,-1,-1,-1,-1,1,-1,1,-1,-1,-1,1,-1,1,-1,-1,1,-1,1,1,-1,-1,1,1,-1,-1,-1,1,1,1,-1,1,1,-1,-1,1,1,1,-1,1,-1,1,1,-1,-1,-1,-1,-1,1,1,1,1,-1,1,-1,1,-1,-1,-1,1,-1,1,1,-1,1,1,1,-1,-1,1,1,1,-1,1,1,-1,1,1,1,1,-1]； in, The expression means that the value on each subcarrier in the sequence numbered -500 to 500 is the value in the HE-LTF sequence in sequence; The expression means that the value on each subcarrier in the sequence numbered -500 to 500 is the value in the EHT-LTF sequence.

4. The method according to claim 1 or 2, characterized in that, The first sequence Satisfy the following formula: ； The second sequence is the HE-LTF sequence. and This refers to a subsequence within the HE-LTF sequence. The imaginary unit, It is an integer greater than or equal to 1 and less than or equal to 7; ； ； ； ； ； ； 。 5. The method according to claim 1 or 2, characterized in that, The first sequence Satisfy the following formula: ； in, ; The second sequence is the HE-LTF sequence. and This refers to a subsequence within the HE-LTF sequence. The imaginary unit; in, =1, It is 7; or, It is 4. It is 5 or 6; or, It is 5. It can be 1 or 2; ； ； ； ； ； 。 6. The method according to claim 1 or 2, characterized in that, The first sequence Satisfy the following formula: ； in, ; ; The second sequence is the HE-LTF sequence. and This refers to a subsequence within the HE-LTF sequence. The imaginary unit; in, =1, It is 6. It is 7; or, =1, It is 7. It is 5 or 6; or, It is 2. It is 7. It is 6 or 7; or, It is 3. It is 5. It is 6; or, It is 3. It is 5. It is 7; or, It is 3. It is 6. It is 5 or 6; or, It is 3. It is 7. It can be 1, 2, 3, or 4; or, It is 4. It is 4. It is 7; or, It is 4. It is 5. It is 3, 4, or 5; or, It is 4. It is 6. It can be 1, 2, 3, or 4; or, It is 5. =1, It is 3 or 4; or, It is 5. =1, It is 5; or, It is 5. It is 2. It is 4, 5, or 6; or, It is 5. It is 3. It can be 1, 2, 3, or 4; or, It is 5. It is 4. It is 1 or 2; or, It is 6. =1, It is 1 or 2; or, It is 6. It is 2. It can be 1, 2, or 3; ； ； ； ； ； ； 。 7. The method according to claim 1 or 2, characterized in that, The first sequence Satisfy the following formula: ； in, ; ; ; The second sequence is the HE-LTF sequence. and This refers to a subsequence within the HE-LTF sequence. The imaginary unit; in, =1, It is 7. It is 4. It is 7; or, =1, It is 7. It is 6. It is 3; or, It is 2. It is 7. It is 7. It is 4; or, It is 3. It is 5. It is 7. It is 4; or, It is 3. It is 6. It is 5. It is 5; or, It is 3. It is 7. =1, It is 5; or, It is 3. It is 7. It is 2. It is 6; or, It is 3. It is 7. It is 3. It is 4; or, It is 4. It is 4. It is 6. It is 7; or, It is 4. It is 6. =1, It is 6; or, It is 4. It is 6. It is 4. It is 3; or, It is 5. =1, =1, It is 7; or, It is 5. It is 2. It is 6. It is 2; or, It is 5. It is 4. =1, =1; or, It is 5. It is 4. It is 2. It is 3; or, It is 6. =1, =1, =1; ； ； ； ； ； ； 。 8. The method according to claim 1 or 2, characterized in that, The first sequence Satisfy the following formula: ； in, ; ; ; ; The second sequence is the HE-LTF sequence. and This refers to a subsequence within the HE-LTF sequence. The imaginary unit; in, =1, It is 7. It is 6. =1, It is 5; or, It is 2. It is 7. It is 5. It is 7. It is 5; or, It is 6. =1, It is 2. It is 4. It is 4; or, It is 4. It is 6. It is 4. =1, It is 6; or, It is 6. It is 2. =1, It is 4. It is 5; or, It is 3. It is 6. It is 7. =1, It is 2; or, It is 5. It is 3. =1, It is 6. =1; or, It is 4. It is 6. It is 2. It is 6. It is 6; ； ； ； ； ； ； 。 9. The method according to claim 1 or 2, characterized in that, The first sequence Satisfy the following formula: ； in, ; ; ; ; ; The second sequence is the HE-LTF sequence. and This refers to a subsequence within the HE-LTF sequence. The imaginary unit; in, It is 5. It is 2. It is 4. It is 7. It is 2. It is 5; or, It is 5. It is 2. It is 5. =1, It is 7. It is 2; or, It is 6. It is 2. It is 2. It is 3. It is 7. It is 5; or, It is 3. It is 6. It is 6. It is 4. It is 5. It is 4; or, It is 4. It is 7. It is 2. It is 2. It is 3. It is 2; or, It is 6. =1, It is 2. It is 3. It is 5. It is 4; or, It is 2. It is 7. It is 7. It is 3. It is 6. It is 3; or, =1, It is 7. It is 5. It is 5. It is 4. It is 2; ； ； ； ； ； ； 。 10. The method according to claim 4, characterized in that, The first to the 489th elements in the HE-LTF sequence. It refers to the 504th to 1001st elements in the HE-LTF sequence.

11. The method according to claim 5, characterized in that, The first to the 489th elements in the HE-LTF sequence. It refers to the 504th to 1001st elements in the HE-LTF sequence.

12. The method according to claim 6, characterized in that, The first to the 489th elements in the HE-LTF sequence. It refers to the 504th to 1001st elements in the HE-LTF sequence.

13. The method according to claim 7, characterized in that, The first to the 489th elements in the HE-LTF sequence. It refers to the 504th to 1001st elements in the HE-LTF sequence.

14. The method according to claim 8, characterized in that, The first to the 489th elements in the HE-LTF sequence. It refers to the 504th to 1001st elements in the HE-LTF sequence.

15. The method according to claim 9, characterized in that, The first to the 489th elements in the HE-LTF sequence. It refers to the 504th to 1001st elements in the HE-LTF sequence.

16. The method according to claim 1 or 2, characterized in that, The first sequence Satisfy the following formula: ； Wherein, the second sequence is the EHT-LTF sequence. and This is a subsequence in the EHT-LTF sequence. The imaginary unit, It is an integer greater than or equal to 1 and less than or equal to 5; ； ； ； ； 。 17. The method according to claim 1 or 2, characterized in that, The first sequence Satisfy the following formula: ； in, ; The second sequence is the EHT-LTF sequence. and This is a subsequence in the EHT-LTF sequence. The imaginary unit; in, It is 5. It can be 1, 2, 3, 4, or 5; or, =1, It is 5; or, It is 4. It is 5; ； ； ； ； 。 18. The method according to claim 1 or 2, characterized in that, The first sequence Satisfy the following formula: ； in, ; ; The second sequence is the EHT-LTF sequence. and This is a subsequence in the EHT-LTF sequence. The imaginary unit; in, It is 5. It is 5. It can be 1, 2, 3, 4, or 5; or, It is 5. =1, It is 5; or, It is 5. =1, =1; ； ； ； ； 。 19. The method according to claim 1 or 2, characterized in that, The first sequence Satisfy the following formula: ； in, ; ; ; The second sequence is the EHT-LTF sequence. and This is a subsequence in the EHT-LTF sequence. The imaginary unit; in, It is 5. It is 5. It is 5. It can be 1, 2, 3, or 4; or, It is 5. It is 5. =1, It is 1, 4, or 5; or, It is 5. =1, It is 5. It is 5; ； ； ； ； 。 20. The method according to claim 1 or 2, characterized in that, The first sequence Satisfy the following formula: ； in, ; ; ; ; The second sequence is the EHT-LTF sequence. and This is a subsequence in the EHT-LTF sequence. The imaginary unit; in, It is 5. It is 5. It is 5. =1, It is 2 or 4; or, It is 5. It is 5. It is 5. It is 4. It is 1 or 5; or, It is 5. It is 5. =1, It is 5. It is 1 or 5; or, It is 5. It is 5. =1, It is 5. It is 5; or, It is 5. It is 5. It is 5. It is 2. It is 5; or, It is 5. It is 5. It is 5. =1, It is 3; ； ； ； ； 。 21. The method according to claim 1 or 2, characterized in that, The first sequence Satisfy the following formula: ； in, ; ; ; ; ; The second sequence is the EHT-LTF sequence. and This is a subsequence in the EHT-LTF sequence. The imaginary unit; in, It is 5. It is 5. It is 5. =1, It is 2. It is 5; or, It is 5. It is 5. It is 5. =1, =1, It is 3; or, It is 5. It is 5. =1, It is 5. It is 5. =1; or, It is 5. It is 5. It is 5. It is 5. It is 3. It is 3; or, It is 5. It is 5. It is 5. =1, =1, It is 2; or, It is 5. It is 5. It is 5. =1, It is 4. =1; or, It is 5. It is 5. It is 5. It is 4. It is 5. =1; or, It is 5. It is 5. It is 5. =1, It is 4. It is 5; ； ； ； ； 。 22. The method according to claim 16, characterized in that, The first to the 492nd elements in the EHT-LTF sequence. It refers to the 504th to 1001st elements in the EHT-LTF sequence.

23. The method according to claim 17, characterized in that, The first to the 492nd elements in the EHT-LTF sequence. It refers to the 504th to 1001st elements in the EHT-LTF sequence.

24. The method according to claim 18, characterized in that, The first to the 492nd elements in the EHT-LTF sequence. It refers to the 504th to 1001st elements in the EHT-LTF sequence.

25. The method according to claim 19, characterized in that, The first to the 492nd elements in the EHT-LTF sequence. It refers to the 504th to 1001st elements in the EHT-LTF sequence.

26. The method according to claim 20, characterized in that, The first to the 492nd elements in the EHT-LTF sequence. It refers to the 504th to 1001st elements in the EHT-LTF sequence.

27. The method according to claim 21, characterized in that, The first to the 492nd elements in the EHT-LTF sequence. It refers to the 504th to 1001st elements in the EHT-LTF sequence.

28. A communication device, characterized in that, The communication device includes a processing module and a transceiver module. The processing module is used to generate a probe frame; the probe frame includes a first field, the first field including a predefined first sequence, wherein the first sequence includes a sequence obtained by modulating a second sequence using at least one of the following modulation methods: quadrature phase shift keying (QPSK), 16-quadrature amplitude modulation (16-QAM), 64-QAM, 256-QAM, 1024-QAM, and 4096-QAM; The transceiver module is used to send the probe frame; The second sequence is either a high-efficiency long training field HE-LTF sequence or an ultra-high throughput long training field EHT-LTF sequence in 4x mode with a bandwidth of 80MHz.

29. A communication device, characterized in that, The communication device includes a processing module and a transceiver module. The transceiver module is used to receive probe frames; the probe frame includes a first field, the first field including a predefined first sequence, wherein the first sequence includes a sequence obtained by modulating a second sequence using at least one of the following modulation methods: quadrature phase shift keying (QPSK), 16-quadrature amplitude modulation (16-QAM), 64-QAM, 256-QAM, 1024-QAM, and 4096-QAM; The processing module is used to perform channel measurement based on the first sequence; The second sequence is either a high-efficiency long training field HE-LTF sequence or an ultra-high throughput long training field EHT-LTF sequence in 4x mode with a bandwidth of 80MHz.

30. A chip, characterized in that, The chip includes at least one logic circuit and an input / output interface. The logic circuit is used to read and execute stored instructions, and when the instructions are executed, the chip causes the chip to perform the method as described in any one of claims 1-27.

31. A computer-readable storage medium, characterized in that, The computer-readable storage medium stores a computer program, the computer program including program instructions that, when executed by a computer, cause the computer to perform the method as described in any one of claims 1-27.

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