A high-order m×n optical switching matrix for all-optical switching
An optical switching matrix and all-optical switching technology, applied in multiplexing system selection devices, wavelength division multiplexing systems, multiplexing communications, etc. problems, to achieve the effect of strong scalability, convenient maintenance and good adaptability
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Embodiment 1
[0049] like figure 1 As shown, a 1×2 optical switch matrix is used to build a 1×4 optical switch matrix, that is, a=1, b=2, M=1, N=4, the number of 1×2 optical switch matrices required at the input end is m, Then there are: t 1 = 0,T 1 Count 0; because 1≤1, stop calculation, the input end has only 1 level, m=1+0=1;
[0050] The number n of 1×2 optical switching matrices required for the output matrix, then f 1 = 0, F 1 Count 0;
[0051] Because 2≤2, the calculation is stopped, and the output terminal has only one level, n=2+0=2; so m+n=3 requires three 1×2 switching matrices to form a 1×4 switching matrix.
Embodiment 2
[0053] like figure 2 As shown, a 2×2 optical switch matrix is used to form an 8×6 optical switch matrix, that is, a=2, b=2, M=8, N=6, the number of 2×2 optical switch matrices required at the input end is m, Then there are: t 1 = 0,T 1 Count 0;
[0054] 4>2, continue to calculate t 2 =0, T 2 Count 0;
[0055] 2≤2, stop calculation, there are 2 levels at the input end, m=4+2+0+0=6;
[0056] The number n of 2×2 optical switching matrices required at the output end, then f 1 = 0, F 1 Count 0;
[0057] 3>2, continue to calculate t 2 ≠0, T 2 Count 1; 1≤2, stop calculation, the output also has 2 levels; so n=3+1+0+1=5;
[0058] m+n=11, so a total of 11 2×2 switching matrices are needed to form an 8×6 switching matrix.
Embodiment 3
[0060] like image 3 As shown, a 96×32 optical switch matrix is built with an 8×8 optical switch matrix, that is, a=8, b=8, M=96, N=32, the number of 8×8 optical switch matrices required at the input end is m, but: t 1 = 0,T 1 Count 0; 12>8, then continue to calculate t 2 ≠0, T 2 Count 1; 1≤8, stop calculation, there are 2 levels at the input end, m=12+1+0+1=14;
[0061] The number n of 8×8 optical switching matrices required at the output end, then f 1 = 0, F 1 Count 0;
[0062] Because 4≤8, the calculation is stopped, and the output terminal has only one level; therefore n=4+0=4; m+n=18, so a total of 18 8×8 switching matrices are required to form a 96×32 switching matrix.
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