A method for determining a conical indentation constraint factor and a representative strain of a titanium alloy
A technology of constraint factors and determination methods, which is applied in special data processing applications, instruments, electrical digital data processing, etc., can solve problems such as the relationship between performance changes of constraint factors, and achieve wide practicability, high precision, and good results. Effect
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Embodiment 1
[0057] Example 1: Taking TC11 titanium alloy as an example, when the elastic modulus is 70Gpa and the yield strength is 800MPa, the strain hardening exponent is 0.04, 0.05, 0.06, 0.07, 0.08, 0.09, 0.10, 0.11, 0.12, and the indentation is limited The indentation hardness calculated by the meta-model is 2.7439, 2.7585, 2.8036, 2.8267, 2.8653, 2.8988, 2.9266, 2.9746, 2.9945, respectively, through the formula ln(H / σ y )=lnC+nln(Eε r / σ y ) for fitting, the constraint factor obtained from the solution is 3.267, and the representative strain is 0.024.
[0058] When the elastic modulus is 70Gpa, the yield strength is 1400MPa, and the strain hardening exponent is 0.04, 0.05, 0.06, 0.07, 0.08, 0.09, 0.10, 0.11, 0.12, the indentation hardness calculated by the indentation finite element model is 4.1262, 4.1508, 4.2107, 4.2497, 4.2798, 4.3178, 4.3749, 4.4186, 4.4531, through the formula ln(H / σ y )=lnC+nln(Eε r / σ y ) for fitting, the constraint factor obtained from the solution is 2...
Embodiment 2
[0061] Example 2: Taking TC11 titanium alloy as an example, when the elastic modulus is 110Gpa and the yield strength is 800MPa, the strain hardening exponent is 0.04, 0.05, 0.06, 0.07, 0.08, 0.09, 0.10, 0.11, 0.12, and the indentation is limited The indentation hardness calculated by the meta-model is 3.0139, 3.0824, 3.0922, 3.1679, 3.1882, 3.2551, 3.2876, 3.3501, 3.3862, respectively, through the formula ln(H / σ y )=lnC+nln(Eε r / σ y ) for fitting, and the constraint factor obtained from the solution is 3.565, representing a strain of 0.024.
[0062] When the elastic modulus is 110Gpa, the yield strength is 1400MPa, and the strain hardening exponent is 0.04, 0.05, 0.06, 0.07, 0.08, 0.09, 0.10, 0.11, 0.12, the indentation hardness calculated by the indentation finite element model is 4.6874, 4.7236, 4.7405, 4.8388, 4.8821, 4.9074, 5.0015, 5.0590, 5.0901, through the formula ln(H / σ y )=lnC+nln(Eε r / σ y ) for fitting, the constraint factor obtained from the solution is 3.1...
Embodiment 3
[0065] Example 3: Taking TC11 titanium alloy as an example, when the elastic modulus is 150Gpa and the yield strength is 800MPa, the strain hardening exponent is 0.04, 0.05, 0.06, 0.07, 0.08, 0.09, 0.10, 0.11, 0.12, and the indentation is limited The indentation hardness calculated by the meta-model is 3.2044, 3.2611, 3.2898, 3.3790, 3.4137, 3.4796, 3.5452, 3.5702, 3.6741, respectively, through the formula ln(H / σ y )=lnC+nln(Eε r / σ y ) for fitting, the constraint factor obtained from the solution is 3.744, and the representative strain is 0.023.
[0066] When the elastic modulus is 150Gpa, the yield strength is 1400MPa, and the strain hardening exponent is 0.04, 0.05, 0.06, 0.07, 0.08, 0.09, 0.10, 0.11, 0.12, the indentation hardness calculated by the indentation finite element model is 5.0260, 5.1123, 5.1213, 5.2425, 5.2936, 5.3282, 5.4536, 5.4965, 5.5590, through the formula ln(H / σ y )=lnC+nln(Eε r / σ y ) for fitting, the constraint factor obtained from the solution is...
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