Process for the one-step preparation of lactide from liquid lactic acid

By using organic solvents containing nitrogen and sulfur and inert gas to remove water, the problems of low hydrolysis efficiency, large amount of polymerization reaction and catalyst deactivation in the one-step preparation of lactide from lactic acid have been solved, realizing efficient continuous production and high yield of lactide.

CN122404280APending Publication Date: 2026-07-17CHINA PETROLEUM & CHEMICAL CORP +1
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Patent Information

Authority / Receiving Office
CN · China
Patent Type
Applications(China)
Current Assignee / Owner
CHINA PETROLEUM & CHEMICAL CORP
Filing Date
2025-01-16
Publication Date
2026-07-17

AI Technical Summary

Technical Problem

In the existing one-step process for preparing lactide from lactic acid, the hydrolysis efficiency is low, the amount of polymerized product is large, the catalyst is easily deactivated, making it difficult to achieve continuous production. Furthermore, the temperature of the azeotropic solvent is difficult to control, affecting the reaction efficiency and catalyst life.

Method used

By mixing nitrogen- and sulfur-containing polar organic solvents such as dimethylpyrrolidone and sulfolane with lactic acid, combined with inert gas to carry away water, and by selecting appropriate reaction temperature and pressure, polymerization reactions can be avoided and catalyst activity can be maintained, thereby achieving high dispersion and continuous production of lactic acid.

Benefits of technology

It improves the conversion rate of lactic acid and the yield of lactide, extends the catalyst life, realizes the efficient and continuous production of lactide in one step, and reduces the amount of polylactic acid generated and the problem of catalyst carbon deposition and deactivation.

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Abstract

提供了液相乳酸一步制备丙交酯的方法,将乳酸原料与选自二甲基吡咯烷酮和环丁砜中的至少一种溶剂混合,并与催化剂接触,于80‑200℃下、‑0.1‑6MPa压力下,乳酸脱水反应生成丙交酯,且所述反应温度及压力使反应体系不发生沸腾,反应的同时向反应体系内通入惰性气体或低沸点惰性溶剂,以将生成的水带出反应体系。本发明基于含氮、硫元素的极性有机溶剂对乳酸具有一定溶解度的发明构思,筛选出两种能实现乳酸一步反应制备丙交酯的有机溶剂,能在反应条件下使乳酸更好地分散,一方面能增加乳酸与固体催化剂的接触,使其反应更完全,降低副产物多聚乳酸的生成,增加丙交酯选择性;另一方面,由于多聚乳酸也能溶于所选择的有机溶剂,所以可降低多聚乳酸在催化剂上的粘附,降低因积碳造成催化剂失活的影响,提高催化剂寿命。
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Citation Information

Patent Citations

  • Method for generating lactide by one-step conversion

    CN112574165A