Thermoelectric component
A technology of thermoelectric elements and components, which is applied in the field of electronics, can solve the problems of low figure of merit, limitations, and low efficiency of thermoelectric conversion, so as to reduce the loss of cold and heat and expand the market space.
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example 1
[0024] Example 1: A thermoelectric component, the figure of merit Z of the thermoelectric material 材 =0.003K -1 , the cross-sectional area S of the thermoelectric element 1 1 = 4 square millimeters, length L 1 = 4 mm, the cross-sectional area S of the thermoelectric element 2 2 = 4 square millimeters, length L 2 = 1 mm. The cross-sectional area of the junction S 3 = 0.2 square millimeters.
[0025] Then S 1 / S 3 =20,Z 3 = Z 1 =0.003K -1 ×20=0.06K -1 . Therefore, under adiabatic conditions, the figure of merit of this semiconductor thermoelectric component from the hot end to the cold end is 0.06 K -1 , the direction is from the hot end of thermoelectric element 1 to the cold end of thermoelectric element 2.
example 2
[0026] Example 2: A semiconductor thermoelectric component, the figure of merit Z of the thermoelectric material 材 =0.0025K -1 , the cross-sectional area S of the thermoelectric element 1 1 =3 square millimeters, the cross-sectional area S of the thermoelectric element 2 2 = 2 square millimeters, L 1 = 2 mm, L 2 = 1 mm, the cross-sectional area S of the joint 3 = 0.1 square millimeters.
[0027] Then S 1 / S 3 = 30, Z 3 = Z 1 =0.0025K -1 ×30=0.075K -1 . Therefore, under adiabatic conditions, the figure of merit of this semiconductor thermoelectric component from the hot end to the cold end is 0.075 K -1 , the direction is from the hot end of thermoelectric element 1 to the cold end of thermoelectric element 2.
example 3
[0028] Example 3: A semiconductor thermoelectric component, the figure of merit Z of the thermoelectric material 材 =0.0035K -1 , the cross-sectional area S of the thermoelectric element 1 1 = 4 square millimeters, S 2 = 4 square millimeters, L 1 = 4 mm, L 2 = 1 mm. The thermoelectric element 1 and the thermoelectric element 2 are connected by welding, and the cross-sectional area S of the joint is 3 =0.1mm², without considering the welding resistance, then S 1 / S 3 = 40, Z 3 = Z 1 =0.0035K -1 ×40=0.14K -1 . Therefore, under adiabatic conditions, the figure of merit of this semiconductor thermoelectric component from the hot end to the cold end is 0.14 K -1 , the direction is from the hot end of thermoelectric element 1 to the cold end of thermoelectric element 2.
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