Method for calculating deformation of valve plate of shock absorber under arbitrary axisymmetric and non-uniform pressure
A non-uniform pressure distribution and axisymmetric technology, applied in the field of hydraulic shock absorbers, can solve difficult problems such as shock absorber throttle valve parameter design and characteristic simulation model
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Embodiment 1
[0069] Example 1: The radius of the inner circle of a ring valve plate of a shock absorber =5.0mm, outer circle radius =8.5mm, elastic modulus E =2.0 and Poisson's ratio mu =0.3, thickness h =0.3mm, apply uniform pressure on the radius [5.0,8.0]mm section and [8.0,8.5]mm section respectively p 0 =3.0MPa and linear non-uniform pressure p ( r )= MPa, calculate the deformation of the shock absorber valve plate under this pressure.
[0070] The calculation method for the deformation of the shock absorber valve plate under any axisymmetric non-uniform pressure provided by the example of the present invention, its calculation process is as follows figure 2 As shown, the specific calculation steps are as follows:
[0071] (1) Determined at the radius r j The microannular pressure proportional coefficient at k pj :
[0072] According to non-uniform pressure p ( r )= MPa and its maximum value is p 0 =3.0MPa, the radius of the inner circle of the shock...
Embodiment 2
[0115] Embodiment 2: The thickness of a shock absorber valve plate h =0.3mm, inner circle radius =5.0mm, outer circle radius =8.5mm, elastic modulus E =2.0 and Poisson's ratio mu =0.3, in [ , ] within the range of the secondary non-uniform pressure MPa, calculate the deformation of the shock absorber valve plate under this pressure.
[0116] The calculation steps of Embodiment 1 are adopted, namely:
[0117] (1) Determined at the radius r j The microannular pressure proportional coefficient at k pj :
[0118] According to non-uniform pressure MPa and its maximum value is p 0 =3.0MPa, the radius of the inner circle of the shock absorber valve plate =5.0mm, outer circle radius =8.5mm, the radius interval [ ] are equally divided into 70 parts, the micro-ring spacing =0.05mm, ( j =1, 2, 3, ..., 70), radius r j The radius of the inner circle of the microring = r j , outer circle radius , ( j =1,2,…,70), determined in the radius r ...
Embodiment 3
[0131] Embodiment 3: The structural parameters and material characteristic parameters of a damper valve plate are the same as those in Embodiment 1, that is, the thickness h =0.3mm, inner circle radius =5.0mm, outer circle radius =8.5mm, elastic modulus E =2.0 and Poisson's ratio mu =0.3, in [ , ] within the range of applied sinusoidal non-uniform pressure MPa, calculate the deformation of the shock absorber valve plate under this pressure.
[0132] Using the calculation steps of Embodiment 1, namely
[0133] (1) Determined at the radius rj The microannular pressure proportional coefficient at :
[0134] According to non-uniform pressure MPa and its maximum value is p 0 =3.5MPa, the radius of the inner circle of the shock absorber valve plate =5.0mm, outer circle radius =8.5mm, the radius interval [ ] are equally divided into 70 parts, the micro-ring spacing =0.05mm, ( j =1, 2, 3, ..., 70), radius r j The radius of the inner circle of ...
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