Submarine-launched missile bionic warhead capable of weakening wave disturbance
A technology of warheads and missiles, applied in the direction of warheads, ammunition, projectiles, etc., can solve problems such as crashes, missile instability, missile flight attitude deflection, etc., and achieve the goal of reducing pressure difference, reducing wave force, and uniform distribution of pressure field Effect
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[0057] Example 1:
[0058] Loaded with a missile model with a bionic grooved warhead such as image 3 As shown, in the model, H=50mm, H2=2.5mm, H1=5mm, and the three parts of the outline f, m and g are combined into a complete outline curve. figure 1 The midpoint o is the origin, os is the positive direction of the x-axis, and op is the positive direction of the y-axis, then the equation of the contour curve is:
[0059] y=0.000004511*x^6+0.0003111*x^5-0.0082*x^4+0.1002*x^3-5949*x^2+1.029*x+5
[0060] Among them: 0≤x≤25mm;
[0061] The outline dimensions of the section at the bottom H3 of the middle section II of the warhead with the bionic groove are as follows:
[0062] n=40, and take θ1=θ2=4.5°, while θ1 and θ2 determine the size of d1 and d2, and the size of D2 is determined by the outline m.
[0063] Since d1=k1*(H 4 / 2-|H 4 / 2-H 3 |) / (|H 4 / 2-H 3 |+j1);
[0064] d2=k2*(H 4 / 2-|H 4 / 2-H 3 |) / (|H 4 / 2-H 3 |+j2),
[0065] Here, d1=d2 is taken, that is, k1=k2...
Example Embodiment
[0067] Example 2:
[0068] Loaded with a missile model with a bionic grooved warhead such as image 3 As shown, in the model, H=50mm, H2=2.5mm, H1=5mm, and the three parts of the outline f, m and g are combined into a complete outline curve. figure 1 The midpoint o is the origin, os is the positive direction of the x-axis, and op is the positive direction of the y-axis, then the equation of the contour curve is:
[0069] y=0.000004511*x^6+0.0003111*x^5-0.0082*x^4+0.1002*x^3-5949*x^2+1.029*x+50
[0070] Among them: 0≤x≤25mm. Among them, the outline size of the section at the bottom H3 of the middle section II of the warhead with the bionic groove is as follows: n=40, and take θ1=θ2=4.5°, and θ1, θ2 determine the size of d1, d2, D2 size is determined by the shape The contour m is determined.
[0071] Since d1=k1*(H4 / 2-|H4 / 2-H3|) / (|H4 / 2-H3|+j1);
[0072] d2=k2*(H4 / 2-|H4 / 2-H3|) / (|H4 / 2-H3|+j2),
[0073] Here, d1=d2 is taken, that is, k1=k2=1 / 6, and j1=j2=4.
[0074] Through ...
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