Method and system for allocating maximum number of soft channel bits available
A soft channel bit and maximum value technology, which is applied in the field of allocation of the maximum value of available soft channel bits, can solve problems such as low buffer utilization, and achieve the effect of preventing buffer overflow and high buffer utilization.
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Embodiment 1
[0063] In this embodiment, the UE capability is 14, and the corresponding total number of soft channel bits is 259200 bits as an example to illustrate the method of allocating the buffer size of HARQ, such as Figure 7 shown, including the following steps:
[0064] Step 710: Node B divides the total number of soft channel bits (Total soft bits T=259200) corresponding to the UE capability level by the number of HARQs (N=6) to obtain temp_process_memory_size (that is, N TIR =43200);
[0065] Step 720: The method for determining the process_memory_size of the first to (N-1)th HARQ is as follows: use temp_process_memory_size (43200) to find the value process memory that is closest to the value but greater than or equal to the temp_process_memory_size from the predefined enumeration values size1=44000.
[0066] Step 730: Then let process_memory_size2 (that is, N LIR )=T-(N-1)×process_memory_size1, get process_memory_size2=39200, then the process memory size of the Nth HARQ is eq...
Embodiment 2
[0070] In this embodiment, the UE capability is 10, and the corresponding total number of soft channel bits is 172800 bits as an example to describe the method of allocating the buffer size of HARQ, such as Figure 8 shown, including the following steps:
[0071] Step 810: Node B divides the total number of soft channel bits (Total soft bits T=172800) corresponding to the UE capability level by the number of HARQs (N=6) to obtain temp_process_memory_size (28800);
[0072] Step 820: The method for determining the process_memory_size of the 1st to (N-1)th HARQ is as follows: use temp_process_memory_size (28800) to find the value closest to the value but greater than or equal to the temp_process_memory_size from the predefined enumeration values process_memory_size1= 28800.
[0073] Step 830: Then set process_memory_size2=T-(N-1)×process_memory_size1 to obtain process_memory_size2=28800, then the process_memory_size of the Nth HARQ is equal to the process_memory_size2 that is ...
Embodiment 3
[0077] In this embodiment, the UE capability is 26, and the corresponding total number of soft channel bits is 619200 bits as an example to describe the method of allocating the buffer size of HARQ, as Figure 9 shown, including the following steps:
[0078] Step 910: Node B divides the total number of soft channel bits (Total soft bits T=619200) corresponding to the UE capability level by the number of HARQs (N=12) to obtain temp_process_memory_size (51600);
[0079] Step 920: The method for determining the process_memory_size of the 1st to (N-1)th HARQ is as follows: use temp_process_memory_size (51600) to find the value closest to the value but greater than or equal to the value of the temp_process_memory_size process_memory_size1= 52000.
[0080] Step 930: Then set process_memory_size2=T-(N-1)×process_memory_size1 to obtain process_memory_size2=47200, then the process memory size of the Nth HARQ is equal to the value closest to but less than Equal to the value of the pro...
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