Low-oxygen constant-humidity storage device and storage method thereof
A storage device and humidity technology, applied in the direction of separation methods, chemical instruments and methods, applications, etc., can solve the problems of difficulty in popularization and application, high cost of active humidity control, etc.
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Embodiment 1
[0055] The low-oxygen and constant-humidity rigid storage cabinet device of the present invention is used for low-oxygen and constant-humidity storage of bronzes. The volume of the hypoxic and constant humidity storage cabinet is 3m 3 , the ventilation rate is 0.02d -1 . Use iron-based oxygen scavenger to remove oxygen and control the oxygen content below 2%. The iron-based oxygen scavenger has the advantages of non-toxic, harmless and low cost. Use silica gel desiccant to control the humidity in the storage space. The target relative humidity is 30% ± 5%. The ambient humidity during storage is 68%, the temperature is 25° C., and the storage time is 6 months.
[0056] Calculate the dosage of oxygen scavenger according to the following formula:
[0057] m 1 =A 1 ·A 2 ·V·(C 1 -C 2 ) / Q+V·N·D·21% / Q;
[0058] Among them, A 1 = 1.3, A 2 = 1 (the space occupied by the bronze ware is very small, so it is ignored), V = 3m 3 , C 1 = 21%, C 2 =2%, Q=0.12m 3 / kg, N=0.02d...
Embodiment 2
[0070] The low-oxygen and constant-humidity rigid storage cabinet of the present invention is used to carry out low-oxygen and constant-humidity insecticide on ancient books. The volume of the hypoxic and constant humidity rigid storage cabinet is 2m 3 , ventilation rate 0.02d -1 . Use an organic type oxygen scavenger to reduce oxygen and control the oxygen content at 0.1% to 1% or below 0.1%, and maintain it for 2 weeks. Use silica gel desiccant for humidity control, and the target relative humidity is 55%±3%. The environmental limit humidity is 80%, and the temperature is 20±5℃.
[0071] Calculate the dosage of oxygen scavenger according to the following formula:
[0072] m 1 =A 1 ·A 2 ·V·(C 1 -C 2 ) / Q+V·N·D·21% / Q;
[0073] Among them, A 1 = 1.3, A 2 =0.5 (ancient books occupy 50% of the volume of the storage cabinet), V=2m 3 , C 1 = 21%, C 2 =0.1%, Q=0.04m 3 / kg, N=0.02d -1 , D = 14 days. Calculated by the above formula, M 1 ≈9.73 kg.
[0074] Calculate ...
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