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Oval cross section equal-strength supporting beam bearing loads evenly distributed at intervals

A technology of uniform load distribution and cross-section, applied in the field of strength support beams, can solve the problems of increasing beam weight, cost increase, waste, etc., and achieve the effect of reducing weight, simplifying structure, and saving materials

Active Publication Date: 2020-08-25
HUNAN NORMAL UNIVERSITY
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  • Summary
  • Abstract
  • Description
  • Claims
  • Application Information

AI Technical Summary

Problems solved by technology

The traditional design mostly determines the structural size of the beam by limiting the maximum stress of the most dangerous section of the beam. The size of the entire beam is the same as the size of the most dangerous section. In this way, where the stress is small, the material does not fully play its role. It not only causes waste, but also increases the weight of the beam, which increases the cost and makes it difficult to operate and use

Method used

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  • Oval cross section equal-strength supporting beam bearing loads evenly distributed at intervals
  • Oval cross section equal-strength supporting beam bearing loads evenly distributed at intervals
  • Oval cross section equal-strength supporting beam bearing loads evenly distributed at intervals

Examples

Experimental program
Comparison scheme
Effect test

Embodiment 1

[0049] Embodiment 1, assuming that the number of sections of the uniformly distributed load on the solid elliptical cross-section beam is n=5, then the maximum sequence number of the odd-numbered bending moment is M 2n+1 , namely M 11 , the maximum serial number of the even-numbered bending moment is M 2n , namely M 10 ;The total load Q=73.5kN of 5 sections of uniform load, so the support reaction force V=Q / 2=36.75kN; beam length L 2 = 3m, interval between uniformly distributed loads of each section Thus L 1 =564mm, evenly distributed load According to formula (1) (odd-numbered section, i.e. the bending moment of interval section) and formula (2) (even-numbered section, i.e. the bending moment of uniformly distributed load section) and the technical scheme of the present invention, the bending moment M of each section can be obtained k (x)(kNm) and beam height dimension h k (x)(m) are as follows:

[0050] The first section 0≤x≤a, that is, 0≤x≤0.03m section, k=1:

[0...

Embodiment 2

[0096] Embodiment two, assuming that the segment number n=5 of the uniformly distributed load on the solid elliptical cross-section beam, then the maximum serial number of the odd-numbered bending moment is M 2n+1 , namely M 11 , the maximum serial number of the even-numbered bending moment is M 2n , namely M 10 ;The total load Q=73.5kN of 5 sections of uniform load, so the support reaction force V=Q / 2=36.75kN; beam length L 2 = 3m, interval between uniformly distributed loads of each section Thus L 1 =360mm, evenly distributed load According to formula (1) (odd-numbered section, i.e. the bending moment of interval section) and formula (2) (even-numbered section, i.e. the bending moment of uniformly distributed load section) and the technical scheme of the present invention, the bending moment M of each section can be obtained k (x)(kNm) and the semi-longitudinal axis of the beam c k (x)(m) is as follows (2c k (x) is beam height).

[0097] (External loads of embodime...

Embodiment 3

[0144]Embodiment 3, the parameters of each working condition are the same as in Embodiment 2, a hollow elliptical cross-section beam is used, the number of segments with uniform load is n=5, and the maximum number of odd-numbered bending moments is M 2n+1 , namely M 11 , the maximum serial number of the even-numbered bending moment is M 2n , namely M 10 ;The total load Q=73.5kN of 5 sections of uniform load, so the support reaction force V=Q / 2=36.75kN; beam length L 2 = 3m, interval between uniformly distributed loads of each section Thus L 1 =360mm, evenly distributed load According to formula (1) (odd-numbered section, i.e. the bending moment of interval section) and formula (2) (even-numbered section, i.e. the bending moment of uniformly distributed load section) and the technical scheme and measures of the present invention, the bending moment of each section can be obtained m k (x) (kNm) is as described in Example 2. The height c(x) of the hollow elliptical secti...

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Abstract

The invention discloses an oval cross section equal-strength supporting beam bearing loads uniformly distributed at intervals, belongs to the technical field of mechanical structure design and manufacturing, and solves the technical problems that beam materials cannot be fully utilized, the structural size is too large and the like due to non-uniform internal load distribution of the beam. The structural size of the oval cross section equal-strength supporting beam with the loads evenly distributed at intervals changes along with the magnitude of the internal loads borne by the oval cross section equal-strength supporting beam, so that the maximum stress on each cross section of the beam is equal, and the technical effects that the strength of each cross section is equal everywhere, materials are saved, the structure is simplified, and the weight is reduced are achieved.

Description

technical field [0001] The invention relates to an elliptical cross-section equal-strength support beam subjected to uniformly distributed loads at intervals, and belongs to the technical field of mechanical structure design and manufacture. Background technique [0002] In actual production, technical problems of girders bearing uniform loads at intervals are often encountered. For example, the aluminum foil of an aluminum foil production plant needs to be supported by girders during heat treatment and other processes. Aluminum foil is produced in rolls, and the aluminum foil is wound outside a hollow core. An aluminum roll is about 300kg to 2000kg. In the heat treatment furnace, a beam passes through the core to support several aluminum foil rolls. Between each aluminum foil roll There is a certain interval. Such as figure 1 is a schematic diagram of aluminum foil roll support, the length is L 2 The girder passes through the core to support several aluminum foil rolls, ...

Claims

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Application Information

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Patent Type & Authority Applications(China)
IPC IPC(8): G06F30/17G06F119/14G06F111/04G06F119/18
CPCG06F30/17G06F2119/14G06F2111/04G06F2119/18
Inventor 朱瑞林朱国林毛爱凤方正兴
Owner HUNAN NORMAL UNIVERSITY