Frequency hopping transmitter, receiver device and frequency hopping method of continuous frequency division multiple address system
A frequency division multiple access, transmitter technology, applied in multi-frequency code system, transmission system, communication between multiple stations, etc., can solve the problems of system PAPR/CM increase, failure, distorted reception, etc.
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[0079] Embodiments of the transmitter and receiver devices of the present invention, such as figure 1 Shown is a functional block diagram of the LFDMA-FH-based system described in the embodiment of the present invention. Wherein the system composed of transmitter and receiver can realize various aspects and implementation solutions of the present invention, as follows:
[0080] Such as figure 1 As shown, the left half is the implementation of the LFDMA-FH transmitter device. In this embodiment, the transmitter device includes: a frequency hopping DFT-S OFDM modulation module, a CP module, and a framing module; wherein, the frequency hopping DFT-S OFDM modulation module performs DFT-S OFDM modulation on the signal, and the CP is added The module handles adding a cyclic prefix to avoid crosstalk between symbols, and then sends it to the framing module for framing.
[0081] Such as figure 2 shown, the attached figure 1 Internal structure and processing method of frequency h...
Embodiment 1
[0097] Embodiment 1, when there are 5 users, corresponding to the Latin square of the 5th order, make it α=2, such as Figure 6 As shown, the bandwidth requirements of users 1 and 4 are 2 RBs, users 0 and 2 are 1 RB, and users 3 are 3 RBs (the settings here are arbitrary and can be changed arbitrarily according to actual needs), then
[0098] At time 0, users occupy spectrum in the following order
[0099] 02413
[0100] Then 0(0), 2(1), 4(2~3), 1(4~5), 3(6~8);
[0101] At time 1, users occupy spectrum in the following order
[0102] 13024
[0103] Then 1(0~1), 3(2~4), 0(5), 2(6), 4(7~8);
[0104] At time 2, users occupy spectrum in the following order
[0105] 24130
[0106] Then 2(0), 4(1~2), 1(3~4), 3(5~7), 0(8);
[0107] And so on in the future.
[0108] Here n(p~q) means that user n occupies the continuous spectrum from p to q, that is, the bandwidth requirement of user n is q-p+1 RBs. For example, 3(7~9) means that user 3 occupies 3 RBs from 7 to 9. a continuous...
Embodiment 2
[0116] Example 2, the above example, due to Σ k = 0 K - 1 X ( k ) = N , Therefore, for the convenience of explanation, M=K is selected (because K=5 is just a prime number). under normal circumstances, Σ k = 0 K - 1 X ( k ) N , You should choose M>K. For example, in the above example, if N=12, then Σ k = 0 K - 1 X ( k ) ...
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