Traditional Chinese medicine health assessment method based on personalized normal state information and application thereof
A technology of health assessment and normality, which is applied in the field of TCM health assessment based on personalized normality information, can solve problems such as not considering individual differences, and achieve the effect of improving accuracy
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Embodiment 1
[0045] A TCM health assessment method based on personalized normal information, such as figure 1 shown, including the following steps:
[0046] (1) Obtain k (k=3) sets of lingual images of the subject to be evaluated, each set of lingual images includes tongue images and facial pictures, and the k (k=3) lingual images are collected every day for three consecutive days obtained once;
[0047] (2) Process the tongue images one by one and obtain the comprehensive health index corresponding to each set of tongue images:
[0048] (2.1) Use the commonly used tongue segmentation method to segment the tongue image to obtain the tongue body (T), and use the target detection algorithm FAST R-CNN in deep learning to segment the facial image to obtain the forehead (P1) and left cheek (P2) , right cheek (P3), nose tip (P4) and lower jaw (P5);
[0049] (2.2) Determine the color space as the LAB color space, and calculate the corresponding values of each part obtained in step (2.1) unde...
example 1
[0064] Take the processing of a set of tongue images as an example:
[0065] The corresponding L value, A value and B value of the tongue body obtained in step (2.2) are: T_L=80, T_A=135, T_B=137;
[0066] The corresponding L value, A value and B value of the forehead (P1), left cheek (P2), right cheek (P3), nose tip (P4) and jaw (P5) are:
[0067] P1_L=95, P1_A=136, P1_B=141;
[0068] P2_L=80, P2_A=135, P2_B=137;
[0069] P3_L=149, P3_A=126, P3_B=136;
[0070] P4_L=85, P4_A=138, P4_B=135;
[0071] P5_L=65, P5_A=135, P5_B=135;
[0072] The corresponding L value, A value and B value of the face are:
[0073] F_L=w1*P1_L+w2*P2_L+w3*P3_L+w4*P4_L+w5*P5_L=39.72;
[0074] F_A=w1*P1_A+w2*P2_A+w3*P3_A+w4*P4_A+w5*P5_A=54.89;
[0075] F_B=w1*P1_B+w2*P2_B+w3*P3_B+w4*P4_B+w5*P5_B=56.45;
[0076] The comprehensive health index obtained in step (2.3) is 0.67;
[0077] Calculate the comprehensive health index corresponding to the three sets of tongue images respectively, in order of...
example 2
[0082] Take the processing of a set of tongue images as an example:
[0083] The corresponding L value, A value and B value of the tongue body obtained in step (2.2) are: T_L=80, T_A=135, T_B=137;
[0084] The corresponding L value, A value and B value of the forehead (P1), left cheek (P2), right cheek (P3), nose tip (P4) and jaw (P5) are:
[0085] P1_L=95, P1_A=136, P1_B=141;
[0086] P2_L=80, P2_A=135, P2_B=137;
[0087] P3_L=149, P3_A=126, P3_B=136;
[0088] P4_L=85, P4_A=138, P4_B=135;
[0089] P5_L=65, P5_A=135, P5_B=135;
[0090] The corresponding L value, A value and B value of the face are:
[0091] F_L=w1*P1_L+w2*P2_L+w3*P3_L+w4*P4_L+w5*P5_L=39.72;
[0092] F_A=w1*P1_A+w2*P2_A+w3*P3_A+w4*P4_A+w5*P5_A=54.89;
[0093] F_B=w1*P1_B+w2*P2_B+w3*P3_B+w4*P4_B+w5*P5_B=56.45;
[0094] The comprehensive health index obtained in step (2.3) is 0.67;
[0095] Calculate the comprehensive health index corresponding to the three sets of tongue images respectively, in order of...
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