Optimization Method for Electrical Equipment Maintenance Decision

Abstract

The present application relates to a method for optimizing electrical equipment maintenance decision-making. The method includes: obtaining a sampling inspection plan sequence with the minimum delay cost for an electrical equipment as the optimal sampling inspection plan sequence; determining each to-be-detected maintenance decision according to the optimal sampling inspection sequence; according to the constraint conditions of a preset integrated model, when each to-be-detected maintenance decision meets the constraint conditions, calculating the selective maintenance cost, sampling inspection quality cost, and sampling inspection plan delay cost of each to-be-detected maintenance decision; calculating the integrated total cost of each to-be-detected maintenance decision according to the selective maintenance cost, sampling inspection quality cost, and sampling inspection plan delay cost; according to the integrated total cost of each to-be-detected maintenance decision, with the goal of minimizing the integrated total cost, determining the optimal integrated total cost, and taking the to-be-detected maintenance decision corresponding to the optimal integrated total cost as the optimal maintenance decision. Using this method can reduce the total cost of maintenance decision-making.

Description

Technical Field

[0001] The present application relates to the technical field of equipment maintenance optimization management, and in particular to an electrical equipment maintenance decision optimization method, device, computer equipment and storage medium. Background Art

[0002] With the development of equipment maintenance optimization management technology, in order to facilitate power companies to reasonably purchase related power equipment and reduce unnecessary costs, electrical equipment maintenance decision optimization technology has emerged.

[0003] Traditionally, electrical equipment inevitably experiences problems during power system operation, such as aging and component damage. This makes maintenance of these equipment crucial. Selective maintenance, which involves making decisions based on equipment condition, including repair, replacement, or no action, offers significant economic benefits and can improve the economic efficiency of grid operations. However, the key consideration is how to make selective maintenance decisions for equipment, minimizing maintenance costs while maximizing benefits. Conventional methods involve spot-checking equipment. This approach calculates the delay costs of the inspection plan, the quality costs of the inspection samples, and the cost of selective maintenance, yielding the expected total cost of the maintenance decision.

[0004] However, the traditional method obtains the planning cost, maintenance cost and quality cost separately without considering the relationship between the three, so it is difficult to obtain the optimal expected cost, which increases the expected total cost of maintenance decision to a certain extent. Summary of the Invention

[0005] Based on this, it is necessary to provide an electrical equipment maintenance decision optimization method that can reduce the total cost of maintenance decisions in response to the above technical problems.

[0006] A method for optimizing maintenance decisions of electrical equipment, comprising:

[0007] Obtain the inspection plan sequence with the minimum delay cost for electrical equipment as the optimal inspection plan sequence;

[0008] Determining each maintenance decision to be tested according to the optimal sampling sequence;

[0009] According to the constraints of the preset integrated model, when each maintenance decision to be tested meets the constraints, the selective maintenance cost, the sampling quality cost and the sampling plan delay cost of each maintenance decision to be tested are calculated;

[0010] Calculating the integrated total cost of each maintenance decision to be tested based on the selective maintenance cost, the random inspection quality cost, and the random inspection plan delay cost;

[0011] According to the total integration cost of each maintenance decision to be measured, with the goal of minimizing the total integration cost, determine the optimal total integration cost, and use the maintenance decision to be measured corresponding to the optimal total integration cost as the optimal maintenance decision.

[0012] In one embodiment, according to the total integration cost of each maintenance decision to be measured, with the goal of minimizing the total integration cost, determine the optimal total integration cost, and use the maintenance decision to be measured corresponding to the optimal total integration cost as the optimal maintenance decision, including:

[0013] According to the intelligent algorithm and the total integration cost of each maintenance decision to be measured, search for the optimal total integration cost with the goal of minimizing the total integration cost. The intelligent algorithm includes simulated annealing algorithm and ant colony algorithm;

[0014] When the intelligent algorithm finds the optimal total integration cost, stop searching for the optimal total integration cost, and determine the maintenance decision to be measured corresponding to the optimal total integration cost as the optimal maintenance decision.

[0015] In one embodiment, before obtaining the sampling inspection plan sequence with the minimum delay cost of the electrical equipment, it further includes:

[0016] Establish a maintenance decision cost model, a sampling inspection quality cost model, and a sampling inspection plan delay cost model respectively;

[0017] Construct an integrated model according to the maintenance decision cost model, the sampling inspection quality cost model, and the sampling inspection plan delay cost model.

[0018] In one embodiment, the maintenance decision cost model includes the first replacement cost, the first repair cost, and the maintenance failure cost. When calculating the cost of selective maintenance according to the maintenance decision cost model, the method includes:

[0019] Obtain the remaining loss cost of each component of the electrical equipment;

[0020] Obtain the first replacement cost, the first repair cost, and the maintenance failure cost of each component. The remaining loss cost is the loss cost of abandoning the remaining life of the component;

[0021] According to the sum of the first replacement cost, the first repair cost, and the maintenance failure cost of each component, obtain the cost of selective maintenance.

[0022] In one embodiment, before replacing or repairing each component, the method further includes:

[0023] Obtain the average remaining life, average life, and cost of each component of the electrical equipment;

[0024] Obtain the proportion of the remaining life of each component according to the ratio of the average remaining life to the average life of each of the components;

[0025] Obtain the remaining loss cost of each of the components according to the product of the proportion of the remaining life of each of the components and the cost, where the remaining loss cost is the loss cost when giving up the remaining life of the component and choosing to repair or replace it.

[0026] In one embodiment, obtaining the first replacement cost, the first repair cost, and the repair failure cost of each of the components includes:

[0027] Obtain the working efficiency of the electrical device and the loss cost when the electrical device is not working, and obtain the total loss cost when the electrical device is not working according to the product of the working efficiency and the loss cost; obtain the loss cost per unit time according to the sum of the total loss cost and the maintenance labor cost; obtain the total loss cost during the replacement time according to the sum of the product of the loss cost per unit time and the replacement time of each of the components; obtain the first replacement cost according to the sum of the total loss cost during the replacement time, the cost of each of the components, and the remaining loss cost;

[0028] For each of the components, obtain the repair time of each of the components, and obtain the total loss cost during the repair time according to the sum of the product of the loss cost per unit time and the repair time of each of the components; obtain the first repair cost according to the sum of the total loss cost during the repair time and the cost of maintenance consumables;

[0029] For each of the components, the repair failure cost includes the replacement failure cost and the repair failure cost. When replacing each of the components, obtain the replacement failure cost according to the sum of the total loss cost during the replacement time and the cost of each of the components; when repairing each of the components, obtain the repair failure cost according to the sum of the total loss cost during the repair time and the cost of maintenance consumables.

[0030] In one embodiment, obtain the cost of selective maintenance according to the sum of the first replacement cost, the first repair cost, and the repair failure cost of each of the components, including:

[0031] For each of the components, multiply the repair failure cost by the possibility coefficient that the component cannot continue to work to obtain the corresponding failure cost;

[0032] Add up each of the failure costs to obtain the total failure cost;

[0033] The cost of the selective maintenance is obtained based on the total cost of failure, the sum of the first replacement cost and the first repair cost.

[0034] In one embodiment, the sampling inspection quality cost model includes the sampling inspection cost, misjudgment cost, cost of investigating the reasons for misjudgment, second replacement cost when the sampling inspection is unqualified, second repair cost when the sampling inspection is unqualified, and cost of resuming operation of the electrical equipment; when calculating the sampling inspection quality cost according to the sampling inspection quality cost, the method includes:

[0035] Obtain the sampling inspection cost, misjudgment cost, cost of investigating the reasons for misjudgment, second replacement cost when the sampling inspection is unqualified, second repair cost when the sampling inspection is unqualified, and cost of resuming operation of the electrical equipment;

[0036] The sampling inspection quality cost is obtained based on the product of the sum of the sampling inspection cost, the misjudgment cost, the cost of investigating the reasons for misjudgment, the second replacement cost, the second repair cost, and the cost of resuming operation, and the expected cycle length of the sampling inspection.

[0037] In one embodiment, when obtaining the sampling inspection cost, misjudgment cost, cost of investigating the reasons for misjudgment, second replacement cost when the sampling inspection is unqualified, second repair cost when the sampling inspection is unqualified, and cost of resuming operation of the electrical equipment, the method includes:

[0038] Obtain the expected number of samples and the number of detected faults of the components in the electrical equipment, and obtain the actual number of samples to be inspected based on the ratio of the expected number of samples and the number of detected faults, and the product of the ratio and the total sample size; obtain the unit sampling inspection cost, and multiply the unit sampling inspection cost and the actual number of samples to be inspected to obtain the sampling inspection cost;

[0039] Obtain the time for investigating misjudgment, the expected number of samples, the sample defect probability, the misjudgment cost, and the loss cost; the misjudgment cost is obtained based on the product of the time for investigating misjudgment, the expected number of samples, the sample defect probability, the misjudgment cost, and the loss cost;

[0040] Obtain the detection duration of the sample and the investigation cost; the cost of investigating the reasons for misjudgment is obtained based on the sum of the investigation cost and the loss cost, and the product of the sum and the detection duration;

[0041] Obtain the duration of the detected fault; the total sampling detection duration is obtained based on the sum of the duration and the time interval from sampling to the end of detection; obtain the maintenance cost corresponding to the defective products that are unqualified in the sampling inspection of the sample; the second replacement cost when the sampling inspection is unqualified is obtained based on the product of the total sampling detection duration, the maintenance cost, and the work efficiency;

[0042] Obtain the repairable cost of defective products that can be repaired in the sample; obtain the second repair cost when the sampling inspection fails according to the product of the total sampling inspection duration, the work efficiency, and the repairable cost; obtain the restoration operation duration; obtain the restoration operation cost according to the product of the work efficiency, the loss cost, and the restoration operation duration, and the sum of the product and the restoration operation cost.

[0043] In one embodiment, obtaining the sampling inspection plan sequence with the minimum delay cost of the electrical equipment as the optimal sampling inspection plan sequence includes:

[0044] Obtain the sampling inspection plan sequences of each batch, and calculate the delay cost of the sampling inspection plan sequence of the current batch respectively to obtain the delay costs of the sampling inspection plan sequences of each batch;

[0045] Select the sampling inspection plan sequence with the minimum delay cost from the delay costs of the sampling inspection plan sequences of each batch as the optimal sampling inspection plan sequence.

[0046] In one embodiment, calculating the delay cost of the sampling inspection plan sequence of the current batch respectively to obtain the delay costs of the sampling inspection plan sequences of each batch includes:

[0047] For the sampling inspection plan sequences of each batch, obtain the delay duration of the sampling inspection plan sequence of the current batch according to the sum of the actual completion time of all batches before the current batch and the processing time of the current batch, and the planned completion time of the current batch;

[0048] Obtain the delay cost per unit time, and multiply the delay duration by the delay cost to obtain the delay cost of the sampling inspection plan sequence of the current batch.

[0049] In one embodiment, the constraint conditions include: the longest time for selective repair is not greater than the preset repair time, the minimum reliability coefficient for selective repair is not less than the preset coefficient, the sampling inspection time is not greater than the preset inspection completion time, and a choice between repair and replacement for the repair and replacement decision;

[0050] The choice between repair and replacement for the repair and replacement decision means that the same component cannot be both repaired and replaced at the same time, and the selective repair is to perform repair based on the choice made according to the repair decision.

[0051] The above electrical equipment maintenance decision optimization method obtains a sampling inspection plan sequence with the minimum delay cost for the electrical equipment as the optimal sampling inspection plan sequence; determines each to-be-tested maintenance decision according to the optimal sampling inspection sequence, and the to-be-tested maintenance decision is the maintenance decision that needs to be tested to obtain the optimal maintenance decision; for each to-be-tested maintenance decision: according to the constraint conditions of the preset integrated model, when each to-be-tested maintenance decision meets the constraint conditions, calculate the selective maintenance cost, sampling inspection quality cost and sampling inspection plan delay cost of each to-be-tested maintenance decision; calculate the integrated total cost of each to-be-tested maintenance decision according to the selective maintenance cost, sampling inspection quality cost and sampling inspection plan delay cost. According to each integrated total cost, with the goal of minimizing the integrated total cost, determine the optimal maintenance decision, and use the integrated total cost corresponding to the optimal maintenance decision as the optimal integrated total cost. That is, first consider the optimal sampling inspection plan sequence. When the delay cost is minimized and each to-be-tested maintenance decision meets the constraint conditions of the integrated model, calculate the selective maintenance cost, sampling inspection quality cost and sampling inspection plan delay cost according to the to-be-tested maintenance decision. According to these three costs, calculate the integrated total cost corresponding to each qualified to-be-tested maintenance decision, so that the to-be-tested maintenance decision with the minimum integrated total cost can be used as the optimal maintenance decision with the goal of minimizing the integrated total cost, and obtain the optimal integrated total cost corresponding to the optimal maintenance decision. It can be seen that the acquisition of the optimal integrated total cost fully considers the correlation between the selective maintenance cost, sampling inspection quality cost and sampling inspection plan delay cost. Therefore, the present application can reduce the total cost of maintenance decisions, and the obtained optimal integrated total cost is no longer fragmented, but comprehensively considers the comprehensive factors of each link, so as to further improve the maintenance quality on the basis of reducing the total cost of maintenance decisions. BRIEF DESCRIPTION OF THE DRAWINGS

[0052] Figure 1 It is an application environment diagram of the electrical equipment maintenance decision optimization method in an embodiment;

[0053] Figure 2 It is a flowchart of the electrical equipment maintenance decision optimization method in an embodiment;

[0054] Figure 3 It is a structural block diagram of the electrical equipment maintenance decision optimization device in an embodiment;

[0055] Figure 4 It is an internal structure diagram of a computer device in an embodiment. DETAILED DESCRIPTION OF THE EMBODIMENTS

[0056] In order to make the purpose, technical solution and advantages of the present application clearer, the present application will be further described in detail below with reference to the accompanying drawings and embodiments. It should be understood that the specific embodiments described herein are only used to explain the present application and are not used to limit the present application.

[0057] The electrical equipment maintenance decision optimization method provided by this application can be applied to an application environment as shown below Figure 1 In the application environment shown. Among them, the terminal 102 communicates with the server 104 through a network. The terminal 102 obtains the sampling inspection plan sequences of each batch of electrical equipment from the server 104, and takes the sampling inspection plan sequence with the minimum delay cost as the optimal sampling inspection plan sequence in the local area of the terminal 102. The to-be-detected maintenance decisions are stored in the server 104. After the terminal 102 determines the optimal sampling inspection plan sequence, the terminal 102 requests the server 104 to obtain each to-be-detected maintenance decision, and the server 104 will respond to this request and send each to-be-detected maintenance decision to the terminal 102. After the terminal 102 obtains each to-be-detected maintenance decision, it determines whether each to-be-detected maintenance decision meets the constraint conditions of the preset integrated model. When it meets the constraint conditions, it calculates the selective maintenance cost, sampling inspection quality cost, and sampling inspection plan delay cost of each to-be-detected maintenance decision. When calculating the total integrated cost, the terminal 102 takes the minimum total integrated cost as the goal, first determines an optimal total integrated cost, and the to-be-detected maintenance decision corresponding to this optimal total integrated cost is used as the optimal maintenance decision.

[0058] Among them, the terminal 102 can be but is not limited to various personal computers, laptop computers, smart phones, tablet computers, and portable wearable devices, and the server 104 can be implemented by an independent server or a server cluster composed of multiple servers.

[0059] In one embodiment, as shown below Figure 2 In the example of the terminal shown, a method for optimizing the electrical equipment maintenance decision is provided, including the following steps: Figure 1 Taking the terminal in the above as an example, the method includes the following steps:

[0060] Step 202: Obtain the sampling inspection plan sequence with the minimum delay cost of the electrical equipment as the optimal sampling inspection plan sequence.

[0061] Among them, the delay cost is the cost incurred when the total time for sampling each component sample of the electrical equipment exceeds the planned time. Each sampling plan sequence corresponds to a delay cost, and the sampling plan sequence with the minimum delay cost will be used as the optimal sampling plan sequence. First, the sampling plan sequence with the minimum delay cost is used as the optimal sampling plan sequence, and then the sampling quality cost and the sampling plan delay cost are calculated based on this optimal sampling plan sequence, thereby limiting the acquisition of the sampling quality cost and the sampling plan delay cost to be based on the minimum delay cost, excluding the combination of the corresponding sampling quality cost and the sampling plan delay cost when the delay cost is not the minimum. In one embodiment, the electrical equipment is an insulator string of a line, and the insulator string has multiple different components. When the insulator string is composed of 26 different components, the selective maintenance costs of each component of the insulator string are shown in Table 1:

[0062] Table 1

[0063]

[0064]

[0065] Note: The replacement cost, repair cost, replacement time, repair time, and maintenance failure cost of each component are given in the table. Different maintenance decisions (including replacement, repair, and maintaining the original state) for the components of an insulator string can obtain different maintenance cost values.

[0066] In one embodiment, obtaining the sampling plan sequence with the minimum delay cost of the electrical equipment as the optimal sampling plan sequence includes: obtaining the sampling plan sequences of each batch, respectively calculating the delay cost of the sampling plan sequence of the current batch to obtain the total delay cost of the sampling plan sequences of each batch; selecting the sampling plan sequence with the minimum delay cost from the delay costs of the sampling plan sequences of each batch as the optimal sampling plan sequence.

[0067] Among them, the sampling inspection plan sequence has multiple batches, and a batch can be understood as a different sampling inspection plan sequence. The components in each sampling inspection plan sequence are the same, and the only difference is the order of sampling inspection of each component in each batch. For example, the sampling inspection plan sequence of the first batch is 9-3-6-8-1-7-10-4-5-2, and the sampling inspection plan sequence of the second batch is 9-3-5-8-1-7-6-4-10-2. The components included in the sampling inspection plan sequences of the two batches are the same, but the components corresponding to the serial numbers 4, 5, 6, and 10 have changed. Due to the different usage degrees of each component, different batches of sampling inspection plan sequences result in different delay cost costs. Each batch of sampling inspection plan sequences has a corresponding delay cost cost. Obtain the delay cost costs of each batch of sampling inspection plan sequences, and select the sampling inspection plan sequence of the batch with the smallest delay cost cost from the delay cost costs of each batch of sampling inspection plan sequences as the optimal sampling inspection plan sequence.

[0068] Step 204: Determine each pending maintenance decision according to the optimal sampling sequence.

[0069] Among them, the optimal sampling inspection plan sequence is a sequence including multiple sampled components. When this sequence is determined according to the smallest delay cost cost, the sampling order of multiple components in this sampling inspection plan sequence is determined, but the maintenance decisions of each component are not yet determined. At this time, it is necessary to determine the corresponding maintenance decisions for each component in this optimal sampling sequence. The maintenance decisions include replacement, repair, or maintaining the original state. Generally, for each component in the sampling inspection plan sequence, it is not possible to replace and repair at the same time, and only one of replacement and repair can be selected. Suppose the optimal sampling sequence is component No. 9 - component No. 3 - component No. 6 - component No. 8, replacement is represented by the number 1, repair is represented by the number 2, and maintaining the original state is represented by the number 0. One of the pending maintenance decisions is 1, 2, 0, 1, that is, component No. 9 is replaced, component No. 3 is repaired, component No. 6 maintains the original state, and component No. 8 is replaced. Multiple combinations of the pending maintenance decisions are made according to the optimal sampling inspection plan sequence to obtain different combination results, that is, each pending maintenance decision is obtained. Each component may choose to be replaced, repaired, or maintain the original state.

[0070] Step 206: According to the constraint conditions of the preset integrated model, when each of the pending maintenance decisions meets the constraint conditions, calculate the selective maintenance cost, sampling inspection quality cost, and sampling inspection plan delay cost of each pending maintenance decision.

[0071] Among them, the integrated model has been pre-set on the terminal. The constraint conditions of the integrated model, based on the cost and completion quality of selective maintenance, limit each to-be-detected maintenance decision from entering the calculation of the total integrated cost, excluding the to-be-detected maintenance decisions that do not meet the selective maintenance cost and completion quality, thereby also improving the efficiency of subsequent computer processing to a certain extent. For each to-be-detected maintenance decision, when the to-be-detected maintenance decision meets the constraint conditions, calculate the selective maintenance cost, sampling inspection quality cost, and sampling inspection plan delay cost of the to-be-detected maintenance decision to obtain the total integrated cost of each to-be-detected maintenance decision. In one embodiment, the constraint conditions include: the longest time of selective maintenance is not greater than the preset maintenance time, the minimum reliability coefficient of selective maintenance is not less than the preset coefficient, the sampling inspection completion time is not greater than the preset inspection completion time, and there is a choice between repair and replacement; the choice between repair and replacement means that the same component cannot be both repaired and replaced at the same time, and selective maintenance is to perform maintenance based on the choice made according to the maintenance decision.

[0072] Among them, according to the constraint conditions obtained from the integrated model: the first is that the total time of selective maintenance is less than or equal to the preset maintenance time (T A ), the second is that the minimum reliability coefficient of selective maintenance is not less than the preset coefficient (A R ), the third is that the sampling inspection completion time is less than or equal to the preset inspection time (ATS L ), and the fourth is that there is a choice between repair and replacement. When the component is repaired, r i takes the value of 1, and R i When the component is replaced, r i takes the value of 0. R i takes the value of 1. When the component is repaired or remains unchanged, R i takes the value of 0. Because the component cannot be both repaired and replaced at the same time, so r i and R i The sum cannot be greater than 1.

[0073]

[0074] The above four constraint conditions need to be satisfied simultaneously to enter the calculation of the selective maintenance cost, sampling inspection quality cost, and sampling inspection plan delay cost. When these four constraint conditions are met, the maintenance result can achieve the following effects: (1) the maintenance time is less than or equal to the expectation; (2) the reliability reaches the standard; (3) the sampling inspection time is less than or equal to the expectation; (4) the same component is not replaced and repaired at the same time.

[0075] The selective maintenance cost is the maintenance cost generated when different maintenance decisions are selected to maintain each component. The sampling inspection quality cost is the cost generated when sampling and inspecting each component. For example, when the current state of a component is misjudged and a component that should have remained unchanged is replaced or repaired, a misjudgment cost is generated. The sampling inspection plan delay cost is the sampling inspection plan delay cost considering the selective maintenance cost and the sampling inspection quality cost.

[0076] Based on the maintenance decision cost model, calculate the selective maintenance cost of each to-be-determined maintenance decision. Based on the sampling inspection quality cost model, calculate the sampling inspection quality cost of each to-be-determined maintenance decision. Based on the sampling inspection plan delay cost model, calculate the sampling inspection plan delay cost of each to-be-determined maintenance decision.

[0077] Step 208: Calculate the integrated total cost of each to-be-determined maintenance decision according to the selective maintenance cost, the sampling inspection quality cost, and the sampling inspection plan delay cost.

[0078] Among them, the integrated model integrates the maintenance decision cost model, the sampling inspection quality cost model, and the sampling inspection plan delay cost model. According to the selective maintenance cost, the sampling inspection quality cost, and the sampling inspection plan delay cost of each to-be-determined maintenance decision, the integrated total cost of each to-be-determined maintenance decision can be calculated based on the integrated model.

[0079] Step 210: According to the integrated total cost of each to-be-determined maintenance decision, with the goal of minimizing the integrated total cost, determine the optimal integrated total cost, and use the to-be-determined maintenance decision corresponding to the optimal integrated total cost as the optimal maintenance decision.

[0080] Among them, when obtaining the integrated total cost of each to-be-determined maintenance decision, in order to obtain the integrated total cost with the smallest cost value, therefore, it is necessary to determine the optimal integrated total cost with the goal of minimizing the integrated total cost. The optimal integrated total cost is the total cost value that is infinitely close to the minimum integrated total cost. According to the determined optimal integrated total cost, determine the to-be-determined maintenance decision corresponding to the optimal integrated total cost as the optimal maintenance decision. When the optimal maintenance decision is determined, the integrated total cost corresponding to the optimal maintenance decision is the optimal integrated total cost.

[0081] In the above electrical equipment maintenance decision optimization method, an inspection plan sequence with the minimum delay cost for the electrical equipment is obtained as the optimal inspection plan sequence; according to the optimal inspection sequence, each to-be-determined maintenance decision is determined, and the to-be-determined maintenance decision is a maintenance decision that needs to be tested to obtain the optimal maintenance decision; for each to-be-determined maintenance decision: according to the constraint conditions of the preset integrated model, when each to-be-determined maintenance decision meets the constraint conditions, calculate the selective maintenance cost, inspection quality cost, and inspection plan delay cost of each to-be-determined maintenance decision; according to the selective maintenance cost, inspection quality cost, and inspection plan delay cost, calculate the integrated total cost of each to-be-determined maintenance decision. According to each integrated total cost, with the goal of minimizing the integrated total cost, determine the optimal integrated total cost, and use the to-be-determined maintenance decision corresponding to the optimal integrated total cost as the optimal maintenance decision. That is, first consider the optimal inspection plan sequence. When the delay cost is minimized and each to-be-determined maintenance decision meets the constraint conditions of the integrated model, calculate the selective maintenance cost, inspection quality cost, and inspection plan delay cost according to the to-be-determined maintenance decision. According to these three costs, calculate the integrated total cost corresponding to each qualified to-be-determined maintenance decision, so as to determine the optimal integrated total cost with the goal of minimizing the integrated total cost, and use the to-be-determined maintenance decision corresponding to the optimal integrated total cost as the optimal maintenance decision. It can be seen that the acquisition of the optimal integrated total cost fully considers the correlation among the selective maintenance cost, inspection quality cost, and inspection plan delay cost. Therefore, this application can reduce the total cost of maintenance decisions, and the obtained optimal integrated total cost is no longer fragmented but comprehensively considers the comprehensive factors of each link, so as to further improve the maintenance quality on the basis of reducing the total cost of maintenance decisions.

[0082] In one embodiment, according to the integrated total cost of each to-be-determined maintenance decision, with the goal of minimizing the integrated total cost, determine the optimal integrated total cost, and use the maintenance decision corresponding to the optimal integrated total cost as the optimal maintenance decision, including: according to the intelligent algorithm and the integrated total cost of each to-be-determined maintenance decision, search for the optimal integrated total cost with the goal of minimizing the integrated total cost, and the intelligent algorithm includes simulated annealing algorithm and ant colony algorithm; when the intelligent algorithm finds the optimal integrated total cost, stop searching for the optimal integrated total cost, and determine the to-be-determined maintenance decision corresponding to the optimal integrated total cost as the optimal maintenance decision.

[0083] Among them, when determining the optimal maintenance decision with the goal of minimizing the integrated total cost, the intelligent algorithm can be used to perform optimization calculation on the integrated total cost of each to-be-determined maintenance decision, that is, with the goal of obtaining the minimum integrated total cost, search for the corresponding optimal integrated total cost. Among them, the intelligent algorithm includes simulated annealing algorithm and ant colony algorithm, but is not limited to these two algorithms, and other optimization algorithms are also applicable to this solution.

[0084] Iteratively search for a smaller value of the integrated total cost according to the intelligent algorithm. The smaller the obtained integrated total cost value, the better the to-be-tested maintenance decision. When the minimum value of the integrated total cost is found, the intelligent algorithm reaches the stop condition and stops the optimization calculation. Take this minimum integrated total cost as the optimal integrated total cost, and take the to-be-tested maintenance decision corresponding to this optimal integrated total cost as the optimal decision parameter.

[0085] In this embodiment, with the goal of minimizing the integrated total cost, the intelligent algorithm is used to optimize the integrated total cost of each to-be-maintained decision, determine the optimal integrated total cost, and determine the optimal integrated total cost as the optimal maintenance decision. Through the optimization calculation of the intelligent algorithm, the obtained optimal integrated total cost is more accurate, and the corresponding optimal maintenance decision is also more scientific.

[0086] In one embodiment, before obtaining the sampling inspection plan sequence with the minimum delay cost of the electrical equipment, it further includes: respectively establishing a maintenance decision cost model, a sampling inspection quality cost model, and a sampling inspection plan delay cost model; constructing an integrated model according to the maintenance decision cost model, the sampling inspection quality cost model, and the sampling inspection plan delay cost model.

[0087] Among them, the maintenance decision cost model is established based on the maintenance costs generated when different maintenance decisions are selected to maintain each component, and is used to calculate the cost of selective maintenance. The sampling inspection quality cost model is established by modeling the costs generated during the sampling inspection of each component, and is used to calculate the sampling inspection quality cost. The sampling inspection plan delay cost model is established by combining the selective maintenance cost and the sampling inspection quality cost, and is used to calculate the sampling inspection plan delay cost. The sampling inspection quality cost model and the sampling inspection plan delay cost model. According to the maintenance decision cost model, the sampling inspection quality cost model, and the sampling inspection plan delay cost model, an integrated model is constructed. Specifically, E(S + M / Q) = E(M) + E(Q) + E(S), where E(M) is the maintenance decision cost model, E(Q) is the sampling inspection quality cost model, E(S) is the sampling inspection plan delay cost model, and E(S + M / Q) is the integrated model.

[0088] In this embodiment, by respectively establishing a maintenance decision cost model, a sampling inspection quality cost model, and a sampling inspection plan delay cost model, and constructing an integrated model according to these three cost models, the integrated model integrates three cost models, namely the maintenance decision cost model, the sampling inspection quality cost model, and the sampling inspection plan delay cost model. Therefore, the integrated total cost calculated based on the integrated model takes into account the three factors of sampling inspection plan delay, sampling inspection quality cost, and selective maintenance decision, enhancing the correlation between the factors.

[0089] In one embodiment, the maintenance decision cost model includes a first replacement cost, the first repair cost, and the maintenance failure cost. When calculating the cost of selective maintenance according to the maintenance decision cost model, the method includes: obtaining the first replacement cost, the first repair cost, and the maintenance failure cost of each of the components; obtaining the cost of selective maintenance based on the sum of the first replacement cost, the first repair cost, and the maintenance failure cost of each of the components.

[0090] Among them, the maintenance decision cost model includes a first replacement cost, a first repair cost, and a maintenance failure cost. The first replacement cost is the cost of replacing a component (the first replacement cost is the replacement cost of all components), the first repair cost is the cost of repairing a component (the first repair cost is the repair cost of all components), and the maintenance failure cost (the cost of all component maintenance failures) includes the cost of replacing a component but the replacement fails (the replaced component still cannot ensure normal operation), and the cost of repairing a component but the repair fails (the repaired component still cannot ensure normal operation). When calculating the cost of selective maintenance according to the maintenance decision cost model, obtain the first replacement cost, the first repair cost, and the maintenance failure cost of each component. Add up the first replacement cost, the first repair cost, and the maintenance failure cost to obtain the cost of selective maintenance.

[0091] The maintenance decision cost model is Among them, n is the number of components, CR i is the replacement cost of the i-th component, Cf i is the maintenance failure cost of the i-th component, Cr i is the repair cost of the i-th component, and E(M) is the cost of selective maintenance of all components.

[0092] In this embodiment, by obtaining the first replacement cost, the first repair cost, and the maintenance failure cost of each component and adding them up, the cost of selective maintenance is obtained, so that the cost of selective maintenance comprehensively considers the costs of replacing, repairing, and replacing / repairing failure of each component.

[0093] In one embodiment, before replacing or repairing each of the components, the method further includes: obtaining the average remaining life, average life, and cost of each of the components of the electrical equipment; obtaining the proportion of the remaining life of each component according to the ratio of the average remaining life and the average life of each of the components; obtaining the remaining loss cost of each of the components according to the product of the proportion of the remaining life of each of the components and the cost, and the remaining loss cost is the loss cost of abandoning the remaining life of the component and choosing to repair or replace.

[0094] Among them, when calculating the cost of selective maintenance according to the maintenance decision cost model, first obtain the remaining loss cost of each component. The remaining loss cost of each component is the loss cost generated by abandoning the remaining life of the component. The calculation formula for calculating the remaining loss cost of each component is as follows:

[0095]

[0096] Among them, C i is the cost of purchasing the i-th component, M i is the average life of the i-th component, MR i is the average remaining life of the i-th component, CL i is the remaining loss cost of the i-th component. The average life refers to the average service life of this type of component. is the proportion of the remaining life. The average remaining life refers to the remaining service life of this type of component compared to the average life of this type of component after it has been used for a period of time and before making a maintenance decision currently. The remaining loss cost is the loss cost when abandoning the remaining life of the component before its service life is exhausted and choosing to repair or replace it.

[0097] In this embodiment, by obtaining the average remaining life, average life, and cost of each component, according to the ratio of the remaining life and average life of each component, the proportion of the remaining life of each component is obtained, and the product of the proportion of the remaining life of each component and the cost is calculated to obtain the remaining loss cost of each component. Before replacing or repairing each of the components, calculating the remaining loss cost of each component and taking this part of the remaining loss cost into consideration is beneficial to further improving the selective maintenance cost.

[0098] In one embodiment, obtaining the first replacement cost of each of the components includes: obtaining the working efficiency of the electrical equipment and the loss cost when the electrical equipment is not working, and obtaining the total loss cost when the electrical equipment is not working according to the product of the working efficiency and the loss cost; obtaining the loss cost per unit time according to the sum of the total loss cost and the maintenance labor cost; obtaining the total loss cost during the replacement time according to the sum of the product of the loss cost per unit time and the replacement time of each of the components; obtaining the first replacement cost according to the sum of the total loss cost during the replacement time, the cost of each of the components, and the remaining loss cost.

[0099] Among them, the calculation formula for the replacement cost of a single component in the sampling inspection plan sequence is: CR i =[TR i ×(η×C<( l +C p )+C i+CL i , the first replacement cost is the sum of the replacement costs of each component in the sampling inspection plan sequence, and the first replacement cost is pre-set and stored in the terminal, where, TR i is the replacement time of the i-th component, η is the working efficiency of the electrical equipment, C l is the loss cost when the electrical equipment is not working, C p is the maintenance labor cost, C i is the cost of purchasing the i-th component, CL i is the remaining loss cost of the i-th component, CR i is the replacement cost of the i-th component, η×C l is the total loss cost, η×C l +C p is the loss cost per unit time, is the total loss cost during the replacement time, is the first replacement cost, is the cost of each component in the sampling inspection plan sequence, is the remaining loss cost of each component in the sampling inspection plan sequence.

[0100] In this embodiment, by obtaining the working efficiency of the electrical equipment and the loss cost when it is not working, the total loss cost when the electrical equipment is not working is obtained according to the product of the working efficiency and the loss cost. According to the sum of the total loss cost and the maintenance labor cost, the loss cost per unit time can be calculated. Based on the sum of the products of the loss cost per unit time and the replacement times of each component, the total loss cost during the replacement time is obtained. According to the sum of the total loss cost during the replacement time, the costs of each component, and the remaining loss costs, the first replacement cost can be calculated.

[0101] In one embodiment, obtaining the first repair cost of each of the components includes: for each of the components, obtaining the repair time of each of the components, and obtaining the total loss cost during the repair time according to the sum of the products of the loss cost per unit time and the repair times of each of the components; obtaining the first repair cost according to the sum of the total loss cost during the repair time and the cost of maintenance consumables.

[0102] Among them, the calculation formula for the repair cost of a single component in the sampling inspection plan sequence is Cr i =[Tr i ×(η×C l +C p )+C si , where, Tr i is the repair time of the zero i-th component, C si is the cost of maintenance consumables, η is the working efficiency of the electrical equipment, C pFor the maintenance labor cost, C l For the loss cost when the electrical equipment is not working, Cr i For the repair cost of the i-th component, η×C l For the total loss cost, η×C l +C p For the loss cost per unit time, Tr i ×(η×C l +C p ) is the product of the loss cost per unit time and the repair time of a single component, which is the loss cost during the repair time of a single component. By accumulating the loss costs during the repair times of each component in the sampling inspection plan sequence, the total loss cost during the repair time can be obtained. For the cost of maintenance consumables for each component, That is, the first repair cost is obtained. (The sum of the repair costs of each component in the sampling inspection plan sequence).

[0103] In this embodiment, for each component, the repair time of each component is obtained, and the total loss cost during the repair time is obtained according to the sum of the products of the loss cost per unit time and the repair times of each component; according to the sum of the total loss cost during the repair time and the cost of maintenance consumables, the first repair cost can be obtained.

[0104] In one embodiment, obtaining the maintenance failure cost of each of the components includes: for each of the components, the maintenance failure cost includes a replacement failure cost and a repair failure cost. When replacing each of the components, the replacement failure cost is obtained according to the sum of the total loss cost during the replacement time and the cost of each of the components; when repairing each of the components, the maintenance failure cost is obtained according to the sum of the total loss cost during the repair time and the cost of maintenance consumables.

[0105] Among them, the calculation formula for the maintenance failure cost is Cf i =[TC i ×(η×C l +C p )+R i ×C i +r i ×C si , in the formula,

[0106]

[0107] When the maintenance decision is to replace a component, the calculation formula for the maintenance failure cost of a single component represents the corresponding calculation formula when replacing fails: Cf i =[TR i ×(η×Cl +C p )+C i .

[0108] When the maintenance decision is to repair a component, the calculation formula for the maintenance failure cost of a single component represents the corresponding calculation formula when the repair fails: Cf i =[Tr i ×(η×C l +C p )+C si .

[0109] The cost of repair failure is the same as the cost of repair, while replacement failure does not result in the remaining loss cost of the component. Because in the case of replacement failure, the original component is still used, so there is no remaining life loss cost, that is, subtract the CL i term. This is the difference between the two. Here, it is considered that the replacement and repair fail, but the equipment can still work in the same state as before.

[0110] In this embodiment, for each component, the maintenance failure cost includes the replacement failure cost and the repair failure cost. When replacing each component, the replacement failure cost is obtained according to the sum of the total loss cost during the replacement time and the cost of each component. When repairing each component, the maintenance failure cost can be calculated according to the sum of the total loss cost during the repair time and the cost of maintenance consumables.

[0111] In one embodiment, according to the sum of the first replacement cost, the first repair cost and the maintenance failure cost of each of the components, the cost of selective maintenance is obtained, including: for each of the components, multiplying the maintenance failure cost by the possibility coefficient that the component cannot continue to work, to obtain the corresponding failure cost; adding up the failure costs to obtain the total failure cost; and obtaining the cost of selective maintenance according to the sum of the total failure cost, the first replacement cost and the first repair cost.

[0112] Among them, the maintenance decision cost model is:

[0113]

[0114] n is the number of components, CR i is the first replacement cost of the i-th component, Cf i is the maintenance failure cost of the i-th component, Cr i is the first repair cost of the i-th component, R t is the reliability that the component can continue to work until the end of its life, which is the reliability coefficient, 1 - R tThe possibility coefficient that the component cannot continue to work, Cf i ×(1 - R t ) is the failure cost corresponding to each component. By accumulating the failure costs corresponding to each component, we get which is the total failure cost. The first repair cost, is the first replacement cost, and E(M) is the cost of selective maintenance for all components.

[0115] There is a possibility of maintenance failure. When calculating the maintenance failure cost, multiplying by the possibility coefficient that the component cannot continue to work, as part of the total maintenance cost, can make the calculated maintenance failure cost more accurate.

[0116] In this embodiment, for each component, multiply the maintenance failure cost by the possibility coefficient that the component cannot continue to work to obtain the corresponding failure cost; add up the failure costs to get the total failure cost; according to the sum of the total failure cost, the first replacement cost and the first repair cost, the cost of selective maintenance can be obtained.

[0117] In one embodiment, the sampling inspection quality cost model includes the sampling inspection cost, misjudgment cost, cost of investigating the reason for misjudgment, second replacement cost when the sampling inspection is unqualified, second repair cost when the sampling inspection is unqualified, and cost of resuming operation of the electrical equipment; when calculating the sampling inspection quality cost according to the sampling inspection quality cost, the method includes: obtaining the sampling inspection cost, misjudgment cost, cost of investigating the reason for misjudgment, second replacement cost when the sampling inspection is unqualified, second repair cost when the sampling inspection is unqualified, and cost of resuming operation of the electrical equipment; multiplying the sum of the sampling inspection cost, the misjudgment cost, the cost of investigating the reason for misjudgment, the second replacement cost, the second repair cost and the cost of resuming operation by the expected cycle length of the sampling inspection to obtain the sampling inspection quality cost.

[0118] Among them, considering two types of detection faults, the situation that causes the need for immediate shutdown for detection is called F1 detection fault, and the situation that causes the machine to degrade or the component quality to deteriorate is F2 detection fault (the equipment can still work, but not under the rated conditions, but is detected when the component quality deteriorates or the equipment degrades). The F2 detection failure rate is:

[0119]

[0120] In the formula, T S is the time interval between the current maintenance and the next maintenance, E(F2) is the number of faults that may cause detection fault F2 during the equipment operation, is the duration of the component in the F2 detection fault, Represents the failure rate.

[0121] The time interval τ (corrective action time) is:

[0122]

[0123] In the formula, H S is the sample time interval, λ is the failure rate detected by F2, τ is the time parameter, referring to the interval time when the corrective action occurs in the interval [i, i + 1]. The samples in this article specifically refer to the various components of electrical equipment.

[0124] The probability α of detecting defective products is:

[0125]

[0126] In the formula, d is the number of defective products (samples that failed the spot check) in the sample, D is the number of qualified products (samples that passed the spot check), N is the total sample size, and P1 is the average proportion of defective products.

[0127] The probability of not detecting defective products in the sample is:

[0128]

[0129] The expected number of samples collected, E s is:

[0130]

[0131] In the formula, H S is the sample time interval, and λ is the failure rate detected by F2.

[0132] The cycle duration of sampling is:

[0133]

[0134] In the formula, the control period (during which the failure can be controlled) is assumed to follow a negative exponential distribution, and the average value is 1 / λ. T F ×E s ×α is the total duration of investigating the misjudgment reason. is the duration of the F2 detection failure. is the sampling duration. T F is the time for investigating the misjudgment reason (investigation misjudgment time). T S is the time required for sampling. T1 is the detection duration, and T2 is the recovery operation duration.

[0135] The spot check quality cost model is:

[0136]

[0137] Where, T s / E(T1) is the expected inspection cycle length, E(C1) is the sampling inspection cost, E(C2) is the misjudgment cost, E(C3) is the cost of investigating the cause of the misjudgment, E(C6) is the cost of resuming operation, and E(C4 / C5) represents the secondary replacement cost when the sample is replaced, and the secondary repair cost when the sample is repaired. Table 2 illustrates the sampling quality cost of a component. Each sampling inspection plan can be calculated to obtain the sampling quality cost. Table 2 uses a line insulator string as an example to illustrate the sampling inspection plan for the line insulator string:

[0138] Table 2

[0139]

[0140] In one embodiment, when obtaining the sampling inspection cost of the electrical equipment, the method includes: obtaining the expected number of samples and the number of detected faults of the components in the electrical equipment, and obtaining the actual number of random inspection samples based on the ratio of the expected number of samples to the number of detected faults, and the product of the ratio and the total sample size; obtaining the unit random inspection cost, and multiplying the unit random inspection cost by the actual number of random inspection samples to obtain the sampling inspection cost.

[0141] The calculation formula for sampling inspection cost is:

[0142]

[0143] Where, is the ratio of the expected number of samples to the number of faults detected by F2, C is +T S ×η×C l ×δ S The unit inspection cost for each sample, C is The inspection fee for each sample, T S ×η×C l ×δ S The sampling cost for each sample.

[0144] In this embodiment, the expected number of samples and the number of detected faults for components in electrical equipment are obtained. The actual number of samples for random inspection is calculated based on the ratio of the expected number of samples to the number of detected faults, and the product of the ratio and the total sample size. The unit inspection cost is obtained and multiplied by the actual number of samples for random inspection to obtain the sampling inspection cost.

[0145] In one embodiment, when obtaining the misjudgment cost of the electrical equipment, the method includes: obtaining the investigation misjudgment time, the expected number of samples, the sample defect probability, the misjudgment cost, and the loss cost; obtaining the misjudgment cost according to the product of the investigation misjudgment time, the expected number of samples, the sample defect probability, the misjudgment cost, and the loss cost.

[0146] Among them, the calculation formula for the misjudgment cost is:

[0147] E(C2) = T F ×E s ×α×(C F +η×C l ),

[0148] In the formula, T F is the time for investigating the misjudgment reason (investigation misjudgment time), E s is the expected number of samples, α is the probability of detecting defective products, C F is the misjudgment cost, η×C l is the total loss cost, and E(C2) is the misjudgment cost.

[0149] In one embodiment, when obtaining the cost of investigating the misjudgment reason of the electrical equipment, the method includes: obtaining the detection duration of the sample and the investigation cost; obtaining the cost of investigating the misjudgment reason according to the sum of the investigation cost and the loss cost, and the product of the sum and the detection duration.

[0150] Among them, the calculation formula for the cost of investigating the misjudgment reason is:

[0151] E(C3) = T1×(C c +η×C l ),

[0152] In the formula, C c is the investigation cost, η×C l is the loss cost, C c +η×C l is the sum of the investigation cost and the loss cost, T1 is the detection duration, and E(C3) is the cost of investigating the misjudgment reason.

[0153] In one embodiment, when obtaining the second replacement cost when the sampling inspection of the electrical equipment is unqualified, the method includes: obtaining the duration of the detected fault; obtaining the total sampling detection duration according to the sum of the duration and the time interval from sampling to the end of detection; obtaining the maintenance cost corresponding to the defective products that are unqualified in the sampling inspection of the sample; obtaining the second replacement cost when the sampling inspection is unqualified according to the product of the total sampling detection duration, the maintenance cost, and the work efficiency.

[0154] Among them, the calculation formula for the second replacement cost is as follows:

[0155]

[0156] In the formula, is the duration of the F2 detection failure, T l is the time interval from sampling to the end of detection, C is is the inspection fee for each sample, C j is the maintenance cost for each defective product, The sum is the total duration of sampling inspection. Multiply the total duration of sampling inspection, work efficiency, and maintenance cost, and the result is the second replacement cost when the sampling inspection is unqualified.

[0157] In one embodiment, when obtaining the second repair cost when the sampling inspection of the electrical equipment is unqualified, the method includes: obtaining the repairable cost of the defective products that can be repaired in the sample; obtaining the second repair cost when the sampling inspection is unqualified according to the product of the total duration of sampling inspection, the work efficiency, and the repairable cost.

[0158] Among them, the calculation formula for the second repair cost when the sampling inspection is unqualified is as follows:

[0159]

[0160] In the formula, is the total duration of sampling inspection, C is +p×P2×C w +(1 - p)×P2×C j is the repairable cost (the cost brought by the defective products that can be repaired during repair), C is is the inspection fee for each sample, p is the probability of being repairable, P2 is the average defect ratio, C w is the repair cost, and E(C5) is the second repair cost.

[0161] In one embodiment, when obtaining the cost of the electrical equipment to resume operation, the method includes: obtaining the duration to resume operation; obtaining the cost to resume operation according to the product of the work efficiency, the loss cost, and the duration to resume operation, and the sum of the product and the cost to resume operation.

[0162] Among them, the calculation formula for the cost to resume operation is as follows:

[0163] E(C6) = C z +(T2×η×C l ),

[0164] In the formula, C z is the cost to resume operation, T2 is the duration to resume operation, T2×η×C lThe cost of loss for the recovery process, and E(C6) is the cost of resuming operation.

[0165] In one embodiment, the sampling inspection plan sequence includes at least two batches. For the sampling inspection plan sequence of each batch, calculate the delay cost of the sampling inspection plan sequence of the current batch respectively to obtain the delay cost of the sampling inspection plan sequence of each batch, including: for the sampling inspection plan sequence of each batch, according to the sum of the actual completion time of all batches before the current batch and the processing time of the current batch, and the planned completion time of the current batch, obtain the delay duration of the sampling inspection plan sequence of the current batch; obtain the delay cost per unit time, and multiply the delay duration and the delay cost to obtain the delay cost of the sampling inspection plan sequence of the current batch.

[0166] Among them, the purpose of the sampling inspection plan is to minimize the delay cost by determining the order of the sampling inspection batches. The delay refers to the difference between the actual completion time and the planned completion time of the inspection. For the kth batch (the current batch), it can be expressed as:

[0167] ΔT k =(T k-1 +P k )-DD k ,

[0168] In the formula, T k-1 is the completion time of the first k - 1 batches, P k is the processing time of the first k batches, DD k is the planned completion time, and ΔT k is the delay duration of the sampling inspection plan sequence of the current batch.

[0169] The calculation formula for the delay cost of the sampling inspection plan sequence of the current batch is:

[0170] S=W k ×max{0,ΔT k},

[0171] In the formula, W k is the delay cost per unit time. If the delay duration ΔT k is greater than zero, then S=W k ×ΔT k , and S is the delay cost of the sampling inspection plan sequence of the current batch. Take the maximum value: if the maximum value is 0, it means there is no delay, so there is no delay cost; if the delay > 0, there will be a delay cost.

[0172] Accumulate the delay costs of the sampling inspection plan sequences of each batch to obtain the total delay cost C Tk , specifically: m is the number of batches.

[0173] In this embodiment, for the sampling inspection plan sequence of each batch, according to the sum of the actual completion times of all batches before the current batch and the processing time of the current batch, and the planned completion time of the current batch, the delay duration of the sampling inspection plan sequence of the current batch is obtained. The delay cost per unit time is obtained, and the delay duration is multiplied by the delay cost to obtain the delay cost of the sampling inspection plan sequence of the current batch.

[0174] In one embodiment, when each to-be-tested maintenance decision meets the constraint conditions, the sampling inspection plan delay cost is calculated, including: First, calculate the failure probability of the i-th component:

[0175] F(b ki ) = F(T k ) - F(T k-1 ),,

[0176] where, T k is the completion time of the first k batches, T k-1 is the completion time of the first k - 1 batches, and F(T k ) - F(T k-1 ) represents the failure probability of the i-th component in the interval [T k-1 , T k .

[0177] When the i-th component fails, the additional delay time (due to component failure, the processing batch may be delayed, and the resulting additional time) is:

[0178] T di = TC i + ATS × QF i ,

[0179] where, ATS is the sampling inspection completion time. Component failure may cause F1 detection failure or F2 detection failure. In the case of F1 detection failure, the delay duration of the sampling inspection plan sequence of each batch is only equal to the corrective action time. However, in the case of F2 detection failure, the quantity produced reaches the sampling inspection completion time and is isolated, and may be rejected / reworked, and re-production is required. Therefore, the delay duration of the sampling inspection plan sequence of each batch is the sum of the corrective action time and the sampling inspection completion time.

[0180] The delay duration of the k-th batch is:

[0181] ΔT Fk = T k-1 + P k + T di - DD k ,

[0182] The sampling inspection plan delay cost model is:

[0183]

[0184] wherein

[0185] Integrating the sampling inspection plan delay cost model, the sampling inspection quality cost model, and the maintenance decision cost model, the integrated model is obtained: E(S + M / Q) = E(M) + E(Q) + E(S),

[0186] wherein, E(S) is the sampling inspection plan delay cost model, E(Q) is the sampling inspection quality cost model, and E(M) is the maintenance decision cost model.

[0187] Table 3 takes the line insulator string as an example and gives the sampling inspection plan delay cost parameters of 10 different line insulator strings:

[0188] Table 3

[0189]

[0190]

[0191] The maintenance decision and the integrated total cost of the line insulator string obtained according to the integrated model are shown in Table 4:

[0192] Table 4

[0193]

[0194] It should be understood that although the steps in the respective flowcharts involved in the above embodiments are shown in sequence according to the arrows, these steps do not necessarily need to be executed in the order indicated by the arrows. Unless there is a clear indication in this article, the execution of these steps does not have a strict order limit, and these steps can be executed in other orders. Moreover, at least a part of the steps in the respective flowcharts involved in the above embodiments may include multiple steps or multiple stages, and these steps or stages do not necessarily need to be executed at the same moment, but can be executed at different moments, and the execution order of these steps or stages does not necessarily need to be sequential, but can be executed alternately or in turn with at least a part of other steps or steps or stages in other steps.

[0195] In one embodiment, as Figure 3 shown, an electrical equipment maintenance decision optimization device is provided, including: an optimal sequence acquisition module 301, a maintenance decision determination module 302, a cost calculation module 303, an integrated total cost calculation module 304, and an optimal integrated total cost determination module 305, wherein:

[0196] The optimal sequence acquisition module 301 is configured to acquire the sampling inspection plan sequence with the minimum delay cost for the electrical equipment as the optimal sampling inspection plan sequence;

[0197] The maintenance decision determination module 302 is configured to determine each to-be-tested maintenance decision according to the optimal sampling inspection sequence;

[0198] The cost calculation module 303 is configured to calculate the selective maintenance cost, the sampling inspection quality cost, and the sampling inspection plan delay cost of each to-be-tested maintenance decision according to the constraint conditions of the preset integrated model when each to-be-tested maintenance decision meets the constraint conditions;

[0199] The integrated total cost calculation module 304 is configured to calculate the integrated total cost of each to-be-tested maintenance decision according to the selective maintenance cost, the sampling inspection quality cost, and the sampling inspection plan delay cost;

[0200] The optimal integrated total cost determination module 305 is configured to determine the optimal integrated total cost with the goal of minimizing the integrated total cost according to the integrated total cost of each to-be-tested maintenance decision, and use the to-be-tested maintenance decision corresponding to the optimal integrated total cost as the optimal maintenance decision.

[0201] For the specific limitations of the electrical equipment maintenance decision optimization device, reference can be made to the limitations of the electrical equipment maintenance decision optimization method in the above text, which will not be elaborated here. Each module in the above electrical equipment maintenance decision optimization device can be implemented in whole or in part through software, hardware, and their combinations. The above modules can be embedded in the processor of the computer device in hardware form or be independent of it, or stored in the memory of the computer device in software form, so that the processor can call and execute the operations corresponding to the above modules.

[0202] In one embodiment, a computer device is provided. The computer device may be a terminal, and its internal structure diagram may be as Figure 4As shown in the figure. The computer device includes a processor, a memory, a communication interface, a display screen, and an input device connected by a system bus. Among them, the processor of the computer device is used to provide computing and control capabilities. The memory of the computer device includes a non-volatile storage medium and an internal memory. The non-volatile storage medium stores an operating system and computer programs. The internal memory provides an environment for the operation of the operating system and computer programs in the non-volatile storage medium. The communication interface of the computer device is used to communicate with external terminals in a wired or wireless manner. The wireless manner can be achieved through WIFI, carrier network, NFC (Near Field Communication), or other technologies. When the computer program is executed by the processor, it implements an optimization method for electrical equipment maintenance decision-making. The display screen of the computer device can be a liquid crystal display screen or an electronic ink display screen. The input device of the computer device can be a touch layer covering the display screen, or a button, trackball, or touchpad provided on the computer device housing, or an external keyboard, touchpad, or mouse, etc.

[0203] Those skilled in the art can understand that Figure 4 the structure shown in the figure is only a block diagram of some structures related to the solution of this application, and does not constitute a limitation on the computer device to which the solution of this application is applied. The specific computer device may include more or fewer components than those shown in the figure, or combine some components, or have different component arrangements.

[0204] In one embodiment, a computer device is further provided, including a memory and a processor. A computer program is stored in the memory. When the processor executes the computer program, the steps in the above method embodiments are implemented.

[0205] In one embodiment, a computer-readable storage medium is provided, on which a computer program is stored. When the computer program is executed by the processor, the steps in the above method embodiments are implemented.

[0206] Those of ordinary skill in the art can understand that all or part of the processes in the methods of the above embodiments can be completed by instructing relevant hardware through a computer program. The computer program can be stored in a non-volatile computer-readable storage medium. When the computer program is executed, it can include the processes of the embodiments of the above various methods. Among them, any reference to a memory, storage, database, or other medium used in the various embodiments provided in this application can include at least one of non-volatile and volatile memories. Non-volatile memory can include read-only memory (ROM), magnetic tape, floppy disk, flash memory, or optical memory, etc. Volatile memory can include random access memory (RAM) or external cache memory. By way of illustration and not limitation, RAM can be in various forms, such as static random access memory (SRAM) or dynamic random access memory (DRAM), etc.

[0207] The technical features of the above embodiments can be combined arbitrarily. For the sake of concise description, not all possible combinations of the technical features in the above embodiments are described. However, as long as there is no contradiction in the combination of these technical features, it should be considered as the scope recorded in this specification.

[0208] The above-described embodiments merely represent several implementation manners of this application. Their descriptions are relatively specific and detailed, but they should not be construed as limitations on the scope of the invention patent. It should be noted that for those of ordinary skill in the art, without departing from the concept of this application, several modifications and improvements can still be made, and these all belong to the protection scope of this application. Therefore, the protection scope of the patent of this application shall be subject to the appended claims.

Claims

1. A method for optimizing electrical equipment maintenance decisions, characterized in that: The method is implemented by a terminal, and includes: Establish maintenance decision cost model, sampling quality cost model and sampling plan delay cost model respectively; constructing an integrated model based on the maintenance decision cost model, the spot inspection quality cost model, and the spot inspection plan delay cost model; The terminal obtains a sampling inspection plan sequence for each batch of electrical equipment from the server, and locally uses the sampling inspection plan sequence with the minimum delay cost as the optimal sampling inspection plan sequence; The terminal requests the server to obtain each maintenance decision to be tested according to the optimal sampling plan sequence, and obtains each maintenance decision to be tested sent by the server in response to the request; According to the constraints of the preset integrated model, when each maintenance decision to be tested meets the constraints, the selective maintenance cost, the sampling quality cost and the sampling plan delay cost of each maintenance decision to be tested are calculated; Calculating the integrated total cost of each maintenance decision to be tested based on the selective maintenance cost, the random inspection quality cost, and the random inspection plan delay cost; Determining an optimal integrated total cost based on the integrated total cost of each maintenance decision to be tested, with the goal of minimizing the integrated total cost, and taking the maintenance decision to be tested corresponding to the optimal integrated total cost as the optimal maintenance decision; According to the maintenance decision cost model, the sampling quality cost model and the sampling plan delay cost model, an integrated model is constructed to satisfy the formula: ； in, is the maintenance decision cost model, is the sampling quality cost model, is the inspection plan delay cost model, It is an integrated model; The constraints include: the maximum time for selective maintenance is not greater than the preset maintenance time, the minimum reliability coefficient of selective maintenance is not less than the preset coefficient, the sampling inspection time is not greater than the preset inspection completion time, and the decision of repair or replacement is either one or the other; The selective repair and replacement decision means that the same component cannot be repaired and replaced at the same time, and the selective repair is a repair performed based on the choice made by the repair decision.

2. The method according to claim 1, characterized in that The method includes determining an optimal integrated total cost based on the integrated total cost of each maintenance decision to be tested and taking minimizing the integrated total cost as a goal, and taking the maintenance decision to be tested corresponding to the optimal integrated total cost as the optimal maintenance decision, including: Finding an optimal total integrated cost based on an intelligent algorithm and the total integrated cost of each maintenance decision to be tested with the goal of minimizing the total integrated cost, wherein the intelligent algorithm includes a simulated annealing algorithm and an ant colony algorithm; When the intelligent algorithm finds the optimal integrated total cost, the search for the optimal integrated total cost is stopped, and the maintenance decision to be tested corresponding to the optimal integrated total cost is determined as the optimal maintenance decision.

3. The method according to claim 1, characterized in that The delay cost is the delay cost incurred when the total time for spot checking samples of various components of electrical equipment exceeds the planned time.

4. The method according to claim 3, characterized in that The maintenance decision cost model includes a first replacement cost, a first repair cost, and a maintenance failure cost. When calculating the cost of selective maintenance according to the maintenance decision cost model, the method includes: Obtaining a first replacement cost, a first repair cost, and a repair failure cost for each of the components; The cost of selective maintenance is obtained according to the sum of the first replacement cost, the first repair cost and the maintenance failure cost of each component.

5. The method according to claim 1, characterized in that Before replacing or repairing each component, the method further includes: Obtaining the average remaining life, average life, and cost of each of the components; Obtaining a proportion of the remaining life of each component according to a ratio of the average remaining life of each component to the average life; The remaining loss cost of each component is obtained by multiplying the proportion of the remaining life of each component by the cost. The remaining loss cost is the loss cost when the remaining life of the component is abandoned and repair or replacement is chosen.

6. The method according to claim 4, characterized in that Obtaining the first replacement cost, first repair cost, and repair failure cost of each component, including: Obtaining the working efficiency of the electrical equipment and the loss cost when the electrical equipment is not working, and obtaining the total loss cost when the electrical equipment is not working based on the product of the working efficiency and the loss cost; obtaining the loss cost per unit time based on the sum of the total loss cost and the maintenance labor cost; obtaining the total loss cost within the replacement time based on the sum of the product of the loss cost per unit time and the replacement time of each of the components; and obtaining the first replacement cost based on the sum of the total loss cost within the replacement time, the cost of each of the components, and the remaining loss cost; For each component, the repair time of each component is obtained, and the total loss cost within the repair time is obtained by summing the product of the loss cost per unit time and the repair time of each component; and the first repair cost is obtained by summing the total loss cost within the repair time and the cost of maintenance consumables; For each of the components, the maintenance failure cost includes the replacement failure cost and the repair failure cost. When replacing each of the components, a replacement failure cost is obtained based on the sum of the total loss cost within the replacement time and the cost of each component; When each of the components is repaired, the repair failure cost is obtained based on the sum of the total loss cost within the repair time and the cost of the repair consumables.

7. The method according to claim 4, characterized in that The cost of selective maintenance is obtained according to the sum of the first replacement cost, the first repair cost, and the maintenance failure cost of each component, including: For each component, multiply the repair failure cost by the probability coefficient of the component being unable to continue working to obtain a corresponding failure cost; Adding up the failure costs to obtain the total failure cost; The cost of the selective maintenance is obtained according to the sum of the total failure cost, the first replacement cost and the first repair cost.

8. The method according to claim 3, characterized in that The sampling inspection quality cost model includes the sampling inspection cost of the electrical equipment, the misjudgment cost, the cost of investigating the cause of the misjudgment, the second replacement cost when the sampling inspection fails, the second repair cost when the sampling inspection fails, and the cost of resuming operation; the method includes: Obtaining the sampling inspection cost, misjudgment cost, misjudgment cause investigation cost, second replacement cost in case of unqualified sampling inspection, second repair cost in case of unqualified sampling inspection, and operation resumption cost of the electrical equipment; The sampling inspection quality cost is obtained by multiplying the sum of the sampling inspection cost, the misjudgment cost, the cost of investigating the cause of misjudgment, the second replacement cost, the second repair cost and the cost of resuming operation by the expected cycle length of the sampling inspection.

9. The method according to claim 8, characterized in that The cost of sampling inspection, misjudgment cost, cost of investigating the cause of misjudgment, second replacement cost in case of unqualified sampling inspection, second repair cost in case of unqualified sampling inspection and cost of resuming operation of the electrical equipment shall include: Obtaining the expected number of samples and the number of detected faults of the components of the electrical equipment, and obtaining the actual number of samples for random inspection based on the ratio of the expected number of samples to the number of detected faults and the product of the ratio and the total sample size; obtaining the unit random inspection cost, and multiplying the unit random inspection cost by the actual number of random inspection samples to obtain the sampling inspection cost; Obtaining the investigation misjudgment time, the expected number of samples, the probability of sample defects, the misjudgment fee, and the loss cost; obtaining the misjudgment cost by multiplying the investigation misjudgment time, the expected number of samples, the probability of sample defects, the misjudgment fee, and the loss cost; Obtaining the sample testing time and investigation fee; obtaining the cost of investigating the cause of the misjudgment based on the sum of the investigation fee and the loss cost, and the product of the sum and the testing time; Obtain the duration of the detection fault; obtain the total sampling detection duration based on the sum of the duration and the time interval from sampling to completion of the detection; obtain the maintenance cost corresponding to the defective products in the sample that failed the random inspection; and obtain the second replacement cost in the event of a random inspection failure based on the product of the total sampling detection duration, the maintenance cost, and the work efficiency; Obtaining the repairable cost of the repairable defective products in the sample; obtaining a second repair cost when the sampling inspection fails based on the product of the total sampling inspection time, the work efficiency, and the repairable cost; Obtaining the recovery operation time; obtaining the recovery operation cost according to the product of the work efficiency, the loss cost and the recovery operation time, and the sum of the product and the recovery operation fee.

10. The method according to claim 1, characterized in that The sampling inspection plan sequence includes at least two batches, and the method further includes: For each batch of sampling inspection plan sequence, the delay time of the current batch of sampling inspection plan sequence is obtained based on the sum of the actual completion time of all batches before the current batch and the processing time of the current batch, as well as the planned completion time of the current batch; Obtain the delay cost per unit time, multiply the delay duration and the delay cost to obtain the delay cost of the inspection plan sequence of the current batch.

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