A Transient Energy Directional Protection Method for Transmission Lines with Static Synchronous Series Compensators
A technology of series compensation and static synchronization, applied to emergency protection circuit devices, electrical components, fault locations, etc., can solve problems such as difficult identification of line faults, achieve the effect of avoiding inconstant changes in positive and negative polarity and improving reliability
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Embodiment 1
[0031] Example 1: 500kV line with static synchronous series compensator such as figure 1 shown. The line parameters are as follows: the total length of the line is 150km for the PM section, 150km for the MN section, and 220km for the NQ end. The ground impedance is 0Ω, and the data sampling rate is 20kHz. A single-phase ground fault occurs 60km away from the M terminal on the MN section.
[0032] (1) Calculate the instantaneous power according to the formula (1) in the manual, the instantaneous power at the M terminal is as follows figure 2 shown.
[0033] (2) According to the formula (2) in the manual, the instantaneous power is integrated to obtain the corresponding transient energy, and the transient energy at the M terminal is as follows image 3 shown.
[0034] (3) Judgment of the sign of the transient energy according to formula (3) in the specification, by image 3 middle sign (E M ) = -1 to know the point of failure (F 11 ) for M terminal relay R 1 Fault in p...
Embodiment 2
[0035] Example 2: 500kV line with static synchronous series compensator such as figure 1 shown. The line parameters are as follows: the total length of the line is 150km for the PM section, 150km for the MN section, and 220km for the NQ end. The ground impedance is 0Ω, and the data sampling rate is 20kHz. A single-phase ground fault occurs 90km away from the M terminal in the MN section.
[0036] (1) Calculate the instantaneous power according to the formula (1) in the manual, the instantaneous power at the M terminal is as follows Figure 4 shown.
[0037] (2) According to the formula (2) in the manual, the instantaneous power is integrated to obtain the corresponding transient energy, and the transient energy at the M terminal is as follows Figure 5 shown.
[0038] (3) Judgment of the sign of the transient energy according to formula (3) in the specification, by Figure 5 middle sign (E M ) = -1 to know the point of failure (F 12 ) for M terminal relay R 1 Fault in...
Embodiment 3
[0039] Example 3: 500kV line with static synchronous series compensator such as figure 1 shown. The line parameters are as follows: the total length of the line is 150km for the PM section, 150km for the MN section, and 220km for the NQ end. The ground impedance is 0Ω, and the data sampling rate is 20kHz. A single-phase ground fault occurs 50km away from the M terminal on the PM section.
[0040] (1) Calculate the instantaneous power according to the formula (1) in the manual, the instantaneous power at the M terminal is as follows Figure 6 shown.
[0041] (2) According to the formula (2) in the manual, the instantaneous power is integrated to obtain the corresponding transient energy, and the transient energy at the M terminal is as follows Figure 7 shown.
[0042] (3) Judgment of the sign of the transient energy according to formula (3) in the specification, by Figure 7 Medium sign (E M)=1 to know the point of failure (F 2 ) for M terminal relay R 1 For the rever...
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