Air energy power-generating method
An air energy and air technology, applied in the field of air energy power generation, can solve the problems of high development cost, difficult to popularize and use, and imperfect collection methods.
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example 1
[0029] An air energy power plant is built in a township, the total vertical height of the pipes is H=100 meters, the flow cross-sectional area of the air outlet at the top is 12 meters in diameter, and the area is A 2 =113.m 2 , the inner diameter of the seat ring of the throat air turbine is 3 meters, and the flow cross-sectional area A=7.06 meters 2 . At this time, the pipeline system can produce the maximum flow rate, and the correction coefficient Φ=0.9 is taken, Take the rated air velocity V at the end of the pipe 2 =10m / s, then the flow in the pipe Q=V 2 A 2 =10×113.1=1131 meters 3 / second, take the air gravity γ = 12.26 N / m 3 , efficiency η=0.75, then the air energy power plant can obtain power:
[0030] N=γH·Q·η=12.26×100×1131×0.75=1040 kilowatts.
example 2
[0032] A city builds an air energy power plant, the total vertical height of the pipeline is H=400 meters, the cross-sectional diameter of the air outlet at the top is 51 meters, and the area is A 2 = 2000 meters 2 , The inner diameter of the throat air turbine seat ring is 14 meters. Flow cross-sectional area A = 154 meters 2 , at this time the pipeline system can produce the maximum flow rate, take the correction coefficient Φ=0.9, Take the rated air velocity at the end of the pipe: V 2 =20m / s, then the flow in the pipe Q=V 2 A 2 =20×2000=40000 meters 3 / second, take the air gravity γ = 12.26 N / m 3 , efficiency η=0.75, then the air power plant can obtain power:
[0033] N=γ·H·Q·η==12.26×400×40000×0.75=147000 kilowatts.
[0034] It can be seen from the above example that increasing the air column height H and the cross-sectional area A increases the flow Q, and the power of the power plant increases greatly. One unit of air energy power station can get a lot of p...
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