Equivalent assessment method and prediction method of current-carrying life of pulse fuse in repetitive frequency operation
A repetition frequency and fuse technology, which is applied in the field of efficiency assessment, can solve the problem of difficulty in testing the high-frequency resonance current-carrying life of pulse fuses in inverter power supplies, and achieve accurate and reliable results, accurate prediction, and simple operation.
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Embodiment 1
[0227]Using the existing 0-DC150A adjustable DC power supply in the laboratory, the equivalent pulsed DC current-carrying life of a DC1600V / 250A / 10kHz pulse fuse was assessed for the high-frequency resonance current-carrying life, including the following steps:
[0228] Step 1. Determine the equivalent pulsed DC loading method
[0229] The resonant frequency carried by the pulse fuse is f 0 =10kHz sinusoidal resonant current I(t)=141sin(20π×10 3 t), the static resistance of the fuse at room temperature is R f0 =6mΩ; from t=0 moment, the pulse fuse carries current T continuously 0 =Pause after 10ms, the pause time is ΔT=10ms, T 0 +ΔT as the time T for one job 1 ,T 1 =T 0 +ΔT=20ms; at t=T 1 At this moment, the pulse fuse starts carrying current for the second time, completely repeats the whole process of carrying current and suspending the first time, and the working time is still T 1 ;According to the above mode, the pulse fuse repeats work n times, n=3000, repetition f...
Embodiment 2
[0239] Using the existing 0-DC150A adjustable DC power supply in the laboratory, a DC1600V / 250A / 10kHz high-frequency resonant current-carrying pulse fuse was used for aging and prediction of equivalent pulsed DC current-carrying pulse, including the following steps:
[0240] Step 1. Determine the equivalent pulsed DC loading method
[0241] The resonant frequency carried by the pulse fuse is f 0 =10kHz sinusoidal resonant current I(t)=141sin(20π×10 3 t), the static resistance of the fuse at room temperature is R f0 =6mΩ; from t=0 moment, the pulse fuse carries current T continuously 0 =Pause after 10ms, the pause time is ΔT=10ms, T 0 +ΔT as the time T for one job 1 ,T 1 =T 0 +ΔT=20ms; at t=T 1 At this moment, the pulse fuse starts carrying current for the second time, completely repeats the whole process of carrying current and suspending the first time, and the working time is still T 1 ;According to the above mode, the pulse fuse repeats work n times, n=3000, repetit...
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