Pipeline arrangement method using maximum horizontal laying distance calculation formula of air-conditioning water system

Abstract

The invention discloses a pipeline arrangement method using a maximum horizontal laying distance calculation formula of an air-conditioning water system, and relates to the field of air-conditioning water systems, and the method comprises the steps: 1, proposing a maximum laying distance calculation formula for ensuring that the unbalance rate is less than 15%, and judging the maximum laying distance of a horizontal pipeline; 2, classifying the buildings, and providing a most suitable pipeline arrangement mode according to different types; and step 3, according to the flow chart, selecting a better pipeline arrangement mode by using a maximum horizontal laying distance calculation formula of the air-conditioning water system. The method solves the problems that only a formula for judging the unbalance rate exists at present, the length of a pipeline which can enable the unbalance rate of each loop to be larger than 15% cannot be determined, and a designer cannot quantitatively judge the form of the air conditioner water system at the beginning of design. The problems that a different-stroke system is not easy to balance and a same-stroke pipe of a same-stroke system wastes pipes are solved.

Description

Technical Field

[0001] The invention relates to the field of air conditioning water systems, and in particular to a pipeline arrangement method using a maximum horizontal laying distance calculation formula for an air conditioning water system. Background Art

[0002] The air conditioning water system is a very important component of the building air conditioning system. It directly determines the cooling and heating capacity of the air conditioning system, so full attention should be paid to the design of the air conditioning water system. Whether the design of the air conditioning water system is reasonable depends on whether each branch is balanced. When the imbalance rate is greater than 15%, consider using the same program system to offset the resistance difference between each loop so that the flow of each loop is consistent with the design value. At present, there is only a formula for determining the imbalance rate. This formula can determine the imbalance rate of the existing system, but it cannot determine how long the pipe will make the imbalance rate of each loop greater than 15%. Designers cannot quantitatively determine the form of the air conditioning water system when starting the design. Summary of the invention

[0003] The purpose of the present invention is to provide a pipeline layout method using a maximum horizontal laying distance calculation formula for an air conditioning water system to solve the following technical problems:

[0004] 1. Currently, there is only a formula for determining the imbalance rate, but it is impossible to determine how long the pipe will make the imbalance rate of each loop greater than 15%. Designers cannot quantitatively determine the form of the air conditioning water system when they start designing; 2. Systems with different flow rates are not easy to balance, and systems with the same flow rate and pipes with the same flow rate waste pipe materials; 3. Unreasonable layout of horizontal pipelines causes large resistance along the way and tight ceiling space; 4. There are many types of buildings, and different types are suitable for different water pipe layout methods.

[0005] To achieve the above object, the present invention adopts the following technical solution:

[0006] The pipeline layout method using the maximum horizontal laying distance calculation formula of the air conditioning water system is as follows:

[0007] Step 1: Propose a formula for calculating the maximum laying distance to ensure that the imbalance rate is less than 15%, and determine the maximum laying distance of the horizontal pipeline;

[0008] After the air conditioning system is determined, its cold and heat sources and terminal resistance are fixed values. The pipeline specific friction resistance is a parameter to be determined before hydraulic calculation, so the riser and horizontal pipeline length are the main variables of hydraulic calculation; assuming that the pipeline specific friction resistance is R Pa / m, the cold and heat sources and terminal resistance are Z Pa, the horizontal pipeline length is X m, and the vertical pipeline length is Ym, then the total length of the most unfavorable loop pipeline is L = 2 (X + Y) m, the local resistance is 50% of the resistance along the way, and the pipeline length of the nearest loop is L' = 2 (X' + Y') m, then the following formula is obtained:

[0009] (1.5RL+Z-(1.5RL^'+Z)) / (1.5RL+Z)≤0.15

[0010] Simplified, 0.85RL≤0.1Z+RL'

[0011] Substitute L=2(X+Y) into 1.7R(X+Y)≤0.1Z+2R(X^'+Y'). The nearest loop X' is close to 0m. Between the same layers, Y=Y', X≤(0.1Z+0.3RY) / 1.7R

[0012] The above formula gives the maximum horizontal laying distance of the pipeline that meets the unbalance rate of 15%. It can be seen that the larger the cold and hot sources and the terminal resistance Z, the longer the maximum horizontal laying distance X of the pipeline. This is because the larger the cold source and the terminal resistance, the smaller the proportion of resistance along the way, the smaller the influence of pipeline length on the unbalance rate, and the longer the pipeline can be.

[0013] It can also be concluded that the longer the riser Y is, the longer the maximum horizontal laying distance X of the pipeline is, that is, the higher the number of layers, the longer the maximum horizontal laying distance X of the pipeline is. This is because the longer the riser Y is, the greater the proportion of the riser resistance will be, and the proportion of the horizontal pipeline resistance will decrease, so the horizontal pipeline can be longer;

[0014] In addition, it is not difficult to conclude that the smaller the specific friction resistance R is, the longer the maximum horizontal laying distance X of the pipeline is. This is because the smaller the specific friction resistance R is, the smaller the proportion of resistance along the way is, and the pipeline can be longer;

[0015] Step 2: Classify the buildings and propose the most suitable pipeline layout according to different types;

[0016] Step 3. According to the flow chart, use the maximum horizontal laying distance calculation formula of the air conditioning water system to select the best pipe layout method.

[0017] In step 2, the specific classification of buildings and the specific pipeline layout methods for different types of buildings;

[0018] Buildings are divided into two categories, and the best same-program and different-program pipeline layout methods are given for each type of building;

[0019] 1. The first type: buildings with corridors;

[0020] 1.1, a building with a cloister;

[0021] Method 1: In a building with a corridor, the water supply riser (2) and the return riser (3) are connected from the pipe well (1) and arranged in opposite directions. After being laid along the corridor, an air release valve (4) is connected at the end to discharge the air in the pipe.

[0022] In this way, the supply and return pipes are laid in opposite directions, which not only realizes the same length of the supply and return pipes, but also saves the same length of pipes, thus saving pipe materials;

[0023] Method 2, in a building with a corridor, a water supply riser (2) and a return riser (3) are arranged in different directions after being connected from the pipe well (1), and after being laid half a circle along the corridor, an air release valve (4) is connected at the farthest end from the pipe well to discharge the air in the pipe;

[0024] In this way, two pipelines are laid at different distances to each take charge of 1 / 2 of the load of the layer, effectively reducing the pipe diameter and saving pipe materials;

[0025] The above two laying methods are also applicable to circular, elliptical and other buildings with corridors; the pipe well can be located at any part of the corridor;

[0026] 1.2, a building with two cloisters;

[0027] Buildings with two corridors are often found in buildings with a core tube. For vertical connection, a pipe shaft is usually set inside the core tube.

[0028] Method 3, in a building with two corridors, the same arrangement is adopted; the water supply riser (2) and the water return riser (3) are connected from the pipe well (1) and arranged in opposite directions, and after leaving the core tube, the water supply pipe (21) and the water return pipe (31) are respectively divided into two branches in opposite directions, and each branch is connected to an air release valve (4) after going around the corridor to discharge the air in the pipe;

[0029] In this arrangement, except for the pipes in the core tube that are responsible for the load of the entire floor, the pipes outside the core tube are all responsible for 1 / 2 of the load of this floor. Not only does it not need to set up the same-course pipe, but it can also reduce the diameter of the main pipe compared to the same-course type that directly goes around the building.

[0030] Method 4, in a building with two corridors, the water supply riser (2) and the return riser (3) are connected from the pipe well (1) and then go out in different directions, go around the two corridors half a circle, and then connect to the air release valve (4) to discharge the air in the pipe;

[0031] The four loops at the end of the arrangement are responsible for 1 / 4 of the building load, which effectively reduces the pipe diameter and saves pipe materials;

[0032] Method 5, when the pipe well is not set in the core tube, the water supply riser (2) and the return riser (3) are connected from the pipe well (1) and then go out in different directions, go around the layer once, and then connect the air release valve (4) at the end to discharge the air in the pipe;

[0033] The middle corridor is connected to pipes at both ends of the corridor, and a vent valve (4) is connected in the center of the corridor to release air. Because the main pipeline is already of the same type at this time, the length of the pipeline directly connected to each device at the end loop is basically the same;

[0034] Method 6, when the pipe well is not set in the core tube, the water supply riser (2) and the return riser (3) are arranged in a different way, and then they are connected from the pipe well (1) and go out in different directions, respectively, go around two annular corridors for half a circle, and then are connected to the air release valve (4) to discharge the air in the pipe;

[0035] The middle corridor is connected to pipes at both ends of the corridor, and a deflation valve (4) is connected in the center of the corridor for deflation. Such an arrangement can effectively reduce the pipe diameter and save pipe materials.

[0036] 1.3, the situation with two or more corridors is basically the same as the pipeline layout method of two corridors;

[0037] 2. The second type: buildings without corridors;

[0038] In buildings without corridors, for the same-course system, it is advisable to set up multiple pipe wells to avoid setting up the same-course pipes;

[0039] Method 7, in a building without corridors, in a same-course system, if the single-story load and the building length are small, a water supply pipe well (11) and a return pipe well (12) can be respectively set at both ends of the corridor, and after the water supply riser (2) is connected, a final air-relief valve (4) is arranged in the direction of the return pipe well (12) to discharge air, and after the return riser (3) is connected, a final air-relief valve (4) is arranged in the direction of the water supply pipe well (11) to discharge air. Such an arrangement not only realizes the same course of the supply and return pipes, but also saves the same-course pipes, but the main pipe is responsible for the load of the entire building;

[0040] Method 8, in a building without corridors, with the same formula system, if the single-layer load and the building length are large, in order to further save pipe materials, three pipe wells can be set, the water supply pipe well (11) is set at the center of the corridor, and the two return pipe wells (12) are respectively set at the two ends of the corridor. The horizontal pipe is connected from the water supply riser (2) and laid to the two return risers at the two ends of the corridor, and finally connected to the vent valve at the two ends of the corridor to discharge air. The horizontal pipe is connected from the return riser (3) and laid to the water supply riser (2) in the center of the corridor, and connected to the vent valve in the center of the corridor to discharge air;

[0041] In this way, the horizontal main pipe is only responsible for 1 / 2 of the load on this floor, and the horizontal stroke of the supply and return pipes can be reduced by half;

[0042] Method 9: In a building without corridors, the system is arranged in an asymmetric manner. The pipe well (1) is arranged in the center of the corridor. The horizontal pipe is connected from the water supply riser (2) and the return riser (3) and then laid to both ends of the corridor. In this way, the horizontal pipe is only responsible for 1 / 2 of the load of this floor, and the pipe diameter can be reduced.

[0043] The pipeline arrangement method for buildings without corridors is not only applicable to the rectangular buildings shown in the figure, but also to semicircular and arc-shaped buildings.

[0044] In step three, the specific method of using the flowchart;

[0045] a, start;

[0046] b. Calculate the maximum horizontal laying distance X;

[0047] c. Determine the building type;

[0048] There are buildings with corridors and buildings without corridors.

[0049] d, if it is a building with a cloister;

[0050] Then determine whether the number of ring corridors is greater than 1;

[0051] If it is greater than 1, then continue to determine whether the well is in the center; if it is in the center, then continue to determine whether X≤L / 2, if so, use the same program system, method 3, otherwise use the different program system, method 4; if it is not in the center, then continue to determine whether X≤L / 2, if so, use the same program system, method 5, otherwise use the different program system, method 6;

[0052] If it is less than 1, then continue to determine whether X≤L / 2; if it is, use the same program system, method 1; if not, use the different program system, method 2;

[0053] e, if it is a building without corridors;

[0054] Continue to determine whether X≤L / 2. If yes, use the same program system, preferably method 8, and select method 9 under conditional restrictions; otherwise, use the different program system, method 9;

[0055] f, end.

[0056] Compared with the prior art, the present invention has the following characteristics and beneficial effects:

[0057] 1. The present invention proposes a formula for calculating the maximum laying distance to ensure that the imbalance rate is less than 15%, which can determine the maximum laying distance of horizontal pipelines and then select a better pipeline layout method according to the building type.

[0058] 2. The different-course system proposed by the present invention has a short laying distance and a small pipe diameter, which saves more pipe materials, and the same-course system does not require the same-course pipes.

[0059] 3. The invention rationally lays out the horizontal air conditioning water pipes, which can reduce the system resistance, save pump work, reduce the pipe diameter and eliminate the need for the same-length pipes, which can not only save pipe materials but also increase the ceiling height.

[0060] 4. The present invention classifies buildings and proposes the most suitable pipeline layout according to different types.

[0061] 5. The present invention can use the formula to select a better arrangement according to the flow chart. BRIEF DESCRIPTION OF THE DRAWINGS

[0062] Figure 1 is a pipeline arrangement diagram of method 1 of the present invention;

[0063] Figure 2 is a pipeline arrangement diagram of method 2 of the present invention;

[0064] Figure 3 is a pipeline arrangement diagram of method 3 of the present invention;

[0065] Figure 4 is a pipeline arrangement diagram of method 4 of the present invention;

[0066] Figure 5 is a pipeline arrangement diagram of method 5 of the present invention;

[0067] Figure 6 is a pipeline arrangement diagram of method 6 of the present invention;

[0068] Figure 7 is a pipeline arrangement diagram of the method 7 of the present invention;

[0069] Figure 8 is a pipeline arrangement diagram of the method 8 of the present invention;

[0070] Fig. 9 is a pipeline arrangement diagram of the method 9 of the present invention;

[0071] Fig.10 It is a flow chart for selecting the pipeline arrangement mode of the present invention;

[0072] Reference numerals: 1—pipe well, 2—water supply riser, 3—water return riser, 4—air release valve,

[0073] 11-water supply pipe well, 12-water return pipe well,

[0074] 21—Water supply pipe,

[0075] 31—Return pipe. DETAILED DESCRIPTION

[0076] The following will be combined with the drawings in the embodiments of the present invention to clearly and completely describe the technical solutions in the embodiments of the present invention. Obviously, the described embodiments are only part of the embodiments of the present invention, not all of the embodiments. Based on the embodiments of the present invention, all other embodiments obtained by ordinary technicians in this field without creative work are within the scope of protection of the present invention.

[0077] See also Figure 1-10 As shown, the present invention uses a pipeline layout method using a maximum horizontal laying distance calculation formula for an air conditioning water system.

[0078] After the air conditioning system is determined, its cold and heat sources and terminal resistance are fixed values. The pipeline specific friction resistance is a parameter to be determined before hydraulic calculation, so the riser and horizontal pipeline length are the main variables of hydraulic calculation; assuming that the pipeline specific friction resistance is R Pa / m, the cold and heat sources and terminal resistance are Z Pa, the horizontal pipeline length is X m, and the vertical pipeline length is Ym, then the total length of the most unfavorable loop pipeline is L = 2 (X + Y) m, the local resistance is 50% of the resistance along the way, and the pipeline length of the nearest loop is L' = 2 (X' + Y') m, then the following formula is obtained:

[0079] (1.5RL+Z-(1.5RL^'+Z)) / (1.5RL+Z)≤0.15

[0080] Simplified, 0.85RL≤0.1Z+RL'

[0081] Substitute L=2(X+Y) into 1.7R(X+Y)≤0.1Z+2R(X^'+Y'). The nearest loop X' is close to 0m. Between the same layers, Y=Y', X≤(0.1Z+0.3RY) / 1.7R

[0082] The above formula gives the maximum horizontal laying distance of the pipeline that meets the unbalance rate of 15%. It can be seen that the larger the cold and hot sources and the terminal resistance Z, the longer the maximum horizontal laying distance X of the pipeline. This is because the larger the cold source and the terminal resistance, the smaller the proportion of resistance along the way, the smaller the influence of pipeline length on the unbalance rate, and the longer the pipeline can be.

[0083] It can also be concluded that the longer the riser Y is, the longer the maximum horizontal laying distance X of the pipeline is, that is, the higher the number of layers, the longer the maximum horizontal laying distance X of the pipeline is. This is because the longer the riser Y is, the greater the proportion of the riser resistance will be, while the proportion of the horizontal pipeline resistance will decrease, so the horizontal pipeline can be longer.

[0084] In addition, it is not difficult to conclude that the smaller the specific friction resistance R is, the longer the maximum horizontal laying distance X of the pipeline is. This is because the smaller the specific friction resistance R is, the smaller the proportion of resistance along the way is, and the pipeline can be longer.

[0085] After the maximum horizontal laying length of the pipeline is obtained through this formula, the present invention also proposes several methods for laying pipelines in different buildings to ensure water balance and save the most pipe materials.

[0086] The present invention divides buildings into two categories, and provides better same-program and different-program pipeline layout methods for each type of building.

[0087] 1. The first type is buildings with corridors.

[0088] 1.1, a building with a cloister.

[0089] Method 1: In a building with a corridor, the same layout is used, such as Figure 1As shown, the water supply riser 2 and the return riser 3 are connected from the pipe well 1 and arranged in opposite directions, and after being laid along the ring corridor for a circle, the air release valve 4 is connected at the end to discharge the air in the pipeline;

[0090] In this way, the supply and return water pipes are laid in opposite directions, which not only realizes the same length of the supply and return water pipes but also eliminates the need for pipes in the same length, thus saving pipe materials.

[0091] Method 2, in a building with a corridor, the layout is different, such as Figure 2 As shown, the water supply riser 2 and the return riser 3 are connected from the pipe well 1 and are respectively connected in different directions. After being laid along the annular corridor for half a circle, an air release valve 4 is connected at the farthest end from the pipe well to discharge the air in the pipe.

[0092] In this way, two pipelines are laid at different distances to each be responsible for 1 / 2 of the load of this layer, effectively reducing the pipe diameter and saving pipe materials.

[0093] The above two laying methods are also applicable to circular, elliptical and other buildings with corridors; the pipe shaft can be located at any part of the corridor.

[0094] 1.2, a building with two corridors.

[0095] Buildings with two corridors are often seen in buildings with a core tube. In order to connect the upper and lower parts, a pipe shaft is usually set inside the core tube.

[0096] Method 3, in a building with two corridors, the same arrangement method is used, such as Figure 3 As shown, the water supply riser 2 and the return riser 3 are connected from the pipe shaft 1 and arranged in opposite directions. After leaving the core tube range, the water supply pipe 21 and the return pipe 31 are respectively divided into two branches in opposite directions. Each branch goes around the annular corridor and is connected to the air release valve 4 to discharge the air in the pipeline.

[0097] With this arrangement, except for the pipes inside the core tube that are responsible for the load of the entire floor, the pipes outside the core tube are all responsible for 1 / 2 of the load of this floor. Not only is there no need to set up same-course pipes, the diameter of the main pipe can also be reduced compared to the same-course type that directly goes around the building.

[0098] Method 4: Different layout methods in a building with two corridors, such as Figure 4 As shown, the water supply riser 2 and the return riser 3 are connected from the pipe well 1 and go out in different directions respectively, go around two circular corridors for half a circle and then are connected to the air release valve 4 to discharge the air in the pipeline.

[0099] The four loops at the end are arranged in this way to each be responsible for 1 / 4 of the building load, effectively reducing the pipe diameter and saving pipe materials.

[0100] Method 5: When the pipe well is not set in the core tube, the same program layout method is used, such as Figure 5As shown, the water supply riser 2 and the return riser 3 are connected from the pipe well 1 and go out in different directions respectively, go around the layer once and then connect to the air release valve 4 at the end to discharge the air in the pipe;

[0101] The middle corridor is connected to the two ends of the corridor respectively, and the air release valve 4 is connected to the center of the corridor for air release. Because the main pipeline is already of the same program at this time, the length of the pipeline directly connected to each equipment at the end loop is basically the same.

[0102] Method 6: When the pipe well is not set in the core tube, the different program layout method is used, such as Figure 6 As shown, the water supply riser 2 and the return riser 3 are connected from the pipe well 1 and go out in different directions, respectively, go around two ring corridors for half a circle, and then are connected to the air release valve 4 to discharge the air in the pipeline;

[0103] The middle corridor is connected to pipes at both ends of the corridor, and an air release valve 4 is connected in the center of the corridor to release air. Such an arrangement can effectively reduce the pipe diameter and save pipe materials.

[0104] 1.3. The situation with two or more ring corridors is basically the same as the pipeline layout method of the two ring corridors.

[0105] 2. The second type is buildings without corridors.

[0106] In the same-course system of buildings without corridors, it is advisable to set up multiple pipe shafts to avoid setting up the same-course pipes.

[0107] Method 7: If the single-story load and building length are small, water supply pipe wells 11 and return pipe wells 12 can be set at both ends of the corridor. Figure 7 As shown, after the water supply riser 2 is connected, a final air valve 4 is arranged in the direction of the return pipe well 12 to exhaust the air. After the return water riser 3 is connected, a final air valve 4 is arranged in the direction of the water supply pipe well 11 to exhaust the air. Such an arrangement not only realizes the same course of the supply and return pipes but also eliminates the same course pipes. However, the main pipe is responsible for the load of the entire building.

[0108] Method 8: If the single-story load and building length are large, three pipe wells can be set up to further save pipe materials, such as Figure 8 As shown, the water supply riser 11 is arranged at the center of the corridor, and the two return water risers 12 and 13 are respectively arranged at the two ends of the corridor. The horizontal pipe is connected from the water supply riser 11 and laid to the two return water risers at the two ends of the corridor, and finally connected to the bleed valves at the two ends of the corridor to discharge the air. The horizontal pipe is connected from the return water risers 12 and 13 and laid to the water supply riser 11 in the center of the corridor, and connected to the bleed valve in the center of the corridor to discharge the air.

[0109] The horizontal main pipe arranged in this way is only responsible for 1 / 2 of the load on this floor, and the horizontal stroke of the supply and return pipes can be reduced by half.

[0110] Method 9: In a building without corridors, the different program system layout, such as Fig. 9As shown, the pipe shaft 1 is arranged in the center of the corridor, and the horizontal pipes are connected from the water supply riser 2 and the return riser 3 and laid to the two ends of the corridor respectively. In this way, the horizontal pipes are only responsible for 1 / 2 of the load of this layer, and the pipe diameter can be reduced.

[0111] The pipeline arrangement method for buildings without corridors is not only applicable to the rectangular buildings shown in the figure, but also to semicircular and arc-shaped buildings.

[0112] In order to better use the above formula to find the best horizontal pipeline layout, this patent draws a flow chart for using the formula to select the best horizontal pipeline layout, see Fig.10 This flowchart can be used to quantitatively select the optimal horizontal pipeline layout suitable for the building based on the results calculated by the formula and the building characteristics.

[0113] In step three, the specific method of using the flowchart;

[0114] a, start;

[0115] b. Calculate the maximum horizontal laying distance X;

[0116] c. Determine the building type;

[0117] There are buildings with corridors and buildings without corridors.

[0118] d, if it is a building with a cloister;

[0119] Then determine whether the number of ring corridors is greater than 1;

[0120] If it is greater than 1, then continue to determine whether the well is in the center; if it is in the center, then continue to determine whether X≤L / 2, if so, use the same program system, method 3, otherwise use the different program system, method 4; if it is not in the center, then continue to determine whether X≤L / 2, if so, use the same program system, method 5, otherwise use the different program system, method 6;

[0121] If it is less than 1, then continue to determine whether X≤L / 2; if it is, use the same program system, method 1; if not, use the different program system, method 2;

[0122] e, if it is a building without corridors;

[0123] Continue to determine whether X≤L / 2. If yes, use the same program system, preferably method 8, and select method 9 under conditional restrictions; otherwise, use the different program system, method 9;

[0124] f, end.

[0125] 1. This patent relates to a formula that can calculate the maximum horizontal laying distance of air conditioning water pipes and a better horizontal pipe layout method, and provides a flow chart for selecting a better water pipe layout method using the formula. According to the formula, the maximum laying distance that ensures the imbalance rate is less than 15% can be calculated, and the most suitable horizontal pipe layout method for the building can be quantitatively obtained based on the calculation results and information such as the building perimeter and type.

[0126] 2. The formula for calculating the maximum horizontal laying distance of air conditioning water pipes and the preferred horizontal pipe layout method according to claim 1 are characterized in that:

[0127] 1) A formula for calculating the maximum laying distance to ensure that the imbalance rate is less than 15% is proposed, which can determine the maximum laying distance of horizontal pipelines and then select the best pipeline layout method according to the building type;

[0128] 2) The different-course system proposed in this patent has a short laying distance and a small pipe diameter, which saves more pipe materials, and the same-course system does not require the same-course pipe;

[0129] 3) Reasonable laying of horizontal air conditioning water pipes can reduce system resistance, save pump work, reduce pipe diameter and eliminate the need for same-length pipes, which can not only save pipe materials but also increase the height of the ceiling;

[0130] 4) Classify buildings and propose the most suitable pipeline layout according to different types;

[0131] 5) The formula can be used to select the best layout according to the flow chart.

[0132] Currently, there is only a formula for determining the imbalance rate, but it is impossible to determine how long the pipeline will make the imbalance rate of each loop greater than 15%, and there are various layout methods for different building types. The present invention proposes a formula for calculating the maximum horizontal laying distance of the pipeline and a better horizontal pipeline layout method, which can bring the following beneficial effects:

[0133] The present invention proposes a formula for calculating the maximum horizontal laying distance of the pipeline that meets the imbalance rate of 15%; the length of the pipeline will affect the resistance of the system, the position of the pipe well will affect the load borne by the horizontal pipeline and thus affect the size of the pipeline, and different building types have their own preferred pipeline layout methods. This patent comprehensively considers multiple factors to propose the most reasonable horizontal layout method for air-conditioning water pipelines, striving to achieve the shortest horizontal layout length and the smallest pipe diameter to save pipe materials.

[0134] The invention can quickly calculate the maximum horizontal laying distance of the pipeline, and select the most reasonable horizontal pipeline arrangement mode according to the three-dimensional size and shape of the building.

[0135] The present invention not only makes the selection of air conditioning water layout form quantifiable, but also proposes a better horizontal pipeline layout method for different buildings. A reasonable pipeline layout method can not only achieve hydraulic balance and reduce resistance along the pipeline, but also save pipe materials and optimize ceiling space, and has good application prospects.

[0136] It will be apparent to those skilled in the art that the invention is not limited to the details of the exemplary embodiments described above and that the invention can be implemented in other specific forms without departing from the spirit or essential features of the invention. Therefore, the embodiments should be considered exemplary and non-limiting in all respects, and the scope of the invention is defined by the appended claims rather than the foregoing description, and it is intended that all variations falling within the meaning and scope of the equivalent elements of the claims be included in the invention. Any reference numeral in a claim should not be considered as limiting the claim to which it relates.

[0137] In addition, it should be understood that although the present specification is described according to implementation modes, not every implementation mode contains only one independent technical solution. This description of the specification is only for the sake of clarity. Those skilled in the art should regard the specification as a whole. The technical solutions in each embodiment may also be appropriately combined to form other implementation modes that can be understood by those skilled in the art.

Claims

1. A pipeline layout method using a formula for calculating the maximum horizontal laying distance of an air conditioning water system, characterized in that: The steps are: Step 1: Propose a formula to calculate the maximum laying distance to ensure that the imbalance rate is less than 15%, and determine the maximum laying distance of the horizontal pipeline; After the air conditioning system is determined, its cold and heat sources and terminal resistance are fixed values. The pipeline specific friction resistance is a parameter to be determined before hydraulic calculation, so the riser and horizontal pipeline length are the main variables of hydraulic calculation; assuming that the pipeline specific friction resistance is R Pa / m, the cold and heat source and terminal resistance is Z Pa, the horizontal pipeline length is X m, and the vertical pipeline length is Y m, then the total length of the most unfavorable loop pipeline is L=2(X+Y) m, the local resistance is 50% of the resistance along the way, and the pipeline length of the nearest loop is L'=2(X'+Y') m, then the following formula is obtained: (1.5RL+Z-(1.5RL^'+Z)) / (1.5RL+Z)≤0.15 Simplified, 0.85RL≤0.1Z+RL' Substitute L=2(X+Y) into 1.7R(X+Y)≤0.1Z+2R(X^'+Y') The nearest loop X' is close to 0m, Y=Y' between the same layers, X≤(0.1Z+0.3RY) / 1.7R The above formula gives the maximum horizontal laying distance of the pipeline that meets the unbalance rate of 15%. It can be seen that the larger the cold and hot sources and the terminal resistance Z, the longer the maximum horizontal laying distance X of the pipeline. This is because the larger the cold source and the terminal resistance, the smaller the proportion of resistance along the way, the smaller the influence of pipeline length on the unbalance rate, and the longer the pipeline can be. It can also be concluded that the longer the riser Y is, the longer the maximum horizontal laying distance X of the pipeline is, that is, the higher the number of layers, the longer the maximum horizontal laying distance X of the pipeline is. This is because the longer the riser Y is, the greater the proportion of the riser resistance will be, and the proportion of the horizontal pipeline resistance will decrease, so the horizontal pipeline can be longer; In addition, it is not difficult to conclude that the smaller the specific friction resistance R is, the longer the maximum horizontal laying distance X of the pipeline is. This is because the smaller the specific friction resistance R is, the smaller the proportion of resistance along the way is, and the pipeline can be longer; Step 2: Classify the buildings and propose the most suitable pipeline layout according to different types; Step 3. According to the flow chart, use the maximum horizontal laying distance calculation formula of the air conditioning water system to select the best pipe layout method.

2. The pipeline layout method using the maximum horizontal laying distance calculation formula of the air conditioning water system according to claim 1 is characterized in that: In step 2, the specific classification of buildings and the specific pipeline layout methods for different types of buildings; Buildings are divided into two categories, and the best same-program and different-program pipeline layout methods are given for each type of building; 1. The first category: buildings with corridors; 1.1, a building with a cloister; Method 1: In a building with a corridor, the water supply riser (2) and the return riser (3) are connected from the pipe well (1) and arranged in opposite directions. After being laid along the corridor, a vent valve (4) is connected at the end to discharge the air in the pipe. In this way, the supply and return pipes are laid in opposite directions, which not only realizes the same length of the supply and return pipes, but also saves the same length of pipes, thus saving pipe materials; Method 2, in a building with a corridor, a water supply riser (2) and a return riser (3) are arranged in different directions after being connected from the pipe well (1), and after being laid half a circle along the corridor, an air release valve (4) is connected at the farthest end from the pipe well to discharge the air in the pipe; In this way, two pipelines are laid at different distances to each take charge of 1 / 2 of the load of the layer, effectively reducing the pipe diameter and saving pipe materials; The above two laying methods are also applicable to circular, elliptical and other buildings with corridors; the pipe well can be located at any part of the corridor; 1.2, a building with two cloisters; Buildings with two corridors are often found in buildings with a core tube. For vertical connection, a pipe shaft is usually set inside the core tube. Method 3, in a building with two corridors, the same arrangement is adopted; the water supply riser (2) and the water return riser (3) are connected from the pipe well (1) and arranged in opposite directions, and after leaving the core tube, the water supply pipe (21) and the water return pipe (31) are respectively divided into two branches in opposite directions, each of which is connected to an air release valve (4) after going around the corridor to discharge the air in the pipe; In this arrangement, except for the pipes in the core tube that are responsible for the load of the entire floor, the pipes outside the core tube are all responsible for 1 / 2 of the load of this floor. Not only does it not need to set up the same-course pipe, but it can also reduce the diameter of the main pipe compared to the same-course type that directly goes around the building. Method 4, in a building with two corridors, the water supply riser (2) and the return riser (3) are connected from the pipe well (1) and then go out in different directions, go around the two corridors half a circle, and then connect to the air release valve (4) to discharge the air in the pipe; The four loops at the end of the arrangement are responsible for 1 / 4 of the building load, which effectively reduces the pipe diameter and saves pipe materials; Method 5, when the pipe well is not set in the core tube, the water supply riser (2) and the return riser (3) are connected from the pipe well (1) and then go out in different directions, go around the layer once, and then connect the air release valve (4) at the end to discharge the air in the pipe; The middle corridor is connected to pipes at both ends of the corridor, and a vent valve (4) is connected in the center of the corridor to release air. Because the main pipeline is already of the same type at this time, the length of the pipeline directly connected to each device at the end loop is basically the same; Method 6, when the pipe well is not set in the core tube, the water supply riser (2) and the return riser (3) are arranged in a different way, and then they are connected from the pipe well (1) and go out in different directions, respectively, go around two ring corridors for half a circle, and then are connected to the air release valve (4) to discharge the air in the pipe; The middle corridor is connected to pipes at both ends of the corridor, and a deflation valve (4) is connected in the center of the corridor to deflate the air. This arrangement can effectively reduce the pipe diameter and save pipe materials. 1.3, the situation with two or more corridors is basically the same as the pipeline layout method of two corridors; 2. The second type: buildings without corridors; In buildings without corridors, for the same-course system, it is advisable to set up multiple pipe wells to avoid setting up the same-course pipes; Method 7, in a building without a corridor, in a same-course system, if the single-story load and the building length are small, a water supply pipe well (11) and a water return pipe well (12) can be respectively set at both ends of the corridor, and after the water supply riser (2) is connected, a final air connection and release valve (4) is arranged in the direction of the water return pipe well (12) to discharge air, and after the water return riser (3) is connected, a final air connection and release valve (4) is arranged in the direction of the water supply pipe well (11) to discharge air. Such an arrangement not only realizes the same course of the water supply and return pipes, but also saves the same course pipe, but the main pipe is responsible for the load of the entire building; Method 8, in a building without corridors, with the same formula system, if the single-story load and the building length are large, in order to further save pipe materials, three pipe wells can be set, the water supply pipe well (11) is set at the center of the corridor, and the two return pipe wells (12) are respectively set at the two ends of the corridor. The horizontal pipe is connected from the water supply riser (2) and laid to the two return risers at the two ends of the corridor, and finally connected to the bleed valve at the two ends of the corridor to discharge air. The horizontal pipe is connected from the return riser (3) and laid to the water supply riser (2) in the center of the corridor, and connected to the bleed valve in the center of the corridor to discharge air. In this way, the horizontal main pipe is only responsible for 1 / 2 of the load on this floor, and the horizontal stroke of the supply and return pipes can be reduced by half; Method 9: In a building without corridors, the system is arranged in an asymmetric manner. The pipe well (1) is arranged in the center of the corridor. The horizontal pipe is connected from the water supply riser (2) and the return riser (3) and then laid to both ends of the corridor. In this way, the horizontal pipe is only responsible for 1 / 2 of the load of this floor, and the pipe diameter can be reduced. The pipeline arrangement method for buildings without corridors is not only applicable to the rectangular buildings shown in the figure, but also to semicircular and arc-shaped buildings.

3. The pipeline layout method using the maximum horizontal laying distance calculation formula of the air conditioning water system according to claim 1 is characterized in that: In step three, the specific method of using the flowchart; a, start; b. Calculate the maximum horizontal laying distance X; c. Determine the building type; There are buildings with corridors and buildings without corridors. d, if it is a building with a cloister; Then determine whether the number of ring corridors is greater than 1; If it is greater than 1, then continue to determine whether the well is in the center; if it is in the center, then continue to determine whether X≤L / 2, if so, use the same program system, method 3, otherwise use the different program system, method 4; if it is not in the center, then continue to determine whether X≤L / 2, if so, use the same program system, method 5, otherwise use the different program system, method 6; If it is less than 1, then continue to determine whether X≤L / 2; if it is, use the same program system, method 1; if not, use the different program system, method 2; e, if it is a building without corridors; Continue to determine whether X≤L / 2. If yes, use the same program system, preferably method 8, and select method 9 under conditional restrictions; otherwise, use the different program system, method 9; f, end.

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