Synchronous adjusting method of balance beam hanging points of hoisting equipment with ultrahigh pump lift
A lifting equipment, synchronous adjustment technology, applied in the direction of load hanging components, transportation and packaging, can solve the problem of wire ropes intertwined at the lifting point, avoid accidents, reduce the asynchronous value, and improve the average lifting speed.
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Embodiment 1
[0102] A lifting mechanism has two lifting points, and the two lifting points are respectively driven by two multi-layer winding reels of steel wire ropes, and the two reels use a mechanical method to ensure the synchronization of the speed of the two reels. The lifting height of the lifting mechanism is equal to 400m, the multiplier m of the pulley block is 1, and the length of the reel is L t Equal to 780mm, roll diameter D t Equal to 500mm, wire rope diameter d s Equal to 21.5mm, the length of wire rope that needs to be wound onto each drum is 410m. This embodiment is to lift heavy objects in a certain deep well.
[0103] Method of the present invention is as follows:
[0104] 1) According to the actual situation, such as well diameter, well components, construction technology and other conditions, the maximum length of the beam is determined to be 1350mm, the maximum asynchronous value Δmax that the balance beam can balance is 2200mm, and the asynchronous value of the a...
Embodiment 2
[0109] The method of this embodiment is basically the same as that of Embodiment 1, the difference is that step 3) the method of selecting b value is different:
[0110] When the reel is fully wound with 5 layers of steel wire rope, even if n=5, using the formulas (6), (8) and (9) can get:
[0111] N = L t / d s =780 / 21.5 =36.28(circle)
[0112] N 5 = n L t / d s =5×780 / 21.5 =181.4 (circle)
[0113] L 5 = nπL t (D t / d s +n) =5×π×780×( 500 / 21.5+5)=346196 (mm)
[0114] Since the length of the steel wire rope that needs to be wound on each drum is 410m, there are 410000-346196=63804mm of steel wire rope to be wound on the 6th floor, and the length of each coil of the steel wire rope on the 6th floor is π[ D t +(2×6-1)d s ] = π[ 500+(2×6―1)×21.5]=2313.78mm, on the 6th floor, 63804 / 2313.78=27.58 circles, namely N na =27.58 circles. There are 36.28-27.58=8.7 coils of wire rope on the 6th floor, which are empty.
[0115] First select the thickness b of the a...
Embodiment 3
[0129] The method of this embodiment is basically the same as that of Embodiment 2, the difference is that step 3) the method of selecting the b value is different:
[0130] Assuming that the out-of-synchronization value Δ=2360mm is all compensated by the original 1~(n-1) layer steel wire rope after adding the flange to initially select b, that is, let Δ in formula (21) , =Δ,N nb =0 to initially determine b:
[0131] b=Δ , m / [nπ(n - 1) + 2N nb πd s ]
[0132] =2360×1 / [6π(6-1)+2×0×π×21.5]=25.04mm
[0133] Take b=25mm for rounding.
[0134] When the reel is fully wound with 5 layers of steel wire rope, even if n=5, using the formulas (6), (8) and (9) can get:
[0135] N = L t / d s =780 / 21.5 =36.28(circle)
[0136] N 5 = n L t / d s =5×780 / 21.5 =181.4 (circle)
[0137] L 5 = nπL t (D t / d s+n) =5×π×780×( 500 / 21.5+5)=346196 (mm)
[0138] In the formula:
[0139] N - the number of turns of each layer of steel wire rope;
[0140] N 5 - the total num...
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