Frame glasses adaptability detection and evaluation method
A technology of adaptability and glasses, which is applied in the directions of glasses/protective glasses, glasses/goggles, optics, etc., can solve the problems of matching the glasses with the wearer's head and face, and cannot effectively guarantee the use effect of fitting glasses. Problems such as optical center and pupil deviation can reduce glasses inappropriateness, protect eyesight development, and measure accurately
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Embodiment 1
[0037] Example 1: The optometry result of the person with ametropic glasses is -6.00DS for the right eye, and the original inclination angle of the lens is 8°, namely Φ s =-6.00DS, Φ c = 0, α 0 = 0°, θ 1 = 8°, when the glasses are in the upright position, the distance from the corneal apex to the lens does not exceed 12 mm; after performing steps 1 to 4 of the above method on the spectacle wearer, the distance from the side corneal apex to the lens does not exceed 12 mm, and read the offset value of the front lens circle The right eye is 6mm down, that is, y=0.6cm x=0cm, the offset value of the side mirror leg is moved forward by 3mm, that is, d=-0.003m, and the straight-line distance before and after the displacement is 5mm, that is, r=5mm and substituted into Formula calculation:
[0038] Px=-x·Φ s +(y·cosα 0 -x sinα 0 )·Φ c · sinα 0 =0
[0039] Py=-y·Φ s +(x·sinα 0 -y·cosα 0 )·Φ c · cosα0 =3.6 Δ
[0040] f B =F A / (1-dF A )=-6 / (1-0.018)=-6.11DS
[0041] θ...
Embodiment 2
[0045] Example 2: The optometry result of a person with ametropic glasses is +4.00DS for both eyes, and the original inclination angle of the lens is 15°, namely Φ s =+4.00DS,Φ c =0,α 0 = 0°, θ 1 = 15°, when the glasses are in the upright position, the distance from the corneal apex to the lens does not exceed 12mm; after performing steps 1 to 4 of the above method on the spectacle wearer, the distance from the side corneal apex to the lens is 12mm, and the offset value of the front lens circle is The left and right sides are 4mm downward, that is, y=0.4cm x=0cm, the offset value of the side temple is moved forward by 5mm, that is, d=-0.005m, and the straight-line distance before and after the displacement is 6mm, that is, r=6mm and Substitute into the formula to calculate:
[0046] Px=-x·Φ s +(y·cosα 0 -x sinα 0 )·Φ c · sinα 0 =0
[0047] Py=-y·Φ s +(x·sinα 0 -y·cosα 0 )·Φ c · cosα 0 =1.6 Δ (The bottom of the prism faces the negative axis of the y-axis)
[004...
Embodiment 3
[0053] Example 3: The optometry result of the person with ametropic glasses is -6.00DS+2.00DC×40° for the right eye. The original inclination angle is 10°, namely Φ s =-6.00DS,Φ c =2.00DC,α 0 =40°,θ 1 = 10°, when the glasses are in the upright position, the distance from the corneal apex to the lens does not exceed 12 mm; after performing steps 1 to 4 of the above method on the spectacle wearer, the distance from the side corneal apex to the lens is less than 12 mm, and the offset value of the front lens ring is read 6mm downward, 3mm outward, that is, y=0.6cm, x=0.3cm, the offset value of the side temple is moved forward by 3mm, that is, d=-0.003m, and the straight-line distance before and after the displacement is 4mm, that is, r= 4mm and substitute into the formula to calculate:
[0054] Px=-x·Φ s +(y·cosα 0 -x sinα 0 )·Φ c · sinα 0 =2.14 Δ
[0055] Py=-y·Φ s +(x·sinα 0 -y·cosα 0 )·Φ c · cosα 0 =3.43 Δ
[0056] P=√(Px 2 +Py 2 ) = 4.04 Δ
[0057] f BS (...
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