Floating power generation using submerged volume

A system using two containers with floating bodies to alternately transfer water, generating electricity through pedal rotation, addresses the need for renewable energy sources by efficiently harnessing buoyancy and gravity, exceeding energy consumption.

JP7855170B2Active Publication Date: 2026-05-08浦本 鸿一
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Patent Information

Authority / Receiving Office
JP · JP
Patent Type
Patents
Current Assignee / Owner
浦本 鸿一
Filing Date
2023-09-11
Publication Date
2026-05-08

AI Technical Summary

Technical Problem

The challenge of insufficient renewable energy sources in the face of the demand for decarbonization, particularly in utilizing buoyancy and gravity to generate energy efficiently.

Method used

A system utilizing two containers with floating bodies of equal submerged volume, where water is alternately transferred to move the bodies up and down, generating electricity through the rotation of bicycle pedals connected to a generator.

Benefits of technology

Generates electricity exceeding the energy consumed by the pumping system, utilizing gravity and buoyancy to power a generator, contributing to decarbonization efforts.

✦ Generated by Eureka AI based on patent content.

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Patent Text Reader

Abstract

To provide a floating body power generation of submerged volume which takes out energy by causing a floating body to do vertical movement using attraction and buoyance.SOLUTION: A pedal 5 is connected with a floating body 3 and a pedal 6 is connected with a floating body 4. When water is displaced from a container 2 to a container 1 by a pump 13, the floating body 3 rises up, and the pedal 5 is pushed up, thereupon, water of the container is drawn out, the floating body 4 is lowered and draws down the pedal 6, when such a motion reaches the peak, and water is displaced from the container 1 to the container 2 by the pump 12, the floating body 4 rises up and the pedal 6 is pushed up. Thereupon, water of the container 1 is drawn out, the floating body 3 is lowered and the pedal 5 is lowered. Thus, while repeating such up and down motion, the pedal is rotated and a power generator 9 is driven.SELECTED DRAWING: Figure 1
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Description

[Technical Field]

[0001] This invention addresses the problem of insufficient renewable energy sources in the face of the demand for decarbonization. The inventor conceived the idea that energy could be extracted by using gravity and buoyancy to cause a floating body to move up and down. However, ingenuity was needed in how to extract that energy. Therefore, the inventor prepared two containers, floated a floating body with a submerged volume in each container, and by moving it up and down, applied pressure to rotate it like a bicycle pedal, thereby extracting energy. [Background technology]

[0002] Submerged volume refers to the volume of the part of a ship that is submerged in water. To obtain energy by utilizing the buoyancy of this submerged volume, two containers containing floating bodies of the same volume are prepared, and the water in these containers is alternately transferred using a pump to move the floating bodies up and down. The resulting buoyancy can then be used to rotate bicycle pedals, and the rotation of these pedals can power a generator, thereby generating electricity. [Properties of Submerged Volume]

[0003] The volume of submerged water is the same: 10,000 m³ 3 But it's 10,000 meters high with a base of 1 meter. 2 But, a base of 100m at a height of 100m 2 But, it's 1 meter high and has a base of 10,000 meters. 2 But the volume submerged is 10,000 m³ 3 This is it. If you were to float this object, which has the same three-dimensional shape as the volume of water it is submerged in, in a slightly larger container, it would have a buoyancy of 10,000 tons. If you pour water into this container, it will float, and the pressure it will exert is 10,000 tons × 1,000 = 10,000,000 kg × 9.8 m / s². 2 This equals 98,000,000N. The floating pressure of 10,000 tons is the same regardless of the shape it takes. Relationship between the rise of a floating object in submerged volume and the volume of water

[0004] When a floating body with a submerged volume slightly smaller than the same three-dimensional shape as the container is floated in the container, the amount of water required to raise it is, for example, when the submerged volume is 10,000 tons, a container with a height of 10,003 m and a base of 1.03 m 2 When a floating body is placed in a container with dimensions 2 and floated 3 m, the amount of water required is (3 m × 1.03 m 2 ) + (10,000 m × 0.03 m 2 ) = 3.09 + 300 = 303.9 m 3 However, when the container has a height of 103 m and a base of 100.03 m 2 In a container with a height of 100 m and a base of 100 m 2 When a floating body with a height of 100 m and a base of 100 m is placed and floated 3 m, the amount of water required is (3 m × 100.03 m 2 ) + (100 m × 0.03 m 2 ) = 300.09 + 3 = 303.09 m 3 Similarly, when a floating body with a height of 1 m and a base of 10,000.03 m is placed in a container with a height of 4 m and a base of 10,000.03 m 2 and floated 3 m, the amount of water required is (3 m × 10,000 m 2 ) + (1 m × 0.03 m 2 ) = 30,000 + 0.03 = 30,000.03 m 2 3 When the height is low, the amount of water required becomes extremely large. The amount of water required to raise it by 2 m or 1 m can be calculated in the same way. This is the case when there is a gap between the container and the floating body. If there is no gap, for a height of 10,000 m, it is 3 m × 1 m 2 = 3 m 3 For a height of 100 m, it is 3 m × 100 m 2 = 300 m 3 For a height of 1 m, it is 3 m × 10,000 m 2 = 30,000 m 3The amount of water needed will vary. This difference is, of course, due to the issue of gaps, but since gaps must be created for things like the outlet when filling and draining, it seems that it's not simply a matter of "the higher the better." In addition, there is the issue of whether it can be built, so it's not the case that higher is always better, but it seems that the amount of water needed will be less the higher it is. So I thought that the best way to determine the height would be to make the submerged volume a cube, and I thought that if the length, width and height were the same, the amount of water at the bottom would be balanced by the gaps. [10,000 m 3 [Amount of energy obtainable from the submerged volume]

[0005] If you do this using a bicycle-style pedaling method, the amount you lift off the ground depends on the pedal reach, and the amount of energy you can generate will also change accordingly. For example, with a pressure of 10,000,000 kg, a bicycle arm 1.5 m long, a reach of 3 m, and rotating it once every 3 minutes. The angular velocity is 1 / 3 × 2 × 3.14 ÷ 60 = 0.03488 rad / s. Therefore, whether the bicycle arm is 1m long, the reach is 2m, the arm is 0.5m, or the reach is 1.0m, if all of them rotate once every 3 minutes, the angular velocity will be 0.03488 rad / s. Using the formula for calculating wattage, wattage = pressure (kg) × arm length × angular velocity. Therefore, for a reach of 3m, the calculation is 10,000,000 kg × 9.8 m / s. 2 ×3 × 0.03488 rad / s = 10,254,720W can be generated. This is for one second, so in one hour it will generate 10,254 kWh. For a reach of 2m, the calculation is 10,000,000kg × 9.8m / s 2 ×2 × 0.03488 rad / s = 6,836,480 W = 6,863 kWh. For a reach of 1m, the calculation is 10,000,000kg × 9.8m / s 2 ×1 × 0.03488 rad / s = 3,418,240 W = 3,418 kWh. This is the amount of electricity that can be generated by floating the floating bodies at heights of 3m, 2m, and 1m. However, when the floating body sinks, since the floating body has no weight, two are made in a pair. When one sinks, the other in the pair floats, and this must be covered. 'The amount of water required in the case of (0005)'

[0006] When floating by 3m, for a height of 10,000m, the amount of water required for one floating is 303.09m 3 Since it is necessary and it rotates once in 3 minutes, 60÷3 = 20 times per hour × 303.09m 3 = 6,061.8m of water must be moved per hour. 3 When floating by 3m, for a height of 100m, the amount of water required for one floating is 303.09m 3 Since it is necessary and it rotates once in 3 minutes, 60÷3 = 20 times per hour × 303.09m 3 = 6,061.8m of water must be moved per hour. 3 When floating by 3m, for a height of 1m, the amount of water required for one floating is 30,000.12 3 Since it is necessary and it rotates once in 3 minutes, 60÷3 = 20 times per hour × 30,000.12 = 600,002.4m per hour 3 is required. Also, when floating by 2m, for a height of 10,000m, the amount of water required for one floating is 302.06m 3 Therefore, since it rotates once in 3 minutes, 60÷3 = 20 times per hour × 302.06 = 6041.2m per hour 3 is required. When floating by 2m, for a height of 100m, the amount of water required for one floating is 203.06m 3 Therefore, since it rotates once in 3 minutes, 60÷3 = 20 times per hour × 203.06 = 4061.2m per hour 3 is required. When floating by 2m, for a height of 1m, the amount of water required for one floating is 20,000.03m 3 Therefore, since it rotates once in 3 minutes, 60÷3 = 20 times per hour × 20,000 = 400,000.6m per hour 3 is required. When floating by 1 m, in the case of a height of 10,000 m, the amount of water required for one floating is 301.03 m 3 Therefore, since it rotates once every 3 minutes, 60÷3 = 20 times per hour × 301.03 = 6020.6 m per hour 3 is required. When floating by 1 m, in the case of a height of 100 m, the amount of water required for one floating is 103.03 m 3 Therefore, since it rotates once every 3 minutes, 60÷3 = 20 times per hour × 103.03 = 2060.6 m per hour 3 is required. When floating by 1 m, in the case of a height of 1 m, the amount of water required for one floating is 10,000.03 m 3 Therefore, since it rotates once every 3 minutes, 60÷3 = 20 times per hour × 10,000.03 = 200,000.6 m per hour 3 That's it. [Table of power generation per hour and required water volume due to differences in height and floating distance with the same submerged volume]

[0007] TIFF0007855170000001.tif68152TIFF0007855170000002.tif20152Theoretically, the higher the height of the floating body, the less water can be used for floating. However, considering the gap between the floating body with the submerged volume and the container and the flow of the injected water, it doesn't seem that the higher one is always better. I think it might be optimal to make a floating body with a submerged volume in a cube shape close to a sphere in terms of volume. Since it's the floating distance, if the submerged volume is the same, the ratio of the required water volume to the power generation is the same. If the power generation is the same, increasing the moving distance can reduce the floor area used. [Make two combinations of a container with a floating body of submerged volume and use them as a pair]

[0008] Buoyancy is upward, and when descending, the floating body has no weight and therefore no gravitational force. To move it up and down, it is necessary to use the upward force of another floating body in a pair, so a combination of two is required, and two containers containing floating bodies of the same volume as the submerged water must be combined. The reason for combining two is that when one floats, the other will descend, so the water is drained from one, and that drained water is transferred to the other, making that one float, thus killing two birds with one stone. [Power consumption of the pump]

[0009] Terada Pump's Cell-Pla Pump 150mm diameter has a discharge volume of 3.2m³. 3 It has a total head of 38m / min and a power consumption of 37kw. Using this pump, 10,000m 3 With a submerged volume of 100m, the floating body reaches the top and hits the limit switch on the floor above. At the same time, the pump that was previously drawing water from the adjacent container and filling it to keep it afloat is stopped, and to transfer the water from the current container to the container from which it was previously drawn, water is drawn from the opposite side and poured into the floating body, which is 3m lower in the submerged volume of the adjacent container. The lower position becomes 3m higher, and the pumping side becomes 3m lower, but since the water level only differs by 3m, the head is 3m. 6,780m per hour 3 To pump water, approximately 6,780 ÷ 3.2 ÷ 60 ≈ 35.4 pumps are needed. The power consumption per pump is 37 kWh, so 35.4 pumps would consume 1,310 kWh. However, this assumes that the same number of pumps are used when filling the other side as well. In reality, it is possible to double the number of pumps and alternate filling half the water at a time to allow one side to rest. In this case, the power consumption remains the same at 1,310 kW. However, this calculation is based on ideal conditions, and in reality, factors such as pump efficiency and piping resistance must be considered. Furthermore, the discharge port, discharge volume, total head, and power consumption vary depending on the pump design. Therefore, to choose the optimal pump, it is best to consult with a pump manufacturer and determine the specifications that meet your requirements. [Electricity that can be obtained]

[0010] 10,000m 3 With a submerged volume of 100m in height and a head of 3m, two pumps working together can generate 10,254kWh of power. Subtracting the pump's power consumption of 1,310kWh leaves 8,944kWh. Even assuming a 50% operating rate, this would still be 4,472kWh. [A method to reduce the load on the pump by shortening the lifting height when transferring between two containers.]

[0011] In a container with a floating body the same volume as the submerged water, the water level always maintains a height that submerges the submerged body. Therefore, the water level will be up to the top of the submerged body, and if there is a water inlet below that top level, the water will be drawn up. The outlet must be attached to the top of the container because the floating body will float, so to fill the bottom with water, it is best to drop it from above, and pouring from below would require pressure, which is disadvantageous. Furthermore, emptying the water from the container containing the float is only necessary at the beginning to lower the float without applying any load. Once operation begins, the motor's load is constantly applied, causing the bottom to touch the bottom of the container. It must be floated immediately, and water must be injected at that point to raise the float. The water level in the container stops at the water level of the container where the float is located and does not drop any further. Therefore, it is sufficient to have the water inlet below that water level, and there is no need to suck water up from the bottom. Method for switching the vertical movement of a floating object with a submerged volume.

[0012] When the float in one container rises to its highest point due to the rising water level, the top of the float touches a limit switch mounted on the ceiling above, and the power to the water pump motor is cut off. Water injection into that container stops, and at the same time, the motor switches to the opposite container, the pump in the other container starts running, and water injection into the other container begins. This process is repeated, with the floats in the two containers moving up and down in opposite directions, rotating the pedal and continuously rotating the generator to generate electricity. What to do if the load is insufficient and the water level does not reach the submerged volume?

[0013] The floating body sinks according to the load, but even with a small load, if the floating body reaches its peak, a limit switch activates and a pump is used to adjust the buoyancy. The limit switch is installed at the top of the floating body and activates when the floating body floats and reaches its peak. The pump is switched on by contact with the limit switch and adjusts the buoyancy by transferring water from one container to another. This mechanism allows for automatic adjustment of the floating body's submerged volume from the time the generator is installed until the peak season. [Overview of the Initiative]

[0014] Prepare two cubic containers, each containing a slightly smaller float, to form a pair. Pour water into one of the containers to make the float buoyant. The float's force pushes the pedal upward, turning the generator. When the pedal reaches its peak, a pump transfers the water to the other container. This causes the float on the opposite side to rise, pushing up the pedal on the other side. Simultaneously, the float that pushed up the pedal loses its water and descends, pulling the pedal down. In this way, the pedal rotates and electricity is generated. As explained in (0007), (0008), (0009), and (0010), if the floating body is made taller, it will be subjected to a stronger gravitational force, increasing its buoyancy. If electricity is obtained in this way, the amount of electricity generated will exceed the amount of electricity consumed by the pump, and electricity can be obtained. [Effects of the Invention]

[0015] This power generation device can decarbonize and reduce carbon emissions by utilizing gravity and buoyancy. [Brief explanation of the drawing]

[0016] [Figure 1] Layout diagram (front view): This diagram shows the layout of the wiring to the motor, the piping for the pump, and the connections to those points. [Figure 2] Layout Diagram (Floor Plan): This floor plan diagram makes the parts that were unclear in the above diagram easier to understand. [Figure 3] Diagram showing the operation status of the selector switch for the pump motor. [Figure 4] Floating structure operation status diagram [Modes for carrying out the invention]

[0017] This device alternately transfers water to containers 1 and 2, causing the floats 3 and 4 to float alternately. This buoyancy is transmitted to pistons 7 and 8, which push up pedals 5 and 6, rotating a shaft that powers a generator 9 to generate electricity. A portion of this electricity is used to power motors 11 and 12, which in turn power pumps 13 and 14 to transfer water to containers 1 and 2, causing the floats to move up and down. The buoyancy of these floats generates more electricity. Sections (0007), (0008), (0009), and (0010) explain that even after using some of this electricity to power the pumps, more electricity can still be generated. [Explanation of symbols] (0018) (Figure 1) (Figure 2) (Layout diagram) Symbol Symbol 1 is the container for holding the float symbol 3 on the left side. Symbol 2 is the container for the float symbol 4 on the right side. The symbol 3 is a floating object to be placed in the left-hand side of symbol 1. The symbol 4 is a floating object to be placed in the right-hand side, symbol 2. Symbol 5 is the pedal that transmits the buoyancy of the floating body 3 to rotate the generator. Symbol 6 is a pedal that transmits the buoyancy of the floating body 4 to rotate the generator. Reference numeral 7 denotes the piston connecting the floating body 3 and the pedal 5. Reference numeral 8 denotes the piston connecting the floating body 4 and the pedal 6. Symbol 9 is a generator Symbol 10 is a switchboard Reference numeral 11 denotes the electric motor that operates the pump on the left side. Reference numeral 12 denotes the electric motor that operates the pump on the right side. Symbol 13 is a pump that transfers water from the container on the left to the container on the right. Symbol 14 is a pump that transfers water from the container on the right to the container on the left. Reference numeral 15 denotes the shaft that transmits rotation to the generator via pedals 5 and 6. Reference numeral 16 denotes a floor for installing a generator or pump. Reference numeral 17 denotes a pipe that transfers water from the pump 13 to the container 2. Reference numeral 18 denotes a pipe that transfers water from the pump 14 to the container 1. Reference numeral 19 denotes a suction pipe that pumps water from container 1 by pump 13 and sends it to reference numeral 17. Reference numeral 20 denotes a suction pipe that pumps water from container 2 by pump 14 and sends it to reference numeral 18. Reference numeral 21 denotes a selector switch that switches the operation of the motors that power pumps 13 and 14. [This switching process is explained in (Figure 3)] Symbol 22 indicates the wiring connecting motor 11 from distribution panel 10. Symbol 23 indicates the wiring connecting motor 12 from distribution panel 10. Reference numeral 24 denotes the wiring connecting motor-11 to changeover switch 21. Reference numeral 25 denotes the wiring connecting motor-12 to changeover switch 21. Symbol 26 indicates the wiring connecting the changeover switch 21 from the distribution panel 10. From point 26, whether you connect to 24 or 25, motors 11 and 12 will operate alternately. Symbol 27 is the wiring that sends electricity from the generator to the switchboard. There, it adjusts the circuit and sends power to the outside, while simultaneously activating the pump that transfers water from the container and the motor. Reference numeral 28 denotes an external power transmission line. (Figure 3) Symbols for the pump motor selector switch Symbol 1 is the container for holding the floating object 3 on the left side. The symbol 2 represents the container for holding the floating body 4 on the right side. Symbol 3 is a float placed in container 1 on the left side. Reference numeral 4 denotes a float to be placed in container 2 on the right side. TIFF0007855170000003.tif9131 The tip touches the wire terminal 9, which is connected to the distribution board 11, and connects to the wiring 20, causing the motor 12 to rotate, the pump 14 to operate, and the water supply pipe 18 TIFF0007855170000004.tif9124 moves to the right side, and even if the limit switch on the left side goes down, the 9 wire terminals remain connected. TIFF0007855170000005.tif8125 remains connected. TIFF0007855170000006.tif10126 The tip touches the wire terminal 10, connects to the wiring 20 which is connected to the distribution board 11, and the motor 13 turns, the pump 15 starts operating and the water supply pipe 19 TIFF0007855170000007.tif9125 moves to the left side, and even if the limit switch on the right side goes down, 10 wire terminals The lines in TIFF0007855170000008.tif9124 remain connected. TIFF0007855170000009.tif9126 Code 8 is a weight (this is because the limit switch connects to wire terminals 9 and 10 but immediately drops down, preventing continuous contact between codes 9 and 10, so a weight is used to prevent this) In TIFF0007855170000010.tif890, code 9 is the wire terminal on the left side (connected to motor 12 by wiring 22). Reference numeral 10 denotes the wire terminal on the right side (connected to motor-13 by wiring 23). Symbol 11 is a switchboard Reference numeral 12 denotes the motor that operates the pump 14. Reference numeral 13 denotes the motor that operates the pump 15. Reference numeral 14 denotes the pump on the left side (a pump that draws water from container 1 through the suction pipe 18 and transfers the water to container 2 through the transfer pipe 16). Reference numeral 15 denotes the pump on the right side (a pump that draws water from container 2 through the suction pipe 19 and transfers the water to container 1 through the transfer pipe 17). Reference numeral 16 denotes a transfer pipe that sends water from the pump (reference numeral 14) to the container 2. Reference numeral 17 denotes a transfer pipe that sends water from the pump reference numeral 15 to container 1. Reference numeral 18 denotes the suction pipe through which the pump 14 draws water from the container of reference numeral 1. Reference numeral 19 denotes a suction tube that draws water from the container of reference numeral 2 using the pump 15. TIFF0007855170000011.tif987 Code 21 is the wiring connecting motor 12, which operates pump 14, and motor 13, which operates pump 15, from the distribution panel of code 11. Reference numeral 22 denotes the wiring connecting motor-12 and terminal 9. Reference numeral 23 denotes the wiring connecting motor-13 and terminal 10. TIFF0007855170000012.tif846 (Figure 4) Symbols for the floating body operation status diagram Reference numeral 1 denotes the container for holding the float 3. Reference numeral 2 denotes the container for holding the float 4. Reference numeral 3 denotes a float that enters container 1. Reference numeral 4 denotes a float that enters container 2. Symbol 5 is connected to the floating body 3 and the pedal Symbol 6 is connected to the pedal of floating body 4. Reference numeral 7 denotes the piston connecting the floating body 3 and the pedal 5. Reference numeral 8 denotes the piston connecting the floating body 4 and the pedal 6. Symbol 9 is a generator Reference numeral 10 denotes the motor that operates the pump of reference numeral 12. Reference numeral 11 denotes the motor that operates the pump of reference numeral 13. Reference numeral 12 denotes a pump that transfers water from container 1 to container 2. Reference numeral 13 denotes a pump that transfers water from container 2 to container 1. Reference numeral 14 denotes the motor-switch for pump operation. Reference numeral 15 denotes the shaft that rotates the generator. The symbol represents the water surface. Figure A shows that the floating body of the container on the left side reaches its peak, and the limit switch on the motor switch for pump operation (indicated by reference numeral 14) presses the pump switch, starting the operation of pump 12. As a result, water from container 1 begins to transfer to container 2, and floating body 4 gradually rises while floating body 3 sinks, leading to Figure B. The water levels of floating body 3 and floating body 4 become the same, and from here floating body 4 rises further while floating body 3 sinks, reaching the state shown in Figure C. Floating body 4 on the left side reaches its peak, and the limit switch presses the pump operation switch (indicated by reference numeral 14), causing motor 11 (opposite of 12) to rotate and start pump 13, sending water from container 2 to container 1. Floating body 3 begins to rise and floating body 4 begins to sink, moving to Figure D. Pump 13 continues to operate thereafter, reaching the state shown in Figure A, and this is repeated. As the floating body continues to move upwards, this motion is transmitted to the pedal by the piston, which rotates the shaft, which in turn rotates the generator and generates electricity. Industrial applicability

[0019] Gravity is an energy source that exists everywhere in the world. By utilizing it, we can generate buoyancy in water, and by applying or removing force, we can move a floating object up and down, and generate electricity from that power. What I want to emphasize here is that, as mentioned earlier in (0007), (0008), (0009), and (0010), the power generated exceeds the power consumption of the pump required, so electricity can be obtained. Furthermore, hydrogen can also be produced using that electricity.

Claims

[Claim 1] A method of generating electricity by placing a floating body inside a container, injecting or discharging a fluid into the container to raise or lower the floating body, and generating electricity based on the change in the floating body's buoyancy, The floats are cubic in shape, and the containers are also cubic in shape, slightly larger than the floats. Two of the containers, each containing a float, form a pair, and these pairs of containers are placed next to each other. A pump alternately transfers fluid between the two pairs of containers, causing the two floats to alternately move up and down. This transmits the buoyancy of the floats to a piston, which pushes up a pedal, rotating a shaft that transmits rotation to a generator, thereby generating electricity. This is a method of generating electricity by changing the buoyancy of the floats.

Citation Information

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