Method for rapidly detecting mixing uniformity of powdery material
A technology of mixing uniformity and powder materials, applied in the direction of analyzing materials, instruments, etc., can solve the problems of narrow application range, poor representativeness, complicated steps, etc., and achieve the effects of rapid detection, simple operation, and strong reference value.
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[0044] Example one
[0045] The Al of different particle size and equal mass ratio 2 O 3 Mix the powder with NaCl powder for 30 minutes.
[0046] Step 1. Determine the properties of the mixture:
[0047] Two mixed materials Al 2 O 3 The particle size of powder and NaCl powder are 147μm and 104μm, respectively. Al 2 O 3 The mass fraction of powder and NaCl powder are both 50%;
[0048] Step two, sampling:
[0049] Randomly sample the materials that have been mixed after 30 minutes, that is, take a circle with a diameter of 5 mm from the mixed materials to take a powder sample, and then count the total number of particles contained in the circle to 7,697;
[0050] Step three, calculation:
[0051] Because it is a mixture of powders of different particle sizes,
[0052] M x =7697
[0053] C 0 =r 1 2 50%+r 2 2 50%=0.147 2 ×0.5+0.104 2 ×0.5=0.006
[0054] Calculate the deviation value
[0055] δ = | log M x - 2 log R - ( log π 4 - log C 0 ) | ...
Example Embodiment
[0058] Example two
[0059] Al with the same particle size 2 O 3 Powder mixed with powder C, Al 2 O 3 The mass ratio of powder to powder C is 1 to 2, mixing for 30 minutes.
[0060] Step 1. Determine the properties of the mixture:
[0061] The particle size of the two mixed materials is 147μm, Al 2 O 3 The mass fractions of powder and C powder are 33.3% and 66.7% respectively, and the theoretical density of each material is ρ Al2O3 Is 4.0*10 -3 g / mm 3 , Ρ c Is 2.25*10 -3 g / mm 3 ;
[0062] Step two, sampling:
[0063] Random sampling of materials that have been mixed after a period of time, that is, take a circle with a diameter of 5 mm from the mixed materials to take a powder sample, and then count the total number of particles contained in the circle to be 9,086;
[0064] Step three, calculation:
[0065] Because when mixing powders of the same particle size,
[0066] M x = 9086
[0067] m x = 4 πr 3 3 ( ρ 1 · 9086 2 + ρ 2 · 9086 2 ...
Example Embodiment
[0073] Example three
[0074] Mix sorghum rice of different particle size and equal quality with millet.
[0075] Step 1. Determine the properties of the mixture:
[0076] The particle sizes of the two mixed materials sorghum and millet are 1.6775mm and 0.67mm, respectively, and the mass fraction of sorghum and millet is 50%;
[0077] Step two, sampling:
[0078] Take a random sample of the mixed material after 3 minutes, that is, take a circle with a diameter of 14 mm from the mixed material to take a powder sample, and then count the total number of particles contained in the circle to 759;
[0079] Step three, calculation:
[0080] Because it is a mixture of powders of different particle sizes,
[0081] M x = 759
[0082] C 0 =r 1 2 50%+r 2 2 50% = 1.6775 2 ×0.5+0.67 2 ×0.5=1.631
[0083] Calculate the deviation value
[0084] δ = | log M x - 2 log R - ( log π 4 - log C 0 ) | 5 = 40 %
[0085] Step 4: Evaluation
[0086] Bec...
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