Curve braking test pavement paving method

Abstract

The invention discloses a curve braking test pavement paving method, which adopts face brick paving, and finally accurately calculates the length and width of each brick by defining the width of a pavement, the length of a center line, the radius of the center line, the theoretical size of the face bricks and a paving scheme, so that the whole pavement keeps consistent adhesion coefficients.

Description

Technical Field

[0001] The invention belongs to the technical field of road construction, and in particular relates to a method for paving a curved braking test road surface in an automobile testing field. Background Art

[0002] Curve brake roads are an indispensable part of road design. Curve brake roads are set to meet the braking needs of vehicles during driving. Their purpose is to ensure sufficient braking distance for vehicles when driving on curves and avoid traffic accidents.

[0003] In the early stage, a curve test road should be designed to conduct a curve braking test. How to extend the service life of the curve braking test road surface without affecting the test results of the curve braking road is one of the technical problems that need to be solved urgently; at the same time, how to meet the design of the road adhesion coefficient is the top priority. The traditional curve braking test is to conduct a water-sprinkling curve braking test in a dynamic square. This method has an inaccurate adhesion coefficient and insufficient trajectory accuracy for controlling the turning radius. Summary of the invention

[0004] To solve the above problems, the present invention provides a method for laying a curved braking test pavement. The method is a solution for laying tiles, and by designing the size of the tiles according to the curvature of the road, the adhesion coefficient of the entire road surface is kept consistent, and the design accuracy is improved.

[0005] The technical solution of the present invention is: a method for paving a curved braking test road surface, which is paved with paving bricks, with the bricks arranged in rows along the road width and in rows along the road length, and half bricks are staggered between each two adjacent rows of bricks;

[0006] Definition: road width B, curve centerline length L 中 , centerline radius R 中 The theoretical size of a whole brick is: length S, width S; the theoretical size of a half brick is: length S, width 0.5S. The width of the brick is along the width of the road, and the length of the brick is along the length of the road. The relationship between S and B is: B = N * 0.5S, N is a non-zero natural number. A row of all whole bricks is an odd row, and a row with half bricks on the roadside is an even row.

[0007] Then we have: in the road width direction,

[0008] 1) In odd-numbered rows, the radius of the arc corresponding to the position of each brick from the inner line of the road to the outer line is: R 奇1 =R 中 -B / 2+S

[0009] R 奇2 =R 中 -B / 2+S+S

[0010] …

[0011] R 奇N =R 中 -B / 2+N 奇 *S

[0012] The total number of bricks in this row is N 奇 =B / S;

[0013] 2) In even-numbered rows, the radius of the arc from the inner line of the road to the outer line of each brick is: R 偶1 =R 中 -B / 2+0.5S

[0014] R 偶2 =R 中 -B / 2+0.5S+S

[0015] …

[0016] R 偶N =R 中 -B / 2+0.5S+(N 偶 -2)S+0.5S

[0017] The total number of bricks in this row is N 偶 =N 奇 +1, two of which are 0.5S wide;

[0018] Then, in the direction of the road length, using the arc length calculation formula: L = n*π*R / 180°,

[0019] 1) In odd-numbered rows, the arc length from the inner line of the road to the outer line of each brick is: L 奇1 =n 平均* π*R 奇1 * / 180°

[0020] …

[0021] L 奇N =n 平均* π*R 奇N * / 180°

[0022] 2) In even-numbered rows, the arc length from the inner line of the road to the outer line of each brick is:

[0023] L 偶1 =n 平均* π*R 偶1 * / 180°

[0024] …

[0025] L 偶N =n 平均* π*R 偶N * / 180°

[0026] n平均 Represents the average central angle of each brick: n 平均 =n / m 块 ;

[0027] n=(L 中 *180) / (π*R 中 ), m 块 =L 中 / L z , L z =S;

[0028] So we have:

[0029] 1) In odd-numbered rows, the length and width of each brick are taken as the corresponding arc length;

[0030] 2) In the even-numbered rows, the length of the two bricks on the roadside is taken as the corresponding arc length, and the width is taken as half the arc length. The length and width of the remaining bricks are taken as the corresponding arc length.

[0031] Further: define the inner radius R 内 , outer radius R 外 ,

[0032] Then we have: R 内 =R 中 -0.5B=R 外 -B;

[0033] R 外 =R 中 +0.5B=R 内 +B;

[0034] In the calculation, R 中 , R 内 , R 外 Calculations are based on any parameter.

[0035] The present invention can accurately calculate the length and width of each tile according to the road width, road length and road radius, and then lay them according to the rules, and finally obtain a road surface with a high-precision adhesion coefficient and ensure the consistency of the adhesion coefficient. The adhesion coefficient of the road surface laid by this method can reach ≤0.5, which can meet the winter test in the north. BRIEF DESCRIPTION OF THE DRAWINGS

[0036] Figure 1 It is a schematic diagram of laying two rows of tiles under the method of the present invention. DETAILED DESCRIPTION

[0037] The present invention is described in detail below in conjunction with the embodiments. Those skilled in the art should know that the following embodiments are not the only limitations on the technical solutions of the present invention, and any equivalent changes or modifications made within the spirit of the technical solutions of the present invention should be deemed to fall within the protection scope of the present invention.

[0038] The invention provides a method for laying a curved braking test pavement, which refers to a method for laying tiles on a pavement, and is used to control the consistency of the pavement adhesion coefficient.

[0039] like Figure 1 As shown, according to the principles of road paving and simplified process, the tiles are laid in rows along the width of the road and in rows along the length of the road, and the adjacent rows of tiles are laid with a staggered row principle, generally half a brick staggered.

[0040] Assume the road width is B, the centerline length of the curve is L 中 , centerline radius R 中 , inner radius R 内 , outer radius R 外 , then: R 内 =R 中 -0.5B=R 外 -B, R 外 =R 中 +0.5B=R 内 +B,R 中 =R 外 -0.5B=R 内 +0.5B, so R is used in the calculation 中 , R 内 , R 外 Either parameter can be used as the basis.

[0041] Because it is paved with bricks, bricks are used to design the arc shape of the curve. Each brick has the characteristics of curvature, arc radius and arc length. If two of the three are known, the third parameter can be calculated using the arc length formula.

[0042] (1) Brick arc radius design

[0043] Due to the principle of staggered laying, the present invention adopts two specifications of brick widths: one is width S, and the other is width 0.5S. During laying, the brick length refers to the definition along the length direction of the curve, and the brick width refers to the definition along the width direction of the curve.

[0044] Therefore, the relationship between S and B is: B=N*0.5S, N is a non-zero natural number. The physical meaning is that the bricks laid along the road width are either all whole bricks with a width of S, or half bricks with a width of 0.5S on both sides (half bricks will inevitably appear on the edges of a row if a row is laid in an offset manner).

[0045] For the convenience of explanation, one row can be defined as the odd row and the other as the even row. It is assumed that the odd row contains all whole bricks with a width of S, and the even row contains two half bricks with a width of 0.5S.

[0046] Then: In the direction of road width, the arc radius of each brick can be expressed by the brick width.

[0047] In odd rows, the number of tiles is N. 奇 = B / S, the arc radius corresponding to each brick from the inner line of the road to the outer line can be expressed by R 中 , R 内 , R 外 Any parameter is calculated as a base number, assuming that R 中 The calculation is as follows:

[0048] R 奇1 =R 中 -B / 2+S (represents the arc radius corresponding to the innermost brick in the odd-numbered row, and so on)

[0049] R 奇2 =R 中 -B / 2+S+S

[0050] …

[0051] R 奇N =R 中 -B / 2+N 奇 *S

[0052] In even rows, the number of tiles is N. 偶 =N 奇 +1, because there are two bricks with a width of 0.5S. Similarly, the arc radius of each brick from the inner line of the road to the outer line is R 中 , R 内 , R 外 Any parameter calculation can be used, assuming that R 中 The calculation is as follows:

[0053] R 偶1 =R 中 -B / 2+0.5S

[0054] R 偶2 =R 中 -B / 2+0.5S+S

[0055] …

[0056] R 偶N =R 中 -B / 2+0.5S+(N 偶 -2)S+0.5S

[0057] Therefore, the number of bricks in each row and the radius of the joints are determined above.

[0058] (2) Arc length design of bricks

[0059] According to the arc length calculation formula: L = n*π*R / 180°, n is the center angle of the arc, R is the radius of the circle corresponding to the arc, then: the center angle of the curve calculated based on the center line is: n = (L 中 *180) / (π*R 中 );

[0060] Again, the number of bricks arranged along the center line along the length of the road can be estimated as: m 块 =L 中 / L z , L z The nominal length of the brick is S. However, because the brick is laid in an arc, the actual length of each brick will be cut and slightly different.

[0061] The average central angle of each brick is: n 平均 =n / m 块 .

[0062] Then: In the length direction of the road, according to the central angle and radius of each brick, the arc length of each brick can be calculated, which is approximately the length of the brick.

[0063] Using the arc length calculation formula: L = n*π*R / 180°, we have:

[0064] L 奇1 =n 平均* π*R 奇1 * / 180° (represents the arc length corresponding to the innermost brick in the odd-numbered row, and so on)

[0065] …

[0066] L 奇N =n 平均* π*R 奇N * / 180°

[0067] L 偶1 =n 平均* π*R 偶1 * / 180°

[0068] …

[0069] L 偶N =n 平均* π*R 偶N * / 180°

[0070] The above is the calculation for the length of each brick in two adjacent rows. The width is equal to or half of the length. Later, the bricks are laid in a cyclic order of odd and even rows in the length direction of the road.

[0071] Therefore, the length and width of each brick on the entire road are calculated based on the arc length and arc radius. This design borrows the road parameters (width, length, radius) and the calculation is very accurate. Each brick is cut according to the calculated size, and there will be no mistakes if the bricks are taken and laid according to the corresponding specifications.

[0072] The following is a specific construction example:

[0073] 1) Take the curve width as 4.5m and the centerline length as L 中 =100m, centerline radius R 中 =150m, then the inner radius R 内 =147.75m, outer radius R 外 =152.25m;

[0074] 2) Use natural polished granite as the paving bricks, with a theoretical design size of 500mm×500mm. In actual paving, a paving gap of 2mm-3mm is reserved, and a staggered half-brick paving scheme is adopted between two rows;

[0075] 3) Theoretically, the number of granite blocks arranged along the center line should be: m 块 = Centerline length L 中 / granite length = 100 / 0.5 = 200 pieces;

[0076] 4) According to the arc length calculation formula: L = α * R = n * π * R / 180 °, so: n = (L * 180) / (π * R), n is the central angle corresponding to the arc length, R is the radius of the circle corresponding to the arc length;

[0077] Calculate the center angle according to the midline: n = (L 中 *180) / (π*R 中 )=(100*180) / (π*150)=38.19718699°;

[0078] Then in the length direction of the road, the central angle of each granite is: n 平均 =n / m 块 =38.19718669 / 200=0.190985935°;

[0079] 5) According to the road width, the number of odd-numbered rows of granite is N. 奇 =4.5 / 0.5=9 (pieces), the arc radius of each brick from the inside to the outside of the road is:

[0080] R 奇1 =R中 -0.5-0.5-0.5-0.25=148.25m

[0081] R 奇2 =148.25+0.5=148.75m

[0082] R 奇3 =148.75+0.5=149.25m

[0083] R 奇4 =149.25+0.5=149.75m

[0084] R 奇5 =149.75+0.5=150.25m

[0085] R 奇6 =150.25+0.5=150.75m

[0086] R 奇7 =150.75+0.5=151.25m

[0087] R 奇8 =151.25+0.5=151.75m

[0088] R 奇9 =151.75+0.5=152.25m

[0089] 6) According to the road width, the number of even-numbered rows of granite is N. 偶 =N 奇 +1=10 (bricks), the arc radius of each brick from the inside to the outside of the road is:

[0090] R 偶1 =147.75+0.25=148.00m

[0091] R 偶2 =148.00+0.5=148.50m

[0092] R 偶3 =148.50+0.5=149.00m

[0093] R 偶4 =149.00+0.5=149.50m

[0094] R 偶5 =149.50+0.5=150.00m

[0095] R 偶6 =150.00+0.5=150.50m

[0096] R 偶7=150.50+0.5=151.00m

[0097] R 偶8 =151.00+0.5=151.50m

[0098] R 偶9 =151.50+0.5=152..00m

[0099] R 偶10 =152.00+0.25=152.25m

[0100] Using the arc length calculation formula: L = n*π*R / 180°, we have:

[0101] 7) Calculate the arc length of each granite block corresponding to the odd-numbered row according to the route length:

[0102] L 奇1 =0.190985935*π*148.25 / 180°=0.4942m

[0103] L 奇2 =0.190985935*π*148.75 / 180°=0.4958m

[0104] L 奇3 =0.190985935*π*149.25 / 180°=0.4975m

[0105] L 奇4 =0.190985935*π*149.75 / 180°=0.4992m

[0106] L 奇5 =0.190985935*π*150.25 / 180°=0.5008m

[0107] L 奇6 =0.190985935*π*150.75 / 180°=0.5025m

[0108] L 奇7 =0.190985935*π*151.25 / 180°=0.5042m

[0109] L 奇8 =0.190985935*π*151.75 / 180°=0.5058m

[0110] L 奇9 =0.190985935*π*152.25 / 180°=0.5075m

[0111] 8) Calculate the arc length of each granite block corresponding to the even-numbered row according to the route length: L 偶1 =0.190985935*π*148.00 / 180°=0.4933m

[0112] L 偶2 =0.190985935*π*148.50 / 180°=0.4950m

[0113] L 偶3 =0.190985935*π*149.00 / 180°=0.4967m

[0114] L 偶4 =0.190985935*π*149.50 / 180°=0.4983m

[0115] L 偶5 =0.190985935*π*150.00 / 180°=0.5000m

[0116] L 偶6 =0.190985935*π*150.50 / 180°=0.5017m

[0117] L 偶7 =0.190985935*π*151.00 / 180°=0.5033m

[0118] L 偶8 =0.190985935*π*151.50 / 180°=0.5050m

[0119] L 偶9 =0.190985935*π*152.00 / 180°=0.5067m

[0120] L 偶10 =0.190985935*π*152.25 / 180°=0.5075m

[0121] Odd and even rows natural polished granite size chart

[0122]

[0123] The road surface paved by this method has an adhesion coefficient of ≤0.5, which can meet the winter test requirements in the north.

[0124] The above description is only a specific embodiment of the present application, so that those skilled in the art can understand or implement the present application. However, various equivalent modifications and changes to these embodiments will be obvious to those skilled in the art, and the present application will not be limited to these embodiments without departing from the spirit or scope of the present application, but will comply with the scope consistent with the claims of the present application.

Claims

1. A method for laying a curved braking test road surface, using paving bricks for laying, taking the bricks as rows along the road width direction and laying them in rows along the road length direction, and adopting half brick staggered laying between each adjacent row of bricks, characterized in that: Definition: road width B, curve centerline length L 中 , centerline radius R 中 The theoretical size of a whole brick is: length S, width S; the theoretical size of a half brick is: length S, width 0.5S. The width of the brick is along the width of the road, and the length of the brick is along the length of the road. The relationship between S and B is: B = N * 0.5S, N is a non-zero natural number. A row of all whole bricks is an odd row, and a row of half bricks on the roadside is an even row. Then we have: in the road width direction, 1) In odd-numbered rows, the radius of the arc corresponding to the position of each brick from the inner line of the road to the outer line is: R 奇1 =R 中 -B / 2+S R 奇2 =R 中 -B / 2+S+S … R 奇N =R 中 -B / 2+N 奇 *S The total number of bricks in this row is N 奇 =B / S; 2) In even-numbered rows, the radius of the arc from the inner line of the road to the outer line of each brick is: R 偶1 =R 中 -B / 2+0.5S R 偶2 =R 中 -B / 2+0.5S+S … R 偶N =R 中 -B / 2+0.5S+(N 偶 -2)S+0.5S The total number of bricks in this row is N 偶 =N 奇 +1, two of which are 0.5S wide; Then, in the direction of the road length, using the arc length calculation formula: L = n*π*R / 180°, 1) In odd-numbered rows, the arc length corresponding to the position of each brick from the inner line of the road to the outer line is: L 奇1 =n 平均* p*R 奇1 * / 180° … L 奇N =n 平均* p*R 奇N * / 180° 2) In even-numbered rows, the arc length from the inner line of the road to the outer line of each brick is: L 偶1 =n 平均* p*R 偶1 * / 180° … L 偶N =n 平均* p*R 偶N * / 180° n 平均 Represents the average central angle of each brick: n 平均 =n / m 块 ; n=(L 中 *180) / (π*R 中 ),m 块 =L 中 / L z ,L z =S; So we have: 1) In odd-numbered rows, the length and width of each brick are taken as the corresponding arc length; 2) In the even-numbered rows, the length of the two bricks on the roadside is taken as the corresponding arc length, and the width is taken as half the arc length. The length and width of the remaining bricks are taken as the corresponding arc length.

2. The method for laying a curved braking test pavement according to claim 1, characterized in that: Define the inner radius R 内 , outer radius R 外 , Then we have: R 内 =R 中 -0.5B=R 外 -B; R 外 =R 中 +0.5B=R 内 +B; In the calculation, R 中 , R 内 , R 外 Calculations are based on any parameter.

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