Method for rapidly distinguishing normal tea and suspicious tea
A tea, normal technology, applied in the field of quickly distinguishing normal tea from suspicious tea, can solve problems such as large errors
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Embodiment 1
[0080] A method for quickly distinguishing normal tea leaves from suspicious tea leaves, comprising the following steps:
[0081] 1) Weigh 0.2 g of commercially available black tea leaves that have been pulverized and processed through No. 2 sieve into a 15 mL centrifuge tube, add 5 mL of 70% ethanol aqueous solution respectively, shake for 30 s, extract in a water bath for 10 min at 70°C, and collect extract, and then add 5 mL of 70% ethanol aqueous solution to repeat the extraction once, and combine the two extracts;
[0082] 2) Take 0.1 mL of the above extract in a test tube, add 2 mL of water and 0.2 mL of 0.1% sodium indigo disulfonate solution, mix well, and then add 0.45 mL of potassium permanganate solution with a concentration of 0.0004 g / mL, shake uniform, the color does not fade within half a minute, and solution A is obtained. See the color of solution A. Figure 4 ;
[0083] 3) Judging that the above-mentioned tea leaves are suspicious tea leaves according to th...
Embodiment 2
[0086] A method for quickly distinguishing normal tea leaves from suspicious tea leaves, comprising the following steps:
[0087] 1) Weigh 0.2 g of commercially available black tea leaves that have been pulverized and processed through No. 2 sieve into a 15 mL centrifuge tube, add 5 mL of 70% ethanol aqueous solution respectively, shake for 30 s, extract in a water bath for 10 min at 70°C, and collect extract, and then add 5 mL of 70% ethanol aqueous solution to repeat the extraction once, and combine the two extracts;
[0088] 2) Take 0.1 mL of the above extract in a test tube, add 2 mL of water and 0.2 mL of 0.1% sodium indigo disulfonate solution, mix well, and then add 0.45 mL of potassium permanganate solution with a concentration of 0.0004 g / mL, shake uniform, the color does not fade within half a minute, and solution A is obtained. See the color of solution A. Figure 5 ;
[0089] 3) Judging that the above-mentioned tea leaves are normal tea leaves according to the ju...
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