Oval cross section equal-strength supporting beam bearing loads evenly distributed at intervals
A technology of uniform load distribution and cross-section, applied in the field of strength support beams, can solve the problems of increasing beam weight, cost increase, waste, etc., and achieve the effect of reducing weight, simplifying structure, and saving materials
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Embodiment 1
[0049] Embodiment 1, assuming that the number of sections of the uniformly distributed load on the solid elliptical cross-section beam is n=5, then the maximum sequence number of the odd-numbered bending moment is M 2n+1 , namely M 11 , the maximum serial number of the even-numbered bending moment is M 2n , namely M 10 ;The total load Q=73.5kN of 5 sections of uniform load, so the support reaction force V=Q / 2=36.75kN; beam length L 2 = 3m, interval between uniformly distributed loads of each section Thus L 1 =564mm, evenly distributed load According to formula (1) (odd-numbered section, i.e. the bending moment of interval section) and formula (2) (even-numbered section, i.e. the bending moment of uniformly distributed load section) and the technical scheme of the present invention, the bending moment M of each section can be obtained k (x)(kNm) and beam height dimension h k (x)(m) are as follows:
[0050] The first section 0≤x≤a, that is, 0≤x≤0.03m section, k=1:
[0...
Embodiment 2
[0096] Embodiment two, assuming that the segment number n=5 of the uniformly distributed load on the solid elliptical cross-section beam, then the maximum serial number of the odd-numbered bending moment is M 2n+1 , namely M 11 , the maximum serial number of the even-numbered bending moment is M 2n , namely M 10 ;The total load Q=73.5kN of 5 sections of uniform load, so the support reaction force V=Q / 2=36.75kN; beam length L 2 = 3m, interval between uniformly distributed loads of each section Thus L 1 =360mm, evenly distributed load According to formula (1) (odd-numbered section, i.e. the bending moment of interval section) and formula (2) (even-numbered section, i.e. the bending moment of uniformly distributed load section) and the technical scheme of the present invention, the bending moment M of each section can be obtained k (x)(kNm) and the semi-longitudinal axis of the beam c k (x)(m) is as follows (2c k (x) is beam height).
[0097] (External loads of embodime...
Embodiment 3
[0144]Embodiment 3, the parameters of each working condition are the same as in Embodiment 2, a hollow elliptical cross-section beam is used, the number of segments with uniform load is n=5, and the maximum number of odd-numbered bending moments is M 2n+1 , namely M 11 , the maximum serial number of the even-numbered bending moment is M 2n , namely M 10 ;The total load Q=73.5kN of 5 sections of uniform load, so the support reaction force V=Q / 2=36.75kN; beam length L 2 = 3m, interval between uniformly distributed loads of each section Thus L 1 =360mm, evenly distributed load According to formula (1) (odd-numbered section, i.e. the bending moment of interval section) and formula (2) (even-numbered section, i.e. the bending moment of uniformly distributed load section) and the technical scheme and measures of the present invention, the bending moment of each section can be obtained m k (x) (kNm) is as described in Example 2. The height c(x) of the hollow elliptical secti...
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