Method used for reducing residual impedance effect of voltage transformer and inductive voltage divider primary winding
A technology of inductive voltage divider and voltage transformer, which is applied in the direction of transformer/inductor coil/winding/connection, voltage divider, inductor, etc., can solve problems such as errors, and achieve accurate and efficient transformers and inductive voltage dividers. Reduce the influence of residual impedance, the effect of large influence
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Embodiment 1
[0027] Example 1, Figure 8 It is a schematic diagram of the method for reducing the influence of the residual impedance of the primary winding of the voltage transformer and the inductive voltage divider described in the present invention, and uses this example to further analyze the essence of the method.
[0028] Let the primary voltage be V 1 , N 1 Winding inductance is Z 1 , the resistance is r 1 , the leakage inductance is l 1 , then the primary winding residual impedance z 1 = r 1 +jωl 1 , current I 1 Flow-through inductive reactance Z 1 The voltage drop across the I 1 Z 1 . Let N 1 , N 2 Between ideal coupling, the voltage I 1 Z 1 will be coupled to winding N 2 , so follower A 1 The input voltage is the primary voltage V 1 coupled with the winding N 2 The difference in the induced voltage, that is, V 1 -I 1 Z 1 , the difference voltage is amplified k times by the inverting amplifier. Amplifier output via DC blocking capacitor C 1 with winding N ...
Embodiment 2
[0030] Embodiment 2, press Figure 7 A double-stage voltage transformer is manufactured with the present invention, the primary voltage is 1000 volts, the secondary voltage is 100 volts, the frequency is 50 Hz, and the load is zero VA.
[0031] Iron core 1 is made of silicon steel Z10 and a strip with a thickness of 0.3mm, the specification is Φ60×180 / 80, and 1000 turns are evenly wound with Φ0.13QZ wire as N 1 , the inductance is 300H, the resistance r 1 =400Ω, approximate residual inductance, then the resistance r 1 The introduced error is -r 1 / Z 1 =j400 / (314×300)=4.246×10 -3 (radian) = 14.6 (minutes). Wind 1000 turns uniformly with Φ0.12QZ wire as N 3 .
[0032] Now stack the iron core 2, the material is nanocrystalline 1k107, the specification is Φ53×187 / 10, use Φ0.13QZ wire to wind 1000 turns evenly on the two iron cores as N 4 , the inductance is 530H, the resistance r 4 =440Ω, approximate residual inductance, then the resistance r 4 The introduced error is -r...
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