BIM-based arrangement method of tie bars for double-layer steel bar meshes
By calculating the mesh intersection points in the double-layer reinforced mesh on the BIM platform and accurately positioning the tension, the problem of difficulty in tensioning layout in complex and special-shaped building forms is solved, and positioning accuracy and working efficiency are improved.
Patent Information
- Application Number
- CN202510214138.X
- Authority / Receiving Office
- CN · China
- Patent Type
- Patents(China)
- Current Assignee / Owner
- Filing Date
- 2025-02-26
- Publication Date
- 2025-06-10
- Estimated Expiration
- 2045-02-26
AI Technical Summary
In the prior art, when designing concrete components in complex and special-shaped buildings, it is difficult to accurately calculate and arrange tension ribs, resulting in difficult to ensure structural safety and stability.
The BIM-based double-layer reinforcement mesh tensioning arrangement method is adopted. By obtaining the BIM three-dimensional model of the component, the grid intersection points in the double-layer reinforcement mesh are calculated, and the tensioning ribs are positioned and arranged to ensure the precise position of the tensioning ribs.
It improves the accuracy and applicability of tensioning rib positioning in complex special-shaped components, solves the problem of difficulty in tensioning rib positioning when two steel bars do not intersect at the grid, reduces artificial processing after drawing, and improves work efficiency.
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Figure CN119720361B_ABST
Abstract
Description
Technical Field
[0001] The present invention belongs to the technical field of three-dimensional reinforcement design and BIM (Building Information Modeling) application, and particularly relates to a method for arranging stirrups of a double-layer steel bar mesh based on BIM. Background Art
[0002] With the continuous development of engineering design technology, BIM forward design has become an important trend in the industry. It not only includes the creation of three-dimensional models of engineering components, but also covers key links such as structural analysis and reinforcement design.
[0003] In terms of reinforcement design, accurately arranging stirrups can not only ensure the safety and stability of the structure, but also bring many advantages. First of all, it can enhance the intuitive display of the three-dimensional model, improve the drawing quality, and reduce later adjustments. Secondly, accurately arranging stirrups can significantly improve the design efficiency and reduce the probability of human errors and rework.
[0004] In the face of increasingly mature three-dimensional modeling technology, there are still certain limitations in the existing technology for stirrup design. This is because the current design of stirrups on most BIM design platforms is based on standard building forms, and it is difficult to achieve the desired effect for complex and irregular building forms. Summary of the Invention
[0005] The purpose of the present invention is to provide a method for arranging stirrups of a double-layer steel bar mesh based on BIM, which solves the problem of difficult calculation of stirrup positions for concrete components with a double-layer steel bar mesh reinforcement form.
[0006] The technical solution adopted by the present invention is: a method for arranging stirrups of a double-layer steel bar mesh based on BIM, including the following steps:
[0007] Step 1: Obtain the BIM three-dimensional model of the component;
[0008] Step 2: Arrange a double-layer steel bar mesh on the reinforcement surface of the model obtained in Step 1;
[0009] Step 3: Calculate the grid intersection points in the double-layer steel bar mesh obtained in Step 2, and position and arrange stirrups based on the calculated grid intersection points.
[0010] The characteristics of the present invention also lie in that,
[0011] In Step 1, an OpenCASCADE based on an open-source modeling engine is selected to build a BIM platform, and a concrete component model is newly created or imported.
[0012] Step 2 specifically includes the following steps:
[0013] Step 2.1: Select the model surface to be reinforced with the steel bar mesh as the reinforcement surface;
[0014] Step 2.2: Offset the reinforcement surface to obtain the surface where the steel bars are located;
[0015] Step 2.3: Construct a cutting plane;
[0016] Step 2.4: Calculate the intersection lines between the surface where the steel bars are located and all the cutting planes to obtain the three-dimensional steel bar positioning lines, i.e., the steel bar lines, and form a layer of steel bar mesh by combining the steel bar groups in two directions of a single layer;
[0017] Step 2.5: Repeat Steps 2.1 to 2.4 to obtain another layer of steel bar mesh and complete the layout of the double-layer steel bar mesh.
[0018] The offset distance in Step 2.2 is calculated by the following formula:
[0019]
[0020] In the formula: is the distance from the outer surface of the steel bar to the reinforcement surface; is the diameter of the steel bar.
[0021] Step 2.3 specifically includes the following steps:
[0022] Step 2.3.1: Select the continuous edge of the model as the guiding line;
[0023] Step 2.3.2: Set the array parameters;
[0024] Step 2.3.3: Combine the array parameters and sequentially arrange distribution points along the guiding line;
[0025] Step 2.3.4: At each distribution point, create a cutting plane passing through the distribution point with the tangent vector of the guiding line as the normal vector;
[0026] Step 2.3.5: Repeat Step 2.3.4 until the creation of the cutting plane is completed at all distribution points.
[0027] The array parameters in Step 2.3.2 include the starting distance, the array spacing, and the ending distance.
[0028] Step 3 specifically includes the following steps:
[0029] Step 3.1: Select four steel bar groups of the double-layer steel bar mesh and respectively set the interval quantity of the stirrup arrangement for each group;
[0030] Step 3.2: According to the four steel bar groups selected in Step 3.1 and the corresponding interval quantities of the stirrup arrangement, screen out the steel bars in each steel bar group that actually participate in the stirrup arrangement;
[0031] Step 3.3. Nestedly traverse the inner steel bars of one layer and the outer steel bars to calculate the shortest distance between two spatial steel bar lines and the coordinates of their corresponding points 、 ;
[0032] Step 3.4. Repeat Step 3.3 to calculate the shortest distance between two spatial steel bar lines on the inner and outer sides of the other layer and the coordinates of their corresponding points 、 ;
[0033] Step 3.5. Combine Step 3.3 and Step 3.4 to obtain a point set composed of four coordinate points in the corresponding order, and calculate two hook positioning points from the following formula 、 :
[0034]
[0035]
[0036]
[0037] In the formula, is the spatial midpoint of the two-layer steel bar mesh; is the function for calculating the distance between two spatial points;
[0038] Step 3.6. Determine the plane where the stirrup is located from the two directions of one layer of steel bar lines at the corresponding points obtained in Step 3.3 or Step 3.4 and the hook positioning points obtained in Step 3.5:
[0039]
[0040] In the formula, represents the bending direction of the hook; represents the unit direction vector of the steel bar line at point , represents the unit direction vector of the steel bar line at point ; 、 Take 、 in Step 3.3 at the same time or take 、 in Step 3.4 at the same time; 、 are direction coefficients;
[0041]
[0042] In the formula, is the normal vector of the plane where the stirrup is located, is the stirrup direction vector;
[0043] Step 3.7: Position the hook points obtained in Step 3.5 and offset the corresponding distance along the hook bending direction obtained in Step 3.6 to obtain the stirrup main body positioning points and , where is the offset direction coefficient;
[0044] Step 3.8: Construct a straight line from the stirrup main body positioning points and obtained in Step 3.7 as the stirrup main body;
[0045] Step 3.9: Construct the bent section and straight section of the stirrup hook at both ends of the stirrup main body obtained in Step 3.8, and the normal vector of the plane where the hook is located is in the same direction as the stirrup plane normal vector obtained in Step 3.6.
[0046] The offset distance in Step 3.7 is the sum of the radii of the corresponding layer of steel bars and the stirrup radius.
[0047] The beneficial effects of the present invention are as follows: The stirrup layout method for double-layer steel bar meshes based on BIM of the present invention is based on BIM forward design, locates the stirrups by calculating the grid intersection points in the steel bar mesh, fully considers the irregular characteristics of the special-shaped steel bar mesh, especially complex special-shaped components such as curved walls, fork holes, and fork pipes, improves the positioning accuracy and applicability. In addition, the present invention introduces an algorithm for obtaining the shortest distance between spatial steel bars, effectively solves the problem of difficult stirrup positioning when two steel bars do not intersect at the grid, comprehensively covers various stirrup layout working conditions, is closer to the actual engineering requirements, fills the gap in the three-dimensional layout of stirrups for such components, reduces the manual processing after drawing, improves the work efficiency, and has good application prospects. BRIEF DESCRIPTION OF THE DRAWINGS
[0048] Figure 1 is a flowchart of the stirrup layout method for double-layer steel bar meshes based on BIM of the present invention;
[0049] Figure 2 is a schematic diagram of the arch top model in the embodiment of the present invention;
[0050] Figure 3 is a schematic diagram of the double-layer steel bar mesh of the arch top in the embodiment of the present invention;
[0051] Figure 4 is a schematic diagram of the shortest distance between two spatial steel bars and their corresponding points in the stirrup layout method for double-layer steel bar meshes based on BIM of the present invention;
[0052] Figure 5 It is a schematic diagram of the bending directions of the stirrup hooks of two spatial steel bars in the method for arranging stirrups of double-layer steel bar meshes based on BIM according to the present invention;
[0053] Figure 6 It is a schematic diagram of the arrangement effect of stirrups for the double-layer steel bar mesh at the vault in the embodiment of the present invention. Specific embodiments
[0054] The present invention will be described in detail below with reference to the accompanying drawings and specific embodiments.
[0055] Embodiment 1
[0056] The present invention provides a method for arranging stirrups of double-layer steel bar meshes based on BIM. As Figure 1 shown, taking a BIM platform with modeling and rendering capabilities as the integration environment, and on the basis of the existing BIM model, steel bar lines are generated by translating the reinforcement surface and making it tangent to the auxiliary surface. By using this method of generating steel bar lines, the arrangement of double-layer steel bar meshes as Figure 3 shown can be completed step by step. Starting from the idea of determining the stirrup hook positioning points using the grid intersection points of the steel bar mesh, considering that there are no precise intersection points in practice due to reasons such as different steel bar lapping and arrangement methods at the grid intersections, the method of obtaining the shortest distance between two steel bars at the grid intersection and the corresponding points on the steel bar lines is used to obtain the stirrup hook positioning points. Finally, the bending direction of the hook and the plane where the stirrup is located are determined, and the straight section and the bent section of the stirrup are arranged according to business requirements. This method is flexible and effective, has no requirements for the shape of the model, can not only meet the stirrup arrangement of regular model components, but also support the stirrup arrangement of special-shaped and complex components.
[0057] Embodiment 2
[0058] The present invention provides a method for arranging stirrups of double-layer steel bar meshes based on BIM, including the following steps:
[0059] Step 1: Based on the BIM forward design idea, create or import a BIM three-dimensional model;
[0060] Step 2: Based on the model obtained in Step 1, create a double-layer steel bar mesh at relevant positions;
[0061] Step 3: Based on the double-layer steel bar mesh reinforcement model obtained in Step 2, arrange stirrups.
[0062] Embodiment 3
[0063] The present invention provides a method for arranging tie bars of a double-layer steel bar mesh based on BIM. On the basis of Embodiment 2, in step 1, a BIM platform can be selected according to business scenarios and technical requirements. This platform needs to support modeling capabilities such as creating points, lines, surfaces, solids, and Boolean operations. Then, according to the selected BIM platform and the data format it supports, a three-dimensional model of the component is created or imported.
[0064] Embodiment 4
[0065] The present invention provides a method for arranging tie bars of a double-layer steel bar mesh based on BIM. On the basis of Embodiment 2, step 2 preferably includes the following steps:
[0066] Step 2.1: Since the steel bar mesh is usually attached to the model surface, select the model surface where the steel bar mesh is to be arranged as the reinforcement surface.
[0067] Step 2.2: Offset the reinforcement surface to obtain the surface where the steel bars are located. The offset distance is calculated by the following formula:
[0068]
[0069] In the formula: is the offset distance; is the distance from the outer surface of the steel bar to the reinforcement surface. If it is an outer steel bar, it is the protective layer thickness. If it is an inner steel bar, its value can be taken as the sum of the protective layer thickness and the diameter of the outer steel bar; is the diameter of the steel bar.
[0070] Step 2.3: Construct a cutting plane; specifically, it includes the following steps:
[0071] Step 2.3.1: Select a continuous edge as the guiding line.
[0072] Step 2.3.2: Set the array parameters, including the starting distance, array spacing, and ending distance.
[0073] Step 2.3.3: Combine the array parameters and sequentially arrange distribution points along the guiding line.
[0074] Step 2.3.4: At each distribution point, create a cutting plane passing through this point with the tangent vector of the guiding line as the normal vector.
[0075] Step 2.3.5: Repeat step 2.3.4 until the creation of the cutting plane is completed at all distribution points.
[0076] Step 2.4: Use the geometric algorithm provided by the platform to calculate the intersection lines between the surface where the steel bars are located and all cutting planes. These lines are the three-dimensional steel bar positioning lines (abbreviation: "steel bar lines") and form a steel bar group therefrom.
[0077] Step 2.5. Repeat Steps 2.1 to 2.4 to complete the arrangement of the double-layer steel bar mesh.
[0078] Example 5
[0079] The present invention provides a method for arranging stirrups for a double-layer steel bar mesh based on BIM. On the basis of Example 2, Step 3 preferably includes the following steps:
[0080] Step 3.1. Select a total of four steel bar groups in two directions for each of the double layers, and set the interval quantity for arranging stirrups for each group of steel bars respectively.
[0081] Step 3.2. According to the four steel bar groups selected in Step 3.1 and their corresponding interval quantities for arranging stirrups, screen out the steel bars actually participating in arranging stirrups for each group.
[0082] Step 3.3. Nest and traverse the two groups of steel bars in the horizontal and vertical directions of one layer. Based on the inner steel bars and outer steel bars obtained for this layer, calculate the shortest distance between two spatial steel bar lines and the coordinates of their corresponding points 、 .
[0083] Step 3.4. Repeat Step 3.3 to calculate the shortest distance between two spatial steel bar lines of the other layer and the coordinates of the corresponding points on the steel bar lines 、 .
[0084] Step 3.5. According to the principle that the hook positioning point should be on the outer steel bar at the grid intersection, combine Steps 3.3 and 3.4 to obtain a point set composed of four points in the corresponding order, and calculate two hook positioning points through the following formula:
[0085]
[0086]
[0087]
[0088] In the formula, is the midpoint in space of the two-layer steel bar mesh; 、 are respectively the stirrup hook positioning points of the two-layer steel bar mesh; is a function for calculating the distance between two points in space.
[0089] Step 3.6. Determine the plane where the stirrup is located from the two directions of the corresponding points obtained in Step 3.3 or Step 3.4 on the steel bar line of one layer and the hook positioning points obtained in Step 3.5:
[0090]
[0091] In the formula, represents the bending direction of the hook; represents the unit direction vector of the steel bar line at point , represents the unit direction vector of the steel bar line at point ; because the hooks at both ends of the stirrup are in the same plane, so , can simultaneously take the , mentioned in step 3.3, , or simultaneously take the , mentioned in step 3.4.
[0092]
[0093] In the formula, is the normal vector of the plane where the stirrup is located, is the direction vector of the stirrup.
[0094] Step 3.7: Offset the hook positioning points , obtained in step 3.5 along the hook bending direction obtained in step 3.6 by a corresponding distance to obtain , . The offset distance is the sum of the radii of the steel bars in the corresponding layer and the radius of the stirrup, and the offset direction coefficient is determined by the shape of the stirrup.
[0095] Step 3.8: Construct a straight line through the two points , obtained in step 3.7 as the main body of the stirrup.
[0096] Step 3.9: Construct the bending section and the straight section of the stirrup hook at both ends of the stirrup main body obtained in step 3.8 according to business requirements. The normal vector of the plane where the hook is located should be in the same direction as the normal vector of the stirrup plane obtained in step 3.6.
[0097] Embodiment 6
[0098] The present invention provides a method for arranging stirrups for a double-layer steel bar mesh based on BIM, which can be specifically implemented according to the following steps:
[0099] S1: Select a BIM platform built based on the open-source modeling engine OpenCASCADE (hereinafter referred to as "Occ") as the modeling engine, and select to create a new one or import a concrete arch roof model as shown in Figure 2 as an embodiment, and the model parameters are shown in Table 1.
[0100] Table 1 Vault Model Parameters (Unit: m)
[0101]
[0102] The reinforcement parameters are shown in Table 2:
[0103] Table 2 Vault Model Reinforcement Parameters (Unit: mm)
[0104]
[0105] S2: First, create the outer steel bars of the soffit and the back of the arch. Select both as the reinforcement surfaces. Use the member function PerformByJoin of the tool class BRepOffsetAPI_MakeOffsetShape provided by Occ for generating offset shapes and pass in the offset values to obtain the TopoDS_Shape objects O-1 and O-2 of the surfaces where the steel bars are located respectively (the base class of all boundary representation (B-Rep) geometries in Occ). The offset value is half of the sum of the cover thickness and the outer steel bar diameter.
[0106] S3: As Figure 2 shown, select the springing edge as the guide line. Pass the selected guide line into the tool class BRepAdaptor_Curve provided by Occ (which adapts the geometric edge in the topology to a parametric curve), construct the object and denote it as CurveA. According to the settings of the start distance, array spacing, and end distance of 5 cm, 20 cm, and 5 cm respectively, evenly distribute the distribution points on the guide line. Then, construct the cutting plane Geom_Plane objects CO-1, CO-2, CO-3,... passing through these points with the tangent vector of the guide line at the distribution points as the normal vector.
[0107] S4: Take the surfaces O-1 and O-2 of the outer steel bars of the two layers of mesh obtained in S2, and the cutting planes CO-1, CO-2, CO-3,... obtained in S3 as parameters respectively to construct the BRepAlgoAPI_Section object (a tool class provided by Occ for calculating the intersection between two geometric objects), and then call its SectionEdges member function to obtain the intersection lines, which are the steel bar lines. All the steel bars generated from O-1 and the cutting planes are denoted as the steel bar group GO-1, and all the steel bars generated from O-2 and the cutting planes are denoted as the steel bar group GO-2.
[0108] S5: Create the inner steel bars of the soffit and the back of the arch. Similarly, select both as the reinforcement surfaces. Obtain the TopoDS_Shape objects I-1 and I-2 of the surfaces where the steel bars are located by offsetting through the method described in S2. The offset value is half of the sum of the cover thickness, the outer steel bar diameter, and the inner steel bar diameter.
[0109] S6: As shown in Figure 2 , select the spandrel as the guiding line, and construct cutting plane Geom_Plane objects CI-1, CI-2, CI-3, … through the method described in S3.
[0110] S7: Through the method described in S4, use I-1, I-2 and cutting planes CI-1, CI-2, CI-3, … to cut each other to generate steel bars. All the steel bars generated by I-1 and the cutting planes are denoted as steel bar group GI-1, and all the steel bars generated by I-2 and the cutting planes are denoted as steel bar group GI-2.
[0111] S8: As shown in Figure 3 , based on the four steel bar groups obtained in S4 and S7, the steel bar mesh of the arch back is composed of inner and outer steel bars GI-1 and GO-1; the steel bar mesh of the arch belly is composed of inner and outer steel bars GI-2 and GO-2. Set the interval number of the stirrup layout for each group of steel bars to 2, and then screen out the steel bars actually participating in the stirrup layout for each group.
[0112] S9: Nest and traverse the inner and outer steel bar groups GI-1 and GO-1 at the arch back. Based on the i th steel bar obtained in GI-1 and the j th steel bar obtained in GO-1, use the tool class BRepExtrema_DistShapeShape provided by Occ for calculating the minimum distance between two geometric shapes, and pass in the and TopoDS_Shape objects, calculate and obtain the corresponding points of the shortest distance between the two spatial steel bar lines through the member functions GetPointOnShape1 and GetPointOnShape2 of BRepExtrema_DistShapeShape , . For the schematic diagram, see Figure 4 (in the figure, , generally refer to the corresponding points of the shortest distance between two steel bar lines on the inner and outer sides of any steel bar mesh layer). Then, respectively construct BRepAdaptor_CompCurve (a tool class provided by Occ, which adapts the composite curve in the topology to a parametric curve) objects from the TopoDS_Shape of steel bar and , and then use the member function D1 of BRepAdaptor_CompCurve to obtain the unit tangent vector of at point and At the point the unit tangent vector .
[0113] S10: Nestedly traverse the inner and outer steel bar groups GI-2 and GO-2 at the spandrel. Based on the i th steel bar obtained in GI-2 and the j th steel bar obtained in GO-2, use the method described in S9 to calculate , , , .
[0114] S11: The , , , (simplified to: , , , ) with the same order obtained from S9 and S10 and the unit tangent vectors , , , (simplified to: , , , ) are combined together as the positioning conditions for constructing a single tie bar.
[0115] The hook positioning point is obtained through the following formula, in this embodiment, = , = .
[0116]
[0117]
[0118]
[0119] S12: As shown in Figure 5 , the bending direction of the tie bar is obtained through the following formula, where the direction coefficient , is determined according to business requirements and the direction of the steel bar line itself. To ensure that the hooks at both ends of the tie bar are in the same plane, and can both take , .
[0120]
[0121] S13: Substituting S11 for , The bending direction of the hook obtained along S12 The sum of the outer reinforcement radius and the reinforcement radius is offset to obtain the reinforcement main body positioning point , .
[0122] S14: Incoming parameters , Construct a BRepBuilderAPI_MakeEdge (a tool class provided by Occ for creating geometric edges) object, and obtain the TopoDS_Shape of the reinforcement body through its member function Shape.
[0123] S15: The normal vector of the plane where the reinforcement is located is obtained according to the following formula :
[0124]
[0125]
[0126] Create tie hooks (including the curved and straight segments at both ends of the body) according to business requirements (hook angle, hook length), provided that the normal vectors of the planes where the two hooks are located are parallel to In this embodiment, the hook angle is 180 degrees, the hook length is 6.25d (d is the diameter of the reinforcement), and the arrangement effect is as follows: Figure 6 shown.
Claims
1. A double-layer steel mesh reinforcement arrangement method based on BIM, characterized in that: The following steps are involved: Step 1: Obtain component BIM 3D model; Step 2, arranging a double-layer steel mesh on the reinforcement surface of the model obtained in step 1; The specific steps include: Step 2.1, select the model surface where the steel mesh is to be installed as the reinforcement surface; Step 2.2, offset the reinforcement surface to obtain the surface where the reinforcement is located; Step 2.3, construct the cutting plane; Step 2.4, calculate the intersection lines between the surface where the steel bars are located and all the cutting surfaces, obtain the three-dimensional steel bar positioning line, i.e., the steel bar line, and group the steel bars in two directions of a single layer into a layer of steel mesh; Step 2.5, repeat steps 2.1 to 2.4 to obtain another layer of steel mesh, and complete the arrangement of the double-layer steel mesh; Step 3, calculating the grid intersections in the double-layer steel mesh obtained in step 2, and locating and arranging the reinforcement based on the calculated grid intersections; specifically comprising the following steps: Step 3.1, select four steel bar groups of the double-layer steel mesh, and set the number of intervals for the reinforcement arrangement for each group of steel bars; Step 3.2, based on the four steel bar groups selected in step 3.1 and the corresponding number of reinforcement arrangement intervals, screen out the steel bars actually involved in arranging the reinforcement in each steel bar group; Step 3.3: Nest and traverse the inner reinforcement of one layer and outer reinforcement , calculate the shortest distance between two spatial steel bars and the coordinates of their corresponding points , ; Step 3.4: Repeat step 3.3 to calculate the shortest distance between the two inner and outer sides of the other layer and the coordinates of their corresponding points. , ; Step 3.5: Combine steps 3.3 and 3.4 to obtain a point set consisting of four coordinate points in the corresponding order, and calculate the two hook positioning points by the following formula: , : In the formula, is the spatial midpoint of the two layers of steel mesh; is a function for calculating the distance between two points in space; Step 3.6: Determine the plane where the reinforcement is located by using the two directions of one layer of reinforcement wire at the corresponding point obtained in step 3.3 or step 3.4 and the hook positioning point obtained in step 3.5: In the formula, Indicates the direction in which the hook bends; Indicates that the reinforcement line is at point The direction unit vector at Indicates that the reinforcement line is at point The direction unit vector at ; , At the same time, take the , Or take the , ; , is the direction coefficient; In the formula, is the normal vector of the plane where the reinforcement is located, is the reinforcement direction vector; Step 3.7: Locate the hook obtained in step 3.5 , Bend the hook along the direction obtained in step 3.6 Offset the corresponding distance to get the main positioning point of the reinforcement , , is the offset direction coefficient; Step 3.8: The main positioning point of the reinforcement obtained from step 3.7 , Construct a straight line as the main body of the reinforcement; Step 3.9: Construct the curved segments and straight segments of the tie hooks at both ends of the tie rod body obtained in step 3.
8. The normal vector of the plane where the hook is located is the same as the normal vector of the tie rod plane obtained in step 3.
6. Same direction.
2. The method for arranging double-layer steel mesh reinforcement based on BIM according to claim 1, characterized in that: In the step 1, OpenCASCADE based on the open source modeling engine is selected to build a BIM platform, and a concrete component model is newly created or imported.
3. The method for arranging double-layer steel mesh reinforcement based on BIM as claimed in claim 1, characterized in that: The offset distance in step 2.2 Use the following formula to calculate: Where: is the distance from the outer surface of the steel bar to the reinforcement surface; is the diameter of the steel bar.
4. The method for arranging double-layer steel mesh reinforcement based on BIM according to claim 1, characterized in that: The step 2.3 specifically includes the following steps: Step 2.3.1, select the continuous edge of the model as the guide line; Step 2.3.2, set array parameters; Step 2.3.3, based on the array parameters, arrange the distribution points along the guide line in sequence; Step 2.3.4, at each distribution point, use the tangent vector of the guide line as the normal vector and create a cutting plane passing through the distribution point; Step 2.3.5: Repeat step 2.3.4 until the cutting planes are created at all distribution points.
5. The method for arranging double-layer steel mesh reinforcement based on BIM as claimed in claim 4, characterized in that: The array parameters in step 2.3.2 include the starting point distance, array spacing and end point distance.
6. The method for arranging double-layer steel mesh reinforcement based on BIM according to claim 1, characterized in that: The offset distance in step 3.7 is the sum of the radius of the corresponding layer of reinforcement and the radius of the tension reinforcement.
Citation Information
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