A Calculation Method of Spare Parts Requirements for Normal Series Parts
A calculation method and technology of demand, applied in the direction of calculation, data processing applications, instruments, etc., can solve the problems of low accuracy, excessive guarantee and insufficient guarantee of spare parts demand results.
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[0043] Taking the number of installed machines N = 3 and the demand for spare parts S = 3 as an example, if the guarantee task is successful, the quantity of spare parts used by each unit location is shown in Table 1:
[0044] Table 1 Quantity of spare parts used in each unit position
[0045]
[0046] For each row in the table, the probability of that event occurring can be calculated. For example, for the row data [1 0 2] in the table, its physical meaning is: all 3 unit positions are guaranteed success, 1 spare part is used in unit 1 position, no spare part is used in unit 2 position, and unit 3 position With 2 spare parts used, the probability of this event is equal to P(N s =1)×P(N s =0)×P(N s = 2), N sThe physical meaning of is the quantity of spare parts used at each unit location during the sustainment mission. Add the probabilities of each row of events in Table 1 to get the probability when the total number of spare parts used is 3.
[0047] Specifically, fo...
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