Calculation device, calculation method, and calculation program
The calculation device and method address the excessive stiffness issue in composite slabs by calculating neutral axes and force ratios in both directions, resulting in cost-effective designs.
Patent Information
- Application Number
- JP2024074255
- Authority / Receiving Office
- JP · JP
- Patent Type
- Applications
- Current Assignee / Owner
- Filing Date
- 2024-05-01
- Publication Date
- 2025-11-14
AI Technical Summary
Existing composite slabs designed with unidirectional deck plates and concrete assume that only the crest-valley extension direction bears the load, leading to excessive stiffness requirements and increased costs.
A calculation device, method, and program that calculate the positions of neutral axes and force ratios in both directions of a composite slab, considering the load distribution in both the crest-valley extension and continuation directions, allowing for reduced material usage and cost.
Enables the design of cost-effective composite slabs by accurately accounting for load distribution in both directions, reducing material requirements without compromising structural integrity.
Smart Images

Figure 2025169519000001_ABST
Abstract
Description
[Technical Field]
[0001] The present invention relates to a computing device, a computing method, and a computing program, and more particularly to a computing device, a computing method, and a computing program that are capable of computing data for designing a unidirectional composite slab. [Background technology]
[0002] BACKGROUND ART Composite slabs are known that are made by combining concrete and a unidirectional deck plate (see, for example, Patent Document 1).
[0003] Such composite slabs have unidirectional properties because they are made by compounding concrete with a unidirectional deck plate. A deck plate (hereinafter referred to as a "composite deck plate") for constructing such a unidirectional composite slab may be a deck plate in which peaks and valleys are continuously formed, as shown in Patent Document 1, for example. In such a composite deck plate, each of the peaks and valleys extends in a direction (hereinafter referred to as a "peak-valley extension direction" for convenience) perpendicular to the direction in which the peaks and valleys are continuous (hereinafter referred to as a "peak-valley extension direction" for convenience). With this configuration, the composite deck plate has greater rigidity in the peak-valley extension direction than in the peak-valley extension direction. Therefore, a composite slab made of such a composite deck plate and concrete generally has unidirectional properties in the peak-valley extension direction.
[0004] The composite deck plate is not limited to a deck plate having continuous peaks and valleys. [Prior art documents] [Patent documents]
[0005] [Patent Document 1] Japanese Patent Application Publication No. 2023-147101 Summary of the Invention [Problem to be solved by the invention]
[0006] When designing a composite slab made of composite deck plate and concrete as described above, it has been assumed that because the composite slab has one-way crest-valley extension, only the component in the crest-valley extension direction of the compressive force acting on the composite slab is borne by the component, in other words, that only both edges of the composite slab in the crest-valley extension direction are fixed to the beams. In other words, the composite slab has been designed without taking into account that the component in the crest-valley continuous direction of the composite slab is borne by the load, in other words, without taking into account that both edges of the composite slab in the crest-valley continuous direction are fixed to the beams.
[0007] This design method for composite slabs allows for greater freedom in designing the length of the continuation of peaks and valleys, since only the stiffness in the direction of peak-valley extension needs to be considered. However, because the load borne by the component in the direction of peak-valley extension is not taken into consideration, it is necessary to design the composite slab so that its stiffness is excessively large, which increases the cost of the composite slab.
[0008] The present invention has been made in consideration of the above points, and one of its objectives is to provide a calculation device, a calculation method, and a calculation program that can calculate data that can be used to design cost-reduced composite slabs. [Means for solving the problem]
[0009] (1): The calculation device of the present invention is a calculation device capable of calculating data usable for designing a composite slab having one directionality, wherein the composite slab has, on one side in the thickness direction of the composite slab, a flat main surface extending in a first direction that defines the one directionality and a second direction that is perpendicular to both the first direction and the thickness direction, and the calculation device is equipped with a memory unit that stores the position of a first neutral axis of a cross section of the composite slab in the first direction as a distance in the thickness direction from the main surface, a first calculation unit that calculates the position of a second neutral axis of a cross section of the composite slab in the second direction as a distance in the thickness direction from the main surface, and a second calculation unit that calculates the ratio of a second force applied to a component of the first force in the first direction of the composite slab to a first force pushing the composite slab in the thickness direction based on the position of the first neutral axis and the position of the second neutral axis.
[0010] (2): In the calculation device of (1), the composite slab includes a deck plate whose peaks and valleys are continuous in the second direction, and concrete poured on the deck plate, and the first calculation unit may calculate the position of the second neutral axis by calculating the peak portion of the concrete that is on the opposite side of the peak from the valley in the thickness direction.
[0011] (3): In the calculation device of (2), the first calculation unit sets the position of the second neutral axis as Ac (mm) and the Young's modulus of the concrete as Ec (N / mm 2 ) and the Young's modulus of the deck plate is Es (N / mm 2 ), the thickness of the deck plate is t (mm), and the sum of the thickness of the convex portion of the concrete and the thickness of the deck plate is T (mm), and the position Ac may be calculated based on the following formula (A): Ac 2 =2×(Es / Ec)×t×(T-Ac)...(A)
[0012] (4): In the calculation device of (2) or (3), the second calculation unit calculates the first force as Pm (N / m2 ), and the second force is Pe (N / m 2 ), the position of the first neutral axis is Ae (mm), the position of the second neutral axis is Ac (mm), the length of the composite slab in the first direction is Lx (m), and the length of the composite slab in the second direction is Ly (m), and the ratio (Pe / Pm) of the second force to the first force may be calculated based on the following equation (B): Pe / Pm={(2Ae / 2Ac) 3 ×(Ly / Lx) 3} / {1+(2Ae / 2Ac) 3 ×(Ly / Lx) 3}···(B)
[0013] (5): The calculation method of the present invention is a calculation method for calculating data that can be used to design a unidirectional composite slab, wherein the composite slab has, on one side in the thickness direction of the composite slab, a flat main surface extending in a first direction that defines the unidirectionality and in a second direction that is perpendicular to both the first direction and the thickness direction, and the calculation method includes a storage step for storing the position of a first neutral axis of a cross section of the composite slab in the first direction as a distance in the thickness direction from the main surface, a first calculation step for calculating the position of a second neutral axis of a cross section of the composite slab in the second direction as a distance in the thickness direction from the main surface, and a second calculation step for calculating the ratio of a second force applied to a component of the first force in the first direction of the composite slab to a first force pushing the composite slab in the thickness direction based on the position of the first neutral axis and the position of the second neutral axis.
[0014] (6): In the calculation method of (5), the composite slab may include a deck plate whose peaks and valleys are continuous in the second direction, and concrete poured on the deck plate, and in the first calculation step, the position of the second neutral axis may be calculated by calculating the peak portion of the concrete that is on the opposite side of the peaks from the valleys in the thickness direction.
[0015] (7): In the calculation method of (6), in the first calculation step, the position of the second neutral axis is set to Ac (mm), and the Young's modulus of the concrete is set to Ec (N / mm 2 ) and the Young's modulus of the deck plate is Es (N / mm 2 ), the thickness of the deck plate is t (mm), and the sum of the thickness of the convex portion of the concrete and the thickness of the deck plate is T (mm), and the position Ac may be calculated based on the following formula (A): Ac 2 =2×(Es / Ec)×t×(T-Ac)...(A)
[0016] (8): In the calculation method of (6) or (7), in the second calculation step, the first force is calculated as Pm (N / m 2 ), and the second force is Pe (N / m 2 ), the position of the first neutral axis is Ae (mm), the position of the second neutral axis is Ac (mm), the length of the composite slab in the first direction is Lx (m), and the length of the composite slab in the second direction is Ly (m), and the ratio (Pe / Pm) of the second force to the first force may be calculated based on the following equation (B): Pe / Pm={(2Ae / 2Ac) 3 ×(Ly / Lx) 3} / {1+(2Ae / 2Ac) 3 ×(Ly / Lx) 3}···(B)
[0017] (9): The calculation program of the present invention is a calculation program that causes a calculation device capable of calculating data that can be used for designing a unidirectional composite slab to perform calculations, wherein the composite slab has, on one side in the thickness direction of the composite slab, a flat main surface extending in a first direction that defines the unidirectionality and a second direction that is perpendicular to both the first direction and the thickness direction, and the calculation program executes a storage step that stores the position of a first neutral axis of a cross section of the composite slab in the first direction as a distance in the thickness direction from the main surface, a first calculation step that calculates the position of a second neutral axis of a cross section of the composite slab in the second direction as a distance in the thickness direction from the main surface, and a second calculation step that calculates the ratio of a second force applied to a component of the first force in the first direction of the composite slab to a first force pushing the composite slab in the thickness direction based on the position of the first neutral axis and the position of the second neutral axis.
[0018] (10): In the calculation program of (9), the composite slab may include a deck plate whose peaks and valleys are continuous in the second direction, and concrete poured on the deck plate, and the first calculation step may be executed to calculate the position of the second neutral axis by treating the peak portion of the concrete that is on the opposite side of the valley portion from the peak portion in the thickness direction as the calculation object.
[0019] (11): In the calculation program of (10), the position of the second neutral axis is set to Ac (mm), and the Young's modulus of the concrete is set to Ec (N / mm 2 ) and the Young's modulus of the deck plate is Es (N / mm 2 ), the thickness of the deck plate is t (mm), and the sum of the thickness of the convex portion of the concrete and the thickness of the deck plate is T (mm), and the first calculation step may be executed to calculate the position Ac based on the following formula (A): Ac 2 =2×(Es / Ec)×t×(T-Ac)...(A)
[0020] (12): In the calculation program of (10) or (11), the first force is Pm (N / m 2 ), and the second force is Pe (N / m 2 ), the position of the first neutral axis is Ae (mm), the position of the second neutral axis is Ac (mm), the length of the composite slab in the first direction is Lx (m), and the length of the composite slab in the second direction is Ly (m), and the second calculation step may be executed to calculate the ratio (Pe / Pm) of the second force to the first force based on the following equation (B): Pe / Pm={(2Ae / 2Ac) 3 ×(Ly / Lx) 3} / {1+(2Ae / 2Ac) 3 ×(Ly / Lx) 3}···(B) [Effects of the Invention]
[0021] According to the present invention, there are provided a calculation device, a calculation method, and a calculation program capable of calculating data that can be used to design a composite slab at reduced cost. [Brief explanation of the drawings]
[0022] [Figure 1] FIG. 1 is a perspective view of a portion of a unidirectional composite slab according to an embodiment of the present invention. [Figure 2] FIG. 1 is a functional block diagram illustrating a computing device according to an embodiment of the present invention. [Figure 3] 1A and 1B are diagrams for explaining the first neutral axis, where (A) is a diagram showing a cross section including the first neutral axis, and (B) is a diagram schematically showing a part of the cross section of (A) for explaining the first neutral axis. [Figure 4] 1A and 1B are diagrams for explaining the second neutral axis, in which (A) is a diagram showing a cross section including the second neutral axis, and (B) is a diagram schematically showing a part of the cross section of (A) for explaining the second neutral axis. [Figure 5] FIG. 1 is a diagram illustrating the concept for deriving formula (A). [Figure 6] FIG. 1 is a diagram for explaining the concept for deriving formula (B). [Figure 7] FIG. 1 is a diagram for explaining the concept for deriving formula (B). [Figure 8] 3 is a table showing a first example of a ratio Pe / Pm calculated by the calculation device shown in FIG. 2. [Figure 9] 10 is a table showing a second example of the ratio Pe / Pm calculated by the calculation device shown in FIG. 2. [Figure 10] 10 is a table showing a third example of the ratio Pe / Pm calculated by the calculation device shown in FIG. 2 . [Figure 11] FIG. 2 is a flow diagram illustrating a calculation method according to an embodiment of the present invention. DETAILED DESCRIPTION OF THE INVENTION
[0023] Below, embodiments for implementing a computing device, a computing method, and a computing program according to the present invention are illustrated with the accompanying drawings. The embodiments illustrated below are intended to facilitate understanding of the present invention and are not intended to limit the present invention. The present invention can be modified or improved from the following embodiments without departing from the spirit of the present invention. Furthermore, in the accompanying drawings, the dimensions of each component may be exaggerated or reduced, and hatching may be omitted, in order to facilitate understanding.
[0024] Fig. 1 is a perspective view showing a portion of a one-way composite slab according to an embodiment. As shown in Fig. 1, the composite slab 100 includes a deck plate 110 and concrete 101 poured on the deck plate 110. When viewed in the thickness direction Z, the composite slab 100 appears rectangular or square.
[0025] The deck plate 110 has a shape in which peaks 111 and valleys 112 are alternately and continuously formed in the second direction Y. That is, the second direction Y is a peak-valley continuous direction in which the peaks 111 and valleys 112 of the deck plate 110 are continuous. Each of the peaks 111 and valleys 112 extends in a first direction X that is perpendicular to both the thickness direction Z and the second direction Y. That is, the first direction X is a peak-valley extending direction in which the peaks 111 and valleys 112 of the deck plate 110 extend. In such a deck plate 110, the rigidity in the first direction X in which the peaks 111 and valleys 112 extend tends to be greater than the rigidity in the second direction Y in which the peaks 111 and valleys 112 are continuous.
[0026] Incidentally, when a rectangular plate-shaped member is imagined as viewed in the thickness direction Z, the rigidity of the plate-shaped member tends to be greater in the short side direction than in the long side direction.
[0027] In this embodiment, the deck plate 110 is formed so that the first direction X, which is the direction in which the peaks and valleys extend, is the short side direction, and the second direction Y, which is the direction in which the peaks and valleys continue, is the long side direction. Therefore, the overall length Lx (m) of the deck plate 110 in the first direction X is shorter than the overall length Ly (m) of the deck plate 110 in the second direction Y. With this configuration, the deck plate 110 has unidirectionality in the first direction X. Note that even when the deck plate 110 is formed so that the first direction X, which is the direction in which the peaks and valleys extend, is the long side direction and the second direction Y, which is the direction in which the peaks and valleys continue, is the short side direction, it still has unidirectionality in the first direction X, although this is inferior to when the deck plate 110 is formed so that the first direction X is the short side direction and the second direction Y is the long side direction.
[0028] The concrete 101 is poured over the entire surface of the deck plate 110 on the side (upper side) where the peaks 111 protrude in the thickness direction Z. Therefore, the total length of each of the concrete 101 and the composite slab 100 in the first direction X is equal to the total length of the deck plate 110, Lx, and the total length of each of the concrete 101 and the composite slab 100 in the second direction Y is equal to the total length of the deck plate 110, Ly. By pouring the concrete 101 onto the deck plate 110, in which the peaks 111 and valleys 112 are continuous, the concrete 101 and the deck plate 110 are combined while preventing them from shifting from one another. The composite slab 100 is constructed in this manner, and the deck plate 110 that constitutes the composite slab 100 functions as a so-called composite deck plate. The composite slab 100 is formed by combining the concrete 101 with the deck plate 110, which has unidirectionality in the first direction X, and therefore has unidirectionality in the first direction X, similar to the deck plate 110.
[0029] The surface of one side of the concrete 101 in the thickness direction Z (the upper side opposite the deck plate 110 side) is a flat surface. Hereinafter, this surface of the concrete 101 will be referred to as the main surface 101MF. In other words, the composite slab 100 has, on one side in the thickness direction Z of the composite slab 100, a flat main surface 101MF that extends in a first direction X that defines unidirectionality and in a second direction Y that is perpendicular to both the first direction X and the thickness direction Z.
[0030] Next, a calculation device capable of calculating data that can be used to design such a unidirectional composite slab 100 will be described.
[0031] Fig. 2 is a functional block diagram showing a calculation device capable of calculating data usable for designing a composite slab 100. The calculation device 1 is configured, for example, by a computer including a CPU (Central Processing Unit), memory, and an interface. As shown in Fig. 2, the calculation device 1 includes, as main functional blocks, a control unit 10, an input unit 11, a memory unit 12, a first calculation unit 13, a second calculation unit 14, and a display unit 15.
[0032] The control unit 10 is a CPU that performs overall control of the entire arithmetic device 1 and executes various processes. For example, when the control unit 10 receives an electrical signal from the input unit 11, it reads out data stored in the memory unit 12, causes the first arithmetic unit 13 and the second arithmetic unit 14 to execute predetermined calculations, and causes the display unit 15 to display data obtained by the calculations performed by the first arithmetic unit 13 and the second arithmetic unit 14, in response to the electrical signal.
[0033] The input unit 11 is an input means such as a keyboard or a mouse. The display unit 15 may be, for example, a display capable of displaying various information. The display unit 15 may display, for example, a screen for inputting numerical values or the like to cause the first calculation unit 13 and the second calculation unit 14 to perform calculations, or may display data obtained by calculations performed by the calculation device 1. A user of the calculation device 1 may input various data, such as predetermined numerical values, into input fields or the like displayed on the display unit 15 via the input unit 11. After inputting the data, the user may press, for example, an execute button or the like on the input unit 11 to cause the calculation device 1 to perform calculations.
[0034] The storage unit 12 includes a ROM (Read Only Memory), a RAM (Random Access Memory), etc. The storage unit 12 stores various data and programs necessary for the calculation device 1 to execute calculations. The various programs include, for example, programs executed by the first calculation unit 13 and the second calculation unit 14. The various data also includes data related to the position of a first neutral axis, which will be described later. The neutral axis refers to a position in a cross section where no tension or compression occurs when a bending moment is applied.
[0035] Here, the first neutral axis will be described. Figure 3 is a diagram for explaining the first neutral axis. Specifically, Figure 3(A) is a diagram showing a cross section including the first neutral axis, and Figure 3(B) is a diagram schematically showing a part of the cross section of Figure 3(A) for explaining the first neutral axis.
[0036] As shown in FIG. 3(A), the composite slab 100 includes a cross section SF1 in the first direction X (the cross section SF1 when viewed in the first direction X). As shown in FIG. 3(B), the cross section SF1 includes a first neutral axis NA1 when the cross section SF1 is bent in the second direction Y. In the thickness direction Z, the first neutral axis NA1 is located at a distance Ae (mm) from the main surface 101MF of the concrete 101 (i.e., the main surface 101MF of the composite slab 100) toward the deck plate 110 (bottom side). The memory unit 12 stores the position Ae of the first neutral axis NA1 of the cross section SF1 as data of the distance (height) in the thickness direction Z from the main surface 101MF.
[0037] As described above, the composite slab 100 has unidirectional properties in the first direction X. Conventionally, such unidirectional composite slabs have been designed on the assumption that the load applied to the composite slab is borne solely by the component in the first direction, which is the crest-to-valley extension direction. In other words, it is assumed that only both edges of the composite slab in the first direction are fixed to beams. Therefore, data on the position Ae of the neutral axis (first neutral axis NA1) of the cross section SF1 in the first direction X is known for each shape of the composite deck plate. Examples of the shape of the composite slab or composite deck plate include the thickness (height) t (mm) of the composite deck plate, the distance (height) Dh (mm) from the crest 111 to the valley 112 in the thickness direction Z, and the thickness (height) Tu (mm) of the crest portion 102 of the concrete 101 located on the opposite side of the crest 111 from the valley 112 in the thickness direction Z. 3(B), for convenience, the lower end of the peak portion 102 is indicated by a dashed line. The memory unit 12 stores data on the position Ae (mm) of the first neutral axis NA1 corresponding to each shape (type) of such composite deck plate.
[0038] Each of the first calculation unit 13 and the second calculation unit 14 may include, for example, a microprocessor or a DSP (Digital Signal Processor). Each of the first calculation unit 13 and the second calculation unit 14 is realized by the cooperation of the hardware resources constituting the calculation device 1 with basic software, which is application software pre-installed in the calculation device 1, and various other software (for example, various software including calculation programs executed by each of the first calculation unit 13 and the second calculation unit 14). Examples of the hardware resources constituting the calculation device 1 include a CPU constituting the control unit 10, a ROM and RAM constituting the storage unit 12, a keyboard constituting the input unit 11, and a display constituting the display unit 15.
[0039] In this embodiment, the first calculation unit 13 calculates the position Ac (mm) of the second neutral axis NA2 (described later) of the cross section SF2 in the second direction Y of the composite slab 100 (the cross section SF2 when viewed looking in the second direction Y) as the distance in the thickness direction Z from the main surface 101MF based on the following formula (A): Ac 2 =2×(Es / Ec)×t×(T-Ac)...(A) In formula (A), Ec is the Young's modulus of concrete (N / mm 2 ), and Es represents the Young's modulus of the deck plate 110 (N / mm 2 ) and as mentioned above, t represents the thickness (mm) of the deck plate 110, and T represents the height (mm) of the cross section SF2, which is the sum of the thickness Tu of the convex portion 102 of the concrete 101 and the thickness t of the deck plate 110 (in other words, the thickness (mm) of the composite slab 100).
[0040] Formula (A) will be explained in detail below.
[0041] Fig. 4 is a diagram for explaining the second neutral axis. Specifically, Fig. 4(A) is a diagram showing a cross section including the second neutral axis, and Fig. 4(B) is a diagram schematically showing a part of the cross section of (A) for explaining the second neutral axis.
[0042] As shown in FIG. 4(A), the composite slab 100 includes a cross section SF2 in the second direction Y (the cross section SF2 when viewed in the second direction Y). As shown in FIG. 4(B), the cross section SF2 includes a second neutral axis NA2 when the cross section SF2 is bent in the first direction X. In the thickness direction Z, the second neutral axis NA2 is located at a distance Ac (mm) from the main surface 101MF of the concrete 101 (i.e., the main surface 101MF of the composite slab 100) toward the deck plate 110 side (lower side).
[0043] As described above, conventionally, composite slabs have been designed on the assumption that the load applied to the composite slab is borne only by the component in the crest-valley direction, in other words, that only both edges of the composite slab in the crest-valley direction are fixed to beams. Therefore, composite slabs have been designed without considering the load borne by the component in the second direction Y, which is the crest-valley continuation direction of the composite slab. In other words, without considering that both edges of the composite slab in the second direction Y are fixed to beams. Therefore, conventionally, there was no knowledge about the position Ac of the neutral axis (second neutral axis NA2) of cross section SF2. Therefore, as a result of extensive research, the inventors have devised the following method for deriving position Ac.
[0044] The composite slab 100 is formed by combining the deck plate 110 and concrete 101 using the peaks 111 and valleys 112 of the deck plate 110 or various uneven structures (such as dovetail grooves and embossments). In light of this combination, the composite slab 100 can be considered a slab formed by joining the peaks 111 of the deck plate 110 to the concrete consisting only of the peaks 102 (hereinafter sometimes simply referred to as the "peaks 102"). Therefore, as shown in FIG. 4(B), the cross section SF2 can be considered a rectangular surface consisting of the peaks 111 and the peaks 102. The second neutral axis NA2 is the neutral axis of this rectangular cross section SF2. In FIG. 4(A), the lower end of the peaks 102 is indicated by a dashed line for convenience.
[0045] Here, as shown in FIG. 5, consider a rectangular composite slab 100A having a surface SF2' as its end surface in the second direction Y. The surface SF2' has a configuration similar to that of the cross section SF2, which is composed of a ridge portion 111 (deck plate) and a ridge portion 102 (concrete). Hereinafter, the surface SF2' will be referred to as the "end surface SF2'." The composite slab 100A has a concrete 101 (ridge portion 102) having a thickness Tu and a deck plate 110 (ridge portion 111) having a thickness t, which has a main surface 101MF. Therefore, the height of the composite slab 100A is T (Tu + t), similar to the composite slab 100. The width (length in the first direction X) of the composite slab 100A is W (mm). The second neutral axis NA2 of the end surface SF2' of the composite slab 100A is located at a distance Ac in the thickness direction Z from the main surface 101MF, similar to the composite slab 100.
[0046] In Figure 5, the end face SF2' when the composite slab 100A is not bent is shown by a solid line, and the end face SF2' when the composite slab 100A is bent is shown by a dashed line. As shown in Figure 5, when the composite slab 100A is bent, the upper part with respect to the second neutral axis NA2 (the side opposite the peak 111 with respect to the second neutral axis NA2) is compressed, and the lower part with respect to the second neutral axis NA2 (the side closer to the peak 111 with respect to the second neutral axis NA2) is stretched. As a result, as shown by the dashed line in Figure 5, the end face SF2' is inclined so that the lower side protrudes with respect to the second neutral axis NA2. When the composite slab 100A is bent, the end face SF2' is linearly inclined in a side view (when viewed in the first direction X). Specifically, in the bent state, the end face SF2' becomes an inclined surface by the upper end of the end face SF2' moving (compressing) toward the other end face SF2' by a distance εc, and the lower end of the end face SF2' moving (expanding) away from the other end face SF2' by a distance εs, based on the unbent state.
[0047] Generally, concrete is strong against compression but weak against tension. For this reason, as shown in FIG. 5, the portion of the end face SF2' that is compressed, namely the portion 102A of the concrete located above the second neutral axis NA2, bears the compressive force due to bending. Here, when the composite slab 100A is bent, the force (compressive force) applied to the end face SF2' increases linearly the further upward. For this reason, the compressive force Fp can be calculated using the same concept as the volume of a right-angled triangular prism. Therefore, the Young's modulus of concrete can be calculated as Ec (N / mm 2 ) and the compressive force Fp can be calculated using the following equation (1). Fp=Ac×W×Ec×εc×1 / 2 (1)
[0048] On the other hand, as mentioned above, concrete is weak in tension, so the concrete 101 (ridge portion 102) cannot substantially withstand the tensile force Fd applied below the second neutral axis NA2. For this reason, as shown in FIG. 5, when the composite slab 100A is bent, the deck plate 110 (ridge portion 111) bears the tensile force Fd. Therefore, the Young's modulus of the deck plate is set to Es (N / mm 2 ) and the tensile force Fd can be calculated using the following equation (2). Fd = t × W × Es × εs (2)
[0049] Here, as described above, since the end surface SF2' is simply bent, the compressive force Fp and the tensile force Fd are substantially balanced. Therefore, the following equation (3) can be derived from equations (1) and (2). Ac×W×Ec×εc×1 / 2=t×W×Es×εs (3)
[0050] Incidentally, the following relationship holds between εc (mm), which is the compression amount at the upper end of the end face SF2', and εs (mm), which is the expansion / contraction amount at the lower end of the end face SF2', based on the similarity relationship of triangles, as shown in Figure 5. εc:εs=Ac:(T-Ac) (4)
[0051] Then, based on the formulas (3) and (4), the following formula (A) expressing the position Ac (mm) of the second neutral axis NA2 is obtained. Ac 2 =2×(Es / Ec)×t×(T-Ac)...(A) In formula (A), Ec is the Young's modulus of concrete (N / mm 2 ), and Es represents the Young's modulus of the deck plate 110 (N / mm 2 ), t represents the thickness (mm) of the deck plate 110, and T represents the height (mm) of the cross section SF2, which is the sum of the thickness Tu of the convex portion 102 of the concrete 101 and the thickness t of the deck plate 110 (in other words, the thickness (mm) of the composite slab 100).
[0052] It is known that the Young's modulus Es of a typical deck plate is 15 times the Young's modulus Ec of typical concrete. Therefore, in formula (A), the ratio of the Young's modulus of the deck plate to the Young's modulus of concrete, Es / Ec, can be set to 15.
[0053] As described above, the first calculation unit 13 calculates the position Ac (mm) of the second neutral axis NA2 in the thickness direction Z based on the formula (A).
[0054] The second calculation unit 14 calculates the first force Pm (N / m 2 ) (see FIG. 7) of the first force Pm, the component in the first direction X of the composite slab 100 bears (applied to the component in the first direction X of the composite slab 100) second force Pe (N / m 2 ) (see FIG. 7) based on the position Ae (mm) of the first neutral axis NA1 and the position Ac (mm) of the second neutral axis NA2. FIG. 7 will be described again later. Specifically, in this embodiment, the second calculation unit 14 calculates the ratio Pe / Pm of the first force Pm (N / m 2 ) and the second force is Pe(N / m 2), the position of the first neutral axis NA1 is Ae (mm) (see Figure 3(B)), the position of the second neutral axis NA2 is Ac (mm) (see Figure 4(B)), the length (total length) of the composite slab 100 in the first direction X is Lx (m) (see Figure 1), and the length (total length) of the composite slab 100 in the second direction Y is Ly (m) (see Figure 1), and the ratio (Pe / Pm) of the second force Pe to the first force Pm is calculated based on the following equation (B). Pe / Pm={(2Ae / 2Ac) 3 ×(Ly / Lx) 3} / {1+(2Ae / 2Ac) 3 ×(Ly / Lx) 3}···(B)
[0055] Formula (B) will be explained in detail below.
[0056] First, assume that the concrete 101 (peak portion 102) of the composite slab 100A shown in FIG. 5 is made of concrete that is strong not only in compression but also in tension, i.e., can withstand tensile force (hereinafter referred to as "virtual concrete"). If the concrete 101 is virtual concrete, the concrete alone can withstand compressive force Fp and tensile force Fd, so a slab 100A' made of only the concrete 101 can be constructed as shown in FIG. 6. The position Ac of the second neutral axis NA2 of the slab 100A' is located at half the height (T = Tu) of the slab 100A'. In the slab 100A', the concrete 101 (peak portion 102) withstands the tensile force Fd, so the tensile force Fd acting below the second neutral axis NA2 can be expressed by the following equation (5): Fd=Ac×W×Ec×εs×1 / 2 (5)
[0057] The rigidity of the slab 100A' made only of concrete 101 (ridge portion 102) in the first direction X and the rigidity of the slab 100A' in the second direction Y can be expressed by the formula (E×I) which represents general bending rigidity. Here, E is the Young's modulus of concrete (i.e., the above-mentioned Ec), and I is the modulus of section quadratic of concrete. The modulus of section quadratic of concrete, I, can be expressed by the following formula (6), where W (m) is the width of the slab 100A' and T (= Tu) (m) is the height of the slab 100A'. I=W×(T) 3 / 12···(6)
[0058] Here, the height T of the slab 100A' having the second neutral axis NA2 is 2Ac, as described above and as shown in Figure 6. Therefore, the bending stiffness EIc of the slab 100A' having the second neutral axis NA2 can be expressed by the following equation (7). EIc=W×(2Ac) 3 / 12···(7) In the formula (7), Ic represents the quadratic coefficient of the cross section of the slab 100A' in the second direction Y.
[0059] Furthermore, when the slab 100A' has a first neutral axis NA1, the height T of the slab 100A' is 2Ae. Therefore, the bending rigidity EIe of the slab 100A' having the first neutral axis NA1 can be expressed by the following equation (8). EIe=W×(2Ae) 3 / 12···(8) In the formula (8), Ie represents the quadratic coefficient of the cross section SF1 of the slab 100A' in the first direction X.
[0060] Next, as shown in FIG. 7, the central region 101MFc of the main surface 101MF of the slab 100A′ is subjected to a first force Pm (N / m 2) is pressed. The central region 101MFc is located at the center of the main surface 101MF and is a square-shaped imaginary region having lengths d in both the first direction X and the second direction Y. The first force Pm is the sum of the second force Pe (N / m 2 ), and a third force Pc (N / m 2 ) is the resultant force. Therefore, the following equation (9) holds true. Pc = Pm - Pe (9) Also, the center of the rod-shaped member is subjected to a force P (N / m 2 The amount of descent σ (mm) of the central portion when pressed with the finger ≡ ... σ=P×L 3 / 192EI···(10) In equation (10), L is the length of the rod-shaped member in the longitudinal direction, E is the Young's modulus of the concrete (i.e., the above-mentioned Ec), and I is the above-mentioned quadratic modulus of the concrete.
[0061] Therefore, in FIG. 7, the amount of lowering σe (mm) of the central region 101MFc of the first region 101MF1 when the central region 101MFc of the first region 101MF1 is pressed with the second force Pe is expressed by the following formula (11). σe=Pe×Lx 3 / 192EIe···(11) Here, Ie is the quadratic coefficient of the cross section in the first direction X described above. In addition, in FIG. 7, the amount of lowering σc (mm) of the central region 101MFc of the second region 101MF2 when the central region 101MFc of the second region 101MF2 is pressed with a third force Pc is expressed by the following formula (12). σc=Pc×Ly 3 / 192EIc···(12) It should be noted that Ic is the quadratic coefficient of the cross section in the second direction Y described above.
[0062] Here, the central region 101MFc is a region where the first region 101MF1 and the second region 101MF2 intersect, and is a region shared by the first region 101MF1 and the second region 101MF2, so the amount of descent σe is equal to the amount of descent σc. Therefore, the following equation (13) is derived from equations (11) and (12). Pe×Lx 3 / 192EIe=Pc×Ly 3 / 192EIc···(13) By transforming equation (13), the following equation (14) is obtained. Pe={(Ly 3 ×EIe) / (Lx 3 ×EIc)}×Pc···(14) Then, by substituting the formulas (7), (8), and (9) into the formula (14), the following formula (B) is derived. Pe / Pm={(2Ae / 2Ac) 3 ×(Ly / Lx) 3} / {1+(2Ae / 2Ac) 3 ×(Ly / Lx) 3}···(B)
[0063] The second calculation unit 14 calculates the first force Pm (N / m 2 ) (see FIG. 7) of the first force Pm, the component in the first direction X of the composite slab 100 bears the second force Pe (N / m 2 ) (see FIG. 7) is calculated as the ratio Pe / Pm.
[0064] The display unit 15 may display (output) a matrix that associates the ratio Pe / Pm calculated by the first calculation unit 13 and the second calculation unit 14 with the total length Lx (m) of the composite slab 100 in the first direction X and the total length Ly (m) in the second direction Y. Each of Figures 8 to 10 shows an example of such a matrix.
[0065] Based on the above-described functional configuration of the arithmetic device 1, the arithmetic device 1 may execute the following arithmetic method. That is, as shown in Fig. 11, the arithmetic method executed by the arithmetic device 1 may include a storage step ST1, a first arithmetic step ST2, a second arithmetic step ST3, and a display step ST4.
[0066] In the storage step ST1, various data are input to the calculation device 1 via the input unit 11, such as the overall length Lx of the composite slab 100 in the first direction X, the overall length Ly of the composite slab 100 in the second direction Y, the thickness t of the deck plate 110, the thickness Tu of the convex portion 102 of the concrete 101, the sum T of the thickness Tu of the convex portion 102 of the concrete 101 and the thickness t of the deck plate, Young's modulus Es of the deck plate 110, Young's modulus Ec of the concrete 101, and the position Ae of the first neutral axis NA1 of the composite slab 100. The various data input to the calculation device 1 are then stored in the storage unit 12.
[0067] After the storage step ST1, a first calculation step ST2 is executed. Specifically, after the storage step ST1, when a signal commanding the execution of calculation is input to the calculation device 1 via, for example, the input unit 11, the control unit 10 of the calculation device 1 causes the first calculation unit 13 to execute calculation. That is, under the control of the control unit 10, the first calculation unit 13 reads data on the Young's modulus Ec of the concrete 101, data on the Young's modulus Es of the deck plate 110, and data on the sum T of the thickness Tu of the convex portion 102 of the concrete 101 and the thickness t of the deck plate from the storage unit 12, and calculates the position Ac of the second neutral axis NA2 of the cross section SF2 of the composite slab 100 in the second direction Y based on the above-mentioned formula (A). The control unit 10 may store the data on the position Ac of the second neutral axis NA2 in the storage unit 12.
[0068] After the first calculation step ST2, the second calculation step ST3 is executed. Specifically, after the first calculation step ST2, the control unit 10 of the calculation device 1 causes the second calculation unit 14 to execute calculation. That is, under the control of the control unit 10, the second calculation unit 14 reads from the storage unit 12 the data on the position Ae of the first neutral axis NA1, the data on the position Ac of the second neutral axis NA2 calculated in the first calculation step ST2, and a first pair of data consisting of any one Lx data and any one Ly data among the plurality of Lx and Ly data stored in the storage unit 12, and executes calculation based on the above-mentioned formula (B). As a result, the ratio Pe / Pm of Lx and Ly to the first pair of data is calculated.
[0069] Furthermore, the control unit 10 may cause the second calculation unit 14 to read out a total of N pairs of data (N is a natural number, and the Nth pair is the Nth pair of data), such as a second pair of data consisting of any other Lx data and any other Ly data among the plurality of Lx and Ly data, and a third pair of data consisting of any further Lx data and any further Ly data among the plurality of Lx and Ly data, from the storage unit, and execute the first calculation step ST2 and the second calculation step ST3 for each of these pairs of data. As a result, matrices such as those shown in FIGS. 8 to 10 are obtained. The control unit 10 may store these matrices in the storage unit 12.
[0070] Finally, a display step ST4 is executed. Specifically, the control unit 10 causes the display unit 15 to display the matrix stored in the storage unit 12.
[0071] In this way, the calculation program that causes the calculation device 1 to execute the above-mentioned calculation method causes the calculation device 1 to execute a storage step ST1 that stores the position Ae of the first neutral axis NA1 of the cross section SF1 in the first direction X as a distance in the thickness direction Z from the main surface 101MF, a first calculation step ST2 that calculates the position Ac of the second neutral axis NA2 of the cross section SF2 in the second direction Y as a distance in the thickness direction Z from the main surface 101MF, and a second calculation step ST3 that calculates the ratio of the second force Pe to the first force Pm that pushes the composite slab 100 in the thickness direction Z based on the position Ae and the position Ac.
[0072] Next, the matrices shown in FIGS. 8, 9, and 10 will be described.
[0073] 8 to 10, the leftmost column represents the total length Lx (mm) of the composite slab 100 in the first direction X (peak-valley extension direction), and the top row represents the total length Ly of the composite slab 100 in the second direction Y (peak-valley continuous direction). The numerical values shown in the matrix consisting of the columns to the right of the leftmost column and the rows below the top row are the ratio Pe / Pm calculated by the first calculation unit 13 and the second calculation unit 14.
[0074] 8 shows a matrix of the ratio Pe / Pm for a composite slab 100 (hereinafter referred to as "composite slab 100-1" for convenience) in which the distance (height) Dh (see FIG. 3(B)) from the valley portion 112 to the peak portion 111 is 50 mm, the thickness Tu (see FIG. 3(B)) of the peak portion 102 of the concrete 101 is 60 mm, and the thickness t (see FIG. 3(B)) of the deck plate 110 is 1.6 mm. For example, as shown in FIG. 8, it can be seen that the ratio Pe / Pm of the composite slab 100-1, in which Lx is 2 m and Ly is 2 m, is 72.3%. This means that in the composite slab 100-1 in which Lx is 2 (m) and Ly is 2 (m), (1) 72.3% of the first force Pm (see FIG. 7) applied to the composite slab 100-1 is applied as the second force Pe (see FIG. 7) to the component in the first direction X of the composite slab 100-1 (in other words, the first region 101MF1 shown in FIG. 7), and this second force Pe is applied to the component in the first direction X of the composite slab 100-1 (the first region 101MF1 shown in FIG. 7). 01MF1), and (2) the remaining 27.7% of the first force Pm applied to the composite slab 100-1 is applied as a third force Pc (see Figure 7) to the component in the second direction Y of the composite slab 100-1 (in other words, the second region 101MF2 shown in Figure 7), and this third force Pc is borne by the component in the second direction Y of the composite slab 100-1 (the second region 101MF2).
[0075] 9 shows a matrix of the ratio Pe / Pm for a composite slab 100 (hereinafter referred to as "composite slab 100-2" for convenience) with a distance (height) Dh of 50 mm, a thickness Tu of 80 mm, and a thickness t of 1.6 mm. For example, as shown in FIG. 9, it can be seen that the ratio Pe / Pm for composite slab 100-2 with Lx of 2 m and Ly of 2 m is 68.9%. This indicates that in the composite slab 100-2, where Lx is 2 (m) and Ly is 2 (m), (1) 68.9% of the first force Pm applied to the composite slab 100-2 is applied as a second force Pe to the component in the first direction X of the composite slab 100-2, and this second force Pe is borne by the component in the first direction X of the composite slab 100-2, and (2) the remaining 31.1% of the first force Pm applied to the composite slab 100-2 is applied as a third force Pc to the component in the second direction Y of the composite slab 100-2, and this third force Pc is borne by the component in the second direction Y of the composite slab 100-2.
[0076] Figure 10 shows a matrix of the ratio Pe / Pm for a composite slab 100 (hereinafter referred to as "synthetic slab 100-3" for convenience) with a distance (height) Dh of 50 mm, a thickness Tu (see Figure 3(B)) of 100 mm, and a thickness t of 1.6 mm. For example, as shown in Figure 10, it can be seen that the ratio Pe / Pm for the composite slab 100-3 with Lx of 2 m and Ly of 2 m is 66.7%. This indicates that in the composite slab 100-3, where Lx is 2 (m) and Ly is 2 (m), (1) 66.7% of the first force Pm applied to the composite slab 100-3 is applied as a second force Pe to the component in the first direction X of the composite slab 100-3, and this second force Pe is borne by the component in the first direction X of the composite slab 100-3, and (2) the remaining 33.3% of the first force Pm applied to the composite slab 100-3 is applied as a third force Pc to the component in the second direction Y of the composite slab 100-3, and this third force Pc is borne by the component in the second direction Y of the composite slab 100-3.
[0077] The matrices in FIGS. 8 to 10 reveal the following.
[0078] Conventionally, composite slabs have been designed on the assumption that the compressive force (first force Pm) acting on the composite slab is borne only by the component in the first direction X of the composite slab. In other words, conventionally, composite slabs have been designed with Pe / Pm = 100%. However, as shown in Figures 8 to 10, in reality, the compressive force (first force Pm) acting on the composite slab is also applied to the component in the second direction Y of the composite slab 100 as a third force Pc, and it can be seen that this third force Pc is borne by the component in the second direction Y of the composite slab 100. Therefore, by taking this third force Pc into consideration, a composite slab can be designed based on the second force Pe, which is the conventional second force Pe (Pe = P) minus the third force Pc.
[0079] That is, according to this embodiment, by generating the matrices shown in Figures 8 to 10 using the calculation device 1 and referring to these matrices, it becomes possible to design a composite slab with a stiffness smaller than the conventional design value of stiffness. Therefore, for example, it is possible to design a composite slab with a thinner concrete thickness or deck plate thickness than conventional ones, and as a result, it is possible to design a composite slab at reduced cost. In this way, according to this embodiment, a calculation device, calculation method, and calculation program are provided that can calculate data (matrices) that can be used to design a composite slab at reduced cost.
[0080] Furthermore, if the ratio Ly / Lx is defined as the side length ratio, it can be seen that the ratio Pe / Pm corresponding to the smallest side length ratio Ly / Lx (Ly / Lx = 2 / 3) is also smallest, as shown in Figures 8 to 10. Specifically, in Figure 8, Pe / Pm for the smallest side length ratio of 2 / 3 is a minimum of 43.6%, in Figure 9, Pe / Pm for the smallest side length ratio of 2 / 3 is a minimum of 39.6%, and in Figure 10, Pe / Pm for the smallest side length ratio of 2 / 3 is a minimum of 37.3%. This indicates that the smaller the side length ratio, i.e., the smaller the overall length Lx of the composite slab in the first direction X (peak-valley extension direction) becomes relative to the overall length Ly in the second direction Y (peak-valley continuation direction), the more of the first force Pm can be borne by the component of the composite slab in the second direction Y.
[0081] Furthermore, when comparing the ratios Pe / Pm shown in the matrix of Fig. 8 with the ratios Pe / Pm shown in the matrix of Fig. 9 and the ratios Pe / Pm shown in the matrix of Fig. 10, it can be seen that the ratios Pe / Pm shown in the matrices decrease in the order of Fig. 8, Fig. 9, and Fig. 10. For example, the ratio Pe / Pm corresponding to Lx=2 and Ly=3 in Fig. 8 is 43.6%, the ratio Pe / Pm corresponding to Lx=2 and Ly=3 in Fig. 9 is 39.6%, and the ratio Pe / Pm corresponding to Lx=2 and Ly=3 in Fig. 10 is 37.3%, so when Lx=2 and Ly=3, the ratio Pe / Pm decreases in the order of Fig. 8, Fig. 9, and Fig. 10. Similarly, it can be seen that the ratio Pe / Pm decreases in the order of Fig. 8, Fig. 9, and Fig. 10 for other combinations of Lx and Ly. As described above, Fig. 8 is the matrix of a composite slab in which the thickness Tu of the ridge portion 102 is 60 mm, Fig. 9 is the matrix of a composite slab in which the thickness Tu of the ridge portion 102 is 80 mm, and Fig. 10 is the matrix of a composite slab in which the thickness Tu of the ridge portion 102 is 100 mm. Therefore, when Figs. 8 to 10 are considered comprehensively, it can be seen that the thicker the ridge portion 102 of a composite slab, the more of the first force Pm can be borne by the component in the second direction Y of the composite slab.
[0082] Although the present invention has been described above using the above-mentioned embodiment as an example, the present invention is not limited to this.
[0083] For example, in the above embodiment, an example was described in which the deck plate 110 is a deck plate in which the peaks 111 and valleys 112 are continuous in the second direction Y, but any deck plate that can impart unidirectionality in the first direction X to the composite slab 100 may be used. In other words, the deck plate 110 may be a deck plate that has unidirectionality in the first direction X.
[0084] Furthermore, those skilled in the art can appropriately modify the arithmetic device, arithmetic method, and arithmetic program according to the present invention in accordance with conventionally known knowledge. As long as such modifications still comprise the configuration of the present invention, they are of course included in the scope of the present invention. [Explanation of symbols]
[0085] 1...Calculation device, 12...Memory unit, 13...First calculation unit, 14...Second calculation unit, 100...Composite slab, 101...Concrete, 101MF...Main surface, 102...Top portion, 110...Deck plate, 111...Crest portion, 112...Trough portion, NA1...First neutral axis, NA2...Second neutral axis, Pm...First force, Pe...Second force, SF1, SF2...Cross section
Claims
1. A computing device capable of computing data usable for designing a unidirectional composite slab, The composite slab has a flat main surface extending in a first direction defining the unidirectionality and a second direction perpendicular to both the first direction and the thickness direction on one side of the thickness direction of the composite slab, The computing device A memory unit that stores the position of a first neutral axis of a cross section of the composite slab in the first direction as a distance from the main surface in the thickness direction; A first calculation unit calculates the position of a second neutral axis of a cross section of the composite slab in the second direction as a distance from the main surface in the thickness direction; a second calculation unit that calculates a ratio of a second force applied to a component of the first force in the first direction of the composite slab to a first force that presses the composite slab in the thickness direction, based on the position of the first neutral axis and the position of the second neutral axis; A computing device comprising:
2. The composite slab includes a deck plate having a peak portion and a valley portion that are continuous in the second direction, and concrete poured on the deck plate, The calculation device according to claim 1, wherein the first calculation unit calculates the position of the second neutral axis by calculating the top portion of the concrete that is on the opposite side of the peak portion from the valley portion in the thickness direction.
3. The first calculation unit sets the position of the second neutral axis as Ac (mm) and the Young's modulus of the concrete as Ec (N / mm 2 ), and the Young's modulus of the deck plate is Es (N / mm 2 ), the thickness of the deck plate is t (mm), and the sum of the thickness of the convex portion of the concrete and the thickness of the deck plate is T (mm), and the position Ac is calculated based on the following formula (A): Ac 2 =2×(Es / Ec)×t×(T-Ac)・・・(A)
4. The second calculation unit calculates the first force as Pm (N / m 2 ), and the second force is Pe (N / m 2 ), the position of the first neutral axis is Ae (mm), the position of the second neutral axis is Ac (mm), the length of the composite slab in the first direction is Lx (m), and the length of the composite slab in the second direction is Ly (m), and the ratio (Pe / Pm) of the second force to the first force is calculated based on the following equation (B). Pe / Pm={(2Ae / 2Ac) 3 ×(Ly / Lx) 3 } / {1+(2Ae / 2Ac) 3 ×(Ly / Lx) 3 }・・・(B)
5. A method for calculating data that can be used to design a unidirectional composite slab, comprising: The composite slab has a flat main surface extending in a first direction defining the unidirectionality and a second direction perpendicular to both the first direction and the thickness direction on one side of the thickness direction of the composite slab, The calculation method includes: A storing step of storing the position of a first neutral axis of the cross section of the composite slab in the first direction as a distance from the main surface in the thickness direction; A first calculation step of calculating the position of a second neutral axis of a cross section of the composite slab in the second direction as a distance from the main surface in the thickness direction; a second calculation step of calculating a ratio of a second force applied to a component of the first force in the first direction of the composite slab to a first force pushing the composite slab in the thickness direction, based on the position of the first neutral axis and the position of the second neutral axis; A calculation method comprising:
6. The composite slab includes a deck plate having a peak portion and a valley portion that are continuous in the second direction, and concrete poured on the deck plate, 6. The calculation method according to claim 5, wherein in the first calculation step, the position of the second neutral axis is calculated by calculating a peak portion of the concrete on the opposite side of the peak portion from the valley portion in the thickness direction.
7. In the first calculation step, the position of the second neutral axis is defined as Ac (mm), and the Young's modulus of the concrete is defined as Ec (N / mm 2 ), and the Young's modulus of the deck plate is Es (N / mm 2 ), a thickness of the deck plate is t (mm), and a sum of the thickness of the convex portion of the concrete and the thickness of the deck plate is T (mm), and the position Ac is calculated based on the following formula (A): Ac 2 =2×(Es / Ec)×t×(T-Ac)・・・(A)
8. In the second calculation step, the first force is calculated as Pm (N / m 2 ), and the second force is Pe (N / m 2 ), the position of the first neutral axis is Ae (mm), the position of the second neutral axis is Ac (mm), the length of the composite slab in the first direction is Lx (m), and the length of the composite slab in the second direction is Ly (m), and the ratio (Pe / Pm) of the second force to the first force is calculated based on the following equation (B). Pe / Pm={(2Ae / 2Ac) 3 ×(Ly / Lx) 3 } / {1+(2Ae / 2Ac) 3 ×(Ly / Lx) 3 }・・・(B)
9. A calculation program that causes a calculation device capable of calculating data that can be used to design a unidirectional composite slab to perform calculations, The composite slab has a flat main surface extending in a first direction defining the unidirectionality and a second direction perpendicular to both the first direction and the thickness direction on one side of the thickness direction of the composite slab, The calculation program A storing step of storing the position of a first neutral axis of the cross section of the composite slab in the first direction as a distance from the main surface in the thickness direction; A first calculation step of calculating the position of a second neutral axis of a cross section of the composite slab in the second direction as a distance from the main surface in the thickness direction; a second calculation step of calculating a ratio of a second force applied to a component of the first force in the first direction of the composite slab to a first force pushing the composite slab in the thickness direction, based on the position of the first neutral axis and the position of the second neutral axis; A calculation program that executes the above.
10. The composite slab includes a deck plate having a peak portion and a valley portion that are continuous in the second direction, and concrete poured on the deck plate, The calculation program according to claim 9, wherein the first calculation step is executed to calculate the position of the second neutral axis by calculating the top portion of the concrete on the opposite side of the peak portion from the valley portion in the thickness direction.
11. The position of the second neutral axis is Ac (mm), and the Young's modulus of the concrete is Ec (N / mm 2 ), and the Young's modulus of the deck plate is Es (N / mm 2 ), a thickness of the deck plate is t (mm), and a sum of the thickness of the convex portion of the concrete and the thickness of the deck plate is T (mm), and the first calculation step is executed to calculate the position Ac based on the following formula (A): Ac 2 =2×(Es / Ec)×t×(T-Ac)・・・(A)
12. The first force is Pm (N / m 2 ), and the second force is Pe (N / m 2 ), the position of the first neutral axis is Ae (mm), the position of the second neutral axis is Ac (mm), the length of the composite slab in the first direction is Lx (m), and the length of the composite slab in the second direction is Ly (m), and the second calculation step is executed to calculate the ratio (Pe / Pm) of the second force to the first force based on the following equation (B). Pe / Pm={(2Ae / 2Ac) 3 ×(Ly / Lx) 3 } / {1+(2Ae / 2Ac) 3 ×(Ly / Lx) 3 }・・・(B)
Citation Information
Patent Citations
Structure and method of junction between deck plate and support member
JP2023147101A