Rapid design method for temperature control and crack prevention temperature stress control over tunnel floor lining concrete
A technology of temperature control and anti-cracking, temperature stress, applied in calculation, hydropower, hydropower stations, etc., can solve problems such as large error of strong constraint method, no design method, and far apart construction plans, etc., to achieve simple calculation formula, The effect of small calculation errors
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Embodiment 1
[0083] F2-type 1.0m-thick lining in the non-pressure section of the flood discharge tunnel in the type III1 surrounding rock area of the city gate tunnel
[0084] The 1.0m-thick F2 lining in the Class III1 surrounding rock area is the structural section with the largest number of Chengmen-type tunnels in the non-pressure section of the flood discharge tunnel, and it is difficult to control the temperature and prevent cracking.
[0085] Such as Figure 5 As shown, the rapid design method for temperature-controlled crack-proof temperature-stress control of tunnel floor lining concrete provided in this embodiment includes the following steps:
[0086] Step 1. Collect data for temperature control and anti-crack calculation of floor lining concrete:
[0087] Lining structure design data, lining structure section, concrete strength grade; environmental data, deformation modulus of surrounding rock under geological conditions, annual variation of temperature in the cave, annual v...
Embodiment 2
[0107] F4 type 1.5m lining in the non-pressure section of the flood discharge tunnel in the floor of the city gate tunnel type IV surrounding rock area
[0108] The basic information is the same as above. In order to reduce the length of the paper, only a brief introduction of the summer temperature control calculation results of the F4-type lining in the surrounding rock area of Category IV is briefly introduced.
[0109] In the design stage, the pouring construction will be carried out on July 1 in summer, and the temperature T in the cave will be calculated. a is 25.63℃, and the lowest temperature in winter is T min = 20°C. According to the above data, H=1.5m, W=15.2m, L=9m, C=40, E=20GPa, T 0 = 18°C. Draw up a temperature control scheme (18°C pouring, no water cooling, 12°C water cooling, 22°C water cooling), calculate Tg as 0°C, 23°C, and 13°C respectively, and substitute the above parameters into formula 1 to calculate: no water Cooling scheme σ max =2.147MPa; 1...
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