A method for spinning a large-size thin-wall steel cylindrical part

Abstract

A large size thin-walled steel cylindrical part is spun on a wheel, and an inner spinning wheel is used instead of a core mold, so that the inner and outer surfaces of the blank can be thinned at the same time, the single pass thinning rate is large, the spinning pass can be reduced under the same total thinning amount, the processing efficiency is improved, and the quality of the workpiece is significantly improved. The spinning of the diameter 2000mm thin-walled steel cylindrical part is realized without the spinning core mold, the spinning product processing cost is reduced, the installation and disassembly of the spinning core mold are avoided, the labor intensity of the workers is reduced, and the safety of the on-site operation is improved. For a spinning blank with a diameter of 2000mm and a thickness of 30mm, if mold spinning is used, three spinning passes are required, and if wheel spinning is used, two spinning passes are required, the processing cycle is shortened by one-third, the processing efficiency of the product is improved, and efficient spinning is realized.

Description

TECHNICAL FIELD

[0001] The present application relates to the field of spinning forming processing, and particularly relates to a high-efficiency and low-cost spinning processing method for large-size thin-wall steel cylindrical parts with a diameter of 1500mm to 4000mm. BACKGROUND

[0002] Spinning forming technology is an advanced process with little or no cutting, which combines the characteristics of extrusion, drawing, ring rolling, bending and rolling. It has significant advantages in processing thin-walled rotary parts, and is widely used in aerospace product manufacturing, such as aircraft engine, solid rocket engine shell, missile guidance cabin, warhead cabin, etc. Solid rocket engine metal shell is a typical thin-walled rotary part. The spinning technology currently applied in the field of solid rocket engine metal shell manufacturing is traditional die spinning technology, which requires a core die with the same shape and size as the inner shape of the workpiece to ensure the spinning process. This results in the need to produce a spinning core die for each product. The larger the diameter and length of the product, the larger the spinning core die that needs to be produced. Due to the long manufacturing cycle and high cost of spinning core die, and the frequent installation and disassembly during use, the die spinning method has high processing cost and low efficiency. The larger the product size, the more prominent the disadvantages of die spinning. Pair spinning uses one or several spinning wheels to process the inner and outer surfaces of the blank at the same time. Since the spinning wheels are in pairs and symmetrically distributed, it is called "pair spinning". Pair spinning is characterized by using an inner spinning wheel instead of a spinning core die, which can quickly realize flexible processing of different specifications. It has unique technical advantages in processing large-size thin-walled cylindrical parts, and has attracted the attention of major industrial powers in Europe and the United States since its inception. Due to the limited application of pair spinning in high-tech fields such as aerospace, and the great difficulty in developing this technology and device, only the United States and Germany have conducted in-depth research and application, and supplied products to NASA (National Aeronautics and Space Administration) and ESA (European Space Agency). According to the data, the foreign pair spinning device is a traditional passive spinning wheel processing. For a long time, some domestic universities and research institutions have only carried out research on the principle and small-scale test machine of pair spinning, and there is no pair spinning equipment that can be used in engineering applications. For example, Xi'an Jiaotong University proposed a pair spinning process and deformation heat treatment for large corrugated pipes in the invention with the publication number CN104175072 B. This invention uses a two-wheel spinning device to form a large corrugated pipe through one pass, and the core is to change the shape of the initial blank without changing its wall thickness. However, the invention uses a pair of spinning wheels to achieve the thinning of ultra-high strength steel thin-walled cylindrical parts, and the materials and processes of the target products are different. Moreover, according to the information, the device used in this invention does not have the ability to process ultra-high strength steel. Harbin Institute of Technology proposed a pair spinning device for forming large thin-walled cylindrical parts in the invention with the publication number CN106270084 A. The core of this invention is the design of the pair spinning device, and it does not involve the pair spinning process.Xi'an Aerospace Power Machinery Factory in the invention disclosed as CN 103736807A proposes a kind of winding and welding cylindrical piece's counter-roller spinning processing method, the invention relies on ordinary vertical lathe, realizes the counter-roller spinning forming of thin-walled aluminum alloy cylindrical structure product, compared with spinning device, lathe power is smaller, and it is a modified device, so the invention is only limited to the processing of small size, low material strength product.Xi'an Aerospace Power Machinery Co., Ltd. in the invention disclosed as CN 112733250A proposes a kind of determination method for inside and outside spinning wheel thinning of cylindrical piece counter-roller spinning, the invention generally gives the determination method for inside and outside spinning wheel thinning when large size cylindrical piece counter-roller spinning, but in actual processing process, spinning wheel thinning is related to the mechanical properties of processing material, spinning device power, device rigidity and process parameters, and needs to be determined according to specific circumstances, in addition, the influence of metal material type and strength, spinning machine rigidity, spinning wheel number, spinning wheel fillet radius and attack angle, cooling mode and cooling liquid flow factor on inside and outside spinning wheel thinning is unified as an influence factor K3, K3 takes 0.8~1.2, the factors involved in influence factor are more, and the range is larger, so that precise guidance cannot be realized.

[0003] In summary, foreign counter-roller spinning equipment adopts spinning wheel passive processing mode, domestic counter-roller spinning principle and small test machine are limited, and there is a blank state in large size thin-walled cylindrical piece counter-roller spinning actual processing.Aiming at the above problems, Xi'an Aerospace Power Machinery Co., Ltd. jointly with Xi'an Jiaotong University and Xi'an Heavy Machinery Research Institute Co., Ltd. develops the first large size counter-roller spinning engineering prototype relying on the proposed full-electric servo active power spinning process principle, and the invention proposes a large size thin-walled steel cylindrical piece counter-roller spinning processing method relying on the device. SUMMARY

[0004] To overcome the high cost, low efficiency and poor flexibility of the prior art, the present application proposes a large size thin-walled steel cylindrical piece counter-roller efficient spinning processing method.

[0005] The specific process of the present application is as follows:

[0006] Step 1, design and make spinning blank.

[0007] The spinning blank of the thin-walled steel cylindrical piece is divided into spinning-up section and forming section.

[0008] Step 1 includes the design of forming section, the design of spinning-up section, the design of spinning blank and the processing of the spinning blank.

[0009] I. The design process of forming section is:

[0010] The spinning blank forming section is a circular ring with equal wall thickness, and the dimensional accuracy and geometric accuracy requirements are as follows: the wall thickness deviation of the spinning blank forming section is required to be ≤±0.05mm, the outer diameter deviation is ≤±0.1mm, the roundness is ≤0.1mm, and the straightness is ≤0.1mm. The surface roughness is Ra 1.6.

[0011] The length L of the spinning blank forming section is calculated according to the plastic deformation volume invariance principle.

[0012] The wall thickness T of the spinning blank forming section is determined by formula (1).

[0013] (1) ;

[0014] In formula (1), t0 is the wall thickness of the processed product, and φ is the limit thinning rate of the processed blank material.

[0015] The structure of the forming section is determined according to the obtained parameters of the forming section.

[0016] II. Design process of the spinning starting section

[0017] The outer circumferential surface and the inner circumferential surface at the end face of the spinning starting section are both inclined surfaces, forming a double inclined surface, and the end face is the starting end of the spinning blank. The thickness t of the small end of the double inclined surface circular ring is one third of the thickness T of the spinning blank forming section, and the thickness of the large end of the double inclined surface circular ring is the same as the thickness T of the spinning blank forming section. The large end of the double inclined surface circular ring is connected with the forming section of the spinning blank. The angle between the inclined surface of the outer circumferential surface of the spinning starting section and the axial direction of the spinning blank is 20°, and the angle between the inclined surface of the inner circumferential surface of the double inclined surface circular ring and the axial direction of the spinning blank is also 20°. The surface roughness of the spinning starting section is Ra 1.6, and the thickness t of the small end of the spinning starting section is 1 / 3T.

[0018] The structure of the spinning starting section is determined according to the obtained parameters of the spinning starting section.

[0019] III. Design process of the spinning blank

[0020] The obtained forming section and the spinning starting section are combined to obtain the structure of the spinning blank. The perpendicularity of the end faces of the spinning blank is ≤0.1mm.

[0021] Step 2, install the spinning wheel.

[0022] The spinning wheel has three pairs; each pair of spinning wheel is composed of an inner spinning wheel N j and an outer spinning wheel W j , and j is the number of the spinning wheel. J=1,2,3.

[0023] The centers of the fillet radii of each pair of installed spinning wheels are in the same horizontal plane. The runout of the spinning wheel fillet surface is 0.03mm.

[0024] Each said spinning wheel fillet radius R=30mm, forming angle α=25°, exit angle β=30°; the center of each pair of spinning wheel fillets is in the same horizontal plane. The runout of each spinning wheel fillet surface is ≤0.05mm per revolution.

[0025] Step 3, install spinning blank;

[0026] Step 4, first pass spinning:

[0027] Set the reduction of each pair of spinning wheels in each pass Wt respectively Wt jk and Nt jk ; said k is the pass, j is the number of pairs of spinning wheels.

[0028] Set the spindle speed of the first pass N1, the feed speed of the spinning wheel F1.

[0029] According to the determined process parameters, the first pass processing program is compiled, and the first pass spinning is completed.

[0030] When setting the first pass spinning parameters:

[0031] I According to formula (2), the reduction of the three pairs of outer spinning wheels in each pair of spinning wheels in the first pass Wt 11 , Wt 21 and Wt 31 ,

[0032] and (2) are determined.

[0033] The unit in formula (2) is mm, T is the coefficient of T, when the thickness T of the blank forming section is ≥30-36mm, 0.35 is taken; when the thickness of the blank is <30mm, 0.35< ≤0.4.

[0034] II The reduction of each inner spinning wheel in each pair of spinning wheels in the first pass Nt 11 , Nt 21 , Nt 31 ,

[0035] and Nt 11 =Nt 21 =Nt 31 = (3) are determined.

[0036] The unit in formula (3) is mm, T is the coefficient of T, when the thickness of the blank is ≥30-36mm, 0.35; when the blank thickness < 30mm, 0.35 < t < 0.4. ≤0.4.

[0037] III. The first pass spindle speed N1 is determined according to formula (4).

[0038] N1 = 12-15 r / min (4)

[0039] When the reduction of each said outer spinning wheel is ≥6mm, the spindle speed is 12≤N1<13, unit: mm / min; when the reduction of each said outer spinning wheel is <6mm, the spindle speed is 13≤N1≤15, unit: mm / min.

[0040] IV. The first pass spinning wheel feed speed F1 is determined according to formula (5).

[0041] F1 = 15-20 mm / min (5)

[0042] When the reduction of each said outer spinning wheel is ≥6mm, the spinning wheel feed speed is 15≤F1<17, unit: mm / min; when the reduction of each said outer spinning wheel is <6mm, the spinning wheel feed speed is 17≤F1≤20, unit: mm / min.

[0043] Step 5, the second pass spinning test spinning:

[0044] The reduction of each outer spinning wheel and the reduction of the inner spinning wheel in the second pass test spinning of the three pairs of spinning wheels are set as follows:

[0045] According to the determined process parameters, the second pass test spinning processing program is compiled, and the test spinning length is 50mm. The second pass test spinning is completed, and the cylinder after the second pass test spinning is obtained.

[0046] The spindle speed of the second pass test spinning is N 2S , and the spinning wheel feed speed is F 2S .

[0047] The measured wall thickness and diameter of the cylinder after the second pass test spinning are T 2S , and D 2S .

[0048] The said Wt 12S is the reduction of the outer spinning wheel W1 in the second pass test spinning; Wt 22S is the reduction of the outer spinning wheel W2 in the second pass test spinning; and Wt 32S is the reduction of the outer spinning wheel W3 in the second pass test spinning.

[0049] The said Nt12S Nt is the reduction amount of the inner spinning wheel N1 in the first pair of spinning wheels during the second trial spinning; 22S For the inner rotating wheel N in the second pair of rotating wheels 22 The reduction amount in the second spin test; Nt 32S This refers to the amount of pressure applied during the second pass of the inner spinning wheel N3 in the third pair of spinning wheels.

[0050] When determining the parameters for the second spin test

[0051] I. According to formula (6), the reduction amount Wt of each outer spinning wheel in the second trial spinning of the three pairs of spinning wheels is determined. 12S Wt 22S and Wt 32S ,and

[0052] Wt 12S =Wt 22S =Wt 32S (6)

[0053] The unit in formula (6) is mm, where T1 is the wall thickness of the cylinder after the first spinning pass, and t0 is the wall thickness of the processed product. For Wt jkS The coefficient, when the blank thickness is ≥30~36mm, is 1.7 < ≤1.8; when the blank thickness is <30mm, Take 1.5≤ ≤1.7.

[0054] The amount of reduction in the second pass of the spinning test of each outer spinner in each pair of spinnerets is obtained.

[0055] II. According to formula (7), the reduction amount Nt for the second trial spinning of each inner spinning wheel in the three pairs of spinning wheels is determined as follows: 12S 、Nt 22S and Nt 32S ,and

[0056] Nt 12S =Nt 22S =Nt 32S (7)

[0057] The unit in formula (7) is mm, where T1 is the wall thickness of the cylinder after the first spinning pass, and t0 is the wall thickness of the processed product. For Nt 2S1 、Nt 2S2 、Nt 2S3 The coefficient, when the blank thickness is ≥30~36mm, is 1.4 < ≤1.5; when the blank thickness is <30mm, Take 1.2≤ ≤1.4.

[0058] III. Determine the spindle speed N of the second pass trial spinning according to formula (8) 2S

[0059] N 2S =12~15r / min (8)

[0060] In formula (8), when the outer roller reduction is ≥5mm, the spindle speed is 12≤N 2S ≤13r / min; when the outer roller reduction is <5mm, the spindle speed is 13<N 2S ≤15r / min.

[0061] IV. Determine the roller feed speed F of the second pass trial spinning according to formula (9) 2S .

[0062] F 2S =15~20mm / min (9)

[0063] In formula (9), when the outer roller reduction is ≥5mm, the roller feed speed is 15≤F 2S ≤17 mm / min; when the outer roller reduction is <5mm, the roller feed speed is 17<F 2S ≤20 mm / min.

[0064] Step six, the second pass spinning.

[0065] The reductions of the three pairs of rollers in the second pass are respectively Wt 12 , Wt 22 , Wt 32 , Nt 12 , Nt 22 and Nt 32 ; wherein:

[0066] Wt 12 is the second pass reduction of the outer roller W1 in the first pair of rollers, Nt 12 is the second pass reduction of the inner roller N1 in the first pair of rollers; Wt 22 is the second pass reduction of the outer roller W2 in the second pair of rollers, Nt 22 is the second pass reduction of the inner roller N2 in the second pair of rollers; Wt 32 is the second pass reduction of the outer roller W3 in the third pair of rollers, Nt 32 is the second pass reduction of the inner roller N 13 in the third pair of rollers.

[0067] The spindle speed of the second pass is N2, and the roller feed speed is F2.

[0068] According to the determined process parameters, a second pass formal spinning process program is compiled, and the second pass spinning is completed.

[0069] Thus, the paired-wheel spinning of the thin-walled steel cylindrical part is completed.

[0070] When determining the reduction of each pair of spinning wheels in the second pass of formal spinning

[0071] I. According to formula (10), the reduction Wt of each outer spinning wheel in the second pass of formal spinning is determined 12 , Wt 22 , and Wt 32 .

[0072] Wt 12 = Wt 22 = Wt 32 Wt 12S (10)

[0073] The unit in formula (10) is mm, where T 2S is the wall thickness of the cylinder part after the second pass trial spinning, t0 is the wall thickness of the processed product; is the coefficient of outer spinning wheel reduction, when T 2S > t0, 1.4; when the blank thickness T 2S < t0, = 1.2.

[0074] II. According to formula (11), the Nt of each inner spinning wheel in the second pass of formal spinning is determined 12 , Nt 22 , and Nt 32 .

[0075] Nt 12 = Nt 22 = Nt 32 = Nt 12S (11)

[0076] The unit in formula (11) is mm, where T 2S is the wall thickness of the cylinder part after the second pass trial spinning, t0 is the wall thickness of the processed product; is the coefficient of outer spinning wheel reduction, when T 2S > t0, 1.2; when the blank thickness T 2S < t0, = 1.0.

[0077] determining the spindle speed N2 of the second pass of the formal spinning of each pair of spinning wheels and the spinning wheel feed speed F2 of the second pass of the formal spinning

[0078] N2= N 2S (12)

[0079] F2=F 2S ±2mm / min. (13)

[0080] In formula (13), when the diameter of the cylinder part after the second pass of the trial spinning is larger than the product diameter, F2=F 2S +2mm / min; when the diameter of the cylinder part after the second pass of the trial spinning is smaller than the product diameter, F2=F 2S -2mm / min.

[0081] Compared with the prior art, the present application has the beneficial effects of:

[0082] The application replaces the core mold with the inner spinning wheel for wheel spinning, saves the spinning core mold cost, and reduces the processing cost of the spinning product. The mold is an indispensable important deformation tool in spinning forming. Due to the spinning deformation property, the surface of the mold bears a considerable local force, and the action point moves along the feeding direction of the spinning wheel according to the spiral line. At the same time, it also bears the torque and bending moment, and the great friction between the material flow and the mold during spinning deformation, etc. Therefore, the requirements for the mold are that it has sufficient strength, stiffness, hardness and good wear resistance, and the internal type precision and surface quality of the product completely depend on the dimensional accuracy and surface quality of the mold, so the mold also needs high dimensional accuracy and surface roughness. In addition, the mold cannot have defects such as cracks, scratches, scratches and local unevenness, sometimes it also requires low heat sensitivity and small linear expansion coefficient, etc. In summary, as a high-performance and high-precision tooling, the spinning mold has high requirements for materials and processing technology, so the manufacturing cost of the spinning mold is usually expensive. Taking a diameter 2000mm thin-walled steel cylindrical part widely used in the domestic aerospace field as an example, a spinning core mold with a diameter of 2000mm needs to be made for spinning with a mold, and the manufacturing cost of the core mold is usually about 2 million yuan, and the manufacturing cycle is more than 6 months. The spinning forming scheme provided by the above-mentioned application can realize the spinning of a diameter 2000mm thin-walled steel cylindrical part without making a spinning core mold, which greatly reduces the processing cost of the spinning product. Compared with spinning with a mold, the loss in the processing process is low, and then the processing cost of the product is low. Because, on the one hand, the surface of the spinning core mold bears a large alternating load during use, there is fatigue wear, and on the other hand, there is a risk of surface scratching during product loading and unloading, and the spinning core mold will directly affect the quality of the product once damaged, and even cause the product to be scrapped, so when the surface of the spinning core mold is damaged to a certain extent, it cannot be used again, and the core mold needs to be made again, which makes the spinning process with a mold face a high damage cost, and the spinning wheel used for spinning a diameter 2000mm thin-walled steel cylindrical part has a manufacturing cost of about 20,000 yuan, which is only one percent of the manufacturing cost of the spinning core mold, so the spinning with a wheel is more helpful to reduce the processing cost of the product.

[0083] Compared with die spinning, the inside and outside surfaces of the blank can be thinned simultaneously by the counter roller spinning, the single pass thinning rate is larger, the spinning pass can be reduced under the same total thinning amount, the processing efficiency is improved, and the quality of the workpiece is obviously improved. For example, a steel cylindrical part with a diameter of 2000mm and a thickness of 8mm is processed by using a spinning blank with a diameter of 2000mm and a thickness of 30mm. If die spinning is used, three spinning passes are needed to form it. If counter roller spinning is used, it can be formed by two spinning passes, the processing period is shortened by one third, the processing efficiency of the product is improved, and high-efficiency spinning is realized.

[0084] Compared with die spinning, the flexibility of counter roller spinning is good, and different diameter cylinders can be processed only by adjusting the distance between the two pairs of rollers. For die spinning, the size and the quality of the inner surface of the product are all guaranteed by the spinning core mold, so the product size and the spinning core mold size are one-to-one corresponding, and therefore for different size products, the corresponding spinning core mold needs to be made. On the one hand, the spinning core mold needs to be made at a high cost, which makes the product cost high, and on the other hand, the spinning core mold needs to be made for a long period, which cannot meet the rapid manufacturing response of the product.

[0085] Compared with die spinning, the installation and disassembly of the spinning core mold are avoided, the labor intensity of the workers is reduced, the safety of the on-site operation is improved, and the processing efficiency of the product is also improved. BRIEF DESCRIPTION OF DRAWINGS

[0086] Figure 1 is a schematic view of a spinning blank structure

[0087] Figure 2 is a flow chart of the present application. DETAILED DESCRIPTION

[0088] 1. A counter roller spinning processing method for a large-size thin-walled steel cylindrical part, characterized in that the specific process is:

[0089] Step 1, design and make a spinning blank.

[0090] The spinning blank of the thin-walled cylindrical part is divided into a spinning starting section and a forming section.

[0091] I. Design of the forming section

[0092] The spinning blank forming section is a circular ring with an equal wall thickness, and the size accuracy and geometric accuracy requirements are that the wall thickness deviation of the spinning blank forming section is required to be ≤ ±0.05mm, the outer diameter deviation is ≤ ±0.1mm, the roundness is ≤0.1mm, and the straightness is ≤0.1mm. The surface roughness is Ra 1.6.

[0093] The length L of the spinning blank forming section is calculated according to the length of the processed product, the wall thickness of the product, the thickness T of the spinning blank forming section and the designed machining allowance, and is calculated according to the principle of plastic deformation volume invariance, and is obtained by referring to the spinning technology on page 708.

[0094] The wall thickness T of the spinning blank forming section is determined by formula (1).

[0095] (1)

[0096] In formula (1), t0 is the wall thickness of the processed product, and φ is the limit thinning rate of the processed blank material.

[0097] Based on the design requirements of the thin-walled cylindrical product, the wall thickness T of the spinning blank forming section is determined by formula (1).

[0098]

[0099] The thickness T of the spinning blank forming section is 24mm.

[0100] According to the spinning technology, the length L of the spinning blank forming section is calculated according to the principle of plastic deformation volume invariance, L=800mm, and the outer diameter D of the spinning blank forming section is 外 =2018mm.

[0101] The structure of the forming section is determined according to the obtained parameters of the forming section.

[0102] II. Design of the spinning starting section

[0103] The spinning starting section is in the shape of a circular ring, and the outer peripheral surface and the inner peripheral surface at the end face are both inclined surfaces, forming double inclined surfaces. The end face is the starting end of the spinning blank, the thickness t of the small end of the double inclined surface circular ring is one third of the thickness T of the spinning blank forming section, and the thickness of the large end of the double inclined surface circular ring is the same as the thickness T of the spinning blank forming section. The large end of the double inclined surface circular ring is connected with the forming section of the spinning blank. The angle between the inclined surface of the outer peripheral surface of the spinning starting section and the axial direction of the spinning blank is 20°, and the angle between the inclined surface of the inner peripheral surface of the double inclined surface circular ring and the axial direction of the spinning blank is also 20°. The surface roughness of the spinning starting section is Ra 1.6. The thickness t of the small end of the spinning starting section is 1 / 3T=8mm.

[0104] The structure of the spinning starting section is determined according to the obtained parameters of the spinning starting section.

[0105] III. Design of the spinning blank

[0106] The obtained forming section and the spinning starting section are combined to obtain the structure of the spinning blank. The perpendicularity of the end faces of the spinning blank is ≤0.1mm.

[0107] IV. Machining the spinning blank

[0108] The spinning blank is machined according to the design by a machining method.

[0109] Step two, installing the spinning wheels.

[0110] The spinning wheels have multiple pairs; each spinning wheel has a fillet radius R=30mm, a forming angle α=25°, and a withdrawal angle β=30°; the centers of the fillet radii of each pair of spinning wheels are on the same horizontal plane. The runout of the fillet surface of each spinning wheel in one rotation is ≤0.05mm.

[0111] Each pair of spinning wheels consists of an inner spinning wheel N j and an outer spinning wheel W j , where j is the number of the pair of spinning wheels. J=1, 2, 3,…

[0112] W 11 and N 11 in the first pair of spinning wheels, W 12 and N 12 in the second pair of spinning wheels, and W 13 and N 13 in the third pair of spinning wheels, respectively.

[0113] Each spinning wheel has a diameter of 500mm, a spinning wheel thickness of 90mm, a fillet radius R=30mm, a forming angle α=25°, a withdrawal angle β=30°, and the centers of the fillet radii of each pair of spinning wheels after installation are on the same horizontal plane. The runout of the fillet surface of each spinning wheel in one rotation is 0.03mm.

[0114] Step three, installing the spinning blank.

[0115] The spinning blank is hoisted on the spindle disc of the spinning device, and the spinning blank falls into the annular clamping groove on the spindle disc. The top block of the annular clamping groove is adjusted to align the spinning blank, and the round runout of the middle part of the spinning blank in one rotation is ensured to be <0.3mm. After alignment, the top block of the annular clamping groove is tightened.

[0116] In this embodiment, the spinning blank is hoisted on the spindle disc of the spinning device, and after the spinning blank falls into the annular clamping groove on the spindle disc, the top block of the annular clamping groove is adjusted to align the spinning blank. The round runout of the middle part of the spinning blank in one rotation is 0.25mm. The top block of the annular clamping groove is tightened.

[0117] Step four, first-pass spinning.

[0118] Each pair of spinning wheels consists of an outer spinning wheel W j and an inner spinning wheel N jWt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3.

[0119] Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3. jk Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3. jk ; the k is pass, and j is the logarithm of the roller.

[0120] Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3. 11 Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3. 11 Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3.

[0121] Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3. 21 Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3. 21 Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3.

[0122] Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3. 31 Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3. 31 Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3.

[0123] Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3. 12 Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3. 12 Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3.

[0124] Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3. 22 Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3. 22 Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3.

[0125] Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3. 32 Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3. 31 Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3.

[0126] Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3. 13 Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3. 13 Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3.

[0127] Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3. 23 Wt = Wtj, k, j, Wt = Ntj, k, j, j = 1, 2, 3; the first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3. 23Nt is the third pass reduction of the inner spinning wheel N1 in the third pair of spinning wheels;

[0128] Wt is the first pass reduction of the outer spinning wheel W1 in the third pair of spinning wheels when k=3 and j=3. 33 Nt is the third pass reduction of the inner spinning wheel N1 in the third pair of spinning wheels. 33 Nt is the third pass reduction of the inner spinning wheel N1 in the third pair of spinning wheels.

[0129] The spindle speed of the first pass is set as N1, and the feeding speed of the spinning wheel is set as F1.

[0130] I. According to formula (2), the first pass reduction of the three pairs of outer spinning wheels in the spinning wheels is determined as Wt 11 , Wt 21 and Wt 31 , and

[0131] Wt 11 =Wt 21 =Wt 31 (2)

[0132] The unit in formula (2) is mm, is the coefficient of T, when the blank thickness is ≥30-36 mm, 0.35 is taken; when the blank thickness is <30 mm, 0.35 ≤0.4.

[0133] In the embodiment, the spinning blank thickness T=24 mm, 0.4 is taken. The first pass reduction of each outer spinning wheel in the three pairs of spinning wheels is Wt 11 =Wt 21 =Wt 31 =0.4×24 / 2+1.8=6.6 mm.

[0134] II. According to formula (3), the first pass reduction of each inner spinning wheel in the spinning wheels is determined as Nt 11 , Nt 21 , Nt 31 , and

[0135] Nt 11 =Nt 21 =Nt 31 = (3)

[0136] The unit in formula (3) is mm, is the coefficient of T, when the blank thickness is ≥30-36 mm, 0.35 is taken; when the blank thickness is <30 mm, 0.35 ≤0.4.

[0137] In this embodiment, the thickness of the spinning blank T = 24 mm, Take 0.4. Get the reduction Nt of the second pass of each inner spinning roller in the three pairs of spinning rollers 11 =Nt 21 =Nt 31 =0.4×24 / 2+1.2=6.0mm.

[0138] III. Determine the first pass spindle speed N1 according to formula (4).

[0139] N1=12~15r / min. (4)

[0140] When the reduction of each outer spinning roller is ≥6mm, the spindle speed is 12≤N1<13, unit: r / min; when the reduction of each outer spinning roller is <6mm, the spindle speed is 13≤N1≤15, unit: r / min.

[0141] In this embodiment, the spindle speed N1 is taken as 12r / min.

[0142] IV. Determine the spinning roller feed speed F1 of the first pass according to formula (5).

[0143] F1=15~20mm / min. (5)

[0144] When the reduction of each outer spinning roller is ≥6mm, the feed speed of the spinning roller is 15≤F1<17, unit: mm / min; when the reduction of each outer spinning roller is <6mm, the feed speed of the spinning roller is 17≤F1≤20, unit: mm / min.

[0145] In this embodiment, the spinning roller feed speed F1 is taken as 15mm / min.

[0146] V. The process parameters determined according to formula (2), (3), (4) and (5) are used to compile the first pass processing program, and the first pass spinning is completed.

[0147] Step five, trial spinning of the second pass spinning:

[0148] Before the second pass spinning, trial spinning is performed, specifically:

[0149] The first pair of spinning rollers is W1 and N1, the second pair of spinning rollers is W2 and N2, and the third pair of spinning rollers is W3 and N3.

[0150] Set the reduction of each outer spinning roller and the reduction of the inner spinning roller in the second pass trial spinning of the three pairs of spinning rollers:

[0151] Wt 12S is the reduction of the outer spinning roller W1 in the first pair of spinning rollers in the second pass trial spinning; Wt 22SWt is the reduction amount of the outer spinning wheel W2 in the second pair of spinning wheels during the second trial spinning; 32S This refers to the amount of pressure applied during the second pass of the outer spinning wheel W3 in the third pair of spinning wheels.

[0152] Nt 12S Nt is the reduction amount of the inner spinning wheel N1 in the first pair of spinning wheels during the second trial spinning; 22S For the inner rotating wheel N in the second pair of rotating wheels 22 The reduction amount in the second spin test; Nt 32S This refers to the amount of pressure applied during the second pass of the inner spinning wheel N3 in the third pair of spinning wheels.

[0153] The spindle speed for the second test spinning was N. 2S The feed speed of the rotary wheel is F 2S .

[0154] I. According to formula (6), the reduction amount Wt of each outer spinning wheel in the second trial spinning of the three pairs of spinning wheels is determined. 12S Wt 22S and Wt 32S ,and

[0155] Wt 12S =Wt 22S =Wt 32S (6)

[0156] The unit in formula (6) is mm, where T1 is the wall thickness of the cylinder after the first spinning pass, and t0 is the wall thickness of the processed product. For Wt jkS The coefficient, when the blank thickness is ≥30~36mm, is 1.7 < ≤1.8; when the blank thickness is <30mm, Take 1.5≤ ≤1.7.

[0157] The amount of reduction in the second pass of the spinning test of each outer spinner in each pair of spinnerets is obtained.

[0158] In this embodiment, the wall thickness of the cylinder after the first spinning pass is T1=14.4mm, and the product thickness is t0=6mm. As can be seen from the above content of the present invention, in formula (6) If we take 1.5, then we determine the reduction Wt of each outer spinning wheel in the second trial spinning of each pair of spinning wheels. 12S =Wt 22S =Wt 32S =5.7mm.

[0159] II. According to formula (7), the reduction amount Nt for the second trial spinning of each inner spinning wheel in the three pairs of spinning wheels is determined as follows: 12S 、Nt22S and Nt 32S ,and

[0160] Nt 12S =Nt 22S =Nt 32S (7)

[0161] The unit in formula (7) is mm, where T1 is the wall thickness of the cylinder after the first spinning pass, and t0 is the wall thickness of the processed product. For Nt 2S1 、Nt 2S2 、Nt 2S3 The coefficient, when the blank thickness is ≥30~36mm, is 1.4 < ≤1.5; when the blank thickness is <30mm, Take 1.2≤ ≤1.4.

[0162] In this embodiment, the wall thickness of the cylinder after the first spinning pass is T1=14.4mm, and the product thickness is t0=6mm; in formula (7) If we take 1.2, then we determine the reduction amount Nt of the second trial spinning of each inner spinning wheel in the three pairs of spinning wheels. 2S1 =Nt 2S2 =Nt 2S3 =5.4mm.

[0163] III. Determine the spindle speed N for the second trial spinning according to formula (8). 2S .

[0164] N 2S =12~15r / min. (8)

[0165] When the outer swivel wheel reduction is ≥5mm in formula (8), the spindle speed is 12≤N. 2S ≤13 r / min; when the outer rotary wheel pressing amount is <5 mm, the spindle speed is 13 < N. 2S ≤15r / min.

[0166] In this embodiment, the spindle speed N during the second trial spinning is... 2S Set the speed to 13 r / min.

[0167] IV. Determine the spinneret feed speed F for the second trial spinning based on formula (9). 2S .

[0168] F 2S =15~20mm / min. (9)

[0169] In formula (9), when the outer swivel wheel reduction is ≥5mm, the swivel wheel feed speed is 15≤F. 2S≤ 17 mm / min; when the outer roller reduction is < 5 mm, the roller feed speed is 17 < F 2S ≤ 20 mm / min.

[0170] The roller feed speed F of the second pass trial spinning in this embodiment 2S Take 16 r / min.

[0171] V. The process parameters determined according to formulas (6), (7), (8) and (9) are used to compile the second pass trial spinning process program, and the trial spinning length is 50 mm. The second pass trial spinning is completed, and the cylinder after the second pass trial spinning is obtained.

[0172] The wall thickness and diameter of the cylinder after the second pass trial spinning are measured, and let T 2S be the wall thickness of the cylinder part after the second pass trial spinning, D 2S be the diameter of the cylinder part after the second pass trial spinning.

[0173] In this embodiment, the wall thickness and diameter of the cylinder part after the second pass trial spinning are measured, wherein the wall thickness T 2S of the cylinder part after the second pass trial spinning is 6.08-6.23 mm, and the diameter D 2S of the cylinder part after the second pass trial spinning is 2000.95 mm.

[0174] Step six, second pass spinning.

[0175] The first pair of rollers is W1 and N1, the second pair of rollers is W2 and N2, and the third pair of rollers is W3 and N3.

[0176] The reduction amounts of the three pairs of rollers in the second pass are respectively Wt 12 , Wt 22 , Wt 32 , Nt 12 , Nt 22 and Nt 32 ; wherein:

[0177] Wt 12 is the second pass reduction amount of the outer roller W1 in the first pair of rollers, Nt 12 is the second pass reduction amount of the inner roller N1 in the first pair of rollers; Wt 22 is the second pass reduction amount of the outer roller W2 in the second pair of rollers, Nt 22 is the second pass reduction amount of the inner roller N2 in the second pair of rollers; Wt 32 is the second pass reduction amount of the outer roller W3 in the third pair of rollers, Nt 32 is the second pass reduction amount of the inner roller N 13 in the third pair of rollers.

[0178] The spindle speed of the second pass is N2, and the feed speed of the roller is F2.

[0179] I. According to formula (10), the reduction Wt of the outer roller of the three pairs of rollers in the second pass is determined 12 , Wt 22 , and Wt 32 .

[0180] Wt 12 = Wt 22 = Wt 32 Wt 12S (10)

[0181] The unit in formula (10) is mm, wherein T 2S is the wall thickness of the barrel part after the second pass trial spinning, and t0 is the wall thickness of the processed product; is the word number of the reduction of the outer roller, when T 2S > t0, 1.4; when the blank thickness T 2S < t0, = 1.2.

[0182] In this embodiment, the wall thickness T 2S of the barrel part after the second pass trial spinning is 6.08-6.23 mm, which is greater than the wall thickness t0 of the processed product, so that 1.4. According to formula (10), the reduction Wt of the outer roller of the three pairs of rollers in the second pass is determined 12 = Wt 22 = Wt 32 = 5.7+0.105 = 5.805 mm.

[0183] II. According to formula (11), the Nt of the inner roller of the three pairs of rollers in the second pass is determined 12 , Nt 22 , and Nt 32 .

[0184] Nt 12 = Nt 22 = Nt 32 = Nt 12S (11)

[0185] The unit in formula (11) is mm, wherein T 2S is the wall thickness of the barrel part after the second pass trial spinning, and t0 is the wall thickness of the processed product; is the word number of the reduction of the outer roller, when T 2S > t0, 1.2; when the blank thickness T 2S <t0, =1.0.

[0186] In this embodiment, the wall thickness T 2S =6.08~6.23mm, which is greater than the wall thickness t0of the processed product, thus according to the above invention content, the 1.2. Thus according to the formula (11), the reduction Nt 12 =Nt 22 =Nt 32 =5.4+0.105=5.49mm.

[0187] III, according to the formula (12), the spindle speed N2of the second pass is determined.

[0188] N2= N 2S (12)

[0189] In this embodiment, the spindle speed N2of the second pass is N 2S =13r / min.

[0190] IV, according to the formula (13), the roller feed speed F2of the second pass is determined.

[0191] F2=F 2S ±2mm / min. (13)

[0192] In the formula (13), when the diameter of the cylinder body part after the second pass trial spinning is greater than the product diameter, F2=F 2S +2mm / min; when the diameter of the cylinder body part after the second pass trial spinning is smaller than the product diameter, F2=F 2S -2mm / min.

[0193] In this embodiment, the diameter D 2S =2000.95mm, which is greater than the product diameter 2000mm, thus according to the above invention content, the roller feed speed F2of the second pass is determined as F 2S +2mm / min=18r / min

[0194] V, the process parameters determined according to the formula (10), (11), (12) and (13) are used to compile the second pass spinning process program, and the second pass spinning is completed.

[0195] The spun cylinder is removed from the spinning device, and thus the double-wheel spinning of the 2000mm diameter thin-walled steel cylindrical part is completed.

[0196] The measured diameter of the finished cylinder is Φ1999.12-Φ2001.35mm, the wall thickness is 5.95-6.08mm, and the length is 3250mm, all meeting the target requirements.

Claims

1. A method for spinning large-size thin-walled steel cylindrical parts using a roller forming process, characterized in that, The specific process is as follows: Step 1: Design and fabricate the spinning blank; The spinning blank of the thin-walled steel cylindrical part is divided into a spinning start section and a forming section; The design includes the design of the forming section, the design of the spinning section, the design of the spinning blank, and the processing of the spinning blank; In the design of the forming section, the wall thickness T of the spinning blank forming section is determined by formula (1); （1）； In formula (1), t0 is the wall thickness of the processed product, and φ is the limit thinning rate of the blank material; Step 2, install the rotating wheel; There are three pairs of rotating wheels; each pair of rotating wheels consists of an inner rotating wheel N. j And an external rotating wheel W j Composition, where j is the number of logarithms of the wheel; J = 1, 2, 3; After installation, the centers of the fillet radii of each pair of rotating wheels are on the same horizontal plane; the runout of the fillet surface of each rotating wheel is 0.03mm during one revolution. Step 3, install the spinning blank; Step 4, First Spinning: The reduction amount Wt for each pair of spinning wheels in each pass is set as Wt. jk and Nt jk ; k represents the number of passes, and j represents the logarithm of the rotary wheel; When setting the first spinning pass: Ⅰ Determine the reduction amount Wt of the three pairs of pairs of rotating wheels in the first pass according to formula (2). 11 Wt 21 and Wt 31 ,and (2); The unit in formula (2) is mm. Let T be a coefficient, and when the thickness T of the forming section of the blank is ≥ 30~36mm, Take 0.35; when the blank thickness is <30mm, 0.35 < ≤0.4; II. Determine the reduction amount Nt of each inner wheel in the first pass of each pair of rotating wheels using formula (3). 11 、Nt 21 、Nt 31 ,and Nt 11 =Nt 21 =Nt 31 = (3); The unit in formula (3) is mm. The coefficient of T is used when the blank thickness is ≥30~36mm. Take 0.35; when the blank thickness is <30mm, 0.35 < ≤0.4; Ⅲ Determine the spindle speed N1 for the first pass according to formula (4); N1 = 12-15 r / min; (4); When the pressing amount of each of the external rotating wheels is ≥6mm, the spindle speed is 12≤N1<13, unit: r / min; when the pressing amount of each of the external rotating wheels is <6mm, the spindle speed is 13≤N1≤15, unit: r / min; IV. Determine the wheel feed speed F1 for the first pass according to formula (5); F1 = 15~20mm / min (5; Set the spindle speed for the first pass to N1 and the feed rate of the spinning wheel to F1; The first processing procedure is prepared according to the determined process parameters, and the first spinning process is completed. Step 5, second spin test: Set the reduction amount of each outer spinning wheel and the reduction amount of each inner spinning wheel in the second pass of the three pairs of spinning wheels: Based on the determined process parameters, prepare the second trial spinning process program, with a trial spinning length of 50mm; complete the second trial spinning to obtain the cylinder after the second trial spinning. The spindle speed for the second test spinning was N. 2S The feed speed of the rotary wheel is F 2S ; The wall thickness and diameter of the cylinder after the second trial spinning were measured, and T was set as follows. 2S D represents the wall thickness of the cylinder section after the second trial spinning. 2S The diameter of the cylinder section after the second trial spinning; Step 6, second spinning pass; The reduction amounts for the second pass of the three pairs of spinning wheels are W t 12 Wt 22 Wt 32 、Nt 12 、Nt 22 and Nt 32 ;in: W t 12 Nt is the second pass reduction of the outer spinning wheel W1 in the first pair of spinning wheels. 12 Wt is the second pass reduction of the inner spinning wheel N1 in the first pair of spinning wheels; 22 Nt is the second pass reduction of the outer spinning wheel W2 in the second pair of spinning wheels. 22 Wt is the second pass reduction of the inner spinning wheel N2 in the second pair of spinning wheels; 32 Nt is the second pass reduction of the outer spinning wheel W3 in the third pair of spinning wheels. 32 The inner wheel N in the third pair of rotating wheels 13 The second reduction amount; The spindle speed for the second pass is N2, and the feed speed of the spinning wheel is F2. Based on the determined process parameters, prepare the second formal spinning process program and complete the second spinning process; This completes the spinning process of the thin-walled steel cylindrical component.

2. The method for spinning large-size thin-walled steel cylindrical parts as described in claim 1, characterized in that, In step 1: Ⅰ. Determine the structure of the forming segment by using the obtained parameters of the forming segment; The forming section is a circular ring with uniform wall thickness, and its dimensional and positional accuracy requirements are as follows: the wall thickness deviation of the spinning blank forming section is required to be ≤ ±0.05mm, the outer diameter deviation is required to be ≤ ±0.1mm, the roundness is required to be ≤ 0.1mm, and the straightness is required to be ≤ 0. 0.1mm; The surface roughness is Ra1.6; The length L of the spinning blank forming section is calculated based on the principle of constant volume during plastic deformation. II. Design process of the starting section Both the outer and inner circumferential surfaces at the end face of the starting section are inclined planes, forming a double inclined plane. This end face is the starting end of the spinning blank. The thickness t of the small end of the double inclined ring is one-third of the thickness T of the forming section of the spinning blank, and the thickness of the large end of the double inclined ring is the same as the thickness T of the forming section of the spinning blank. The large end of the double inclined ring is related to the forming section of the spinning blank. Segment connection; The angle between the inclined surface of the outer circumference of the starting section and the axis of the spinning blank is 20°, and the angle between the inclined surface of the inner circumference of the double-inclined ring and the axis of the spinning blank is also 20°; the surface roughness of the starting section is Ra 1.6; the thickness of the small end of the starting section is t=1 / 3T; The structure of the starting section is determined by the obtained parameters of the starting section; III. The design process of the spinning blank is The obtained forming section is combined with the spinning starting section to obtain the structure of the spinning blank; the perpendicularity of both end faces of the spinning blank is ≤0.1mm.

3. The method for spinning large-size thin-walled steel cylindrical parts as described in claim 1, characterized in that, Each of the above The radius of the rotary wheel fillet is R=30mm, the forming angle is α=25°, and the exit angle is β=30°; the centers of the fillet radii of each pair of rotary wheels are on the same horizontal plane; the runout of the fillet surface of the rotary wheel after one revolution of each rotary wheel is ≤0.05mm.

4. The method for spinning large-size thin-walled steel cylindrical parts as described in claim 1, characterized in that, When each place When the pressing amount of the outer rotating wheel is ≥6mm, the feed speed of the rotating wheel is 15≤F1<17, unit: mm / min; when the pressing amount of each of the outer rotating wheels is <6mm, the feed speed of the rotating wheel is 17≤F1≤20, unit: mm / min.

5. The method for spinning large-size thin-walled steel cylindrical parts as described in claim 1, characterized in that, Wt 12S Wt is the reduction amount of the outer spinning wheel W1 in the second pass of the first pair of spinning wheels; 22S Wt is the reduction amount of the outer spinning wheel W2 in the second pair of spinning wheels during the second trial spinning; 32S The amount of reduction in the second pass of the outer spinning wheel W3 in the third pair of spinning wheels; Nt 12S Nt is the reduction amount of the inner spinning wheel N1 in the first pair of spinning wheels during the second trial spinning; 22S For the inner rotating wheel N in the second pair of rotating wheels 22 The reduction amount in the second spin test; Nt 32S This refers to the amount of pressure applied during the second pass of the inner spinning wheel N3 in the third pair of spinning wheels.

6. The method for spinning large-size thin-walled steel cylindrical parts as described in claim 1, characterized in that, During the second test spinning... I. According to formula (6), the reduction amount Wt of each outer spinning wheel in the second trial spinning of the three pairs of spinning wheels is determined. 12S Wt 22S and Wt 32S , and Wt 12S = Wt 22S = Wt 32S = (6); The unit in formula (6) is mm, where T1 is the wall thickness of the cylinder after the first spinning pass, and t0 is the wall thickness of the processed product. For Wt jkS The coefficient, when the blank thickness is ≥30~36mm, is 1.7 < ≤1.8; when the blank thickness is <30mm, Take 1.5≤ ≤1.7; The amount of reduction in the second pass of the spinning test of each outer spinner in each pair of spinnerets is obtained; II. According to formula (7), the reduction amount Nt for the second trial spinning of each inner spinning wheel in the three pairs of spinning wheels is determined as follows: 12S 、Nt 22S and Nt 32S , and Nt 12S = Nt 22S = Nt 32S = (7); The unit in formula (7) is mm, where T1 is the wall thickness of the cylinder after the first spinning pass, and t0 is the wall thickness of the processed product. For Nt 2S1 、Nt 2S2 、Nt 2S3 The coefficient, when the blank thickness is ≥30~36mm, is 1.4 < ≤1.5; when the blank thickness is <30mm, Take 1.2≤ ≤1.4; III. Determine the spindle speed N for the second trial spinning according to formula (8). 2S ; N 2S =12~15r / min; (8); When the outer swivel wheel reduction is ≥5mm in formula (8), the spindle speed is 12≤N. 2S ≤13 r / min; when the outer rotary wheel pressing amount is <5 mm, the spindle speed is 13 < N. 2S ≤15r / min; IV. Determine the spinneret feed speed F for the second trial spinning based on formula (9). 2S ; F 2S =15~20mm / min; （9）； In formula (9), when the outer swivel wheel reduction is ≥5mm, the swivel wheel feed speed is 15≤F. 2S ≤17 mm / min; when the outer rotary wheel pressing amount is <5 mm, the rotary wheel feed speed 17 < F 2S ≤20 mm / min.

7. The method for spinning large-size thin-walled steel cylindrical parts as described in claim 1, characterized in that, Step 6 When determining the reduction amount of each pair of spinning wheels in the second pass of the formal spinning process I. Determine the reduction Wt of the second formal spinning of each of the three pairs of spinning wheels according to formula (10). 12 Wt 22 and Wt 32 ; W t 12 =Wt 22 =Wt 32 = Wt 12S (10); The unit in formula (10) is mm, where T 2S t0 represents the wall thickness of the cylinder section after the second trial spinning, and t0 represents the wall thickness of the processed product. It is the number of characters for the amount of pressure applied by the outer rotating wheel, when T 2S When >t0, 1.4; When the blank thickness T 2S When <t0, =1.2; II. Determine Nt for the second formal spinning of each inner spinning wheel in the three pairs of spinning wheels according to formula (11). 12 、Nt 22 and Nt 32 ; Nt 12 =Nt 22 =Nt 32 = Nt 12S + (11); The unit in formula (11) is mm, where T 2S t0 represents the wall thickness of the cylinder section after the second trial spinning, and t0 represents the wall thickness of the processed product. It is the number of characters for the amount of pressure applied by the outer rotating wheel, when T 2S When >t0, 1.2; When the blank thickness T 2S When <t0, =1.

0.

8. The method for spinning large-size thin-walled steel cylindrical parts as described in claim 1, characterized in that, Step 6 When determining the spindle speed N2 for the second pass of formal spinning and the spindle feed speed F2 for the second pass of formal spinning for each pair of spinning wheels... N2= N 2S (12); F2=F 2S ±2mm / min; (13); In formula (13), when the diameter of the cylinder section after the second trial spinning is larger than the product diameter, F2 = F 2S +2mm / min; When the diameter of the cylinder section is smaller than the product diameter after the second trial spinning, F2 = F 2S -2mm / min.

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