Method for measuring conveying capacity of belt conveyor
The technology of a belt conveyor and a measuring method is applied in the direction of measuring device, weighing, weighing equipment for continuous material flow, etc. The effect of capital cost
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example 1
[0019] Such as figure 1 The belt conveyor of the conveying method in (c). The conveying speed v of the belt conveyor is 2.5m / s; the vertical lifting height h is 18m; the no-load time t is 0.5 hours, and the no-load power consumption E 1 is 26.699kWh; load time t 1 for 1 hour, load power consumption E 2 is 117.831kWh; the amount of material conveyed within 1 hour is m; the acceleration of gravity g is 9.8m / s 2 ;1kWh=1×1000×3600J; When the material enters the belt conveyor, the speed parallel to the conveying direction is 0, how many tons is the conveying capacity of the belt conveyor within 1 hour of load.
[0020] Substitute the above data into the formula m=(E 2 –E 1 t 1 / t) / (gh+0.5v 2 –0.5v 1 2 )have to:
[0021] Substitute the parameters to get:
[0022] m=(117.831-26.699*1 / 0.5)*1000*3600 / (9.8*18+0.5*2.5^2-0.5*0^2)
[0023] m=1292069.628kg=1292.069t
[0024] After calculation, the material transport volume of this belt conveyor within 1 hour is 1292.069t.
example 2
[0026] Such as figure 1 The belt conveyor of the conveying method in (a). The conveying speed v of the belt conveyor is 2m / s; the vertical lifting height h is 9m; the power factor of the belt conveyor motor 0.9, the voltage is 380V; no-load current I 空载 is 45.164A; load current I 负载 is 67.205A; the acceleration of gravity g is 9.8m / s 2 ; 1 hour is 3600 seconds; when the conveying material enters the belt conveyor, the speed parallel to the conveying direction is 0, how much material is conveyed in 2 hours.
[0027] Since the delivery volume is calculated for 2 hours, the empty time t is 2 hours, and the load time t 1 for 2 hours.
[0028] 2 hours no-load power consumption E 1 for:
[0029]
[0030] 2 hours load power consumption E 2 for:
[0031]
[0032] Substitute the above parameters into m=(E 2 –E 1 t 1 / t) / (gh+0.5v 2 –0.5v 1 2 ),inferred:
[0033] m=(286621045.344-192618895.795*2 / 2) / (9.8*9+0.5*2^2-0.5*0^2)
[0034] m=1042152.434kg=1042.152t
[003...
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