Calculation method of deformation of coaxial cab stabilizer bar system
A stabilizer bar system and calculation method technology, applied in the direction of calculation, design optimization/simulation, special data processing applications, etc., can solve the problem that cannot provide analytical calculation formulas, cannot meet the coaxial cab stabilizer bar system, and is difficult to obtain accurate and reliable Deformation displacement calculation value and other issues, to achieve the effect of reliable deformation displacement calculation method
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Embodiment 1
[0043] Embodiment 1: The structure of a coaxial cab stabilizer bar system is left-right symmetrical, such as figure 2 As shown, it includes: swing arm 1, suspension rubber bushing 2, torsion rubber bushing 3, torsion tube 4; wherein, torsion tube 4 and torsion rubber bushing 3 are coaxial; the distance between the left and right swing arms 1 L c =1550mm, that is, the suspension distance of the stabilizer bar; the distance l between the suspension rubber bushing 2 and the torsion rubber bushing 3 1 =380mm, that is, the length of the swing arm; the distance from the suspension position C of the swing arm to the outermost end A is Δl 1 =47.5mm; the length L of the twisted tube 4 w =1500mm, inner diameter d=35mm, outer diameter D=50mm, elastic modulus E=200GPa, Poisson’s ratio μ=0.3; the structure and material properties of the left and right four rubber bushes are exactly the same, as image 3 As shown, it includes: an inner circle sleeve 5, a rubber sleeve 6, and an outer ci...
Embodiment 2
[0075] Embodiment 2: The structure of a coaxial cab stabilizer bar system is left-right symmetrical, such as figure 2 As shown, among them, the distance L between the left and right swing arms c =1400mm, that is, the suspension distance of the stabilizer bar; the distance l between the suspension rubber bushing 2 and the torsion rubber bushing 3 1 =350mm, that is, the length of the swing arm; the distance Δl from the suspension position C of the swing arm to the outermost end A 1 =52.5mm; the length L of the torsion tube 4 w =1000mm, inner diameter d=42mm, outer diameter D=50mm. The structure and material properties of the left and right four rubber bushes are exactly the same, such as image 3 Shown, wherein, the inner circle diameter d of the inner circle sleeve 5 x =35mm, wall thickness δ=5mm; length L of rubber sleeve x =40mm, inner circle radius r a =22.5mm, outer circle radius r b =37.5mm; the material properties of the stabilizer bar and the material properties ...
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