An air conditioner, its compound defrosting control method and device, and storage medium
A control method and technology of control devices, which are applied in heating and ventilation control systems, heating and ventilation safety systems, mechanical equipment, etc., can solve the problem that the input power is continuously attenuated, the suction superheat degree is always 0 °C, and the efficiency of defrosting is affected. , unclean defrosting and other problems, to achieve the effect of improving defrosting effect and comfort
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Embodiment 1
[0101] The temperature of the outer tube is -10°C, and the exhaust temperature is 65°C.
[0102] Taking the quantization factor introduced in the above embodiment as an example, the calculated fuzzy value of the outer pipe temperature is 3, and the fuzzy value of the exhaust gas temperature is -3. Check Table 1 and Table 2 respectively, the fuzzy language of the outer tube temperature is PS (0.8), PB (0.6), and the rest is 0, which can be understood as PS with a probability of 0.8 / 1.4 and PB with a probability of 0.6 / 1.4. Similarly, look up table 2 and get the exhaust temperature 0.8 / 1.4 probability is NS, 0.6 / 1.4 probability is NB.
[0103] Combined with Table 3:
[0104] When Tg is PS and Tp is NS, and the result is ZO, it can be considered that the fuzzy evaluation result has a probability of 0.8 / 1.4*0.8 / 1.4 as ZO;
[0105]When Tg is PS and Tp is NB, and the result is NS, it can be considered that the fuzzy evaluation result has a probability of 0.8 / 1.4*0.6 / 1.4 as NS;
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Embodiment 2
[0111] The temperature of the outer tube is -10°C, and the exhaust temperature is 85°C.
[0112] As above, the fuzzy value of the outer pipe temperature is 3, and the fuzzy value of the exhaust temperature is 3. Check Table 1 and Table 2 respectively, the outer pipe temperature has a probability of 0.8 / 1.4 as PS, 0.6 / 1.4 probability as PB, and the exhaust temperature is 0.8 The / 1.4 probability is PS, and the 0.6 / 1.4 probability is PB.
[0113] Combined with Table 3,:
[0114] When Tg is PS and Tp is PS, the result is PS, and the probability is 0.8 / 1.4*0.8 / 1.4;
[0115] When Tg is PS and Tp is PB, the result is PB, and the probability is 0.8 / 1.4*0.6 / 1.4;
[0116] When Tg is PB and Tp is PS, the result is PB with a probability of 0.6 / 1.4*0.8 / 1.4;
[0117] When Tg is PB and Tp is PB, the result is PB, and the probability is 0.6 / 1.4*0.6 / 1.4;
[0118] In summary, 16 / 49 is PS and 33 / 49 is PB. x=1*16 / 49+2*33 / 49=1.673. Then the target duration ts=30*(2+1.673)+30=140.2s.
[0119...
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