Transient energy direction protection method for power transmission line with static synchronous series compensator
A series compensation, static synchronization technology, applied in emergency protection circuit devices, electrical components, information technology support systems, etc., can solve problems such as difficulty in identifying line faults, avoid inconstant changes in positive and negative polarities, and improve reliability. Effect
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Embodiment 1
[0031] Example 1: 500kV line with static synchronous series compensator figure 1 Shown. The line parameters are as follows: the length of the line is 150km at the PM section, 150km at the MN section, and 220km at the NQ end. The ground impedance is 0Ω, and the data sampling rate is 20kHz. A single-phase ground fault occurred 60km from the M end of the MN section.
[0032] (1) Calculate the instantaneous power according to the formula (1) in the manual, the instantaneous power of the M terminal is as follows figure 2 Shown.
[0033] (2) Integrate the instantaneous power according to the formula (2) in the manual to obtain the corresponding transient energy, the transient energy of the M terminal is as image 3 Shown.
[0034] (3) According to the formula (3) in the manual, judge the sign of transient energy, by image 3 Sign in ( E M ) = -1 Know the fault point ( F 11 ) For M terminal relay R 1 It is a fault in the positive direction.
Embodiment 2
[0035] Example 2: 500kV line with static synchronous series compensator figure 1 Shown. The line parameters are as follows: the length of the line is 150km at the PM section, 150km at the MN section, and 220km at the NQ end. The ground impedance is 0Ω, and the data sampling rate is 20kHz. A single-phase ground fault occurred at 90km from the M end of the MN section.
[0036] (1) Calculate the instantaneous power according to the formula (1) in the manual, the instantaneous power of the M terminal is as follows Figure 4 Shown.
[0037] (2) Integrate the instantaneous power according to the formula (2) in the manual to obtain the corresponding transient energy, the transient energy of the M terminal is as Figure 5 Shown.
[0038] (3) According to the formula (3) in the manual, judge the sign of transient energy, by Figure 5 Sign in ( E M ) = -1 Know the fault point ( F 12 ) For M terminal relay R 1 It is a fault in the positive direction.
Embodiment 3
[0039] Example 3: A 500kV line with static synchronous series compensator is like figure 1 Shown. The line parameters are as follows: the length of the line is 150km at the PM section, 150km at the MN section, and 220km at the NQ end. The ground impedance is 0Ω, and the data sampling rate is 20kHz. A single-phase ground fault occurred at 50km from the M end of the PM segment.
[0040] (1) Calculate the instantaneous power according to the formula (1) in the manual, the instantaneous power of the M terminal is as follows Image 6 Shown.
[0041] (2) Integrate the instantaneous power according to the formula (2) in the manual to obtain the corresponding transient energy, the transient energy of the M terminal is as Figure 7 Shown.
[0042] (3) According to the formula (3) in the manual, the sign of transient energy is judged by Figure 7 Sign in ( E M )=1 Know the fault point ( F 2 ) For M terminal relay R 1 Fault in the opposite direction. ...
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