Method for detecting N-acetylaspartic acid by using nuclear spin single-state selectivity
A technology of aspartic acid and nuclear spin, which is applied in the field of magnetic resonance, can solve the problems of inconvenient and fast, real-time selective detection of N-acetylaspartic acid, etc., and achieve short test time and simple and fast test method , good selectivity and reproducibility
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Embodiment 1
[0035] The specific steps from preparation of N-acetylaspartic acid singlet to realization of N-acetylaspartic acid signal filtering (the instrument used is BrukerAVANCE III 500MHz nuclear magnetic resonance instrument):
[0036] Step 1: In this example, N-acetylaspartic acid is dissolved in D 2 O system, prepare an N-acetylaspartic acid deuterium aqueous solution with a mass fraction of 0.6% and apply a 90° pulse to obtain figure 1 N-Acetyl Aspartate 1 H spectrum, where the triplet at 4.63 ppm is the signal of H on the methine of N-acetylaspartate, the single peak at 4.69 ppm is the water peak signal, and the group of peaks at 2.82 ppm is the N-acetyl sky Two H signals on the methylene group of the aspartic acid molecule. Select the three Hs on the methylene and methine groups in the structure of N-acetylaspartic acid (such as figure 2 Shown 1 The peaks of No. 1, 2, and No. 3 peaks marked on the H spectrum are used as the target peaks, calibrated to the middle of No. 2 and No. 3...
Embodiment 2
[0064] The specific steps from preparing N-acetylaspartic acid singlet under the mixed system to realizing N-acetylaspartic acid signal filtering (the instrument used is BrukerAVANCE III 500MHz nuclear magnetic resonance instrument):
[0065] Step 1: Configure a deuterium aqueous solution of N-acetylaspartic acid and glucose with a mass fraction of 0.6%, place it in a nuclear magnetic resonance instrument, and apply a 90° pulse to obtain Figure 7 Mixed solution shown 1 H spectrum, the triplet at 4.63ppm is the signal of H on the methine of N-acetylaspartate, the single peak at 4.69ppm is the water peak signal, and a set of peaks at 2.82ppm is N-acetylaspartate The two H signals on the methylene of the acid molecule, the rest are the glucose signals. Read the J coupling value between the hydrogens of the system and the corresponding chemical shift:
[0066] ω 1 =899.13Hz,ω 2 =0.39Hz,ω 3 =-0.99Hz;
[0067] J 12 = 6.26 Hz, J 13 =6.15Hz,J 23 = 17.22 Hz.
[0068] Step 2: In the mixed sys...
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