Circumference indexing scribing compass
An indexing and gauge technology, applied in metal processing mechanical parts, precision positioning equipment, metal processing equipment, etc., can solve the problems of high cost of indexing tools, cumbersome operation, poor accuracy, etc., to achieve simple use, accurate adjustment, Efficient indexing effect
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[0029] Example 1:
[0030] Such as image 3 As shown, the inner hole diameter of the part is Φ340mm, the required indexing circumference diameter is Φ410 mm, the positioning diameter of the positioning pin 3 is 10mm, and the measuring diameter is 20mm. The radial length or diameter of the indexing slider 4 and the fixed pin 2 are both 10mm. Use a vernier caliper to measure the distance D1 between the two positioning pins 3 and the fixed pin 2, considering that the positioning pin 3 and the fixed pin 2 have a certain size, so to ensure that the two positioning pins 3 are tangent to the inner hole of the part, draw a rule The center of rotation of the body 1 (that is, the center of the fixed pin 2) coincides with the center of the part. D1 should meet: D1=170 (radius of the inner hole of the part) + 10 (radius of the fixed pin + radius of the positioning pin) = 180mm, and then Use a vernier caliper to measure the distance D2 between the indexing slider 4 and the fixed pin 2. It is ...
Example Embodiment
[0033] Example 2:
[0034] Such as Figure 4 As shown, the outer diameter of the part is Φ500mm, the required indexing circumference diameter is Φ410 mm, the positioning diameter of the positioning pin 3 is 10mm, and the measuring diameter is 20mm. The radial length or diameter of the indexing slider 4 and the fixed pin 2 are both 10mm. Use a vernier caliper to measure the distance D1 between the two positioning pins 3 and the fixed pin 2, so to ensure that the two positioning pins 3 are tangent to the outer circle of the part, the center of rotation of the ruler body 1 (that is, the center of the fixed pin 2) and The center of the parts coincide, D1 should meet: D1=250 (part outer radius) + 20 (fixed pin radius + positioning pin positioning radius + positioning pin measurement radius) = 270mm, then use the vernier caliper to measure the indexing slider 4 and fix The distance D2 between the pins 2 also takes into account that the indexing slider 4 and the fixed pin 2 have a certa...
Example Embodiment
[0042] Example 3:
[0043] Such as Image 6 As shown, the diameter of the inner hole of the part is Φ500 mm, the fixed pin 2 is on the circle with the center of the gauge body as the center and the radius is 400 mm, the required indexing circle diameter is Φ600 mm, and the positioning diameter of the positioning pin 3 is 10mm. The diameter is 20mm, the radial length or diameter of the indexing slider 4 and the fixed pin 2 are both 10mm, and the distance D1 between the two positioning pins 3 and the fixed pin 2 is measured with a vernier caliper, taking into account the positioning pin 3 and the fixed pin 2. It has a certain size. Therefore, in order to ensure that when the two positioning pins 3 are tangent to the inner hole of the part, the center of rotation of the ruler body 1 coincides with the center of the part, D1 should meet: D1=400 (circumference radius where the fixed pin is located)-250 ( Part inner hole radius) + 20 (fixed pin radius + locating pin positioning radius ...
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