Catalytic synthesis of phenylhydroxylamine compound
A compound and a technology for phenylhydroxylamine, which is applied in the field of synthesizing phenylhydroxylamine compounds under selenium catalysis, can solve the problems of not being used for the preparation of phenylhydroxylamine compounds, corrosive large chlorine-containing by-products, easy to pollute the environment, etc., and achieve easy and clean production , The effect of less equipment investment and mild reaction conditions
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Embodiment 1
[0014] Embodiment 1, the synthesis of phenylene (N-hydroxyaniline) under selenium catalysis
[0015] Add nitrobenzene (10mmol), selenium (0.5mmol), sodium borohydride (25mmol), and absolute ethanol 40mL to a 100mL round-bottomed flask under nitrogen protection, and stir the reaction at room temperature (12°C) for 3 hours. After the completion of product filtration, the filtrate was concentrated and purified by recrystallization from petroleum ether (60-90° C.) to obtain benzene, m.p. 81° C. (decomposition), and the yield was 77%.
Embodiment 2
[0016] Embodiment 2, the synthesis of phenylene (N-hydroxyaniline) compounds under selenium catalysis
[0017] Replacing nitrobenzene with substituted nitrobenzene according to the method of Example 1 for the reaction. The results are summarized in Table 1 in tabular form:
[0018]
[0019] Table 1: Synthesis of phenylene (N-hydroxyaniline) compounds under selenium catalysis
Embodiment 3
[0020] Embodiment 3, taking the synthesis of phenylhydrazine (N-hydroxyaniline) as an example, the synthesis of phenylhydrazine (N-hydroxyaniline) under different reaction conditions such as reducing agent, temperature, solvent, and reaction time. The results are summarized in Table 2 in tabular form.
[0021] Table 2: Effects of conditions such as reducing agent, temperature, solvent, and reaction time on the reaction
[0022] serial number
[0023] Reaction conditions: nitrobenzene 10mmol; sodium borohydride (potassium borohydride) 25mmol; selenium 0.5mmol; absolute ethanol 40mL; temperature 12-78°C; reaction time 0.25-3.0 hours; 2 O / THF is V H2O :V THF =0.5:40mL.
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