Transmission processing method and device and related equipment
A processing method and transmission block technology, applied in the field of communication, can solve problems such as the limitation of the number of OFDM symbols in the time slot and the limitation of coverage capability, and achieve the effects of improving reliability, coverage capability, and throughput rate
- Summary
- Abstract
- Description
- Claims
- Application Information
AI Technical Summary
Problems solved by technology
Method used
Image
Examples
Embodiment approach 1
[0169] Embodiment 1, scheduling transmission on 2 time slots, using SLIV 1 A time domain resource allocation indication is determined.
[0170] Step 1, calculate SLIV 2 The SLIV 2 Satisfy:
[0171] In the case of (L-1)≤21, SLIV 2 =14*[L-1-14*(N-1)]+S;
[0172] In the case of (L-1)>21, SLIV 2 =14*[28-(L-1)]+(14-1-S);
[0173] Among them, 14
[0174] Step 2, calculate SLIV 1 ,SLIV 1 =SLIV 2 +M. When M is equal to 128, SLIV 1 The value of , and the corresponding relationship between S and L are shown in Table 2. Therefore when SLIV 1 =153, then S=11, L=16 can be uniquely determined.
[0175] Table II:
[0176]
[0177] When M is equal to 105, SLIV 1 The value of , and the corresponding relationship between S and L are shown in Table 3 below. When SLIV=142, S=9 and L=17 can be uniquely determined.
[0178] Table three:
[0179]
[0180]
Embodiment approach 2
[0181] Implementation mode two, first use bits indicate the number of slots occupied by time domain resources, for example, use '00' to represent N=1, '01' to represent N=2, '10' to represent N=3, and '11' to represent N=4; reuse the existing SLIV The mode indicates the allocation of slots, and the default is L1>28. As shown in the above Table 1, assuming that SLIV=26 is indicated, it means S=12, L1=2, but N=3, the actual indicated L=L1+14*2=30, at this time, when N is equal to 3, the SLIV The corresponding relationship between values, S and L is shown in Table 4 below.
[0182]
Embodiment approach 3
[0183] Embodiment 3, using SLIV 3 Determine time domain resource allocation indication, SLIV 3 =14*(L-1)+S. When L ranges from 1 to 42 and S ranges from 0 to 13, SLIV 3 The value of , and the corresponding relationship between S and L are shown in Table 5 below. Among them, the filled part indicates that when N=2, SLIV 3 Correspondence with S and L. For example, when SLIV 3 =214, then S=4, L=16 can be uniquely determined.
[0184] Table five:
[0185]
[0186]
PUM
Login to View More Abstract
Description
Claims
Application Information
Login to View More - R&D
- Intellectual Property
- Life Sciences
- Materials
- Tech Scout
- Unparalleled Data Quality
- Higher Quality Content
- 60% Fewer Hallucinations
Browse by: Latest US Patents, China's latest patents, Technical Efficacy Thesaurus, Application Domain, Technology Topic, Popular Technical Reports.
© 2025 PatSnap. All rights reserved.Legal|Privacy policy|Modern Slavery Act Transparency Statement|Sitemap|About US| Contact US: help@patsnap.com



