Method for climate control in buildings
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[0054]In practice, a plurality of the afore-described variables are measured directly at a building 1 by means of corresponding sensors or are calculated by means of a corresponding logic in the regulation.
[0055]The following example is to clarify this. Assumption:
Ta = 12°φa = 0.8Ti = 18° C.φ1 = 0.5Building height = 5 mmwind speed = 3 m / s
It follows from this:[0056]1) A partial water vapor pressure difference from outside to inside of 91 Pascal.[0057]2) A pressure drop of the internal building pressure Pi of 1.2 Pascal and an internal building pressure Pi in the lower range of −0.6 Pascal. An overpressure P+ of 5.6 Pascal results through the wind.[0058]3) A temperature drop of 6 Kelvin from the inside to the outside.
[0059]It is to now be determined, how the air flow is to be forced through the ventilation system 2. When considering only the critical relative humidity of 0.8, it can then be determined that the inside air would reach a critical moisture value when passing through the i...
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