Calculation Method of Shock Absorber Valve Plate Deformation under Arbitrary Axisymmetric Non-uniform Pressure
A non-uniform pressure distribution and axisymmetric technology, which is applied in the field of hydraulic shock absorbers, can solve difficult problems such as shock absorber throttle valve parameter design and characteristic simulation model
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Embodiment 1
[0052] Example 1: The radius r of the inner circle of a ring valve plate of a shock absorber a =5.0mm, outer circle radius r b =8.5mm, elastic modulus E=2.0×10 11 Pa and Poisson's ratio μ=0.3, thickness h=0.3mm, on the radius [5.0,8.0]mm segment and [8.0,8.5]mm segment, respectively apply uniform pressure p 0 =3.0MPa and linear non-uniform pressure Calculate the deformation of the shock absorber valve plate under this pressure.
[0053] The calculation method for the deformation of the shock absorber valve plate under any axisymmetric non-uniform pressure provided by the example of the present invention, its calculation process is as follows figure 2 As shown, the specific calculation steps are as follows:
[0054] (1) Determined at the radius r j The microannular pressure proportional coefficient k at pj :
[0055] According to non-uniform pressure and its maximum value is p 0 =3.0MPa, the radius r of the inner circle of the damper valve plate a =5.0mm, outer cir...
Embodiment 2
[0081] Embodiment 2: The thickness of a shock absorber valve plate is h=0.3mm, and the radius of the inner circle is r a =5.0mm, outer circle radius r b =8.5mm, elastic modulus E=2.0×10 11 Pa and Poisson's ratio μ = 0.3, in [r a ,r b ] within the range of the secondary non-uniform pressure Calculate the deformation of the shock absorber valve plate under this pressure.
[0082] The calculation steps of Embodiment 1 are adopted, namely:
[0083] (1) Determined at the radius r j The microannular pressure proportional coefficient k at pj :
[0084] According to non-uniform pressure and its maximum value is p 0 =3.0MPa, the radius r of the inner circle of the damper valve plate a =5.0mm, outer circle radius r b =8.5mm, the radius interval [r a ,r b ] are evenly divided into 70 parts, that is, 70 microrings, the width of each microring is Δr=0.05mm, and at radius r j The inner radius r of the microring at kj = r j , outer circle radius r tj = r kj +Δr=r j+1 , w...
Embodiment 3
[0097] Embodiment 3: The structural parameters and material characteristic parameters of a shock absorber valve plate are the same as those in Embodiment 1, that is, the thickness h=0.3mm, and the inner circle radius r a =5.0mm, outer circle radius r b =8.5mm, elastic modulus E=2.0×10 11 Pa and Poisson's ratio μ = 0.3, in [r a ,r b ] within the range of applied sinusoidal non-uniform pressure Calculate the deformation of the shock absorber valve plate under this pressure.
[0098] Using the calculation steps of Embodiment 1, namely
[0099] (1) Determined at the radius r j The microannular pressure proportional coefficient k at prj :
[0100] According to non-uniform pressure and its maximum value is p 0 =3.5MPa, the radius r of the inner circle of the damper valve plate a =5.0mm, outer circle radius r b =8.5mm, the radius interval [r a ,r b ] are evenly divided into 70 parts, that is, 70 microrings, the width of each microring is Δr=0.05mm, and at radius r j T...
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