Method for indirectly measuring content of 1,3-dioleoyl-2-palmitoyl triglyceride
A technology of palmitic acid triglyceride and dioleic acid, applied in the field of chemical analysis, can solve the problems of interfering with the effective performance of products, affecting the accuracy of OPO, etc., to achieve the effect of supporting healthy growth and meeting nutritional requirements
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Embodiment 1
[0041] The first step of indirect detection of OPO:
[0042] Analyzing the dairy mixture gives:
[0043] 1. Total fatty acid composition
[0044] 2. sn-2 fatty acid composition
[0045] Using GB / T24894-2010 as the detection method, the result is:
[0046] Overall %P = 3 / 9 = 33.3%;
[0047] %P of sn-2 bits = 1 / 3 = 33.3%
[0048] Overall %O = 6 / 9 = 66.7%
[0049] %O = 2 / 3 = 66.7% for the sn-2 position.
Embodiment 2
[0051] The second step of indirect detection of OPO:
[0052] Calculated from the result:
[0053] 1. Content of sn-2 P in total fat
[0054] 2. Content of sn-1+3 in total fat
[0055] (1) Proportion of sn-2 P in total fat:
[0056] Because the P in the sn-2 position accounts for 1 / 3 of the total fatty acids, the ratio of the P in the sn-2 position to the total fat is: 33.3% / 3=11.1%.
[0057] (2) Proportion of sn-1+3 O in total fat:
[0058] The proportion of sn-2 O in total fat: 66.7% / 3=22.25%.
[0059] (total %O)-(%O in sn-2 position)=%O in sn-1+3 position, so the proportion of sn-1+3 position O in total fat: 66.7%-22.25%=44.4%
Embodiment 3
[0061] The third step of indirect detection of OPO:
[0062] based on:
[0063] sn-2 P in total fat content: 11%
[0064] sn-1+3 O in total fat content: 44.4%
[0065] Calculate OPO:
[0066] According to sn-2 bit P
[0067] According to sn-1+3 bit O
[0068] We choose a relatively low value as the limiting factor
[0069] OPO calculated from P:
[0070] Every 1% of the P content of the sn-2 position must correspond to 3% of the OPO content,
[0071] That is: P content at sn-2 position×3=11.1%×3=33.3%.
[0072] Calculate OPO according to O:
[0073] Every 1% of sn-1+3 O must correspond to 1.5% of OPO content,
[0074] Namely: O content at sn-1+3 position×1.5=44.4%*1.5=66.7%.
[0075] OPO content calculated from P is 33.3%
[0076] OPO content calculated from O is 66.7%
[0077] Because 33.3%<66.6%, the OPO content is 33.3%, even if the indirect method is used to measure the digested substances in the form of OPO, the result is correct.
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