Message processing method and device
A message processing and message technology, applied in the field of communication, can solve the problems of unguaranteed service quality, discarding messages by local devices, and not knowing how to deal with them, so as to avoid chain effects, avoid infinite increase, and reduce overhead.
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example 1
[0091] Example 1: Suppose C1=12
[0092] Then, 7≤X1≤10, that is to say, if the period value indicated by the label of the message received by the first device at period 12 belongs to [7, 10], it means that these messages are normal messages, otherwise it is Abnormal message.
[0093] Specifically, when C1=12, the first device will send the message sent by the first device in period 6, that is, the first device will send Q1, and Q2, Q3, Q4, and Q0 can receive it. As can be seen from Table 1, the cycles of the second device corresponding to Q2, Q3, Q4, and Q0 are 7, 8, 9, and 10 respectively, and the first device sends Q2, Q3, Q4, and Q0, therefore, if 7≤X1≤10, the first packet is considered to be a normal packet. It should be understood that although the queue corresponding to the message sent by the second device in cycle 5 is Q0, since the first device will send the message sent by the second device in cycle 5 in the 11th cycle, if the message sent by the second device in c...
example 2
[0094] Example 2: Suppose X1=8
[0095] Then, 10≤C1≤13. That is to say, if the first device receives a packet with X1=8 in a period from period 12 to period 15, it considers the packet as a normal packet; otherwise, it considers the packet as an abnormal packet.
[0096] Specifically, the first device will send a message with X1=8 in cycle 14, and the queue for the message with X1=8 to enter is Q3. If the message of X1=8 is reached, the message is considered as a normal message. Referring to Table 1, it can be seen that, when the first device receives a message with X1=8 in any period from period 10 to period 13, it considers the message with X1=8 as a normal message.
[0097] More specifically, it can be seen from Table 1 that under normal circumstances, the message with X1=8 will arrive at period 12 or 13. Then, it can be determined that the messages with X1=8 received in periods 12 and 13 are normal messages.
[0098] Since in the four cycles between cycle 10 and cycle ...
example 3
[0114] Example 3: Suppose C1=12
[0115] Then, 13≤X2≤16. That is to say, if the first device receives in period 12 a packet that needs to be sent in any period from period 13 to period 16, it considers the packet as a normal packet.
[0116] Specifically, in cycle 12, the first device will send a message of X1=6, and the queue corresponding to the message of X1=6 is Q1. At this time, the first device can receive messages corresponding to queues Q2, Q3, Q4, and Q0. message. It can be seen from Table 1 that the messages of X1=7 / 8 / 9 / 10 correspond to Q2, Q3, Q4 and Q0 respectively, while the messages of X1=7 / 8 / 9 / 10 correspond to the periods to be sent respectively It's 13, 14, 15 and 16. Therefore, if the first device receives a packet in period 12 that needs to be sent in any period from period 13 to period 16, it considers the packet as a normal packet.
[0117] It should be understood that when S is other values other than 1, the principle of judging whether the first mes...
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