A faucet and its flow cut-off elimination algorithm
By designing a faucet that includes a specific through-hole structure and a ball head, the problem of flow interruption caused by bubble accumulation in the existing ice dropper pot faucet is solved, and the smooth passage of water droplets and air is achieved and blocked.
Patent Information
- Application Number
- CN202210482304.0
- Authority / Receiving Office
- CN · China
- Patent Type
- Patents(China)
- Current Assignee / Owner
- Filing Date
- 2022-05-05
- Publication Date
- 2025-05-30
- Estimated Expiration
- 2042-05-05
AI Technical Summary
The existing ice dropper faucet has a flow cut, and bubbles accumulate in the runner, causing blockage and unable to pass through the faucet.
A faucet is designed, which includes a shell, sealed and embedded rubber pad, adjustment knob and a specific through-hole structure. Through the gap between the ball head and the inner wall of the through-hole, water droplets and air can pass smoothly to avoid bubble accumulation.
Effectively prevent small bubbles from adsorbing on the inner wall of the through holes, avoiding large bubbles, ensuring that water droplets and air can pass smoothly, and completely solving the blockage problem.
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Figure CN115095677B_ABST
Abstract
Description
Technical Field
[0001] The present invention relates to a faucet and a flow interruption elimination algorithm thereof. Background Art
[0002] The ice drip kettle is characterized in that there is a container at the top to store liquid, and after the faucet is connected to the container, it is required that the water flow drips from the water outlet end in a drip-by-drip manner; however, at present, the faucets supporting the ice drip kettles in the industry have the phenomenon of flow interruption. The reason is that the existing faucet structure is prone to accumulating air bubbles. When the air bubbles block at the narrow part of the flow channel, they will sink all the way to the faucet switch and cannot pass through the faucet due to the surface tension of water. Eventually, the air cannot rise or pass through under the action of pressure, resulting in blockage, which needs to be further improved. Summary of the Invention
[0003] Aiming at the current situation of the above-mentioned existing technology, the technical problem to be solved by the present invention is to provide a faucet and a flow interruption elimination algorithm thereof that can ensure that both water droplets and air can smoothly pass through the gap between the ball head and the inner wall of the through hole to completely solve the blockage problem.
[0004] The technical solution adopted by the present invention to solve the above technical problems is as follows: A faucet, characterized in that it includes a housing, a rubber gasket hermetically embedded inside the housing, and an adjusting knob screwed through one side of the housing. A tapered counterbore is opened at the center of the upper end of the rubber gasket, and a through hole is opened on the bottom surface of the tapered counterbore; a side hole is opened on the inner wall of one side of the through hole, and a sealing section is formed outward at the threaded end of the adjusting knob. The end of the sealing section passes through the side hole in an interference fit and vertically extends into the through hole. The outer wall of the end of the sealing section is hermetically attached to the inner wall of the through hole, and a ball head is further formed at the end of the sealing section. The outer wall of the ball head cooperates with the outer wall of the through hole.
[0005] Preferably, a counterbore is opened at the upper end of the housing, and a rubber sleeve is also hermetically embedded in the counterbore.
[0006] Preferably, a cavity is opened at the center of the bottom surface of the counterbore, and the rubber gasket is hermetically embedded in the cavity.
[0007] Preferably, a water outlet hole is opened at the center of the bottom surface of the cavity, and the upper end opening of the water outlet hole is communicated with the lower end opening of the through hole.
[0008] Preferably, the distance h between the upper side edge of the inner end opening of the side hole and the upper end opening of the through hole is 1 mm.
[0009] Preferably, the included angle b between the inner wall of the tapered counterbore and the inner wall of the through hole is 45 degrees.
[0010] Preferably, the inner diameter of the through hole is greater than 3 mm.
[0011] A flow cut elimination algorithm for a faucet, characterized by comprising the following steps:
[0012] (1) Consider the acceleration a generated by (buoyancy - gravity);
[0013] From ρ 液 v 排 g - mg = ma
[0014] ρ 液 v 排 g = ρ 气 v 排 (a + g)
[0015] We get: a = (ρ 液 / ρ 气 - 1)g;
[0016] (2) Consider the influence of the negative acceleration generated by the water resistance;
[0017] The resistance f is proportional to the square of the bubble radius r and proportional to the square of the velocity v;
[0018] That is: the resistance is f 阻 = kr 2 v 2
[0019] From: kr 2 v 2 = ma = ρ 气 (4pai / 3)r 3 a
[0020] We get: a 负 = 3kvv / (4paiρ gas r)
[0021] (3) Consider the influence of velocity on the resistance;
[0022] When the bubble velocity reaches the stable maximum value, the resistance f = (buoyancy - gravity), that is, the absolute values of the two accelerations obtained in steps (1) and (2) are equal;
[0023] From (ρ 液 / ρ 气 - 1)g = 3kv 2 / (4paiρ 气 r)
[0024] The maximum velocity is obtained as:
[0025] v = (4pai / 3k)(ρ 液 - ρ 气 )gr
[0026] (4) Consider the influence of deformation on the resistance;
[0027] The larger the volume of the bubble, the greater the deformation ratio;
[0028] (5) From steps (1), (2), (3), and (4) above, it can be seen that the rising speed of the bubble is proportional to the volume of the bubble.
[0029] Compared with the prior art, the advantages of the present invention are as follows: The present invention can prevent small bubbles from adhering to the inner wall of the through hole, thus effectively avoiding the generation of large bubbles, and further ensuring that both water droplets and air can smoothly pass through the gap between the ball head and the inner wall of the through hole, thereby completely solving the blockage problem. Description of the Drawings
[0030] Figure 1 It is the rear view structure diagram of the present invention;
[0031] Figure 2 It is the left view structure diagram of the present invention;
[0032] Figure 3 It is the sectional structure diagram in the direction A of the present invention. Detailed Embodiment
[0033] Unless otherwise defined, the technical terms or scientific terms used in the present invention shall have the ordinary meanings understood by those of ordinary skill in the field to which the present invention pertains. The "first", "second" and similar terms used in the present invention do not denote any order, quantity or importance, but are only used to distinguish different components. The terms such as "comprising" or "including" mean that the elements or items appearing before this word cover the elements or items listed after this word and their equivalents, without excluding other elements or items. The terms such as "connected" or "coupled" are not limited to physical or mechanical connections, but may include electrical connections, whether direct or indirect. The terms such as "upper", "lower", "left", "right" are only used to indicate relative positional relationships, and when the absolute position of the object being described changes, the relative positional relationship may also change accordingly.
[0034] In order to keep the following description of the embodiments of the present invention clear and concise, the detailed descriptions of known functions and known components are omitted in the present invention.
[0035] Such as Figures 1 to 3As shown in the figure, a faucet includes a housing 4, a rubber gasket 1 hermetically embedded inside the housing 4, and an adjusting knob 2 screwed through one side of the housing 4. A tapered counterbore 11 is formed at the center of the upper end of the rubber gasket 1, and a through hole 12 is formed on the bottom surface of the tapered counterbore 11. A side hole 13 is formed on the inner wall of one side of the through hole 12. The threaded end of the adjusting knob 2 forms a sealing section 21 outward. The end of the sealing section 21 passes through the side hole 13 by interference and vertically extends into the through hole 12. The outer wall of the end of the sealing section 21 is hermetically attached to the inner wall of the through hole 12. A ball head 22 is further formed at the end of the sealing section 21, and the outer wall of the ball head 22 cooperates with the outer wall of the through hole 12.
[0036] A counterbore 41 is formed at the upper end of the housing 4, and a rubber sleeve 3 is hermetically embedded in the counterbore 41.
[0037] A cavity 42 is formed at the center of the bottom surface of the counterbore 41, and the rubber gasket 1 is hermetically embedded in the cavity 42.
[0038] An outlet hole 43 is formed at the center of the bottom surface of the cavity 42, and the upper opening of the outlet hole 43 is communicated with the lower opening of the through hole 12.
[0039] The distance h between the upper side edge of the inner end opening of the side hole 13 and the upper opening of the through hole 12 is 1 mm.
[0040] The included angle b between the inner wall of the tapered counterbore 11 and the inner wall of the through hole 12 is 45 degrees.
[0041] The inner diameter of the through hole 12 is greater than 3 mm.
[0042] Usage method:
[0043] Socket the upper opening of the rubber sleeve 3 on the water outlet pipe. The water in the water outlet pipe enters the through hole 12 through the rubber sleeve 3 and the tapered counterbore 11. Then, rotate the adjusting knob 2 by hand so that the outer wall of the ball head 22 slowly moves away from the inner wall of the through hole 12, thereby creating a gap between the ball head 22 and the inner wall of the through hole 12. As a result, the water enters the outlet hole 43 through the above-mentioned gap and is finally discharged outward through the outlet hole 43.
[0044] A water cut-off elimination algorithm for a faucet includes the following steps:
[0045] (1) The object rises because the buoyant force acting on it is greater than the resistance it encounters during motion (the resistance is greater in more viscous liquids). However, in the case of water, the influence of viscosity can generally be ignored. Therefore, the resistance mainly comes from the adsorption force on the side walls (bubbles in water adhere to the surface of other objects due to surface tension), and the pressure of the liquid at the top (this can cause the bubble to adhere completely to the inner side of the tube at the gap, resulting in the liquid being cut into two segments at the bubble, and at this time, the pressure from the top liquid will decrease or even disappear, thereby reducing or eliminating the buoyant force). The buoyant force causes an object to float when the pressure difference between the upper and lower surfaces of the object in water is greater than its own weight. The weight of the bubble itself is extremely light and can basically be ignored.
[0046] Consider the acceleration generated by (buoyant force - gravity)
[0047] ρ 液 v 排 ρvg - mg = ma
[0048] ρ 液 v 排 ρvg = ρ 气 v 排 (a + g)
[0049] We get: a = (ρ 液 / ρ 气 - 1)g
[0050] This result obviously has nothing to do with the volume, will not affect the acceleration, and naturally will not affect the speed change or the speed.
[0051] (2) Consider the influence of the negative acceleration generated by the resistance of water (temporarily not considering deformation, assuming it is a pure circular bubble);
[0052] The resistance f is proportional to the square of the bubble radius r and the square of the speed v
[0053] That is: the resistance is f 阻 = kr 2 v 2
[0054] kr 2 v 2 = ma = ρ 气 (4π / 3)r 3 a
[0055] a 负 = 3kv² / (4πρₐr)
[0056] It is because the resistance f is proportional to r 2 and the volume is proportional to r 3Is directly proportional. Due to this difference of 1 power, when r is large, the absolute value of this negative acceleration is smaller instead.
[0057] Therefore, the resistance has a smaller obstructive effect on large air bubbles than on small air bubbles.
[0058] Let's consider that if there is no resistance, then the air bubble will undergo uniformly accelerated upward motion with the acceleration a = (ρ 液 / ρ 气 - 1)g in step (1). Since the ratio of ρ 液 / ρ 气 is very large, this acceleration will be very large, and the air bubble will accelerate crazily.
[0059] However, in fact, we have not observed "crazy air bubbles". Actually, the degree of acceleration of the air bubble is very limited.
[0060] This indicates that most of this acceleration a is offset by the negative acceleration a 负 of the water resistance. Therefore, the resistance f must absolutely not be ignored here, and not only cannot be ignored, but it is also a very important factor.
[0061] Therefore, from the conclusion that the resistance f is inversely proportional to r, it can be seen that if the ratio of r of two air bubbles is 1:2, then the ratio of the absolute values of the resistance accelerations is 2:1, and this ratio is quite significant.
[0062] (3) Consider the influence of velocity on the resistance;
[0063] In step (2), we only considered the influence of r on the resistance f. In fact, the influence of v on the resistance f is also very large; the resistance f is directly proportional to v 2 . When v becomes larger and larger, the resistance increases rapidly; thus, when v reaches a certain level, the resistance is equal to the buoyancy in step (1). Then the water bubble reaches the maximum stable velocity, and the water bubble becomes a uniform upward motion (assuming the container is high enough so that the water bubble in the container has the opportunity to reach this maximum stable velocity). Next, let's calculate this maximum value:
[0064] When reaching the maximum stable value,
[0065] The resistance f = (buoyancy - gravity)
[0066] That is, the absolute values of the two accelerations obtained in steps (1) and (2) are equal,
[0067] From (ρ 液 / ρ 气 - 1)g = 3kv 2 / (4πρ 气 r)
[0068] The maximum speed obtained is:
[0069] v = (4π / 3k)(ρ 液 - ρ 气 )gr
[0070] (4) Consider the influence of deformation on resistance;
[0071] Deformation has no influence on buoyancy and gravity. Buoyancy and gravity only depend on volume and have nothing to do with shape. However, the influence of deformation on buoyancy cannot be ignored. If the bubble does not move, its stable state in water should be a standard spherical shape. But once it encounters resistance during movement, it will become a streamline shape to avoid resistance.
[0072] The larger the volume of the bubble, the greater its deformation. However, the deformation ratio of large bubbles and small bubbles is different. The larger the bubble, the greater its deformation ratio.
[0073] If the forces are the same, the deformation ratio of large-volume bubbles is larger (for example: when stepping on a table tennis ball with a diameter of 20 cm and a standard-sized table tennis ball, assuming they are made of the same material, it is easy to know that the smaller one is more difficult to be stepped on and deformed). The reason is that the smaller the radius of curvature, the more stable the structure of this object is in engineering.
[0074] Moreover, for bubbles with different forces, the large bubbles are subjected to greater forces, so the deformation ratio is even larger.
[0075] So the deformation ratio is larger for large bubbles, and naturally, more acceleration generated by the resistance f is avoided.
[0076] By carefully observing the deformation of the bubble's cross-section, it can be found that large bubbles tend to become fat cucumber-shaped. Assuming the radius only changes by 20%, that is, the radius becomes 0.8 times the previous value. Then the resistance f is proportional to r, and naturally it will also become 0.8 times. Moreover, not only is the instantaneous resistance smaller, the instantaneous acceleration increases, but also the final stable maximum speed will increase. 1 / 80% - 1, that is, it increases by 25% (note that here it explains the reason for the larger "deformation ratio" of large bubbles, rather than the reason for larger "deformation").
[0077] (5) According to step (1), we can see that the final stable speed is proportional to the radius r. Bubbles with a larger radius r can reach a higher stable speed. Step (2) tells us that when the speeds are equal, bubbles with a larger radius obtain a greater acceleration. Step (3) tells us that the upper limit of the stable speed that bubbles with a larger radius can reach is greater. Step (4) tells us that the deformation ratio of the bubble is proportional to the volume of the bubble. In summary, the rising speed of the bubble is proportional to the volume of the bubble.
[0078] As can be seen from the above, the key to solving the problem of air bubbles lies in reducing the contact area between the air bubbles and the side wall and increasing the pipe diameter. However, due to the small water outlet gap, the faucet needs to be made small for design considerations. Therefore, the key to the structural design lies in:
[0079] (1) The pipe diameter of the water inlet end of the faucet should be as large as possible;
[0080] (2) By designing the distance h between the upper side edge of the inner end opening of the side hole 13 and the upper end opening of the through hole 12 to be 1 mm and the angle b between the inner wall of the tapered counterbore 11 and the inner wall of the through hole 12 to be 45 degrees, the strength of the seal can be taken into account while making it impossible for small air bubbles to adsorb as much as possible, thereby avoiding the accumulation of large air bubbles.
[0081] (3) According to the experimental data, for air bubbles with a diameter of less than 3 mm, their rise is most affected by the tension. Therefore, the inner diameter of the through hole 12 is designed to be greater than 3 mm to prevent the air bubbles from being adsorbed on the side wall in a blocking manner.
[0082] The present invention can prevent small air bubbles from adsorbing on the inner wall of the through hole 12, thereby effectively avoiding the generation of large air bubbles, and further ensuring that both water droplets and air can smoothly pass through the gap between the ball head 22 and the inner wall of the through hole 12, thus completely solving the blockage problem.
[0083] Finally, it should be noted that the above embodiments are only used to illustrate the technical solutions of the present invention, and are not intended to limit them; although the present invention has been described in detail with reference to the foregoing embodiments, those skilled in the art should understand that they can still modify the technical solutions described in the foregoing embodiments, or perform equivalent replacements for some of the technical features; and these modifications or replacements do not make the essence of the corresponding technical solutions deviate from the spirit and scope of the technical solutions of the embodiments of the present invention.
Claims
1. A faucet, characterized in that, it includes a housing, a rubber gasket hermetically embedded inside the housing, and an adjusting knob screwed through one side of the housing. A tapered counterbore is formed at the center of the upper end of the rubber gasket, and a through hole is formed on the bottom surface of the tapered counterbore; a side hole is formed on the inner wall of one side of the through hole. The threaded end of the adjusting knob forms a sealing section outward. The end of the sealing section passes through the side hole by interference and vertically extends into the through hole. The outer wall of the end of the sealing section is hermetically attached to the inner wall of the through hole. A ball head is further formed at the end of the sealing section, and the outer wall of the ball head cooperates with the outer wall of the through hole; the distance h between the upper side edge of the inner end opening of the side hole and the upper end opening of the through hole is 1 mm; the included angle b between the inner wall of the tapered counterbore and the inner wall of the through hole is 45 degrees.
2. The faucet according to claim 1, characterized in that, a counterbore is formed at the upper end of the housing, and a rubber sleeve is hermetically embedded in the counterbore.
3. The faucet according to claim 2, characterized in that, a cavity is formed at the center of the bottom surface of the counterbore, and the rubber gasket is hermetically embedded in the cavity.
4. The faucet according to claim 3, characterized in that, a water outlet hole is formed at the center of the bottom surface of the cavity, and the upper end opening of the water outlet hole is communicated with the lower end opening of the through hole.
5. The faucet according to claim 1, characterized in that, the inner diameter of the through hole is greater than 3 mm.
Citation Information
Patent Citations
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CN110388477A
Novel water faucet
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CN217815066U